A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?

Have a great day!

Answer:

about 2000 klm per min

Explanation:

Answer:

C

Explanation:

Option C - Its displacement in a given period of time is the correct alternative.

We have the velocity of an object.

We have to find out what other quantity is needed to determine the velocity.

Velocity is defines as the rate of change of displacement with time. Mathematically -

v = Δx/Δt

According to the question -

As discussed above, velocity is the ratio of displacement and time taken to cover that displacement. Velocity is the measure of how fast a specific object is moving. Lesser the time taken to cover the distance, faster is the object as -

F \(\alpha\) 1 / t

Acceleration, weight and mass of the object has nothing to correlate with the velocity of object at any specific location since mass and weight will remain constant throughout.  Therefore it is displacement in given period of time that is required.

Hence, Option C is the correct alternative.

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By careful construction and measurement, -5N is the magnitude and direction of the resulting force.

Calculate the resultant force by deducting the larger force's size from the smaller force's magnitude. The direction of the smaller force and the resulting force are identical.

When two forces apply on an object 20N to the north and 12N to the south, the resultant force will act towards the north with a magnitude of 8N.

Create coordinate axes on the free-body diagram. It is best to separate the X and Y components from the forces acting on the item. The x and y components of the final force are obtained by adding the x and y components of each force.

7N - 12N = -5N.    

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Answer:

7 Seconds

Explanation:

P=W/t

t=W/P

t=875,000/125,000

t=7 seconds

Answer:

no

Explanation:

because it will bind together in the molecular level

The electric force between two point charges is 1/6 N.

Given data:

Initial distance between the charges (r1) = 2.0 cm

The new distance between the charges (r2) = 8.0 cm

Initial electric force between the charges - F1 = 1.0 N

Solution:

Lets' say the two charges are q and q2. The formula to calculate electric force between the two charges is given below

F = K |q1| |q2| / r^2

K is a constant.

New electric force can be expressed as

F2/F1 = K |q1| |q2| / r2^2 ÷  K |q1| |q2| / r1^2

F2/F1 = r2^2 / r1^2

After substituting the values we will get

F2 = 1.0 N ( 2.0 / 8.0)^2

F2 = 4/64 N

F2 = 1/16N

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Answer:

sEE BELOW

Explanation:

Well.....because the numbers are 'astronomical'....meaning VERY, VERY , VERY LARGE

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-

a) Here is a sketch of the velocity-time graph for the motion described:

```

| _________

v (m/s)| / \

| / \

| / \

| / \

|___/__________________\___

t=0 15s 3min 3min 30s

```

b)

i. The highest velocity reached by the car is the velocity it travels at during the uniform motion phase, which is constant at the end of the acceleration phase. We can find this velocity using the equation:

v = u + at

where u is the initial velocity (10 m/s), a is the acceleration (1 m/s^2), and t is the time taken to accelerate (15 s).

v = 10 + 1(15) = 25 m/s

So the highest velocity reached by the car is 25 m/s.

ii. The time spent decelerating can be found using the equation:

v = u + at

where v is the final velocity (0 m/s), u is the initial velocity (25 m/s), a is the deceleration (unknown), and t is the time taken to decelerate.

0 = 25 + a(t)

t = -25/a

We know that the distance travelled during deceleration is 500 m, so we can also use the equation:

s = ut + 0.5at^2

where s is the distance travelled (500 m), u is the initial velocity (25 m/s), a is the deceleration (unknown), and t is the time taken to decelerate (from above).

