a control loop for a sump pump that uses a float switch with on/off contacts is an example of

Answer:

Using the Manning's Equation, the discharge rate can be calculated as follows:

Q = (1.49/n) x A x R^(2/3) x S^(1/2)

Where:

Q = discharge rate (m^3/sec)

n = Manning's roughness coefficient (0.011)

A = cross sectional area of the ditch (2m x 0.5m = 1 m^2)

R = hydraulic radius (half the width of the ditch, or 1 m)

S = slope of the ditch (0.0009)

Q = (1.49/0.011) x 1m^2 x 1m^(2/3) x 0.0009^(1/2)

Q = 13,636.36 m^3/sec

The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

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Modulus of Rupture = 940.3 ksi, Apparent modulus of elasticity = 42,999 ksi.

Using the information provided, we can calculate the modulus of rupture (MOR) and the apparent modulus of elasticity (MOE) of the wood lumber.

The equations to calculate these values are:

\(MOR = (3FL)/(2bd^2)\)

\(MOE = (FL^3)/(4bd^3δ)\)

Where:

F = maximum load (240 kips)

L = span (4 ft or 48 in.)

b = width of the lumber (4 in.)

d = depth of the lumber (unknown)

δ = deflection at mid-span (2.4 in.)

To solve for d, we can use the ratio of the width to the depth of the lumber, which is assumed to be 1:2 based on the given orientation. Therefore, we have:

b/d = 1/2

d = 2b

Substituting the known values, we get:

d = 2b = 2(4 in.) = 8 in.

Now we can calculate the MOR and MOE:

\(MOR = (3FL)/(2bd^2) = (3*240 kips*48 in.)/(2*4 in.*8 in.^2) = 940.3\) ksi

\(MOE = (FL^3)/(4bd^3δ) = (240 kips*(48 in.)^3)/(4*(4 in.)*(8 in.)^3*(2.4 in.)) = 42,999 ksi\)

Therefore, the modulus of rupture of the wood lumber is 940.3 ksi and the apparent modulus of elasticity is 42,999 ksi.

Note that the units of MOR and MOE are both in ksi (kips per square inch), which is a common unit used for strength and stiffness of materials.

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Software engineering is the activity of designing, developing, maintaining, testing and evaluating computer software. There are several success factors for software engineering, two of them are: clear objectives and goals and good management.

These two factors (clear objectives and good management) are very essentials in software engineering. What makes software engineering different from other branches of engineering is that software engineering involves more than one element. It involves design elements, testing, implementation and maintenance elements. So, it is more complex than other branches of engineering. And it also involves hardware and software, because to make a good software you have to know more about the hardware.

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Answer:

true ...............

Some refrigerants R11, R12, and R115 contain CFC. The statement is true.

Chlorofluorocarbons (CFCs), as the name suggests, are compounds made of the atoms of fluorine, chlorine, and carbon. Because they are neither hazardous nor combustible, they have a variety of uses, including in refrigeration. Refrigeration is the process of maintaining the temperature of the required space cooler than that of an atmosphere.

As the public learned in 1974 that CFCs were alarmingly destroying the ozone layer, most CFCs were outlawed, and by 1995, their manufacture of them had virtually ended worldwide.  CFCs were replaced with other products since they were no longer produced and the things they were used for required new products.

Therefore, some refrigerants R11, R12, and R115 contain CFC. The statement is true.

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Answer:

That's not true, if your house is burning down, leave. Let the firefighters do their jobs.

Explanation:

Answer:

answer letter c

Explanation:

yun anserr hhehehe

Answer:

The Euler buckling load of a 160-cm-long column will be 1.33 times the Euler buckling load of an equivalent 120-cm-long column.

Explanation:

160 - 120 = 40

120 = 100

40 = X

40 x 100 / 120 = X

4000 / 120 = X

33.333 = X

120 = 100

160 = X

160 x 100 /120 = X

16000 / 120 = X

133.333 = X

To design the circuit, you can use a combination of logic gates and adders.

