A 7. 15L balloon filled with gas is warmed from 256. 1K to 297. 1 K. What is the volume of the gas after it is heated?

2.7g is the mass of zinc chloride is produced if If 1.92 grams of zinc react  with hydrochloric acid.

The name zinc chloride refers to inorganic chemical compounds having the formula  ZnCl\(_2\) and their hydrates. Zinc chlorides, which exist in nine crystalline forms, are colorless and white and very soluble in water.

This salt is both hygroscopic and deliquescent. Zinc chloride is widely used in textile manufacturing, metallurgical fluxes, as well as chemical synthesis.

Zn + 2HCl → ZnCl\(_2\) + H\(_2\)

moles of zinc= mass/molar mass

                    =  1.92/ 65.3

                   =0.02moles

the mole ratio between zinc and  ZnCl\(_2\) is 1:1

moles of ZnCl\(_2\) =0.02moles

mass = 0.02×136.3=2.7g

Therefore, 2.7g is the mass of zinc chloride is produced.

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At an elevation of 12,000 feet, the proportion of oxygen in the air is calculated to be approximately 10.3%.

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each individual gas in the mixture. Using this law, we can calculate the proportion of oxygen in the air at an elevation of 12,000 feet, given that the atmospheric pressure is 500 mmHg and that oxygen molecules form 20.9% of the gas mixture at sea level with a partial pressure of 160 mmHg.

To do this, we can use the following formula:

Partial pressure of O2 at high altitude / Total pressure at high altitude = Partial pressure of O2 at sea level / Total pressure at sea level

Plugging in the values we know, we get:

Partial pressure of O2 at high altitude / 500 mmHg = 160 mmHg / 760 mmHg

Solving for the partial pressure of O2 at high altitude, we get:

Partial pressure of O2 at high altitude = (500 mmHg x 160 mmHg) / 760 mmHg = 105.26 mmHg

To find the proportion of oxygen in the air at high altitude, we can use the formula:

Proportion of O2 at high altitude = Partial pressure of O2 at high altitude / Total pressure at high altitude

Plugging in the values we know, we get:

Proportion of O2 at high altitude = 105.26 mmHg / 500 mmHg = 0.21

Therefore, at an elevation of 12,000 feet, the proportion of oxygen in the air is approximately 21%.

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If Half- life of an isotope is 30 days and it was assumed that the person ate 100 Bq of isotope, there are 50 transformations in the stomach.

The radioactive decay of a sample of an isotope can be characterized by the half-life of that isotope. When a radioisotope undergoes decay, its nucleus becomes unstable, and it emits particles or energy to become more stable. The half-life of an isotope is the time it takes for half of the original sample to decay. The question states that the half-life of an isotope is 30 days, and the person ingested 100 Bq of isotope. It also says to calculate the number of transformations in the stomach using GI track model information .

Since the isotope has a half-life of 30 days, we can use the following formula to find the number of transformations in the stomach:` N = N₀ (1/2)^(t/T₁/₂)`where: N₀ = initial number of nuclei N = final number of nuclei (after time t)T₁/₂ = half-life of the isotope The isotope has a half-life of 30 days, so T₁/₂ = 30 days. The question doesn't specify how long the person has had the isotope in their stomach, so we'll assume it's been there for one half-life, or 30 days. Therefore, t = 30 days.

Substituting into the formula:` N = 100 (1/2)^(30/30)`Simplifying:` N = 100 (1/2)^1`Evaluating:`N = 50`So after 30 days in the stomach, the person would have 50 Bq of the isotope left. Therefore, the number of transformations in the stomach is the difference between the initial number of transformations (100 Bq) and the final number of transformations (50 Bq):`Number of transformations in stomach = 100 - 50 = 50 transformations. Therefore, there are 50 transformations in the stomach.

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Answer:

they both revolve or rotate around something

Explanation:

The earth revolves around the sun and the moon rotates around the earth.

Answer:

The negative charge (fewer protons than electrons) for an anion is shown by a number and minus sign after the formula. If there's just a minus sign, it means the charge is minus 1. Here are several examples of anions: If an ion consists of two or more atoms it is called a polyatomic ion.

Explanation:

Answer: I think it’s A, positive charge

Explanation:

Answer:

the difference is  the presence of a carbon atom

Explanation:

So

Now total enthalpy:-

The AH value when the bonds in 0.5 mole of HI are broken is: AH = 295 kJ - 293.5 kJ = 1.5 kJ

To calculate the AH value for breaking the bonds in 0.5 mole of HI, we need to use the following formula:

AH = total bond enthalpy of bonds broken - total bond enthalpy of bonds formed

The balanced chemical equation for the reaction of 0.5 mole of HI is:

HI (g) → 1/2 H2 (g) + 1/2 \(I_{2}\)(g)

In this equation, one H-I bond is broken and two new bonds (H-H and I-I) are formed.

