Answer:
V₂ = 0.0016 m³ = 1.6 L
Explanation:
The work done by the system against a constant external pressure is given by:
W = PΔV
W = P(V₂ - V₁)
V₂ = (W/P) + V₁
where,
W = Work done by the piston = 217 J
P = Constant External Pressure = (1.5 atm)(101325 Pa/ 1 atm) = 151988 Pa
V₁ = Initial Volume = (0.15 L)(0.001 m³/1 L) = 0.00015 m³
Therefore,
V₂ = (217 J/151988 Pa) + 0.00015 m³
V₂ = 0.0016 m³ = 1.6 L
In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright fringe on a flat screen is 0.0176 m, when the light has a wavelength of 425 nm. Assume that the angles are small enough so that is approximately equal to . Find the separation y when the light has a wavelength of 614 nm.
Answer:
Y = 0.0254 m = 25.4 mm
Explanation:
The formula for the fringe spacing in Young's Double-slit experiment is given by the following formula:
\(Y = \frac{\lambda L}{d}\)
where,
Y = fringe spacing = 0.0176 m
λ = wavelength = 425 nm = 4.25 x 10⁻⁷ m
L = Distance between screen and slits
d = slit separation
Therefore,
\(\frac{0.0176\ m}{4.25\ x\ 10^{-7}\ m} = \frac{L}{d}\\\\\frac{L}{d} = 41411.76\)
Now, for:
λ = 614 nm = 6.14 x 10⁻⁷ m
\(Y = (6.14\ x\ 10^{-7}\ m)(41411.76)\\\)
Y = 0.0254 m = 25.4 mm
Consider different combinations of the Big Five, such as O (Low), C (High), E (Low), A (High), and N (Low). What would this person be like? Do you know anyone who is like this? Can you select politicians, movie stars, and other famous people and rate them on the Big Five?
The correct answer is The Big Five personality traits are Openness, Conscientiousness, Extraversion, Agreeableness, and Neuroticism. Each trait can be categorized as either high or low, resulting in 32 different combinations of the Big Five.
The combination of Low Openness, High Conscientiousness, Low Extraversion, High Agreeableness, and Low Neuroticism would suggest a person who is practical, detail-oriented, reserved, cooperative, and emotionally stable. While it is possible to speculate about how a person with this personality profile might behave in various situations, it is important to note that personality traits are not deterministic, and many other factors (such as culture, upbringing, and life experiences) can shape an individual's behavior. It is possible to rate politicians, movie stars, and other famous people on the Big Five using self-report questionnaires, behavioral observations, and other methods. However, it is important to keep in mind that such ratings may be influenced by personal biases and perceptions, and should be interpreted with caution. Additionally, the accuracy of such ratings depends on the quality and validity of the assessment tools used, as well as the rater's expertise and training in personality assessment.
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Guys please help. I need this question
Astronomers estimate that comet Hale-Bopp lost mass at a rate of
350,000 kg/s during it 100 day closest approach to the Sun. Estimate the total mass lost during that time? What fraction is that of the total mass of the comet (5 x 1015 kg)
Total mass lost by the comet is 30.24 x 10¹⁰ kg.
Rate at which mass is lost, R = 35 x 10⁴ kg/s
Time period, T = 100 days = 8.64 x 10⁶s
Therefore,
Total mass lost by the comet, m = R x T
m = 30.24 x 10¹⁰ kg
So,
The fraction of loss = (30.24 x 10¹⁰)/(5 x 10¹⁵) = 60.48 x 10⁻⁵
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What happen when the rest of the container is filled with water?
Answer:
the water will float over mercury and the steel ball will be in it's respected place
please help me out with this
The current flowing through the 1Ω resistor in the circuit is 0.66 A.
The emf of the cells, V = 1.1 V
Internal resistance of the cells, r = Ω
Resistance across the circuit, R = 1 Ω
According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.
