a box of 5kg is lifted 10m. how much work is done?

The two individuals will move together with a velocity of -2 km/h.

Assuming that the initial velocity of the space shuttle is zero, and neglecting the effect of gravity, the total momentum of the system before the collision is zero, since the space shuttle and the two individuals are at rest. After the collision, the momentum of the system must still be zero, since there are no external forces acting on it.

If your buddy bumps into you and holds onto you, the two of you will move together with a common velocity.

Since your buddy has a velocity of 4 km/h with respect to the ship, the momentum of your buddy before the collision is:

momentum = mass x velocity = m x v = m x 4 km/h

To conserve momentum, the momentum of the two individuals after the collision must also be equal to m x (-4 km/h), since the momentum is opposite in direction.

Since the two individuals have the same mass, their common velocity after the collision can be calculated as:

momentum = mass x velocity = 2m x v'

where;

Therefore:

2m x v' = m x (-4 km/h)

v' = (-4 km/h) / 2 = -2 km/h

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Answer:

The first answer is in the picture

b. The box will move foward

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Impact of the car with the object. There are two collisions that happen during a crash, the first one is the impact of the car with the object and the second one is the impact of the passengers with the car's interior.

The main answer to the question is "a)

Both of these collisions are responsible for the injuries of the passengers and the extent of damage to the car. In the first collision, the car's energy is absorbed by the object or surface it collides with, causing damage to the car and the passengers inside.

The second collision is when the passengers' bodies collide with the interior of the car, including the steering wheel, dashboard, doors, windows, and so on. lt in death in severe cases.In conclusion, the main collision that happens during a crash is the impact of the car with the object, which causes damage to the car and the passengers inside.

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In a car crash, two collisions occur. The impact of the car with the object it hits, and the impact of the occupants with the interior of the car. The aim is always to lengthen these collisions to reduce the forces involved, hence reducing injuries.

During a car crash, there are primarily two collisions that happen. The first collision is the impact of the car with the object. This could be another vehicle, a tree, or a wall. The momentum of the car changes during this time, leading to an abrupt stop or change in direction. The force exerted on the car will be less if this collision time is prolonged, which is why cars are manufactured to crumple upon impact, resulting in a lengthier, less forceful collision.

The second collision occurs between the occupants of the car and the interior of the car. When the car abruptly stops or changes direction, the passengers continue to move at the original speed due to inertia. This might lead to impacts with the dashboard, windscreen, or seat in front. To decrease the force acted upon the bodies of the passengers during this second collision, car safety equipment such as seatbelts and airbags are used. These gadgets increase the collision time, hence reducing the force with which the passengers might collide with the car's interior.

Therefore, the correct response to your question would be the impact of the car with the object.

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1. A current is induced in the wire loop as a result of the changing magnetic field. 2. The direction of the current is determined by the right-hand rule.

Current is the flow of electricity through a conductor or circuit, usually measured in amperes. It is a fundamental physical quantity and is the basis of electricity. Current is generated by a battery, a generator, or an alternator. It is also generated by the movement of charged particles, such as electrons in a circuit. Current is a measure of how much energy is available in a circuit and is used to power electrical appliances, lights, and motors.

The wire loop has a certain number of turns and when the bar magnet is pushed towards the center of the loop, it creates a changing magnetic field around the loop. This changing magnetic field induces a current in the wire loop due to Faraday's law of induction. This current is known as an electromotive force (EMF). The right-hand rule is used to determine the direction of the current in the loop. Place your right hand around the loop so your thumb points in the direction of the bar magnet. Your fingers will then curl in the direction of the induced current.

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Answer:

Rounded to three significant figures:

(a) \(2 \times 575\; \rm nm = 1150\; \rm nm = 1.15\times 10^{-6}\; \rm m\).

(b) \(\displaystyle \left(1 + \frac{1}{2}\right) \times (575\;\rm nm) \approx 863\; \rm nm = 8.63\times 10^{-7}\; \rm m\).

Explanation:

Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.  

Let \(k\) denote a natural number (\(k \in \left\lbrace0,\, 1,\, 2,\, \dots\right\rbrace\).) In a double-split experiment of a monochromatic light:

The path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where \(k = 0\) in \(\text{Path difference} = 0\).

The path difference increases while moving on the screen away from the center. The first order maximum is at \(k = 1\) where \(\text{Path difference} = \lambda\).

Similarly, the second order maximum is at \(k = 2\) where \(\text{Path difference} = 2\, \lambda\). For the light in this question, at the second order maximum: \(\text{Path difference} = 2\, \lambda = 2 \times 575\; \rm nm = 1.15\times 10^{-6}\; \rm m\).