Use two AND gates to check if the least significant bit (LSB) and the second least significant bit (SLB) of X are both 0, indicating an even number.

Connect the output of the AND gates to a 2-input multiplexer (MUX) with inputs X and X+2.

Use an XOR gate to check if the LSB of X is 1, indicating an odd number.

Connect the output of the XOR gate to a 2-input multiplexer (MUX) with inputs X+1 and X+3.

Connect the outputs of both MUXes to a 3-bit register, which stores the result as Y.

Connect the 3-bit output of the register to three LEDs to display the binary equivalent of Y.

Connect the 3-bit output of the register to a 3-to-8 decoder, which outputs the decimal equivalent of Y to the 7-segment display.

This circuit will add 2 to X if it's even or add 3 if it's odd, displaying the binary equivalent on LEDs and the decimal equivalent on the 7-segment display.

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In the case above about manual transmission, the gears are engaged manually.

The Definition of the term manual transmission is regarded as a kind of a system where there is the changing gears in a manual way.

Hence, In the case above about manual transmission, the gears are engaged manually is correct.

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On the print you would expect the pitch diameter of the gear to be 9.00 inches. Option A is right.

Gear ratio = 1/3

This is solved as number of teeth on pinion / teeth on gear

= Np/Ng

The pitch diameter = 1.5 x 2

= 3

Diametral pitch = 12

NP = 3 x 12 = 36

This is the teeth on piston

Ng = 3NP

Ng = 3 * 36

= 108

Hence pitch diameter = 108/12 = 9

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Answer:

Explanation:

It is a device which consists of four layers and two terminals. The construction is almost the same as that of the transistor. But there are certain points which deviate from the construction from the transistor. The differentiating points are-

There is no base terminal in the DIAC

The three regions have almost the same level of doping

It gives symmetrical switching characteristics for either polarity of voltages

DIAC Diode

A program Input an integer and then Tests if it is a multiple of 5 or not.

To create the desired program, prompt the user to input an integer number. Then, perform a test to check if the number is a multiple of 5 or not.

This can be done by checking if the remainder of dividing the number by 5 is equal to 0. If the remainder is 0, it means the number is divisible by 5 and hence, a multiple of 5. If the remainder is not 0, it means the number is not divisible by 5 and therefore not a multiple of 5.

Based on the test result, display an appropriate message indicating whether the number is a multiple of 5 or not. This can be achieved using conditional statements such as if-else.

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When welding a T-joint, the reason that the arc need to be directed more toward the bottom workpiece is so that a person can hinder or stop any form of undercutting of the given top piece.

The Positioned flat of the flat position weld, often known as a "downhand" position, is the simplest and frequently the first weld that new pupils learn.

The welder places the metals to be welded flat and moves the electric arc across them while it travels across the workpiece in a way that is said to be an  horizontal orientation.

Therefore, based on the above, When welding a T-joint, the reason that the arc need to be directed more toward the bottom workpiece is so that a person can hinder or stop any form of undercutting of the given top piece.

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Programmers who use object-oriented methods consider in terms of a class instance that has its own properties and behaviours, which is how they vary from those who use procedural methods.

Procedural programming tackles applications by managing difficulties using a top-down method where it solves problems from the top of the code and to the bottom, whereas object-oriented programming is known to be one that employs classes and objects. A programming design strategy known as procedural programming attempts to break down clearly specified tasks into modules, functions, etc. In object-oriented programming, objects are only the individual parts of a programme. The (c) Method defines the behaviour of objects. The behaviour of objects is defined through methods, which are merely functions and subroutines. Consider the following approach, for instance: Public static int (int I Fibonacci

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Answer:

rotation

Explanation:

I just answered this!

