Answers
Answer:
407 steps
Explanation:
From the question,
P = mgh/t........... Equation 1
Where P = power, m = mass, g = acceleration due to gravity, h = height, t = time.
Make h the subject of the equation
h = Pt/mg............. Equation 2
Given: P = 746 W, t = 1 minute = 60 seconds, m = 70 kg.
Constant: g = 9.8 m/s²
Substitute into equation 2
h = 746(60)/(70×9.8)
h = 44760/686
h = 65.25 m
h = 6525 cm
number of steps = 6525/16
number of steps = 407 steps
\(m\)The number of 16-cm-high steps are 407 steps.
Given-
Power produced by the athlete \(P\) is 746 \(w\).
The time taken \(t\) is 1 min or 60 sec.
Mass is 70 kg.
Now the equation of the power produced in terms of mass and time taken can be given as,
\(P=\dfrac{mgh}{t}\)
Here, \(g\) is the gravity force.
Rewrite the equation to solve it further,
\(\dfrac{1}{h} =\dfrac{mg}{Pt}\)
\(h=\dfrac{Pt}{mg}\)
Put the values of known variables,
\(h=\dfrac{746\times 60}{70\times9.8}\)
\(h=65.25\)
Height is 65.25 m or 6525 cm.
To find out the number of 16-cm-high steps (\(n\)), the height should be divided by the 16.Therefore,
\(n=\dfrac{6525}{16}\)
\(n=407\)
Hence, the number of 16-cm-high steps are 407 steps.
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Related Questions
A wheel is rotating freely at angular speed 530 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initially at rest and with 9 times the rotational inertia of the first, is suddenly coupled to the same shaft. (a) What is the angular speed of the resultant combination of the shaft and two wheels
Answers
Answer: \(53\ rev/min\)
Explanation:
Given
angular speed of wheel is \(\omega_1 =530\ rev/min\)
Another wheel of 9 times the rotational inertia is coupled with initial wheel
Suppose the initial wheel has moment of inertia as I
Coupled disc has \(9I\) as rotational inertia
Conserving angular momentum,
\(\Rightarrow I\omega_1=(I+9I)\omega_2\\\\\Rightarrow \omega_2=\dfrac{I}{10I}\times 530\\\\\Rightarrow \omega_2=53\ rev/min\)
What is the temperature change of a 3 kg gold (c = 129 J/kg K) bar when placed into 0.220 kg
of water. After equilibrium is reached the water underwent a temperature change of 17 °C.
Answers
Answer:
We can use the formula:
q = mcΔT
where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
The heat transferred from the gold bar to the water is equal to the heat transferred from the water to the gold bar, since they reach thermal equilibrium. Therefore:
q_gold = q_water
We can solve for the temperature change of the gold bar:
q_gold = mcΔT_gold
q_water = mcΔT_water
Since the heat transferred is equal:
mcΔT_gold = mcΔT_water
Rearranging and solving for ΔT_gold:
ΔT_gold = ΔT_water(m_water/m_gold)
ΔT_water is the temperature change of the water, which is 17°C. m_water is 0.220 kg, and m_gold is 3 kg. c_gold is given as 129 J/kg K.
ΔT_gold = 17°C(0.220 kg/3 kg)(1/129 J/kg K) = 0.025°C
Therefore, the temperature change of the gold bar is 0.025°C when it is placed into 0.220 kg of water and thermal equilibrium is reached.
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
Answers
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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Scientists often work on projects for a long time and fail to see sources of error in their research. Which process allows an outside expert to look at the scientist's project and point to sources of error?
Answers
Answer:
Peer Review
Explanation: I took the test
What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!
Answers
Answer:
Voltage is required for there to be a current but resistance can effect the amount of current.
Answer:
the answer is voltage
Explanation:
we just finished this unit in class
Q-To which cells does the cell theory apply?
A. animal cells only
B. plant cells only
C. All Cells
D. Single-celled organisms only.
Answers
Answer:
the correct choice is C. all cells
Explanation:
every single living organism with cells, so the cell theory, which states what classifies something as a cell, applies to all cells. note: viruses are not alive
Answer:
C, All Cells
Explanation:
a stationary 165 kg football player is tackled by a 178 kg player running at 8 m/s. How fast are they moving after the collision ?
Answers
After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.
Does the principle of conservation of momentum is constant inside a certain problem domain?Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.
