The time taken for the cork to reach the shore is 92.1 s.
The given parameters:
Frequency of the oscillation, f = 2 HzWavelength of the oscillation, λ = 7.6 cmDistance of the cork from the shore, d = 14.0 mThe speed of the wave is calculated as follows;
\(v = f \lambda \\\\v = 2 \times 0.076 \\\\v = 0.152 \ m/s\)
The time taken for the cork to reach the shore is calculated as follows;
\(time = \frac{distance}{speed} \\\\time = \frac{14}{0.152} \\\\time = 92.1 \ s\)
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Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced human society as a whole.
Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.
Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.
Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.
Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.
Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.
Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.
Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.
Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.
Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.
Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.
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A horizontally launched projectile lands 75.72 m below the launch point and a horizontal distance of 104.42 m/s from the launch point. How long did it take to hit the ground?
With an initial horizontal velocity of 32.31 m/s and a time of 3.23 seconds to impact the earth, the projectile was launched.
Is the projectile's velocity in the y direction zero when it is fired horizontally?When an object is hurled horizontally in projectile motion, it has zero initial vertical velocity and only a horizontal initial velocity. Through the projectile's entire motion, the original horizontal velocity is maintained.
\(y = 1/2 * a_y * t^2\)
\(t^2 = 2y / a_y\)
\(t = sqrt(2y / a_y)t = sqrt(2*75.72 m / 9.81 m/s^2)\)
t = 3.23 s (rounded to two decimal places)
\(x = vi_x * t\)
\(vi_x = x / t\)
\(vi_x = 104.42 m / 3.23 s\)
\(vi_x = 32.31 m/s\)(rounded to two decimal places)
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A 50gram bracelet is suspected of not being pure gold. It is dropped into a glass of water and 4 cm3of water overflows. Is the bracelet pure gold? How do you know?
Since, density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
To know if the bracelet is pure gold, we calculate the density of the bracelet and compare it to the density of pure gold (19.3 g/cm³).
That is, for the bracelet to pure gold,
Density of bracelet ≈ 19.3 g/cm³
What is Density?Density can be defined as the ratio of the mass and the volume of a substance.
The formula of Density is give as
D = m/v................... Equation 1⇒ Where:
D = Density of the braceletm = mass of the braceletv = volume of the braceletFrom the question,
⇒ Given:
m = 50 gv = 4 cm³ (an object displace an amount of water equal to it's own volume)⇒ Substitute these values into equation 1
D = 50/4D = 12.5 g/cm³Hence, since the density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
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the thermal energy of what system does change
Answer:
there is the increase the temperature of cold body and decrease the temperature of hot body
A football is kicked from the ground with a speed of 30 m/s at an angle of 60º with the ground. What is the horizontal component of the football immediately after it is kicked?
a
30 m/s
b
30 tan(60º) m/s
c
30 sin(60º) m/s
d
30 cos(60º) m/s
Answer:
D
Explanation:
30 m/s is the hypothenuse. The horizontal component will be x. Using trig, you can see that
\(cos(angle) = \frac{x}{hypotenuse} \)
two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then what is the magnitude and the direction of the resultant force
what is its acceleration of x and y component
what is the magnitude of acceleration of the object
Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.
The acceleration of the object in the x-component (\(a_x\)) is 2.4 \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8 \(m/s^{2}\).
The magnitude of the acceleration of the object is 3 \(m/s^{2}\).
To find the magnitude and direction of the resultant force, we need to add the two given forces together.
Given:
f1 = (8i + 3j) N
f2 = (4i + 6j) N
To find the resultant force (\(F_res\)), we simply add the corresponding components:
\(F_res\) = f1 + f2
= (8i + 3j) + (4i + 6j)
= (8 + 4)i + (3 + 6)j
= 12i + 9j
The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:
\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)
= \(\sqrt{144 + 81}\)
= \(\sqrt{225}\)
= 15 N
So, the magnitude of the resultant force is 15 N.
To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:
θ = arctan(9/12)
= arctan(3/4)
≈ 36.87 degrees
Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.
Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:
F = ma
For the x-component:
\(F_x\)= 12 N
m = 5 kg
Using \(F_x\)= \(ma_x\), we can solve for \(a_x\):
12 N = 5 kg * \(a_x\)
\(a_x\)= 12 N / 5 kg
\(a_x\) = 2.4 \(m/s^{2}\)
For the y-component:
\(F_y\) = 9 N
m = 5 kg
Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):
9 N = 5 kg * \(a_y\)
\(a_y\) = 9 N / 5 kg
\(a_y\)= 1.8 \(m/s^{2}\)
So, the acceleration of the object in the x-component (\(a_x\)) is 2.4 \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8 \(m/s^{2}\).
To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:
|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)
= \(\sqrt{(2.4^2) + (1.8^2}\)
= \(\sqrt{5.76 + 3.24}\)
= \(\sqrt{9}\)
= 3 \(m/s^{2}\)
Therefore, the magnitude of the acceleration of the object is 3 \(m/s^{2}\)
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Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?
The wavelength of this radio signal is equal to 3.18 meters.
Given the following data:
Frequency = \(9.45 \times10^7\) Hz.Speed of light = \(3 \times 10^8\) m/s.What is wavelength?Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.
How to calculate wavelength.Mathematically, the wavelength of a wave is given by this formula:
\(\lambda = \frac{V}{F}\)
Where:
F is the frequency of a wave.V is the speed of a sound wave.\(\lambda\) is the wavelength of a sound wave.Substituting the given parameters into the formula, we have;
\(\lambda = \frac{3 \times 10^8}{9.45 \times10^7}\)
Wavelength = 3.18 meters.
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The wavelength of the radio signal travel at speed of light is 3.17m.
Given the data in the question;
Frequency of the radio wave; \(f = 9.45 * 10^{7}Hz = 9.45 * 10^{7} s^{-1}\)Wavelength of a radio signal; \(\lambda = \ ?\)WavelengthWavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength is expressed as;
\(\lambda = \frac{v}{f}\)
Where \(\lambda\) is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( \(c = 3*10^8m/s\) )
We substitute our values into the expression above.
\(\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m\)
Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.
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The mass of Jupiter is 0.001 solar mass. The orbital period of Jupiter is 11.9 Earth years.
What is the distance between Jupiter and the Sun?
5.2 AU
41 AU
52 AU
410 AU
Answer:
The distance between Jupiter and the Sun is 5.2 AU.
The answer would be A: 5.2 Au away from the sun (AU is the unit that is the same length as the distance between Earth and the Sun)
What is harmonic motion
Answer: NNOOOOOOOOOOOOOOOOOOONONONO
Explanation: simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side. The time interval of each complete vibration is the same. The force responsible for the motion is always directed toward the equilibrium position and is directly proportional to the distance from it. That is, F = −kx, where F is the force, x is the displacement, and k is a constant. This relation is called Hooke’s law.
A specific example of a simple harmonic oscillator is the vibration of a mass attached to a vertical spring, the other end of which is fixed in a ceiling. At the maximum displacement −x, the spring is under its greatest tension, which forces the mass upward. At the maximum displacement +x, the spring reaches its greatest compression, which forces the mass back downward again. At either position of maximum displacement, the force is greatest and is directed toward the equilibrium position, the velocity (v) of the mass is zero, its acceleration is at a maximum, and the mass changes direction. At the equilibrium position, the velocity is at its maximum and the acceleration (a) has fallen to zero. Simple harmonic motion is characterized by this changing acceleration that always is directed toward the equilibrium position and is proportional to the displacement from the equilibrium position. Furthermore, the interval of time for each complete vibration is constant and does not depend on the size of the maximum displacement. In some form, therefore, simple harmonic motion is at the heart of timekeeping.
A girl runs 120m due north in 15s. she then runs 80m due east in 12s.What is average speed?
The average speed of the girl is 2.26 m/s.
The average speed is calculated by dividing the total distance traveled by the total time taken. In this case, the girl traveled a total distance of 120 m + 80 m = 200 m. She took a total time of 15 s + 12 s = 27 s to travel this distance.
Therefore, the average speed is:
average speed = total distance / total time
average speed = 200 m / 27 s
average speed = 2.26 m/s
The average speed does not take into account the direction of the motion. The girl traveled in two different directions, so the average speed is not a meaningful measure of her speed.
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i
e. network executives make hasty
When winding an old clock, it is important not to overwind it. Over-
winding occurs when the mainspring is almost fully wound, but the
operator continues to turn the winding key. This causes the main
spring to coil too tight, and might even break it.