The dark fringe closest to the center of the screen is the first minimum. \(\displaystyle \text{Path difference} = \left(0 + \frac{1}{2}\right)\cdot \lambda = \frac{1}{2}\, \lambda\) at that point.

Add one wavelength to that path difference gives another dark fringe- the second minimum. \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda\) at that point.

For the light in this question, at the second order minimum: \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda = \left(1 + \frac{1}{2}\right)\times (575\; \rm nm) \approx 8.63\times 10^{-7}\; \rm m\).

Answer:

the baby would still be 30 kg on the moon because that’s mass, not weight.

However, it will feel like 5 kg, because the acceleration is 1/6 and the force is 1/6 and the actual weight (product of mass and acceleration will be 1/6).

The child has a mass of 30 kg on earth and has one-sixth gravity on the moon will have a weight of 50 kg on the moon.

Gravity is a fundamental interaction that causes all objects with mass or energy to attract one another. The weakest of the four fundamental interactions is gravity, by far. The Moon's gravity causes sublunar tides in the oceans, just as gravity on Earth imparts weight to physical objects.

Given:

The mass of the child (m) = 30 kg,

The gravity on the moon (G) = 1/6 of the earth.

To calculate the weight of the child on the moon, use the formula given below,

F = m × a

Here

\(F\) is the weight, \(m\) is the mass and \(a\) is the gravity on earth, gravity on earth \(10\ m/s^2\).

Substitute the values

\(F=30*10/6\)

\(F = 50\ kg\)

Therefore, the weight of a child on the moon is 50 kg.

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Answer:

In the medium where the angle of incedence is 10°

Explanation:

This is because angle of incedence is directly proportional to refractive index of a medium.

Since refractive index is inversely proprtional to speed of light in medium, it will be the case.

Correct option is:- C) Work is a measure of how much energy a force transfers.

Explanation:

the speed of the dog was 400

The speed of the cars just after the collision is 0.875 m/s.the formula to be used  m1u1 + m2u2 = m1v1 + m2v2.V=14000*1.5÷14000+1000=0.875m/s

Teenagers, young adults, and the others take the stimulant drug "speed" to feel more focused and alert, as well as, in some circumstances, to get high. Several types of speed are also used by some people to suppress their appetite.

Simply because they are not paying attention on their driving pace, drivers frequently go above the speed limit. Traffic flow, operating a powerful car, and listening to music were all mentioned as contributing factors. Some drivers claimed that passengers' distraction caused them to accelerate.

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Answer:

The force of gravity acting on a 10 kg object is 98N.

Explanation:

What is gravity?

How to calculate the force of gravity acting on a body?

        where F = the force of gravity

        m = mass of the object and

        g = acceleration due to gravity

It is given that

Putting these values in the equation  F = mg, we find

F = 10 kg x 9.8 m/s²

  = 98 kgm/s² or 98 N.

Therefore, the force of gravity acting on a 10 kg object is 98N.

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Explanation:

can u pls ask the question again? No full information! I mean are you required the time it takes or what ?

A basketball player running at 4.60 m/s directly towards the basket jumps into the air to dunk the ball while maintaining his horizontal velocity.

When the basketball player jumps into the air, he experiences a parabolic trajectory due to the effects of gravity. However, since he maintains his horizontal velocity, his horizontal motion remains unaffected throughout the jump.

The vertical motion of the player can be analyzed using the equations of motion under constant acceleration. The initial vertical velocity is zero, and the acceleration due to gravity is approximately 9.8 m/s². Using these values, we can calculate various parameters of the player's jump.

For instance, the time it takes for the player to reach the peak of his jump can be found using the equation v = u + at, where v is the final vertical velocity (which is zero at the peak), u is the initial vertical velocity, a is the acceleration due to gravity, and t is the time.

The maximum height reached by the player can be determined using the equation h = ut + 0.5at², where h is the height, u is the initial vertical velocity, a is the acceleration due to gravity, and t is the time.

Since the player maintains his horizontal velocity throughout the jump, his horizontal displacement remains the same, which depends on the initial horizontal velocity and the time of flight.

By solving these equations, we can obtain the specific values for the time of flight, maximum height reached, and horizontal displacement of the player during his jump.

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Answer:

4

Explanation:

Not all plants can grow flowers. Only the ones thay have buds can.

Not all plants produce flowers. Hence, this is the characteristic which is not common in all plants.Therefore, the correct option is 4.

Flowers are the structures of plants. They are responsible for producing seeds that will grow into new plants. Flowers typically consist of a colorful or ornamental part called the corolla, which attracts pollinators such as bees and butterflies, and a reproductive part called the stamen and pistil, which contain the plant's male and female organs.

