A Clear Falls wrestler brings a barbell down to his chest as he bench presses 90 kg. If the barbell accelerates downward at a rate of 2.69 m/s2 , what is the force exerted by the wrestler on the weights?
Answers
Force exerted by the wrestler on the weights is 161.4 N.
Force is the intensity by which any object is pulled or push-ed.
Also it is the product of mass and accelerationMathematically, force can be denoted as F = m*a .The bench press is a machine for the exercise of the body. It is commonly used to build body strength
This exercise targets the muscles of the shoulder.Mass noted by the bench press = m = 60 kg
Acceleration at which the bench press accelerated = a = 2.69
Force = F = m * a
F = 60 * 2.69
F = 161.4 N
161.4 N of force will be exerted on the weights.
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Related Questions
Distinguish between kinectic energy and potential energy
Answers
Answer:
kinectic energy-in physics kinetic energy of an object is the energy that it possesses due to its motion
it is defined as the work needed to accelerate a body of a given mass from rest to its started velocity.having gained this energy during its accelerationThe body maintains this kinetic energy unless its speed changes.
potential energy-in physics potential energy is the energy held by an object because of its position relative to other objects,its electric charge,or other factors
in the case of a bow and arrow ,when archer does work on the bow drawing the string back some if the chemical energy of the archer's body is transformed into elastic potential energy in the bent limb of bowAnswer:
Hey!
Well KINETIC ENERGY is...
the energy generated by the / of the object is that it possesses due to its motion...
POTENTIAL ENERGY is...
The energy held by an object because of its position relative to other objects, its electric charge, or other factors...
Explanation:
So in easier terms, KINETIC ENERGY is just the ENERGY GENERATED BY THE OBJECT'S MOVEMENT and...
POTENTIAL ENERGY IS THE TOTAL AMOUNT OF ENRGY THAT THE OBJECT HOLDS (due to an electric charge etc)
Hope this helps!
gases expand to fill the volume and shape of their container, because the rapidly moving particles experience negligible attractive forces for each other. group startstrue or false true, unselected false, unselected
Answers
The quickly moving particles experience insignificant attraction forces for one another, therefore gases do indeed expand to fill the volume and form of their container.
The attraction forces is an attraction that draws the body to it. In nature, there are many alluring forces at work. Among these are gravitational force, magnetic force, electric force, and electrostatic force. When a gases is heated, the particles' kinetic energy rises, which causes the gases to expand. When a gas is heated, the container's volume needs to be raised in order to maintain the pressure.
Because the quickly moving particles encounter low attraction forces for one another, gases expand to fill the volume and shape of their container.
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To make a position-time graph, you plot position relative to the starting point on the y-axis against the corresponding_______on the x-axis.
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A friend of yours tells you that electric potential and voltage are the same thing. should you correct her, and if so, how?
Answers
I’d correct her in this way.
Electrical potential is the amount of energy acquired or lost per unit of charge when a charge is moved away from a reference point where the potential is assumed to be zero. Voltage is the difference in potential between any two places, where the potential may or may not be zero.
Suppose that point A's potential is 10000 volts and point B's potential is 10100 volts with respect to a stated reference point that is sometimes an infinite distance away. So 100 volts of voltage will exist between B and A.
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A cheerleader jumps off from the shoulders of two of her teammates. They all fell at the same rate, as a result. This type of collision is...?
Answers
Answer:
elastic collision
Explanation:
a volume of 100 ml of 1.00 m hcl solution is titrated with 1.00 m naoh solution. you added the following quantities of 1.00 m naoh to the reaction flask. classify the following conditions based on whether they are before the equivalence point, at the equivalence point, or after the equivalence point.
Answers
Without the quantities of NaOH added, it is not possible to classify the conditions as before, at, or after the equivalence point. However, in a titration of HCl with NaOH,
the equivalence point occurs when the number of moles of NaOH added is stoichiometrically equivalent to the number of moles of HCl in the solution. At this point, the solution will be neutral and the pH will be 7. Before the equivalence point, the HCl in solution will react with the added NaOH until all of the HCl is consumed, resulting in a decreasing pH. After the equivalence point, excess NaOH will be present in solution, resulting in an increasing pH. The point of inflection on a titration curve indicates the equivalence point, and the shape of the curve before and after the equivalence point depends on the acid-base properties of the substances being titrated.
