As the book slides across the horizontal tabletop, it possesses kinetic energy. This kinetic energy is due to the motion of the book.
However, as the book slows down, its kinetic energy decreases until it comes to rest. Therefore, the change that occurs in the book's kinetic energy as it slows is a decrease in its kinetic energy. This is because the energy that was once attributed to the motion of the book has now been dissipated due to frictional forces acting upon the book and the table. This frictional force causes the book to lose its kinetic energy as heat energy is generated through the conversion of energy.
The change that occurs in the book's internal energy as it slows is negligible. This is because internal energy refers to the energy stored in the system due to the temperature of the object. In this case, the book's temperature remains constant. Although, some energy is converted into heat energy due to friction, this is not enough to significantly change the internal energy of the book. Therefore, the change in the internal energy of the book as it slows down is not noticeable.
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What is the answer please help me!
Answer:
The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground
Explanation:
We know that the earth's center attracts everything towards its center with an acceleration of 9.8 m/s² so it simply means that the change in velocity must occur to produce acceleration. When the ball comes towards the earth, its speed continuously increases and it is at maximum level when it is about to hit the ground so this is the point where gravitational force is maximum.
I hope this helps ^_^
Kieran ran 8 laps of the track in 18 minutes. Jevon ran 6 laps of the track. Who had a greater average speed
Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.
We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.
Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.
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A spring has an unstretched length of 0.2 m. A 0.2 kg mass hanging from the spring stretches it to an equilibrium length of 0.3 m. Suppose the mass is pulled down to where the spring’s length is 0.5 m. When it is released, it begins
to oscillate. What is the amplitude of the oscillation?
in physics class, carrie learns that a force, f, is equal to the mass of an object, m, times its acceleration, a. she writes the equation f
The acceleration of the object can be calculated using the formula f = ma. With a force of 7.92 N and a mass of 3.6 kg, the acceleration is approximately 2.2 m/s².
According to Newton's second law of motion, the force acting on an object is equal to the product of its mass and acceleration. The formula is represented as f = ma, where f is the force, m is the mass, and a is the acceleration.
Given that f = 7.92 N and m = 3.6 kg, we can substitute these values into the equation and solve for a.
f = ma
7.92 N = 3.6 kg * a
To find the value of a, we can rearrange the equation:
a = f / m
a = 7.92 N / 3.6 kg
a ≈ 2.2 m/s²
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tia phản xạ trên gương phẳng nằm trong cùng mặt phẳng với:
Answer:
can anyone translate
Explanation:
because i cant read this
What important example, shown in the picture, is given regarding a real-life
connection to these elements?
Answer:
Explanation:
There is no picture!
A spacecraft can be regarded as a uniform cylinder, \(1 \mathrm{~m}\) in diameter and of mass \(250 \mathrm{~kg}\). It is spinning about its cylindrical axis with a period of \(3 \mathrm{~s}\).
(a) What is the angular momentum of this isolated system?
The angular momentum of this isolated system is 78.75 kgm²/s.
What is angular momentum?The angular momentum (L) is defined as the distance of the object from a rotation axis multiplied by the linear momentum.
L = mvr
where;
m is mass of the cylinderv is the velocity of the cylinderr is the radius of the cylinderv = 2πr/T
where;
T is the period of oscillationv = (2π x 0.5) / 3
v = 0.63 m/s
L = mvr
L = 250 kg x 0.63 m/s x 0.5 m
L = 78.75 kgm²/s
Thus, the angular momentum of the isolated system depends on the mass and speed of the spacecraft.
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a centrifuge in a forensic investigation laboratory rotates at an angular speed of 3,800 rev/min, clockwise (when viewed from above). when switched off, it rotates through 48.0 revolutions before coming to rest. assuming it is constant, what is the magnitude of angular acceleration (in rad/s2)?
The magnitude of the angular acceleration of the centrifuge is approximately 68.7 rad/s^2.
To solve this problem, we can use the formula for the angular displacement of an object
θ = ω_i t + 1/2 α t^2
where θ is the angular displacement, ω_i is the initial angular velocity, α is the angular acceleration, and t is the time.