The total bond enthalpy of bonds broken is:

1 x 295 kJ/mol = 295 kJ

The total bond enthalpy of bonds formed is:

(1/2) x 436 kJ/mol + (1/2) x 151 kJ/mol = 293.5 kJ

Therefore, the AH value when the bonds in 0.5 mole of HI are broken is:

AH = 295 kJ - 293.5 kJ = 1.5 kJ

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After 7.5 days, only about 2.64 mg of the original 16.0 mg Ni-57 sample remains due to its 36.0-hour half-life.

The half-life of Ni-57 is given as 36.0 hours, which means that every 36.0 hours, half of the sample decays. We need to calculate the number of half-lives that occur in 7.5 days.

There are 24 hours in a day, so 7.5 days is equal to 7.5 * 24 = 180 hours. To determine the number of half-lives, we divide the total time (180 hours) by the half-life (36.0 hours):

Number of half-lives = 180 hours / 36.0 hours = 5

Therefore, after 7.5 days, the original sample of 16.0 mg will have undergone 5 half-lives. With each half-life, the amount remaining is halved. So, after the first half-life, the sample will be reduced to 8.0 mg, then to 4.0 mg after the second half-life, and so on.

After 5 half-lives, the remaining fraction of the original sample is (1/2)^5 = 1/32. To find the remaining amount in milligrams, we multiply this fraction by the initial sample size:

Remaining amount = (1/32) * 16.0 mg = 0.5 mg

Therefore, after 7.5 days, approximately 0.5 mg of the Ni-57 sample remains.

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Answer:

The element is Phosphorus

Explanation:

Answer:

I do not know. I think there is .as we are the living creatures in this earth. maybe aliens are creatures of other planet or galaxies. I am not scientists to prove it.sorry.

Answer:

pure substance

Explanation:

Answer:

1. Combination (Synthesis) reaction

A + B → AB

2. Decomposition reaction

AB → A + B

3. Displacement reaction

A + BC → AB + C

4. Double displacement reaction

AB + CD → AD + BC

5. Combustion reaction

\(CH_{4} + 20_{2} → CO_{2} 2Hx_{2} O\)

A combination reaction, also known as a synthesis reaction, is a reaction in which two or more substances combine to form a single new substance. Combination reactions can also be called synthesis reactions.

A decomposition reaction is a reaction in which a compound breaks down into two or more simpler substances.

A single-replacement reaction is a reaction in which one element replaces a similar element in a compound.

A double-replacement reaction is a reaction in which the positive and negative ions of two ionic compounds exchange places to form two new compounds.

A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve  O2 as one reactant. The combustion of hydrogen gas produces water vapor

Explanation: Hope this helps and good luck :))

The molar solubility of C2D3 is calculated to be equal to 9.67 x 10^-3 mol/L .

The solubility of a substance is measured by the number of moles of the solute that dissolve in one liter of solution, or molar solubility. The quantity of ions dissolved per liter of solution is measured by molar solubility. In this case, solubility refers to how many ions can be dissolved in a specific volume of solvent.

As, C2D3 = (2x)^2 * (3x)^3= 108 x^5

Given, solubility product constant - 9.14×10−9

SO, 9.14 x 10^-9 = 108 x^5

Now, x = 9.67 x 10^-3

Hence,  the molar solubility is 9.67 x 10^-3 mol/L.

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Answer:

Well what I found was that this was this answer  

Explanation:

A mole is 6.022 x 1023 objects of any kind - atoms, electrons, molecules, cars, people, etc... . It is known as Avogadro's number after the scientist who discovered ... Blah blah I think you get it.  

Strong heating has no effect on this substance. Long-term storage at room temperature is possible, but it must be kept dry because it interacts fast with moisture and water in the air.

On a large scale, it can be produced via the reaction of silicon or silicon carbide with iodine when heated to roughly 200 °C. The interaction of silane with iodine vapor at temperatures between 130 and 150 °C is of more academic interest because a variety of compounds, including iodosilane SiH3I, diiodosilane SiH2I2, and triiodosilane SiHI3, are produced. The liquid forms of these compounds are colorless at normal temperatures. [3] Iodoform, a related carbon compound that is a yellow solid at ambient temperature, can be easily separated from the final one.