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What is a cost benefit analysis?
Answers
Answer:
Cost–benefit analysis, sometimes also called benefit–cost analysis, is a systematic approach to estimating the strengths and weaknesses of alternatives used to determine options which provide the best approach to achieving benefits while preserving savings.
Explanation:
Plz Give Brainliest
The cost-benefit analysis is a systematic process to analyze the potential rewards expected from s situation. It is used to measure the benefits of a decision or action.
What are advantages of cost benefit analysis?Businesses employ a systematic procedure called cost-benefit analysis to choose which options to take and which to ignore. The cost-benefit analyst adds up the possible benefits anticipated from a circumstance or course of action before deducting the overall expenses related to that course of action.
Additionally, some consultants or analysts create models to put a monetary value on intangible things like the advantages and disadvantages of relocating to a specific location.
Intangible benefits, costs, or consequences of a choice, such staff morale and customer happiness, can also be included in a cost-benefit analysis. Sensitivity analysis, discounting of cashflows, and what-if scenario analysis for numerous choices may all be included in a more complicated cost-benefit analysis.
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Elasticity of demand is unitary when there is a _____________ (but inverse)change in quantity demanded for a given price change.
Answers
Elasticity of demand is unitary when there is a proportional (but inverse) change in quantity demanded for a given price change.
When the elasticity of demand is unitary, it indicates a balanced relationship between price and quantity demanded. The term "unitary" refers to a unit elasticity, where the percentage change in quantity demanded is equal in magnitude but opposite in direction to the percentage change in price.
In practical terms, a unitary elasticity of demand suggests that consumers are responsive to price changes in a manner that maintains their total expenditure on the product or service. When the price increases, the quantity demanded decreases proportionally, ensuring that the total amount spent by consumers remains constant. Conversely, when the price decreases, the quantity demanded increases proportionally, again maintaining the same total expenditure.
This unitary elasticity of demand is often observed for goods and services that are considered to have relatively elastic demand in one direction (e.g., price increases) and relatively inelastic demand in the opposite direction (e.g., price decreases). It implies that consumers are more sensitive to price increases and adjust their purchasing behavior accordingly, while being less sensitive to price decreases.
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Can someone please help meeeeeeee! I’m so bad at these stuff. Ill give brainliest too
Answers
2.) the rate of decrease is larger the higher the latitude.
3.) 9 hours, 46 minutes
4.) Key West, FL 78.1°F
5.) Russian city of Yakutsk
Last one don’t know how to answer sorry
a pilot performs an evasive maneuver by diving vertically at 330 m/s . if he can withstand an acceleration of 9.0 g 's without blacking out, at what altitude must he begin to pull out of the dive to avoid crashing into the sea?
Answers
12100 m is altitude must he begin to pull out of the dive to avoid crashing into the sea
Data given us that,
Velocity = 330 m/s
Acceleration = 9.0g s
centripetal acceleration
a=v^2/r
r=v^2/a
v = velocity
r = altitude
a = acceleration
Put the value
r=108900/9
r=12100 m
Gravity has an impact on how the missile moves vertically. As a result, the vertical component of the starting speed will be 0 at the highest altitude point. The projectile will slow down as it ascends to its highest point, come to a complete halt, and then begin its free fall plummet to the ground.
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A force of 6.0 N acts on a 4.0 Kg object for 10.0s. What is the object's change in momentum?
Answers
Answer:
60 Ns
Explanation:
change in momentum = Fxt
6*10
60 Ns
A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
change in momentum = force . time
change in momentum = 6 . 10 = 60
A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.
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We've seen that stout tendons in the legs of hopping kangaroos store energy. When a kangaroo lands, much of the kinetic energy of motion is converted to elastic energy as the tendons stretch, returning to kinetic energy when the kangaroo again leaves the ground. If a hopping kangaroo increases its speed, it spends more time in the air with each bounce, but the contact time with the ground stays approximately the same. Explain why you would expect this to be the case. Drag the terms on the left to the appropriate blanks on the right to complete the sentences._ stays the same) [doesn't depend on the amplitude] [decreases) is in inverse proportion with the amplitude is in direct proportion with the amplitude [increases) When in contact with the ground it is like a spring in simple harmonic motion. When kangaroo is hopping faster, the amplitude of the oscillation _____, while the period _____ because it _____, hence the time in contact with the ground
Answers
Answer:
Follows are the soplution to this question:
Explanation:
In the given scenario it would be like a fluid in a simple harmonic in contact with the earth. Whenever a cheetah hops quicker, oscillatory amplitude rises, while the duration stays the same since it does not depend on frequency, which mostly means that time will be the same if you're in contact with the substrate.
