A bakery sells 10 types of pies: apple, cherry, blueberry, strawberry, peach, key lime, pumpkin, sweet potato, pecan, and chocolate. Assume that it has an unlimited supply of each type. How many different ways are there to choose 6 pies from these 10 types if... a. ...there are no restrictions? b. ...all the pies chosen are of the same type? C. ...all the pies chosen are of different types? d. ...at least 2 apple pies and 1 cherry pie are chosen? e....at most 3 key lime pies are chosen?

Answer:

\(\huge\boxed{\sf 6(x + 2)}\)

Step-by-step explanation:

= 2(5x + 3) - 2(2x - 3)

Expand

= 10x + 6 - 4x + 6

Combine like terms

= 10x - 4x + 6 + 6

Add or subtract as indicated

= 6x + 12

Take 6 common

= 6(x + 2)

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

72

Step-by-step explanation:

here's your solution

=> x= 8

=> y= -3

=> putting the value

=> 8*6 - (8*-3)

=> 48 + 24

=> 72

hope it helps

Hey there!

If x = 8 and y = -3, then SUBSTITUTE it into the equation

6(8) - 8(-3)

6(8) = 48

48 - 8(-3)

8(-3) = -24

48 - (-24)

- & - = +

48 + 24 = 72

Answer: 72

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Step-by-step explanation:

Multiply 20 by 12:

Multiply 240 by 5:

Multiply the lengths:

Answer:

The missing side is 5 cm

Step-by-step explanation:

Step 1:  Determine the missing side

\(V=l*w*h\)

\(1200\ cm^3 = 20\ cm * w * 12\ cm\)

\(\frac{1200\ cm^3}{20\ cm * 12\ cm} = w\)

\(\frac{1200\ cm^3}{240\ cm^2} = w\)

\(5\ cm = w\)

Answer: The missing side is 5 cm

The total number of cups of flour that Rebecca will need to bake three cakes is 369 cups of flour.

Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. For example, 3 × 4 means 3 is added to itself 4 times, and vice versa for the other number.

Given that the recipe for one cake calls for 123 cups of flour. Also, Rebecca needs to bake three cakes, therefore, the total number of cups of flour that Rebecca will need is,

Total number of cups of flour = Number of cakes ×  Number of cups of flour in a cake

                                                 = 3 cakes × 123 cups of flour per cake

                                                 = 369 cups of flour

Hence, the total number of cups of flour that Rebecca will need to bake three cakes is 369 cups of flour.

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Using the Lagrange multiplier method, the maximum values of x and y for the given function and constraint are x = 8 and y = 4.

To maximize the function f(x, y) = x^(1/2) * y^(1/2) subject to the constraint 2x + y = 20, we can employ the Lagrange multiplier method.

Set up the Lagrange function L(x, y, λ) = f(x, y) - λ(g(x, y)), where g(x, y) represents the constraint equation.

Differentiate L with respect to x, y, and λ, and set the partial derivatives equal to zero.

Solve the resulting system of equations to find critical points.

Evaluate the critical points and check the endpoints of the feasible region.

Determine the maximum values of x and y that maximize the function f(x, y) while satisfying the given constraint.

Applying these steps, we find that x = 8 and y = 4 maximize the function f(x, y) subject to the constraint. Thus, the maximum values of x and y are 8 and 4, respectively.

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We are given a set of vectors S and we need to determine whether each given vector can be written as a linear combination of the vectors in S.

(a) For vector (2, -1, -2), we need to check if there exist scalars k₁ and k₂ such that k₁(2, -1, 3) + k₂(5, 0, 4) = (2, -1, -2). By solving the system of equations, we find that k₁ = -1 and k₂ = 0, so the vector can be written as a linear combination of the vectors in S.

(b) For vector (8, -14, 27/4), we need to check if there exist scalars k₁ and k₂ such that k₁(2, -1, 3) + k₂(5, 0, 4) = (8, -14, 27/4). By solving the system of equations, we find that there are no solutions, so the vector cannot be written as a linear combination of the vectors in S.

