A charge of 35.0 μC is placed on conducting sphere A of radius 8.00 cm. Another identical conducting sphere B (radius 8.00 cm) carrying 65.0 uC of charge is placed such that its center is 40.0 cm away from the center of the first sphere (A). a. If the two conducting spheres are now connected by a thin conducting wire, what are the new charges on the spheres? b. Now, the conducting wire is cut and the spheres are released from rest. What are their speeds when they are far apart (infinite distance away) from each other? Take the mass of each conductor to be 80.0 grams. Ignore gravity. Assume that the potential is zero at infinity.
Answers
Answer:
a) 50μC
b) 37.45 m/s
Explanation:
a) If the spheres are connected the charge in both spheres tends to be equal. This because is the situation of minimum energy.
Thus, you have:
\(Q_T=35\mu C+65\mu C=100\mu C\\\\Q_s=\frac{Q_T}{2}=50\mu C\)
Hence, each sphere has a charge of 50μC.
b) You use the fact that the total work done by the electric force is equal to the change in the kinetic energy of the sphere. Then, you use the following equations:
\(\Delta W=\Delta K\\\\\int_{0.4}^\infty Fdr=\frac{1}{2}m[v^2-v_o^2]\\\\F=k\frac{Q^2}{r^2}\\\\v_o=0m/s\\\\m=0.08kg\\\\kQ^2\int_{0.4}^{\infty} \frac{dr}{r^2}=kQ^2[-\frac{1}{r}]_{0.4}^{\infty}=\frac{kQ^2}{0.4m}=\frac{(8.98*10^9Nm^2/C^2)(50*10^{-6}C)^2}{0.4m}\\\\kQ^2\int_{0.4}^{\infty} \frac{dr}{r^2}=56.125J\)
where you have used the Coulomb constant = 8.98*10^9 Nm^2/C^2
Next, you equal the total work to the change in K:
\(\frac{1}{2}mv^2=56.125J\\\\v=\sqrt{\frac{2(56.125J)}{m}}=\sqrt{\frac{2(56.125J)}{0.08kg}}=37.45\frac{m}{s}\)
hence, the speed of the spheres is 37.45 m/s
Related Questions
What is the density of a substance that has a volume of 14 milliliters and a mass of 13.2 grams
Answers
Answer:
Below
Explanation:
You can use this formula to find the density of something
density = mass / volume
Plugging our values in.....
density = 13.2 / 14
density = 0.9428571429 g/mL
Rounding to sig figs we get....
density = 0.94 g/mL
Hope this helps! Best of luck <3
Answer:
\(\huge\boxed{\sf Density = 0.94\ g/mL}\)
Explanation:
Given:
Volume = 14 mL
Mass = 13.2 g
Required:
Density = ?
Formula:
Density = Mass / Volume
Solution:
Density = 13.2 / 14
Density = 0.94 g/mL
\(\rule[225]{225}{2}\)
Hope this helped!
~AH1807Peace!How far will you have traveled on a bus driving 31 m/s for 3 hours.
Answers
Flag question: Question 48
Question 481 pts
Aggression is intended to inflict physical or psychological harm on another individual?
Group of answer choices
True
False
Flag question: Question 49
Question 491 pts
Physical attractiveness is important in attraction across cultures because it indicates good health, sound genes, and high fertility.
Group of answer choices
True
False
Flag question: Question 50
Question 501 pts
The study of how other people influence our thoughts, feelings, and actions is called social psychology.
Group of answer choices
True
False
Answers
The given statement "Aggression is intended to inflict physical or psychological harm on another individual" is true statement because Aggression is a general term for a variety of actions that might hurt you, other people, or inanimate things in the environment physically or psychologically.
"Physical attractiveness is important in attraction across cultures because it indicates good health, sound genes, and high fertility "is true statement.
"The study of how other people influence our thoughts, feelings, and actions is called social psychology." is true statement.
