Answers
The average force the bat exerts on the ball when it touches it for the given period of time is 975 N.
The given parameters:
mass of the ball, m₁ = 65 ginitial velocity of the ball, v₁ = 25 m/sfinal velocity of the ball, v₂ = 35 m/s opposite directiontime of action, t = 4 msThe average force the bat exerts on the ball when it touches it for the given period of time is calculated by applying Newton's second law as follows;
\(F = ma\\\\F = \frac{M(v_2 - v_1)}{t} \\\\F = \frac{0.065(35 - (-25))}{4 \times 10^{-3}} \\\\F = \frac{0.065(35 + 25)}{4 \times 10^{-3}} \\\\F = 975 \ N\)
Thus, the average force the bat exerts on the ball when it touches it for the given period of time is 975 N.
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Related Questions
Select the correct answer.
In a given chemical reaction, the energy of the products is less than the energy of the reactants. Which statement is true for this chemical
reaction?
Answers
Answer:
This makes the products have less energy than the reactants that combined to produce them.
Explanation:
suppose a force of 8 N east, a force of 12 N west, and a force of 4 N east acts on a moving object.
Try sketching this example on a piece of scrap paper.
Use different colors to model the forces on the object.
What is the net force on the object?
N
Are the forces you modeled balanced or unbalanced? use correct spelling.
Answers
Answer:
LOL "use correct spelling" to an engineer type is probably the hardest part of this problem!!!
Net force is 0 N
The forces are balanced and no change occurs to the velocity of the object.
4 N ───→ ┌┐ ←──────────── 12 N
8 N ────────→ └┘
The forces are balanced and the net force on the object is zero.
What is meant by net force ?Net force acting on an object is defined as the vector sum of all the forces acting on it.
Here,
A force of 8 N is acting towards the east, a force of 12 N is acting towards the west and a force of 4 N is acting towards the east on the object.
The free body diagram represents the force vectors acting on the object.
From the diagram,
The forces 8 N and 4 N are acting on the same direction and the 12 N force is acting in the opposite direction.
So, the resultant of the forces 8 N and 4 N are opposite to the 12 N force.
Resultant of 8 N and 4 N = 8 + 4 = 12 N towards east.
The rest force acting is 12 N towards west.
Now, resultant shows that they are equal and opposite.
Therefore, the net force on the object is zero. ( since 12 N east and 12 N west cancels each other).
That means the forces are balanced and so they cancel each other.
Hence,
The forces are balanced and the net force on the object is zero.
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Attaching the image here.
Air pressure pushes in all directions because air particles ____ in all directions.Ex:_.__
Answers
Air pressure pushes in all directions because air particles MOVES in all directions.
Explanation
Let's remember that the air is a fluid, . As a fluid, air is able to flow in every direction and take any shape.
the pressure force acts perpendicular to the surface
so,the answer is
Air pressure pushes in all directions because air particlesb MOVES in all directions.
I hope this helps you
A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. A 1.2 kg raven flying horizontally at 5.0 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction..What is the angular speed of the gate just after it is struck by the unfortunate raven?
Answers
Answer:
ω = 1.82 rad/sec
Explanation:
Given
mass of the gate = 4.5 kg
distance between the hinge 1.5 m
mass of the bird = 1.2kg
velocity of the bird = 5 m/s
The gate is rotates in circular motion
Inertia ot the gate = \(\frac{1}{3}\)×m×r²
= \(\frac{1}{3}\)×4.5×1.5²
= 3.3 kg/m²---------(1)
momentum of the the rave = mv
= 1.2×5
= 6.0 kg
angular momentum of the gate = Iω
By conservation of energy
6. 0= 3.3×ω
ω= 6.0/3.3
= 1.82 rad/sec
from equation 1
I = 3.3 kg/m^2
ω = 1.82 rad/sec
A body of mass 1 kg is pushed at a constant speed against a vertically placed wall, with a constant force F, which forms an angle of 45 degrees with the horizontal, as in the picture. The sliding friction coefficient is 0.2. What is the intensity of the force F? For the acceleration of the heavier force, take g=10 m/s2.
Answers
The intensity of the force F is calculated to be approximately 2.83 N.
What is sliding friction coefficient?Coefficient of sliding friction is a value that measures force of sliding friction for particular surface type.