110. This paragraph best supports the statement that
a. clocks have changed over the years.
b. old-fashioned clocks become fragile with age.
c. old-fashioned clocks were operated by an internal spring.
d. overwinding clocks used to be a common mistake.
e. time flies when you're having fun.
The paragraph primarily discusses the concept of overwinding old clocks and its consequences, indicating that overwinding clocks used to be a common mistake. Here option D is the correct answer.
The paragraph explains that overwinding occurs when the mainspring is almost fully wound, but the operator continues to turn the winding key, resulting in the spring coiling too tightly or even breaking.
This suggests that overwinding was a mistake commonly made in the past when operating old-fashioned clocks. The other options, such as clocks changing over the years or clocks becoming fragile with age, are not directly addressed in the paragraph and are therefore less supported.
The option e. "time flies when you're having fun" is unrelated to the paragraph and can be disregarded as an irrelevant answer choice. Hence option D is the correct answer.
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Three 7Ω resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?
ANSWER:
21Ω
STEP-BY-STEP EXPLANATION:
Given:
R1 = R2 = R3 = 7Ω
The resistance in a series circuit has the following equation
\(R_{eq}=R_1+R_2\ldots+R_n\)We replacing in this case:
\(\begin{gathered} R_{eq}=R_1+R_2+R_3 \\ R_{eq}=7+7+7 \\ R_{eq}=21\Omega \end{gathered}\)The equivalent resistance of the circuit is 21Ω
The largest identified asteroid is Ceres and is about three times the size of the Moon.
True
or
False
\(false\)
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Experiment 7 static equilibrium of a rigid body.
1. Do the equilibrium conditions meet in Measurements #1 and #2? If errors exist, what are the main error sources?
The answer is yes. You know this because the table isn't moving or rotating.
A block of mass m is hung from the ceiling by the system of massless springs consisting of two layers. The upper layer consists of 3 strings in paralle, and the lower layer consists of 2 strings in parallel. The horizontal bar between the two layers has negligible mass. The force constants of all springs are k. Calculate the period of the vertical oscillations of the block.
Answer:
T₀ = 2π \(\sqrt{\frac{m}{k} }\) T = \(\sqrt{\frac{5}{6} }\) T₀
Explanation:
When the block is oscillating it forms a simple harmonic motion, which in the case of a spring and a mass has an angular velocity
w = \(\sqrt{k/m}\)
To apply this formula to our case, let's look for the equivalent constant of the springs.
Let's start with the springs in parallels.
* the three springs in the upper part, when stretched, lengthen the same distance, therefore the total force is
F_total = F₁ + F₂ + F₃
the springs fulfill Hooke's law and indicate that the spring constant is the same for all three,
F_total = - k x - k x - kx = -3k x
therefore the equivalent constant for the combination of the springs at the top is
k₁ = 3 k
* the two springs at the bottom
following the same reasoning the force at the bottom is
F_total2 = - 2 k x
the equivalent constant at the bottom is
k₂ = 2 k
now let's work the two springs are equivalent that are in series
the top spring is stretched by an amount x₁ and the bottom spring is stretched x₂
x₂ = x -x₁
x₂ + x₁ = x
if we consider that the springs have no masses we can use Hooke's law
\(-\frac{F_{1} }{k_{1} } - \frac{F_{2}}{k_{2} } = \frac{F}{k_{eq} }\)
therefore the equivalent constant is the series combination is
\(\frac{1}{k_{eq} } = \frac{1}{k_{1} } + \frac{1}{k_{2} }\)
we substitute the values
\frac{1}{k_{eq} } = \frac{1}{3k } + \frac{1}{2k }
\frac{1}{k_{eq} } = \frac{5}{6k} }
k_eq = \(\frac{6k}{5}\)
therefore the angular velocity is
w = \(\sqrt{\frac{6k}{5m} }\)
angular velocity, frequency, and period are related
w = 2π f = 2π / T
T = 2π / w
T = 2π \(\sqrt{\frac{5m}{6k} }\)
T₀ = 2π \(\sqrt{\frac{m}{k} }\)
T = \(\sqrt{\frac{5}{6} }\) T₀
What is the current in the 60.0 Q resistor? 120.0 V O A. 80.0 A B. 2.00 A O C. 1.50 A OD. 12.0 A 60.002 20.0 Q A
2A
Given ,
Resistance=60
V=12
V=IR
I=V/R
I=120/60=2A
The pace at which electrons flow past a location in a complete electrical circuit is defined as current. At its most fundamental, current Means flow.