In this case, we know that the initial angular velocity ω_i is 3,800 rev/min. To use this in the formula, we need to convert it to radians per second
ω_i = (3800 rev/min) x (2π rad/rev) x (1/60 min/s) = 397.89 rad/s
We also know that the final angular velocity ω_f is 0, since the centrifuge comes to rest. Therefore, we can use the formula for the final angular velocity in terms of the initial angular velocity, angular acceleration, and time
ω_f = ω_i + α t
Since ω_f is 0, we can solve for the time it takes for the centrifuge to come to rest
0 = ω_i + α t
t = -ω_i / α
We also know that the angular displacement of the centrifuge is 48 revolutions, or 96π radians (since 1 revolution = 2π radians). Plugging in the values we know and solving for α, we get
96π = (397.89 rad/s) (-397.89/α) + 1/2 α (-397.89/α)^2
96π = -397.89^2/α + 1/2 α (-397.89)^2/α^2
96π = -397.89^2/α + 1/2 (-397.89)^2/α
α = 397.89^2 / (2 x 96π)
α ≈ 68.7 rad/s^2
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Value analysis of (DEWA) Dubai Electricity & Water Authority ?
Value analysis is a method used to evaluate the worth and effectiveness of an organization or project.
In the case of DEWA (Dubai Electricity & Water Authority), conducting a value analysis can provide insights into the overall value created by the organization. Here are some key points to consider in a value analysis of DEWA:
1. Service Quality: Evaluate the quality and reliability of the electricity and water services provided by DEWA. Assess factors such as uptime, response time, customer satisfaction, and the overall impact on the daily lives of residents and businesses in Dubai.
2. Cost Efficiency: Analyze the cost-effectiveness of DEWA's operations, including the generation, transmission, and distribution of electricity, as well as water production and distribution. Assess the efficiency of resource utilization, cost management practices, and the impact on consumer tariffs.
3. Sustainability: Evaluate DEWA's commitment to sustainable practices, such as renewable energy integration, water conservation efforts, and environmental stewardship. Assess the organization's contributions to reducing carbon emissions and promoting a greener future.
4. Innovation and Technology: Assess DEWA's adoption of innovative technologies, such as smart grids, advanced metering systems, and digital solutions. Evaluate the impact of these technologies on service delivery, efficiency, and customer experience.
5. Stakeholder Engagement: Analyze DEWA's relationships with stakeholders, including customers, suppliers, government entities, and the community. Assess the effectiveness of communication, collaboration, and the organization's contribution to social and economic development in Dubai.
By conducting a comprehensive value analysis of DEWA, stakeholders can gain a holistic understanding of the organization's performance, impact, and value proposition. This analysis can guide decision-making, identify areas for improvement, and support DEWA's ongoing efforts to provide reliable, sustainable, and affordable electricity and water services to the residents and businesses of Dubai.
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What force causes centripetal acceleration of a car making a turn on a flat road?
The force that causes centripetal acceleration of a car making a turn on a flat road is friction
The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.
Fc = f
m v² / r = μ N
Fc ∝ 1 / r
The larger the centripetal force the the smaller the radius of curvature.
Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction
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Question 11 (5 points)
If a force of 10.8 newtons is applied to an object that has a mass of 4.6 kg, what will
be the object's acceleration?
*Include ABBREVIATED units in your answer
*Round your answer to 1 decimal place
Answer:
2.3 m/s2
Explanation:
F = ma
a = F/m
a = 10.8 / 4.6
a = 2.3 m/s2
I hope this helps.
a lever is used to lift a heavy load. when a 50-n force pushes one end of the lever down 1.2 m, the load rises up 0.2 m. calculate the weight of the load.
Answer:
The weight of the load can be calculated by using the principle of mechanical advantage of a lever. The mechanical advantage of a lever is the ratio of the force exerted on the load (F_L) to the force applied to the lever (F_A). In this case, the mechanical advantage of the lever is given by the ratio of the distance the load moves (0.2 m) to the distance the force is applied (1.2 m), or MA = 0.2/1.2 = 1/6.
So the force exerted on the load (F_L) is 6 times the force applied to the lever (F_A) and the weight of the load can be calculated as:
Weight of the load (F_L) = Mechanical advantage x Applied force (F_A)
F_L = (1/6) * 50 N = 8.33 N
So the weight of the load is 8.33 N.
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In which scenario will the two objects have the least gravitational force between them? A. Mass of object 1 = 12 kg Mass of object 2 =12 kg Distance between objects =1.5 m B. Mass of object 1 =15 kg Mass of object 2 = 12 kg Distance between objects =1.5 m DC. Mass of object 1 = 15 kg Mass of object 2= 12 kg Distance between objects = 0.5 m ()D. Mass of object 1 =12 kg Mass of object 2=12 kg Distance between objects = 0.5 m
If both objects have a mass of 12 kg and are separated by 1.5 m, scenario A would have the least gravitational pull on them. (option-a)
The gravitational pull between any two objects is determined by both their masses and their separation from one another. The force of gravity is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects, according to Newton's law of universal gravitation.
