a bus with a maximum speed of 20m/s takes 21 sec to travel 270m from stop to stop. Its acceleration is
twice as great as its deceleration.
Find:
A, the acceleration
B, the distance traveled at maximum speed

The acceleration can be calculated using the formula:

Acceleration = (Final velocity - Initial velocity) / Time taken

Given that the bus starts from rest, the initial velocity is 0 m/s.

Acceleration = (20 m/s - 0 m/s) / 21 sec = 20/21 m/s².

The distance travelled at maximum speed can be calculated by subtracting the distances covered during acceleration and deceleration from the total distance.

Distance during acceleration = (1/2) * acceleration * time² = (1/2) * (20/21 m/s²) * (21 sec)² = 210 m.

Distance during deceleration is the same as distance during acceleration.

Distance travelled at maximum speed = Total distance - 2 * distance during acceleration = 270 m - 2 * 210 m = -150 m.

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The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores

Explanation:

In magnetic elements, each atom’s magnetic domains are aligned which creates magnetic force. In nonmagnetic elements, each atom’s domains are pointing in the different directions so, resulting element has nonmagnetic force.

Attraction or repulsion that arises between electrically charged particles because of their motion is called magnetic force and it is the basic force responsible for such effects as action of electric motors and also attraction of magnets for iron.

Magnetism is caused by motion of electric charges. Every substance is made up of tiny units called atoms and each atom has electrons, particles that carry electric charges. Spinning like tops, electrons circles the nucleus, or core, of an atom.

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Sound travels through air at a speed of around 350 m/s in a room that is about 5 m wide.

Frequency is the number of waves that pass a specific area in a defined amount of time. As a result, the frequency is 2 per second if a wave travels through in half a second. If it takes 1/100 of an hour, the frequency is 100 times per hour.

Frequency is defined as the rate of changes in current direction per second. It is given in hertz (Hz), an internationally recognized unit of measurement. One cycle per second is equal to one hertz. Cycles per second are represented by the unit hertz (Hz).

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Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, \(V_T = 60 \ m/s\)

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

\(F_D = kV_T^2\)

Where;

k is a constant

\(k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}\)

When the new drag force is half of the original drag force;

\(F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}= \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}= 0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s\)

Therefore, the speed of the resistive force is 42.426 m/s

At terminal speed, the speed of the resistive force will be:

"42.426 m/s".

According to the question,

Skydriver's mass, m = 75 kg

Terminal velocity, \(V_T\) = 60 m/s

Constant = k

We know the relation,

→ \(F_D\) = k\(V_T^2\)

here, k = \(\frac{F_D_1}{V_T_1^2} = \frac{F_D_2}{V_T_2^2}\)

Now,

  \(F_D_2\) = \(\frac{F_D_1}{2}\)

  \(\frac{F_D_1}{V_T_1^2}= \frac{F_D_2}{V_T_2^2}\)

   \(\frac{1}{V_T_1^2} = \frac{1}{2V_T_2^2}\)

By applying cross-multiplication,

  \(V_T_2^2 = \sqrt{\frac{V_T_1^2}{2} }\)

By substituting the above values,

  \(V_T_2\) = 0.7071 (\(V_T_1\))

        = 0.7071 × 60

        = 42.426 m/s

Thus the above response is correct.

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The highest point of a roller coaster is almost always the first hill. In the majority of roller coasters, the hills get smaller as the train travels down the track.

To find the answer, we have to know more about the mechanical energy of a system.

                  Mechanical energy = U = mgh

Where m represents the car mass, g represents gravity, and h represents height

Finally, by applying the principle of energy conservation, we may determine that, the initial hill must be the highest.

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The point where the object's speed is one-half its final speed may located at 3/4 of the initial height of the object, the answer would be "lower than the midpoint of the path."

Assuming the object is subject to a constant acceleration due to gravity, the speed of the object at any given point can be described by the following equation:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity

a = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)

s = distance traveled

Let's suppose the object is dropped from rest at a height h above the ground. Then its initial velocity is u=0, and the equation simplifies to:

v² = 2gh

where g is the acceleration due to gravity and h is the initial height of the object.

To find the point at which the object's speed is one-half its final speed, we can set v = 1/2 * √(2gh) and solve for s:

1/2 * √(2gh) = √(2gh - 2gs)

Simplifying this equation, we get:

1/4 * 2gh = 2gh - 2gs

s = 3/4 * h

This means that the point where the object's speed is one-half its final speed is located at 3/4 of the initial height of the object. Therefore, the answer is "lower than the midpoint of the path."