500 = 25(-25/a) + 0.5a(-25/a)^2

500 = -625/a + 3125/a

500a = 3125 - 625

a = 5 m/s^2

Substituting this value of a back into the expression for t, we get:

t = -25/5 = -5 s

Since time cannot be negative, we take the absolute value of t:

t = 5 s

So the time spent decelerating is 5 seconds.

iii. The distance between the speed limit sign and the checkpoint is the sum of the distances travelled during each phase of the motion:

s = ut + 0.5at^2 (for acceleration phase)

s1 = 10(15) + 0.5(1)(15)^2 = 187.5 m

s2 = vt (for uniform motion phase)

s2 = (25)(3)(60) = 4500 m

s3 = vt + 0.5at^2 (for deceleration phase)

s3 = (25)(0) + 0.5(5)(5)^2 = 62.5 m

s_total = s1 + s2 + s3 = 187.5 + 4500 + 62.5 = 4750 m

So the distance between the speed limit sign and the checkpoint is 4750 meters.

iv. The average velocity for the whole journey is given by the total distance travelled divided by the total time taken:

s_total = 4750 m

t_total = 15 + 180 + 5 = 200 s

v_avg = s_total / t_total = 4750 / 200 = 23.75 m/s

So the average velocity for the whole journey is 23.75 m/s.

It is true that the spongy bone is composed of osteocytes

The spongy bone is also called as cancellous bone or trabecular bone. It is commonly found in animals. It is porous and vascularized. It contains red bone marrow. It is commonly located at the end of a long bone and is surrounded by a compact bone.

The functions of spongy bone is as follows:

Therefore, it is true that the spongy bone is composed of osteocytes

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The unit in which force is measured.

A newton is the unit in which force is measured because it represents the amount of force required to accelerate a 1 kilogram mass at a rate of 1 meter per second squared. In other words, it is the force needed to cause a mass of 1 kilogram to accelerate at a rate of 1 meter per second squared. This relationship between force, mass, and acceleration is described by Newton's second law of motion. The unit is named after Sir Isaac Newton, a physicist and mathematician who formulated the laws of motion.

Answer:

F = G Mm/r²

Explanation:

Gravitational force is given by the product of the gravitational constant and the product of masses of both objects, divided by the square of the distance between them.

If you know, there is a gravitational force that acts between EVERY object in the universe, but how big is it? Well, Newton wanted to figure that out too!

When Newton was trying to formulate a relationship between the gravitational force that acts between two objects, he found that the gravitational force is directly proportional with the product of the masses of the objects, and inversely proportional to the square of the distance between them.

We get now F ∝ Mm/r²
To get rid of the proportionality sign, all we have to do is multiply the quantity on the right with a constant. This is the Gravitational constant (G), which was found out experimentally. The value of G is (6.6743 ± 0.00015) × 10−11 m3 kg−1 s−2

Now, our equation is F = G Mm/r²

To solve problems based on this, you have to find the values of either
1. Mm
2. r or r²
3. F
While given the rest of the values. I doubt if they would ask, but best try to remember the value of G. You can even be asked to formulate the unit of G, which is not hard as all you have to do is take G to the other side of the equation and solve it using the SI unit of other quantities.

I would always recommend Khan academy for any sort problems in theoretical understanding, so you can probably check that out.

Hope this helps you :)
Please reach out if you have any doubts on the same topic

Answer:

Is a)

Explanation: i took the test so dw

Answer:

no the answer

Explanation: is D i know i took the test

Answer:

To answer your question:

a) The formula to calculate the number of wavelengths within a laser pulse is:

number of wavelengths = pulse duration / wavelength

Plugging in the values given in the question, we get:

number of wavelengths = 38 ps / 1062 nm

Converting picoseconds to seconds and nanometers to meters, we get:

number of wavelengths = 38 x 10^-12 s / 1062 x 10^-9 m

number of wavelengths = 0.0358

Therefore, there are approximately 0.0358 wavelengths within the laser pulse.

b) To fit only one wavelength, the pulse duration would need to be equal to the wavelength. The formula to calculate the pulse duration is:

pulse duration = wavelength

Plugging in the value given in the question, we get:

pulse duration = 1062 nm

Converting nanometers to picoseconds using the speed of light ©, we get:

pulse duration = wavelength / c

pulse duration = 1062 x 10^-9 m / 3 x 10^8 m/s

pulse duration = 3.54 x 10^-12 s

Therefore, the pulse would need to be approximately 3.54 ps long to fit only one wavelength.

