The centripetal force acting on the car, after the calculations is 3750 Newtons
To calculate the centripetal force acting on the car, we can use the formula:
Centripetal force (Fc) = (mass of the car) × (centripetal acceleration)
Given:
Mass of the car (m) = 1500 kg
Radius of the curve (r) = 250 m
Speed of the car (v) = 90 km/hr
First, we need to convert the speed from km/hr to m/s:
Speed (v) = 90 km/hr × (1000 m/1 km) × (1 hr/3600 s)
= 25 m/s
Next, we calculate the centripetal acceleration (ac):
Centripetal acceleration (ac) = (velocity squared) / (radius)
= (v^2) / r
Substituting the values:
Centripetal acceleration (ac) = (25 m/s)^2 / 250 m
= 625 m^2/s^2 / 250 m
= 2.5 m/s^2
Finally, we calculate the centripetal force (Fc):
Centripetal force (Fc) = (mass) × (centripetal acceleration)
= 1500 kg × 2.5 m/s^2
= 3750 N
Therefore, the centripetal force acting on the car is 3750 Newtons.
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What factors affect an objects kinetic energy?
Answer:
friction
air drag
every thing that opposes the motion affects kinetic energy
Explanation:
kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest
potential energy ∝ 1/(kinetic energy)
as kinetic energy increases potential energy decreases
9. A bicyclist is moving down a hill. Her position on the hill gives her 720 J of potential energy, and her
movement gives her 680 J of kinetic energy. What is her total mechanical energy?
A. 260 J
B. 1400 J
C. 2648 J
D. 2.86×105 J
The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.
The total mechanical energy of a moving object is the sum of its kinetic energy and potential energy. Kinetic energy is defined as the energy an object has due to its motion, whereas potential energy is the energy an object has due to its position or configuration.Therefore, the total mechanical energy of the bicyclist is calculated by adding her kinetic energy and potential energy. According to the question, the bicyclist has 720 J of potential energy and 680 J of kinetic energy.Total mechanical energy = Potential energy + Kinetic energy = 720 J + 680 J = 1400 JTherefore, the total mechanical energy of the bicyclist is 1400 J. Therefore, the correct answer is option B.For more questions on mechanical energy
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What time is the lunar eclipse tonight in california?
A particle moves in a straight line with the given velocity v(t) = 3t2 − 30t + 63 (in meters per second). Find the displacement and distance traveled over the time interval [0, 10].?
The displacement over the time interval [0, 10] is -130 meters, and the distance traveled is 130 meters.To find the displacement and distance traveled over the time interval [0, 10] for the particle with velocity v(t) = 3t^2 - 30t + 63, we need to integrate the velocity function.
The displacement is given by the definite integral of the velocity function over the interval [0, 10]:
Displacement = ∫[0, 10] (3t^2 - 30t + 63) dt
To calculate this integral, we need to find the antiderivative of the velocity function. Taking the antiderivative of each term, we get:
Displacement = t^3 - 15t^2 + 63t | [0, 10]
Now we substitute the upper and lower limits of integration:
Displacement = (10^3 - 15(10)^2 + 63(10)) - (0^3 - 15(0)^2 + 63(0))
Simplifying the expression:
Displacement = (1000 - 1500 + 630) - (0 - 0 + 0)
Displacement = -130 meters
The displacement over the time interval [0, 10] is -130 meters.
To find the distance traveled, we take the integral of the absolute value of the velocity function over the interval [0, 10]:
Distance = ∫[0, 10] |3t^2 - 30t + 63| dt
This involves evaluating the integral separately for the positive and negative parts of the velocity function. However, since the velocity function is always positive over the interval [0, 10], the distance traveled is equal to the displacement, which is 130 meters.
Therefore, the displacement over the time interval [0, 10] is -130 meters, and the distance traveled is 130 meters.
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Consider the percentage differences between the total momentum before the collision and the total momentum after the collision for the various trials of Collisions [, II; and III: [f they are less than 10%, they are good evidence that momentum is conserved and if they are less than 5%, they are very good evidence: To what extent do your data indicate that momentum is conserved?
