A common drinking glass is 7 cm in diameter and fi lled to a depth of 12 cm with water. Calculate the pressure difference between the top and bottom of the glass sides.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

If the voltage of the power supply is increased by a factor of 3 and the resistance was held constant, the new current will be 0.008 A or 8 mA

Power is the rate at which work is done. Electrical power is measured in Watt.

Given that a circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA Determine the new current if the voltage of the power supply was increased by a factor of 3 and the resistance was held constant

Let the

From the power formula, power will always be constant. That is, initial power will be the same with new power

Since P = IV

24/1000 V = I × 3V

0.024V = 3IV

V cancels out

3I = 0.024

I = 0.024/3

I = 0.008 A

Therefore, the new current will be 0.008 A.

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Answer:

doubled

Explanation:

When thrust is double so will the pressure I hope this helps

enjoy

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

Wheres the table?

Explanation:

The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.

The percent uncertainty in measuring the light weight object is calculated as follows;

\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)

The uncertainty of the heavy object if the scale remains constant is calculated as follows;

\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)

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The equivalent resistance between points A and B is 0.837Ω.

Resistors in series are connected end-to-end so that the current flows through them in sequence. The equivalent resistance of resistors in series is the sum of their individual resistances.

The formula for equivalent resistance of resistors in series: R_eq = R_1 + R_2 + ... + R_n

Resistors in parallel are connected across each other so that the voltage is the same across each resistor. The equivalent resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of their individual resistances.

The formula for equivalent resistance of resistors in parallel: 1/R_eq = 1/R_1 + 1/R_2 + ... + 1/R_n

Here in the Fig.

we can simplify the second set of resistors in parallel (4.8 Ω, 3.3 Ω, and 8.1 Ω) using the same formula:

1/Req1 = 1/4.8 + 1/3.3 + 1/8.1

Req1=1.575Ω

This Req1 connected series with 6.3Ω, then Req of this two resistance given by:

Req2= 1.575Ω+ 6.3Ω

Req2=7.875Ω

Once again this req2 makes the parallel with the other two resistance i. e 1.5Ω and 2.5Ω

Their equivalent resistance  is given by,

1/Req3=1/1.5 + 1/2.5 + 1/7.875

Req3=0.837Ω

Hence, The equivalent resistance between points A and B is 0.837Ω

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Answer:

30m/s

Explanation:

Ya that's the right answer.

Answer:

Explanation:

I will ASSUME that the struck car was initially at rest. Would not have to be, but a different mass will result if it was

Conservation of momentum

14000(8.1) + m(0) = (14000 + m)(3.6)

14000(8.1) = 14000(3.6) + m(3.6)

m = 14000(8.1 - 3.6) / 3.6

m = 17500 kg

The mass of the second car is 17500 kg.

The law of conservation of momentum asserts that, unless an external force is applied, the total momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

Newton's third law of motion has a direct impact on the idea of momentum conservation.

mass of the first car = 14000 kg.

Initial speed of first car = 8.1 m/s.

Final speed of the two cars = 3.6 m/s.

From law of conservation of momentum; we can write:

Total initial momentum = total final momentum

14000 kg ×8.1 m/s + m×0 = (14000 + m) kg × (3.6 m/s)

14000(8.1) = 14000(3.6) + m(3.6)

m = 14000(8.1 - 3.6) / 3.6

m = 17500 kg

Hence, the mass of the second car is 17500 kg.

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Answer:

When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.

Explanation:

Hope it helped =)

The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m

According to the question;

The cannonball is fired straight up at a speed of 25 m/s

Additionally, the cannonball is fired against the force of gravity.

Consequently, the motion is in the opposite direction of the acceleration due to gravity.

From the equation of motion;

At the maximum altitude, V = 0.

The maximum altitude that it will reach is;

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Answer:

Explanation:

Since the front and back of the rocket simultaneously line up with forward and backward end of the platform respectively .

Then length of the platform = length of the train rocket .

A )

Time to cross a particular point on the platform

= length of rocket train / .96 x 3 x 10⁸

= 90 /  .96 x 3 x 10⁸

= 31.25 x 10⁻⁸ s

B)  Rest length of the rocket = length of platform = 90 m

C ) length of platform  as viewed by moving observer =

\(\frac{90}{\sqrt{1-\frac{v^2}{c^2 } } }\)

= \(\frac{90}{\sqrt{1-\frac{0.92}{1 } } }\)

= 321 m

D )  For the observer on platform time taken = 31.25 x 10⁻⁸ s

for the observer in the rocket , time will be dilated so time recorded by observer in motion ,

\(31.25\times10^{-8} \times \sqrt{1-\frac{.96^2}{1} }\)

8.75 x 10⁻⁸ s .

