A coaxial cable consists of a thin insulated straight wire carrying a current of 2.00 A surrounded by a cylindrical conductor carrying a current of 3.50 A in the opposite direction. The cylindrical conductor has a radius of 0.420 cm. What is the magnitude of the magnetic field outside of the cylindrical conductor 2.00 cm from the central wire

The region a represents the distance of the electron from the nucleus.

According to the wave mechanical model of the atom, the probability of finding an electron within a given volume element (representing the atom) is the square of the wave function psi.

Since a is the region in space where there is the greatest probability of finding the electron in the atom, it follows that distance of the electron form the atom is always a.

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Answer:

the same question I want to know

a. Spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:

\(\rm \[ F = \frac{k Q^2}{R^2} \]\), b. The net force on sphere A now is the force due to sphere B, which is: \(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\), c. The magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.

a) The magnitude of the force (F) sphere B exerts on sphere A can be calculated using Coulomb's law:

\(\rm \[ F = \frac{k Q_1 Q_2}{R^2} \]\)

where:

k is Coulomb's constant \(\rm \( k = \frac{1}{4\pi\epsilon_0} \)\) where \(\rm \( \epsilon_0 \)\) is the vacuum permittivity constant),

\(\rm \( Q_1 \)\) and \(\rm \( Q_2 \)\) are the charges on spheres A and B respectively, and

\(\rm \( R \)\) is the distance between the two spheres.

Since both spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:

\(\rm \[ F = \frac{k Q^2}{R^2} \]\)

b) When an identical sphere C makes contact with sphere B, they share the charge equally. Sphere B now carries \(\rm \( \frac{Q}{2} \)\) charge, and sphere C carries \(\rm \( \frac{Q}{2} \)\) charge.

When sphere C is moved far away, it exerts no force on sphere A. So, the net force on sphere A now is the force due to sphere B, which is:

\(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\)

c) When sphere C makes contact with sphere A, they both share the charge equally. Each sphere now carries \(\rm \( \frac{Q}{2} \)\) charge.

When sphere C is moved far away, the net force on sphere A now is the force due to the charge on sphere A itself, which is:

\(\rm \[ F = \frac{k \frac{Q}{2} \cdot \frac{Q}{2}}{R^2} \\\\\rm = \frac{3}{8} \frac{k Q^2}{R^2} \]\)

So, the magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.

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The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.

The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.

The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.

As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.

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Answer: ITS B

Explanation:

BECAUSE I GOT IT WRONG AND IT WAS ACTUALLYT B F IN THE CHAT FOR ME

IF U GIVE ME HEART FOR HELPING THAT WOULD BE GREAT, THANKS......

Answer: The answer is B. Nuclear fission splits an atom apart, while nuclear fusion fuses two atoms together.

Explanation:

Answer:

pp

Explanation:

hahahahhahahhahahahahahaahhahaha..  tbh

Answer: what characterizes moral development in mid to late childhood is

People at this level of moral development base their decisions on what their parents and/or law enforcement says is right. Stage 3 is about social conformity. ... Stage 4 is all about law and order for all. For example, someone may think, 'If I steal, I will break the law and breaking the law is wrong.Feb 17, 2016

Explanation:

The pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

To determine the speed of the pendulum when it passes through the lowest point of its swing, we can use the principle of conservation of mechanical energy.

At the highest point (2.9 cm above the resting position), the pendulum has gravitational potential energy. As it swings down, this potential energy is converted into kinetic energy, given by the equation:

Potential Energy (PE) = Kinetic Energy (KE)

The highest point's potential energy is given by:

PE = mgh

Where:

m = pendulum mass (4.0 kg).

g = acceleration due to gravity (9.8 m/s^2)

h = height above the resting position (2.9 cm = 0.029 m)

Substituting the values, we have:

PE = 4.0 kg * 9.8 m/s^2 * 0.029 m = 1.1356 J

Since energy is conserved, this potential energy will be completely converted into kinetic energy at the lowest point. Thus, the kinetic energy is also 1.1356 J:

KE = 1.1356 J

The following equation gives the kinetic energy:

KE = (1/2)mv^2

Where:

m = pendulum mass (4.0 kg).

v = velocity of the pendulum at the lowest point

Rearranging the equation to solve for v:

v^2 = (2KE) / m

v^2 = (2 * 1.1356 J) / 4.0 kg

v^2 = 0.5678 m^2/s^2

Taking the square root of both sides results in the following:

v ≈ 0.754 m/s

Therefore, the pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

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Answer:

Answer:

on the left of the periodic table

Answer:

in the middle towards the left

Explanation:

just finished the quiz

The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and  475 nm is\(6.31 x 10^14 Hz\)

The equation that links the speed of light to wavelength and frequency is

c = λν

Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.

Calculating the frequency of light with a wavelength of

655 nm:λ = 655 nm = \(6.55 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)

Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).

Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

Añ=10+4(n-1)

Explanation:

The explicit definition which matches the sequence an={10,if n=1an−1−4,if n>1 } is option A that is an = 10 + 4(n – 1) . Where the value of a correct matches with the sequence.

Sequences are a particular set or collection of values that obey a certain criteria where repetition is allowed.The length of the sequence is called its limits. Thus a sequence can have a lower limit and upper limit.

The criteria of function of a sequence are represented in brackets '{}'. Only the values which are included within the limits are there in the set.

Given that the function of sequence is an={10,if n=1an−1−4}. As per this function, if n=1 an= 10 which means a = 10. If n >1 , then the function is an = an-1-4. That is 10n-1-4.

Option A satisfices the first condition where, an = 10 + 4n-4. Thus for n=1 the equation comes equal to 10. Not any other option satisfies this condition and thus option A is correct.

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Answer:

13 g

Explanation:

Gold-198 has a half-life of approximately 3 days. If a 100 g sample of gold-198 decays for 9 days, approximately how much gold-198 remains in the sample?

13 g

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

Answer:1. the object with the greater speed 2. The car is moving faster. 3.a car with a mass of 1,000 kg moving at 30 m/s 4. The wildlife keeper increases speed and catches the rabbit. 5. His kinetic energy increased for a while, then it became constant.

Explanation: i did it

The net force on the book is equal to 1.61 N.

The net force on the object can be defined as the vector sum of all the forces together. Net force becomes resultant force and shows the same effect on the rotational motion as all actual forces.

Given, the angle of the book with the table, α = 35°

The force of friction, f = 11N

The normal force acting on the book, N = 18N

The force of gravity, W = 22 N

The net force along the table is F₁ = Wsinα - f

F₁= 22× sin35° - 11

F₁ = 1.6 N

The net force perpendicular to table is F₂ = W cosα -N

F₂= 22×cos35° -18

F₂ = 0.021 N

The net force on the book is \(F_{net} = \sqrt{F_1^2+F_2^2}\)

\(F_{net} = \sqrt{(1.6)^2+(0.021)^2}\)

\(F_{net} = 1.61N\)

Therefore, the net force on the book is equal to 1.61 Newtons.

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The mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.

Given in the question

The volume of the liquid = Volume of the container

                                  =  120 cm³

Total Mass = 145 grams

Mass of the empty Beaker = 51 grams

To find

Mass of the liquid

The density of the liquid

Now,

Total Mass = Mass of LIquid + Mass of the empty Beaker

Mass of LIquid = Total Mass -  Mass of the empty Beaker  

Put in the value, we get

Mass of liquid = 145 - 51 grams

Mass of liquid = 94 grams

Now, Density is the ratio of the mass of the substance and the volume, the substance occupies in the space. It is not a constant value and is variable with the variation in the temperature of the substance. Its S.I. unit is Kg/m³. B ut its other commonly used unit is gram/cm³.

The density of liquid = Mass of the liquid/ Volume of the liquid

Put in the value, we get

The density of the liquid = 94/120  grams/cm³

The density of the liquid = 0.78 grams/cm³ = 780 Kg/m³

Therefore, the mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.

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Your question was incomplete. Please find the full content below.

A Measuring Cylinder liquid contains a volume of 120cm³ the liquid was then poured into an empty beaker of mass 51g. The total mass was then found to be 145g . Calculate the mass of the liquid and the density of the liquid.

As vₙ<v, no photoelectron is emitted, thus no extraction work is required.

The minimum frequency of incident radiation below which photoelectric emission or electron emission is not feasible is referred to as the threshold frequency.

The frequency of light at which an electron will be forced to leave a metal surface is referred to as the threshold frequency.

The wavelength of incident radiation is λ = 180nm = 1800A = 1800 * 10⁻¹⁰ m.

Therefore, the frequency of incident radiation is

v = c / λ

v = 3 * 10⁸ / 1800 * 10⁻¹⁰

v = 0.166 * 10¹⁶ Hz

Therefore, threshold frequency is

v₀ = c/λₙ

vₙ = 3 * 10⁸ / 275 * 10⁻¹⁰

vₙ = = 1.09 * 10¹⁶ Hz

As vₙ<v, no photoelectron is emitted.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

(8.0÷6.0)×10[(-2)-(-3)]

The compound identified as sugar would be the organic compound, such as sucrose (C12H22O11).The compound identified as salt would be the ionic compound, such as sodium chloride (NaCl).

To determine which compound dissolved more easily and had the lower boiling point, we need more specific information about the compounds being compared. However, assuming we are comparing a typical organic sugar compound, such as sucrose (C12H22O11), with a common ionic salt compound, such as sodium chloride (NaCl), we can draw some conclusions.

The salt compound (NaCl) would generally dissolve more easily than the sugar compound (C12H22O11). This is because salt is composed of ions, which readily dissociate in water due to the polar nature of water molecules. Sugar, on the other hand, is a covalent compound and requires breaking of covalent bonds for dissolution, which is typically a slower process.