1. Using a non-correlated sub-query, the names of employees who are not working on any projects can be found using the following query:

SELECT name FROM Employees WHERE employee_id NOT IN (SELECT employee_id FROM Projects);

2. Using a correlated sub-query, the names of employees who are not working on any projects can be found using the following query:

SELECT name FROM Employees WHERE NOT EXISTS (SELECT * FROM Projects WHERE Employees.employee_id = Projects.employee_id);

3. Using a non-correlated sub-query, the names of the employees who work on projects that are located in the same city where the employees are located can be found using the following query:

SELECT e.name FROM Employees e INNER JOIN Projects p ON e.employee_id = p.employee_id WHERE e.city = p.city;

4. Using a correlated sub-query, the names of the employees who work on projects that are located in the same city where the employees are located can be found using the following query:

SELECT name FROM Employees e WHERE EXISTS (SELECT * FROM Projects p WHERE e.employee_id = p.employee_id AND e.city = p.city);

5. Using a sub-query, the names of the employees with the highest rate can be found using the following query:

SELECT name FROM Employees WHERE rate = (SELECT MAX(rate) FROM Employees);

6. Using a sub-query and the ALL operator, the names of the employees with the highest rate can be found using the following query:

SELECT name FROM Employees WHERE rate >= ALL (SELECT rate FROM Employees);

7. Using inline views and sub-query, the names of employees with the highest rate can be found using the following query:

SELECT name FROM (SELECT name, MAX(rate) AS max_rate FROM Employees GROUP BY name) AS e WHERE e.max_rate = (SELECT MAX(rate) FROM Employees);

8. Using self-join, the names of the employees who work on more than one project can be found using the following query:

SELECT DISTINCT e1.name FROM Employees e1 INNER JOIN Projects p1 ON e1.employee_id = p1.employee_id INNER JOIN Projects p2 ON e1.employee_id = p2.employee_id WHERE p1.project_id != p2.project_id;

9. Using a non-correlated sub-query, the names of the employees who work on more than one project can be found using the following query:

SELECT name FROM Employees e WHERE e.employee_id IN (SELECT employee_id FROM Projects GROUP BY employee_id HAVING COUNT(*) > 1);

10. Using a correlated sub-query, the names of the employees who work on more than one project can be found using the following query:

SELECT name FROM Employees e WHERE EXISTS (SELECT * FROM Projects p WHERE e.employee_id = p.employee_id GROUP BY p.employee_id HAVING COUNT(*) > 1);

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Answer:

control loop unit

Explanation:

Edmentum/Plato

Answer:

B. evaluation of a particular program

Explanation:

Before students enrol into any given discipline, they should first ensure that their program of choice is well accredited. In a specific program, specialized accreditation has the function of telling would be students if the program meets up with academic standards in the field

Accreditation is a way of assessing faculty and curriculum quality of schools to make sure that they are up to academic standards and are also preparing students to future success in the field.

Answer:

Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang

Answer: hello attached below is the diagram which is part of your question

Total entropy change  = entropy change in cold reservoir + entropy change in hot reservoir = -0.166 + 0.083 = -0.0837 kj/k  it violates Clausius increase of entropy which is Sgen > 0

Explanation:

Clausius statement states that it is impossible to transfer heat energy from a cooler body to a hotter body in a cycle or region without any other external factors affecting it .  

applying the increase in entropy principle to prove this

temp of cold reservoir (t hot)= 600 k

temp of hot reservoir(t cold) = 1220 k

energy (q) = 100 kj

total entropy change  = entropy change in cold reservoir + entropy change in hot reservoir = -0.166 + 0.083 = -0.0837 kj/k

entropy change in cold reservoir = Q/t cold = 100 / 600 = -0.166 kj/k

entropy change in hot reservoir = Q / t hot = 100 / 1220 = 0.083 kj/k

hence it violates  Clausius inequality of increase of entropy principle which is states that generated entropy has to be > 0

For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about one.

A particular disk is activated by mounting software, which makes its contents accessible to the computer's file system. A partition is created in the computer's file system for the mounted device when it is mounted.

