A car of mass 2000 kg is moving with a constant velocity of 10 m/s due east. What is the momentum of the car?

Answer:

Yes, in case of uniform velocity

Explanation:

This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.

Since, acceleration is defined as the rate of change of velocity.

Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.

a = ΔV/t = 0/t

a = 0 m/s²

So, the acceleration of the body is 0 m/s², but it has a uniform velocity

Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.

The formula for the position at time t is x(t) = A\(e^{rt}\)cos(ωt) + B\(e^{rt}\)sin(ωt), where A and B are constants, r is the damping coefficient, and ω is the angular frequency.

The motion is critically damped.

The graph of x(t) on the interval [-0.3, 1.5] will show the position of the weight over time.

(a) To find the formula for the position at time t, we can start by considering the general equation of motion for a damped harmonic oscillator: mx'' + cx' + kx = 0, where m is the mass, c is the damping coefficient, k is the spring constant, and x is the position. In this case, we have a weight of 4 lb and a damping force of Fd = 2.5x'. By comparing coefficients, we can determine that m = 4 lb, c = 2.5, and k = 24 lb/in.

Solving for the roots of the characteristic equation, we find that r = -c/2m = -2.5/8 = -0.3125. The angular frequency ω is calculated as ω = sqrt(k/m) = sqrt(24/4) = 3. Using these values, the general solution can be written as x(t) = A\(e^{rt}\)cos(ωt) + B\(e^{rt}\)sin(ωt), where A and B are constants.

(b) The motion is critically damped when the damping coefficient is equal to the critical damping value, which is given by 2sqrt(km). In this case, the critical damping value is 2sqrt(24*4) ≈ 9.798. Since the damping coefficient c = 2.5 is less than the critical damping value, the motion is critically damped.

(c) To graph x(t) on the interval [-0.3, 1.5], we can choose appropriate values for A and B based on the initial conditions. Since the weight is pulled down 8 in from its equilibrium position and released from rest, we can set x(0) = -8 and x'(0) = 0. Substituting these values into the general solution, we can solve for A and B. Once we have determined the values of A and B, we can plot the graph of x(t) using a suitable software tool like Desmos, setting the time interval from -0.3 to 1.5.

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Answer:

a or b

Explanation:

Answer:

The answer is C, condensation or large amounts of water vapor and the second question is correct too.

Explanation:

The coefficient of linear expansion of the coin is 2.87 × 10⁻⁶ / °K.

The coefficient of linear expansion (α) can be calculated using the formula:

  α = ΔL / (L₀ × ΔT)

Where ΔL is the change in length, L₀ is the original length, and ΔT is the change in temperature.

Given:

We need to convert the temperature change from °F to °K, since the coefficient of linear expansion is usually expressed in terms of Kelvin. We can use the formula:

  ΔT (°K) = ΔT (°F) × 5/9

  ΔT (°K) = 75 × 5/9

  ΔT (°K) = 41.67

Now we can plug in the values into the formula for the coefficient of linear expansion:

  α = ΔL / (L₀ × ΔT)

  α = (2.20 × 10⁻⁵) / ((1.75 × 10⁻²) × 41.67)

  α = 2.87 × 10⁻⁶ / °K

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Answer:

4

Explanation:

Impact Force = mv/2t

Impact force is inversely proportional to t

If m and v are constant and the only thing that changes is t, then:

0.005 s increases by a factor of 4 to 0.020 s

Therefore, impact force reduces by a factor of 4 (1/4 less than when the time of impact was 0.005 s)

(a) To find the magnetic field at a distance of 50.0 cm from a straight wire carrying 1200 A, we can use the formula B = (μ0I)/(2πr), where B is the magnetic field, μ0 is the permeability of free space (4π x 10^-7 Tm/A), I is current, and r is the distance from the wire. Plugging in the values, we get B = (4π x 10^-7 Tm/A) x (1200 A)/(2π x 0.5 m) = 4.8 x 10^-3 T.

The magnetic field at a distance of 50.0 cm (0.5 m) from a straight wire carrying 1200 A, we can use the formula for the magnetic field produced by a long, straight current-carrying conductor: B = (μ₀ * I) / (2 * π * r), where B is the magnetic field, μ₀ is the permeability of free space (4π x 10⁻⁷ T m/A), I is the current (1200 A), and r is the distance from the wire (0.5 m).