Not all green plants produce flowers. Flowering plants are a type of plant that belong to the group Angiosperms, but there are also non-flowering plants like ferns and mosses that do not produce flowers. Therefore, the correct option is 4.

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The kinematic energy of the positive charge is 2 10⁻⁸ J

This electrostatics exercise must be done in parts, the first part: let's start by finding the charge of the capacitor, the capacitance is defined by

        C = \(\frac{Q}{\Delta V}\)

        C = ε₀ \(\frac{A}{d}\)

we solve for the charge (Q)

        \(\frac{Q}{\Delta V} = \epsilon_o \frac{A}{d}\)

indicates that for the initial point d₁ = 3 mm = 0.003 m and the voltage is DV₁ = 12

         Q = \(\epsilon_o \ \frac{A \ \Delta V_1 }{d_1}\)

Now the voltage source is disconnected so the charge remains constant across the ideal capacitor.

For the second part, the condenser is separated at d₂ = 5mm = 0.005 m

         Q = \epsilon_o \  \frac{A \ \Delta V_2 }{d_2}

we match the expressions of the charge and look for the voltage

          \(\frac{\Delta V_1}{d_1} = \frac{\Delta V_2}{d_2}\)

          ΔV₂ = \(\frac{d_2}{d_1 } \ \Delta V_1\)

The third part we use the concepts of conservation of energy

starting point. With the test load (q = 1 nC = 1 10⁻⁹ C) next to the left plate

          Em₀ = U = q DV₂

          Em₀ = q  \frac{d_2}{d_1 } \ \Delta V_1

final point. Proof load on the right plate

         Em_f = K

energy is conserved

         Em₀ = em_f

         q  \frac{d_2}{d_1 } \ \Delta V_1 = K

we calculate

         K = 1 10⁻⁹  12  \(\frac{0.005}{0.003}\)  

         K = 20 10⁻⁹ J

In this exercise, as the conditions at two different points of separation give, the area of ​​the condenser is not necessary and with conservation of energy we find the final kinetic energy of 2 10⁻⁸ J

The speed with which the train reaches the rock slide is 19.36 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The initial velocity of the train can be obtained as illustrated below:

–1.6 = (0 – u) / 12.1

Cross multiply

0 – u = –1.6 × 12.1

– u = –19.36

Divide both sides by –1

u = –19.36 / –1

u = 19.36 m/s

Thus, the train uses 19.36 m/s to reach the rock slide

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Answer: A standard 9V battery has about 400-600 mAh capacity. In the most basic terms, these batteries can supply about 500 milliamps for one hour before being "dead". With electricity, we measure the amount of charge flowing through the circuit over a period of time. Current is measured in Amperes (usually just referred to as "Amps"). An ampere is defined as 6.241*10^18 electrons (1 Coulomb) per second passing through a point in a circuit. In a series circuit, amperage, or amplitude, of the current remains constant and can be calculated using Ohm's law V = I/R while the voltage drops across each resistor that can be summed up to get the total resistance.

Hope this helps........ Stay safe and have a Merry Christmas!!!!!!!! :D

The correct option is B, the most likely composition of the piece of metal is Copper.

Density = Mass / Volume

The metal's volume is determined by:

Volume = (5.0 mm) x (15.0 mm) x (30.0 mm) = \(2.25 \times 10^-5 m^3\)

Therefore, the density of the metal is:

Density = 0.0200 kg / (\(2.25 \times 10^-5 m^3\)) = \(888.9 kg/m^3\)

Density is a physical property of matter that describes how much mass is contained within a certain volume. It is defined as the amount of mass per unit volume of a substance. In other words, density is the measure of how tightly packed the particles of a substance are. The units of density are typically grams per cubic centimeter (g/cm3) or kilograms per cubic meter (kg/m3).

The density of a substance can provide useful information about its physical and chemical properties. For example, the density of a material can be used to identify it, and it can also give insight into its strength, durability, and other characteristics. Additionally, the density of a substance can affect its behavior in various environments, such as its buoyancy in water or its ability to conduct heat and electricity.