A 5 Kg mass has an initial speed of 5m/s. After 3 sec, it has come to a speed of 70 m/s.
a. What is the acceleration of the mass?
b. What net force is acting on the mass during those 3 seconds?
Answers
Answer:
a
\(a = 21.7 \ m/s^2\)
b
\(F = 108.5 \ N\)
Explanation:
From the question we told that
The mass is m = 5 kg
The initial speed \(u = 5 m/s\)
The time taken to attain \(v = 70 \ m/s\) is t = 3 s
Generally from kinematic equation we have that
\(v = u + at\)
=> \(70 = 5 + a * 3\)
=> \(a = 21.7 \ m/s^2\)
Generally the force acting is mathematically represented
\(F = m * a\)
=> \(F = 5 * 21.7\)
=> \(F = 108.5 \ N\)
Calculate the youngs modulus for the material of the wire
Answers
First, plot the data shown as points.
The points are (0,0), (1.4, 10), (2.8, 20), (4.2, 30), (4.9, 35), (5.8, 40), and (8, 45).
The graph shows a proportional part (a straight line) and a curvy part. So, the limit of proportionality is shown at the end of the straight line segment. The image below shows this limit.
The gradient of the straight-line portion refers to the slope. Let's use the points (1.4, 10) and (2.8, 20).
\(m=\frac{y_2-y_1}{x_2-x_1}=\frac{20-10}{2.8-1.4}=\frac{10}{1.4}\approx7.14\)Therefore, the gradient is 7.14.
The Young modulus formula is
\(E=\frac{\frac{F}{A}}{\frac{\Delta l}{l}}\)Let's use the greater force and the greater extension.
\(E=\frac{\frac{45N}{7\times10^{-8}m^2}}{\frac{8\times10^{-3}m}{2m}}=1.6\times10^{11}\)Therefore, Young Modulus is 1.6x10^11.
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)
Answers
Answer:
a. bernoulli's principle
b. archimedes' principle
c. pascal's principle
Explanation:
Answer:
Bernoulli - a
Archimedes - b
Pascal - c
If you drive at 120km/hr for 5 hours, how far will you go?
Distance:
Speed:
Time:
Answers
The distance of the travel covered within 5 hours with a speed of 120km/hr is the product of time and this speed and it is 600 km.
What is velocity?Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.
Velocity = distance/time.
Hence, as the time taken for the travel increases velocity will decreases. The time given here is 5 hours and the speed of the vehicle is 120 km/hr. Hence, the distance can be calculated as follows:
Distance = time × speed
= 5 hr × 120 km/hr
= 600 km.
Hence, if you drive at a speed of 120 km/hr for 5 hours you will cover a distance of 600 km.
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When elements gain electrons (negative friends), they become more ________
A. positive
B. neutral
C. negative
Answers
How many millimeters of water can dissolve 5g of lead nitrate
Answers
The solubility of lead nitrate is 52 grams per 100 milliliters of water at 0°C. Since the question does not specify the temperature, we will assume it is 0°C.To calculate the number of millimeters of water required to dissolve 5 g of lead nitrate,
we must first calculate the number of milliliters of water required to dissolve 5 g of lead nitrate.52 grams of lead nitrate can dissolve in 100 milliliters of water. So,5 g of lead nitrate can dissolve in x milliliters of water.= (5 g / 52 g) × 100 mL= 9.6 mLTherefore, 5 g of lead nitrate can dissolve in 9.6 mL of water. However, the question is asking for the number of millimeters of water, not milliliters. Since 1 milliliter of water weighs 1 gram,9.6 milliliters of water will weigh 9.6 grams.Thus, 5 g of lead nitrate can dissolve in 9.6 millimeters of water.
main answer:5 g of lead nitrate can dissolve in 9.6 millimeters of water. :52 grams of lead nitrate can dissolve in 100 milliliters of water. So, 5 g of lead nitrate can dissolve in x milliliters of water.= (5 g / 52 g) × 100 mL= 9.6 mLTherefore, 5 g of lead nitrate can dissolve in 9.6 mL of water. However, the question is asking for the number of millimeters of water, not milliliters. Since 1 milliliter of water weighs 1 gram,9.6 milliliters of water will weigh 9.6 grams.Thus, 5 g of lead nitrate can dissolve in 9.6 millimeters of water.