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Answer:

When the same amount of heat is added to cold sand and cold water, the temperature change of sand will be higher because of its lower specific heat capacity.

What is specific heat capacity?

Specific heat capacity is the quantity

of heat required to raise a unit mass of

a substance by 1 kelvin.

Specific heat capacity of water and sand

{refer to the above attachment}

Δθ = Q/mc

Thus, for an equal mass of water and sand, when the same amount of heat is added to cold sand and cold water, the temperature change of sand will be higher because of its lower specific heat capacity.

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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Answer:

B) All elements are made of a single type of atom.

Explanation:

Elements are made up of a single type of atom and are bound together chemically. Elements cannot be broken down further by chemical or physical means.

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3.17 x 10^-8 Newtons is the required gravitational force between them.

The gravitational force between two objects is given by the formula:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (6.6743 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between the centers of mass of the two objects.

In this case, the masses of the man and the woman are:

m1 = 80 kg

m2 = 65 kg

The distance between them is:

r = 10 m

Plugging these values into the formula, we get:

F = 6.6743 x 10^-11 * (80 kg * 65 kg) / (10 m)^2

F = 3.17 x 10^-8 Newtons

Therefore, the attractive gravitational force between the man and the woman is approximately 3.17 x 10^-8 Newtons.

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Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.

(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.

(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?

For part (a):

The magnitude of an electric field can be given as  \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.

So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)

An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.

For part (b):

We know that...

- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).

- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).

- \(\vec F_e=q\vec E\)

- \(\vec F =m\vec a\)

\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)

\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)

Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)

\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)

\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)

The distance from the positive plate we'll call, "D."

\(D=0.20+\Delta \vec x\)

\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)

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(a) The work done by the applied force is 32.6 J.

(b) The work done by gravity on the block is 29.4 J.

(c) The magnitude of the normal force is 29.4 N.

The force applied to the block is determined by applying the formula for the net force on the block.

F(net) = 0

Fcosθ - mg - Fsinθμ = 0

Fcosθ - Fsinθμ = mg

F(cosθ - sinθμ) = mg

F = (mg) / (cosθ - sinθμ)

F = (3 x 9.8) / (cos26  -  0.2 x sin26)

F = 36.25 N

The work done by the applied force is calculated as;

W = Fd cosθ

W = (36.25 x 1) x cos(26)

W = 32.6 J

The work done by gravity on the block is calculated as follows;

W = mgd

W = 3 x 9.8 x 1

W = 29.4 J

The magnitude of the normal force is calculated as follows;

N = mg

N = 3 x 9.8

N = 29.4 N

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Explanation:

India. Total wealth: $8.9 trillion | Wealth per capita: $6,440 | India, which is the fifth-largest economy in the world, is home to 3,57,000 HNWIs and 128 billionaires.

Answer:

50505050128128128128

Explanation:

Answer:

5N

Explanation:

The net force= force applied - friction force

10 - 5

= 5N

The banking angle is the angle that the surface makes with the horizontal, or the angle of inclination.

v = √rg tanθ

tanθ=v²/rg  

The relation gives the angle of banking of the cyclist going round the curve. Here v is the speed of the cyclist, r is the radius of the curve, and g is the acceleration due to gravity.

The banking angle is the angle that the surface makes with the horizontal, or the angle of inclination. The normal force acting on the car while travelling through such a curving road has a horizontal component. The centripetal force needed to prevent skidding is provided by this component.

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The density of the metal sphere is 2 times the density of the liquid as proved.

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:Lack of experience.

Explanation:

Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.

Answer:

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Answer:

A. The rays can change molecules and atoms in the body into ions.

Answer:

Fossil fuels are energy sources that come directly from nature. First, the sun's radiant energy is stored as chemical energy in plants by photosynthesis. When the plants die, they start decaying. After many years, the plants are turned into fossil fuels.

Explanation:

Fossil fuels rely on the Sun's energy because the energy in fossil fuels came from plants and algae as they performed photosynthesis, which requires sunlight.

When sunlight strikes a plant, some of the energy is trapped through photosynthesis and is stored in chemical bonds as the plant grows.

(u should paraphrase it)

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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Answer:

false. the medium never moves

Explanation:

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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