A 87 kg weight-watcher wishes to climb a

mountain to work off the equivalent of a large

piece of chocolate cake rated at 948 (food)

Calories. How high must the person climb? The

acceleration due to gravity is 9. 8 m/s

2

and 1

food Calorie is 103

calories. Answer in units of km

The concentration of the acute leukemia cc95 combination value in micromolar (μm) units is  6 × 10-4 μM.

Acute lymphocytic leukemia (ALL) is also called acute lymphoblastic leukemia. “Acute” means that the leukemia can progress quickly, and if not treated, would probably be fatal within a few months. "Lymphocytic" means it develops from early (immature) forms of lymphocytes, a type of white blood cell.

A rapidly progressing cancer that starts in blood-forming tissue such as the bone marrow, and causes large numbers of white blood cells to be produced and enter the blood stream.

In acute leukemia, the abnormal blood cells are immature blood cells (blasts). They can't carry out their normal functions, and they multiply rapidly, so the disease worsens quickly. Acute leukemia requires aggressive, timely treatment.

This corresponds to 0.6 × 10^-9 M × (1 μM/1 × 10^-6 M) = 0.6 × 10^-3 μM = 6 × 10-4 μM.

Acute myeloid leukemia (AML) is caused by a DNA mutation in the stem cells in your bone marrow that produce red blood cells, platelets and infection-fighting white blood cells. The mutation causes the stem cells to produce many more white blood cells than are needed.

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The time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.

In rock, S waves generally travel about 60% the speed of P waves, and the S wave always arrives after the P wave.

v ∝ 1/t

v₁t₁ = v₂t₂

t₁/t₂ = v₂/v₁

t₁/t₂ = 0.6v₁/v₁

t₁/t₂ =  0.6

t₁ = 0.6t₂

t₁ = 0.6 x 22 mins

t₁ = 13.2 mins

Thus, the time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.

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Answer:

Explanation:

Given:

r = 5·10⁻⁵ m

q₁ = q₂ = | 1.602·10⁻¹⁹ | C - electron charge modulus

k = 8.99·10⁹  m² / C₂  -   the Coulomb’s constant

_______________

F - ? - electron repulsion force

According to Coulomb's law:

F = k·q² / r²

F = 8.99·10⁹·(1.602·10⁻¹⁹)² / (5·10⁻⁵)² ≈ 9,23·10⁻²⁰  N

The weight of the same object on a planet where gravitational attraction is mg /10.

Force = mg

On Earth weight = force = mg where g = acceleration of gravity

But according to your question

On a planet with gravity 1/10 of the earth is

Weight = force = mg /10.

On the Moon, gravity pulls less on objects so they weigh less. For example, a rock that weighs 1 pound weighs less on Earth than it does on the Moon. Weight is the result of the law of universal gravitation. Any two objects are attracted to each other by their masses with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The mass remains the same and the weight decreases on the moon. When flying to the moon the gravitational acceleration is less than the gravitational acceleration. That's about one-sixth of the acceleration due to gravity. If gravity is halved, atmospheric pressure is halved. This equates to climbing above 5,000 meters. This means that all humans will struggle to breathe enough oxygen, more than they can live on forever.

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To express the angular velocity in deg/min, we need to convert the revolutions per minute to degrees per minute. One revolution is equivalent to 360 degrees, so the second hand moves at a rate of 360 degrees per minute. Therefore, the angular velocity in deg/min would be 360 deg/min.

The angular velocity of the second hand on a clock can be expressed in two different units: revolutions per hour (rev/hr) and degrees per minute (deg/min).
To calculate the angular velocity in rev/hr, we need to know the number of revolutions made by the second hand in one hour. Since the second hand completes one full revolution every 60 seconds, it will complete 60*60 = 3600 revolutions in one hour. Therefore, the angular velocity in rev/hr would be 3600 rev/hr.
In summary, the angular velocity of the second hand on a clock can be expressed as 3600 rev/hr or 360 deg/min. This information is useful for understanding how quickly the second hand is rotating and can be used in calculations involving the motion of the clock's hands.

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Answer:

The SI unit of electric charge is the coulomb and is represented by the symbol C.

\( \large\sf \leadsto\pmb{ Symbol \: Unit \: For \: Electric \: Charge}\)

\( \sf \blue {The \: SI \: unit \: of \: electric \: charge \: is \: coulomb \: which \: is \: also \: represented \: as \: C!}\)

Answer:

Below

Explanation:

Work = F x d  = 120 N * 8 m = 960 Joules

Power = work / time = 960 J / 30 s = 32 watts

Important Formulas:

\(w=Fd\)

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

\(p=\dfrac{w}{t}\)

power(measured in watts) = work(measured in joules) / time(measured in seconds)

__________________________________________________________

Given:

\(F=120N\)

\(d=8m\)

\(t=30s\)

\(p=?\)

__________________________________________________________

Finding work:

\(w=Fd\)

\(w=120\times8\)

\(w=960J\)

__________________________________________________________

Finding power:

\(p=\dfrac{w}{t}\)

\(p=\dfrac{960}{30}\)

__________________________________________________________

Answer:

\(\fbox{p = 32 Watts}\)

Answer:

distance- I think it is 6 then the displacement is 13.41

Explanation:

neither, a shadow cant be darker unless your closer to the surface your pointing the light at.

