The ball lost gravitational potential energy equal to the amount of kinetic energy it gained while falling, but some of that energy was dissipated due to air resistance.
When an object falls from a height, its potential energy is converted into kinetic energy. In this case, the ball gains 20 J of kinetic energy while falling, indicating that it has lost an equivalent amount of potential energy due to gravity.
However, the presence of air resistance complicates the situation. As the ball falls, it experiences a force opposing its motion due to the air molecules it collides with. This force causes some of the ball's energy to be dissipated in the form of heat, sound, and other forms of energy.
Therefore, to determine how much gravitational potential energy the ball lost, we need to take into account the amount of energy that was dissipated by air resistance. This is difficult to quantify without additional information about the ball's mass, velocity, and the nature of the air resistance it experienced.
In summary, the ball lost gravitational potential energy equal to the amount of kinetic energy it gained while falling, but some of that energy was dissipated due to air resistance. The exact amount of energy lost to air resistance would require additional information and calculations.
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Which type of stress causes fault-block mountains?
Answer:
tension
Explanation:
correct on edge
which is more important while hitting a home run a heavier bat or faster swing? why?
Answer:
Explanation:
the hitting should be in the almost top so the more faster and strong u hit more the ball more at top will go and more far will go
a 2.0-kg mass is attached to the end of a horizontal spring of spring constant 50 n/m and set into simple harmonic motion with an amplitude of 0.10 m. what is the total mechanical energy of this system?
Answer:
0.25 J
Explanation:
Why must the rockets use great force to get into outer space?
Imagine that instead of looking at ice in water, you were looking at a rock in magma, respectively. Assume that the rock solidified from the magma. What do you expect to happen next? To answer this question, you can think of the water in the glass as liquid magma, and the ice as a solid rock solidified from the magma.
A. The rock would sit in the magma at about the same proportional depth as the ice sits in the water.
B. The rock would rise up and extend higher above the magma as proportionally compared to the position of the ice in the water.
C. The rock would sink to the bottom of the magma.
c. The rock would fall to the magma's base.
This is due to the fact that rock generally has a density higher than the magma from which it crystallized.
The rock would sink to the bottom because it would be denser than the surrounding magma, much like how a solid ice cube descends to the bottom of a glass of water.
Why is it known as magma?When molten rock behaves similarly to a thick, pasty substance within the Earth, the word "magma" is derived from the Italian language. Another word for molten rock is lava, which is an Italian word that means to slide.Where does magma originate?Magma originates above the oceanic crust slab that is subducting, builds up at the bottom of the Earth's inflexible crust, and then gathers in a storage zone 13 km (8 mi) beneath the volcano before erupting.
Why does a magma form?Mantle rock melting causes magma to develop. The rocks begin to melt a little bit as they rise (or as water is added to them).
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A 100 kg physics teacher pushes a 1.0 kg physics textbook across a 222 kg physics demo table.
If the teacher needs to apply a force of 5.0 N to start the book sliding, what is the coefficient of static friction between the book and the table?
If the teacher needs to apply a force of 4.0 N to keep the book sliding at a constant 0.30 m/s across the table, what is the coefficient of kinetic friction between the book and the table?
If the teacher then stops pushing the book, how far does the book slide before coming to rest?
Show all work.
Answer: To find the coefficient of static friction:
Frictional force needed to start the book sliding:
f_s = F_applied = 5.0 N
The maximum force of static friction can be found using:
f_s,max = μ_s N
where N is the normal force between the book and the table.
To find N, we need to consider the forces acting on the book:
The force of gravity acting downwards (weight)
The normal force from the table acting upwards
Since the book is not accelerating vertically, we can say:
N - mg = 0
N = mg
where m is the mass of the book, and g is the acceleration due to gravity.
So, N = (1.0 kg + 100 kg) x 9.81 m/s^2 = 1089.9 N
Now we can find μ_s:
f_s,max = μ_s N
5.0 N = μ_s x 1089.9 N
μ_s = 0.0046
Therefore, the coefficient of static friction between the book and the table is 0.0046.
To find the coefficient of kinetic friction:
Frictional force needed to keep the book sliding at a constant velocity:
f_k = F_applied = 4.0 N
The force of kinetic friction is given by:
f_k = μ_k N
where N is the normal force, which we already found to be 1089.9 N.
So, μ_k = f_k / N
μ_k = 4.0 N / 1089.9 N
μ_k = 0.0037
Therefore, the coefficient of kinetic friction between the book and the table is 0.0037.