We must choose the scenario with the least gravitational force among the ones provided. Let's examine each instance:
A. The weights of the first and second objects are each 12 kg, and their separation is 1.5 m.
B. Mass of object 1 = 15 kg, Mass of object 2 = 12(option-a)
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A capacitor is connected across the terminals of an ac generator that has a frequency of 440 Hz and supplies a voltage of 24 V. When a second capacitor is connected in parallel with the fi rst one, the current from the generator increases by 0.18 A. Find the capacitance of the second capacitor.
2.71 μF is the capacitance of the second capacitor.
What is voltage in simple terms?
Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).Given
Frequency of AC generator f = 440 Hz
Voltage a across capacitor Vc = 24 V
Voltage across capacitor is
Vc = I / 2 πf C 1
I = ( 2 πf C 1 ) Vc ........ ( 1)
A second capacitor is conected in parallel combination with the forst capacitor . Voltage across each capacitor is same.
Equivalent capacitance is C1 + C 2
Voltage across capacitor is
Vc = ( I + 0.18 A ) / 2 πf ( C 1 + C2 )
( I + 0.18 A ) = 2 πf ( C 1 + C2 ) * Vc
( 2 πf C 1 ) Vc + 0.18 = ( 2 πf C 1 ) Vc + ( 2 πf C 2 ) Vc
( 2 πf C 2 ) VC = 0.18
Capacitance of second capacitor is
C 2 = 0.18 A / 2πf V C
= 0.18 / 2π ( 440 ) ( 24 )
= 2.71*10-6 F
or
= ( 2.71*10-6 F )( 1 μF / 10-6 F )
= 2.71 μF
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I have this bigfoot worksheet for science. It says, "When designing an experiment, which two groups must be involved?" Can you help me?
Answer:
control group and experimental group
plz help I will give brainly to the correct answer
Answer:
D. x-rays
Explanation:
Lower frequency: Radio waves, microwaves and infrared have lower frequency than visible light. Shorter wavelength: Ultraviolet, x-rays and gamma rays have a shorter wavelength than visible light.
Problem 15.34 - Enhanced - with Feedback In a science museum, a 110 kg brass pendulum bob swings at the end of a 11.5 m -long wire. The i pendulum is started at exactly 8:00 a.m. every morning by pulling it 1.2 m to the side and releasing it. Because of its compact shape and smooth surface, the pendulum's damping constant is only 0.010 kg/s You may want to review (Page) mit Previous Answers All attempts used; correct answer displayed Here we learn how to calculate the amount of oscillations for the pendulum Part B. What is its amplitude at noon? Express your answer to two significant figures and include the appropriate units. 4 ? A-0.78 m Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining
The amplitude of the pendulum at noon is approximately 0.78 m.
To determine the amplitude of the pendulum at noon, we need to consider the effect of damping on the oscillations. The amplitude of an oscillating system gradually decreases over time due to damping.
Given that the pendulum is started at 8:00 a.m. and the damping constant is 0.010 kg/s, we can use the formula for damped oscillations:
Amplitude = initial amplitude * e^(-damping constant * time)
The time elapsed from 8:00 a.m. to noon is 4 hours or 14400 seconds.
Using the given information, the initial amplitude of the pendulum is 1.2 m.
Amplitude at noon = 1.2 m * e^(-0.010 kg/s * 14400 s) = 0.78 m
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What is the mass of a bullet moving at 970 m/s if the bullet’s kinetic energy is 3.0 x 10^3 J?
The mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
What is Kinetic Energy?Kinetic energy is simply a form of energy that a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given the data in the question;
Velocity of the bullet v = 970m/s Kinetic energy of the bullet K = 3.0 × 10³J = 3000kgm²/s²Mass of the bullet m = ?We substitute our given values into the expression above.