I hope this helps

The spring compresses up to 0.046 m which is equal to 4.6 cm.

The given problem requires us to determine the extent to which the putty block system compresses the spring. Let’s start with a brief introduction to the Putty block system and the Spring. The Putty block system is a mass that is dropped from a height of h onto a spring. The spring is compressed by a distance x before coming to rest and then returns to its initial position. Spring is defined as a resilient device that can be compressed or extended by an applied force and can store energy in the process. The potential energy stored in a spring is equal to the product of half of the spring constant and the square of the displacement produced in it. The formula to calculate the amount of compression in the spring is given by; x = mgh / k

where; x = amount of compression in the spring

m = mass of the putty block system                        

g = acceleration due to gravity h = height from which the block was dropped

k = spring constant Substituting the values given,

we have; x = 0.34 x 9.81 x 0.15 / 37x = 0.046 m

The spring compresses up to 0.046 m which is equal to 4.6 cm.

The Putty block system is a simple experiment that helps understand the properties of a spring. The putty block system compresses the spring by 4.6 cm when the mass is dropped from a height of 15 cm. It is important to note that the extent to which the spring is compressed depends on the mass of the object dropped and the height from which it is dropped. Additionally, the amount of compression in the spring can be used to determine the spring constant.

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Answer:

i think it is 40 kilometers in the positive direction... if not im sorry

Explanation:

The area of contact between each tire and the ground is approximately 6.77 x 10⁻⁴ m².

To find the area of contact between each tire and the ground, we can use the formula for pressure:

Pressure = Force / Area

We are given the gauge pressure (6.80 x 10⁵ Pa) and the total weight of the rider plus the bike (830 N + 91 N = 921 N). Since the weight is supported equally by the two tires, the force on each tire is half the total weight:

Force on each tire = 921 N / 2 = 460.5 N

Now, we can rearrange the formula to find the area of contact:

Area = Force / Pressure

Substitute the values for force and pressure:

Area = 460.5 N / (6.80 x 10⁵ Pa)

Area ≈ 6.77 x 10⁻⁴ m²

So, between each tire and the ground, the area of contact is approximately 6.77 x 10⁻⁴ square meters.

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Uniformly Accelerated motion : When a body moves along a straight line and its velocity increases by equal amounts in equal interval of time then the motion is called uniformly accelerated motion. E.g.:- Motion of a freely falling body.

Uniform Motion : When a body covers equal distances in a straight line, equal intervals of time are called uniform motion. Example: a car moving at 20km/h in a straight line. When a body covers unequal distance in equal intervals of time in a straight line is called non-uniform Example : spinning wheel.

In Uniform Velocity Motion a body will be moving with a constant /unchanging velocity moving in a particular direction and thus acceleration will be zero whereas in Uniform accelerated motion a body will move at constant acceleration and its velocity will keep changing with time at a constant/ steady rate.

When the boy realizes he is late for dinner, he doubles his acceleration. The force that the boy is pulling the wagon now will also be doubled.

What is Newton's first law?

Unless influenced by an imbalanced force, an item at rest stays at rest, and an object in motion keeps moving in a straight path at a constant pace.

An item that is stationary is one that is not shifting or considered the beginning.  In such posture, all the forces exerting pressure on it are balanced out or their combined magnitudes are zero.

Based to their inertia, stationary objects which have already balanced forces acting on them prefer to stay that way. When an unbalanced force is operating on a stationary item will it move.

As we continuously  increases the force some particular object the acceleration also increases proportionally. so, the mass does not change as the acceleration increases, we can say that force that the boy is pulling the wagon is equal to acceleration. Therefore, if the boy double the force double the acceleration.

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Answer:

My answer will be (D) . A few thousand years

Explanation:

Carbon-14 is a radioactive isotope of carbon, containing 6 protons and 8 neutrons, that is present in the earth's atmosphere in extremely low concentrations.2

It is naturally produced in the atmosphere by cosmic rays (and also artificially by nuclear weapons), and continually decays via nuclear processes into stable nitrogen atoms.