To find the distance the book slides before coming to rest:
When the teacher stops pushing the book, the only force acting on it is the force of kinetic friction, which acts to slow down the book. The book will eventually come to rest when its velocity is zero.
We can use the equation of motion:
v^2 = u^2 + 2as
where u is the initial velocity, v is the final velocity (which is zero), a is the acceleration (which is the same as the deceleration due to friction), and s is the distance travelled.
Rearranging the equation, we get:
s = (v^2 - u^2) / 2a
Substituting the given values:
u = 0.30 m/s (since the book is moving at a constant velocity before the teacher stops pushing it)
v = 0 m/s (since the book comes to rest)
a = - μ_k g (since the force of friction acts in the opposite direction to the book's motion)
a = - 0.0037 x 9.81 m/s^2 = -0.0363 m/s^2
Plugging in the values, we get:
s = (0 - (0.30 m/s)^2) / (2 x (-0.0363 m/s^2))
s = 0.41 m
Therefore, the book slides 0.41 meters before coming to rest.
Explanation:
a car of mass 772 kg is traveling 21.4 m/s when the driver applies the brakes, which lock the wheels. the car skids for 4.87 s in the positive x-direction before coming to rest.
A car of mass 772 kg is traveling at 21.4 m/s when the driver applies the brakes, which lock the wheels. The car skids for 4.87 s in the positive x-direction before coming to rest.
The required calculations can be performed using the following equations:
1. F = ma2. v = u + at3. s = ut + (1/2) at^2
Here, u = 21.4 m/s (initial velocity)
a = (-μg) = (-0.5 x 9.8) = -4.9 m/s^2 (deceleration due to the lock)
μ = 0.5 (frictional coefficient between road and tires)
g = 9.8 m/s^2 (acceleration due to gravity)
The normal force is given as:
N = mgN = 772 x 9.8N = 7580.6 N
Now, the force due to friction can be calculated:
F = μN = 0.5 x 7580.6F = 3790.3 N
Therefore, acceleration can be calculated as follows:
F = ma=> a = F/m=> a = 3790.3/772a = 4.91 m/s^2
Now, the final velocity can be calculated as:
v = u + at=> v = 21.4 + (-4.91 x 4.87)v = -0.384 m/s
A negative sign indicates that the car is moving in the negative x-direction.
In order to calculate the distance traveled, we will use the formula:s = ut + (1/2) at^2=> s = 21.4 x 4.87 + (1/2) x (-4.91) x (4.87)^2s = 52.79 mT
herefore, the car skids for 52.79 m in the negative x-direction before coming to rest.
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The electrical energy stored in a capacitor is given by E = (1/2)CV^2
V= potential difference across the capacitor
C= the capicatance of the capacitor in units of farads
Which of the following combinations of coulombs, joules, and/or volts is equivalent to a farad?
a) C^2/J
b) V/C
c) J/C^2
d) C^2/V
The energy stored in a capacitor can be expressed in three ways: Ecap=QV2=CV22=Q22C E cap = QV 2 = CV 2 2 = Q 2 2 C , where Q is the charge, V is the voltage, and C is the capacitance of the capacitor. The energy is in joules when the charge is in coulombs, voltage is in volts, and capacitance is in farads.
Question 6 of 10
What is the frequency of a wave that has a wavelength of 0.20 m and a speed
of 22 m/s?
A. 4.4 Hz
B. 110 Hz
C. 0.23 Hz
D. 0.001 Hz
Answer: Try A. 110 Hz
Explanation:
Answer:
i got 110 Hz..
Explanation:
!! HELP PLEASE !! As seen from above, a 73.9 kg water skier is pulled by a 105 N force at a 22.5° angle, while the water creates a 74.8 N force pulling directly backward. What is the x-component of the total force on the skier?
Answer: The x-component of the total force 97N
Explanation:
Given the following :
Mass (M) of skier = 73.9 kg
Pull force on the skier = 105N
Angle of pull = 22.5°
The direct backward force directly pulling the skier = 74.8N
the x-component of the total force on the skier
The horizontal component of the force = Magnitude of the pulling force × cosine of the angle of pull (FCosΘ)
FCosΘ = 105cos22.5°
105cos22.5 = 105 × 0.9238795
= 97.007350
= 97N
The backward force acting directly backward = 74.8N
Therefore, net x - component of the total force equals ;
97N - 74.8N = 22.2N
Is it possible for the sum of kinetic energy and potential energy of an object to change without work having been done on the object
The sum of kinetic energy and potential energy of an object can change without work having been done on the object.