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Complete Question:-

You purchase a rectangular piece of unknown metal from a thrift store that has dimensions 5.0 mm by 15.0 mm by 30.0 mm. At home you determine the mass to be 0.0200 kg. What is the most likely composition of the piece of metal?

a. Silver

b. Copper

c. Iron

d. Brass

It is also important to note that conductor 2 will now be at a different potential than it was before the charged rod was brought near. It is at the same potential that it was before the charged rod was brought near. Option E

When the negatively charged rod is brought near the initially uncharged conductors 1 and 2, the conductors will experience a redistribution of charges due to induction. The negative charges on the rod will repel the electrons in the conductors, causing them to move away from the rod and towards the opposite end of the conductors.
When conductor 2 is moved to the right by pushing its stand, it becomes electrically isolated from conductor 1. This means that the excess negative charges that were induced on conductor 2 by the negatively charged rod will remain on it, and there will be no further redistribution of charges between the conductors. Therefore, the correct answer is C. Conductor 2 is negatively charged.
It is important to note that the magnitude of the charge on conductor 2 cannot be determined without additional information. However, we do know that it has a negative charge due to the induction caused by the negatively charged rod. Additionally, we can conclude that conductor 1 is positively charged since it has lost electrons to conductor 2 during the induction process.

Finally, it is also important to note that conductor 2 will now be at a different potential than it was before the charged rod was brought near. Option E is correct.

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a. The lowest frequency fmin,1 that gives the minimum signal (destructive interference) at the listener’s location is 25.5 Hz.

b. The number must fmin,1 be multiplied to get the second lowest frequency fmin,2 which gives a minimum signal is 1.60.

c. The third lowest frequency fmin,3 that gives minimum signal is 61.5 Hz.

d. The lowest frequency fmax,1 that gives a maximum signal (constructive interference) at the listener’s location is 51.2 Hz.

e. The number must fmax,1 be multiplied to get the second lowest frequency fmax,2 which gives the maximum signal is 1.99.

f. The third lowest frequency fmax,3 that gives maximum signal is 154 Hz

a. To find the lowest frequency fmin, we use the formula for destructive interference is:

2d /λ = (m + 1/2)

Where d is the distance between the two loudspeakers, λ is the wavelength, and m is an integer. Thus,  λ = 2d / (m + 1/2).

For the lowest frequency, m = 0, therefore:

λ = 2 × 3.35 / (0 + 1/2) = 13.4 m, and

fmin, 1 = v / λ = 343 / 13.4

= 25.5 Hz

b. The second lowest frequency fmin,2 that gives minimum signal is (m = 1)

λ = 2d / (m + 1/2)

λ = 2 × 3.35 / (1 + 1/2)

= 8.38 m

fmin,2 = v / λ = 343 / 8.38 = 40.9 Hz

fmin,2/fmin,1 = 40.9/25.5

= 1.60

c. The third lowest frequency fmin,3 that gives minimum signal is (m = 2)

λ = 2d / (m + 1/2)

λ = 2 × 3.35 / (2 + 1/2)

= 5.57 m

fmin,3 = v / λ = 343 / 5.57

= 61.5 Hz

d. The lowest frequency fmax,1 that gives the maximum signal (constructive interference) at the listener’s location is 239 Hz. The formula for constructive interference is:

2d /λ = m

Where m is an integer. Thus, λ = 2d / m.

For the lowest frequency, m = 1, therefore:

λ = 2 × 3.35 / 1 = 6.70 m, and

fmax,1 = v / λ = 343 / 6.70

= 51.2 Hz

e. The second lowest frequency fmax,2 that gives maximum signal is (m = 2)

λ = 2d / m

λ = 2 × 3.35 / 2 = 3.35 m

fmax,2 = v / λ = 343 / 3.35

= 102 Hz

fmax,2/fmax,1 = 102/51.2

= 1.99

f. The third lowest frequency fmax,3 that gives the maximum signal is (m = 3)

λ = 2d / m

λ = 2 × 3.35 / 3 = 2.23 m

fmax,3 = v / λ = 343 / 2.23

= 154 Hz

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A. Assume incompressible flow

Since volumtric flow rate will be same in both section

Q1 = Q2

A1*V1 = A2*V2

V2 = A1*V1/A2

V2 = 6.9*10^-4*288*10^-2/(3.3*10^-4)

V2 = 6.02 m/sec

B. using bernoulli's equation:

P1/rho + v1^2/2 + g*h1 = P2/rho + v2^2/2 + g*h2

Since pipes are horizontal

h1 = h2

P1/rho + v1^2/2 = P2/rho + v2^2/2

P2 = P1 + (v1^2 - v2^2)*rho/2

P2 = 1.5*10^5 + (2.88^2 - 6.02^2)*1100/2

P2 = 1.35*10^5 Pa

The rate of change in position of an object in any course. Speed is measured because the ratio of distance to the time wherein the distance became included. Speed is a scalar amount because it has handiest route and no significance.

