A 58.72 kg person holding a steel ball stands motionless on a frozen lake.
The person then throws the ball, which propels the person at 1.05 m/s to the
right and the ball 3.75 m/s to the left. If the initial momentum of the system is
zero, what is the mass of the steel ball?

Answer:

c

Explanation:

pls give brainliest have a great day

TDS and ppm are common units used to measure the quantity of substance in the water, therefore the correct answer is option A.

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

Common units used to measure the amount of material in water are TDS and part per million.

As given in the problem we have to find out for what measurement, the units TDS (Total dissolved solid )and ppm (parts per million) are used.

The total dissolved solid and parts per million are used to measure the amount of substance present in the water, therefore the correct answer is option A.

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Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

We are given the following function:

This is an absolute value function. The graph of this function is the following:

Where we change the function to:

When the absolute value function is multiplied by a number smaller than one its graphs "opens more". Therefore, the new graph should look as follows:

The Free Body Diagram must include all forces acting on an object, not just weight and normal force. For example,The friction force between a box and a ramp must be considered, directed up the ramp and opposite to the weight force, to accurately analyze equilibrium and predict behavior.

1. The Free Body Diagram only shows two forces acting on the box - the weight force and the normal force from the ramp.

2. However, there are other forces that should be included in the diagram, such as the force of friction between the box and the ramp.

3. The force of friction would be directed up the ramp, opposite to the direction the box would slide if it were not stationary.

4. Therefore, the Free Body Diagram should include an arrow representing the force of friction, pointing up the ramp and opposite to the direction of the weight force.

5. Including all the forces in the Free Body Diagram is important to accurately analyze the equilibrium of the box and predict its behavior.

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Wouldn't it be B because it's a majority pointing to it?

Sorry if i'm wrong.

The cannon recoil with velocity of 7.5 m/s.

Velocity defines the direction of the movement of the body or the object.

To calculate the resulting velocity of the cannon, we use the concept of conservation of momentum.

m1v1 = m2v2

Here,  is the mass of cannon and its value is 2000 kg,  is the mass of the shell which is fired from cannon and its value is 30.0 kg,  is the velocity of shell and  is the resulting velocity of cannon.

Substituting these values in above formula we get,

2000kg x v1 = 30.0 kg x 500 m/s

v1 =30.0 kg x 500 m/s  = 7.5 m/s.

           2000kg

Therefore, The cannon recoil with velocity of 7.5 m/s.

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Answer:

xf = 5.68 × 10³ m  

yf = 8.57 × 10³ m  

Explanation:

given data

vi = 290 m/s

θ = 57.0°

t = 36.0 s

solution

firsa we get here origin (0,0) to where the shell is launched

xi = 0                            yi = 0

xf = ?                            yf = ?

vxi =  vicosθ               vyi = visinθ  

ax = 0                          ay = −9.8 m/s

now we solve x motion: that is

xf = xi + vxi × t + 0.5 × ax × t²     ............1

simplfy it we get

xf = 0 + vicosθ × t + 0

put here value and we get

xf = 0 + (290 m/s) cos(57) (36.0 s)

xf = 5.68 × 10³ m  

and

now we solve for y motion: that is

yf = yi + vyi × t + 0.5 × ay × t ²     ............2

put here value and we get

yf = 0 + (290 m/s) × sin(57) × (36.0 s) + 0.5 × (−9.8 m/s2) × (36.0 s)  ²

yf = 8.57 × 10³ m  

These waves are traveling at the same speed.  The wave with the highest frequency is option C, "A wave frequency with line crossing in the middle."

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For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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The wavelength of the wave shown in the image is approximately 0.0018 m.

we can see that there are two points marked as "A" on the string, which represents two consecutive peaks of the wave. The distance between these two points is 45 m.

The wavelength of a wave is the distance between two consecutive peaks or troughs of the wave. Therefore, in this case, the wavelength is simply the distance between the two points marked as "A".

Using the ruler provided in the image, we can measure the distance between the two points marked as "A" to be approximately 0.18 cm. However, this measurement is not in meters, which is the standard unit for measuring wavelength.

To convert the measurement to meters, we need to divide it by 100, since there are 100 centimeters in 1 meter. Therefore, the distance between the two points marked as "A" is:

0.18 cm ÷ 100 = 0.0018 m

So the wavelength of the wave shown in the image is approximately 0.0018 m.

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Answer: 52 kg skydiver: 9.09 m/s and 522.55 s

              95 kg skydiver: 12.3 m/s and 386.2 s

Explanation: Drag Force is an opposite force when an object is moving in a fluid.

For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.

Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:

\(F_{G}=F_{D}\)

\(mg=\frac{1}{2}C \rho Av_{T}^{2}\)

\(v_{T}=\sqrt{\frac{2mg}{\rho CA} }\)

where

m is mass in kg

g is acceleration due to gravitational force in m/s²

ρ is density of the fluid in kg/m³

C is drag coefficient

A is area of the object in the fluid in m²

Calculating:

The 52kg skydiver has terminal velocity of:

\(v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }\)

\(v_{T}=\) 9.09

The 95kg skydiver's terminal velocity is

\(v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }\)

\(v_{T}=\) 12.3

The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.

The time each one will reach the floor will be:

52 kg at 9.09 m/s:

\(t=\frac{4750}{9.09}\)

t = 522.5

95 kg at 12.3 m/s:

\(t=\frac{4750}{12.3}\)

t = 386.2

The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.

Answer:

3.6×10⁻⁶  Nm

Explanation:

From the question,

The expression for maximum torque is given as

τ = BANI.................Equation 1

where τ = maximum torque, B = magnetic field, A = Area of the coil, N = number of turns, I = current carried by the coil.

Given: B = 0.1 T, A = (5×12) = 60 cm² = 0.006 m², N = 600 turns, I = 10⁻⁵ A.

Substitute these values into equation 1

τ = 0.1(0.006)(600)(10⁻⁵)

τ = 3.6×10⁻⁶  Nm

Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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Answer:

  A. separation is increasing at about 9.90 m/s

  B. about 9.90 m/s

  C. see attached

Explanation:

A. Both stones are accelerated at the same rate, so the difference in their velocities is the velocity stone A had when stone B was dropped. The distance between the stones increases linearly at that velocity, about 9.90 m/s.

__

B. The speed when accelerated from rest over some distance d can be found as ...

  v = √(2dg) = √(2(5 m)(9.8 m/s²)) = 7√2 m/s

The speed of stone B at 5 meters is about 7√2 ≈ 9.90 m/s.

__

C. See the attachment for a velocity vs. time graph. Stone B has traveled 10 m when its velocity is -14 m/s

Answer:

The ambient temperature is 35°C.

It takes 15 minutes to cool the substance from 40°C to 35°C.

Explanation:

Using Newton's Law of Cooling to answer the given problem.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Newton's Law of Cooling:}}\\\\ \frac{dT}{dt} =-k(T-T_a)\end{array}\right}\)

Given:

The time it takes to cool from 50°C to 45°C = 3 minutes

The time it takes to cool from 45°C to 40°C = 5 minutes

Find:

Time ambient temperature and the time it takes to cool the substance from 40°C to 35°C

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(1) - Using first initial condition:

\(\text{Avg temp =} \ \frac{50+45}{2}=\boxed{47.5 \textdegree C}\\\\\Longrightarrow \frac{50-45}{3}=-k(47.5-T_a) \\\\\Longrightarrow \boxed{ \frac{5}{3}=-k(47.5-T_a)}\)

(2) - Using the second initial condition:

\(\text{Avg temp =} \ \frac{45+40}{2}=\boxed{42.5 \textdegree C}\\\\\Longrightarrow \frac{45-40}{5}=-k(42.5-T_a) \\\\\Longrightarrow \boxed{1=-k(42.5-T_a)}\)

(3) - Now we have a system of equations.

\(\left \{ \frac{5}{3}=-k(47.5-T_a)}} \atop {1=-k(42.5-T_a)}}} \right.\)

(4) - Solve the system by dividing the top equation by the bottom equation.

\(\Longrightarrow \frac{\frac{5}{3}=-k(47.5-T_a)}{1=-k(42.5-T_a)} \\\\\Longrightarrow\frac{5}{3}=\frac{47.5-T_a}{42.5-T_a}\\ \\ \Longrightarrow 5(42.5-T_a)=3(47.5-T_a)\\\\\Longrightarrow 212.5-5T_a=142.5-3T_a\\\\\Longrightarrow 2T_a=70\\\\\therefore \boxed{T_a=35 \textdegree C}\)

Thus, the ambient temperature is 35°C.

(5) - Find the value of "k" using either of the two previous equations

\(1=-k(42.5-T_a)\\\\\Longrightarrow 1=-k(42.5-35)\\\\\Longrightarrow 1=-7.5k\\\\\Longrightarrow \boxed{ k \approx -0.133}\)

(6) - Now finding "dt"

\(\text{Avg temp =} \ \frac{40+35}{2}=\boxed{37.5 \textdegree C}\\\\\Longrightarrow \frac{40-35}{dt}=0.133(37.5-35) \\\\\Longrightarrow \frac{5}{dt}=0.3325\\\\\therefore \boxed{dt \approx15 \ min}\)

Thus, it take 15 minutes to cool the substance from 40°C to 35°C.