This is possible because the sum of kinetic energy and potential energy is the total mechanical energy of an object. Total mechanical energy is the sum of kinetic energy and potential energy.The mechanical energy of an object refers to the sum of kinetic and potential energy of an object. Therefore, the mechanical energy of an object is the sum of its potential and kinetic energies, i.e. Emechanical = Epotential + EkineticThus, it is possible for the sum of kinetic energy and potential energy of an object to change without work having been done on the object.Learn more about potential and kinetic energy:
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Milk being heated on top of a stove will do what?
Group of answer choices
Expand
Contract
Stay the same
The mass of an object is the measure of what characteristic of the object?
O A. its volume
OB. the space it occupies
OC, the amount of matter it has
OD. its weight
ANSWER PLZ
Answer:
C. The amount of matter it has
Which soil conservation method involves planting different crops in a field
each year to restore nutrients.
Answer:
Crop rotation is the practice of growing a series of different types of crops in the same area across a sequence of growing seasons. It reduces reliance on one set of nutrients, pest and weed pressure, and the probability of developing resistant pest and weeds
A 263 kg crate slides 3.2 m until coming to a stop after being pushed by a large man. The effective coefficient of kinetic friction between the crate and the surface is 0.13. Calculate the work done by friction .
WORK OUT AND USE UNITS
The work done by friction when a crate of 263 kg slides 3.2 m is 1072.2 J.
What is friction?Friction is the force that opposes the motion of two bodies in contact.
To calculate the work done by friction, we use the formula below.
Formula:
W = mgdμ............ Equation 1Where:
W = Work done by frictionm = Mass of the crateg = Acceleration due to gravityd = Distance traveled by the crateμ = Coefficient of kinetic frictionFrom the question,
Given:
m = 263 kgh = 3.2 mg = 9.8 m/s²μ = 0.13Substitute these values into equation 1
W = (263×3.2×9.8×0.13)W = 1072.2 JHence, the work done by friction is 1072.2 J.
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An object travels for 5 minutes with constant motion. What conclusion can you make about the sum of the forces (total force) acting upon an object? How did you reach this conclusion?
Two students are asked to find the height of a particular building using a barometer. Instead of using the barometer as an altitude-measuring device, they take it to the roof of the building and drop it off, timing its fall. One student reports a fall time of 3. 0 s, and the other, 3. 3 s. What % difference does the 0. 3 s make for the estimates of the building's height? Express your answer using one significant figure
According to given information, The 0.3 second difference in fall times results in a 9.5% difference in the estimates of the building's height.
The students attempted to estimate the height of a building by dropping a barometer off the roof and timing its fall. One student recorded a fall time of 3.0 seconds, while the other student recorded a fall time of 3.3 seconds. We need to calculate the percentage difference in their estimates of the building's height based on this time difference.
To find the percentage difference, we can use the formula:
Percentage Difference = (Difference / Average) x 100
First, let's calculate the difference in fall times:
Difference = 3.3 s - 3.0 s = 0.3 s
Next, we need to find the average of the two fall times:
Average = (3.3 s + 3.0 s) / 2 = 3.15 s
Now, let's substitute the values into the formula:
Percentage Difference = (0.3 s / 3.15 s) x 100
Simplifying the calculation:
Percentage Difference = 0.0952 x 100
Percentage Difference = 9.5%
So, the 0.3 second difference in fall times results in a 9.5% difference in the estimates of the building's height.
In conclusion, the 0.3 second difference in fall times results in a 9.5% difference in the estimates of the building's height.
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What Do Supernovas Do That Fusion In The Cores Of Stars Cannot? A. Create The Heaviest Elements In The Universe B. Create Heat And light
C. Create iron D. All of the above
Create the heaviest elements in the universe. Supernovas are incredibly powerful explosions that occur when massive stars reach the end of their lives and collapse.