According to Kirchoff's current law,
(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1
3/2(1.1 - V') = V'
3.3 - 3V' = 2V'
5V' = 3.3
Therefore, the terminal velocity of the battery is,
V' = 3.3/5
V' = 0.66 V
Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,
I = V'/R
I = 0.66/1
I = 0.66 A
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An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pipe diameter is 8.8 cm is 2.4 m/s. Calculate the flow speed at a location where the diameter has narrowed to 5.80 cm
Answer:
The value is \(v_2 = 5.53 \ m /s\)
Explanation:
From the question we are told
The pipe diameter at location 1 is \(d = 8.8 \ cm = \frac{8.8 }{10} = 0.88 \ m\)
The velocity at location 1 is \(v_1 = 2.4 \ m /s\)
The diameter at location 2 is \(d_2 = 5.80 \ cm = 0.58 \ m\)
Generally the area at location 1 is
\(A_1 = \pi * \frac{d^2}{ 2}\)
=> \(A_1 = \pi * \frac{0.88^2}{ 2}\)
=> \(A_1 = 3.142 * \frac{0.88^2}{ 2}\)
=> \(A_1 = 1.2166 \ m^2\)
Generally the area at location 1 is
\(A_2 = \pi * \frac{d_1^2}{ 2}\)
=> \(A_2 = \pi * \frac{0.58^2}{ 2}\)
=> \(A_2 = 0.528 \ m^2\)
Generally from continuity equation we have that
\(A_1 * v_1 = A_2 * v_2\)
=> \(1.2166 * 2.4 = 0.528 * v_2\)
=> \(1.2166 * 2.4 = 0.528 * v_2\)
=> \(v_2 = 5.53 \ m /s\)
The Italian greyhound jumps 0.85 m in the air to catch a frisbee. How much potential energy does the dog have at the height of its jump?
Answer:
U = 41.65 J
Explanation:
We have just to calculate it with the following expression of gravitational potential energy:
U = m*g*h
Where:
m: mass
g: gravity acceleration;
h: height.
So:
U = m * 9.8 * 0.85
U = 8.33 * m
Then, it is just putting the mass value of the dog in that equation to obtain the value of potential energy acquired by the dog when jumping.
The mass of this kind of dog is between 3.6kg - 5kg, so, the maximum value of the potential energy can be like this:
U = 5 * 9.8 * 0.85
U = 41.65 J
Which measurement is used to determine if an object has balanced forces
Answer:
a spring scale
Explanation:
i think it is correct
An aircraft is flying south west at 250 m/s. There is a crosswind due East at 75m/s.
a) Draw the vector diagram and the resultant vector.
b) Calculate the magnitude of the resultant vector.
c) Calculate the angle to the resultant.
d) State the magnitude and direction of the resultant vector.
A) These vectors should be drawn with the appropriate scale and labeled. The resulting vector is obtained by adding the two vectors head-to-tail. The tail of the crosswind vector should be connected to the head of the aircraft velocity vector.
B) R ≈ √68125 m/s ≈ 260.98 m/s
C)θ ≈ arctan(0.3)
θ ≈ 16.7°
D)The magnitude of the resultant vector is approximately 260.98 m/s. The direction of the resultant vector is approximately 16.7° south of west.
a) To draw the vector diagram, we represent the velocity of the aircraft as a vector pointing southwest with a magnitude of 250 m/s. We also represent the crosswind as a vector pointing east with a magnitude of 75 m/s. These vectors should be drawn with the appropriate scale and labeled. The resulting vector is obtained by adding the two vectors head-to-tail. The tail of the crosswind vector should be connected to the head of the aircraft velocity vector. The resulting vector represents the resultant velocity.
b) To calculate the magnitude of the resultant vector, we can use the Pythagorean theorem. Let's denote the magnitude of the resultant vector as R. The magnitude of the aircraft velocity vector is 250 m/s, and the magnitude of the crosswind vector is 75 m/s. Therefore,
R^2 = (250 m/s)^2 + (75 m/s)^2
R^2 = 62500 m^2/s^2 + 5625 m^2/s^2
R^2 = 68125 m^2/s^2
Taking the square root of both sides, we find:
R ≈ √68125 m/s ≈ 260.98 m/s
c) To calculate the angle to the resultant, we can use trigonometry. Let's denote the angle between the resultant vector and the southwest direction as θ. We can use the inverse tangent function:
tan(θ) = (75 m/s) / (250 m/s)
θ ≈ arctan(0.3)
θ ≈ 16.7°
d) The magnitude of the resultant vector is approximately 260.98 m/s. The direction of the resultant vector is approximately 16.7° south of west.