Based on the information provided, it seems that the question is related to a physics experiment involving collisions. The question asks about the percentage differences between the total momentum before and after the collision, and whether these differences indicate that momentum is conserved.
In physics, momentum is defined as the product of mass and velocity. When two objects collide, they exchange momentum, and the total momentum of the system should remain constant if no external forces act on the system. This is known as the principle of conservation of momentum. In the experiment described in the question, the collisions were conducted in three different trials, labeled I, II, and III. For each trial, the percentage difference between the total momentum before and after the collision was calculated. If the difference was less than 10%, it was considered good evidence that momentum was conserved. If the difference was less than 5%, it was considered very good evidence. Based on the data collected, it can be determined to what extent momentum was conserved in the different trials. If the percentage differences were within the acceptable range (i.e., less than 10% or less than 5%), it would suggest that momentum was conserved in those trials. However, if the differences were greater than 10%, it would indicate that momentum was not conserved, and there may be external forces acting on the system that are affecting the momentum. Therefore, without knowing the actual percentage differences obtained in the experiment, it is not possible to determine to what extent momentum was conserved. The data collected would need to be analyzed to determine whether momentum was conserved in each of the three trials.
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A hiker moves 15 km due east then heads 8 km due west. What is the direction of the resultant vector?
Answer:
east
Explanation:
15km east
_______________
X________
8km west
so you are where the xX is so you are still in the eastward direction
A marble on a frictionless track, starting from point A in the drawing, is projected down the curved runway. (This means that the initial speed of the particle is NOT zero!) Upon leaving the runway at point B, the particle is traveling straight upward and reaches a height of 5.00 m above the floor before falling back down. Ignoring air resistance, find the initial speed of the particle (v0) at point A.
Answer:
v = 4.4 m / s
Explanation:
Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.
Starting point. Point A
Em₀ = K + U = ½ m v2 + mg y_a
point B.
Em_f = U = m g y
the energy is conserved
Em₀ = Em_f
½ m v² + mg y_a = m g y
½ m v² = m g (y -y_a)
v = \(\sqrt {2g ( y - y_a)}\)
In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m
v = \(\sqrt{ 2 \ 9.8 ( 5 -4)}\)
v = 4.4 m / s
A spring with spring constant 58N/cm is stretched 4cm. How much force is it applying
Answer:
232 N
Explanation:
By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so
F = kx
Where F is the force, k is the spring constant and x is how much it is stretched.
So, replacing k by 58N/cm and x by 4 cm, we get
F = (58 N/cm)(4 cm)
F = 232 N
Therefore, the force applied is 232 N
A corona is a circle of light that can be seen around the Moon during a solar eclipse.
O True
False
Particles q1 = + 8.0 uc q2 = + 3.5 uc and q3 = - 2.5 uc are in a line. Particles q1 and q2 are separated by 0.10 m and particles q2 and q3 are separated by 0.15 m what is the net force on particle q2
The net electrostatic force acting on the charged particle q₂ is 28.7 N.
Charge on the first particle, q₁ = 8 μC
Charge on the second particle, q₂ = 3.5 μC
Charge on the third particle, q₃ = - 2.5 μC
Distance between the charges q₁ and q₂, r₁ = 0.1 m
Distance between the charges, q₂ and q₃, r₂ = 0.15 m
Electrostatic force exerted on the charged particle q₂ and q₁,
F₁ = 1/4πε₀ (q₁q₂/r₁²)
F₁ = 9 x 10⁹ x (8 x 10⁻⁶ x 3.5 x 10⁻⁶)/(0.1)²
F₁ = 25.2 N
Electrostatic force exerted on the charged particle q₂ by q₃,
F₂ = 1/4πε₀ (q₂q₃/r₂²)
F₂ = 9 x 10⁹ x (3.5 x 10⁻⁶x -2.5 x 10⁻⁶)/(0.15)²
F₂ = -78.75 x 10⁻³/22.5 x 10⁻³
F₂ = -3.5 N
The net electrostatic force acting on the charged particle q₂ is,
F = F₁ - F₂
F = 25.2 - -3.5
F = 25.2 + 3.5
F = 28.7 N
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A student places five books next to each other on their ends. She then pushes the first book with her finger, and a few seconds later, the last book falls. Which statement is correct about this chain of events?(1 point) There is a correlation between the force of the finger and the placement of the books. The acceleration of the books as they fall causes the force of the finger. The force of the finger causes the books to accelerate and fall. There is causation between the force of the finger and the placement of the books.
