The electric potential at the center of the conducting sphere is (kQ/R), where k is the Coulomb's constant. This can be derived using the formula for electric potential due to a point charge and superposition principle for electric potential.
The conducting sphere with a total charge Q will have an electric potential due to its own charge distribution. This electric potential can be calculated at any point outside or inside the sphere.
At any point outside the sphere, the electric potential is given by V = kQ/r, where r is the distance from the center of the sphere to the point outside. As r approaches infinity, the electric potential becomes zero, which is given in the question.
Now, at the center of the sphere, the electric potential due to the sphere's own charge distribution will be the sum of electric potential due to all charges on the sphere. By the symmetry of the sphere, we can assume that the electric potential at the center is the same as the electric potential due to a point charge at the center.
The electric potential due to a point charge q at a distance r from it is given by V = kq/r. For the conducting sphere, we can consider the entire charge Q to be concentrated at the center of the sphere, which is the same as a point charge Q at the center.
Thus, the electric potential at the center of the sphere is V = kQ/R.
The electric potential at the center of a conducting sphere with a total charge Q and radius R is given by (kQ/R), where k is the Coulomb's constant. This is derived using the formula for electric potential due to a point charge and superposition principle for electric potential.
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please help ill give you 100 points
Answer:
\(ke = \frac{1}{2} mv {}^{2} \)
which term describes a lens with a surface that curves outward like the exterior of a sphere?
Answer:
Convex lens
hope that helps you
1) Sketch a walking model and a running model. List four events that occur in a walking cycle of one leg, and four events that occur in a running cycle of one leg. (5 pts) 2) Write the governing equation of ground reaction force based on 2nd Newtonian Law. Write the governing equations of forward kinetic energy and gravitational potential energy during walking. (5pts)
Walking and running are distinct forms of locomotion characterized by different movement patterns and energy dynamics. During walking, the forward kinetic energy is governed by the equation 1/2 mv^2.
In walking, the cyclic movement of one leg consists of four events. Firstly, during heel strike, the heel of the foot makes initial contact with the ground. Secondly, the foot continues to roll forward until it reaches foot flat, where the entire foot is in contact with the ground. Thirdly, at midstance, the leg is directly under the body, and the body's weight is supported by that leg. Finally, during toe-off, the heel lifts off the ground, and the leg propels forward for the next step.
In running, the cycle of one leg is more dynamic. It begins with initial contact, where the foot strikes the ground, usually with the midfoot or forefoot. This is followed by the loading response, during which the leg and foot absorb and distribute the forces generated by impact. Next is the midstance phase, where the body's weight is primarily supported by the stance leg. Finally, during propulsion, the leg pushes off the ground, generating forward momentum for the next stride.
The governing equation for ground reaction force is derived from Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). In the context of locomotion, the ground reaction force represents the force exerted by the ground on the leg or foot. This force is equal in magnitude but opposite in direction to the force exerted by the leg or foot on the ground.
During walking, the forward kinetic energy is determined by the equation 1/2 \(mv^2\) , where m represents the mass of the moving object (e.g., leg) and v denotes its velocity. This equation describes the energy associated with the leg's forward motion. Gravitational potential energy during walking is governed by the equation mgh, where m is the mass of the object, g is the acceleration due to gravity, and h represents the height of the center of mass of the leg above a reference point, such as the ground. This equation describes the energy associated with the leg's position relative to the ground and the Earth's gravitational field.
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This passage describes an example of cultural diffusion through
A country has recently made high-speed Internet available
to its citizens. As a result, people are able to connect with
others around the world. Some people are using social
networks to make friends in other countries. Others are
learning about how other countries deal with social issues
like discrimination.
A. migration
B. trade
C. communication
оо
D. war
Answer:
C is the correct answer
Explanation:
I got it right on my test
Answer:
Communication
Explanation:
See how the people are using the internet
They are socially connectedThey are connected with other countries affairsThey are communicating among themselves in society and furtherSo option C is correct
A block of mass 4m can move witheut friction on a horizontal table. This block is attached to another block of mass m by a string thet passes over a frictionless pulley. If the masses of the string and the pulley are negligible, what is the magnitude of the acceleration of the descending block? A. g/5 B. g/4 C. g/3 D. 2g/3 E. g
To find the magnitude of the acceleration of the descending block, we can analyze the forces acting on the system.