An ampere (AM-pir), sometimes known as an amp, is the international unit for measuring current. It denotes the number of electrons (also known as "electrical charge") that pass across a location in a circuit over a specific time period.
A current of one ampere indicates that one coulomb of electrons—that is, 6.24 billion billion (6.24 x 1018) electrons—moves across a circuit in one second. The method is comparable to determining how many gallons move through a single spot in a pipe in one minute (gallons per minute, or GPM).
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A charged particle is located 1 meter away from a charged sphere, and experiences a force of −0.5 N. If the distance is increased to 2 meters, which of the following would be correct?
A.The force would be one-fourth the original force.
B.The force would be one-half the original force.
C.The force would be two times greater.
D.The force would be four times greater.
the correct answer is A. The force would be one-fourth the original force.
According to Coulomb's law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The mathematical expression for Coulomb's law is:
F = k * q1 * q2 / \(r^2\)
where F is the force, k is the Coulomb constant, q1 and q2 are the charges of the particles, and r is the distance between them.
In this case, the force is given as -0.5 N, which means that the charges must be of opposite signs. Let's assume that the charged sphere has a positive charge, so the test particle must have a negative charge. The distance between them is initially 1 meter.
Plugging in the given values into Coulomb's law, we get:
-0.5 N = k * q_sphere * q_particle / \((1 m)^2\)
where q_sphere is the charge of the sphere and q_particle is the charge of the test particle.
If we double the distance between the particles to 2 meters, then the new force can be calculated using the same equation:
F' = k * q_sphere * q_particle / (\(2 m)^2\)
To determine how the new force F' relates to the original force F, we can take the ratio of the two equations:
F' / F = (k * q_sphere * q_particle / \((2 m)^2\\\)) / (k * q_sphere * q_particle / (1 \(m)^2\))
= (1/4)
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Answer: A
Explanation: the correct answer is A, The force would be one-fourth the original force.
Lithium an element in group 1. What element is below Lithium in the same group
Answer:
Group 1A (or IA) of the periodic table are the alkali metals: hydrogen (H), lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).
Explanation:
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the tension T in Newtons in the string of a yoyo of mass 0.001kg is give by the function of two variables (see equation in photo).
find the approximate change in T if R increases from 4cm to 4.1cm and r increases from 0.8cm to 0.9cm. use your answer to explain if the tension increases or decreases.
The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.
How can the correct description of the change in the graph of the function be found?
Mass of the yoyo = 0.001 kg
Initial value of the spindle radius, R = 4 cm
Initial length of the radius of the yo–yo, r = 0.8 cm
The final values are;
R2 = 4.1 cm, r2 = 0.9 cm
Which gives;
\(T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} \)
Which gives;
\(T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} \)
\(T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} \)
Therefore;
\( \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} \)
Given that difference between the final and the initial states is negative, the the value of the tension decreases
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The 4 kg bob swings on a massless cable 2 meters in length. Determine the velocity of the swinging pendulum at the instant = 33 degrees and the cable tension is 60 N. Report the result in m/s.
The given problem can be exemplified in the following diagram:
To determine the velocity when the mass is located at point 2 we will consider that the change in gravitational potential energy from 1 to 2 is equal to the kinetic energy at 2, therefore, we have:
\(\Delta U=K\)Where:
\(\begin{gathered} \Delta U=\text{ change in gravitational potential energy} \\ K=\text{ kinetic energy} \end{gathered}\)Now, we use the following formula for the gravitational potential energy:
\(\Delta U=mgh\)Where:
\(\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \\ h=\text{ change in height} \end{gathered}\)The kinetic energy is given by:
\(K=\frac{1}{2}mv^2\)Now, we substitute the formulas:
\(mgh=\frac{1}{2}mv^2\)We can cancel out the mass "m":
\(gh=\frac{1}{2}v^2\)Now, we solve for the velocity by multiplying both sides by 2:
\(2gh=v^2\)Now, we take the square root to both sides:
\(\sqrt[]{2gh}=v\)Now, we determine the height "h" using the following triangle:
We notice that the adjacent side of the triangle plus the height "h" is equal to the length of the pendulum, therefore, we have the next relationship:
\(x+h=2\)We solve for "h" by subtracting "x" from both sides:
\(h=2-x\)Now, we determine the value of "x" by using the function cosine:
\(\cos 33=\frac{x}{2}\)Now, we multiply both sides by 2:
\(2\cos 33=x\)Now, we substitute the value of "x":
\(h=2-2\cos 33\)Solving the operations:
\(h=0.32\)Therefore, the change in height is 0.32 meters. Substituting in the formula for the velocity we get:
\(\sqrt[]{2(9.8\frac{m}{s^2})(0.32m)}=v\)Solving the operations:
\(2.5\frac{m}{s}=v\)Therefore, the velocity of the mass is 2.5 m/s.