B = (4π x 10⁻⁷ T m/A * 1200 A) / (2 * π * 0.5 m)
B ≈ 4.8 x 10⁻⁴ T

(b) If the wires to and from the drive mechanism are side by side, we can use the formula B = (μ0I)/(2πd), where d is the distance between the wires. Plugging in the values, we get B = (4π x 10^-7 Tm/A) x (2400 A)/(2π x 0.5 m) = 9.6 x 10^-3 T. This is twice the field of a single wire because the currents in the wires are in the same direction, which adds to the magnetic field.

When the wires to and from the drive mechanism are side by side, their magnetic fields will partially cancel each other out due to opposite directions of the current flow. The net magnetic field will be the difference between the individual fields produced by each wire.

B_net = |B₁ - B₂|

Assuming the currents in both wires are equal (1200 A), the magnetic fields will be the same, and B_net = 0 T.


(c) The magnetic field from the wires could affect the accuracy of a compass on the submarine that is not shielded. The compass needle would align with the magnetic field, so if the wires are close to the compass, the needle could be deflected from its true north position. In addition, the magnetic field could induce electrical currents in nearby metal objects, which could cause interference with other electronic equipment on the submarine. To minimize these effects, the submarine would need to use shielding to block the magnetic field from the wires and ensure that the compass and other equipment are properly calibrated and shielded.

The magnetic field produced by the current-carrying wires can interfere with a compass on the submarine if it's not shielded. When the wires are separated, the magnetic field is significant (4.8 x 10⁻⁴ T) and may cause deviations in the compass reading. However, when the wires are side by side, their magnetic fields cancel out, reducing the interference with the compass. It's essential to shield the compass or take precautions to account for these magnetic field variations to ensure accurate navigation.

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Answer:

this frequency is in the near UV range

Explanation:

The accelerated movement of a charge creates an electromagnetic wave, the speed of the wave is the speed of light

         c = λ f

the emitted frequency is f = 10⁶ 10⁹ Hz = 10¹⁵5 hz,

light of this frequency is in the near UV range

     Mach number is "the ratio of the speed of a body to the speed of sound in the surrounding medium" (Oxford Languages). Put simply, it's a ratio comparing the local flow velocity to the speed of sound in the medium.

     It is represented with the following formula. M is the mach number, u is the local flow velocity, and c is the speed of the sound in the medium.

                  \(\boxed{\displaystyle M=\frac{u}{c} }\)

Answer: A

Explanation: A neutral atom has an equal number of protons and electrons.

The potential at the origin due to the five identical point charges is 52.2 volts.

To find the potential at the origin due to the five point charges, we can use the formula for the potential due to a point charge:

V = k * (Q / r)

where V is the potential, k is the electrostatic constant (k = 9 × 10^9 Nm²/C²), Q is the charge, and r is the distance from the charge to the point where the potential is being calculated.

Calculating the potential for each charge individually:

V₁ = k * (Q / r₁) = (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 2 m)

V₂ = k * (Q / r₂) = (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 3 m)

V₃ = k * (Q / r₃) = (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 4 m)

V₄ = k * (Q / r₄) = (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 5 m)

V₅ = k * (Q / r₅) = (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 6 m)

Since the potential is a scalar quantity, we can simply add up the potentials due to each charge to get the total potential at the origin:

V = V₁ + V₂ + V₃ + V₄ + V₅

Calculating the values and summing them up:

V = (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 2 m) + (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 3 m) + (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 4 m) + (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 5 m) + (9 × 10^9 Nm²/C²) * (20 × 10^(-9) C / 6 m)

Simplifying the expression and evaluating:

V = 18 + 12 + 9 + 7.2 + 6

V = 52.2 volts

Therefore, the potential at the origin due to the five identical point charges is 52.2 volts.

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Answer:

B Raise the object farther off the ground

Answer:

it contains nitrogen, potassium and phosphorus

Explanation:

the fertilisers contain nitrogen potassium and phosphorus . this makes the plants and algae grow faster.

Answer:

An online UPS.

Explanation:

An online UPS is a type of uninterruptible power supply uses AC power to continuously charge its battery, while also providing power to devices through the battery. It combines the inverter and rectifier to provide power to the alternating current (AC) load while supplying alternating current (AC) power during an outage to the load through the inverter.