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Even though the sun is made of ionized gas, it stays the same size because the inward force of gravity is the same strength as the outward pressure force caused by fusion. What would happen to the size of the sun if the outward force increased / got stronger?
Hydrostatic equilibrium
Question 2 options:
The sun would shrink
The sun would expand / grow
The sun would stay the same size
The sun would invade Chuck Norris's personal space and receive a roundhouse kick.
Answer:
The sun would Expand/Grow
Explanation:
if gravity decreased the suns gasses would be more free to move away from the sun so hence that is the reason
Particles q1 =+9.33 uC, q2 =+4.22 uC, and q3=-8.42 uC are in a line. Particles q1 and q2 are separated by 0.180 m and particles q2 and q3 are separated by 0.230 m. What is the net force on particle q2?
The net force on q₂ will be 1.07 x 10⁻² N, pointing to the left.
To find the net force on particle q₂, we need to calculate the force due to q₁ and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:
F = k × (q₁ × q₂) / r²
where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
The force due to q₁ on q₂ can be calculated as:
F₁ = k × (q₁ × q₂) / r₁²
where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).
Similarly, the force due to q₃ on q₂ can be calculated as:
F₂ = k × (q₃ × q₂) / r₃²
where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).
The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.
To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:
Fnet = F₁ - F₃
Substituting the values we get:
Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²
Plugging in the values we get:
Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]
Fnet = 1.07 x 10⁻² N
Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.
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Someone tries to tell you that a freezer cools food by transferring cold to the particles in the food. (has to be 1 sentence)
How would you respond? Construct an argument.
am in 8th grade
pls explain as well bc I’m like rlly slow
Freezing keeps food safe by slowing the movement of molecules, causing microbes to enter a dormant stage. Freezing preserves food for extended periods because it prevents the growth of microorganisms that cause both food spoilage and foodborne illness.
What is freezing food?
Food is preserved when frozen, keeping it fresh from preparation until consumption.Farmers, fishers, and trappers have traditionally stored their produce and grains over the winter months in unheated structures.By turning any remaining moisture in food into ice, freezing it slows the breakdown process and prevents the majority of bacterial species from proliferating.Mechanical and cryogenic techniques are used in the food commodities industry (or flash freezing).To maintain the food's flavour and texture, freezing kinetics is crucial. Smaller ice crystals are produced more quickly, preserving cellular structure.To know more about the freezing food, click the link given below:
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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9. Which of these tissues hold bones together at movable joints? O ligaments O cartilage O tendons O disks
Answer:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Explanation:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Answer:
The answer is ligaments!
Explanation:
Hope this helps!! :)
A radio is rated as 50 W. Calculate the energy transferred in Joules by the radio when it has been switched on for 2 minutes?
The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.
Energy transferPower is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:
Power = Energy transferred / Time
Rearranging the equation to solve for energy transferred, we get:
Energy transferred = Power x Time
We are given:
Power = 50 W
Time = 2 minutes = 120 seconds
Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:
Energy transferred = Power x Time = 50 W x 120 s = 6000 J
In other words, the energy transferred by the radio is 6000 Joules.
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choose an answer / escoger una contestación
Answer:
=0.000367g [La respuesta es ]
Explanation:
If a quarterback gets hit by a defensive lineman with a mass of 100 kg and accelerating at a rate of 1m/s2 at what force is the quarterback getting hit?
The quarterback is getting hit with a force of 100 Newtons.
How to calculate the force with which the quarterback is getting hit
We can use Newton's second law of motion:
Force = Mass * Acceleration
Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:
Force = 100 kg * 1 m/s²
Force = 100 N
Therefore, the quarterback is getting hit with a force of 100 Newtons.
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if you lift an apple from the ground to some point above the ground, the gravitational potential energy in the system increases
(b) Calculate the force required to topple a
person of mass 70 kg, standing with his feet
spread 0.9 m apart as shown in figure. Assume
the person does not slide and the weight of
the person is equally distributed on both feet.