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An object has a mass of 20 kg and a volume of 5 mL. What is the object's density?
the answer is 4 kg/cm 3. but how do I get to this conclusion?
Answers
Think of a cube that is 1 cm by 1 cm by 1 cm. The volume of this cube is 1*1*1 = 1 cubic cm = cm^3. This is equivalent to 1 mL by definition
So the object's volume of 5 mL is the same as 5 cm^3.
To get the density of an object, we divide the mass over volume
density = (mass)/(volume)
density = (20 kg)/(5 mL)
density = (20 kg)/(5 cm^3)
density = (20/5) (kg/cm^3)
density = 4 kg/cm^3
The density is 4 kilograms per cubic centimeter. In other words, each cubic centimeter of volume has about 4 kilograms of material.
an EM wave has a speed of 3 x 10^8 m/s and a frequency of 5.0 x 10 ^7 Hz. what is the wavelength of the EM wave
0.17m
1.5 x 10 ^ 16m
6.0m
0.06 m
30 POINTS
Answers
Answer:
i think it is 0.06 but im not sure sorry if im wrong
Explanation:
How much kinetic energy does a 2 kg book falling out of the backpack with a velocity of 4 m/s have?
Answers
Answer:
E = 16 J
Explanation:
Given that,
Mass of a book, m = 2 kg
Velocity of the book from the backpack, v = 4 m/s
We need to find the kinetic energy of the book falling out of the backpack. Due to the motion of the object, kinetic energy is possessed by it. It can be given by :
\(E=\dfrac{1}{2}mv^2\\\\=\dfrac{1}{2}\times 2\ kg\times (4\ m/s)^2\\\\=16\ J\)
So, the kinetic energy of the book is 16 J.
which statement best describes the position vs. time and acceleration vs. time graphs for an object that is speeding up and for an object that is not?
Answers
The position vs. time graph is a depiction of the motion of an object with time, while the acceleration vs. time graph is a depiction of how the acceleration of an object changes with time. The position-time graph will show an increasing slope for a moving object and a decreasing slope for a stationary object.
When an object is speeding up, its acceleration increases, and when it is slowing down, its acceleration decreases.The slope of the acceleration-time graph reflects the change in velocity over time. For an object that is speeding up, the acceleration-time graph has a positive slope since the object's speed is increasing, whereas for an object that is slowing down, the slope of the acceleration-time graph is negative, and the object's speed is decreasing. Finally, for an object that is stationary, the acceleration-time graph has a slope of zero since the speed is not changing.
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What is the biggest quad muscle
A. Vastus Intermedius
B. Vastus Lateralis
C. Rectus Femoris
D. Vastus Medialis
Answers
Answer:
b
Explanation:
Answer:
B. Vastus Lateralis
Explanation:
The vastus lateralis muscle is located on the side of the thigh. This muscle is the largest of the quadriceps group.
How hot is 70°c in Fahrenheit?
Answers
In the Fahrenheit scale, 70°C equals 158°F.
The Fahrenheit scale was invented in 1724 by physicist and inventor Daniel Gabriel Fahrenheit as a temperature measurement system. At typical atmospheric pressure, the freezing point of water is 32°F and the boiling point is 212°F on the Fahrenheit scale.
Fahrenheit = (Celsius * 9/5) + 32 is the formula for converting Celsius to Fahrenheit.
So, first multiply 70°C by 9/5 to obtain 126, then add 32 to get 158°F. This indicates that 70°C corresponds to 158°F on the Fahrenheit scale.
This formula is often used in scientific and weather-related applications to convert temperatures. It is a system for determining how hot or cold an object or substance is. Temperature scales are commonly used in three ways: Celsius (°C), Fahrenheit (°F), and Kelvin (K).