During a supernova, the star's core undergoes a catastrophic collapse, triggering a series of nuclear reactions that create extremely high temperatures and pressures. These extreme conditions allow for the creation of the heaviest elements in the universe, such as gold, platinum, and uranium, which cannot be produced through fusion in the cores of stars. Fusion reactions in the cores of stars can only produce elements up to iron, which has the highest binding energy per nucleon. Supernovas are also responsible for dispersing these heavy elements throughout the universe, as the explosion ejects material from the star's core into space. This material can then become incorporated into new stars, planets, and other celestial bodies. In addition to creating heavy elements, supernovas also generate large amounts of heat and light. The intense radiation from a supernova can outshine entire galaxies and can be visible from millions of light-years away. However, the creation of heat and light is not something that supernovas can do that fusion in the cores of stars cannot do. It is the creation of heavy elements that sets supernovas apart from other stellar phenomena.
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The capacity of a battery to deliver charge, and thus power, decreases with temperature. The same is not true of capacitors. For sure starts in cold weather, a truck has a 500 F capacitor alongside a battery. The capacitor is charged to the full 13.8 V of the truck's battery. How much energy does the capacitor store? What is the ratio between the energy density per unit mass of the 9.0 kg capacitor system and the 130,000 J/kg of the truck's battery.
The energy stored in the capacitor is calculated as 630150 J. The ratio between the energy density per unit mass of the 9.0 kg capacitor system and the 130,000 J/kg of the truck's battery is 70.17
The formula to calculate the energy stored in a capacitor is expressed by the formula:
E = (1/2)CV²
where E is energy, C is capacitance, and V is voltage.
The question mentions that the capacitor is fully charged to 13.8 V. Therefore, the energy stored in the capacitor is given by the formula:
\(E = (1/2)CV^2 \\= (1/2)\times (500 F)\times {(13.8 V)}^2\\= 630150 J\)
The ratio between the energy density per unit mass of the 9.0 kg capacitor system and the 130,000 J/kg of the truck's battery can be computed by dividing the energy density of the capacitor system by the energy density of the truck's battery.
We know that energy density = energy / mass of the system.
Thus, the formula to calculate the ratio is:
\(Ratio = \dfrac{energy density per unit mass of capacitor system}{ energy density per unit mass of truck's battery}\\Ratio= \dfrac{630150 J / 9 kg}{ 130,000 J / 1 kg}= 70.017\)
Therefore, the ratio of energy density per unit mass of the capacitor system to that of the truck's battery is 70.017.
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Which of these best describes what happens when a ball hits the sweet spot (node) of a bat?
Group of answer choices
Most of the energy from the swinging of the bat is transferred to the ball.
Much of the energy of the ball hitting the bat is turned into oscillating the bat.
The waves created when the ball hits the bat and bounces off make the bat oscillate.
The bat breaks.
Answer:
The first option, energy is transferred.
Explanation:
Which condition must be met in order for an equation to be balanced?
Answer:
There must be an equal amount of each element on both sides of the equation. Hope this helps and please marks as the brainliest.
Explanation:
Answer:
The answer is D
Explanation:
Hope this helps!
The cost of operating an electrical appliance is based upon its
Aage.
Bease of use.
Cwattage and time used.
D original purchase price.
Answer:
wattage and time used
Explanation:
Look
If a electrical appliance has more power or wattage it will use more energy and cost more
If a electrical appliance is used for more time the cost is more
Hence Option C is correct
What is spring-mass-damper system formula?
The formula of a spring-mass-damper system is given by md2x/dt2 + cdx/dt + kx = F(t).
The spring-mass-damper system is a common model used in physics and engineering to describe the behavior of various mechanical systems, such as a car suspension system or a building during an earthquake. The equation of motion for a spring-mass-damper system is typically given by:
md2x/dt2 + cdx/dt + kx = F(t)
where m is the mass of the object attached to the spring and damper, x is the displacement of the mass from its equilibrium position, t is time, c is the damping coefficient, k is the spring constant, and F(t) is an external force applied to the system at time t.
The term md2x/dt2 represents the acceleration of the mass, while cdx/dt represents the damping force (i.e. resistance to motion) caused by the damper, and kx represents the force exerted by the spring. The external force F(t) can be any force applied to the system, such as an oscillating force or a constant force.
The solution to this differential equation depends on the initial conditions (i.e. the initial position and velocity of the mass) and the specific values of the parameters m, c, and k. The behavior of the system can be analyzed using various techniques, such as finding the natural frequency of the system or using numerical simulations to model the motion over time.
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The largest grand piano in the world is really grand. Built in London, it has a mass of 1,152 kg. Suppose a pianist finishes playing this piano and pushes herself from the piano so that she rolls backwards with a speed of 1.5 m/s. Meanwhile, the piano rolls forward with a constant velocity of 0.06 m/s. Assuming the stool that the pianist is sitting on has a negligible mass, what is the pianist’s mass? Round to the hundredths.