Suppose we have a sample of a substance containing some carbon-14. Let m be the mass of carbon-14 in nanograms after t years. 3

It turns out that, if the sample is isolated, then m and t approximately 4 satisfy the differential equation

dmdt=−0.000121m.

Suppose our sample initially contains 100 nanograms of carbon-14. Let's investigate what happens to the sample over time.

First, we can solve the differential equation. Since m has a continuous decay rate of −0.000121, a general solution to the differential equation is

m(t)=Ce−0.000121t,

where C is a constant. Substituting the initial condition t=0, m=100 gives C=100, so

m(t)=100e−0.000121t.

With this formula, we can calculate the amount m of carbon-14 over the years.

Mass of carbon-14 in sample

t (years) m (ng to 4 decimal places)

0 100.0000

100 98.7973

1000 88.6034

2000 78.5056

5000 54.6074

10 000 29.8197

20 000 8.8922

Every year, the mass m of carbon-14 is multiplied by e−0.000121≈0.999879. After 100 years, 98.7973 nanograms still remain. After 1000 years, we still have 88.6034 nanograms. But after 5000 years, however, almost half of the carbon-14 has decayed.

Graph showing the decay of 100 nanograms of Carbon-14.

Detailed description

half-life of carbon-14  

Example

How long does it take for precisely half of the carbon-14 in the sample to decay; that is, when does m=50? Give the answer to three significant figures.

Solution

The mass of carbon-14 in our sample is given by

m(t)=100e−0.000121t.

So we solve 50=100e−0.000121t, which gives e−0.000121t=12. Hence,

t=loge12−0.000121≈5730 years (to three significant figures).

The time period calculated in this example is called the half-life of carbon-14. In fact over any period of 5730 years, the amount of carbon-14 in an isolated sample will decay by half. This fact is used in radiocarbon dating to determine the age of fossils up to 60 000 years old. Roughly speaking, while an organism is alive, its interactions with its environment maintain a constant ratio of carbon-14 to carbon-12 in the organism; but after it dies, the carbon-14 is no longer replenished, and the ratio of carbon-14 to carbon-12 decays in a predictable way. (See Wikipedia Open new window for more on radiocarbon dating.)

Exercise 1

Explain why the mass of carbon-14 in the sample is given (approximately) by

m(t)=100(12)t5730,

and hence explain why the amount of carbon-14 in the sample decays by half over any period of 5730 years.

Half-life in general

In general, whenever a quantity x(t) obeys an exponential decay equation

x(t)=Cekt,

where the continuous decay rate k is negative, then the quantity x has a half-life T. After any time period of length T, the quantity x decreases by half. Let us see why.

As k is negative, the factor ekt decreases from 1 (at t=0) towards 0 (as t approaches ∞). Therefore there is a time t=T such that

ekT=12.

We now solve for T and obtain

kT=loge12=−loge2,

so

T=−1kloge2.

This T is the half-life. From time t=0 to time t=T, the factor ekt decreases from e0=1 to ekT=12, that is, decreases by half. Similarly, over any time period of length T, the term ekt decreases by half. 5

Note that, when k=−0.000121, we obtain T=5730, in agreement with our calculation for carbon-14.

Hope this work

If I'm wrong I'm sorry

If I'm right thank you (brainliest plz )

Giants are known to be large in radius because of various scientific studies and observations. Astronomers and astrophysicists use methods such as photometry and spectroscopy to analyze the physical properties of stars, including their size and temperature.

These studies have shown that giants are typically much larger in radius than main sequence stars, with radii that can be up to ten times larger than the radius of the Sun.

This increase in size is due to the fact that giants have evolved to a later stage in their life cycle, where they have exhausted the hydrogen fuel in their cores and have expanded and cooled as a result.

Additionally, observational studies of binary star systems have provided further evidence for the large size of giants, as the gravitational influence of the giant star on its companion can be used to measure its size and mass.

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Answer:

El elevador puede levantar 5.76 toneladas de carga máxima.