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Answer: The two categories is porous evidence and nonporous evidence. Nonporous item of evidence is when you put the latent print on the surface and it just sits on the surface. Porous item of evidence is when you put the latent print on the surface and it absorbs the latent print deposit.

After 3 half-lives, approximately 12.5% of element X would be remaining.

To determine the percentage of element X remaining after 3 half-lives, we can follow these steps:
1. Identify the half-life of element X: 2 million years.
2. Determine the number of half-lives that have passed: 3 half-lives.
3. Calculate the remaining percentage using the formula: remaining percentage = (1/2)^number of half-lives * 100%.
So, after 3 half-lives, the percentage of element X remaining would be:
Remaining percentage = (1/2)^3 * 100% = (1/8) * 100% ≈ 12.5%.
Therefore, after 3 half-lives, approximately 12.5% of element X would be remaining.

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Depending on the antifreeze solution's content, 2100 g of water needs 20 g of ethylene glycol to freeze at a lower temperature. Because ethylene glycol is hygroscopic—it collects water from the air—the amount of antifreeze needed to attain a certain freezing point will vary based on the relative humidity of the surrounding area.

Typically, a 40% antifreeze solution is utilised, which implies that 60% of the solution is water and 40% of the solution is ethylene glycol. This data may be used to determine how much ethylene glycol is needed.

Ethylene glycol is needed in amounts equivalent to 40% of the total solution in a 40% solution, or 0.4 x 2100 g = 840 g of ethylene glycol. Therefore, 840 g is required to lower the antifreeze solution.

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The mass of (NH4) 2S in the solution is : Mass = 0.0600 mol × 60.08 g/mol = 3.60 g.

The given molarity and volume of the solution can be used to calculate the number of moles of ammonium sulfide (NH4)2S.Then, the number of moles can be converted to mass using the molar mass of (NH4)2S.Mass of ammonium sulfide (NH4)2S in 3.00 L of a 0.0200 M solution is given by : Mass = moles × molar mass.The number of moles of (NH4)2S can be found using the equation:Molarity = Number of moles / Volume.Rearranging this equation, we get:Number of moles = Molarity × Volume Number of moles of (NH4)2S = 0.0200 M × 3.00 L.Number of moles of (NH4)2S = 0.0600 mol.The molar mass of (NH4)2S can be calculated by summing the molar masses of ammonium (NH4) and sulfide (S) ions.Molar mass of (NH4)2S = (2 × Molar mass of NH4) + Molar mass of S= (2 × 14.01 g/mol) + 32.06 g/mol= 60.08 g/mol.

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It might directly convert into a photoelectric effect like a solar panel. Alternatively, it may be transformed first into mechanical energy, as in boiling a working fluid and powering a turbine, or it could be transformed into chemical energy, as in photosynthesis, which grows trees and then burns the wood to power a steam engine and generator.

Electrons are released when a material is exposed to electromagnetic radiation, such as light, known as the photoelectric effect. These electrons are referred to as photoelectrons. To derive conclusions regarding the properties of atoms, molecules, and solids, the phenomena are researched in condensed matter physics, solid state chemistry, and quantum chemistry. Electronic devices designed for light sensing and precisely timed electron emission have found usage for the effect.

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Aluminum reacts with a certain nonmetallic element to form a compound with the general formula Alx. element x is a diatomic gas at room temperature. element x must be nitrogen.

Natural substances known as non-metals are fragile and don't produce electricity or heat . The non-metallic elements in the periodic table seem to be hydrogen, carbon, nitrogen, oxygen, phosphorus, arsenic, as well as selenium.

Alx → \(Al^{3+}\) + \(X^{3-}\)

AlN →  \(Al^{3+}\)  + \(N^{3-}\)

Non-metals have substances that are lackluster, sonority, ductility, and malleability, and are poor conductors of heat as well as electricity. They are soft and dull in appearance.

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Aluminum reacts with a certain nonmetallic element to form a compound with the general formula alx. element x is a diatomic gas at room temperature. element x must be ________.

(a) Nitrogen,

(b) Sulfur

(c) Bromine

(d) oxygen

The chemical name of the aspirin is acetylsalicylic acid.                

It is a commonly used medication that belongs to a class of drugs called nonsteroidal anti-inflammatory drugs (NSAIDs). Aspirin is primarily used for pain relief, reducing inflammation, and reducing fever. It works by inhibiting the production of prostaglandins, which are involved in the body's inflammatory response.    

Aspirin is available over-the-counter in various doses and is used to treat a variety of conditions, including headache, menstrual cramps, arthritis, and cardiovascular disease. Aspirin works by inhibiting the production of prostaglandins, which are involved in the body's inflammatory response.