(c) For vector (1, -8, 12), we need to check if there exist scalars k₁ and k₂ such that k₁(2, -1, 3) + k₂(5, 0, 4) = (1, -8, 12). By solving the system of equations, we find that there are no solutions, so the vector cannot be written as a linear combination of the vectors in S.

(d) For vector (1, 1, -1), we need to check if there exist scalars k₁ and k₂ such that k₁(2, -1, 3) + k₂(5, 0, 4) = (1, 1, -1). By solving the system of equations, we find that there are no solutions, so the vector cannot be written as a linear combination of the vectors in S.

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The best measure of center is the mean

The are 20 students represented by the whisker

The percentage of classrooms with 23 or more is 25%

The percentage of classrooms with 17 to 23 is 50%

From the question, we have the following parameters that can be used in our computation:

The box plot

There are no outlier on the boxplot

This means that the best measure of center is mean

Here, we calculate the range

So, we have

Range = 30 - 10

Evaluate

Range = 20

From the boxplot, we have

Third quartile = 23

This means that the percentage of classrooms with 23 or more is 25%

From the boxplot, we have

First quartile = 15

Third quartile = 23

This means that the percentage of classrooms with 17 to 23 is 50%

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Answer:

part c is the correct answer to this question

Answer:

3

Step-by-step explanation:

27 tickets = 9 prizes

Since they are all equal, it would be 27 divided by 9 = 3

The quality control manager at Sony uses systematic sampling to estimate the percentage of defects in a manufacturing batch of music CDs. Therefore, the quality control manager can estimate that approximately 20% of the entire manufacturing batch of music CDs may have defects based on the systematic sample she obtained.

Systematic sampling involves selecting items from a population at regular intervals. In this case, the quality control manager selects every 16th music CD starting from the ninth. This method ensures that every CD has an equal chance of being selected, providing a representative sample of the batch.

By using systematic sampling, the quality control manager obtains a sample of 140 music CDs. She can then examine these CDs to determine the number of defective ones. Let's assume she finds 28 defective CDs in the sample.

To estimate the percentage of defects in the manufacturing batch, the quality control manager can use the formula:

Defect percentage = (Number of defective CDs / Sample size) *100

Substituting the values, we have \((\frac{28}{140}) * 100 = 20%\).

Therefore, the quality control manager can estimate that approximately 20% of the entire manufacturing batch of music CDs may have defects based on the systematic sample she obtained. This estimation provides valuable information for assessing the quality of the batch and taking necessary actions for improvement.

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How likely something is to occur is known as its probability.Probability when die rolled 1st time is 6C1 i.e. (1,2,3,4,5,6).

How likely something is to occur is known as its probability.We can discuss the probabilities of various outcomes—how likely they are—when we aren't sure how a particular event will turn out. Statistics describes the examination of events subject to probability.

Probability when die rolled 1st time=6C1 i.e. (1,2,3,4,5,6) suppose 1 comes, then 2nd time it should not be .as it is given that no 2 people will roll same number.

so 2nd time probability=5C1 i.e. (2,3,4,5,6). same way 3rd and 4th time probability=4C1 and 3C1 respectively.Probability that no one rolls the same no. = 6*5*4*3and total possibility =6^4 

p(same number)= 6*5*4*3/ 6^4

= 5/18

p(no same number will roll)=1-5/18

=13/18

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The school cook has 10^20 ways to plan her schedule without restrictions, and if she wants to cook each meal the same number of times, she has a specific combination of 20 school days for each meal.

(a) To calculate the number of ways for the school cook to plan her schedule of menus for the 20 school days without any restrictions on the number of times she cooks a particular type of meal, we can use the concept of permutations.

Since she knows how to cook ten different meals, she has ten options for each of the 20 school days. Therefore, the total number of ways she can plan her schedule is calculated by finding the product of the number of options for each day:

Number of ways = 10 * 10 * 10 * ... * 10 (20 times)

= 10^20

Hence, there are 10^20 ways for her to plan her schedule of menus for the 20 school days without any restrictions on the number of times she cooks a particular type of meal.

