a binary system, like cygnus x-1, may have a black hole in it if the following is known about it: (2 answers)

Answer:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Answer:

-Computer going blank .

-Mouse pointer freezing.

-Keyboard getting stuck.

Explanation:

Any problems with the computer related to its hardware will consist of issues directly related to the physical components of the PC or computer. So any problem involving the physical component of the computer, then it can be termed as a hardware problem.

Based on the problems given in the option, the hardware issues will be problems with the computer, mouse, and keyboard. These form the physical parts of the computer so they will be a hardware issue.

Thus, the correct answers are the third, fourth, and fifth options.

Answer:

c d e

Explanation:

Answer:

The original seven wastes, or muda, are transportation, inventory, motion, waiting, overproduction, overprocessing and defects. ... When manufacturers are able to identify the seven wastes, they can correct and prevent further loss of time, money and other resources.

Explanation:

Answer:

transportation, inventory,motion, waiting,overproduction,overprocessing,and defects

Explanation:

they are often referred to by the acronym TIMWOOD

It is necessary to categorize the device into Layer 3 of the OSI model if Carlos has just created a new subnet for the finance department and needs to be able to allow the employees in finance to retrieve files from the sales server, which is located in another subnet.

The OSI model (Open Systems Interconnection model) is a reference model for communication between computers. It divides the communication system into seven layers: Physical, Data Link, Network, Transport, Session, Presentation, and Application. The OSI model is a reference model for communication between computers, including routers, switches, and other networking devices.The seven layers of the OSI model are:Physical layer, Data Link layer, Network layer, Transport layer, Session layer, Presentation layer, Application layer, The layer responsible for routing, addressing, and forwarding data packets across networks is called the Network layer, which is Layer 3 of the OSI model.

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Answer:eyesight

Explanation:

You were given the opportunity to be a project manager for Apple to work on a new product by Product control examples additionally consist of the branding and consumer conversation.

Good mission managers recognize and recognize their marketplace and the enterprise in their projects. They look at the opposition and compare alternatives. A desirable mission supervisor remains updated at the brand new developments withinside the enterprise in their mission, and they show off a stable knowledge and know-how in their enterprise.

Product control examples additionally consist of the branding and consumer conversation required to release a brand new product. Each product, in its nascent form, calls for right branding. This creates recognition approximately the product withinside the marketplace. Advertising and PR managing additionally fall beneath neath the umbrella of product control.

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There are several possible explanations for the discrepancy in plagioclase presence between samples HOR1, HOR3, and HOR4:

   Difference in initial mineralogy: The three samples may have had different initial mineralogy, which would result in different compositions and reactions during uplift.

   Different rates of uplift: Samples HOR1 and HOR3 may have experienced uplift at different rates than sample HOR4, which could have affected the kinetics of the reaction and resulted in different mineral assemblages.

   Differences in fluid composition: The fluid composition, including temperature, pressure, and chemical composition, can affect the reaction kinetics and the resulting mineral assemblages. Samples HOR1 and HOR3 may have experienced different fluid compositions during uplift than sample HOR4, which could explain the absence of plagioclase.

In response to question b)

   Chloritization:

   Diopside + H₂O + Mg₂+ => Mg-chlorite + SiO₂(aq) + Na+

   Anorthite + H₂O + Mg₂+ => Mg-chlorite + SiO₂(aq) + Ca+

   Albitization of plagioclase:

   Anorthite + H₂O => Albite + SiO₂(aq) + Na+

Therefore, In the above reaction, the anorthite component of the plagioclase mineral is altered to albite, with the transfer of Na+ from the rock to the fluid. The total chemical composition of the rock is altered, with the albite component replacing the anorthite component.

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See full question below



Task 3

a) In the class you have studied thin sections of peridotite samples HOR1, HOR3, and HOR4. Sample HOR4 locally shows coexisting spinel and plagioclase in fine-grained aggregates, which may indicate a spinel breakdown reaction during ophiolite uplift. Remarkably, no plagioclase is observed in samples HOR1 and HOR3, even though these rocks had a similar uplift history. Discuss possible explanations for this discrepancy!

b) In the class you have studied a number of rocks that had been subject to hydrothermal alteration. Write down the schematic reactions and qualitative element transfer between rock and seawater for the alteration reactions listed below. You do not have to balance the equations. Examples:

Mineralı + H2O + Element1 => Mineral2

Mineral + H2O => Mineral2 + Element1

Remember that the system is open for mobile cations (e.g., Na+, Ca2+, Mg2+) and SiO2(aq).