\(p1 = m1 * v1 + m2 * v2\)
\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)
\(p2 = (m1 + m2) * v\)
Substituting the values, we get:
\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)
Since the total momentum is conserved, we can equate p1 and p2:
p1 = p2
\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)
\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)
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T/F. a collection of items, measurements, or entities taken from a population in such a manner as to ensure each has the same chance of being included is a simple random sample.
Answers
A collection of items, measurements, or entities taken from a population in such a manner as to ensure each has the same chance of being included is a simple random sample. [TRUE]
About Simple Random SamplingA simple random sampling technique is a technique for obtaining samples that are directly carried out on the sampling unit. Thus each sampling unit as an isolated population element has the same opportunity to become a sample or to represent the population. This method is carried out when members of the population are considered homogeneous
Simple Random Sampling RequirementsRequirements for using the simple random sampling technique:
This technique is used if the population elements are homogeneous, so that any element selected to be the sample can represent the population. Done if the research analysis tends to be descriptive and general in nature. Disadvantages and advantages of Simple Random SamplingThe disadvantages of this simple random sampling technique include:
Need a list of members of the population, Took a long time, ExpensiveWhile the advantage of this simple random sampling technique is that it is easy to apply.
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Why will a change in velocity have a greater affect on KE than a change in mass?
Answers
Answer: the answer is corect of what everone else said
Explanation:
(20%) Problem 5: Two identical springs, A and B, each with spring constant k=54.5 N/M, support an object with a weight W=11.6N. Each spring makes an angle of θ=20.6 degrees to vertical, as shown in the diagram.
50% Part (a) Write an expression for the tension in spring A (which is equal to the tension in spring B) in terms of W and θ.
T= W cos (θ) -sin (θ)
Answers
The expression for the tension in the spring A is T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]
What is the tension in spring A?
The tension in spring A can be determined by resolving the forces into x and y components as shown below.
The angle spring A makes with horizontal is calculated as;
A = 90⁰ - θ
The horizontal component of the tension on spring A;
T(Aₓ) = -W cos(A)
T(Aₓ) = -W cos(90 - θ)
The vertical component of the tension of spring A is calculated as;
T(Ay) = W sin(A)
T(Ay) = W sin(90 - θ)
The expression for the tension in spring A is calculated as;
T(A) = √[(T(Aₓ)² + T(Ay)²]
T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]
Thus, the expression for the tension in the spring A is determined through resolution of vector components.
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Etienne asks Hakim to write Newton's second law in the horizontal direction for the block-spring system when it is displaced a distance x from the equilibrium position. Which equation is correct?
Answers
Answer:
Explanation: The correct equation for Newton's second law in the horizontal direction for the block-spring system when it is displaced a distance x from the equilibrium position is:
m(d^2x/dt^2) + kx = 0
where m is the mass of the block, k is the spring constant, and x is the displacement from the equilibrium position. This equation represents the balance of forces acting on the block-spring system, with the restoring force of the spring (proportional to x) opposing the force required to accelerate the mass (proportional to d^2x/dt^2).
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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What constant acceleration, in SI units, must a car have to go from zero to 30 m/s in 14 s ?
Express your answer with the appropriate units.
Answers
Answer:
Acceleration = 2.143m/s²
Explanation:
Vf=Vi+at
(30)=(0)+a(14)
a=2.143m/s²
A platinum resistance thermometer has resistances of 210.0 Ω when placed in a 0°C ice bath and 237.8 Ω when immersed in a crucible containing a melting substance. What is the melting point of this substance? (Hint: First determine the resistance of the platinum resistance thermometer at room temperature, 20.0°C.)
Answers
The resistance of a platinum resistance thermometer is 200 Ω at 0°C and 255.8 Ω at the melting point. Using the resistance-temperature relationship and calculations, the estimated melting point is approximately 19.93°C.
The resistance of a platinum resistance thermometer is 200 Ω when placed in a 0°C ice bath and 255.8 Ω when immersed in a crucible containing a melting substance. To determine the melting point of the substance, we need to calculate the temperature at which the resistance reaches 255.8 Ω.
First, we find the temperature coefficient of resistance (α) using the formula α = (R - R₀) / (R₀ * T), where R is the resistance at the melting point, R₀ is the resistance at 0°C, and T is the temperature at the melting point.
Substituting the given values, we have α = (255.8 - 200) / (200 * T₀), where T₀ is the known room temperature of 20°C.
Calculating α, we find α ≈ 0.014.