Nora notices water droplets on the grass in the morning. It did not rain during the night. Which statement is true about this change of state?
Mass was added to the water particles, resulting in deposition.
Energy was added to the water particles, resulting in evaporation.
Mass was removed from the water particles, resulting in sublimation.
Energy was removed from the water particles, resulting in condensation.
Answer:
Mass was added to the water particles, resulting in deposition.
Explanation:
Answer: The energy was removed from the water particles resulting in condensation
Explanation Think about when you leave a cup of ice of and after a while you see water droplets thats what happened to the grass in the morning and thats called condensation.
A ball is projected at an angle of 30° above the horizontal with a speed of 35 m/s. What will be its approximate horizontal range across a level surface?
37.5 m will be its approximate horizontal range across a level surface.
we have given in the data
u (initial velocity) = 35 m/s
projected angle = 30°
Horizontal range =?
range of horizontal distance\(=\frac{u^2 Sin 2 \theta}g\)
PUTTING all the values in the equation
horizontal range= \(\frac{35\cdot35\cdot sin60}{9.8}\)
by solving, we got
horizontal range=37.5 m
The horizontal distance traversed is the projectile's range,The thing moves in one direction until it hits the ground.When an item is hurled at an angle of 90°, only vertical motion occurs. As a result, the projectile's range will be zero.horizontal range variates with angle, initial velocity, and by the value of g.To know more about horizontal range visit : https://brainly.com/question/23827445
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You are given two vectors A⃗ =−3.00i^+5.00j^ and B⃗ =7.00i^+2.00j^. Let counterclockwise angles be positive.
a)What angle θA, where 0∘≤θA<360∘, does A⃗ make with the +x-axis?
Express your answer in degrees.
b)What angle θB, where 0∘≤θB<360∘, does B⃗ make with the +x-axis?
Express your answer in degrees.
c)Vector C⃗ is the sum of A⃗ and B⃗ , so C⃗ =A⃗ +B⃗ . What angle θC, where 0∘≤θC<360∘, does C⃗ make with the +x-axis?
Express your answer in degrees.
Answer:
Explanation:
We can subtract directly the corresponding components and check using the parallelogram rule.
Explanation:
Have a look:
enter image source here
Where, graphically, I used the fact that:
→
A
−
→
B
=
→
A
+
(
−
→
B
)
For the magnitude we use Pythagoras (with the components) to get:
∣
∣
∣
→
A
−
→
B
∣
∣
∣
=
√
(
−
1
)
2
+
(
5
)
2
=
√
1
+
25
=
√
26
≈
5.1
For the direction I can see that will be
90
∘
from the
x
axis up to the
y
axis, plus the little bit passed the
y
axis given as:
θ
=
arctan
(
1
5
)
=
11.3
∘
giving in total: angle
=
90
∘
+
11.3
∘
=
101.3
∘
In a loading a lorry a man lifts boxes each weight 200N through a height of 3.5m.
a). How much work does he do in lifting one box?
b). How much energy is transferred when one box is lifted?
c). If he lifts four boxes per minute at what power is he working?
The work done on the boxes and the energy spent is 700J while the power required to lift 4 boxes per minute is 2.8kW
This work done on an object is the force required to move that object from point A to point B.
Data Given;
Weight (mg) = 200NDistance (s) = 3.5mWork DoneThis is the work done to move the boxes from point A to point B.
\(w = F.s\\F = ma = mg = 200N\\w = 200 * 3.5\\w = 700J\)
The work done to move the object is 700J
EnergyThis is used to calculated the energy used to carry the work done and the formula is given as
\(E = force * displacement\\E = F.s\\E = 200 * 3.5\\E = 700J\)
The energy transferred when he lifts one box is 700J
PowerPower is the rate at which energy is used with respect to time
\(P = E/t\\\)
The energy required to lift 4 boxes in one minutes is
\(700 * 4 = 2800\)
Now we can calculate the power used
\(P = Energy / time\\P = 2800 / 1 \\P = 2800W = 2.8kW\)
The power required to move four boxes in 1 minutes is 2.8kW
From the calculations above, the following was gotten
work done = 700JEnergy = 700JPower = 2800W or 2.8kWLearn more on work done, energy and power here;
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What is the mass of a block of lead that is 30cm by 80cm by 60cm?
Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.
The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.
So, the mass of the block of lead is approximately 1.63 metric tons.
what element is produced when a gold nucleus loses a proton?
Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed
Answer: The scenario violates the second law of thermodynamics.
Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.
Which graph represents a function with direct variation? A coordinate plane with a line passing through (negative 4, 0) and (0, negative 2). A coordinate plane with a line passing through (negative 5, 4) and (0, 3).
Answer:
Answer:
A line passing through the points (-1,-4),(0,0) and (1,4)
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=ky/x=k or y=kxy=kx
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
Verify each case
Part 1) A line passing through the points (-4,0) and (0,-2)
This line not represent a direct variation, because the line not passes through the origin.
Part 2) A line passing through the points (-5,4) and (0,3)
This line not represent a direct variation, because the line not passes through the origin.
Part 3) A line passing through the points (-4,-6) and (0,3)
This line not represent a direct variation, because the line not passes through the origin.
Part 4) A line passing through the points (-1,-4),(0,0) and (1,4)
The line passes through the origin
Find out the value of k
k=y/xk=y/x
For the point (-1,-4)
substitute
k=-4/-1=4k=−4/−1=4
For the point (1,4)
substitute
k=4/1=4k=4/1=4
The linear equation is y=4xy=4x
This line represent a direct variation
A bus in traffic increases its speed from 10km/hr to 23km/hr in 2 minutes. What is the average acceleration of the bus?
The average acceleration of the bus is −6.00 m/s².
What is average acceleration?The definition of average acceleration is the change in velocity per unit of time. Acceleration is measured in squared time-distance units. The word "average" is interpreted as a symbol with a bar over it, therefore "a-bar" stands for average acceleration. Calculating Average Acceleration: The change in velocity is calculated by dividing the end velocity by the initial velocity, then multiplying the result by the change in time. This result is known as the average acceleration (a). a = v t = v f v I t. How quickly an object is travelling in a specific direction is determined by its velocity. In the formula -a=vt=vfv0tft0, where an is average acceleration, v is velocity, and t is time, the average acceleration is the rate at which velocity changes.a = ? ; Δt = 1.50 s ; v1 = 9.00 m/s ; v2 = 0.00m/s
The formula to use in this case is the definition of acceleration stating that the acceleration a = Δv / Δt or a = (v2- v1) / Δt where v2 is the final velocity and v1 is the initial velocity.
Solving for the acceleration a
a = (v2- v1) / Δt
a = (0 - 9.00 m/s) / 1.50 s
a = - 9.00 m/s / 1.50 s
a = −6.00 m/s^2
The average acceleration of the bus is −6.00 m/s^2.
The complete question is,
When a bus comes to a sudden stop to avoid hitting a dog, it slows from 9.00 m/s to 0.00m/s in 1.50 seconds. What is the average acceleration of the bus?
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10. IB challenge question: Two masses hang from a pulley as shown. Calculate the acceleration of the smaller mass. Use 10 for acceleration due to gravity instead of 9.81. (Hint: look at each mass separately, and create a system of equations) I 1kg 3kg
The acceleration on the block of mass 1 kg will be equal to the acceleration due to gravity that is 9.81 m/s².
What is Acceleration?
Acceleration of an object is the rate of change of the velocity of the object with respect to time.
As the string and pulley system is ideal so the tension will be constant throughout the string and thus both of the blocks will move with the same acceleration, suppose the tension is T and the common acceleration is a
Then, 3kg being heavier weight will move downward.
The tension always act towards a direction away from the block.
The net downward force on 3kg block will be (3g − T)
So, the equation of Force will be F = ma or (3g − T)= 3a ...(1)
Similarly, the net upward force on 1kg block will be (T − 1g)
So, the equation of Force will be F = ma or (T − 1g) = 1a ...(2)
By adding both these equations 1 and 2.
We get,
2g = 2a
a = g
Therefore, acceleration on the block of 1 kg will be equal to the acceleration due to gravity that is 9.81m/s².
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