Here b option is correct because the frequency affe

To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:

Lenses:

Place an object at different distances to the left of a lens with a focal length (f).

a) Object placed beyond 2f:

In this case, the object is placed far beyond twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.

SALTS:

Size: The image will be smaller than the object.

Attitude: The image will be inverted.

Location: The image will be located between the focal point and twice the focal length.

Type: The image will be real.

b) Object placed at 2f:

In this case, the object is placed at twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens at twice the focal length.

SALTS:

Size: The image will be the same size as the object.

Attitude: The image will be inverted.

Location: The image will be located at twice the focal length.

Type: The image will be real.

c) Object placed between f and 2f:

In this case, the object is placed between the focal point and twice the focal length of the lens.

In this case, the object is placed far beyond twice the focal length of the mirror.

Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.

Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.

Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.

The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.

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Answer: D

Explanation:

Answer:

λ = c / f     or    f = c / λ

f = 3.0E8 / 4.0E-7 = .75E15 / sec = 7.5E14 / sec = 7.5 X 10^14 /sec

Answer:

The target was higher than the cannon

Explanation:

Given that a cannon ball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s.

The initial velocity must be 56 m/s, while the final velocity will be 35 m/s.

When an object is thrown upward with an initial velocity, the object continues to move upwards with decreasing in magnitude of velocity till it reaches the maximum height where the final velocity will be equal to zero.

In this question, since the final velocity is less than the initial velocity, we can conclude that the target is higher.

Therefore, the target was higher than the cannon.

It's important to know that a comet has a tale, a nucleus, and a coma.

The nucleus refers to the center of the "head" of the comet.

Hence, the answer is Nucleus.

a.

The heat the engine extracts from its heat source in each cycle is 3.79 × 10⁴ J

The efficiency of the Carnot engine, ε = W/Q where W = work done per cycle = 2.5 × 10⁴ J and Q = heat extracted in each cycle.

Making Q subject of the formula, we have

Q = W/ε

Since ε = 66% = 0.66, we substitute the values of the variables into the equation for Q.

So, Q = W/ε

Q = 2.5 × 10⁴ J/0.66

Q = 3.79 × 10⁴ J

So, the heat the engine extracts from its heat source in each cycle is 3.79 × 10⁴ J

b.

The temperature of its heat source is 588.76 °C

Also, the efficiency of the Carnot engine, ε = 1 - T/T' where T = temperature of exhaust heat = 20° C = 273 + 20 = 293 K and T' = temperature of heat source.

Making T' subject of the formula, we have

T' = T/(1 - ε)

Since ε = 66 % = 0.66

Substituting the values of the variables into the equation, we have

T' = T/(1 - ε)

T' = 293 K/(1 - 0.66)

T = 293 K/0.34

T = 861.76 K

We convert this to Celsius.

T(K) = T(°C) + 273

T(°C) = T(K) - 273

T(°C) = 861.76 - 273

T(°C) = 588.76 °C

So, the temperature of its heat source is 588.76 °C

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Answer:

magnitude and direction of a plane's speed. There is a wind of 35 MPH in the direction of 260 if it is flying with .

Answer:

Explanation:

Since the speed of the aircraft and the wind speed are directed in the same direction, the actual speed of the aircraft:

V = 340 + 40 = 380 km/h

The wavelength of this wave is the distance between two consecutive points in the curve.

Wavelength is the distance between two successive peaks or troughs in a wave. It is the physical quantity that is used to measure the frequency of a wave. Wavelength can be used to measure a variety of waveforms, including electromagnetic waves, such as light and radio waves, sound waves, and even gravitational waves. Wavelengths are typically measured in meters or centimeters. The shorter the wavelength, the higher the frequency of the wave.

a) Wavelength: The wavelength of this wave is the distance between two consecutive points in the curve. In this case, the distance between points A and B is approximately 10 cm. Therefore, the wavelength is 10 cm.

b) Speed: The speed of this wave is equal to the product of its wavelength and frequency. The frequency of this wave can be calculated by dividing the time between the two snapshots (10 ms) by the distance between two points (10 cm). This gives a frequency of 0.1 Hz. Therefore, the speed of this wave is equal to its wavelength times its frequency, or 1 cm/s.

c) Frequency: As calculated above, the frequency of this wave is 0.1 Hz.

d) Amplitude: The amplitude of this wave is the difference in height between its maximum and minimum values. In this case, the maximum value is at point B (3 cm) and the minimum value is at point A (2 cm). Therefore, the amplitude of this wave is 1 cm.