(b) If the school cook wants to cook each meal the same number of times, she needs to distribute the 20 school days equally among the ten different meals.

To calculate the number of ways for her to plan her schedule under this constraint, we can use the concept of combinations. We need to determine the number of ways to select a certain number of school days for each meal from the total of 20 days.

Since she wants to cook each meal the same number of times, she needs to divide the 20 days equally among the ten meals. This means she will assign two days for each meal.

Using the combination formula, the number of ways to select two school days for each meal from the 20 days is:

Number of ways = C(20, 2) * C(18, 2) * C(16, 2) * ... * C(4, 2)

= (20! / (2!(20-2)!)) * (18! / (2!(18-2)!)) * (16! / (2!(16-2)!)) * ... * (4! / (2!(4-2)!))

Simplifying the expression gives us the final result.

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The lower cost will occur at the extreme point, that is if the number of videos rented daily is 8 pieces and the cost will be $550.

The cost function is given by:

C(x) = 2x² - 32x + 678

The lowest cost happens at the extreme point. In this point the derivative of C(x) is equal to zero.

Take the derivative:

C'(x) = 4x - 32 = 0

4x = 32

x = 32/4 = 8

Hence, the lowest cost will occur if the number of video rented daily is 8 pcs.

Substitute x = 8 into the cost function:

C(8) = 2(8)² - 32.(8) + 678 =  550

Complete question:

The owner of a video store has determined that the cost c, C(x) = 2x² - 32x + 678 in dollars, of operating the store is approximately given by where x is the number of videos rented daily. find the lowest cost to the nearest dollar

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The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y ⇒ last answer

Step-by-step explanation:

Let us revise the reflection across the y-axis , horizontal translation

and vertical translation

1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)

2. If point (x , y) is translated h units to the right, then its image is

  (x + h , y), if translated h units to the left, then its image is (x - h , y)

3. If point (x , y) is translated k units up, then its image is (x , y + k),

  if translated k units down, then its image is (x , y - k)

∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The x-coordinates of the vertices of Δ B'C'D' have the same

  magnitude of x-coordinates of Δ BCD and opposite signs

∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)

∵ The image of -1 is 5 and the image of -5 is 1

∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6

∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2

∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted

  by 5

∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right

 and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

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The composition of transformations that maps BCD to B"C"D" is described by the following rule:

Composition translation of 6 units x, negative 5 units y across the y-axis last response

Let us rewrite the y-axis reflection, horizontal translation, and vertical translation.

1. If point (x, y) is mirrored across the y-axis, the image of that point is (-x , y)

2. If point (x, y) is translated h units to the right, its image is (x + h, y), and if it is translated h units to the left, its image is (x + h, y) (x - h , y)

3. If point (x, y) is translated k units up, its image is (x, y + k), but if it is translated k units down, its image is (x , y - k)

∵ Triangle BCD has (1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. Triangle B'C'D' has (-1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. The x-coordinates of the B'C'D' vertices have the same magnitude as the x-coordinates of BCD and opposite signs. B'C'D' is the picture of ABC after it has been reflected across the y-axis.

The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3), (1, -2)

The vertices of triangle B"C"D" are (5, -1), (5, -3), (1, -2)

The x-coordinates of the triangle B'C'D' vertices are added by 6.

The image of 4 is -1, the image of 2 is -3, and the image of 3 is -2.

The y-coordinates of triangle B'C'D' vertices are subtracted by 5.

∴ Δ B"C"D" is the image of Δ B'C'D' by translating 6 units to the right

and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

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If a card is drawn from a standard deck and replaced. after the deck is shuffled, another card is pulled. Then the probability that the first card drawn is a heart and the second card is a spade is 1/16.

The probability of drawing a heart on the first card is 1/4 since there are 13 hearts out of a total of 52 cards in a standard deck.