A person's bodily or emotional harm to another is at the heart of aggression. Aggression in psychology refers to a variety of actions that can injure oneself, others, or inanimate things in the environment. The primary goal of this kind of behaviour is to hurt another person, either physically or mentally. It can indicate a physical condition, substance use disorder, or underlying mental health condition.
Thus, all the given statement are true.
To know more about psychological
https://brainly.com/question/4625790
#SPJ1
Q14. A particle starts from rest and moves with a constant acceleration of 0. Sms-s. What is the distance covered by the particle in 10s.
Answers
The distance covered by the particle in 10 seconds is 0 meters.
Given that the particle starts from rest and moves with a constant acceleration of 0. Sms-s, we can use the equation of motion to determine the distance covered by the particle in 10 seconds.
The equation for distance covered (s) by an object with constant acceleration can be expressed as:
s = ut + (1/2)at²,
where u is the initial velocity (which is zero in this case), a is the constant acceleration, and t is the time taken.
In this scenario, the particle starts from rest, so its initial velocity (u) is 0 m/s. The acceleration (a) is given as 0 m/s². The time (t) is 10 seconds.
Substituting the given values into the equation, we have:
s = 0(10) + (1/2)(0)(10)² = 0 + 0 = 0.
For more such questions on acceleration
https://brainly.com/question/30595126
#SPJ8
In which direction does the magnetic field in the center of the coil point?
Answers
Answer:
Right
Explanation:
Coil move right yes
a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direct with a speed of 1.3 m/s whats the mass of the cannon.
Answers
The mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.
What is velocity?When anything is moving, its velocity tells us how rapidly that something's location is changing from a certain vantage point and as measured by a particular unit of time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.
Given:
The mass of the cannonball, m = 5 kg,
The velocity of the cannon, v = 550 m/s,
The recoil speed of the cannon, vₐ = 1.3 m / s,
Then by using momentum conservation calculate the mass of the cannon,
\(m \times v = m_{a} \times v_{a}\)
Here mₐ is the mass of the cannon,
Substitute the values,
5 × 550 = mₐ × 1.3
mₐ = 2115.4 kg
Therefore, the mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.
To know more about velocity:
https://brainly.com/question/19979064
#SPJ1
A guitar player tunes her strings so thatthere is a beat frequency of 1.0 Hzbetween them. If one string has afrequency of 220 Hz, what is thefrequency of the other string? (Thereare two possible answers; give one.) -(Unit = Hz)
Answers
Fb = beat frequency = 1 Hz
F1 = frequency 1 = 220 Hz
Fb = l F1 - F2 l or
Fb= l F2 - F1 l
Replacing:
1 = 220 - F2
f2 = 220 - 1
f2 = 219 HZ
A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
Answers
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
For more questions on acceleration due to gravity
https://brainly.com/question/18515494
#SPJ8
When the mass remains the same, and more force is used, the acceleration:
o increases
O decreases
O remains the same
O No answer text provided.
Answers
Answer:
increases
Explanation:
when the mass of an object is constant and you add more force, acceleration increases
28. An electron with a speed of 4.0 x 10° m/s enters a uniform magnetic field of magnitude 0.040 T at an angle of 35 degrees to the magnetic field lines. The electron will follow a helical path. a) Determine the radius of the helical path. b) How far forward will the electron have moved after completing one circle?
Answers
Answer:
r= 1.09×10^-4
Explanation:
Given
V=speed=4.0×10^5 m/s
B= magnetic field= 0.040 T
©=angle= 35°
m= mass of electron= 9.11×10^-31
q= charge of electron= 1.60×10^-19
solution
qv×B= mv²/r
qvBsin©=mv²/r
qBsin©=mv/r
r=mv/qBsin©
r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)
r= 1.09×10^-4 m
a) r = 1.09 * \(10^{-4}\) m
b) Distance travelled : 6.845 * \(10^{-4}\) m
What is an electron ?
An electron is a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
given
charge of electron : 1.6 * \(10^{-19}\) C
mass of electron = 9.11 * \(10^{-31}\) kg
v = 4.0 x 10 m/s
B = 0.040 T
theta = 35 degrees
since ,
force in magnetic field on electron = centripetal force
a) q(v*B) = m \(v^{2}\) / r
q v B sin(theta) = m \(v^{2}\) / r
r =m v /q B sin(theta)
r = 9.11 * \(10^{-31}\) * 4.0 x \(10^{5}\)/ 1.6 * \(10^{-19}\) sin (35)
r = 1.09 * \(10^{-4}\) m
b) far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr
= 2 * 3.14 * 1.09 * \(10^{-4}\) m = 6.845 * \(10^{-4}\) m
learn more about electron
https://brainly.com/question/1255220?referrer=searchResults
#SPJ2
What hazard can arise when the current flowing in the circuit is too high? Select all that apply.
Heating up of the wire
Melting of the insulation
Fire
Poisonous fumes
Sounding of the alarm
Answers
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
Answers
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
For more such information on; volume
https://brainly.com/question/14197390
#SPJ8
. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
Answers
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
Know more about work here:
https://brainly.com/question/28356414
#SPJ8
Question 19 of 25
The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
- Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 70 m/s east
O B. 20 m/s west
O c. 70 m/s west
D. 20 m/s east
Answers
The velocity of car 2, from the frame of reference of car 1, is 20 m/s west. (Answer: B)
When considering the frame of reference of car 1, we need to subtract the velocity of car 1 from the velocity of car 2 to determine the relative velocity. Since car 1 is moving at 45 m/s west and car 2 is moving at 25 m/s east, we can subtract these velocities to find the relative velocity of car 2 with respect to car 1.
45 m/s (west) - 25 m/s (east) = 20 m/s (west)
Therefore, car 2 has a velocity of 20 m/s west when observed from the frame of reference of car 1. It is important to note that velocities are vector quantities, which means they have both magnitude and direction. In this case, the direction is west because car 2 is moving in the opposite direction of car 1. (Answer: B)
for such more questions on velocity
https://brainly.com/question/80295
#SPJ8
A simple pendulum is constructed by attaching a 1.0 kg mass to a length L of fishing line. At the equilibrium point the pendulum bob has a kinetic energy of 2.0 joules and an angular velocity about the pivot point of 0.66 radians/sec. What is the period of the pendulum?
Answers
The period of the pendulum, given that the pendulum has an angular velocity about the pivot point of 0.66 radians/sec is 9.52 seconds
How do i determine the period of the pendulum?First, we shall list out the given parameters from the question. This is shown below:
Mass (m) = 1.0 KgKinetic energy (KE) = 2.0 joules Angular velocity (ω) = 0.66 radians/secPeriod of pendulum (T) =?The period and angular velocity are related according to the following formula:
ω = 2π/ T
Inputting the given parameters, we can obtain the period of the pendulum as follow:
0.66 = (2 × 3.14) / T
0.66 = 6.28 / T
Cross multiply
0.66 × T = 6.28
Divide both sides by 0.66
T = 6.28 / 0.66
T = 9.52 seconds
Thus, we can conclude that the period of the pendulum is 9.52 seconds
Learn more about period:
https://brainly.com/question/30954684
#SPJ1
how cold does it have to be for a snowflake to form around a dust particle?
Answers
Answer:
32 degrees Fahrenheit
Snow forms when the atmospheric temperature is at or below freezing and there is a minimum amount of moisture in the air. If the ground temperature is at or below freezing, the snow will reach the ground.
Explanation:
7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
Answers
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
To learn more about tension, click:
https://brainly.com/question/30037765
#SPJ1
earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________
Answers
earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.
What is energy?Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The term earth's energy budget is also described as the balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.
The earth's energy budget was mainly three types as shown:
shortwave radiation, longwave radiation, and internal heat sources.Learn more about energy at:
brainly.com/question/1932868
#SPJ1
Read more on Brainly.com - https://brainly.com/question/28267182#readmore
Calculate the net force on the particle q1.
Answers
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
Tarnish is produced by a redox reaction that occurs when a metal reacts with
a nonmetallic compound. The green tarnish on a copper penny might be
produced by a reaction between copper and hydrogen sulfide. What occurs
during this reaction?
A. Hydrogen sulfide acts as an acid, and copper acts as a base.
B. Copper atoms gain electrons from sulfur atoms.
C. A double-replacement reaction takes place.
D. Copper atoms lose electrons to sulfur atoms.
Answers
Answer:
Copper atoms lose electrons to sulfur atoms
Explanation:
a p e x (:
Radioactivity is a natural process. Is this true or false?
Answers
Radioactivity is defined as the decay of unstable atoms. Radioactivity can be found in nature. But it can also be man-made. A lot of man-made radioactivity because of its uses in the military, medical and scientific purposes.
Thus the given statement is false. Radioactivity can be natural as well as man-made.
Answer: True
Explanation: Radioactivity is a natural process that occurs spontaneously in certain types of atoms. It involves the decay or disintegration of atomic nuclei, resulting in the release of radiation. Hence, the answer is True.
To accelerate, an object must
Answers
Answer:
be acted upon an object or person
Explanation:
PHYSICS! HELP ME PLEASE ASAP!
1.) If an ambulance passes you while you're walking your dog, a change in pitch is ____?
A.) not perceived by either the pedestrian or you
B.) perceived by the you
C.) perceived by the driver
2.) In the star wars movies, the soundtrack is very important. musicians and sound technicians spend weeks perfecting the noise of the light sabers, lasers, tie fighters and explosions. in real life, there would be no sound at all in space. Why?
A.) mechanical waves require a medium to travel
B.) sound is an electromagnetic wave
C.) mechanical waves do not require a medium to travel
D.) sound is a product of vibration
3.) what is a compression?
A.) region of zero pressure in a medium caused by a wave passing
B.)region of a high altitude in a medium caused by a passing wave
C.) region of a high pressure in a medium cause by a passing wave
D.) region of low pressure in a medium caused by a passing wave
Answers
Answer:
1B, 2B and 3C hope this helps
Explanation:
Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
acceleration of Claudia's 1.80kg foot? B) What is the acceleration of the table if it has a mass
of 20.0kg? (ignore any frictional effects) C) Why would Claudia's toe hurt less if the table had
less mass?
Answers
Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more
A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to the wall is 300 m The time delay between clap an echo is 1.5 seconds. Calculate the speed of sound
Answers
Explanation:
∆x=300 m×2
∆t=1.5 s
v=∆x/∆t → v=2×300/1.5 = 400 m/s
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
for more question on force
https://brainly.com/question/12785175
#SPJ8
If a 40 N block is resting on a rough horizontal table with a coefficient of static friction
Answers
If a 40 N block is resting on a rough horizontal table with a coefficient of static friction is 12 N.
What is static friction?Static friction is a force that resists the motion of two objects that are in contact with each other. It is caused by the forces of attraction between the two objects and is usually greater than the force of kinetic friction. The forces of static friction oppose the movement of the two objects and can be overcome by applying a force greater than the static friction.
The maximum force the block can withstand before it starts to move is 40 N multiplied by the coefficient of static friction.
The coefficient of static friction between the block and the table is determined by the materials of the block and the table and the surface roughness of the table.
If the coefficient of static friction is 0.3, then the maximum force the block can withstand before it starts to move is 40 N × 0.3 = 12 N.
To learn more about static friction
https://brainly.com/question/22696010
#SPJ1
According to Newton's first law, an object at rest will _____.
never move
stay at rest forever
start moving
stay at rest unless moved by force
Answers
Select the correct answer.
What is a pendulum?
Answers
there are no answer choices so this is the best i can do sorry.
Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
Answers
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
For more question on tension
https://brainly.com/question/24994188
#SPJ11