1) Chloritization: diopside + anorthite => Mg-chlorite

2) Albitization of plagioclase: anorthite component => albite

Answer:

Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.

Explanation:

Normal fuel crossfeed system operation in multiengine aircraft allows for fuel transfer between engine fuel tanks to maintain balanced fuel distribution and prevent fuel starvation.

Ensure Proper Configuration: The fuel crossfeed system is typically operated during normal flight conditions when the fuel imbalance reaches a predetermined threshold.

Activate Crossfeed Valve: The crossfeed valve, located in the cockpit, is selected to the "open" position. This allows fuel to be transferred from one engine's fuel tank to the other.

Monitor Fuel Gauges: Pilots monitor the fuel quantity gauges to ensure the balanced transfer of fuel between the tanks. The goal is to equalize the fuel levels or maintain a desired fuel imbalance as per aircraft limitations.

Maintain Awareness: Pilots remain aware of any changes in fuel imbalance and adjust the crossfeed valve as needed to maintain proper fuel distribution.

Fuel Management: Pilots may also manage fuel consumption and crossfeed operation to optimize performance and efficiency during different phases of flight.

Deactivate Crossfeed: Once the desired fuel balance is achieved or during specific flight conditions, the crossfeed valve is returned to the "closed" position to isolate the fuel tanks and allow independent operation of each engine.

Proper operation of the fuel crossfeed system ensures optimal fuel management and contributes to the safety and efficiency of multiengine aircraft during normal flight operations.

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Answer:

please give me brainlist and follow

Explanation:

Example of an irreverseble isothermal process is mixing of two fluids on the same temperature - it requires a lot of energy to unmix Jack and coke. ... Example of an reversible process with changing temperature is isentropic expansion.

According to the question, an isothermal heat-transfer process can be either reversible or irreversible depending on the nature and characteristics of the closed system.

An isothermal process may be defined as a type of thermodynamic process in which the specific temperature of a system always remains constant. This means that ΔT = 0. In this thermodynamic process, the temperature of the whole system remains constant over a period of time.

An example of an isothermal process necessarily internally reversible may definitely include the working process of a radiator that involves the heating of the room while having a constant temperature is an irreversible isothermal process. An example of a reversible process with changing temperature is isentropic expansion.

Therefore, according to the question, an isothermal heat-transfer process can be either reversible or irreversible depending on the nature and characteristics of the closed system.

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Known :

Pg = 51 psi

Patm = 28 inHg = 13.7 psi

Solution :

Absolute pressure is gauge pressure plus the atmospheric pressure :

Pabs = Pg + Patm

Pabs = 51 + 13.7

Pabs = 64.8 psi

Non-quasi-equilibrium compression processes require more work input and produce entropy due to irreversibilities. Non-quasi-equilibrium expansion processes provide less work and generate more entropy. Reversible processes are quasi-equilibrium, but the reverse is not always true.

a) Non-quasi-equilibrium compression processes require a larger work input than the corresponding quasi-equilibrium processes because non-quasi-equilibrium compression processes result in the development of entropy due to the creation of irreversibilities.

b) A non-quasi-equilibrium expansion process provides less work than the corresponding quasi-equilibrium process because it produces more entropy due to the creation of irreversibilities.

c) Reversible expansion or compression processes are necessarily quasi-equilibrium processes, but the reverse is not necessarily true. Reversible expansion or compression processes are quasi-equilibrium processes because they occur infinitely slowly and do not generate irreversibilities.

However, a quasi-equilibrium expansion or compression process does not need to be reversible, since it can still generate some degree of irreversibility.

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Answer:

red RTV is sealant for areas that get hot black RTV is for oily surfaces like oil pans and head covers

Explanation:

The bronze C86100 pipe's maximum shear stress with an outer diameter of 1. 5 in. is around 16.98 psi.

To find the maximum shear stress in the pipe, use the formula:

τ = F / (2A)

where τ = shear stress, F = applied force, and A = area on which the force is acting.

Assume that the force is evenly distributed around the circumference of the pipe, so the area on which it is acting is equal to the circumference times the thickness:

A = πD t

where D = outer diameter and t = thickness.

Substituting the given values:

D = 1.5 in

t = 0.125 in

F = 20 lb

A = πD t = π(1.5)(0.125) = 0.589 in²

Therefore, the maximum shear stress is:

τ = F / (2A) = 20 / (2 × 0.589) = 16.98 psi

So the maximum shear stress in the pipe is approximately 16.98 psi.