Basically, an uninterruptible power supply unit is used to provide constant power supply to an electrical device, especially during a power outage.

The angular acceleration is -1.33 revolutions per second.

The angular acceleration can be calculated using the following formula:
Angular acceleration (α) = (Final angular velocity - Initial angular velocity) / Time


Initial angular velocity = 1200 revolutions per minute (rpm) = 20 revolutions per second (rps)
Final angular velocity = 0 revolutions per second (rps)
Time = 15 seconds
Angular acceleration (α) = (0 - 20) / 15 = -1.33 revolutions per second squared (rps2)

Moreover, the temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration. A rigid body's points all share the rotating velocity and acceleration. Here, The rotation is in the clockwise direction and the angular acceleration is negative.

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Answer:

For any given motion, the distance is

Explanation:

Explanation:

Given:

v₀ = 5.0 m/s

a = 2.5 m/s²

Equation:

Δx = v₀ t + ½ at²

Δx = (5.0 m/s) t + ½ (2.5 m/s²) t²

Δx = 5t + 1.25t²

Make a table of data using 1.0 increments for t.

Graph the data.  See included image.

Answer:

build the resilience of the society physically, socially and economically.

Explanation:

They actually build the resilience of the society , physically or socially or economically All three .

Answer:

= 24.76m

= 2476 cm

Explanation:

18 meters from point of origin = 18m north 90 degrees?

17 meters from point of origin = 17m west 0 degrees?

                                                                                                        _

If these routes are one after the other then we get a triangle  |

18 side and 17 side

This means we need to do Pythagoras Theorem.

18^2 + 17^2 = c^2

sqrt 324 + sqrt 289 =  c^2

c^2 = sqrt 613 = 24.7588368

= 24.76m

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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Answer:

Count the number of hydrogen and oxygen atoms on each side of the arrow.

Explanation:

Answer:

Explanation:

always accerelation it measures in m/second sguared.

Answer:

Voltage across 3 resistor =13.5v

Explanation:

Voltage=resistance *Current

But we don't have total current, so we must find total current

Current =v/R

Current=9/2

Current =4.5I

From

V=R*I

V=3*4.5

V=13.5v

The helicopter is moving at a velocity of 8.5 km/h in the north direction with respect to the ground.

The velocity of the helicopter with respect to the ground is calculated as follows;

Velocity of helicopter in the north direction = 5 km/h

Velocity of clouds moving past the ground = 3.5 km/h in the north direction

Vr/g = Vn + Vc

where;

Vr/g = 5 km/h + 3.5 km/h

Vr/g = 8.5 km/h

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a. The final pressure is 1.39 atm.

b. The final temperature is 80.4 °C.

The final pressure can be calculated using the adiabatic expansion equation:

P₂/P₁ = (V₁/V₂)^(γ)

where P₁, V₁, and P₂, V₂ are the initial and final pressures and volumes, respectively, and γ is the adiabatic index, which is 1.4 for diatomic gases like O2.

Substituting the given values, we get:

P₂/2.5 atm = (1/2)^(1.4)

P₂ = 1.39 atm

Therefore, the final pressure is 1.39 atm.

The final temperature can be calculated using the adiabatic expansion equation:

T₂/T₁ = (V₁/V₂)^(γ-1)

Substituting the given values, we get:

T₂/443.15 K = (1/2)^(0.4)

T₂ = 353.4 K

Therefore, the final temperature is 80.4 °C.

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Answer:

A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. Animal cells simply have a cell membrane, but no cell wall.

hope this helps :)

Answer:

Compare animal cell and plant cell: Both are eukaryotic cells, both contain membrane bound organelles. Both contain similar membranes such as cytosol and cytosketal elements.

Explanation:

Answer:

Explanation:

Power = mgh/t

           = 1500 * 9.8 * 14 / 600 = 343 watts

Answer:

Power = 343 watts

Explanation:

The formula we use,

→ P = (m × g × h)/t

Then the required power will be,

→ P = (m × g × h)/t

→ P = (1500 × 9.8 × 14)/600

→ P = 205800/600

→ [ P = 343 watts ]

Hence, the answer is 343 watts.