Since there is no friction, the tension in the string is the same on both sides of the pulley. Let's consider the forces acting on each block individually:
For the block of mass 4m:
Weight (mg) acts downward.
Tension in the string (T) acts upward.
For the block of mass m:
Weight (mg) acts downward.
Tension in the string (T) acts upward.
The net force acting on each block is equal to the mass times the acceleration (F = ma). Since the blocks are connected by a string, they have the same acceleration.
For the block of mass 4m:
mg - T = (4m)a ---(1)
For the block of mass m:
T - mg = (m)a ---(2)
Adding equations (1) and (2), we eliminate the tension T:
mg - T + T - mg = (4m)a + (m)a
0 = (5m)a
Since the net force on the system is zero, the acceleration is zero.
Therefore, the magnitude of the acceleration of the descending block is zero. Option E (g) is the correct answer.
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Wolves, which are top predators, were eliminated from Yellowstone National Park in the 1930s. In 1995, wolves were reintroduced into Yellowstone. During the period in which wolves were absent from Yellowstone, which MOST likely occurred?
A. an increase in competition for food resources among small prey
B. a greater opportunity for primary producers to flourish
C. an increase in the population of tertiary consumers
D. a greater balance of predator-prey relationships
Answer:
The answer is E
Explanation:
Wolves died off from the rona virus back in the 1930s so when they came back they brought C- 19 with them
HELLPP I WILL GIVE BRAINLY
the heat generated by burning coals is an example of what type of energy conversion ?
A ) Chemical ----> mechanical
B ) Radiant ----> mechanical
C ) chemical----> thermal
D ) Mechanical ---> Chemical
Answer:
The energy conversion is:
C) Chemical - - - - > Thermal.
20 points
A net force of 24 N is applied to an object for 5.0 s. The object is pushed a total of 5.2 m. What is the mass of the object? What equations will be used?
Answer:
S = V0 t + 1/2 a t^2 net distance traveled
5.2 = a/2 * 25
a = 10.4 / 25 = ,416 m / s^2
F = m * a
m = F / a = 24 / .416 = 57.7 N
Please answer!
Ocean waves are hitting the seashore at a rate of 15 Hz. The distance between two successive crests is 3 m. Calculate the speed of the ocean waves. (note: crest/s = 1 Hz)
\( \sf \nu \: = \lambda \times \upsilon\)
λ = Wavelength [Given = 3 m]υ = Frequency [Given = 15 Hz]ν = Speed [To find]\( \sf \nu = 3 \times 15\)
\( \sf \nu \: = 45 \: m/s\)
➪The speed of ocean waves is 45 m/s...~
how does the wind reversing make the tempurature change asap pls
Answer:
Because the difference in air temperature of neighbouring air masses causes the wind to blow. Warmer air is less dense, so colder air subsides into the space occupied by the warmer air due to the force of gravity, displacing the warmer air upwards. This is fundamentally the reason temperature change may be accompanied by wind. It is possible to think of situations where only one of these effects is observed at any one place, due to the large size or stationary nature of atmospheric boundary phenomena.
Explanation:
Answer: The temperature of the air does not change the heat loss from the skin changes. Wind helps remove the warm air next to the skin and makes it feel colder.
Explanation:
11. In the original Ghostbusters, when asked by Dr. Peter Venkman what would happen if they crossed the streams from their proton packs, Dr. Egon Spengler responded, "It would be bad." The same thing could reasonably be said about _________ Specifically, the reason for this is due to violation of the assumption of _____________
The same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.
Let us understand what these terms mean:
MulticollinearityIn statistical analysis, multicollinearity is the high correlation among predictors in a regression model. It is problematic because of its adverse effects on the model, including making it difficult to determine the effect of an independent variable, coefficients becoming insensitive to small changes in the model, and reducing the reliability of the model.