Explanation:

De acuerdo a la ley de Pascal:

\( p_{1} = p_{2} \)          

\( \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} \)   (1)

En donde:

F: es la fuerza

P: es la presión

A: es el área

Sabiend que p₁ = 5x10⁵ N/m², tenemos que F₂ es:                              

\( F_{2} = p_{1}A_{2} \)       (2)

El área del embolo viene dada por el área de una circunferencia:  

\( A_{2} = \pi r^{2} \)    (3)

Introduciendo la ecuación (3) en la ecuación (2) tenemos:

\( F_{2} = p_{1}\pi r^{2} = 5 \cdot 10^{5} N/m^{2} \pi (0.20 m)^{2} = 62832 N \)

Dado que el rendimiento es del 90%, la fuerza máxima es:

\( F_{2} = 62832 N*0.90 = 56549 N \)

Ahora sabemos que la fuerza del elevador para levantar la carga máxima  es 56549 N y para encontrar el valor de toneladas de la carga máxima que puede levantar el elevador, debemos encontar la fuerza necesaria para levantar 1 tonelada:          

\( F = mg = 1000 kg*9.81 m/s^{2} = 9810 N \)  

Finalmente, si para levantar 1 tonelada se debe aplicar una fuerza de 9810 N, y la fuerza total es igual a 56549 N, el numero de toneladas que puede levantar el elevador es:      

\( N = \frac{F_{2}* 1 ton}{F} = \frac{56549 N* 1 ton}{9810 N} = 5.76 ton \)

Por lo tanto, el elevador puede levantar 5.76 toneladas de carga máxima.

Espero que te sea de utilidad!

A. The brightness order will be: 6 > 4 = 5 > 3 > 1 = 2.

B. The voltage drop order will be: 6 > 4 = 5 > 3 > 1 = 2.

C. V3 = Vbattery - \(\rm (V_5 + V_6)\)

A. 6 will get all the battery current and hence the largest drop across it. The drop across 4 = drop across 5 = (Vbattery - \(\rm V_6\)). The drop across 3 and combi of 1 and 2 will be equal. Drop across 1 and 2 = \(\rm V_3\)/2.

More the drop, more the wattage, P = \(\rm V^2\)/R

So the brightness order will be: 6 > 4 = 5 > 3 > 1 = 2.

B. 6 will get all the battery current and hence the largest drop across it. The drop across 4 = drop across 5 = (Vbattery - \(\rm V_6\)). The drop across 3 and combi of 1 and 2 will be equal. Drop across 1 and 2 = \(\rm V_3\)/2.

More the drop, more the wattage, P = \(\rm V^2\)/R

So the voltage drop order will be: 6 > 4 = 5 > 3 > 1 = 2.

C. V3 = Vbattery - \(\rm (V_5 + V_6)\)

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I'm pretty sure this poor guy could never have been accepted for astronaut training, much less a mission to the Moon.  

He weighs something like 335 pounds when he's ON THE MOON !

If he has enough fuel, and survives a trip back to Earth, he'll weigh around 9,080 Newtons here.  That's like 2,040 pounds ... durn close to a ton ! !

Answer:

Gravitational field strength:

Moon is 1.6N/kg

Earth is 9.8N/kg or 10N/kg

Moon:

Weight = mass x gravitational field

1500N = m x 1.6N/kg

÷1.6 both sides

937.5 = m

Mass of astronaut is 937.5kg

(Your mass doesn't change, no matter where you go, in space)

Earth:

Weight = mass x gravitational field

= 937.5kg x 9.8 N/kg

= 9187.5N

Or

Weight = mass x gravitational field

= 937.5kg x 10 N/kg

= 9375N

Thus, the astronaut's weight will be 9187.5N or 9375N on Earth.

Hope this helps!

Carbon-12 has 6 protons and 6 neutrons. Carbon-14 has 6 protons and 8 neutrons.

All atoms of the same element have the same number of protons, which is what determines the element's atomic number. In this case, carbon-12 and carbon-14 both have an atomic number of 6, meaning they both have 6 protons in their nucleus.