Weight = mg = 1 kg x 10 m/s² = 10 N (acting downwards)
F_vertical - Weight = 0
F_vertical = 10 N
As Frictional force = coefficient of friction x normal force
Frictional force = 0.2 x 10 N = 2 N (acting to the left)
F_horizontal = F x cos(45) = F / √2
F_horizontal - frictional force = 0
F_horizontal = frictional force = 2 N
F / √2 = 2 N
F = 2 N x √2
F ≈ 2.83 N
Therefore, the intensity of the force F is approximately 2.83 N.
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At present, NASA is planning a mission to Europa, to try and assess its habitability. An argument might also be made for Enceladus, however. Let's imagine you had to pick one of those moons to send an uncrewed (i.e. robotic) mission to. The spacecraft will probably orbit the giant planet (Jupiter in the case of Europa, Saturn in the case of Enceladus), and make many flybys of the moon you're studying. Which moon would you pick, and why?
Answers
Answer:
Jupiter
Explanation:
For this space trip, the distance to the planet must be taken into account, so Because Jupiter is much closer it should be the correct choice
.
It must also be taken into account that Saturn has a series of rings, for which the ship has a probability of colliding with one of these in one of its turns, therefore taking this into account, Jupiter must also be chosen.
What is the best anime show to watch? I need to watch some more anime and I need some shows lol
Answers
Try watching Demon Slayer on Netflix. It's a new series, and it's very entertaining to watch!! :)
(Brainliest please!)
A budding magician holds a 3.98-mW laser pointer, wondering whether he could use it to keep an object floating in the air with the radiation pressure. This might be an idea for a new trick! Assuming the laser pointer has a circular beam 3.00 mm in diameter and the magician rigs up a totally reflecting sail on which to shine the laser, what is the maximum weight the magician could suspend with this technique
Answers
Answer:
F = 2.65 10⁻¹¹ N
Explanation:
The radiation pressure for a fully reflective surface is
P = 2S / c
where S is the pointiing vector which is the energy per unit area,
S = I = \(\frac{\ P_{prom} }{A}\)
the area of a circle is
A = π r² = π d²/4
S = \(\frac{3.98 \ 10^{-3} }{ \frac{\pi \ 0.003^2 }{4} }\)
S = 0.563 10⁻³ W / m2
let's calculate the pressure
P = 2 0.563 10⁻³/3 108
P = 0.3753 10⁻⁵ N / m²
this pressure exerts an upward force, the definition of pressures
P = F / A
F = P A
let's calculate
F = 0.3753 10-5 π / 4 0.003²
F = 2.65 10⁻¹¹ N
two cars both with a mass off 500kg are traveling down a road. The first car has a velocity of 65 m/s east and the second car has a velocity of 85 m/s west.
Answers
Explanation:
The momentum of an object is given by
D= mv
where
m is the mass
vis the velocity
For the first car, m = 500 kg and v = 65 m/s east, so the momentum is
PI
= (500) (65) = 32500kgm/s east
For the second car, m = 500 kg and v = 85 m/s west, so the momentum is
p2 = (500) (85) = 42500k gm/s
west
By comparing the two momentum, we see that the second car has larger
momentum.
Some runners train with parachutes that trail behind them to provide a large drag force. These parachutes are designed to have a large drag coefficient. One model expands to a square 1.8 m on a side, with a drag coefficient of 1.4. A runner completes a 200 m run at 5.0 m/s with this chute trailing behind. Part A How much thermal energy is added to the air by the drag force
Answers
Answer:
13.9 kJ
Explanation:
Given that
Length of the side, l = 1.8 m
Drag coefficient, C(d) = 1.4
Distance of run, d = 200 m
Velocity of run, v = 5 m/s
Density, ρ = 1.23
Using the Aerodynamics Drag Force formula. We have
F(d) = 1/2.ρ.A.C(d).v²
The Area, A needed is 1.8 * 1.8 = 3.24 m². So that,
F(d) = 1/2 * 1.23 * 3.24 * 1.4 * 5²
F(d) = 139.482/2
F(d) = 69.74
recall that, energy =
W = F * d
W = 69.74 * 200
W= 13948
W = 13.9kJ
Therefore, the thermal energy added to the air by the drag force is 13.9kJ
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom of the hill and car C is at the top. Suppose each car suddenly brakes hard and starts to skid. Assume μk=1.00. What is the x-component of the tangential acceleration (i.e., the acceleration parallel to the road) of car A?