The sugar compound (C12H22O11) would generally have a higher boiling point compared to the salt compound (NaCl). Covalent compounds tend to have higher boiling points than ionic compounds due to the stronger intermolecular forces between covalent molecules.

No, the answers to 1 and 2 do not refer to the same compound. The strength of the bonds in the sugar compound (covalent) is different from the strength of the bonds in the salt compound (ionic).

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The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.

The initial volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:

V = π(0.5 cm)²(40 cm)

V = 31.4 cm³

The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:

β = ΔV/(VΔT)

where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:

ΔV = βVΔT

We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:

ΔV = π(0.5 cm)²(40 cm - 37 cm)

ΔV = 0.59 cm³

Plugging in all the values, we get:

0.59 cm³ = β(31.4 cm³)(-10°C)

β = 0.002

To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:

ΔT = ΔV/(βV)

We know that ΔV is the difference between the initial volume and the volume at the new height, which is:

ΔV = π(0.5 cm)²(49 cm - 40 cm)

ΔV = 6.86 cm³

Plugging in all the values, we get:

ΔT = 6.86 cm³/(0.002)(31.4 cm³)

ΔT = 109.5°C

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Answer:

1) m = 0.3137 kg

2a)T_f = -181.7°C

2b) T_f = -1176.97°C

Explanation:

1) We are given;

Length; l = 4.30 cm = 0.043 m

Width; w = 14.0 cm = 0.014 m

height; h = 27.0 cm = 0.027 m

density of gold; ρ = 19.3 × 10³ kg/m³

Formula for the density is known as;

ρ = mass/volume

Thus;

m =ρV

m = 19.3 × 10³ × (lwh)

m = 19.3 × 10³ × (0.043 × 0.014 × 0.027)

m = 0.3137 kg

2a) We are given;

Diameter of brass; L_br = 10 cm

Diameter of aluminum; L_al = 10.01 cm

Now, to some for change in temperature we will use the formula;

L_f = L_i + αL_i(Δt)

Where α is coefficient of expansion.

Now, for the ring to be removed from the rod, the final diameter of the brass has to be same as the aluminium.

Thus;

L_f(brass) = L_f(aluminium)

From table attached, α_brass ≈ 19 × 10^(-6) /°C

Also, α_aluminium ≈ 24 × 10^(-6) /°C

Thus;

L_f(brass) = 10 + (19 × 10^(-6) × 10 × (Δt))

Similarly,

L_f(aluminium) = 10.01 + (24 × 10^(-6) × 10.01 × (Δt))

Since L_f(brass) = L_f(aluminium), then;

10 + (19 × 10^(-6) × 10 × (Δt)) = 10.01 + (24 × 10^(-6) × 10.01 × (Δt))

Rearranging, we have;

10.01 - 10 = (19 × 10^(-6) × 10 × (Δt)) - (24 × 10^(-6) × 10.01 × (Δt))

0.01 = Δt(-50.24 × 10^(-6))

Δt = 0.01/(-50.24 × 10^(-6))

Δt ≈ -199°C

Thus, temperature at which the combination must be cooled to separate the two metals is;

T_f = T_i + Δt

T_f = 17.3 + (-199)

T_f = -181.7°C

2b) Diameter of aluminum is now;

L_al = 10.06 cm

Thus;

10.06 - 10 = (19 × 10^(-6) × 10 × (Δt)) - (24 × 10^(-6) × 10.01 × (Δt))

0.06 = Δt(-50.24 × 10^(-6))

Δt = 0.06/(-50.24 × 10^(-6))

Δt = -1194.27°C

T_f = 17.3 + (-1194.27)

T_f = -1176.97°C

The direction of the given vector B of 18.6 m that is 80° left of the positive y-axis is 170°

Angle of the vector made with positive y-axis = 80°

Angle between positive x and y axis = 90°

Direction of B, θ = 90° + 80°

θ = 170°

Direction of a vector is the angle of the vector that is made with positive x-axis. A vector with a certain direction of certain degrees means that the vector is rotated that much degrees in counter-clockwise direction relative to positive x-axis.

Therefore, the direction of the vector B is 170°

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Answer:

Based on the information provided, the lightbulb lights when the loop rotates because the movement of the wire in an electric or magnetic field causes electrons in the wire to move and become either mechanical energy or an electric current. This energy causes the light to glow. The energy change involved is the conversion of electrical or mechanical energy used to rotate the loop into either light or electrical energy

Explanation:

Answer:

The energy that is changing during a phase change is potential energy. During a phase change, the heat added (PE increases) or released (PE decreases) will allow the molecules to move apart or come together. Heat absorbed causes the molecules to move farther apart by overcoming the intermolecular forces of attraction.

Answer:

Speed = 328 m/s

Explanation:

Given the following data:

Wavelength = 4 m

Frequency = 82 Hz

To find the speed of the radio wave;

Speed = wavelength * frequency

Speed = 4 * 82

Speed = 328 m/s

Therefore, the radio wave is travelling at 328 meters per seconds.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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