The atomic mass of an atom is the sum of its protons and neutrons. Carbon-12 has an atomic mass of 12, meaning it has 6 protons and 12-6= 6 neutrons. Carbon-14 has an atomic mass of 14, meaning it has 14-6=8 protons and 8 neutrons.

So, while both carbon-12 and carbon-14 have the same number of protons, they have a different number of neutrons, which makes them different isotopes of carbon.

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The radioulnar joint is a synovial joint located at the elbow that connects the radius and the ulna, enabling rotational motion.

The radioulnar joint allows for pronation and supination. Pronation refers to the motion of rotating the forearm so that the palm faces downwards, while supination refers to the motion of rotating the forearm so that the palm faces upwards. The radioulnar joint allows the radius and ulna to move relative to each other, resulting in rotational motion.

When the forearm is pronated, the radius rotates over the ulna and crosses it, while the ulna remains stationary. When the forearm is supinated, the radius rotates back to its original position, and the two bones are parallel to each other.The radioulnar joint is important in many activities, including writing, typing, playing musical instruments, and sports like tennis and golf. Any damage to this joint can result in a loss of pronation and supination, making daily activities challenging.

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Answer:

A) speed up

is the correct option

Answer:

slows down

Explanation:

As the temperature difference decreases the rate of transfer slows (hope this helps)

Answer:

it is positive feedback loop

Explanation:

It's a phenomenon scientists call a positive feedback loop: deforestation causes drought, which in turn, worsens deforestation, and so on, intensifying the effect. The study concluded that deforestation causes 4% of drought, while drought accounts for 0.13% of deforestation per millimeter of rain in the Amazon biome.

Answer:

A quantity which does not depend on direction is called a scalar quantity. Vector quantities have two characteristics, a magnitude and a direction. Scalar quantities have only a magnitude. When comparing two vector quantities of the same type, you have to compare both the magnitude and the direction.

I rarely share my notes. But these are my last year notes, so I can share with you. Click on the photo to view the answer.

The telescope created the data gathered by Kepler and his team.

What is a star?

A star is a large luminous astronomical body which produces light and heat energy as well as radiation.

There are billions of stars in the universe organized into galaxies.

The Sun is the star of our solar system.

The Kepler project produced a wide range of data products and documentation to assist the community in using data from the mission to help study both exoplanets and other astrophysical areas.

In the video, a mysterious star was observed which is 50 percent bigger and 1,000 degrees hotter than the Sun.

By mean of telescopes, it was observed that the dimming seen in the diet was dues to dust particles.

These data produced ranges from engineering data on the detectors to lists of planet candidates and includes many of the intermediate data products in the data processing path.

The Kepler first mission came to an end after four years when two of the four reaction wheels, used to point the spacecraft malfunctioned.

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One of the best defensive driving techniques for windy conditions is driving with both hands on the steering wheel.

When driving in windy conditions, it is essential to take some safety precautions to avoid accidents and maintain control over the vehicle. A vehicle's stability and safety depend on the driver's ability to control it, especially in extreme weather conditions. Driving with both hands on the steering wheel is the most recommended defensive driving technique to stay in control of the vehicle during windy conditions. Besides driving with both hands on the steering wheel, it's essential to maintain a slow and steady speed, pay attention to the wind direction, and stay focused on the road. The strong wind can cause vehicles to drift, sway, or even flip, so it's necessary to keep a safe distance from other vehicles, especially large trucks or buses. When driving on a windy day, it's crucial to remain calm and avoid panic. Sudden movements and reactions can cause the driver to lose control of the vehicle, which could result in a severe accident. Therefore, it's best to stay alert, keep both hands on the steering wheel, and maintain a slow and steady speed to stay safe in windy conditions.

In conclusion, the best defensive driving technique for windy conditions is driving with both hands on the steering wheel, maintaining a slow and steady speed, and keeping a safe distance from other vehicles. Stay focused, stay calm, and stay safe. The answer to the question is: driving with both hands on the steering wheel.

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