K = (1/2)mv²
3000kgm²/s² = 0.5 × m × (970m/s)²
3000kgm²/s² = 0.5 × m × 940900m²/s²
3000kgm²/s² = m × 470450m²/s²
m = 3000kgm²/s² ÷ 470450m²/s²
m = 0.00064kg
m = 6.4 × 10⁻⁴kg
Therefore, the mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
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723 grams to kilograms
Answer:
we know that 1 kg = 1000g
therefore ;
1g = 1/1000 kg
723g = 723/1000
= 0.723kg is answer
while at the county fair, you decide to ride the ferris wheel. having eaten too many candy apples and elephant ears, you find the motion somewhat unpleasant. to take your mind off your stomach, you wonder about the motion of the ride. you estimate the radius of the big wheel to be 15 m, and you use your watch to find that each loop around takes 25 seconds.
a. Your speed will be 0.0628 m/s
b. The magnitude of your acceleration is 0.000263 m/s2
c. The ratio of your weight at the top of the ride to your weight while standing on the ground is 99.997%
d. The ratio of your weight at the bottom of the ride to your weight while standing on the ground is 100.003%
Using the data given above,
Where:
Radius = 15 m
Time for each loop = 25 minutes (25*60 = 1500 seconds) to complete.
a. To find the speed, which is the length of each loop per unit of time to complete each loop, we use the equation for uniform velocity v where:
v = C/t
Where:
Circumfrence of the ferris wheel; C = ?
Time to go round; t = 1500s
Circumference of the Ferris wheel would be:
C = 2πR = 2π*15 = 94.25 m
v = 94.25 / 1500
v = 0.0628 m/s
b. Since the circular motion is constant, the only acceleration from the motion is the centripetal acceleration. To find the magnitude of acceleration, we use the equation for centripetal acceleration which is:
ac = v²/r
Where:
Velocity; v = 0.0628 m/s
Radius; r = 15
ac = 0.0628/15
ac = 0.000263m/s²
c. Let g = 9.8 ms². At top of the ride, the centripetal acceleration would be pushing you up, while gravity pushes you down, so the weight you experience (compare to standing on ground would be):
g-ac/g
Where
Gravity; g = 9.8ms² (a constant)
Centripetal acceleration; ac = 0.000263m/s²
9.8 - 0.000263/9.8
= 0.99997
= 99.997%
d. At the bottom of the ride, both centripetal acceleration and gravity would be pushing you downward, making you feel like
g+ac/g
Where
Gravity; g = 9.8ms² (a constant)
Centripetal acceleration; ac = 0.000263m/s²
9.8 + 0.000263/9.8
= 1.00003
= 100.003%
Here's the complete question:
While at the county fair, you decide to ride the ferris wheel. having eaten too many candy apples and elephant ears, you find the motion somewhat unpleasant. to take your mind off your stomach, you wonder about the motion of the ride. you estimate the radius of the big wheel to be 15 m, and you use your watch to find that each loop around takes 25 seconds.
a.What is your speed?
b.What is the magnitude of your acceleration?
c.What is the ratio of your weight at the top of the ride to yourweight while standing on the ground?
d.What is the ratio of your weight at the bottom of the ride toyour weight while standing on the ground?
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A slingshot consists of a light leather cup, containing astone, that is pulled back against two parallel rubber bands. Ittakes a force of 15 N to stretch either one of these bands 1.0cm.
(a) What is the potential energy stored in the two bands togetherwhen a 50-g stone is placed in the cup and pulled back 0.20 m fromthe equilibrium position?
(b) With what speed does the stone leave the slingshot?
The answer depends on the force-distance relationship for stretching the bands and the displacement of the stone from the equilibrium position.
The force required to stretch one rubber band by 1.0 cm is 15 N. Therefore, the force required to stretch it by 0.20 m is (15 N/0.01 m) * 0.20 m = 300 N.
The potential energy stored in each rubber band is given by the formula PE = (1/2) * k * \(x^2\), where k is the spring constant and x is the displacement. Since we have two rubber bands, the total potential energy stored in the two bands together is PE = 2 * (1/2) * k * \(x^2\).
Substituting the values, where k = 300 N/m and x = 0.20 m, we can calculate the potential energy:
PE = 2 * (1/2) * (300 N/m) * \((0.20 m)^2\) = 12 J.
Therefore, the potential energy stored in the two bands together when the stone is pulled back 0.20 m is 12 J.
(b) To determine the speed at which the stone leaves the slingshot, we can use the principle of conservation of mechanical energy. At the point of release, all the potential energy stored in the bands is converted into kinetic energy of the stone.
The potential energy stored in the bands is given by PE = (1/2) * m * \(v^2,\) where m is the mass of the stone and v is its velocity.