Answers
Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.
How do kinetic and potential energy compare?The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.
They are being affected by the kinetic frictional force, which is caused by:
f = μk * N
Therefore,
fB = μk * N = μk * mB * g
Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,
fC = μk * N = μk * mC * g
where mC is the mass of Car C.
For Car A, the x-component of the tangential acceleration is given by:
aA = (fB - fC) / mA
where mA is the mass of Car A.
We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:
aA = (μk * mB * g - μk * mC * g) / mA
aA = μk * g * (mB - mC) / mA
Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:
aA = (mB - mC) * 9.81 / mA
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a man throws a ball vertically upward with an initial speed of 20m/s . what is the maximum height reached by the ball and how long does it take to return to the point it was thrown.
Answers
A ball is thrown vertically upward with a velocity of 20 m/s. calculate maximum height and time taken to reach maximum height. H = U2/ (2g) = (202)/ (2 x 9.8)=20.4 m T = U/g = 20/9.8 = 2.04 sec
What observations can the geologist make by working outdoors instead of in a lab?
Answers
Answer:
Geology is the study of the Earth that involves the process at Earth, materials of which it is made, and its history.
Geologists combine both laboratory and field data to illustrate the results of their research. Some observations that can the geologist make by working outdoors instead of in a lab are as follows:
Understanding and exploring the earth's surface closely using geophysical tools.Collecting samples by own and make some interpretations at the same time.Observation of the landscapesClose observation of outcropsThe world record for the 100-meter dash is 9.76 s. What is the runner's average speed?
Answers
Answer:
mine is 9.75 so take that as you will
Explanation:
A space ship has four thrusters positioned on the top and bottom, and left and right as shown below. The thrusters can be operated independently or together to help the ship navigate in all directions.
Initially, the Space Probe is floating towards the East, as shown below, with a velocity, v. The pilot then turns on thruster #2.
Select one:
a.
Space ship will have a velocity to the West and will be speeding up.
b.
Space ship will have a velocity to the East and will be speeding up.
c.
Space ship will have a velocity to the East and will be slowing down.
d.
Space ship will have a velocity to the West and will be slowing down.
e.
Ship experiences no change in motion.
Answers
Answer:
The correct answer is - c. Spaceship will have a velocity to the East and will be slowing down.
Explanation:
In this case, if turned on thruster #2 then it will exert force on the west side as thruster 2 is on the east side and it can be understood by Newton's third law that says each action has the same but opposite reaction.
As the spaceship engine applies force on the east side then according to the law the exhauster gas applies on towards west direction. It will try to decrease the velocity of the spaceship however, the direction of floating still be east side initally.
A yo-yo is released from a stationary hand and spins freely without slipping as the string unwinds. Simultaneously, the yo-yo moves downwards 0.70 m. The radius of the yo-yo is 0.008 m, the mass is 0.05 kg, and the rotational inertia is 3.5 * 10 -5kg*m 2 . a. Calculate the initial gravitational potential energy
Answers
The initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be calculated by multiplying the mass of an object with the square of its velocity. Kinetic energy is a form of energy that is associated with the movement of objects. It is released when objects collide or when objects are deformed. Kinetic energy can also be converted into other forms of energy, such as thermal energy, sound energy and electrical energy.
The initial gravitational potential energy of the yo-yo is equal to the change in height multiplied by the weight of the yo-yo. The weight of the yo-yo can be calculated using the equation W = m × g, where m is the mass and g is the acceleration due to gravity. Therefore, the initial gravitational potential energy of the yo-yo is equal to 0.05 kg ×9.8 m/s2 ×0.70 m = 0.343 Joules.
b. Calculate the initial rotational kinetic energy of the yo-yo.
The initial rotational kinetic energy of the yo-yo is equal to ½Iω2, where I is the rotational inertia and ω is the angular velocity. The angular velocity can be calculated using the equation ω = v/r, where v is the linear velocity and r is the radius of the yo-yo. Therefore, the initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.
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Consider a pair of planets for which the distance between them is decreased by a factor of 4.
How many times does the force between them increase?
F (after)/ F(before)= ????
Someone please explain this for me!