After replacing the card and shuffling the deck, the probability of drawing a spade on the second card is also 1/4 since there are 13 spades out of a total of 52 cards in the deck (assuming the deck is well-shuffled).

To find the probability of both events happening (drawing a heart and then a spade), we multiply the individual probabilities together:

Probability = (1/4) * (1/4) = 1/16

Therefore, the probability that the first card drawn is a heart and the second card is a spade is 1/16.

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The Diwali occurred on 0.408 or 40.8% of the year in 2017.

To find the fraction of the year that Diwali occurred in 2017, we need to divide the number of days between Diwali and the start of the year by the total number of days in the year.

Diwali occurred on Thursday, October 19, 2017. The start of the year 2017 is January 1, 2017 which is a Sunday.

There are 365 days in a non-leap year. Since 2017 is not a leap year, there are 365 days in that year.

So the fraction of the year that Diwali occurred in 2017 can be calculated as: (days between Diwali and the start of the year) / (total days in the year) = ( 19 + 31 + 30 + 31 + 30 + 19 ) / 365 = (148) / 365 = 0.408

So, the Diwali occurred on 0.408 or 40.8% of the year in 2017.

Therefore, Diwali occurred on 0.408 or 40.8%

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A circle is a curve sketched out by a point moving in a plane. Except for the first statement both the second and the third statement is true.

A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the center.

The complete question is mentioned in the below image.

For the given circle,

The area of the sector is,

Area of sector = π(4)²×[2π/(3×2π)] = 16π/3

The area of the circle is,

Area of the circle = π×(4)² = 16π

The length of the Arc is,

Length of the arc = 2π×(4)×[2π/(3×2π)] = 8π/3

Hence, Except for the first statement both the second and the third statement is true.

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Desde el gráfico, se encuentra que hay una probabilidad de 9.9% que el primer usuario que responda la encuesta sea mujer de más de 44 años.

------------------------

De el gráfico, hay:

5.1% + 2.7% + 2.1% = 9.9%, puesto que:

Hay una probabilidad de 9.9% que el primer usuario que responda la encuesta sea mujer de más de 44 años.

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Permutation test is used to synthesize the population distribution of the statistic of interest for hypothesis testing of mean, median, and quartiles

An estimation of the population distribution—the distribution from which our observations originated—is the goal of a permutation test. We can then calculate how uncommon our observed values are in comparison to the population.

I find the permutation test to be more natural, and it only relies on the assumption of random assignment of treatment groups.

In a permutation test, you compare the observed test statistic to the distribution of values

you get when the treatment group assignments are shuffled/randomized/permuted.

The null hypothesis that two distinct groups originate from the same distribution is tested using permutation tests, also known as exact tests, randomization tests, or re-randomization tests. A permutation test can be used for hypothesis testing or significance testing (including A/B testing) without requiring any presumptions to be made about the distribution of the samples, such as that the samples must be normally distributed.

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Answer: 100

Step-by-step explanation:

Answer:

The square root of 10000 is 100

Step-by-step explanation:

The probability that you win a prize is 0.00003797372

Here, we have,

From the question, we have the following parameters:

Sample Space = 1 to 22

This means that

Sample size, n = 22 i.e. the count of numbers from 1 to 22

The count of numbers to be drawn is 5

So, the individual probabilities are

P(1) = 5/22

P(2) = 4/21

P(3) = 3/20

P(4) = 2/19

P(5) = 1/18

The probability of winning is the product of the above

So, we have

p = 5/22 * 4/21 * 3/20 * 2/19 * 1/18

Evaluate

p = 0.00003797372

Hence, the probability is 0.00003797372

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complete question:

In a certain state's lottery, 22 balls numbered 1 through 22 are placed in a machine and 5 of them are drawn at random. If the 5 numbers drawn match the numbers that a player had chosen, the player wins $30,000. In this lottery, THE ORDER THE NUMBERS ARE DRAWN DOES MATTER. Compute the probability that you win the prize if you purchase a single lottery ticket.