A framework or foundation that supports or supports something else. Mounting is another word for support.

The procedure through which the operating system of a computer makes the files and directories on a storage device (such as a hard drive, CD-ROM, or network share) accessible to users via the computer's file system is known as mounting.

For surface-mounted and pendant-hung luminaires, mounting rods should be placed so that they develop about one.

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An environmental hazard is a substance, state or event which has the potential to threaten the surrounding natural environment and/or adversely affect human's health. This term incorporates topics like pollution, natural disasters and human-made hazards. Health studies investigate the human health effects of exposure to environmental hazards ranging from chemical pollutants to natural, technological or terrorist disasters. The environment in which we live can be considered as having three fundamental sets of components, physical, chemical, biological. Associations between an exposure and an adverse health effect do not, on their own, prove that the former is the cause of the latter. Many other non-causal associations could explain the findings. Physical hazards involve environmental hazards that can cause harm with or without contact. Examples are earthquakes, electromagnetic fields, floods, light pollution, noise pollution, vibration, x-rays etc. Radioactivity is associated with an exposure dependent risk of some cancers notably leukaemia. The scientific evidence of adverse health effects from general environmental exposure to these fields is "not proven". If there are adverse effects yet to be proven, the risk is probably likely to be small. Chemical substances cause significant damage to the environment. Tobacco smoke is the single biggest known airborne chemical risk to health, whether measured in terms of death rates or ill-health. To a much lesser degree of risk, these adverse effects apply to non-smokers exposed passively to sidestream tobacco smoke. Health effects of concern are asthma, bronchitis, lung cancer and similar lung diseases, and there is good evidence relating an increased risk of symptoms of these diseases with increasing concentration of Sulphur dioxide, ozone and other pollutants. Biohazards generally fall into two broad categories: those which produce adverse health effects through infection (microorganisms, viruses or toxins) and those which produce adverse effects in non-infective (allergic) ways.

Hope this helps...:)

The key to using organization to improve productivity is to establish clear systems, prioritize tasks, and create an environment that supports efficient work processes.

One way to use organization to improve productivity is by separating tasks instead of grouping them.

By breaking down your workload into smaller, manageable tasks, you can prioritize and focus on one task at a time, leading to increased efficiency and productivity.

This approach helps prevent overwhelm and allows you to allocate your time and energy effectively.

Another way is to organize your brain, workspace, and time. This involves maintaining a clear and organized mindset, decluttering and arranging your physical workspace for easy access to resources and tools, and managing your time efficiently.

By creating a structured and organized environment, you can reduce distractions, streamline your workflow, and optimize your productivity.

However, it's important to note that organizing by multi-tasking may not always be the most effective approach.

Research suggests that multi-tasking can actually decrease productivity and lead to errors and distractions. Instead, focusing on one task at a time and giving it your full attention can yield better results.

Lastly, spreading important items and tools out can also improve productivity.

By strategically placing frequently used items within reach and organizing them in a logical manner, you can minimize time spent searching for things and enhance your workflow.

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To prove the given theorem, we need to show that the sum of the moments of two couples lying in the same plane can be replaced by a single couple lying in the same plane and being equal in magnitude and direction to the sum of the moments of the given couples.

Let the two couples be represented by vectors A and B, where A and B are perpendicular to the plane of the couples, and the magnitudes of A and B represent the magnitudes of the moments of the respective couples. Let the position vectors of the points of application of the two couples be c1 and c2, respectively.

The moment of vector A about point P is given by the cross product of the position vector c1 and the vector A:

M1 = c1 x A

Similarly, the moment of vector B about point P is given by:

M2 = c2 x B

The sum of the moments of the two couples is given by:

M = M1 + M2

To replace the two couples by a single couple, we need to find a single vector V lying in the same plane as the two couples, such that its moment about point P is equal to M.