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Answer:

Buyer is encouraged to obtain and read the booklet entitled "The Homeowners Guide to Earthquake Safety." In most cases a questionnaire within the booklet must be completed by Seller and the entire booklet given to the Buyer if the Property was built prior to 1960.

Answer:

This article deals with weight formula and its derivation. Weight refers to the force which acts on a body or object due to the effect of gravity. So, when an individual stands on a scale, the reading that appears is the weight. The more an individual weighs consequently means a higher reading on the scale. When an individual loses weight, he should think of it as lessening one’s force on the Earth due to gravity.

weight formula

What is Weight?

Simply speaking, weight refers to the force of gravity. Weight is certainly a force that acts on all bodies or objects at all times near a heavenly body such as the Earth. The Earth pulls all objects downward towards the center with a force of gravity. One can find the magnitude of the force of gravity by multiplying the magnitude of the acceleration due to gravity by the mass of the particular object.

Some books describe weight as a scalar quantity, the magnitude of the gravitational force. In contrast, some books refer to weight as a vector quantity, the gravitational force which acts on the object. Moreover, some experts explain weight as referring to the magnitude of the reaction force which is exerted on a body by various mechanisms. Also, these mechanisms keep the body in place.

The unit of measurement for weight is certainly that of force. This unit in the International System of Unit (SI) is the newton. The object with a mass of 1 kilogram would weigh about 9.8 Newtons on the Earth’s surface. Furthermore, it would weigh about one-sixth as much on the moon.

Weight Formula

The weight of an object or body certainly depends on the mass of the object and the gravity acting on it. This is why, the weight is different from mass. The mass of an object would be same whether on the Earth or on the Moon. The weight of an object due to the influence of gravity would be different on the Earth than on the Moon. The weight formula can be explained as follows:

Weight = mass × gravity

The formula for this is:

w = mg

Here we have,

w = weight

m = mass

g = gravity

Explanation:

An array that will hold 5 names with 20 characters in the name would be defined using  d. char names[5][21];

An array refers to a group of data elements that are indexed and share the same data type. In C, arrays allow for the combination of multiple entities that share a common data type.

This declaration specifies a 2D array named which has the capacity to store up to 5 strings with a maximum length of 21 characters each. The initial dimension denotes that there are five strings, whereas the second dimension indicates the upper limit of 21 characters for each string.

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Answer:

6.564 is the answers i learned that in the american school i live there

A. New die areaThe area of the 20 cm diameter wafer can be calculated as follows: Area = πr² = π(10)² = 100π cm²The area of each die is calculated by dividing the total area of the wafer by the number of dies: Area per die = (100π cm²)/100 = π cm².

If the number of dies per water is increased by 5%, then the new number of dies will be 100 + 5 = 105 dies. Therefore, the new area per die will be New area per die = (100π cm²)/105 = 0.952π cm²The new die area is 0.952π cm². New YieldThe initial yield is calculated by subtracting the number of defects from the number of good dies and then dividing by the number of good dies: Initial yield = (100 - 0.03 x 100)/100 = 99.97%If the defects per area increases by 10%, then the new defects per area will be 0.03 + (0.1 x 0.03) = 0.033 defects/cm². Therefore, the new yield will be New yield = (105 - 0.033 x 105)/105 = 96.67%B. Percentage yield changeThe percentage yield change can be calculated as follows: Percentage yield change = ((New yield - Initial yield)/Initial yield) x 100%Percentage yield change = ((96.67% - 99.97%)/99.97%) x 100%Percentage yield change = -3.30%C. Cost per die changeThe cost per die is calculated by dividing the cost of the wafer by the number of dies: Cost per die = 15 units/100 = 0.15 unitsIf the number of dies per water is increased by 5%, then the new number of dies will be 105. Therefore, the new cost per die will be: New cost per die = 15 units/105 = 0.143 unitsThe percentage cost per die change can be calculated as follows: Percentage cost per die change = ((New cost per die - Cost per die)/Cost per die) x 100%Percentage cost per die change = ((0.143 units - 0.15 units)/0.15 units) x 100%Percentage cost per die change = -4.67%. The new die area is 0.952π cm². The new yield is 96.67%. The percentage yield change is -3.30%. The new cost per die is 0.143 units. The percentage cost per die change is -4.67%.

