A car with weight of 7,656newton is moving with 43.13km/h. The driver applies thebreaks to stop the car in 9.38seconds. The magnitude of theforce (in newton) needed tostop the car is:

Measure the angle of the sun at the same time, on the same day every month for twelve months.

A slanted axis is around which the Earth is revolving. Or, to say it another way, our earth is perpetually leaned over and never stands erect.

Over the course of a year, this lean does not drastically alter in direction, but over thousands of years, it does so gradually.

The Earth leans periodically towards the sun and sometimes away from it as it moves through space in its orbit.

Because of the sun's bigger and more direct angular position over us during the summer, there is a greater amount of direct solar radiation, which warms the air. We receive less direct solar energy during the winter because of the sun's reduced angle and smaller surface area, making it colder.

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The velocity in the first and the second case will be 1.8028 and 5.408 m/sec.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

Given data:

Kinetic energy, KE=26 J

Mass,m=16 kg

The velocity is obtained as;

\(\rm KE= \frac{1}{2}mv^2 \\\\ v=\sqrt{\frac{2KE}{m} } \\\\ v=\sqrt{\frac{2 \times 26}{16} } \\\\v=1.8028 \ m/sec\)

The second stone has mass and nine times the kinetic energy:

\(\rm KE= \frac{1}{2}mv^2 \\\\ v'=\sqrt{\frac{9\times 2KE}{m} } \\\\ v=\sqrt{9 \times \frac{2 \times 26}{16} } \\\\v=5.408 \ m/sec\)

Hence the velocity in the first and the second case will be 1.8028 and 5.408 m/sec.

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The coefficient of kinetic friction on material B is greater than material A, causing an increase in net force on block 2.

The coefficient of kinetic friction between block 1 and material B is greater than that between block 1 and material A, which causes an increase in the net force acting on block 2 as block 1 slides from material A to material B.

This is because the increased friction on material B results in a greater opposing force to the motion of block 1, which in turn causes a greater tension force on the string and therefore a greater net force on block 2.

This effect is due to the properties of the different materials and the interaction between the materials and the block, which ultimately determine the amount of friction present and the resulting force acting on the system.

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Answer: a = 0.647 m/s^2

Explanation:

Acceleration = change in speed / time → a = 22 / 34 → a = .647 m/s^2

Answer:

Therefore the friction Force is 65 N.

Explanation:

Look at the image above.

The frictional force of the rubber block is 63.7N.

Friction is defined as a force that opposes the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are many types of friction such as dry friction which is defined as the force that opposes the relative lateral motion of two solid surfaces in contact.

This friction force is directed in the opposite direction to the motion of the object itself because the friction described so far between surfaces in relative motion is called kinetic friction.

For above given information,

mass of the block, m =10kg

coefficient of friction, µ=0.65

f=coefficient of the friction ×normal= µ*R

R= normal =mg = 9.8×10=98N

So, f =0.65×98=63.70N

≈65N(when g is taken as 10m/s²)

Thus, the frictional force of the rubber block is 63.7N.

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Answer:

True!

Explanation:

The total energy of a system can increase only if energy enters the

system.

option A.

The law of conservation of energy states that in a chemical reaction or an isolated system, the energy of the system is neither created nor destroyed but can be converted from one form to another.

The statements that are not true about  the law of conservation of energy are;

Thus, the only true statement is;

The total energy of a system can increase only if energy enters the

system.

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Answer:

The speed of the rock when it strikes the ground is 34.55 m/s

Explanation:

Given;

height of the building, h = 15 m

initial velocity of the rock, V₀ = 30 m/s

angle of projection, θ = 33°

The velocity of the rock before it strikes the ground, can be calculated from vertical component of the velocity and horizontal component of the velocity.

Vertical component of the velocity,\(V_y\)

\(V_y^2 = (V_oSin \theta)^2 + 2gh\\\\V_y^2 = (30Sin \ 33)^2 + 2(9.8)(15)\\\\V_y^2 = 266.93 + 294\\\\V_y = \sqrt{560.93} \\\\V_y = 23.684 \ m/s\)

Horizontal component of the velocity, \(V_x\)

\(V_x = V_0 Cos\theta\\\\V_x = 30Cos33\\\\V_x = 25.161 \ m/s\)

The velocity of the rock when it strikes the ground, V

\(V = \sqrt{V_y^2 + V_x^2} \\\\V = \sqrt{23.684^2 + 25.161^2} \\\\V = 34.55 \ m/s\)

Therefore, the speed of the rock when it strikes the ground is 34.55 m/s

Let M n stand for an n-dimensional upper triangular square matrix. On n, we apply induction. There is no evidence to support the null hypothesis for n = 1. Assume that the assertion is accurate for n 1 and n > 1.