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A change in the structure of DNA in the egg cell could result in a
Answers
Answer: A mutation
Explanation: because it changes the DNA sequence of a gene
A boy walks towards a stationary plane mirror at a speed of 12ms^1 what is the relative speed of approach of the boy and his image? (a)zero (b)1.2ms^-1 (c) 2.4ms^-1 (d)1.44ms^-1
Answers
Answer:
a
Explanation:
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Justify why polonium decay is considered a nuclear reaction and not a chemical reaction.
Answers
the energy released is greater than a chemical reaction
nuclear reaction: reaction of the nucleus of the atom
chemical reaction: reaction of the atoms
having students run in place at different speeds to illustrate particle movement in states of matter is an example of
Answers
Having students run in place at different speeds to illustrate particle movement in states of matter is an example of kinetic theory of matter.Kinetic theory of matter is the explanation of how particles in matter behave.
The kinetic theory explains that particles in matter are always in constant motion. The movement of these particles depends on the temperature and phase of matter.Particles in a solid state move slower than particles in a liquid state. Also, particles in a liquid state move slower than particles in a gaseous state. The faster the particles are moving, the higher the temperature.This means that having students run in place at different speeds to illustrate particle movement in states of matter is an example of kinetic theory of matter.
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displacement vector points due east and has a magnitude of 2.00 km. displacement vector points due north and has a magnitude of 3.75 km. displacement vector points due west and has a magnitude of 2.50 km. displacement vector points due south and has a magnitude of 3.00 km. find the magnitude and direction (relative to due west) of the resultant vector
Answers
The magnitude and direction of the resultant vector is 0.9 km and 56.3⁰ respectively.
What is the magnitude and direction of the resultant vector?The magnitude and direction of the resultant vector is calculated as follows;
The resultant vector vertical direction;
Vy = 3.75 km north - 3.0 km south
Vy = 0.75 km due north
The resultant vector horizontal direction;
Vx = 2 km east - 2.5 km west
Vx = 0.5 km west
The magnitude of the resultant vector is calculated as;
V = √ ( 0.75² + 0.5² )
V = 0.9 km
The direction of the vectors is calculated as;
θ = arc tan ( Vy / Vx )
θ = arc tan (0.75 / 0.5 )
θ = 56.3⁰
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20m/s at 275 degrees from the x-axis
Answers
So, the magnitude of velocity concerning:
x-axis approximately 1.74 m/s to the x-positive, andy-axis approximately -19.92 m/s (19.92 m/s to the y-negative).Introduction and Formula UsedHi! Here I will help you to solve problems related to the velocity vector. In this problem, we know that a particle moves at a certain speed with an angle (\( \sf{\theta} \)) on the x-axis. Of course, with conditions like this, velocity can be described on the x or y-axis. The result of the x-axis velocity is horizontal movement. On the other hand, the y-axis velocity is vertical movement. See the equation below to know the magnitude of velocity concerning the x and y-axis.
Velocity respect to the x-axis\( \boxed{\sf{\bold{v_x = v_i \cdot \cos(\theta)}}} \)
Velocity respect to the y-axis\( \boxed{\sf{\bold{v_y = v_i \cdot \sin(\theta)}}} \)
With the following condition:
\( \sf{v_i}\) = the initial velocity\( \sf{\theta}\) = elevation angle\( \sf{v_x}\) = the velocity respect to the x-axis\( \sf{v_y}\) = the velocity respect to the y-axisProblem SolvingWe know that:\( \sf{v_i}\) = the initial velocity = 20 m/s\( \sf{\theta}\) = elevation angle = 225°What was asked?\( \sf{v_x}\) = the velocity respect to the x-axis = ... m/s.\( \sf{v_y}\) = the velocity respect to the y-axis = ... m/s.Step by step:Find the magnitude of velocity respect to the x-axis\( \sf{v_x = v_i \cdot \cos(\theta)} \)
\( \sf{v_x = 20 \cdot \cos(275^{\circ})} \)
\( \sf{\bold{v_x \approx 1.74 \: m/s}} \)
Find the magnitude of velocity respect to the y-axis\( \sf{v_y = v_i \cdot \sin(\theta)} \)
\( \sf{v_y = 20 \cdot \sin(275^{\circ})} \)
\( \sf{\bold{v_y \approx -19.92 \: m/s}} \)
ConclusionSo, the magnitude of velocity concerning:
x-axis approximately 1.74 m/s to the x-positive, andy-axis approximately -19.92 m/s (19.92 m/s to the y-negative)