Independent PredictorsIn regression analysis, independent predictors are those variables that contribute to the prediction of the dependent variable or outcome, and their inclusion in the model improves the accuracy of the prediction of the model.
In a regression model, it is an assumption that predictors are independent, which means that the predictors have little to no correlation with each other. If this assumption is violated, it is known as multicollinearity.
Therefore, the same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.
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Deserts are only found near the equator.
Answer:
False
Explanation:
Texas is and astralia exsist.
If he leaves the ramp with a speed of 37.5 m/s and has a speed of 35.8 m/s at the top of his trajectory, determine his maximum height (h) (in m) above the end of the ramp. Ignore friction and air resistance.
When a ball or any other object is thrown into the air, it reaches a maximum height and then falls back to the ground. The maximum height attained by the object is known as the maximum height.
To determine the maximum height of an object thrown into the air, you must first calculate the initial velocity and the final velocity. The first step in solving this problem is to determine the object's initial velocity, which is given as 37.5 m/s. The second step is to determine the final velocity, which is given as 35.8 m/s.
Since the object's speed decreases as it rises to its maximum height, the final velocity will always be less than the initial velocity.Finally, you must calculate the object's maximum height by using the conservation of energy principle.
Since no friction or air resistance is present, the initial energy of the object is equal to its maximum potential energy plus its kinetic energy at its highest point.
The conservation of energy formula is:mgh = 1/2mv² - 1/2mv²wherem = mass of the objectv = velocity of the object at the top of its trajectoryh = maximum heightg = acceleration due to gravityTo calculate the maximum height of the object, you must first solve for mgh.
This equation represents the potential energy of the object at its maximum height. Then, you can substitute the values of m, v, and g into the equation and solve for h. After that, you should get the answer in meters.
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What would the products of a double-replacement reaction between Na2S
and MgF2 be?
A. NaF and MgS
B. MgF and Nas
C. F2S and MgNa2
D. MgF2 and Nas
Answer:
A. NaF and MgS
Explanation:
The reaction equation is given as:
Na₂S + MgF₂ → 2NaF + MgS
The product of this reaction is NaF and MgS.
In a double displacement reaction there is an actual exchange of partners to form new compounds. This reaction takes place between ionic compounds.
The driving force for the reaction is:
formation of an insoluble precipitateformation of water or any other non-ionizing compound liberation of a gaseous product.1. During the experiment with the hot metal block in cold water, in which direction did the thermal energy flow? By what method did the energy
flow?
1
When there is a temperature difference/Gradient, heat flows from a region of high concentration to region of low concentration.
Energy and Heat/Mass TransferThermal energy flow from region of higher temperature gradient to region of low temperature gradient till equilibrium is reached.
When the hot metal is places in a cold water bath, there will be a temperature difference and by conduction(water conducts heat) the heat will travel in the water medium and circulate till equilibrium
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arrange 6.002, 6.023, 6.302, 6.020 from least to greatest
WILL MARK BRAINLIEST
Answer:
6.002
6.020
6.023
6.302
Explanation:
Please help. Will give Brainlist.
Answer:
No and yes it's like a 30%or 20%
Explanation:
"researchers say that there is no proof that dimples are inherited."
meaning that if the mom or dad had dimples it might have a chance or no since a dominant trait not a recessive trait
Can anyone help me please ..I need it hurry within 6 hrs.please.
Brainliest for the first best answer.
(i) Switch k1 is closed:
The current passing through the circuit is: 0.25 amps
R_total = R1 + R2 = 3 + 5 = 8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / 8 = 0.25 amps
(ii) Switches k1 and k2 are closed:
The current passing through the circuit is: 1.07 amps
1/R_total = 1/R1 + 1/(R2 + R3) = 1/3 + 1/(5 + 0) = 8/15
R_total = 15/8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / (15/8) = 1.07 amps
(iii) Switch k1 is open and k2 is closed:
The current passing through the circuit is: 1.07 amps
1/R_total = 1/R2 + 1/(R1 + R3) = 1/5 + 1/(3 + 0) = 1/5 + 1/3 = 8/15
R_total = 15/8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / (15/8) = 1.07 amps
So the current passing through the circuit depends on which switches are closed, and can range from 0.25 amps to 1.07 amps.