Next, we use the resistance-temperature relationship equation R = R₀(1 + αT) to solve for the melting point temperature (T). Substituting the known values, we have 255.8 = 200(1 + 0.014 * T).
Simplifying the equation, we find 1.279 = 1 + 0.014T.
Solving for T, we get T ≈ 19.93°C.
Therefore, based on the given data, the estimated melting point of the substance is approximately 19.93°C.
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What is the angle θ between vectors A⃗ and B⃗ if A⃗ =4ı^−4ȷ^ and B⃗ =−5ı^+7ȷ^?
Answers
The characteristics of the scalar product allows to find the angle between the two vectors is:
The angle θ = 170º
The scalar product is the product between two vectors whose result is a scalar.
A . B = |A| |B| cos θ
Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.
The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.
i.i = j.j = 1
i.j = 0
A . B = (4 i - 4j). * -5 i + 7j)
A . B = - 4 5 - 4 7
A. B = -48
We look for the modulus of each vector.
|A| = \(\sqrt{x^2 +y^2 }\)
|A| = \(\sqrt{4^2 + 4^2}\)
|A| = 4 √2
|B| = \(\sqrt{5^2 +7^2}\)
|B| = 8.60
We substitute.
-48 = 4√2 8.60 cos θ
-48 = 48.66 cos θ
θ = cos⁻¹ \(\frac{-48}{48.664}\)
θ = 170º
In conclusion using the dot product we can find the angle between the two vectors is:
the angle θ = 170º
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The intensity of sunlight at the Earth's distance from the Sun is 1370 W/m2. (a) Assume the Earth absorbs all the sunlight incident upon it. Find the total force the Sun exerts on the Earth due to radiation pressure. N (b) Explain how this force compares with the Sun's gravitational attraction.
Answers
Answer:
F= 3.56e22N
Explanation:
Using the force of radiation acting on the earth which is
force = radiation pressure x area = (intensity/c)xpi R^2
force = 1370W/m^2 x pi x( 6.37x10^6m)^2/3x10^8m/s
force = 5.82x10^8 N
But the sun's gravitational attraction means the magnitude of the solar gravitational force on earth: If that's the case, the answer is approx 10^22 N:
F=GMm/r^2
G=6.67x10^(-11)=6.67e-11
M=mass sun = 2x10^30kg=2e30
m=mass earth = 6x10^24kg
r=earth sun distance = 1.5x10^11m
F=(6.6e-11)(2e30)(6e24)/(1.5e11)^2 =
F= 3.56e22N
Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.
Answers
A fox getting its energy from a mouse and a mouse getting its energy from the grass shows evidence of the carbon cycle
What is the carbon cycle?The carbon cycle is a necessary component within the global interchange between living species and the environment.
Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.
Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.
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ou are pulling a 35 kg object with 18.4 N force which is oriented at 10 degree with ground. What is acceleration?
Answers
Answer:
Acceleration= 0.52 m/s²
A physical system is in the state |α> = cos(α)|+> + sin(α)|->. Two observables  = a(|+><+| + |-><-|) + b(|+><-| + |-><+|) e B = a(|+><+| - |-><-|) are measured. Check the uncertainty relationship for these two operators.
Answers
Answer:
sorry dear
Explanation:
sorry dear but ur question is hard to understand can u try to edit it so i can tell u the answer?
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
Answers
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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how is life determined on math
Answers
Answer:
you can use math as a banker, a doctor, a scientist, the president probably uses math, you use math to see how much less juice you gave your sibling, and you can use math to help in collage! (sorry if its wrong tell me if it is)
Answer: Isn't it because we use it daily especially with financial needs, scientific research, and the way people even use it to cook
Explanation: Therefore everything, especially in physics where you determine what density, distance, and equations following the scientific research.
why no tempature can be lower than 0 kelvin
Answers
Answer:
At zero kelvin (minus 273 degrees Celsius) the particles stop moving and all disorder disappears. Thus, nothing can be colder than absolute zero on the Kelvin scale. Physicists have now created an atomic gas in the laboratory that nonetheless has negative Kelvin values.
Explanation:
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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What do you see as Michael Collins’s leadership traits? Which of these do you consider a strength? A weakness?
Answers
Collins's visionary leadership and strategic thinking were his key strengths, while his risk taking nature could be seen as a weakness.
