A Clear Falls wrestler bench presses 64 kg. If the barbell accelerates upward at a rate of 2.57 m/s2, what is the force exerted by the wrestler on the weights?

The net force acting on the crate is determined as 176 N to the left.

The net force acting on the crate is calculated as follows;

∑F = F1 + F2 + F3 + F4

F(net) = -440y + 176x + 440y - 352x

F(net) = -176 x

The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

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The maximum height attained by the ball is 32 units.

Principle-

The second derivative can show graphically whether a curve is concave upwards or downwards at a point x in the domain.

The graph is concave upward if the second derivative at point x in the domain is positive. The graph is concave downward if the second derivative at a point x in the domain is negative.

A function has a local minimum at a point x in its domain if the first derivative is zero and the second derivative is positive at that location. When a function's second derivative is negative and its first derivative is zero at a given point x in its domain, the function is said to have a local maximum there.

calculations-

\(S= 128 +80t -16t^{2}\)

Taking derivative of this function

\(S'=80+32t\)

Now again taking derivative of function

\(S''= 32\)⇒height attained.

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Force applied is directly proportional to displacement.

It is given by the formula

Here F is the force , k is the spring constant , x is the displacement.

Substituting the values,

Answer:

Series

Explanation:

Wired in 'series' means there is only one path for current.....so when either light burns out, the circuit is broken and there is no path for current so the other light will be unlit

Sir Isaac Newton's three laws of motion are manifested in nearly every activity of everyday life including traffic accidents. From flying birds to racing cars these laws of motion are everywhere. In fact, nearly 99% of all activity in our physical world is usually governed by these laws.

Newton's laws of motion are very important when engineers design airplanes sports equipment cars train toys and more. This article describes Newton's three laws of motion in car accidents. Newton's first law of motion states that when an object is in motion, it will move at the same speed and in the same direction, or if it is at rest, it will continue to move until acted upon by an external force. In other words, objects have a natural tendency to continue doing what they were doing until they respond.

In the absence of an external force, a moving object maintains its original state of motion or remains stationary.  This law is usually called the law of inertia. Newton's second law of motion states that an object subjected to a force experiences an acceleration such that the force is equal to the mass times the acceleration. Mathematically this is expressed as . In other words, the force exerted during a collision is proportional to the mass of the colliding vehicle. This means that the more force a car collides with the more force it applies which means more destruction. The opposite is also true If the mass of the colliding vehicle is less, less force will be applied and there will generally be less destruction.

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The jolt you feel when your car speeds up or slows down suddenly is called acceleration or deceleration.

The jolt you feel when your car speeds up or slows down suddenly is called acceleration. When the car speeds up, it experiences positive acceleration, and when it slows down, it experiences negative acceleration, also known as deceleration.

Acceleration is the rate at which the velocity of an object changes with time. Accelerations are vectors (because they have magnitude and direction). The direction of acceleration of an object is given by the direction of the resultant force acting on that object. As stated in Newton's second law, the magnitude of the object's acceleration is a combination of two factors:

The sum of all external forces acting on the product size is proportional to the net profit;

The size of the object depends on the material from which it is made - the size is inversely proportional to the size of the object.

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The trailer pulls on the vehicle with an average force of A=B=C.

Newton's second law of acceleration is expressed as follows: F = ma

In this case, the mass is m, and the acceleration is a.

Assume that g=9.8 m/s2 represents the acceleration caused by gravity.

The acceleration of the object will be zero if it is travelling at a constant speed.

Because of the constant velocity, the van's net force on the trailer is therefore zero.

As a result, the van applies the same amount of force to each trailer. Thus, FA FB = FC.

As a result, each trailer pulls on the van with the same amount of force in the opposite direction. FA' = FB' = Fc', therefore.

As a result, A=B=C represents the rank of the force the trailer exerts on the van.

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Explanation:

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Answer:

The force of gravity acting on a 10 kg object is 98N.

Explanation:

What is gravity?