What is current?
Crrent refers to the flow of electric charge through a conductor, such as a wire. It is measured in amperes (A) and is defined as the rate at which electric charge flows past a given point in a circuit. current is caused by the movement of charged particles, such as electrons or ions, through a conductor.
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Which statement illustrates how engineering has influenced society?
A. Digital cameras require far less time to generate images than film cameras
do.
B. Digital cameras allow people to take more pictures and share them more
widely than film cameras did.
C. People want the cameras in their cell phones to be able to capture high-
resolution images
D. People expect that advances in imaging technology will keep up with their
needs for sharing pictures.
The statement illustrates how engineering has influenced society in that People want the cameras in their cell phones to be able to capture high-resolution images. Option C is corect.
What is a digital camera?A digital camera that creates pictures that can be saved on a computer and seen on a screen.
People want their mobile phone cameras to be able to take high-resolution pictures, which shows how engineering has affected society.
Statement B illustrates how engineering has influenced society.
Hence option C is correct.
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write the law of friction???
Answer:
The friction of the moving object is proportional and perpendicular to the normal force
The friction of the moving object is proportional and perpendicular to the normal force. The friction experienced by the object is dependent on the nature of the surface it is in contact with. Friction is independent of the area of contact as long as there is an area of contact.
prepare a pro d. How does the use of prefixes make each expression and conversion of measurement easier? Write with examples.
The use of prefixes makes expressing and converting measurements easier by providing a consistent way to describe quantities and their units. For example, the prefix "kilo-" means 1000, so one kilometer is equal to 1000 meters.
Proper use of prefixes in measurements is essential for converting units from one system to another, or even within the same system. It can help avoid errors and confusion and simplify calculations.
The use of prefixes makes expressing and converting measurements easier by providing a consistent way to describe quantities and their units. A prefix is a group of letters placed before a unit symbol to change its value by a factor of 10.
For example, the prefix "kilo-" means 1000, so one kilometer is equal to 1000 meters. The prefix "centi-" means one-hundredth, so one centimeter is equal to one-hundredth of a meter. The prefix "milli-" means one-thousandth, so one milliliter is equal to one-thousandth of a liter.
Using prefixes can also simplify calculations involving measurements. For instance, if we need to convert 1000 millimeters to meters, we can divide by 1000 since milli- means one-thousandth, resulting in 1 meter. Similarly, if we need to convert 2 kilometers to centimeters, we can multiply by 100,000 since kilo- means 1000, resulting in 200,000 centimeters.
Furthermore, prefixes are also used in scientific notation to express very large or very small numbers. For instance, the speed of light is approximately \(3 * 10^8\) meters per second, which can be written as 300,000,000 m/s.
In conclusion, using prefixes in measurements can make it easier to express, convert, and understand quantities and their units. They provide a consistent way to change the value of a unit by a factor of 10 and are essential in scientific calculations and measurements.
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Light waves require a medium to travel. *
True
False
Calculate the distance and azimuth between point A and point B
Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"W
Point B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W
Note: Azimuth in clockwise
Compute for the spherical triangle Point A-North Pole-Point B
The forward azimuth from point A to point B is approximately 151.3421° (clockwise).
The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.
Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.
Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.
Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.
Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.
The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.
Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.
where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.
Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).
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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).
The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.
Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.
Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.
Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.
Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.
The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.
Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.
where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.
Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).
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If the work done when a charge of 5.2 × 10-13 coulombs is moved between two points is 4.7 × 10-12 joules, what is the potential difference?
A.
4.7 volts
B.
5.2 volts
C.
9.0 volts
D.
10 volts
E.
12 volts
Answer:
9.0, might be to late but someone in the future might need it.