Answer:

The answer is 12 units

Step-by-step explanation:

The length of the radius is 12 units

The radius of a circle is a line drawn from the center of the circle to its circumference

The length (L) of the arc is given as:

\(L = 10\pi\)

The length of an arc is:

\(L = r\theta\)

So, we have:

\(r\theta =10\pi\)

The angle at the center of the circle is \(\frac{5\pi}{6}\)

So, we have:

\(r* \frac{5\pi}{6}=10\pi\)

Multiply both sides by 6

\(r* 5\pi=60\pi\)

Divide both sides by 5pi

\(r = 12\)

Hence, the length of the radius is 12 units

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Answer:

5 minus m ( variable)

Step-by-step explanation:

np

Answer:

the lines arent parallel, so you cant use corresponding angles theorem

The error is corresponding property does not apply.

Parallel lines are those lines that are equidistant from each other and never meet, no matter how much they may be extended in either directions. For example, the opposite sides of a rectangle represent parallel lines.

We know that when two lines are parallel they the following property:

As, there is no parallel lines line.

So, the measurement if <1 = 88 can't be true because corresponding doesn't apply.

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The 4P model of resisting corruption is a useful framework that can be utilized to combat corruption. It emphasizes the importance of prevention, punishment, promotion, and participation.

The 4P model is a method of combating corruption by focusing on becoming more aware of it. It is a framework that includes four elements:

Prevention, Punishment, Promotion, and Participation.

The first component of the 4P model is prevention, which entails identifying and eliminating the underlying causes of corruption. The objective is to minimize the opportunities for corruption and to promote ethical behavior.

This can be achieved through the establishment of strong policies and regulations, as well as the implementation of accountability mechanisms.

The second element of the 4P model is punishment. When corruption occurs, penalizing those who engage in it is critical to deter others from doing so. This entails implementing strict laws and regulations and ensuring that those caught face harsh consequences.

The third component of the 4P model is promotion. This element is all about promoting transparency and ethical conduct. The aim is to create a culture of integrity where people are encouraged to do the right thing and transparency is prioritized.

The 4P model of resisting corruption is a useful framework that can be utilized to combat corruption. It emphasizes the importance of prevention, punishment, promotion, and participation.

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Given:

Circumference of a circle = C

Diameter of a circle = d

To find:

The relationship between the circumference, c, and diameter, d, of any circle.

Solution:

We know that, circumference of a circle is

\(C=2\pi r\)

It can be written as

\(C=(2r)\pi \)

\(C=d\pi \)         \([\because d=2r]\)

On dividing both sides by d, we get

\(\dfrac{C}{d}=\pi \)

Therefore, the correct option is (F).

Answer:

Yes

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

When we plot (-2, -4) onto the graph, we can envision that the point is within the shaded region of the graphed line.

∴ (-2, -4) would be a solution.

We can determine if the process is in control by checking if any of the data points fall outside the control limits.

To construct a control chart for monitoring the proportion of incorrect forms, we will use the P chart because we are interested in monitoring the proportion of defects relative to the total number of forms processed.

To calculate the standard deviation of p (sigma_p) for the P chart, we can use the formula:

sigma_p = sqrt((p * (1 - p)) / n)

where:

p = average proportion of defective forms

n = number of forms processed

First, let's calculate the average proportion of defective forms (p):

p = Sum of incorrect forms / (200 * Number of days)

p = 143 / (200 * 10)

p ≈ 0.0715

Next, let's calculate sigma_p using the formula mentioned above:

sigma_p = sqrt((0.0715 * (1 - 0.0715)) / (200 * 10))

sigma_p ≈ 0.0093

For the P chart, the Upper Control Limit (UCL) is given by:

UCL = p + 3 * sigma_p

UCL ≈ 0.0715 + 3 * 0.0093

UCL ≈ 0.0994

The Lower Control Limit (LCL) for the P chart is typically set to zero since the proportion cannot be negative:

LCL = 0

Now, we can determine if the process is in control by checking if any of the data points fall outside the control limits.

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