Answers
Answer: the force will increase 16 times
Explanation:
as the equation of the force is written, it's denominator is the distance squared
\(f = G\frac{m_{1}.{m_{2}}}{r^{2} }\)
so the distance is reduced by a factor of 4 ,the equation becomes\(f = G\frac{m_{1}.{m_{2}} }{{[r/4]}^{2} }\)
now as the distance r is divided by 4 the complete equation is multiplied by 16.
h. If the mass of an object is 390 g and its volume is 50 cm?, then its density is ....... g/cm' or ....... kg/m”.
- The relative density of the object in part "h" is
Edit: nvm I'm an idiot I remembered this but thanks anyway
Answers
Answer: See explanation
Explanation:
The density would like be calculated by dividing the mass by volume. This will be:
Density = Mass / Volume
Density = 390 / 50
Density = 7.8g/cm
Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate
Answers
Answer:
Jim Crow Laws Effects.
User
What were Jim Crow laws? Your response should also describe at least two effects Jim Crow laws
had on the rights of Black Americans. (4 points)
ChatGPT
Jim Crow laws were a set of state and local laws in the United States, enacted between the 1870s and 1960s, that enforced racial segregation and discrimination against Black Americans. These laws were named after a popular 19th-century minstrel show character who stereotyped African Americans.
Two effects of Jim Crow laws on the rights of Black Americans were:
Limited access to public facilities: Jim Crow laws mandated that public spaces such as schools, parks, hospitals, and restaurants were segregated by race. Black Americans were often denied access to public spaces that were reserved for white people. This segregation limited the ability of Black Americans to participate fully in public life and access resources and opportunities that were available to white Americans.
Restricted voting rights: Jim Crow laws were used to disenfranchise Black Americans by making it difficult or impossible for them to vote. These laws included literacy tests, poll taxes, and other requirements that were designed to exclude Black Americans from voting. As a result, many Black Americans were unable to exercise their constitutional right to vote until the Voting Rights Act of 1965 was passed. This restriction on voting rights undermined the ability of Black Americans to participate fully in democracy and have their voices heard.
User
Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate
ChatGPT
To calculate Gavin's typing rate, we need to divide the amount he can type by the time it takes him to type it.
First, we need to convert the mixed number 5 3/4 into an improper fraction:
5 3/4 = (4 x 5 + 3)/4 = 23/4
Next, we can convert the mixed number 1/2 into an improper fraction:
1/2 = 2/4
Now, we can add the two fractions:
23/4 + 2/4 = 25/4
This means that Gavin can type 25/4 pages in 5 3/4 minutes.
To find Gavin's typing rate, we need to divide the amount he can type (25/4 pages) by the time it takes him to type it (5 3/4 minutes):
Typing rate = (25/4) / (5 3/4)
To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction:
Typing rate = (25/4) x (4/23)
Simplifying the fractions, we get:
Typing rate = 25/23
Therefore, Gavin's typing rate is 25/23 pages per minute.
Compare the table of information with the bar graph shown. What makes verifying that the bar graph has the same information as the table especially challenging? own answer
Answer:The table uses metric tons as its numerical scale unit, whereas the bar graph uses pounds. This use of differing units means the reader must convert units of measurement before verifying that the information in the table matches the information in the bar graph.
Answers
When displaying sections of data, bar charts is used. As long as the number of categories to compare, vertical bar charts can be useful for comparing several category discrete data, like ages, classes, schools.
Why are graphs more illuminating than tables?Charts and graphs are useful visual aids because they make information accessible and quick to understand. So, it is not unexpected that both print and digital media frequently use graphs. When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.
What do the tables, graphs, and data represent?Visual representations of data, such as tables and graphs, are used to arrange information and reveal patterns and correlations. To present the results of their research, scientists and researchers frequently employ tables and graphs.
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Corn plants and milkweed plants grow in the same area. Over several years, the milkweed plants have taken over the field and the corn plants no longer have space to grow.
This best demonstrates which type of an interaction between the plants?
cooperation
parasitism
commensalism
competition
Answers
The interaction between the Corn plants and milkweed plants demonstrates as competition.
What is competition in Plants community?Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.
In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.
As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and milkweed plants demonstrates competition.