How to calculate the force of gravity acting on a body?

        where F = the force of gravity

        m = mass of the object and

        g = acceleration due to gravity

It is given that

Putting these values in the equation  F = mg, we find

F = 10 kg x 9.8 m/s²

  = 98 kgm/s² or 98 N.

Therefore, the force of gravity acting on a 10 kg object is 98N.

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Answer:

1) Superposition results in adding the two waves together. Constructive interference is when two waves superimpose and the resulting wave has a higher amplitude than the previous waves. Destructive interference is when two waves superimpose and cancel each other out, leading to a lower amplitude.

I'm sorry thats all I can help with

Answer:

Turn off the second drip and then add a barrier with one slit. What do you observe on the right side of the wall? What do you observe on the left side of the wall? From a physics perspective, explain your observations of what is happening on both sides of the barrier.

Explanation:

 The speed and amplitude of the waves are affected when hitting the barrier. The two waves reflect off the barrier and they travel in opposite directions.

you may check it online

It's important to know that the wavelength and the frequency has inverse relationship, which means the longest is its wavelength, the more intense will be the frequency.

A synchronous motor is taking 50 A at 440 volts and 0.9 power factor lagging, the efficiency of the motor is approximately 87.37%. The correct option is c.

We must first know the input and output power of the synchronous motor in order to assess its efficiency.

Here, it is given that:

Current (I) = 50 A

Voltage (V) = 440 V

Power factor (pf) = 0.9 (lagging)

Effective resistance (R) = 0.8 Ω

Friction and windage loss (Pfw) = 500 W

Pin = V * I * pf

Pin = 440 V * 50 A * 0.9

Pin = 19800 W

Pout = Pin - Pfw - I^2 * R

Pout = 19800 W - 500 W - (50 A)^2 * 0.8 Ω

Pout = 19800 W - 500 W - 2000 W

Pout = 17300 W

Finally,

η = (Pout / Pin) * 100%

η = (17300 W / 19800 W) * 100%

η = 87.37%

Therefore, the efficiency of the motor is 87.37%. The correct option is c.

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F = 0(I1I2L)/(2d) represents the force between two parallel wires, where 0 is the permeability of free space, L represents the wires' length, and d represents the spacing between the wires. We obtain r = 5.02 by solving for r in the formula F = I2 r and substituting the supplied values.

F = 0(I1I2L)/(2d), where 0 is the permeability of empty space, I1 and I2 are the currents flowing through the wires, L is the length of the wires, and d is the distance between the wires, calculates the force between two parallel wires. The formula F = I2 r, where F is the force between the wires and I2 is the current running through one of the wires, may be used to determine the resistance value that will produce a force of 1.26x10-4 N. We get r = 5.02 by entering the specified data into these calculations. This indicates that a resistor with a value of 5.02 ohms would produce a force between the two of 1.26x10-4 N.

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Answer:

You need to give the options but the formula is p=mv

Explanation:

The quadratic function in standard form is:h(t) = -6t² + 19.5072t + 24.384 meters.

The acceleration of gravity on Mars is 12 meters/second²A rock is thrown vertically from a height of 80 feet with an initial speed of 64 feet/second. The given values are in two different units, we should convert them into the same unit.1 feet = 0.3048 meterTherefore,80 feet = 80 × 0.3048 = 24.384 meters64 feet/second = 64 × 0.3048 = 19.5072 meters/second

The quadratic function for the given problem can be found using the formula:

h = -1/2gt² + v₀t + h₀

whereh₀ = initial height of rock = 24.384 mv₀ = initial velocity of rock = 19.5072 m/st = time after which the rock hits the groundg = acceleration due to gravity = 12 m/s²

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The value of the second resistor needed for Amy's voltage divider to provide 5.0 V

To determine the value of the second resistor needed for Amy's voltage divider to provide 5.0 V, we can use the voltage divider formula:

V_out = V_in * (R2 / (R1 + R2))

Where V_out is the desired output voltage (5.0 V), V_in is the input voltage from the battery (6.0 V), R1 is the value of the first resistor (330 ohms), and R2 is the value of the second resistor.