ANSWER:
46.08 kg
STEP-BY-STEP EXPLANATION:
Given
m1 = 1152 kg
v1 = 0.06 m/s
v2 = -1.5 m/s
We apply law of conservation of linear momentum:
\(\begin{gathered} P_i=P_f \\ P_i=0 \\ P_f=m_1\cdot V_1+m_2\cdot V_2 \end{gathered}\)We plug in and calculate for the mass, just like this:
\(\begin{gathered} 0_{}=m_1\cdot V_1+m_2\cdot V_2 \\ 0=1152\cdot0.06+m_2\cdot-1.5 \\ -1.5m_2=-69.12 \\ m_2=\frac{-69.12}{-1.5} \\ m_2=46.08\text{ kg} \end{gathered}\)Which means that the mass of the pianist is 46.08 kg
Can someone please explain
1) Centripetal force with example
2) Centrifugal force with example
3) Circular motion with example
Explanation:
centripetal force is a force that makes a body follow a curved path. for example, twirling,a lasso, cream seperator etc.
A force that causes an objectmoving in a circular path to move out and away from the centres of it's path is centrifugal force. for example,drifting, banked roads, washing machine etc.
Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. for example, stirring batter, stone tied to a string etc
hope its helpfull♡
PLZ HELP DUE IN 10MIN!!!!!!!!!The temperature of the water vapor (H2O) inside a pressure cooker increased from 295 K to 395 K. As
the sample is heated, the pressure of the water vapor went from 21.0 kPa to _____.
Answer:
p2=28.12KPa
Explanation:
Given data:
Initial temperature = 295 K
Final temperature= 395 K
Initial pressure = 21.0 KPa
Final pressure = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
21.0 KPa / 295 K = P₂/395 K
P₂ = 21.0 KPa× 395 K / 295 K
P₂ = 8295 KPa. K /295 K
P₂ = 28.12 KPa
How much is the plane's acceleration while breaking if it takes 15 s for its velocity
is changing from 145 m/s to 75m/s?
A. 4.67 m/s
B. 3.4 m/s
C. 45 m/s
D. 23 m/s
Answer:
A. 4.67 m/s²
Explanation:
u = 145 m/s
v = 75 m/s
t = 15 s
a = v - u / t
= 145 - 75 / 15
= 4.67 m/s²
Hope this helped...
Examine the following circuit diagram and state the value of
(a) V2 (b) I2 (c) R1 (d) R2 (e) RT
With the use of Ohm's law formula and some assumption, the answers are
(a) V2 = 30v
(b) I2 = 5 A
(c) R1 = 1 Ω
(d) R2 = 6 Ω
(e) RT = 4 Ω
What is Current ?Current can simply be defined as the rate at which charges flow in a conducting material. It is measured in Ampere.
From the given circuit,
a) V2 and V3 are in parallel, so they will have the same voltage. The voltage dropped in V1 should be taken away from the total voltage. That is,
V2 = VT - V1
V2 = 40 - 10
V2 = 30v
b) The current produced from the battery is assumed to split equally on R2 and R3. Therefore, I2 = 5 A
c) The total current will flow through I1. That is,
I1 = 10 A
Using Ohm's law V1 = I1 × R1
10 = 10 × R1
R1 = 10/10
R1 = 1 Ω
d) From Ohm's law, V2 = I2 × R2
30 = 5R2
R2 = 30/5
R2 = 6 Ω
e) By using Ohm's law again
VT = IT × RT
40 = 10 × RT
RT = 40/10
RT = 4Ω
Therefore, The resistance in R1, R2 and R3 are 1Ω, 6Ω and 6Ω
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how does a simple cell work
Answer:
A simple cell can be made by connecting two different metals in contact with an electrolyte
I'm walking 1.6m/s to 7-11 and it started to rain so I sped up to 2.7m/s in 1.2
seconds. What is my acceleration?
a=(vf-viyt
-0.92m/s2
O 01.1m/s2
0.92m/s2
1.1m/s2
1 points
Save A
Answer:
Explanation:
\(a = \frac{v_f-v_0}{t}\) which is the final velocity minus the initial velocity in the numerator, and the change in time in the denominator. For us:
\(a=\frac{2.7-1.6}{1.2}\) so
a = .92 m/s/s (NOT negative because you're speeding up)