A rigid, insulated tank whose volume is 10 L is initially evacuated. A pinhole leak develops and air from the surroundings at 1 bar, 25 C enters the tank until the pressure in the tank becomes 1 bar (assume ideal gas model k=1.4 for the air). Find:
A) final temperature in tank.
B) amount of air that leaks into tank in grams.
C) amount of entropy produced in J/K.
Answer:
The answer is "\(143.74^{\circ} \ C , 8.36\ g, and \ 2.77\ \frac{K}{J}\)"
Explanation:
For point a:
Energy balance equation:
\(\frac{dU}{dt}= Q-Wm_ih_i-m_eh_e\\\\\)
\(W=0\\\\Q=0\\\\m_e=0\)
From the above equation:
\(\frac{dU}{dt}=0-0+m_ih_i-0\\\\\Delta U=\int^{2}_{1}m_ih_idt\\\\\)
because the rate of air entering the tank that is \(h_i\) constant.
\(\Delta U = h_i \int^{2}_{1} m_i dt \\\\= h_i(m_2 -m_1)\\\\m_2u_2-m_1u_2=h_i(M_2-m_1)\\\\\)
Since the tank was initially empty and the inlet is constant hence, \(m_2u-0=h_1(m_2-0)\\\\m_2u_2=h_1m_2\\\\u_2=h_1\\\\\)
Interpolate the enthalpy between \(T = 300 \ K \ and\ T=295\ K\). The surrounding air
temperature:
\(T_1= 25^{\circ}\ C\ (298.15 \ K)\\\\\frac{h_{300 \ K}-h_{295\ K}}{300-295}= \frac{h_{300 \ K}-h_{1}}{300-295.15}\)
Substituting the value from ideal gas:
\(\frac{300.19-295.17}{300-295}=\frac{300.19-h_{i}}{300-298.15}\\\\h_i= 298.332 \ \frac{kJ}{kg}\\\\Now,\\\\h_i=u_2\\\\u_2=h_i=298.33\ \frac{kJ}{kg}\)
Follow the ideal gas table.
The \(u_2= 298.33\ \frac{kJ}{kg}\) and between temperature \(T =410 \ K \ and\ T=240\ K.\)
Interpolate
\(\frac{420-410}{u_{240\ k} -u_{410\ k}}=\frac{420-T_2}{u_{420 k}-u_2}\)
Substitute values from the table.
\(\frac{420-410}{300.69-293.43}=\frac{420-T_2}{{u_{420 k}-u_2}}\\\\T_2=416.74\ K\\\\=143.74^{\circ} \ C\\\\\)
For point b:
Consider the ideal gas equation. therefore, p is pressure, V is the volume, m is mass of gas. \(\bar{R} \ is\ \frac{R}{M}\) (M is the molar mass of the gas that is \(28.97 \ \frac{kg}{mol}\) and R is gas constant), and T is the temperature.
\(n=\frac{pV}{TR}\\\\\)
\(=\frac{(1.01 \times 10^5 \ Pa) \times (10\ L) (\frac{10^{-3} \ m^3}{1\ L})}{(416.74 K) (\frac{8.314 \frac{J}{mol.k} }{2897\ \frac{kg}{mol})}}\\\\=8.36\ g\\\\\)
For point c:
Entropy is given by the following formula:
\(\Delta S = mC_v \In \frac{T_2}{T_1}\\\\=0.00836 \ kg \times 1.005 \times 10^{3} \In (\frac{416.74\ K}{298.15\ K})\\\\=2.77 \ \frac{J}{K}\)
Why do the balls react differently when you drop them together?
A car of mass 1150 kg drives in a circle of radius 44 m. If the car has a speed of 13 m/s, what is the
centripetal force acting on the car?
Answer:
4417
i think because
mv^2/r is centripetal force
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Please can you explain what this paragraph is trying to say. Also what does it mean in the sentence 'the difference in charge across the battery provides push for current' and what is the difference in charge.
Here's paragraph I need to have a simple definition of:
A high waterfall is also like a large voltage. It will transfer a lot of energy to the water (charge), making the river flow very fast (a large current) the difference in height makes the river flow. In a circuit , the difference in charge across battery provides push for the current.
Annalise observes a streak of light in the sky and says she is seeing a shooting star. What is she most likely
observing?
a falling star
an asteroid
O a meteor
O a dwarf planet
Answer:
A meteor
Explanation:
It travels so fast, that when it enters earth's atmosphere it burns up leaving that trail of fire which makes it look like a shooting star.
Answer:
meteor
Explanation:
Its right on edge 2021!
A boat sails for 24 km pointed in the direction [40° S of WI. A constant current moves the boat 8 km [30° W of N]. If the trip takes 3 hours, find the boats resultant velocity
Please brainliest, really need it!!!
The resultant velocity of the boat is 7.5 km/h.
What is the resultant displacement of the boat?The resultant displacement of the boat is calculated as follows;
Sum of the vertical displacement of the boat is calculated as;
∑Fy = -24 km sin(50) + 8 km sin(60)
∑Fy = -11.5 km
Sum of the horizontal displacement of the boat is calculated as;
∑Fx = -24 km cos(50) - 8 km cos(60)
∑Fx = -19.4 km
The resultant displacement is calculated as follows;
d = √ (-11.5² + 19.4²)
d = 22.55 km
The resultant velocity of the boat is calculated as follows;
v = ( 22.55 km ) / ( 3 hrs )
v = 7.5 km/h
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if no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is lily to worsen lessen or remain the same during the next 50 years
If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then a. likely to worsen
Astronomers already have a serious problem with light pollution from cities and other sources, which makes it more challenging to detect dim objects in the night sky. Light pollution is predicted to get worse unless action is taken to stop it as urbanisation grows and more artificial lights are installed.
Astronomical observations can be affected by radio interference from telecommunications, and unless steps are taken to reduce the issue, the issue is only going to become worse as the number of radio-emitting devices rises. In addition, astronomers' instruments and spacecraft are increasingly in danger from space debris. The probability of collisions and other accidents is anticipated to rise as the amount of trash in space continues to rise.
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Complete Question:
If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then -
a. likely to worsen
b. lessen or remain the same during the next 50 years
A 1400-N crate rests on the floor.
How much work is required to move it at constant speed 5.0 m
vertically.
Express your answer to two significant figures and include the appropriate units.
The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.
The formula for gravitational potential energy is given by:
Potential energy = mass * acceleration due to gravity * height
In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).
Given:
Weight of crate (W) = 1400 N
Acceleration due to gravity (g) = 9.8 m/s^2
Vertical distance (height) = 5.0 m
First, calculate the mass of the crate:
1400 N = m * 9.8 m/s^2
m = 1400 N / 9.8 m/s^2 ≈ 143 kg
Now we can calculate the work:
Work = Potential energy = mass * g * height
Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J
Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
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Suppose that a magnetic field of 1 T goes out of the plane of the page. A straight wire carries a current 1 A from right to left. Find the direction of force acting on the wire.Group of answer choicesout of the pageinto the pageleft, in the plane of the pageright, in the plane of the pageup, in the plane of the page
Given:
The magnetic field, B=1 T
The current through the wire, I=1 A
To find:
The direction of the magnetic force.
Explanation:
The direction of the magnetic force is given by the right-hand rule. It states that when you hold the index finger, thumb, and middle finger perpendicular to each other if the index finger is pointing in the direction of a magnetic field and the thumb is pointing in the direction of the flow of the current then the middle finger is will be pointing in the direction of the magnetic force.
By applying this rule, we can see that the middle finger is directed up the plane of the page.
Final answer:
Thus the magnetic field is directed up, in the plane of the page.
you are given a set of facts regarding a lens : object heigh, and dostance to objects. Given this jnformation, how can you tell if you're dealing with a concave or convex lens
Answer:
concave curves inward like an hourglass and convex is an outward curve like a football
Explanation:
hope this helps