Answer:
The force of the finger causes the books to accelerate and fall.
Explanation:
Answer:
Explanation:
1.) A line of dominos is knocked down. Which explanation is true?
ANSWER: An increase in force caused an increase in acceleration.
2.) When raindrops form, the force of gravity pulls them toward the ground. Which statement is correct about this chain of events?
ANSWER: The force of gravity causes the raindrops to accelerate.
3.) A student observes that for the same net force, heavier objects accelerate less. Which statement describes a correct conclusion?
ANSWER: There is a negative correlation between mass and acceleration.
There is a negative correlation between mass and acceleration.
4.) A nonzero net force acts on a moving ball, and the ball comes to a stop. Which statement is correct about the relationship between the net force and the ball's movement?
ANSWER: The net force causes a decrease in acceleration because without the force the ball's velocity would remain the same.
5.) A student places five books next to each other on their ends. She then pushes the first book with her finger, and a few seconds later, the last book falls. Which statement is correct about this chain of events?
ANSWER: The force of the finger causes the books to accelerate and fall.
I hope this helps <33
how deep under water would you need to be in order to be at double atomosphric pressure
Answer:
You would need to be 33 feet deep.
Explanation:
A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
Please provide the formula and the working
Answer:
Explanation:
The equation for acceleration is
\(a=\frac{v_f-v_0}{t}\) where vf is the final velocity and v0 is the initial velocity. For us, the final velocity is 25 m/s and the initial is 0 because the train started from resting position. Filling in and solving for a:
\(a=\frac{25-0}{30.0}\) so
a = .83 m/s/s
on a distance time graph, an increasing line that the speed of the object is increasing and therefore the acceleration is
The acceleration will be zero when speed is plotted against time.
As the velocity slope is a straight line when distance time graph is considered. Straight slope indicates increasing velocity constantly with time.
Acceleration:
The rate of change of velocity with respect to time. it is a vector quantity (both magnitude and direction). SI unit of acceleration is given as meter/second square
speed= Distance/Time
Acceleration = velocity/ Time
acceleration is equal to differentiation of velocity with time.
(differentiation of constant= zero)
differentiation of constant velocity gives zero acceleration.
Thus the graph with constant velocity acceleration will be zero.
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Select all the correct answers. Which three statements are true about the energy flow in an ecosystem?.
An ecosystem has a single path of energy flow. Plants absorb energy from the sun, which is then transferred to organisms that eat plants, which are then transferred to organisms that eat those organisms, and so on. An ecosystem as a whole experiences a straight, unidirectional flow of energy as a result.
What is the ideal energy flow within ecosystems?Sunlight is converted into chemical energy or food by producers. When consumers eat producers, they absorb some of that energy. When eaten, they also transfer some of their energy to other consumers. Energy moves from one living creature to another in this way.
Which of the following energy-related statements is accurate?According to the Law of Conservation of Energy, energy cannot be created or destroyed.
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what is the difference between passive and active range of motion
Answer:
Passive range of motion can be defined as what is achieved when an outside force, such as a therapist, causes movement of a joint. It is usually the maximum range of motion. Active range of motion is what can be achieved when opposing muscles contract and relax, resulting in joint movement
A hill that has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal
The angle of incline of the hill above the horizontal is 8.81°.
Since the hill has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction.
Tangent of the angle of the incline of the hill,The tangent of the angle of the incline of the hill, Ф is
tanФ = vertical rise/horizontal distance = grade of hill
Now, the vertical rise = 15.5 m and the horizontal distance = 100.0 m
So, substituting the values of the variables into the equation, we have
tanФ = vertical rise/horizontal run
tanФ = 15.5 m/100.0 m
tanФ = 0.155
Angle of incline of the hill
Taking inverse tan of both sides, we have
Ф = tan⁻¹(0.155)
Ф = 8.81°
So, the angle of incline of the hill above the horizontal is 8.81°.