Answer:

0.66 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0

Final velocity (v) = 5.4 m/s

Time (t) = 8.2 secs

Acceleration (a) =....?

The acceleration of the dog can be obtained as follow:

v = u + at

5.4 = 0 + a × 8.2

5.4 = 8.2a

Divide both side 8.2

a = 5.4/8.2

a = 0.66 m/s²

Therefore, the acceleration of the dog is 0.66 m/s².

Answer:

using the pressure of stump

Answer: Using the pressure of a stump

The potential difference across a 15-mm-long, 2.0-mm-diameter copper wire carrying a 7.4 A current is approximately 0.17 V.

Given data: Length of the copper wire, l = 15 mm = 0.015 m Diameter of the copper wire, d = 2.0 mm = 0.002 m Current flowing in the copper wire, I = 7.4 A Potential difference across the copper wire can be calculated by using the formula;

V = (π / 4) × d² × ρ × I / l

Where, V = Potential difference across the copper wireρ = Resistivity of the copper wire. To find the potential difference across a 15-mm-long, 2.0-mm-diameter copper wire carrying a 7.4 A current, we need to calculate the resistivity of copper. Resistivity is a physical quantity that describes how strongly a material opposes the flow of electric current. The symbol for resistivity is the Greek letter rho (ρ). The resistivity of copper is 1.7 x 10⁻⁸ Ωm.

Now we will substitute the given values and calculate the potential difference across the copper wire: V = (π / 4) × d² × ρ × I / l V = (π / 4) × (0.002 m)² × (1.7 x 10⁻⁸ Ωm) × (7.4 A) / (0.015 m)V ≈ 0.17 V Therefore, the potential difference across a 15-mm-long, 2.0-mm-diameter copper wire carrying a 7.4 A current is approximately 0.17 V.

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Answer:

A pair of scales

Explanation:

The energy separation between adjacent quantum states is equal to the energy of the harmonic oscillator, which is 3.5 eV. Thus, the energy difference between adjacent states is 3.5 eV.

The energy separation between adjacent quantum states of a harmonic oscillator (or any quantum system) is called energy spacing. This energy spacing is equal to the difference between the energy of the higher energy state and the energy of the lower energy state.

This can be calculated using the formula En=(n+1/2)hw. For the ground state (n=0), the energy is En=hw/2. Since hw=3.5 eV, En=3.5 eV/2=1.75 eV. Thus, the energy difference between adjacent states is 3.5 eV.

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Answer:

D

Explanation:

It says constant positive linear acceleration, which means that the velocity increases at a constant rate.

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 8 × 2

We have the final answer as

Hope this helps you

Answer:

55.56%

Explanation:

We'll begin by calculating the work done in pushing the wedge. This can be obtained as follow:

Force (F) = 900 N

Distance (s) = 0.1 m

Workdone (Wd) =..?

Wd = F × s

Wd = 900 × 0.1

Wd = 90 J

Finally, we shall determine the efficiency. This can be obtained as follow:

Work output = 50 J

Work input = 90 J

Efficiency =?

Efficiency = work output / work input

Efficiency = 50 / 90 × 100

Efficiency = 55.56%

Thus, the efficiency is 55.56%

The formula remains \(CuCO_{3}\) since atoms must combine in simple whole number ratios.

We know that according to the Dalton atomic theory, when atoms, combine, they do so in simple whole number ratios. Thus the combination of the atoms can not be fractional. This is the first thing that we must have in mind as we discuss this given issue.

Even if we have 5.3 parts copper to 4 parts oxygen to 1 part carbon, we have to ensure that a whole number ratio is maintained in the formula of the compound thus the formula remains \(CuCO_{3}\).

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Answer:

B. Electrical energy transforms into mechanical energy.

Explanation:

In the case when the wire loop transforms between the two permanent magnets in a generator so here the electrical energy turns to mechanical energy as there is a working principle behind the generator that the electrical energy would turns into mechanical energy

Therefore as per the given scenario, the option b is correct

And, the rest of the options are wrong

Jaipal can calculate for the voltage (V) in the circuit

Ohm's laws states as follow:

V = IR

Where:

V is the voltage (unit V)

I is the current (unit A)

R. Is the resistance (unit ohm)

Current (I) = 1.2 A

Resistance (R) = 24 ohms

From the above we can see that the voltage is missing.

Thus, using ohm's law, Jaipal can calculate for the voltage (V) in the circuit

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Jaipal can calculate the Voltage in the circuit from the current and resistance he measured.