In a semiconductor IC fabrication, assume a 20 cm diameter wafer has a cost of 15 units, contains 100 dies, and has 0.03 defects/cm². If the number of dies per wafer is increased by 5% and the defects per area increase by 10%, the new die area is 0.952π cm². The new yield is 96.67%. The percentage yield change is -3.30%. The new cost per die is 0.143 units. The percentage cost per die change is -4.67%.

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Answer:

H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

Explanation:

Since we are required to determine the transfer function G(s) and Y(s) = G(s)H(s). So, H(s) = Y(s)/G(s).

Since our system is given as y′′(t) + 8y′(t) +6y(t) = g(t), t>0 with all initial condition zero, that is, y(0) = 0, y"(0) = 0 and g(0) = 0.

Taking the Laplace transform of both the left hand side and right hand side of the equation, we have

y′′(t) + 8y′(t) +6y(t) = g(t),

L{y′′(t) + 8y′(t) +6y(t)} = L{g(t)}

L{y′′(t)} + L{8y′(t)} + L{6y(t)} = L{g(t)}

L{y′′(t)} + 8L{y′(t)} + 6L{y(t)} = L{g(t)}

[s²Y(s) - sy(0) - y'(0)] + 8[sY(s) - y(0)] + 6Y(s) = G(s)

[s²Y(s) - s(0) - 0] + 8[sY(s) - 0] + 6Y(s) = G(s)

s²Y(s) + 8sY(s) + 6Y(s) = G(s)

(s² + 8s + 6)Y(s) = G(s)

Y(s)/G(s) = 1/(s² + 8s + 6)

So, H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

Answer:

Explanation:

Understanding the business is important when designing a database because it enables the designer to align the database structure with the specific needs and requirements of the business. By comprehending the business processes, workflows, and data dependencies, the designer can create a database schema that accurately represents the real-world entities, relationships, and business rules. This alignment ensures that the database effectively supports the operations and goals of the business, leading to improved efficiency and productivity.

Furthermore, understanding the business helps in identifying and prioritizing the data to be stored in the database. By understanding the key information needed for decision-making and analysis, the designer can determine the essential data elements that should be included in the database. This ensures that the database captures and retains the critical information required by the business, facilitating accurate reporting, data analysis, and informed decision-making.

In summary, understanding the business is crucial for designing a database that is well-suited to the specific needs and requirements of the enterprise. It enables the designer to align the database structure with the business processes and data dependencies, and it helps in identifying and prioritizing the essential data to be stored. Ultimately, this understanding ensures that the database effectively supports the operations and goals of the business, contributing to its overall success.

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Answer:

ABS: Antilock Braking System – Prevents the wheels from locking during emergency braking.

ACC: Adaptive Cruise Control – Monitors traffic ahead and reduces or increases the car's speed based on the flow of traffic.

AEB: ...

AWD: ...

BHP: ...

CVT: ...

DDI: ...

DFI:

Explanation:

hope it helpssss

Answer:

ABS: Antilock Braking System – Prevents the wheels from locking during emergency braking.

ACC: Adaptive Cruise Control – Monitors traffic ahead and reduces or increases the car's speed based on the flow of traffic.

AEB: ...

AWD: ...

BHP: ...

CVT: ...

DDI: ...

DFI:

Answer:

i) Primary sensing element.

ii) Variable conversion element.

iii) Variable manipulation element.

Explanation:

Answer:

The main functional elements of a measurement system are:

i) Primary sensing element.

ii) Variable conversion element.

iii) Variable manipulation element.

v) Data transmission element.

Answer:

Two basic components of a buildings superstrcuture are beams and slabs. These components both safley transger the live loads, dead loads, and other loads to the substrutufe. This further distributes it to the underlying earth

Explanation:

Answer:

a) i) The maximum pressure is approximately 122.37 bar

ii) The thermal efficiency is approximately 56.47%

iii) The mean effective pressure is approximately 20.974 bar

b) (b) Four types of internal combustion engine includes;

1) The diesel engine

2) The Otto engine

3) The Brayton engine

4) The Wankel engine

Explanation:

The parameters of the Otto cycle are;

The heat added, \(Q_{in}\) = 2,800 kJ/kg

The compression ratio, r = 8

The beginning compression pressure, P₁ = 1 bar

The beginning compression temperature, T₁ = 300 K

Cp = 1.005 kJ/kg·K

Cv = 0.718 kJ/kg·K

R = 287 kJ/kg·K

K = Cp/Cv = 1.005 kJ/kg·K/(0.718 kJ/kg·K) ≈ 1.4

T₂ = T₁×r^(k - 1)