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1. Define and compare the process of external and internal respiration
2. Summarise the physical principles controlling air movement in and out of the lungs and muscles responsible
3. Summarise the physical principles of gas diffusion in and out of blood and body tissues
4. Summarise the function of haemoglobin and transport of oxygen and carbon dioxide in the blood
5. Describe age-related changes in the respiratory system
1. External respiration refers to the exchange of gases (oxygen and carbon dioxide) between the lungs and the external environment. It involves inhalation of oxygen-rich air into the lungs and the diffusion of oxygen into the bloodstream, while carbon dioxide diffuses out of the bloodstream into the lungs to be exhaled.
Internal respiration, on the other hand, is the exchange of gases between the blood and the body tissues. It occurs at the cellular level, where oxygen diffuses from the blood into the tissues, and carbon dioxide diffuses from the tissues into the blood.
2. Air movement in and out of the lungs is governed by the principles of pressure gradients and Boyle's law. During inhalation, the diaphragm and intercostal muscles contract, expanding the thoracic cavity and decreasing the pressure inside the lungs, causing air to rush in. During exhalation, the muscles relax, the thoracic cavity decreases in volume, and the pressure inside the lungs increases, causing air to be expelled.
3. Gas diffusion in and out of blood and body tissues is facilitated by the principle of concentration gradients. Oxygen moves from areas of higher partial pressure (in the lungs or blood) to areas of lower partial pressure (in the tissues), while carbon dioxide moves in the opposite direction. The exchange occurs across the thin walls of capillaries, where oxygen and carbon dioxide molecules passively diffuse based on their concentration gradients.
4. Hemoglobin is a protein in red blood cells that binds with oxygen in the lungs to form oxyhemoglobin. It serves as a carrier molecule, transporting oxygen from the lungs to the body tissues. Additionally, hemoglobin also aids in the transport of carbon dioxide, binding with it to form carbaminohemoglobin, which is then carried back to the lungs to be exhaled.
5. Age-related changes in the respiratory system include a decrease in lung elasticity, reduced muscle strength, and decreased lung capacity. The lungs become less efficient in gas exchange, leading to reduced oxygen uptake and impaired carbon dioxide removal. The respiratory muscles may weaken, affecting the ability to generate sufficient airflow. These changes can result in decreased respiratory function and increased susceptibility to respiratory diseases in older individuals.
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Which statement best expresses Newton's second law of motion?
A: The acceleration of an object depends on the balance between the net applied forces.
B: The acceleration of an object depends on the balance between friction and gravity.
C: The acceleration of an object depends on the object's mass and the net applied force.
D: The acceleration of an object depends on the object's mass and its velocity.
Answer:
option C
since F=ma
the acceleration of an object depends on the object's mass and the net applied force
a device consists of eight balls each of mass 0.6 kg attached to the ends of low-mass spokes of length 1.4 m, so the radius of rotation of the balls is 0.7 m. the device is mounted in the vertical plane. the axle is held up by supports that are not shown, and the wheel is free to rotate on the nearly frictionless axle. a lump of clay with mass 0.20 kg falls and sticks to one of the balls at the location shown, when the spoke attached to that ball is at 45 degrees to the horizontal. just before the impact the clay has a speed 7 m/s, and the wheel is rotating counterclockwise with angular speed 0.24 radians/s.
Answer:
First, let's find the initial angular momentum of the system before the clay hits the ball. Since the wheel is rotating counterclockwise, the direction of the angular momentum is into the page (out of the screen). The initial angular momentum of the system is:
L1 = Iω1
where I is the moment of inertia of the wheel and ω1 is its initial angular velocity.
The moment of inertia of the wheel can be calculated using the formula:
I = Σmr^2
where Σmr^2 is the sum of the products of the mass of each ball (m) and the square of its distance from the center of the wheel (r). Since all the balls are equidistant from the center, we can simplify this to:
I = 8m(0.7)^2 = 3.136m
where m is the mass of each ball.