Answer:
C. 9.0
Explanation:
I like boys
Two football players are attempting to tackle each other. If one football player has a mass of 100 kg and pushes with a force of 100N onto another football player whose mass is 80kg, how much force does the other player push back with?
Answer:
is it 20kg. Two opposing forces pushing onto each other
A collision is elastic only when kinetic energy and momentum are conserved through the collision. Group of answer choices True False
Answer:
Both momentum and kinetic energy are conserved quantities in elastic collisions.
Explanation:
An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.
which relationship benefits two organisms
Answer:
mutualism
Explanation:
Mutualism, a relationship in which both species benefit, is common in nature. In microbiology, there are many examples of mutualistic bacteria in the gut that aid digestion in both humans and animals.
A point on the edge of a disk rotates around the center of the disk with an initial angular velocity of 3rad/s clockwise. The graph shows the point's angular acceleration as a function of time. The positive direction is considered to be counterclockwise. All frictional forces are considered to be negligible.
What is the angular displacement of the point after 10s?
The angular displacement of the point after 10 seconds will be 270 radians
We have been given a point that rotates with an angular velocity of 3rad/s
In the Graph value of the angular acceleration is 6 rad/\(s^{2}\) which is constant
Since counterclockwise direction is to be considered as positive, so the angular velocity will be negative since the point is rotating in the clockwise direction
Initial displacement we will take as 0
We will use the angular kinematic equation to solve this problem and the second equation will be used
\(V_{0}\)=\(U_{0}\)+\(w_{0}\)t+\(\frac{1}{2}\)αt², \(U_{0}\)=Initial displacement, \(w_{0}\)=initial angular velocity, a= acceleration
\(V_{0}\) = 0 + (-3)10 + \(\frac{1}{2}\)×6×10²
\(V_{0}\)= 270 rad/s
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A 2.24x10^3 kg car slows down uniformly from 20.0 m/s to a stop (assume constant acceleration) via a braking force of 8.41x10^3 N . How far did the car travel during this time?
Answer:
Explanation: 139 m
1. Two 500 g point masses are rotating on a light frame at a radius of 0.1 m from a vertical axis. The angular speed of the system is 20 rad s-1. a a) What is the moment of inertia of the system about the axis? b) What is the angular momentum of the system about the axis? c) If the masses were pulled into a radius of 0.05 m by an internal radial force, what would the angular momentum of the system now be? d) What is the new angular speed of each mass? e) By how much did the energy of the masses change?
(a) The moment of inertia of the system about the axis can be calculated using the formula for the moment of inertia of a point mass rotating about an axis.
(b) The angular momentum of the system about the axis can be determined by multiplying the moment of inertia by the angular speed.
(c) If the masses are pulled into a smaller radius, the moment of inertia will change, resulting in a new angular momentum for the system.
(d) The new angular speed of each mass can be calculated using the principle of conservation of angular momentum.
(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system.
(a) To calculate the moment of inertia of the system about the axis, we consider the two point masses rotating at a given radius. The moment of inertia for each point mass is given by the formula I = m * r², where m is the mass and r is the radius.
Since there are two masses, we can calculate the total moment of inertia by summing the individual moments of inertia.
(b) The angular momentum of the system is determined by multiplying the moment of inertia by the angular speed. Using the formula L = I * ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular speed, we can find the angular momentum of the system.
(c) If the masses are pulled into a smaller radius, the moment of inertia will change. We can calculate the new moment of inertia using the same formula as in (a) but with the new radius. With the new moment of inertia, we can determine the new angular momentum of the system.
(d) To find the new angular speed of each mass, we apply the principle of conservation of angular momentum. The initial angular momentum of the system is equal to the final angular momentum. By rearranging the equation L = I * ω and solving for ω, we can calculate the new angular speed.
(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system. The initial kinetic energy is given by (1/2) * I * ω², where I is the initial moment of inertia and ω is the initial angular speed.
Similarly, the final kinetic energy can be calculated using the new moment of inertia and angular speed. The difference between the initial and final kinetic energies represents the change in energy of the masses.
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