What is accurate ?

English language learners The definition of exact is the absence of faults or mistakes and the capacity to provide correct outcomes. view the definition of accurate in the Learner's Dictionary for English Language Learners.

What does accurate proofreading mean?

being diligent; acting or acting with care and accuracy: a thorough proofreader. [Latin: accrtus, done with care; accrre, to do with care] Ad-, ad- + crre, to care for (form cra, care; see cure) Accuracy (noun) Fifth Edition of the American Legacy® Lexicon of the English Language.

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Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Answer:

Below

Explanation:

The Kinetic Energy the mass has ( 1/2 mv^2) is the amount of work that must be done to bring it to a stop

work = 1/2 (2 kg) ( 7 m/s)^2 = 49 J

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Explanation:

pressure=density of water × gravity ×height

=1000×9.8×20=196,000N/m^2

=196000/1000=196kpa which is almost 200kpa

The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.

In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.

Motion is a change in position of an object over the  time and is described in terms of displacement, distance, velocity, acceleration, time and speed.

Change in position of a body with time when compared with another body is known as  motion.

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The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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Answer:

Iodine is most similar  to the other non- metals in the Halogen Family, such as Fluorine, Chlorine, Bromine, Astatine .

Explanation:

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

1.25 m

Explanation:

Constant Acceleration Equations (SUVAT)

\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the ball separately.

As the ball rolls off the table with a horizontal velocity only, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 10 ms⁻²

As we need to find the vertical displacement of the ball, resolve vertically, taking ↓ as positive:

\(u=0 \quad a=10 \quad t=0.5\)

\(\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(0)(0.5)+\dfrac{1}{2}(10)(0.5)^2\\s&=0+\dfrac{1}{2}(10)(0.25)\\s&=(5)(0.25)\\ \implies s&=1.25 \; \sf m\end{aligned}\)

Therefore, the vertical displacement of the ball is 1.25 m, and so the table is 1.25 m above the floor.

Answer:

261

Explanation:

Acellus

(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.

(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;

Fg = Gm₁m₂ / R²

where;

The acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.

Force on the rock;

F = mg

where;

F = 6.6 kg x 9.8 m/s²

F = 64.68 N

The force on the pebble;

F = mg

F = 5.6 x 10⁻⁴  x 9.8

F = 5.488 x 10⁻³ N

Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

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Answer:

Acceleration = m/s²

Explanation:

T= Newtons compared to the weight W = Newtons for the hanging mass. If the weight of the hanging mass is less than the frictional resistance force acting on the mass on the table, then the acceleration will be zero.

Answer:

The magnitude of the electric field strength is 6.4 x 10⁵ N/C, directed from positive particle to negative particle.

Explanation:

Given;

charge of each particle, Q = 2 x 10⁻⁷ C

distance between the two charges, r = 15 cm = 0.15 m

distance midway between the charges = 0.075 m

The magnitude of the electric field is calculated as;

\(E_{net} = E_{+q} + E_{-q}\\\\E_{net} = \frac{kQ}{r_{1/2}^2} + \frac{kQ}{r_{1/2}^2}\\\\E_{net} = 2(\frac{kQ}{r_{1/2}^2})\\\\E_{net} = 2 (\frac{9\times 10^9 \ \times 2\times 10^{-7}}{0.075^2} )\\\\E_{net} = 6.4\times 10^5 \ N/C\)

The direction of the electric field is from positive particle to negative particle.

a. traction

If your vehicle has a high center of gravity or if the surface traction is less than ideal, it is important to enter a curve slower than the posted speed. This is because vehicles with a high center of gravity or poor surface traction are more prone to instability and are more likely to roll over or lose control when negotiating sharp turns or curves at high speeds.

Traction refers to the friction or grip between the tires of a vehicle and the road surface. Poor surface traction can be caused by a variety of factors, such as wet or slippery roads, loose gravel or debris, or worn or damaged tires. When surface traction is poor, it becomes more difficult for the tires to maintain contact with the road and to transmit the forces of acceleration, braking, and steering to the road.