Substituting the given values, we get:
I = 8(0.6)(0.7)^2 = 1.176 kg·m^2
The initial angular velocity is ω1 = 0.24 rad/s. Therefore:
L1 = Iω1 = (1.176 kg·m^2)(0.24 rad/s) = 0.28224 kg·m^2/s
When the clay hits the ball, it sticks to it, and the ball starts to rotate with the same angular velocity as the wheel. Let ω2 be the final angular velocity of the system after the collision. Then the final angular momentum of the system is:
L2 = Iω2 + mvR
where m is the mass of the clay, v is its velocity just before the collision, and R is the distance of the point of impact from the center of the wheel.
Substituting the given values, we get:
L2 = (1.176 kg·m^2)ω2 + (0.20 kg)(7 m/s)(0.7 m)
L2 = 1.176ω2 + 0.588 kg·m^2/s
Since angular momentum is conserved, we have L1 = L2. Equating the two expressions for L and solving for ω2, we get:
ω2 = (L1 - 0.588 kg·m^2/s) / 1.176 kg·m^2
ω2 = (0.28224 kg·m^2/s - 0.588 kg·m^2/s) / 1.176 kg·m^2
ω2 = -0.2214 rad/s
The negative sign indicates that the direction of the angular velocity is clockwise, opposite to the initial direction of rotation. Therefore, the final angular velocity of the system after the collision is 0.2214 rad/s clockwise.
Finally, we can calculate the new kinetic energy of the system after the collision. The initial kinetic energy is:
K1 = (1/2)Iω1^2
Substituting the given values, we get:
K1 = (1/2)(1.176 kg·m^2)(0.24 rad/s)^2 = 0.03372 J
The final kinetic energy is:
K2 = (1/2)Iω2^2
Substituting the calculated value of ω2, we get:
K2 = (1/2)(1.176 kg·m^2)(0.2214 rad/s)^2 = 0.01408 J
Therefore, the new kinetic energy of the system after the collision is 0.01408 J.
Therefore, the new kinetic energy of the system after the collision is 0.01408 J.
First, let's find the initial angular momentum of the system before the clay hits the ball. Since the wheel is rotating counterclockwise, the direction of the angular momentum is into the page (out of the screen). The initial angular momentum of the system is:
L1 = Iω1
where I is the moment of inertia of the wheel and ω1 is its initial angular velocity.
The moment of inertia of the wheel can be calculated using the formula:
I =
where Σ\(mr^2\) is the sum of the products of the mass of each ball (m) and the square of its from the center of the wheel (r). Since all the balls are equidistant from the center, we can simplify this to:
I = \(8m(0.7)^2\) = 3.136m
where m is the mass of each ball.
Substituting the given values, we get:
I = \(8(0.6)(0.7)^2 = 1.176 kg * m^2\)
The initial angular velocity is ω1 = 0.24 rad/s. Therefore:
Since angular momentum is conserved, we have L1 = L2. Equating the two expressions for L and solving for ω2, we get:
\(w2 = (L1 - 0.588 kgm^2/s) / 1.176 kgm^2\\w2 = (0.28224 kgm^2/s - 0.588 kgm^2/s) / 1.176 kgm^2\\w2 = -0.2214 rad/s\)
The negative sign indicates that the direction of the angular velocity is clockwise, opposite to the initial direction of rotation. Therefore, the final angular velocity of the system after the collision is 0.2214 rad/s clockwise.
Finally, we can calculate the new kinetic energy of the system after the collision. The initial kinetic energy is:
K2 = \((1/2)Iw_2^2\)
Substituting the calculated value of ω2, we get:
K2 = \((1/2)(1.176 kgm^2)(0.2214 rad/s)^2 \\= 0.01408 J\)
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Describe how the properties of sound waves change as they spread out in a spherical pattern.
To solve this we must be knowing each and every concept related to sound waves. Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.
What is sound waves?A sound is a type of energy or a vibration that moves through a material such as air or water. Sound may pass through with a gaseous medium as well. It is anything that is audible. The speed that sound varies depending on the medium.
A wave is a medium that transmits energy from one location to another. Waves are classified into three types: transverse waves, longitudinal waves, or surface waves. A sound waves change as they spread out in a spherical pattern, they go up and down.
Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.
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For this object, what color will you observe?
Answer:
blue
Explanation:
blue is the only color being reflected, meaning it's the only one that will be visible
1) Identify a source of interest to you. Provide the bibliographic information for the reader.
2) Summarize the source in at least two well developed paragraphs. Identify the main point of the article as well as the evidence advanced in support of it.
3) Significance. Identify the significance of the source—why is it important?—what practical or theoretical consequences might follow from the main point?—what limitations, objections, or weaknesses might be present that could serve to undermine the significance of the source?
4) Explain what you learned about philosophy as a whole; would you recommend that our class address the themes covered in the source? Why or why not?
5) Recommendation: One a scale of 1-5, with five being the highest, rank the quality and importance of this article. Be sure to explain your ranking.
https://aeon.co/essays/natural-laws-cant-be-broken-but-can-they-be-defined
The significance of a source in research is crucial as it determines the reliability and validity of the information presented. A credible source is important because it ensures that the information presented is accurate and trustworthy.
Using sources that are not credible or reliable can lead to the spread of misinformation, which can have practical consequences such as wrong decisions and actions based on incorrect information. Theoretical consequences could include flawed research or faulty arguments. It is important to consider the limitations, objections, or weaknesses of a source, as these can undermine its significance. This includes evaluating factors such as bias, sample size, and methodology used in the research.
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--The complete Question is, Identify the significance of the source—why is it important?—what practical or theoretical consequences might follow from the main point?—what limitations, objections, or weaknesses might be present that could serve to undermine the significance of the source?--
Show your work: zero credit for this question. pieces and the lengths are 49.19 cm and 49.93 cm. What is the total Taguchi quality cost of these two pieces of metal? a) The Taguchi parameter T is $/cm^2
(round your response to two decimal places). b) The Taguchi Quality Cost of the second metal rod is $ (round your response to two decimal places). c) The Taguchi Quality Cost of the first metal rod is $ (round your response to two decimal places). d) What is the total Taguchi Quality Cost of that sample of two units? \$ (round your response to two decimal places).
To calculate the Taguchi quality cost, we need to multiply the length of each piece by the Taguchi parameter T, and then sum up the costs.
Given:
Length of the first metal rod = 49.19 cm
Length of the second metal rod = 49.93 cm
a) Taguchi parameter T:
Since we don't have the specific value of T, we cannot calculate it.
b) Taguchi Quality Cost of the second metal rod:
Taguchi Quality Cost = Length of the second metal rod * Taguchi parameter T
c) Taguchi Quality Cost of the first metal rod:
Taguchi Quality Cost = Length of the first metal rod * Taguchi parameter T
d) Total Taguchi Quality Cost of the two units:
Total Taguchi Quality Cost = Taguchi Quality Cost of the first metal rod + Taguchi Quality Cost of the second metal rod
Since we don't have the Taguchi parameter T, we cannot calculate the specific values for parts (b), (c), and (d).
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The populations P (in thousands) of a particular county from 1971 through 2014 can be modeled byP = 71.7e0.0345twhere t represents the year, with t = 1 corresponding to 1971.(a) Use the model to complete the table. (Round your answers to the nearest whole number.)YearPopulation1980101240 Correct: Your answer is correct.1990142949 Correct: Your answer is correct.2000201843 Correct: Your answer is correct.2010285000 Correct: Your answer is correct.(b) According to the model, when will the population of the county reach 350,000?2018 Incorrect: Your answer is incorrect.
ANSWERS
(a) Year - Population
• 1980 - 101,240
,• 1990 - 142,949
,• 2000 - 201,843
,• 2010 - 285,000
(b) 2016
EXPLANATION
(a) The population (in thousands) each year is given by,
\(P=71.7\cdot e^{0.0345t}\)If t = 1 represents year 1971, then for each year we have to find the difference between the year and 1970.
For year 1980,
\(P=71.7\cdot e^{0.0345(1980-1970)}\approx101.240\)The population is 101,240.
For year 1990,
\(P=71.7\cdot e^{0.0345(1990-1970)}\approx142.949\)The population is 142,949.