∴ T₂ = 300 K×8^(1.4 - 1) ≈ 689.219 K

\(\dfrac{P_1\cdot V_1}{T_1} = \dfrac{P_2\cdot V_2}{T_2}\)

\(P_2 = \dfrac{P_1\cdot V_1 \cdot T_2}{T_1 \cdot V_2} = \dfrac{V_1}{V_2} \cdot \dfrac{P_1 \cdot T_2}{T_1 } = r \cdot \dfrac{P_1 \cdot T_2}{T_1 }\)

∴ P₂ = 8 × 1 bar × (689.219K)/300 K ≈ 18.379 bar

\(Q_{in}\) = m·Cv·(T₃ - T₂)

∴ \(Q_{in}\) = 2,800 ≈ 0.718 × (T₃ - 689.219)

T₃ = 2,800/0.718 + 689.219 = 4588.94 K

P₃ = P₂ × (T₃/T₂)

P₃ = 18.379 bar × 4588.94K/(689.219 K) = 122.37 bar

The maximum pressure = P₃ ≈ 122.37 bar

(ii) The thermal efficiency, \(\eta_{Otto}\), is given as follows;

\(\eta_{Otto} = 1 - \dfrac{1}{r^{k - 1}}\)

Therefore, we have;

\(\eta_{Otto} = 1 - \dfrac{1}{8^{1.4 - 1}} \approx 0.5647\)

The thermal efficiency, \(\eta_{Otto}\) ≈ 0.5647

Therefore, the thermal efficiency ≈ 56.47%

(iii) The mean effective pressure, MEP is given as follows;

\(MEP = \dfrac{\left(P_3 - P_1 \cdot r^k \right) \cdot \left(1 - \dfrac{1}{r^{k-1}} \right)}{(k -1)\cdot (r - 1)}\)

Therefore, we get;

\(MEP = \dfrac{\left(122.37 - 1 \times 8^{1.4} \right) \cdot \left(1 - \dfrac{1}{8^{1.4-1}} \right)}{(1.4 -1)\cdot (8 - 1)} \approx 20.974\)

The mean effective pressure, MEP ≈ 20.974 bar

(b) Four types of internal combustion engine includes;

1) The diesel engine; Compression heating is the source of the ignition, with constant pressure combustion

2) The Otto engine which is the internal combustion engine found in cars that make use of gasoline as the source of fuel

The Otto engine cycle comprises of five steps; intake, compression, ignition, expansion and exhaust

3) The Brayton engine works on the principle of the steam turbine

4) The Wankel it follows the pattern of the Otto cycle but it does not have piston strokes

Answer:45

Explanation:

because i am gay

Answer:

The best recommendation to prevent emissions systems failure is to regularly maintain the fuel and emissions system.

Explanation:

One approach to managing pain is through patient education.

Patient education plays a crucial role in the management of pain. As a nurse, it is essential to provide patients and their families with the necessary knowledge and skills to understand and effectively manage pain at home. By educating patients about pain management, they can take an active role in their own care, leading to better outcomes and improved quality of life.

When it comes to pain, individuals have unique experiences and varying degrees of pain tolerance. By providing education, nurses can help patients develop a better understanding of their pain, its possible causes, and the available treatment options. This knowledge empowers patients to make informed decisions about their pain management and collaborate with healthcare providers in developing personalized care plans.

Patient education also encompasses the importance of adhering to prescribed medications and techniques for pain management. Nurses can explain the purpose, dosage, and potential side effects of medications, ensuring that patients and their families are aware of how to safely administer them. Additionally, nurses can demonstrate and guide patients through non-pharmacological pain management techniques, such as relaxation exercises, heat therapy, or distraction techniques, depending on the individual's needs and preferences.

By equipping patients with the necessary knowledge and skills, nurses help them become active participants in their pain management journey. This proactive approach fosters self-efficacy, reduces anxiety, and promotes better pain control. Patient education serves as a foundation for effective pain management both during the hospital stay and when transitioning to home care.

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Satellite broadband, fixed wireless broadband, or a mobile broadband link are a few possibilities.

A wireless local area network (WLAN) or wireless wide area network is used to offer wireless broadband, which is high-speed internet and data service (WWAN).

Wireless broadband is similar to other wireless services in that it can be either stationary or mobile.

In the latter case, a client receives high-speed internet wirelessly from an internet service provider (ISP), which is frequently referred to as wireless internet, broadband wireless, or cellular internet. Broadband is a colloquial term for high-speed internet connectivity in this situation.

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