Rearranging the formula to find R2, we get:

R2 = (V_out * (R1 + R2)) / V_in

Plugging in the known values and solving:

R2 = (5.0 * (330 + R2)) / 6.0

R2 = (1650 + 5R2) 6.0

R2 = 275 + 5/6R2

R2 - 5/6R2 = 275

0.1667 R2 = 275

R2 = 165

Solving for R2, we find that its value should be approximately 165 ohms.

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The magnitude of the gravitational force acting on the satellite is 3.16 x 10^22 N.

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation: F = G * (m1 * m2) / r^2, where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers.

To calculate the gravitational force acting on the satellite, we need to know the mass of the satellite (m1) and the distance between the center of Earth (m2) and the center of the satellite (r).

The mass of the satellite is given as 1,500 kg

The distance between the center of Earth and the center of the satellite is the distance from the surface of Earth to the satellite + the radius of Earth:

r = (1 Earth radius + 6.37 x 106 m)

We can use the given information to calculate the force of gravity acting on the satellite:

F = G * (m1 * m2) / r^2

F = (6.67 x 10^-11 N*(m^2)/(kg^2)) * (1,500 kg * 5.97 x 1024 kg) / (6.37 x 106 m + 6.37 x 106 m)^2

F = 3.16 x 10^22 N

The magnitude of the gravitational force acting on the satellite is 3.16 x 10^22 N.

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Answer:

3,700 N

Explanation:

Someone already explained it, but didn't give an answer that can be put into khan academy.

The voltage across the conductor is 500V.

Ohm's law states that the current through a conductor is directly proportional to the voltage across the conductor.

Here,

Current in the conductor, I = 50A

Resistance of the conductor, R = 10 Ω

According to Ohm's law,

V α I

V = IR

V = 50 x 10

V = 500 V

Hence,

The voltage across the conductor is 500V.

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Answer:

Mechanical energy

Explanation:

Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.

The inventor who developed the idea of a central power station was Thomas Edison.

He is credited with creating the first central power station in New York City in 1882. This power station was used to provide electricity to customers in a concentrated area, and it marked the beginning of the widespread use of electricity for lighting and power.

Edison's development of the central power station system was a major step in the advancement of the electrical power industry.

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Yes, the flow does directly move outward from high pressure to low pressure at the surface. The surface winds and winds aloft can’t move directly from high pressure to low pressure. This is because of the Coriolis effect.

The Coriolis effect is a deflection of moving objects when they are viewed from a rotating reference frame. In a reference frame with clockwise rotation, the deflection is to the left of the motion of the object; in one with counter-clockwise rotation, the deflection is to the right.

Because Earth rotates, it has a Coriolis effect – winds and currents deflect to the right in the Northern Hemisphere and to the left in the Southern Hemisphere.

Corollary to this, there is something called geostrophic balance in the upper atmosphere where the pressure gradient force (which is directed from high pressure to low pressure) and the Coriolis force act in opposite directions.

This means that the upper-level winds move parallel to the isobars (lines of equal pressure) and that air flows from high pressure to low pressure along a path that is perpendicular to the isobars.

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Yes, the flow does directly move outward from high pressure to low pressure at the surface. The surface winds and winds aloft can’t move directly from high pressure to low pressure. This is because of the Coriolis effect.

The Coriolis effect is a deflection of moving objects when they are viewed from a rotating reference frame. In a reference frame with clockwise rotation, the deflection is to the left of the motion of the object; in one with counter-clockwise rotation, the deflection is to the right.

Because Earth rotates, it has a Coriolis effect – winds and currents deflect to the right in the Northern Hemisphere and to the left in the Southern Hemisphere.

Corollary to this, there is something called geostrophic balance in the upper atmosphere where the pressure gradient force (which is directed from high pressure to low pressure) and the Coriolis force act in opposite directions.

This means that the upper-level winds move parallel to the isobars (lines of equal pressure) and that air flows from high pressure to low pressure along a path that is perpendicular to the isobars.

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The language of the given pushdown automaton (PDA) can be described as follows:

The PDA has a stack alphabet consisting of symbols 'a', 'b', 'z', '6', '1', '۸', '2', '9', '0', 'x', 'y'. 'z' represents the stack end symbol.