For year 2000,
\(P=71.7\cdot e^{0.0345(2000-1970)}\approx201.843\)The population is 201,843.
For year 2010,
\(P=71.7\cdot e^{0.0345(2010-1970)}\approx285.000\)The population is 285,000.
(b) In this problem we're given the population 350,000 and we have to find in what year the county will reach that population. In other words, we have to find t and then add that to 1970 to find the year.
Let's solve for t,
\(P=71.7\cdot e^{0.0345t}\)Divide both sides by 71.7,
\(\begin{gathered} \frac{P}{71.7}=\frac{71.7}{71.7}\cdot e^{0.0345t} \\ \frac{P}{71.7}=e^{0.0345t} \end{gathered}\)Apply natural logarithm to both sides,
\(\begin{gathered} \ln \frac{P}{71.7}=\ln e^{0.0345t} \\ \ln \frac{P}{71.7}=0.0345t \end{gathered}\)Divide both sides by 0.0345,
\(\begin{gathered} \frac{\ln \frac{P}{71.7}}{0.0345}=\frac{0.0345t}{0.0345} \\ \frac{\ln\frac{P}{71.7}}{0.0345}=t \end{gathered}\)And finally replace P and solve. Remember that P is in thousands of years, so we have to replace it by 350,
\(t=\frac{\ln \frac{350}{71.7}}{0.0345}=45.955\approx46\)This is 46 years after 1970,
\(1970+46=2016\)Let's see what's the population in 2016 to check the answer,
\(P=71.7\cdot e^{0.0345(2016-1970)}\approx350.546\)It is a bit more than 350,000. But let's see what's the population in 2015,
\(P=71.7\cdot e^{0.0345(2015-1970)}\approx338.658\)In 2015 population of the county won't reach 350,000. Thus, the county will have a population of 350,000 in 2016
a stone is thrown vertically upward with a speed of 24.0 m/s. how fast is it moving when it reaches.
Answer: When it reaches what?
Explanation: Provide more info.
3x+5=40 solve for x to get the answer.
This is question isnt real i just need to talk
with someone
Explanation:
3x=40-5
3x=35
x=35/3
x=11.66 or x=11 2/3
According to the Standard Model of Particle Physics, a meson is composed of (A) a quark and a muon neutrino (B) a quark and an
According to the Standard Model of Particle Physics, a meson is composed of (B) a quark and an antiquark. The mesons are the particles that are composed of two quarks.
They are made up of one quark and one antiquark, which binds them together via the strong nuclear force. According to the Standard Model of Particle Physics, a meson is composed of (B) a quark and an antiquark.The Standard Model of Particle Physics is a theory of particle physics that explains the behavior of subatomic particles in terms of fundamental particles and interactions. It consists of three types of particles: quarks, leptons, and bosons.Mesons are subatomic particles that are composed of two quarks.
They are made up of one quark and one antiquark, which binds them together via the strong nuclear force. Mesons are classified according to their quark composition. They are made up of a combination of up, down, and strange quarks, as well as their respective antiquarks.In conclusion, the answer to the question is that according to the Standard Model of Particle Physics, a meson is composed of a quark and an antiquark.
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A Student missed the bus and had to walk 2 miles West to school. They got detention and missed the bus back, so they had to walk 2 miles East to get home. What is the total Distance the student traveled?
If you add 2 miles from west then 2 miles east then it would 4 miles all together.
a 0.10 kg mass is attached to a string 0.75 m long and swings in a horizontal circle, revolving once every 0.80 s.how much tension is in the string?
The tension in the string is 4.62N
What is tension in a spring system?When an external force operates at one of the ends of a rope or string, tension, a form of force (pulling force), emerges down the length of the string or rope. The string's tension has an opposing effect to the external force. One type of force is the tension in a rope. Therefore, the units of tension are equivalent to the units of force.As a result, the CGS unit is dyne while the SI unit of tension is Newton (N).Using the three tension force formulas mentioned above, it is simple to determine a rope's tension at mechanical equilibrium.
Given
m = 0.10
l = 0.75
t = 0.80
v = 2πr/t
tension, T = mv^2/t = 4.62 N
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