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6. A persen was travelling inside a car in winter season. Suddenly a high potential(voltage) wire broke and fell on his car. He immediately stopped car and called on emergency number 100 for help. He got an advice to stay within the car unless technicians of Electricity Authority arrive for help. a. Why do wires often break in winter season? [1] b. Why do you think the technician advised the person to sit inside the car unless help arrives? [2] c. What happens if he opens the door and slowly moves out of car?
Answers
(a) Wires usually made of copper, contracts with drop in temperature in winter.
(b) The technician advised the person to sit in the car to be avoid being electrocuted.
(c) He will still be electrocuted because he will touch the metal part of the car.
Why do wires often break in winter season?Wires usually made of copper, contracts with drop in temperature in winter hence breaks if it becomes too tight between the poles.
Why the technician advised the person to sit inside the car?The technician advised the person to sit in the car to be avoid being electrocuted when he touches the metal part of car on moving out.
What happens if he opens the door and slowly moves out of car?He will still be electrocuted because he will touch the metal part of the car. Thus, the wire must be disconnected from the high tension before he moves out.
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You hold a 5 lb bag of sugar in your hand, you must push upwards on it with a force of 5 lb. Is this an example of Newton's Law?
Answers
Newton's laws of motion describe the behaviour of objects when they are at rest or in motion.
The three laws of motionAn object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an external force. The acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass. For every action, there is an equal and opposite reaction.First law of motion in this scenarioThe 5 lbs bag of sugar is at rest in this situation, and you are exerting a 5 lbs upward force on it. The sugar bag will continue to be at rest unless an outside force acts upon it, in accordance with the first law of motion. It is being subjected to an external force that you are applying.
Second law of motion in this scenarioAccording to the second law of motion, theforce exerted on the bag of sugar will have a direct proportional effect on how fast it accelerates. The mass of the bag of sugar is 5 pounds, and the force you are exerting on it is 5 lbs. Because\(\textsf{$\frac{\textsf{5 lbs (force)}}{\textsf{ 5 lbs (mass)}}$ = 1 (unit of accleration)}\), the bag of sugar will accelerate by 1 (unit of acceleration).
Third law of motion in this scenarioThe third law of motion states that there is an equal and opposite reaction to every action. In this case, the sugar bag pushes down on your hand with a 5 lb force when you push up on it with a 1 lb force. The force you are providing to the bag of sugar will have an equal and opposite reaction here.
Therefore, this scenario illustrates all three of Newton's laws of motion
----------------------------------------------------------------------------------------------------------
Yes, this is an example of Newton's Third Law of Motion. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. In this example, when you push upwards on the 5 lb bag of sugar with a force of 5 lb, the bag of sugar also pushes downwards on you with a force of 5 lb.In other words, the action is you pushing upwards on the bag of sugar and the reaction is the bag of sugar pushing downwards on you with the same amount of force. So, this is an example of Newton's Third Law of Motion.
Why does the shape of the lens in your eye change?
Answers
The Lens Changes Shape to Focus Near Objects. Light rays from objects that are close to the eye are not parallel. Therefore, the eye must bend them more in order to focus the rays on the retina. To accomplish this, the lens change shape.
Hope this helps
Answer:
to focus the light
PLASES HELP ASAP
A baseball bat company is testing a new alloy that they claim will improve the power of its bats for very weak or low-power batters. Given the provided data of three bat compositions, swing force, and resulting ball travel distance, what conclusion can be made regarding their new alloy? A) There is no hypothesis provided. B) The hypothesis of the company is refuted. C) The hypothesis of the company is verified. D) The hypothesis was neither verified or refuted.
Answers
Answer:
B.
Explanation:
I'm not sure if it's the right answer but I think it is. I hope I helped out in some way.
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
Answers
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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energy of fossil fuel is also derived from solar energy why
Answers
Explanation:
All the energy in oil, gas, and coal originally came from the sun captured through photosynthesis. In the same way that we burn wood to release energy that trees capture from the sun, we burn fossil fuels to release the energy that ancient plants captured from the sun.
Pls Help Me with this problem
Answers
Answer:
explanation
Explanation:
1 = C
2 = A
3 = D
4 = E
5 = B
A FBD of a rocket launching into space should include:
Answers
Answer:
Explanation:
the force of the rocket engine pushing it up, the force of gravity pulling it down, maybe some force of air resistance as the rocket goes fast, hmmm Free Body Diagrams (FBD) should have any and all forces on the model, unless they are negligible . or so slight they really make little difference in the total outcome.