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The spontaneous drying of leaves occurs due to the loss of moisture through evaporation, primarily facilitated by transpiration and environmental factors such as temperature, humidity, and airflow. Aging and senescence also contribute to the process.

The spontaneous process of drying leaves, also known as desiccation, is a natural occurrence that takes place as a result of various factors. Primarily, it involves the loss of moisture from the leaf tissues through evaporation. Leaves have specialized structures called stomata, small openings on their surfaces, which facilitate the exchange of gases, including water vapor.

When environmental conditions such as high temperature, low humidity, and increased airflow prevail, water molecules escape through the stomata into the surrounding air. This process, called transpiration, plays a significant role in leaf drying. Additionally, sunlight accelerates the rate of evaporation by providing energy to convert water into vapor.

As moisture content decreases, the cell walls of the leaf tissues contract, causing the leaf to become dehydrated and eventually dry. The process is also influenced by the plant's natural aging and senescence, where the leaf undergoes programmed cell death.

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The rubber band travels horizontally 7.0 cm in second time.

Given parameters:

the rubber band is stretched = 2.0 cm.

And, the rubber band travels = 3.5 cm.

Secondly,  the rubber band is stretched = 4.0 cm.

As force is directly proportional with stretching and landing at a horizontal distance,  it travels horizontally in second time

= 4.0 cm x 3.5 cm/ 2.0 cm.

= 7.0 cm.

The vertical movement can't be measured as a new gravitational force comes in play in this case.

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Answer: a) 2,508

Explanation:

Answer:

c

velocity gradient is dimensionally represented as [M^0 L^0 T^-1)

An elastic spring extends by 0.1 m due to the action of a force of 15 N. The elasticity constant of that spring will be 150 Newton/ meters.

Elastic constants are the constants which are used to determine the deformation which is produced by a given stress system acting on the material. There are many types of elastic constants such as Bulk modulus (K). The expression for Bulk modulus for elasticity.

F = kx

where, F is the force applied,

k is Elasticity constant,

x is the extension of the spring

k = F/ x

k = 15/ 0.1

k = 150

Therefore, the elasticity constant of the spring will be 150 Newton/ meters.

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Answer: 10.98 N

Explanation:

Given

mass of box is \(m=0.5\ slugs\approx 7.3\ kg\)

The coefficient of kinetic friction is \(\mu= 0.4\)

It is given that on the application of force box started moving with constant speed i.e. there is no net external force

\(\Rightarrow F+mg\sin 30^{\circ}=\mu mg\cos 30^{\circ}\\\Rightarrow F=mg(\mu \cos 30^{\circ}-\sin 30^{\circ})\\\Rightarrow F=7.3\times 9.8(0.866\times0 .4-0.5)=-10.98\ N\\\)

The negative sign indicates direction of force is opposite i.e. it must be applied upwards

Answer:

Geology is the study of the Earth that involves the process at Earth, materials of which it is made, and its history.

Geologists combine both laboratory and field data to illustrate the results of their research. Some observations that can the geologist make by working outdoors instead of in a lab are as follows:

To find the distance that the Earth travels in three days in its path around the sun, we first need to find the circumference of the Earth's orbit. We can use the formula for the circumference of a circle, C = 2πr, where C is the circumference, π is approximately equal to 3.14, and r is the radius of the circle (93 million miles).

C = 2πr = 2 * 3.14 * 93 million miles = 584 million miles

Now that we know the circumference of the Earth's orbit, we can find the distance the Earth travels in three days by multiplying the circumference by the proportion of the orbit that the Earth travels in three days.

Three days is 3/365 of a year, so we can use the following formula:

Distance = (3/365) * C = (3/365) * 584 million miles = 40,931 miles

Therefore, the distance that the Earth travels in three days in its path around the sun is approximately 40,931 miles

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