Equating the potential energy to the initial potential energy (12 J) and solving for v, we have:
(1/2) * m * \(v^2\) = 12 J.
Substituting the values, where m = 50 g = 0.05 kg, we can solve for v:
(1/2) * (0.05 kg) * \(v^2\) = 12 J.
\(v^2\) = (12 J) / (0.025 kg) = 480 \(m^2/s^2.\)
Taking the square root of both sides, we find v ≈ 21.9 m/s.
Therefore, the stone leaves the slingshot with a speed of approximately 21.9 m/s.
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PLEASE HURRY What is "a section of a chromosome that typically contains the code for a particular protein, which determines a specific trait" called?
heterozygous
genetics
species
gene
Answer:
It is a gene!!
Explanation:
It is because RNA is referred to as a gene. Genes are contained in chromosones.
what changes if the light is underwater and the light goes into air
Answer:
Therefore, when a light ray traveling through air enters water or glass it slows down, refracts, and bends toward the normal line. ... For example, when light goes from glass or water to air, it speeds up. Refraction changes how objects look.
Explanation:
The light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction. It is the change in the speed of the light that causes refraction.
How light and water affects the speed of the light?Light is slowed down in transparent media such as air, water and glass. The ratio by which it is slowed is called the refractive index of the medium and is always greater than one.Because of the physical differences in the makeup of the materials light actually travels slower through water and glass. Speed of light in a vacuum and air = 300 million m/s or 273,400 mph. Speed of light in water = 226 million m/s or 205,600 mph. Speed of light in glass = 200 million m/s or 182,300 mph.The light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction. It is the change in the speed of the light that causes refraction.
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PLEASE HELP ! ASAP !!!!!!!!!!!!
Answer:
the last option
Explanation:
1. Shelly pushes a .0035 kg marble with
a force of .07.N.
Answer:
pressure= force/area
Explanation:
pressure= 0.07/0.0035
= 20 pascal
Define kinetic energy and derive its relation.
Answer:
The kinetic energy of a body is the energy that it possessed due to its motion. Kinetic energy can be defined as the work needed to accelerate an object of a given mass from rest to its stated velocity. Kinetic energy depends upon the velocity and the mass of the body.
An object has a mass of 10 kg and it is accelerating at a rate of 12 m/s2. What is the net force causing this acceleration?
100 N
O 120 N
0 140 N
O 160 N
Answer:
net force causing acceleration is 120N
Explanation:
Given parameters:
Mass of the object = 10kg
Acceleration = 12m/s²
Unknown:
Net force of this acceleration = ?
Solution:
According to newtons second law of motion;
Force = mass x acceleration
Sine the unknown is the net force, input the parameters and solve for it;
Force = 10 x 12 = 120N
The net force causing acceleration is 120N
If a volleyball accelerates towards the ground at 10m/s/s and it takes 1.6 seconds to hit the ground, how tall is the building
Answer:
Distance, S = 12.8m
Explanation:
Given the following data;
Acceleration = 10
Time = 1.6
Initial velocity = 0
To solve for acceleration, we would use the second equation of motion;
\( S = ut + \frac {1}{2}at^{2}\)
Substituting the values into the equation;
\( S = 0(1.6) + \frac {1}{2}*10*(1.6)^{2}\)
\( S = 5 *2.56\)
Distance, S = 12.8m
Therefore, the height of the building is 12.8 meters.
Please help me fast
A house uses eight 60 W lamps for lighting. On an average, each lamp is switched on for 6 hours each day. If the electricity tariff is Rs. 15 per unit, find the cost of electricity
a) for one day
b) for the month of January
(a) The cost of electricity for one day is Rs. 42 .
(b) The cost of electricity for the month of January is Rs. 1,302.
Average energy usedThe electric energy consumed in each is calculated as follows;
E = Pt
E = 60 x 6 = 360 Wh
E(total) = 8 x 360 Wh = 2880 Wh
The cost of Electricity is in kWh
2880 Wh = 2.8 kWh
Cost of electricicty for one dayC = 2.8 kWh x (Rs. 15)/kWh
C = Rs. 42
Cost of electricity for the month of January (31 days)C = Rs.42 x 31
C = Rs. 1,302
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What is atomic composition
Answer:
The atom consists of a tiny nucleus surrounded by moving electrons. The nucleus contains protons, which have a positive charge equal in magnitude to the electron's negative charge. The nucleus may also contain neutrons, which have virtually the same mass but no charge.
Explanation: