1 ) The cheetah catches its prey after 277 m
2 ) The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is 31.5 m
Let the velocity of cheetah be Vc and that of gazelle be Vg.
Vc = 95.2 km / h
Vg = 79.9 km / h
Since they both travel for same amount of time,
Tc = Tg
dc / Vc = dc / Vg
( 0.0531 + x ) / 95.2 = x / 79.9
95.2 x = 4.24 + 79.9 x
15.3 x = 4.24
x = 0.277 km
x = 277 m
Distance travelled by cheetah in 7.5 seconds = 26.4 m / s * 7.5 s
Distance travelled by cheetah in 7.5 seconds = 198 m
Distance travelled by gazelle in 7.5 seconds = 22.2 m / s * 7.5 s
Distance travelled by gazelle in 7.5 seconds = 166.5 m
Distance that the gazelle need be ahead of cheetah to escape = 198 - 166.5 = 31.5 m
Therefore,
1 ) The cheetah catches its prey after 277 m
2 ) The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is 31.5 m
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Plz do all of it i will give brainlest and thanks to best answer
plz do it right
Answer:
d
Explanation:
Answer:
Earth absorbs heat from the sun.
Explanation:
This radiation is absorbed by greenhouse gases which then radiate energy into all directions including downwards and thereby trapping heat in the atmosphere.
Hope you have a good day :)
calculate the frequency of each wavelength of electromagnetic radiation: 632.8 nm (wavelength of red light from helium–neon laser) 503 nm (wavelength of maximum solar radiation) 0.052 nm (wavelength contained in medical x-rays)
the frequency of each wavelength of electromagnetic radiation is
A)frequency of wavelength 632.8nm(red light from helium–neon laser)
is 4.738×10¹⁴ s⁻¹
B)frequency of wavelength 503 nm (maximum solar radiation)
is5.960×10¹⁴ s⁻¹
C)frequency of wavelength 0.052nm (medical x-rays)
is5.765×10¹⁸s⁻¹
A)
632.8 nm (wavelength of red light from helium–neon laser)
1 nm = 10⁻⁹ m
632.8 nm = 632.8×10⁻⁹ m = 6.328×10⁻⁷ m
The speed of light is c = 2.998×10⁸ m/s
λ = 6.328×10⁻⁷ m
the frequency can be calculated as
ƒ = c / λ
ƒ = (2.998×10⁸m/s) / (6.328×10⁻⁷ m)
ƒ = 4.738×10¹⁴ s⁻¹
frequency of wavelength 632.8nm is 4.738×10¹⁴ s⁻¹
B)
503 nm (wavelength of maximum solar radiation)
1 nm = 10⁻⁹ m
503 nm = 503×10⁻⁹m = 5.03×10⁻⁷ m
c = 2.998×10⁸ m/s
λ = 5.03×10⁻⁷ m
the frequency can be calculated as;
ƒ = c / λ
ƒ = (2.998×10⁸ m/s) / (5.03×10⁻⁷m)
ƒ = 5.960×10¹⁴ s⁻¹
frequency of wavelength 503 nm is5.960×10¹⁴ s⁻¹
C)
0.052 nm (wavelength contained in medical x-rays)
1 nm = 10⁻⁹ m
0.0520 nm = 0.0520×10⁻⁹ m = 5.20×10⁻¹¹m
Where the speed of light is
c = 2.998×10⁸ m/s
λ = 5.20×10⁻¹¹ m
the frequency can be calculated as
ƒ = c / λ
ƒ = (2.998×10⁸ m/s) / (5.20×10⁻¹¹ m)
ƒ = 5.765×10¹⁸s⁻¹
frequency of wavelength 0.052nm is5.765×10¹⁸s⁻¹
A)frequency of wavelength 632.8nm(red light from helium–neon laser)
is 4.738×10¹⁴ s⁻¹
B)frequency of wavelength 503 nm (maximum solar radiation)
is5.960×10¹⁴ s⁻¹
C)frequency of wavelength 0.052nm (medical x-rays)
is5.765×10¹⁸s⁻¹
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a spring attached to the ceiling is stretched 100 mm when a mass of 2 kg is hung on its end. how much work must be done to compress the spring by 6 cm?
The work that must be done to compress the spring by 6 cm is 0.3528 J.
To determine the work that must be done to compress the spring by 6 cm:
\(U = (1/2)kx^{2}\)
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position :
\(F = kx\)
where F is the force exerted by the spring and x is the displacement from the equilibrium position:
\(F = mg = 2 kg * 9.8 m/s^{2} = 19.6 N\)
\(k = F/x = 19.6 N / 0.1 m = 196 N/m\)
Now, to find the work required to compress the spring by 6 cm (or 0.06 m), we can use the potential energy formula :
\(U = (1/2)kx^2 = (1/2)(196 N/m)(-0.06 m)^{2} = 0.3528 J\)
Therefore, the work that must be done to compress the spring by 6 cm is 0.3528 J.
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what is the main source of power in america
Answer:
Natural gas was the largest source—about 40%—of U.S. electricity generation in 2020
Explanation:
What is the wavelength of a 285-Hz sound wave when the speed of sound is 375 m/s?A. 1.2 mB. 1.32 mC. 106.875 kmD 0.76 m
ANSWER
\(B.\text{ }1.32\text{ }m\)EXPLANATION
The speed of a wave is given by the formula:
\(v=\lambda *f\)where λ = wavelength
f = frequency
Hence, the wavelength of the wave is:
\(\lambda=\frac{v}{f}\)Therefore, the wavelength of the sound wave is:
\(\begin{gathered} \lambda=\frac{375}{285} \\ \lambda=1.32\text{ }m \end{gathered}\)The answer is option B.
The South Pole-Aitken (SPA) impact basin, located on the far side of the Moon, is about 8 km deep and appears to be in isostatic balance. Describe how you would use the principle of isostasy to compute the thickness of the crust surrounding the basin, under the assumption that the basin forming impact excavated all the way to the mantle. For crustal and mantle densities of 2800 kg/m3 and 3400 kg/m3, respectively, compute the crustal thickness and discuss the reliability of this estimate.
Calculate crustal thickness around the South Pole-Aitken (SPA) basin by applying the principle of isostasy, assuming the basin excavated all the way to the mantle, with given densities of 2800 kg/m3 for the crust and 3400 kg/m3 for the mantle, and discuss the reliability of this estimate.
How to use the principle of isostasy?The principle of isostasy states that the Earth's crust will reach a state of equilibrium when it floats on the denser mantle below. In the case of the SPA impact basin, the thickness of the crust surrounding the basin can be computed by determining the amount of crust that would be required to balance the load of the impact basin.
Assuming that the impact excavated all the way to the mantle, the crustal thickness can be calculated as the depth of the basin plus the amount of crust required to balance the load. Using the given densities of 2800 kg/m3 for the crust and 3400 kg/m3 for the mantle, the crustal thickness is estimated to be around 35 km.
However, this estimate may not be entirely reliable as it assumes that the impact basin is in perfect isostatic equilibrium, which may not be the case. Additionally, there may be variations in crustal density and thickness in the region surrounding the basin that could affect the estimate. Therefore, further analysis and data would be needed to obtain a more accurate measurement of the crustal thickness.
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A(n) ________ is an interpretation of something you have observed?
A. inference
B. accuracy
C. critical thinking
D. bias
E. matter
Answer:
inference
Explanation:
inference is when u observe something and make ur own conclusion off of it so it may not be entirely accurate
hello people ~
64 drops each having the capacity C and potential V are combined to form a big drop. If the charge on the small drop is q, then the charge on the big drop will be
(a) 2q
(b) 4q
(c) 16q
(d) 64q
Answer:
64q
Explanation:
Note that
Charges are addaptive quantitiesHere
Capacitance C and potential V is given
We know
Q=CVSo charge is also same
Now
there are 64 drops so 64q charge
Which of the following is NOT an example of acceleration?
А
Speeding up
B
Slowing down
C Remaining at rest
D Stopping
Remaining at rest is not an example of acceleration. Acceleration is
defined as the rate in which the velocity of a body changes with time.
Acceleration could either be
Positive - Example include speeding up, etc.Negative- Example include slowing down, stopping etcWhile remaining at rest there is no change in velocity of the body. This is
why it is the most appropriate choice.
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John is a runner. He runs the 100m sprint in 10.6s. What speed did he travel at? (in m/s)
The answer you are looking for is approximately 9.4 m/s.
Solution/Explanation:
First, writing out the formula for the speed of an object, encompassing distance and time, in meters per second, or m/s,
S=D/T.
"S" stands for "Speed."
"D" stands for "Distance."
"T" stands for "Time."
Speed (S)=????
Distance (D)=100m.
Time (T)=10.6s.
Substituting the given values of the variables,
S=100m/10.6s.
100÷10.6=9.43396226415≈9.4.
So, therefore, the final answer is approximately 9.4 m/s.
I hope that this has helped answer your question. Good day to you.
the decibel level of sound is 50 db greater on a busy street than in a quiet room where the intensity of sound is 10^-10 watt/m2.
the level of sound in the quiet room is ____ dB, and the intensity of sound in the busy street is ____ watt/m^2.
Use the formula β = 10log(I/Io) , where β is the sound level in decibels, l is the intensity of sound, and Io is the smallest sound intensity that can be heard by the human ear (roughly equal to 1x10^-12 watts/m^2)
The level of sound in the quiet room is 20db and the intensity of sound in the busy street is \(l_{2} = 10^-^5 W\cdot m^-^2\)
Note, β = 10log(I/I₀)
Lets find level of sound in the quiet room given:
I = 10⁻¹⁰ W·m⁻²
I₀ = 1 × 10⁻¹² W·m⁻²
\(\beta = 10log[(10^-^1^0/(1 * 10^-^1^2)] = 10log(10^2) = 10 * 2 = 20 dB\)
Sound level in the quiet room is 20db
Lets find the intensity of sound in the busy street given:
β(street) - β(room) = 50 dB
Let us denote the intensity level equation
\(\beta = 10logI - 10 logl_{0}\)
Let A = the room and B = the road. Then,
(A) β₂ = 10logI₂ - 10logI₀
(B) β₁ = 10logI₁ - 10log I₀
Lets subtract (B) from (A)
\(\beta_{2} - \beta_{1} = 10logl_{2} - 10logl_{1}\)
\(50 = 10logl_{2} - 10log(10^-^1^0)\)
Lets divide each side by 10
\(5 = logl_{2} - log(10^-^1^0)\)
\(5 = logl_{2} - (-10)\)
\(5 = logl_{2} + 10\)
Lets subtract 10 from each side:
\(-5 = logl_{2}\)
Collect antilog of each side:
\(l_{2} = 10^-^5 W\cdot m^-^2\)
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you walk 5km north for 3 hrs and 2km south for 1 hr what your speed , velocity
Answer: Probably 0.33km/hr south is the net velocity
Explanation:
Speed= Distance/ Time
Speed in North = 5km/3hrs=1.67km/hr
Speed in South= 2/1hrs=2.00km/hr
Since north and south are in opposite directions, and taking north as the +ve y, we get 1.67-2.00= -0.33km/hr, (-ve represents south direction).
Which of the following cannot be addressed through scientific methods? (1 point) the freezing point of ethanol best rock band of all time mass of Mars energy needed to melt a 100 kilogram block of ice
Answer: The option that cannot be addressed through scientific methods is the best rock band of all time.
Explanation: scientific methods are powerful tools for understanding the natural world, but they have limitations. One of these limitations is that they cannot address subjective matters, value judgments, and personal preferences. These are areas where individual opinions and preferences play a significant role, and scientific methods are not designed to provide definitive answers in such cases.
For example, determining the freezing point of ethanol, the mass of Mars, and the energy needed to melt a 100 kilogram block of ice are all questions that can be addressed through scientific methods. These questions involve measurable quantities and can be investigated through observation, experimentation, and data analysis.
However, when it comes to identifying the best rock band of all time, personal preferences and opinions come into play. Different people may have different criteria for what makes a band the best, and these criteria are subjective and not easily quantifiable. Scientific methods cannot provide a definitive answer to this question because it is a matter of personal preference.
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The best rock band of all time cannot be addressed through scientific methods.
While scientific methods can be used to investigate and answer questions related to the freezing point of ethanol, the mass of Mars, and the energy needed to melt a 100 kilogram block of ice, determining the best rock band of all time is a subjective matter that falls within the realm of personal preference and opinion. It is not a question that can be objectively addressed or answered using scientific methods.
Scientific methods rely on observation, experimentation, and empirical evidence to study and understand the natural world. However, matters of taste, preference, and subjective judgment, such as determining the best rock band, involve personal opinions and can vary from person to person. Therefore, while scientific methods are applicable to many questions, they cannot provide a definitive answer to subjective matters like artistic preferences.
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Cellular respiration takes place in the mitochondria of cells.
Answer:
True
Because mitochondria is the powerhouse of the cell.
Explanation:
Hope this helps you
Answer:
True
Explanation:
A passenger car traveling at 75 m/s passes a truck traveling in the same direction at 35 m/s. After the car passes, the horn on the truck is blown at a frequency of 240 Hz. The speed of sound in air is 336 m/s. The frequency heard by the driver of the car is A) 208 Hz B) 169 Hz C) 328 Hz D) 266 Hz E 277 Hz 21. Tuning fork A has a frequency of 440 Hz. When A and a second tunine fork Bare struck simultaneously Coro
A passenger car traveling at 75 m/s passes a truck traveling in the same direction at 35 m/s. the frequency heard by the driver of the car is approximately 267.67 Hz, which is closest to option D) 266 Hz.
To determine the frequency heard by the driver of the car after the car passes the truck, we need to consider the Doppler effect.
The Doppler effect describes how the frequency of a sound wave changes when there is relative motion between the source of the sound and the observer. When the source and observer are moving towards each other, the frequency is higher, and when they are moving away from each other, the frequency is lower.
In this case, the car is moving towards the truck. The frequency heard by the driver of the car can be calculated using the formula:
Observed frequency = Source frequency × (Speed of sound + Speed of observer) / (Speed of sound + Speed of source)
Plugging in the given values:
Observed frequency = 240 Hz × (336 m/s + 75 m/s) / (336 m/s + 35 m/s)
Calculating the expression:
Observed frequency = 240 Hz × 411 m/s / 371 m/s
Simplifying:
Observed frequency ≈ 267.67 Hz
Therefore, the frequency heard by the driver of the car is approximately 267.67 Hz, which is closest to option D) 266 Hz.
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Moon A has a mass of 3M and a radius of 2R. Moon B has a mass of 4M and a radius of R. What is the ratio of the force of gravitational attraction of Moon A for Moon B to the force of gravitational attraction of Moon B for Moon A?
A.) 1:1
B.) 1:5.3
C.) 5.3:1
D.) 0.75:4
Answer:
c
Explanation:
5.3" (and any subsequent words) was ignored because we limit queries to 32 words.
A circus performer is putting together an act that involves lying on a bed of nails without getting hurt. The tip of each nail has a radius of 1 mm and the performer has a mass of 65 kg. A typical human pain threshold for pressure on the skin is about 0.4MPa (1MPa = 10 Pa). This is the minimum pressure that causes a sensation of pain. Part a (1 points) If the performer stepped on a single nail, what pressure would the nail exert on his foot? Give you answer in mega-Pascals (MPa).
The pressure exerted by a single nail on the performer's foot is approximately 203 MPa.
How much pressure does a single nail exert on the performer's foot?To determine the pressure exerted by a single nail on the performer's foot, we need to calculate the force exerted by the nail and divide it by the area of contact.
The force exerted by the nail can be calculated using the formula:
Force = mass x acceleration
Given that the performer has a mass of 65 kg and the acceleration due to gravity is approximately 9.8 m/s²,
we can calculate the force as:
Force = 65 kg x 9.8 m/s² = 637 N
The area of contact can be approximated by considering the tip of the nail as a circle with a radius of 1 mm.The area of a circle can be calculated using the formula:
Area = π x (radius)²
Substituting the values, we have:
Area = π x (0.001 m)² ≈ 3.14 x 10⁻⁶ m²
Finally, we can calculate the pressure exerted by the nail on the foot by dividing the force by the area:
Pressure = Force / Area
Pressure = 637 N / (3.14 x 10⁻⁶ m²) ≈ 2.03 x 10⁸ Pa
Converting this pressure to mega-Pascals (MPa), we divide by 10⁶:
Pressure ≈ 2.03 x 10² MPa
Therefore, if the performer stepped on a single nail, the nail would exert a pressure of approximately 203 MPa on his foot.
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what is the concentration of a chemical in an oil spill in ppb if 0.060 mg of it is found in 4600 kg of soil?
The concentration of an chemical in an oil spill in ppb is 0.013 ppb (approx).
What is concentration?concentration is the abundance of a constituent divided by the total volume to the mixture. Several by the types of mathematical description can be the distinguished: mass of the concentration, molar concentration, number and concentration, and volume concentration.
Calculate the concentration in ppb by multiplying to the ratio of the mass of solute to mass of solution by 1 billion or 10 ^9
So here the answer can be calculated by
(10^ 9)(6×10 ^-8)/4600
(Here 0.060 mg = 6 × 10 ^-8 kh)
= 6/460
= 0.013 ppb (approx)
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Question 23 of 25 Which statement describes a question that can guide the design of a scientific investigation? A. It asks about a cause-and-effect relationship between two variables. B. It asks about how the observations will be organized. C. It asks about whether a controlled variable is necessary. OD. It asks about the preferred outcome of the investigation.
Scientific investigation asks about a cause-and-effect relationship between two variables. Thus, the correct answer is (a).
Scientific investigation is intended to create a hypothesis and demonstrate its validity or lack thereof. Experiments must be conducted in order to test these hypotheses, and these experiments are planned in accordance with the discovery of a cause-and-effect relationship between the two variables under scientific investigation. In these experiments, the "cause" is variable upto various degrees, and the "effect" of the variance is noted. The experimental design, which will try to manipulate the causes to see how these manipulations impact the second variable, will thus be guided by knowledge of the cause-and-effect connection.
Observations are frequently the first step in a scientific investigation.
An observation is something that is discovered using the senses of humans or tools and measurement technologies that support the senses of humans. Important scientific discoveries may result from unintentional observations.
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A wave has a speed of 2.2 kilometers per second (km/s), and a wavelength 2 points
of 1.8 kilometers (km). What is the frequency of the wave.
Answer:
pjgfiomohibugydtdraesrsstdytsrstatfgikokugulfyiditsrsrftftdyfypjgfiomohibugydtdraesrsstdytsrstatfgikokugulfyiditsrsrftftdyf
HELP. A river flows South with a speed of 8m/s. From the shore, you see a boat moving South with a speed of 10 m/s. From their frame of reference, how fast are the rowers moving?
Answer:
18 m/s
Explanation:
Given that,
Speed of river is 8 m/s due South
From the shore, you see a boat moving South with a speed of 10 m/s. Both boat and river are moving in same direction. The resultant velocity will add up.
v = 10 m/s + 8 m/s
v = 18 m/s
Hence, the rowers are moving with a speed of 18 m/s.
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
Describe a situation in which all four spheres of the Earth interact with each other.
Answer:
All the spheres interact with other spheres.
Explanation:
Rain (hydrosphere) falls from the clouds in the atmosphere to the lithosphere and then forms streams and and rivers that provide drinking water for wildlife and humans and water for plants and crops to grow.
Complete each statement to identify the form of asexual reproduction.
During
, a new plant grows from parts of the parent plant.
During
, a cell divides to produce a new, genetically identical cell.
During vegetative propagation, a new plant grows from parts of the parent plant.
During binary fission, a cell divides to produce a new genetically identical cell.
Asexual reproduction involves fission, budding, fragmentation, and parthenogenesis, whereas sexual reproduction is achieved by combining the germ cells of two individuals. The statement describing asexual reproduction is Offspring are born that have the same DNA as the parent.
Only one parent is needed to produce a child. Includes cell division similar to cell division in mitosis. Asexual reproduction is a form of reproduction in which the offspring produced are exactly like their parents. Also, there is no formation of two different gametes, nor the involvement of two different sexes. In unicellular organisms, mitosis is the mode of asexual reproduction.
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Aiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two subatomic particles. Do you agree with her? Why or why not?
Answer:
I don't agree
Explanation:
Atoms have 3 subatomic particles protons, electrons and neutrons,
Plane used to remove the tip of your nose
A. Transverse (top/bottom)
B. Sagittal (sides)
C. Frontal (front/back)
Plane used to remove the tip of your nose is known to be called option C. Frontal (front/back).
What is another name for the coronal plane?In regards to biology, If a person were to cut their nose off, it is one that is known to be called coronal.
The coronal plane is said to be a term that is often referred to as the frontal plane and it is seen as any vertical plane that shares the body into ventral as well as dorsal (belly and back) parts.
Therefore one can say that the coronal Plane (Frontal plane) used to remove the tip of your nose.
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1. Black Panther ran 567.6 km to the east in 23 hours then turned around and ran 221.8 km to the west in 1.2 hours. What was his average velocity during the trip in km h?p
Answer:
80.08 km/h
Explanation:
Given that Black Panther ran 567.6 km to the east in 23 hours
Velocity = distance covered/time
Substitute the distance covered and time into the formula
Velocity = 567.6/23
Velocity = 24.68 km/h
then turned around and ran 221.8 km to the west in 1.2 hours.
Velocity = 221.8/1.2
Velocity = 184.83 km/h
What was his average velocity during the trip in km/h ?
Average velocity = (V + U)/2
Since the two velocity are opposite to each other, the average velocity will be:
Average velocity = (-24.68 + 184.83)/2
Average velocity = 160.15/2
Average velocity = 80.08 km/h
Therefore, his average velocity during the trip is 80.08 km/h
hydrostatic pressure force always acts on the centroid of the area. true false
False. Hydrostatic pressure force does not always act on the centroid of the area.
The statement that hydrostatic pressure force always acts on the centroid of the area is false. Hydrostatic pressure is the pressure exerted by a fluid at rest due to the weight of the fluid above it. It depends on the depth and density of the fluid and is perpendicular to any surface it acts upon.
When considering a submerged surface, such as a submerged plate or wall, the hydrostatic pressure force is indeed applied normal to the surface. However, this force does not necessarily act at the centroid of the area. The distribution of hydrostatic pressure forces depends on the shape and orientation of the surface.
For irregularly shaped surfaces or surfaces with varying depths, the hydrostatic pressure force acts differently at different points. It follows the principle of Pascal's law, which states that the pressure at a point in a fluid is transmitted equally in all directions. As a result, the force distribution can vary across the surface.
In summary, the hydrostatic pressure force does not always act on the centroid of the area. Its distribution depends on the shape, orientation, and depth of the submerged surface, following the principles of Pascal's law.
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11. In conflict resolution,
promotes____ a win-lose outcome.
negotiation.
SANA MAKATULONG.
In the conflict resolution, promotes competition a win-lose outcome. Competition results into conflict when two parties tend to seek control over a situation.
What is Competition in conflict management?Competition results when one's own needs are advocated over the needs and requirements of others. It relies on an aggressive style of communication, which is of low regard for future relationships, and the exercise of coercive power. Those who are using a competitive style tend to seek control over a situation, in both the substance and ground rules.
There are times, when competition between two individuals can escalate into an unproductive, and dangerous conflict. The danger can range from unproductive behavior of a person to unethical behavior which could include physical attack. This results into a win-lose outcome.
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A man can swim still with a velocity of 4 m\s.He crosses a river directly perpendicular to the river when he heads 30° with the normal to the riverbank. What is the velocity of the river?
The velocity of the river is 8 m/s. The standard unit for velocity is meters per second (m/s).
What is Velocity?
Velocity is a physical quantity that refers to the rate at which an object changes its position with respect to a reference point. In other words, velocity describes both how fast an object is moving and in what direction it is moving.
This problem can be solved using vector addition.
Let the velocity of the swimmer be v_s = 4 m/s at an angle of 30 degrees to the normal to the riverbank.
Let the velocity of the river be v_r = ? m/s in an unknown direction.
The velocity of the swimmer relative to the river can be found using vector addition:
v_s/r = sqrt(v_s^2 + v_r^2 - 2v_sv_r*cos(theta))
where theta is the angle between the velocity of the swimmer and the velocity of the river.
Since the swimmer is crossing the river directly perpendicular to the river, theta = 90 degrees.
v_s/r = sqrt(v_s^2 + v_r^2 - 2v_sv_r*cos(90))
v_s/r = sqrt(v_s^2 + v_r^2)
Substituting in the values:
4/v_r = sqrt(4^2 + v_r^2)
16/v_r^2 = 16 + v_r^2
v_r^2 + 16v_r - 256 = 0
Using the quadratic formula:
v_r = (-16 ± sqrt(16^2 + 41256)) / 2*1
v_r = (-16 ± sqrt(1024)) / 2
v_r = (-16 ± 32) / 2
The negative solution is not physically meaningful, so we take the positive solution:
v_r = 8 m/s
Therefore, the velocity of the river is 8 m/s.
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