Let the position vector of the point of application of the single couple be c. Then, the moment of vector V about point P is given by:

M' = c x V

For the two couples to be equivalent to the single couple, we need to find V such that:

M' = M

Substituting the expressions for M, M1, and M2, we get:

c x V = (c1 x A) + (c2 x B)

Taking the cross product of both sides with c, we get:

c x (c x V) = c x (c1 x A) + r x (c2 x B)

Using the vector triple product identity, we get:

(c.V)c - (c.c)V = (c.A)c1 - (c1.c)A + (c.B)c2 - (c2.c)B

Simplifying the right-hand side, we get:

V = (A+B) + (((c1-c2).A)c2 - ((c1-c2).B)c1)/(c.(c1-c2))

Thus, we have found a vector V that lies in the same plane as the two couples, and its moment about point P is equal to the sum of the moments of the two couples. Therefore, the two couples can be replaced by a single couple lying in the same plane and equal in magnitude and direction to the sum of the moments of the given couples.

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The ability to make quick and effective decisions is essential in a fast-paced environment. When this ability is slowed down, it can lead to negative consequences. By improving your decision-making abilities, you can increase your chances of success and thrive in any fast-paced setting.

It is important to note that decision-making is a crucial aspect of any fast-paced environment. However, when your ability to make decisions is slowed down, it can hinder your progress and cause delays. This can be due to various factors such as lack of experience, limited information, or cognitive overload.

It is important to identify the root cause of the issue and work towards improving your decision-making abilities. This can be achieved through training, seeking advice from experts, and developing a systematic approach to decision-making.

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The covers and guardrails are required in all of the following areas except ditches.

Yes, they do need a covers and/or guardrails and it is one that is known or shall be provided to help in the protection of personnel from the hazards that pertains to open pits, tanks, vats and others.

Note that they are often needed that is covers and/or guardrails need to be provided to help to protect personnel.

Therefore, The covers and guardrails are required in all of the following areas except ditches.

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Answer:

Option D. is correct

Explanation:

Joe uses one of his CAT5 patch cables to connect two hubs to add a new segment to his local network. As he can only connect to it from a workstation within that segment,  he is not able to reach the new network segment from his workstation.

The most problem is that the technician used a straight-through cable.

Option D. is correct.

To calculate the surface deflection under the center of a tire, we can use the two-layer theory which considers the pavement layer and the subgrade layer. The formula for the surface deflection is given by:

δ = (P/a) * (1-v) * (h1/((E1/((1-v1^2) + (E2/((1-v2^2))))))

Where,

P = tire pressure = 552 kPa

a = contact area of the tire = 152 mm

v = Poisson's ratio

h1 = thickness of the pavement layer = 305 mm

E1 = modulus of elasticity of the pavement layer = 345 MPa

v1 = Poisson's ratio of the pavement layer

E2 = modulus of elasticity of the subgrade layer = 69 MPa

v2 = Poisson's ratio of the subgrade layer

Substituting the given values in the above formula, we get:

δ = (552/152) * (1-0.25) * (305/((345/((1-0.25^2) + (69/((1-0.3^2))))))

δ = 3.029 mm

The interface deflection can be calculated as:

δi = (P/a) * ((h2 * (E1/((1-v1^2) + (E2/((1-v2^2))))))

Where,

h2 = thickness of the subgrade layer

Substituting the given values in the above formula, we get:

δi = (552/152) * ((0.0 * (345/((1-0.25^2) + (69/((1-0.3^2))))))

δi = 0 mm

As there is no thickness of subgrade layer given, the interface deflection is zero.

The deflection that takes place within the pavement layer can be calculated as the difference between the surface deflection and the interface deflection:

δp = δ - δi

δp = 3.029 - 0

δp = 3.029 mm

Therefore, the surface deflection under the center of a tire is 3.029 mm, the interface deflection is 0 mm, and the deflection that takes place within the pavement layer is 3.029 mm.

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