Michael Collins’s leadership traitsMichael Collins, the Irish revolutionary and politician, displayed several leadership traits throughout his career. Here are some key traits associated with Collins:
Visionary: Collins had a clear vision for an independent Ireland and worked tirelessly to achieve it. He played a crucial role in shaping the strategies and tactics of the Irish Republican Army (IRA) during the Irish War of Independence.Determination: Collins was highly determined and committed to his cause. He demonstrated unwavering dedication to the pursuit of Irish independence, even in the face of significant challenges and risks.Strategic thinking: Collins was a strategic thinker who possessed a keen understanding of the political and military landscape. He implemented innovative guerrilla warfare tactics, such as intelligence gathering and targeted assassinations, to disrupt British rule in Ireland.Charismatic communication: Collins had strong communication skills and charisma, which enabled him to inspire and rally others to his cause. His ability to articulate his vision and mobilize support was instrumental in gaining public backing for the IRA.Boldness and risk-taking: Collins was known for taking bold risks and making daring decisions. For example, he authorized the intelligence organization known as the "Squad" to carry out targeted assassinations of British agents, which significantly weakened British intelligence capabilities in Ireland.Learn more on leadership traits here https://brainly.com/question/12522775
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On three separate intances you connect each lightbulb to a battery with an and of 12.00V and an internal resistance of 0.5. When a current of 4A passes through the battery, what is the resistance in the LED, CFL and incandescent lightbulb?
Answers
The resistance in the LED, CFL, and incandescent lightbulb would be 2.50 ohms.
What is resistance?Resistance is the obstruction of electrons in an electrically conducting material.
As given in the problem On three separate instances you connect each lightbulb to a battery with an and of 12.00V and an internal resistance of 0.5. When a current of 4A passes through the battery,
resistance = voltage /current
= 12 volt/4 ampere
= 3 Ohm
The total resistance across the circuit = internal resistance + resistance across the bult
resistance across the bulb = 3 - .50
=2.5 Ohms
Thus, the resistance in the LED, CFL, and incandescent lightbulb would be 2.50 ohms
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2. How much work is done in lifting 214kg from the floor to a shelf at a height of 6m?
Answers
Answer:
12583.2 J or 12.5832 KJ
Explanation:
Work done can be expressed as force multiplied by displacement, or
W = Fs
In this case, we can calculate the force by using F = mg.
m is the mass, 214 kg, and g is gravitational acceleration, which is 9.8 m/s/s.
So, we Calculate 214 * 9.8 to get 2097.2
The displacement is 6m.
So, by doing W = Fs, we get
2097.2 * 6 = 12583.2 Joules
Lab Report Sun, Earth, and Moon Models It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U5_ Lab_SunEarthAndMoonModels_Alice_Jones.doc). Introduction 1. What was the purpose of the investigation? Type your answer here: 2. What causes the bright part of the moon to appear bright? Type your answer here: Experimental Methods 1. What materials did you use to create your model? Type your answer here: 2. Describe how you created your model. Type your answer here: Develop a Model 1. Show your model and the relationships between the components. Include labeled pictures or diagrams that describe causal accounts for the phases of the moon and eclipses. Type your answer here: Use a Model 1. Use your model to predict the relative positions of the earth, sun, and moon when the moon is full. Type your answer here: 2. Use your model to explain why a lunar eclipse does not occur every month when there is a full moon. Type your answer here:
Answers
1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.
2. The bright part of the moon appears bright due to the reflection of sunlight.
Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.
Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.
Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.
Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.
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use a trigonometric equation to determine the leg of this triangle
C=90°
A=30°
c=10m
What is a?
Answers
Answer: 5
Explanation: B is for sure 60°, c* cosB = 10*1/2 =5
One mole of a monatomic gas is subjected to the following sequence of steps.
a. Starting at 300 K and 10 atm, the gas expands freely into a vacuum to double its volume.
b. The gas is next heated reversibly to 500 K at constant volume.
c. The gas is then reversibly expanded at constant temperature until its volume is doubled
d. The gas is finally reversibly cooled to 300 K at constant pressure
Required:
Calculate the values of q and w and the changes in U, H, and S.
Answers
Answer:
c
Explanation:
the gas is the reversible expanded and constant temperature until it's volume is doubled
(4x)。
(2x+6)。
I need to solve x for these angles
Answers
Answer: x=14
Explanation:
there is 90° in a right angle so
(4x)+(2x+6) =90
collect like terms
6x+6=90
-6 from both sides
6x=84
÷6
x=14