Velocity can be notion of as the rate at which an object covers distance. A quick-moving object has a high speed and covers a notably big distance in a given amount of time, whilst a sluggish-shifting item covers a relatively small amount of distance in the same amount of time.

The primary unit or the S.I. unit of velocity is m/s or ms?¹.

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The difference (d) and standard deviation (sg) help to determine whether there is a consistent change in body temperature between the two time points and how varied those changes are among the subjects.

However, it seems that the data for the temperatures at both times are not provided completely. I can still explain the terms you mentioned.
d: In this context, 'd' likely represents the difference between the paired measurements (temperature at 8 AM minus temperature at 12 AM) for each subject. You would calculate this value for each subject using the provided data.

sg: This is likely referring to the standard deviation of the differences (d). Standard deviation is a measure of the dispersion or spread of data points in a dataset. In this case, sg would give an indication of how consistently the body temperature changed from 8 AM to 12 AM across the five subjects.
In general, the difference (d) and standard deviation (sg) help to determine whether there is a consistent change in body temperature between the two time points and how varied those changes are among the subjects.

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The force produced by the train's engine will be 175000N.

Force is an external agent that has the power to alter an object's state of motion or rest. In a brief, force is a vector quantity that's also defined as a push or pull exerted on an object as a result of the object's contact with another object. The Newton (N) is the unit of force F.

F = ma

Here, F  is force, m is mass and a is acceleration of the object.

We are given here,

The force by the train weight = \(Fw\) =  150,000N

The force creates by the friction = \(F_{f}\) = 25,000N

Thus , to get the total force of the train's engine by adding force by weight and force by friction is given as,

\(F_{t} = F_{w}+ F_{f}\)

Then for getting total force of the train's engine putting above values in the expression ,

\(F_{t} = 150,000 N +25,000N\\F_{t} = 175,000N\)

Hence, the train’s engine has to produce 175000N force to become in equilibrium.

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Answer:

The circuit in series has a greater resistance.

Explanation:

The current is forced to flow throw two resistors instead of just one as it if it were in parallel.

The acceleration due to gravity on the surface of the Moon is 1.635 m/s² and on the surface of Venus is 8.8634 m/s².

There is acceleration, gravitational force, and acceleration due to gravity, all three are completely different from each other.

We know that the acceleration of gravity on the moon = 1/6 acceleration of gravity on the Earth

Therefore, the acceleration of gravity on the surface of the moon is given as

= 9.81 / 6

= 1.635 m/s²

b) For any planet (Venus) the acceleration of gravity is given as

g = GM/ R²

G = 6.67 × 10⁻¹¹

M = 4.88 × 10²⁴

R = 6.06 × 10⁶

g = ( 6.67 × 10⁻¹¹)(4.88 × 10²⁴) / (6.06 × 10⁶)²

g = 8.634 m/s²

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(a) The trip covers a total distance of 6.0 + 4.0 + 2.0 = 12.0 km, so the jogger's average speed is (12.0 km)/(2.0 h) = 6.0 km/h.

(b) The jogger undergoes a total displacement given by the vector

(6.0 km) i + (4.0 km) j + (-2.0 km) i = (4.0 km) (i + j)

where i is the unit vector pointing due East and j is the unit vector pointing due North. This vector has magnitude

||(4.0 km) (i + j)|| = (4.0 km) √(1² + 1²) ≈ 5.7 km

so the jogger's average velocity is approximately (5.7 km)/(2.0 h) ≈ 2.8 km/h.

The rocket that launched the satellite utilized two rocket stages and onboard thrusters to maneuver the satellite into orbit. The two rocket stages worked sequentially to provide the initial thrust and ascent, while the onboard thrusters were responsible for fine adjustments and orbital maneuvers.

The first stage of the rocket is typically the largest and most powerful. It provides the initial thrust needed to lift the rocket and satellite off the ground. Once the first stage has burned out and expended its fuel, it is jettisoned to reduce weight and allow the second stage to take over.

The second stage of the rocket continues the ascent, carrying the satellite further into space. It may use a different type of engine or fuel to optimize performance in the upper atmosphere or vacuum of space. After the second stage has completed its burn, it is also discarded.

Once the rocket stages have completed their roles, the satellite is in a suborbital trajectory. The onboard thrusters, often powered by smaller engines or even electric propulsion systems, take over to fine-tune the orbit and perform necessary maneuvers such as circularization and orientation adjustments. These thrusters provide the necessary thrust and control to place the satellite into its intended orbit and maintain its position throughout its operational lifetime.

Therefore, the combination of two rocket stages and onboard thrusters enables the rocket to deliver the satellite into its desired orbit by providing the necessary initial thrust, ascent, and subsequent orbital adjustments.

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