Explanation:

Object is under the effect of the acceleration of gravity

v = 1/2 a t^2       a = 9.81 m/s^2   t = 2.3

v = 25.9 m/s^2 = ~ 26 m/s   ( two significant digits)

Answer:

The answer is below

Explanation:

An LR series circuit has a differential equation in the form of:

\(L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=200,for\ 0 \leq t \leq\ 50. Hence:\\\\50\frac{di}{dt}+5i =200\\\\\frac{di}{dt}+0.1i =4\\\\Solving\ the\ differential\ equation:\\\\The\ integrating\ factor(I)=e^{\int\limits {0.1} \, dt }=e^{0.1t}. The\ DE\ becomes:\\\\e^{0.1t}\frac{di}{dt}+e^{0.1t}(0.1i) =4e^{0.1t}\\\\e^{0.1t}i=\int\limits {4e^{0.1t}} \, dt \\\\e^{0.1t}i=40e^{0.1t}+A\\\\i(t)=40+Ae^{-0.1t}\\\\but\ i(0)=0\\\\0=40+Ae^{-0.1(0)}\\\\A=-40\\\\i(t)=40-40e^{-0.1t}\\\\\)

At 50 seconds:

\(i(50)=40-40e^{-0.1*50}\\\\i(50)=40-40e^{-5}\)

\(L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=0,for\ t> 50. Hence:\\\\50\frac{di}{dt}+5i =0\\\\\frac{di}{dt}+0.1i =0\\\\\frac{di}{dt}=-0.1i\\\\\frac{di}{i}=-0.1dt\\\\\int\limits {\frac{di}{i}} =\int\limits {-0.1} \, dt\\ \\ln(i)=-0.1t+A\\\\taking\ exponential:\\\\i=e^{-0.1t+A}\\\\i=e^{-0.1t}e^A\\\\i(t)=Ce^{-0.1t}\\\\i(50)=40-40e^{-5}=Ce^{-5}\\\\C=40(e^5-1)\\\\i(t)=40(e^5-1)e^{-0.1t}\\\\\)

\(i(t)=\left \{ {{40-40e^{-0.1t}\ \ \ \ 0 \leq t \leq 50 } \atop {40(e^5-1)e^{-0.1t}\ \ \ \ t>50}} \right.\)

Answer:

PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

Answer:

The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters

Explanation:

it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.

i.e

v = u + gt

whte v is final velocity of the object

u is initial velocity of the object

g is acceleration due to gravity and

t is time. thanks

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Assuming there is little air resistance, the acceleration felt by both objects when one drops a 20-ton object and a 10-ton object at the same time will be the same.

Even though both objects accelerate at the same rate, the forces acting on them will be different because of their different masses. Newton's second law of motion states that an object's force is inversely proportional to its mass (F = ma). The 20-ton object will therefore encounter twice as much force as the 10-ton object, but their rates of acceleration will remain constant.

In conclusion, both the 20-ton and 10-ton objects will accelerate to about 9.8 meters per second squared when dropped simultaneously with little air resistance.

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Answer:

a.   m = 4.2•10⁻⁴ kg

b.   B = 0.01962 N

c.   ∑F = 0.0155 N (upward)

d.   a = 6.51•10⁻⁶ m/s² (upward)

Explanation: I'm unsure if you have the correct values, but either way, the steps are below:

a. Mass:

Volume • Density = Mass

(2 cm³)(210 kg/m³)(10⁻⁶ m³/cm³)= 0.00042 kg or 4.2•10⁻⁴ kg

b. Buoyant Force:

Fluid Density • Displaced Volume • Gravity = Buoyant Force

**The Fluid is water, so the fluid density = 1 g/cm³, and the displaced volume is the same as the volume of the cork.**

ρ • V • g = B

[(1 g/cm³)(10⁻³ kg/g)](2 cm³)(9.81 m/s²) =

(10⁻³)(2)(9.81) = 0.01962 N

c. Net Force:

∑F: B - W = ma

mass • gravity = W

(4.2•10⁻⁴ kg)(9.81 m/s²) = 0.0041202 N

(0.01962) - (0.0041202) = 0.0154998 N

d. Acceleration:

F = ma

F/m = a

(0.0155•10⁻² kg•m/s²)/(4.2•10⁻⁴ kg) = 0.000006509916 m/s²

                                                      or 6.51•10⁻⁶ m/s²

––––––––––––––––––––––––––––––––––––––

The reason the values are so small is because N = kg•m/s², so all mass units need to stay in kg, even though it would be simpler to have them in grams.

Answer:

3.8 m/s/s^2

Explanation:

The acceleration due to gravity on the planet where a 80 kg astronaut weighs only 304 N is 3.8 m/s².

The gravitational force is the force by which an object attracts other objects into its centre of mass. The force it exerts depends on the mass of the body and distance between them. Earth attracts every objects on its surface to the ground by gravitational force

The acceleration arises in the body due to the force of gravitation is called acceleration due to gravity (g). It varies from planets to planet. The weight we experience in earth is due to the gravity.

Weight = m g

where m is the mass.

given the mass of an astronaut = 80 kg

weight  = 304 N

then g = weight/ mass

           = 304 N / 80 Kg = 3.8 m/s²

Therefore, the acceleration due to gravity of the planet is 3.8 m/s².

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Answer:

Endurance, or aerobic

Strength, or resistance training

Balance

Flexibility

Explanation:

Answer:

Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).

The concept of left or right can be described mathematically by using ( m₁*v₁)initial  + (m₂*v₂)initial  = (m₁*v₁)final + (m₂*v₂)final because as per the conservation of the momentum the, momentum before and after the collision will remain conserved.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle,

P = mv

As given in the problem we have described the concept of left or right mathematically by using( m₁*v₁)initial  + (m₂*v₂)initial  = (m₁*v₁)final + (m₂*v₂)final

The total momentum of the object before the collision would be equal to the total momentum of the objects after the collision.

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Answer:

a sphere of influence mmmmmmmmmmm not actually right

The value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.

Significant figures is a digit that is meaningful with respect to the precision of a measurement.

Significant figures constitutes a digit that is nonzero, followed by a nonzero digit, or (for trailing zeroes) justified by the precision of the derivation or measurement.

According to this question, the following arithmetic expression is given:

15.2 ÷ 4.368 = 3.47985348

Therefore, the value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.

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To solve the problem, let's break it down into three parts:

1. Determining the distance covered by cars A and B as a function of time:

For uniformly accelerated rectilinear motion, we can use the following equation to calculate the distance covered:

distance = initial velocity * time + (1/2) * acceleration * time^2

For car A:

The initial velocity is 0 m/s, and the acceleration is 4 m/s².

So, the distance covered by car A at time t is:

d¹(t) = 0.5 * 4 * t^2 = 2t^2

For car B:

The initial velocity is 0 m/s, and the acceleration is -2 m/s² (opposite direction to car A).

So, the distance covered by car B at time t is:

d²(t) = 0.5 * -2 * t^2 = -t^2

2. Deducing the time of meeting for the two cars:

To find the time of meeting, we need to set the distances covered by both cars equal to each other:

2t^2 = -t^2

Simplifying the equation:

2t^2 + t^2 = 0

3t^2 = 0

Since the equation equals zero, the only solution is t = 0. This means that the two cars meet at the starting point at t = 0.

3. Considering car B in uniform rectilinear motion with a speed of 10 m/s:

If car B is moving at a constant speed of 10 m/s, it means its acceleration is 0 m/s². Therefore, the equation for car B's distance covered becomes:

d²(t) = initial velocity * time = 10 * t = 10t

Now, we can answer the preceding questions using this new equation for car B.

1. The distance covered by car A at time t is still d¹(t) = 2t^2.

The distance covered by car B at time t is now d²(t) = 10t.

2. The time of meeting for the two cars can be found by setting the distances equal to each other:

2t^2 = 10t

Simplifying the equation:

2t^2 - 10t = 0

2t(t - 5) = 0

From this equation, we have two solutions:

t = 0 (the initial meeting point)

t = 5 seconds (when the two cars meet again after 5 seconds)

Therefore, the cars meet again after 5 seconds.

Please note that the distances calculated above are in terms of t, the time elapsed since t = 0.

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Answer:

The two moments must be the same:

p1=p2

m1v1=m2v2

v2=(m1v1)/m2

v2=(90 kg x 0.9 m/s)/110kg=0.7 m/s

Answer:

The two answers that are likely to be true are:

She will think of the results as an opportunity to find joy.

She will identify areas for self-development in her results.

By setting her mind on growth, Jackie is likely to approach the personality test with a positive and open mindset. This can lead to the following outcomes:

She will think of the results as an opportunity to find joy: Jackie may view the test results as a chance to discover aspects of her personality that bring her joy and satisfaction. She might focus on finding strengths and positive qualities that can contribute to her personal and professional growth.

She will identify areas for self-development in her results: Rather than viewing the test results as fixed labels or limitations, Jackie is likely to see them as valuable feedback for self-improvement. She may actively seek out areas where she can further develop her skills, knowledge, and personality traits to enhance her personal and career growth.

It's important to note that the other options listed in the question (1. She will score high in the areas she chooses to and 2. She will respond based on what's best in her desired career path) are not directly related to having a growth mindset. They suggest a more biased or strategic approach to the test, which may not align with the concept of growth and self-improvement.