The given parameters:

According to Ohms law, the voltage across a conductor is directly proportional to the current flowing the conductor.

V = IR

where;

V = 1.2 x 24

V = 28.8 V

Thus, Jaipal can calculate the Voltage in the circuit from the current and resistance he measured.

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Answer:

0.125

Explanation:

acellus

Circumpolar stars, such as those in the Big and Little Dippers in the northern hemisphere, are stars that completely circle a celestial pole. They don't set; they just hang out in the night sky.

The stars known as circumpolar stars never set below the horizon. (The horizon is the line that marks the boundary between the sky and the ground.) While circumpolar stars appear to revolve around the South Star or Sigma Octantis in the Southern Hemisphere, the North Star or Polaris, in the Northern Hemisphere. A circumpolar star is one that appears to be close to one of the celestial poles and never sets below the horizon when seen from a particular latitude on Earth. The celestial equator is not far from these stars.Their name derives from the celestial pole around which they revolve. The northern celestial pole star in the northern hemisphere is Polaris. These stars can be found close to the celestial pole.

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The resistors are connected in parallel between the terminals of a battery.

Note: If those resistors are connected in parallel, then their equivalent resistance is already 5 ohms, even if they're still in the drawer or in a box on the shelf. They don't have to be connected to a source of voltage for that to happen.

Answer:

Give me some time okkkk

Answer:

a)the process by which heat or electricity is directly transmitted through the material of a substance when there is a difference of temperature

b)the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat

c)radiation is the emission or transmission of energy in the form of waves or particles through space or through a material medium.

The velocity of the fourth piece after the explosion is 118.5 m/s at 14.7⁰ east of north.

The principle of conservation of linear momentum states that the sum of the initial momentum is equal to sum of final momentum.

Initial momentum of the bomb before explosion is equal to the final momentum of pieces of bomb after explosion.

Pi = Pf

0 = P₁ + P₂ + P₃ + P₄

0 = mv₁ + mv₂ + mv₃ + mv₄

0 = v₁ + v₂ + v₃ + v₄

Consider x-y plane for the velocity of the piece of bomb;

\(0 = (v_1x + v_1y) + (v_2x + v_2_y) + (v_3x + v_3_y) + (v_4_x + v_4_y)\\\\0 = (0 - 50y) + (-80x + 0) + (-40cos30x + 40sin30y) + (v_4_x + v_4_y)\\\\0 = -50y -80x - 34.64x + 20y + v_4_x + v_4_y\\\\0 = -30y - 114.64x + v_4_x + v_4_y \\\\v_4_x + v_4_y = 114.64x + 30y\\\\|v_4| = \sqrt{114.64^2 + 30^2} \\\\|v_4| = 118.5 \ m/s\\\\tan(\theta ) = \frac{30}{114.64} \\\\tan(\theta) = 0.262\\\\\theta = tan^{-1} (0.262)\\\\\theta= 14.7 \ ^0\)

Thus, the velocity of the fourth piece is 118.5 m/s at 14.7⁰ east of north.

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The most comprehensive variety of oscilloscope software for applications-specific debugging, compliance, and debugging is provided by Keysight.

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The self inductance can be calculated as 4.444 Henry.

The inductor will store energy = 20 joule,

current = 3 ampere.

     The current carrying conductor which allows or opposes the change of flow of current is known as self-inductance. The rate of change of current can also be given through self inductance.

Formula can be given  for the energy in the inductor as,

                      E = 1 / 2 × L × I² joule.

where as,    E - Energy

                    L - Inductance

                    I - Current flowing through the coil.

The equation can be rearranged as,

                      L =  2 E/ I²

                         =  2 × 20 / 3²

                         =  40 / 9

Hence,           L =  4.4444 Henry

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Answer:

Space Launch System (SLS)

Explanation:

Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.

-TheUnknownScientist 72

Most phospholipids in a membrane have two fatty acid tails but some have three. In reality, all phospholipids in the membrane have two fatty acid tails, which are hydrophobic and nonpolar, and a polar phosphate head, which is hydrophilic.

The incorrect comment about the phospholipid bilayer is Most phospholipids in a membrane have two fatty acid tails but some have three.

This unique structure of phospholipids allows them to spontaneously arrange themselves in a bilayer with the hydrophilic heads facing the aqueous cytosol and the hydrophobic tails oriented toward the center of the membrane. This arrangement provides a stable barrier that separates the intracellular environment from the extracellular environment, while allowing for the selective transport of molecules across the membrane. As for the other comments in the list, they are all correct. Phospholipids can move laterally from one layer to another in the membrane when the temperature changes, which affects the fluidity of the membrane. The fatty acid chains are indeed sequestered to the center of the bilayer, and the phosphate region of a phospholipid is more likely to form hydrogen bonds than the fatty acid tail region.

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