By entering a curve slower than the posted speed, you can reduce the lateral forces acting on your vehicle and give your tires more time to grip the road. This can help you maintain control and stability, and reduce the risk of accidents or injuries. It is important to always adjust your speed and driving style to suit the conditions of the road and the capabilities of your vehicle.

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Explanation:

a. mm

b. μm

c. cm

d. km

e. m

f. nm

Answer:

Explanation:

b.  helmet is aerodynamic; and he is leaning down, which reduces his surface area

c.  open parachute exposes more surface area to the air, which increases the drag

9.  A and D will float because density is less than 1.0

When he pushes the object down, then lets it go, it bobs back up because of the upward force (upthrust) of the water acting on the object.

Answer:

Weight of object = 11.2 N

Apparent weight = 3.83 N     when immersed

Weight of water displaced = 11.2 - 3.83 = 7.37 N      

d (density) W / V       weight / volume      the weight density

Wo = Vo do    weight of object

Ww = Vo dw    where Ww is weight of equivalent volume of water = 7.37

Wo / Ww = do / dw    dividing previous equations

do = 11.2 / 7.37 dw = 1.52 dw

The density of the object is 1.52 that of water

The density of water is 1000 kg / m^3 * 9.8 m/s^2 = 9800 N/m^3

So the weight density is 14900 N/m^3

An irregularly shaped object weighs 11.20 N in air. When immersed in water, the object has an apparent weight of 3.83 N. It's density can be calculated as 1523 kg/m³.

To find the density, the given values are,

Weight in air = 11.20 N

Weight in water = 3.83 N

density of water = 1000 kg/m³

According to the Archimedes principle, when a body is immersed in a liquid partly or wholly, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in weight of the body.

Loss in weight of the object = Weight of object in air - weight of object in water

Loss in weight = 11.20 - 3.83 = 7.37 N

Volume of body x density of water x g = 7.37

Let V be the volume of body

V x 1000 x 9.8 =7.37

V = 7.5× 10⁻⁴ m³

Weight in air = Volume of body x density of body x g

11.20 = 7.5× 10⁻⁴ x d x 9.8

d = 1523 kg/m³.

Thus, the density of body is 1523 kg/m³.

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Answer:

77 N

Explanation:

Draw free body diagrams for each block.

The smaller block has four forces acting on it:

Weight force m₁g pulling down,

Normal force N₁ pushing up,

Friction force μN₁ pushing to the left,

and tension force T pulling to the right.

Sum of forces in the y direction:

∑F = ma

N₁ − m₁g = 0

N₁ = m₁g

N₁ = (1.2 kg) (9.8 m/s²)

N₁ = 11.76 N

Sum of forces in the x direction:

∑F = ma

T − μN₁ = m₁a

T = m₁a + μN₁

T = (1.2 kg) (3.0 m/s²) + (0.25) (11.76 N)

T = 6.54 N

The larger block has five forces acting on it:

Weight force m₂g pulling down,

Normal force N₂ pushing up,

Friction force μN₂ pushing to the left,

Tension force T pulling to the left,

and applied force F pulling 69° above the horizontal.

Sum of forces in the y direction:

∑F = ma

N₂ + F sin 69° − m₂g = 0

N₂ + F sin 69° = m₂g

N₂ + F sin 69° = (3.2 kg) (9.8 m/s²)

N₂ + F sin 69° = 31.36 N

Sum of forces in the x direction:

∑F = ma

F cos 69° − T − μN₂ = m₂a

F cos 69° − μN₂ = m₂a + T

F cos 69° − 0.25 N₂ = (3.2 kg) (9.8 m/s²) + 6.54 N

F cos 69° − 0.25 N₂ = 37.9 N

We have two equations and two variables. Solve for N₂ in the first equation and substitute into the second.

N₂ = 31.36 − F sin 69°

F cos 69° − 0.25 (31.36 − F sin 69°) = 37.9

F cos 69° − 7.84 + 0.25 F sin 69° = 37.9

F (cos 69° +0.25 sin 69°) = 45.74

0.592 F = 45.74

F = 77.3 N

Rounded to two significant figures, the magnitude of the force is 77 N.

Answer:

34.29 km/hr

Explanation:

Looking for km/hr

  so plug in the values given   120 km / 3.5 hr = 34 .29 km / hr  

                                                                                       ( 34  2/7 km/hr)