The transitions of the pushdown automaton (PDA) are as follows:

Thus, the language accepted by this PDA is characterized by a sequence of 'a's followed by a sequence of 'b's, where the number of 'b's is three times the number of 'a's, and each 'b' is followed by a corresponding sequence of '90', '91', '92', 'a', 'b', 'b', 'b', '1', 'b', 'b', '1', and ending with '1'.

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The voltages across the resistor, capacitor, and inductor are 12.0 V, 23.4 V, and 40.2 V, respectively.

First, let's calculate the total impedance of the circuit, which is the total opposition to the flow of current:

Z = R + Xc + Xl

where R is the resistance, Xc is the capacitive reactance, and Xl is the inductive reactance.

R = 15.0 ohms (given)

Xc = 1/(2πfC) = 1/(2π(1400 Hz)(3.80 × 10^-6 F)) = 29.3 ohms

Xl = 2πfL = 2π(1400 Hz)(5.70 × 10^-3 H) = 50.3 ohms

Z = 15.0 + 29.3 + 50.3 = 94.6 ohms

Now, we can find the voltage across each component using the voltage divider rule:

V = IRX

where I is the current in the circuit, and RX is the resistance, capacitive reactance, or inductive reactance of the component.

To find the current, we can use Ohm's law:

V = IR

I = V/R = (12.0 V)/(15.0 ohms) = 0.8 A

Voltage across the resistor:

VR = IR = (0.8 A)(15.0 ohms) = 12.0 V

Voltage across the capacitor:

VC = IXc = (0.8 A)(29.3 ohms) = 23.4 V
Voltage across the inductor:

VL = IXl = (0.8 A)(50.3 ohms) = 40.2 V

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The approximate length of the shadow cast by the tower when the angle of elevation to the Sun is 65º is 66.2 feet.

To determine this, we can use the concept of similar triangles. The angle of elevation to the Sun and the angle of elevation to the top of the tower are the same for both scenarios. Therefore, the ratios of the corresponding sides of the triangles will be equal. Given that the length of the shadow is 64.3 feet when the angle of elevation is 69º, we can set up the following proportion: (Length of the shadow)/(Height of the tower) = (Length of the shadow when angle of elevation is 65º)/(Unknown height of the tower).

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Answer:

program explanation

Explanation:

program explanation

The set of activities having a long-term aim should be a program.

A program refers to a set of instructions that a computer follows in order to perform a specific task. At the time When you program a computer, you provide it a set of instructions to make it able to perform a particular task.

So here the program should be considered.

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The radius of the cylindrical barrel is 0.78 m.

The circular area of the cylindrical barrel is calculated as follows;

P = F/A

A = F/P

where;

A = mg/P

A = (50 x 9.8) / (260)

A = 1.885 m²

A = πr²

r² = A/π

r = √(A/π)

r = √(1.885/π)

r = 0.78 m

Thus, the radius of the cylindrical barrel is 0.78 m.

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The forces acting on a skateboard include gravity, friction, air resistance, and applied force, and they all affect the motion of the skateboard in different ways.

When a skateboard is in motion, several forces act on it that affect its movement. The main forces acting on a skateboard are:

Gravity: This is a force that pulls the skateboard downwards towards the ground. The weight of the skateboard and the rider are also affected by gravity.

Friction: This is a force that opposes the motion of the skateboard. Friction is caused by the skateboard's wheels rolling on the ground or surface, and it can slow down the skateboard's speed.

Air resistance: This is a force that opposes the motion of the skateboard as it moves through the air. The faster the skateboard moves, the more air resistance it experiences.

Applied force: This is the force applied by the rider to propel the skateboard forward or to perform tricks. The amount of applied force determines how fast or slow the skateboard moves.

The combination of these forces affects the motion of the skateboard. If the applied force is greater than the forces of friction, air resistance, and gravity, the skateboard will accelerate. If the forces of friction, air resistance, and gravity are greater than the applied force, the skateboard will slow down or come to a stop.

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