Aspirin is also used as a blood thinner to reduce the risk of blood clots that can lead to heart attack or stroke. However, it should be used with caution in some individuals, such as those with a history of stomach ulcers or bleeding disorders, and under the guidance of a healthcare provider.      

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Find the number of moles in each reactant in the formula CO + 2 H2 CH3OH.

= 174371 g = 174.4 kg.

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Therefore, the original volume of the balloon was 939 m³.

Volume is a measure of the amount of space occupied by a three-dimensional object or substance. It is a physical quantity that can be described as the amount of space that an object or substance takes up in three dimensions, which can be measured in cubic units such as cubic meters, cubic feet, or liters. In mathematical terms, the volume of an object is calculated by multiplying its length, width, and height together. For example, the volume of a rectangular box with length L, width W, and height H can be calculated as V = L x W x H.

Here,

To solve this problem, we can use the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the gas constant, and T is the temperature of the gas in Kelvin.

We can use the ideal gas law to solve for the original volume of the balloon, assuming that the number of moles of gas and the gas constant remain constant.

First, we need to convert the temperatures to Kelvin:

20°C + 273.15 = 293.15 K (initial temperature)

-56°C + 273.15 = 217.15 K (final temperature)

Next, we can use the ideal gas law to solve for the number of moles of gas in the balloon at the initial conditions:

n = PV/RT

n = (101 kPa)*(V)/(8.31 J/mol·K)*(293.15 K)

Simplifying:

n = 0.00407V

We can use this expression to solve for the initial volume of the balloon, since we know that the final volume is 35.4 m³ and the pressure, temperature, and number of moles of gas are all constant:

n = (11.7 kPa)*(35.4 m³)/(8.31 J/mol·K)*(217.15 K)

Simplifying:

n = 0.00407V

Solving for V, we get:

V = n(8.31 J/mol·K)*(293.15 K)/(101 kPa)

V = 939 m³

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Answer: the answer is a=10m/s^2 right

Explanation: it just make more since then the other answers .

Answer:

c 10

Explanation:

ape.x verified

Answer:

C - 2 e- → C

Explanation:

2 NaHCO3 → 2 Na + H2O + -1 CO + 3 CO2

2 NaI + 2 e- → 2 Na0

C - 2e - C

The addition of solute molecules can lead to a decrease in the rates of both evaporation and condensation.

How does the solute affect the rate of various reactions?

1. Evaporation: The addition of solute molecules to a solvent reduces the rate of evaporation. This is because solute molecules occupy spaces at the liquid surface and decrease the surface area available for solvent molecules to escape into the vapor phase. Additionally, solute-solvent interactions can lower the kinetic energy of the solvent molecules, making it harder for them to overcome the attractive forces and evaporate.

2. Condensation: The presence of solute molecules can also affect the rate of condensation. The solute molecules in the solution occupy space, reducing the amount of space available for vapor molecules to condense back into the liquid phase. As a result, the condensation rate might be reduced.

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The final electron acceptor in aerobic respiration is oxygen (O2).The electron transport chain (ETC) in cellular respiration relies on a final electron acceptor to help oxygen get reduced into water. This is why oxygen is considered the final electron acceptor in cellular respiration.

During cellular respiration, glucose is broken down into pyruvate. Pyruvate is then transformed into acetyl CoA and enters the citric acid cycle, where it is oxidized and generates ATP, NADH, and FADH2. The final stage of aerobic respiration involves the electron transport chain, in which electrons from NADH and FADH2 are passed through a series of proteins and coenzymes in the inner mitochondrial membrane, ultimately reducing oxygen to form water.

This process is known as oxidative phosphorylation.In conclusion, the final electron acceptor in aerobic respiration is oxygen (O2), and carbon dioxide is generated in the link reaction (pyruvate oxidation) and the citric acid cycle.

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Answer:

an agent that helps accept electrons on others like oxygen, halogens

Explanation:

a substance that tends to bring about oxidation by being reduced and gaining electrons.

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The volume of a gas that initial occupies 1.56 L at 101.3 KPa is 3.47L.

The volume of a gas at a given pressure can be calculated using Boyle's law equation as follows:

P1V1 = P2V2

Where;

According to this question, a gas occupies 1.56 L at 101.3 kpa, the volume of this gas if the pressure becomes 45.5kpa can be calculated as follows:

101.3 × 1.56 = 45.5 × V2

158.028 = 45.5V2

V2 = 3.47L

Therefore, the volume of a gas that initial occupies 1.56 L at 101.3 KPa is 3.47L.

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