A diver running dives out horizontally from the edge of a vertical cliff and 3.0 s later reaches the water below. How high was the cliff and how far from its base did the diver hit the water?

Answer:

A

Layer E was deposited after the intrusion of C B

Answer:

Power = Work / Time

P = m g h / t = 80 kg * 9.8 m/s^2 * 15 m / 39 s = 320 N m/ s = 392 J / s

= 392 Watts

The magnitude of power the monkey demonstrated is equal to 392 J/S.

To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:

                                              \(P = \frac{m\times g\times d}{t}\)

Thus, applying the values ​​given by the statement we have:

                                          \(P = \frac{80 \times 9.8 \times 15}{30}\)

                                           \(P = 392 J/s\)

So, the power performed by the monkey climbing 15 meters is equal to 392J/s.

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The magnitude of the vector is approximately 35.85 m.

The angle that this vector makes with the positive x-axis is approximately 32 degrees.

To find the magnitude of the vector with components Ax=29 m and Ay=18 m, we use the Pythagorean theorem:

|A| = √(Ax^2 + Ay^2)

|A| = √(29^2 + 18^2)

|A| = √(841 + 324)

|A| = √1165

|A| =  34.13 m

To find the angle that this vector makes with the positive x-axis, we can use the inverse tangent function:

θ = tan^-1(Ay/Ax)

θ = tan^-1(18/29)

θ = 31.82 degrees

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Answer:it’s negative then positive then no correlation I just took the test

Explanation:

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

Answer:

The Great Pyramid of Giza (also known as the Pyramid of Khufu or the Pyramid of Cheops) is the oldest and largest of the pyramids in the Giza pyramid complex bordering present-day Giza in Greater Cairo, Egypt.It is the oldest of the Seven Wonders of the Ancient World, and the only one to remain largely intact.

Explanation:

Explanation:

Given:

v₀ = 30 m/s

v = 0 m/s

a = -7.0 m/s²

Find: t and Δx

v = at + v₀

0 m/s = (-7.0 m/s²) t + 30 m/s

t = 4.3 seconds

v² = v₀² + 2aΔx

(0 m/s)² = (30 m/s)² + 2 (-7.0 m/s²) Δx

Δx = 64 meters

Answer:

#1 - True (touch) charging when electric conductors actually touch one another.

#2. True - electrical charges are conserved (not destroyed)

Answer:

\(\boxed {\boxed {\sf 5 \ meters/second}}\)

Explanation:

Speed is equal to distance over time.

\(s=\frac{d}{t}\)

The distance is 100 meters and the time is 20 seconds.

\(d= 100 \ m \\t= 20 \ s\)

Substitute the values into the formula.

\(s=\frac{100 \ m }{20 \ s}\)

Divide.

\(s= 5 \ m/s\)

Aman's speed is 5 meters per second.

Answer:ok yes

Explanation:yes of course

1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.

2. The bright part of the moon appears bright due to the reflection of sunlight.

Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.

Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.

Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.

Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.

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Answer:

Explanation:

Given parameters:

Electrical energy  = 18J

Quantity of charge Q = 12C

Unknown:

Voltage  = ?

Solution:

The expression of electrical potential energy is given as:

      Electrical potential energy  = \(\frac{1}{2}\) c v²

c is the quantity of charge

v is the voltage

           18  =  \(\frac{1}{2}\)  x 12 x v²  

           18 = 6v²  

              v² = 3  

               v = 1.7v

Answer:

To pinpoint specific locations on Earth

Explanation:

The satellite has a full specific view of a specific area just like other satellites do. Satellites communicate together which also communicates with your GPS to give you an accurate location where you are or where you want to be. That is how satellites are used in GPS.

Hope this helps you out :)

We have a positive test charge and another positive charge.

Since both, the charges are positive they will repel each other.

It means that the direction of the force on the positive test charge will point away from the other positive charge.

If the other charge was negative then the direction would have been towards the other charge since opposite charges attract each other.

The direction of the force on a positive test charge near another positive charge is away from the other charge.

Therefore, we can conclude that the given statement is true.

Answer:

–50.96

Explanation:

The following data were obtained from the question:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =

a = (Vբ – Vᵢ) / t

With the above formula, we can determine how fast the object is traveling after 5 s as follow:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

a = (Vբ – Vᵢ) / t

– 9.8 = (Vբ – 0) / 5.2

– 9.8 = Vբ / 5.2

Cross multiply

Vբ = –9.8 × 5.2

Vբ = –50.96 m/s

Therefore, the object is traveling at

–50.96 m/s

The amount of work done by the gas in the given expansion is 1800 J.

The given parameters;

The amount of work done by the gas in the given expansion is calculated as follows;

W = PΔV

where;

Substitute the given parameters and solve for the work done;

W = 1000(2.4  -  0.6

W = 1800 J

Thus, the amount of work done by the gas in the given expansion is 1800 J.

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These relationships are referred to as the equation of motion.

s = ut + ½at². and v = u + at.

length of the Run way = 1350m

Take of speed of the plane is 90 m/s.

The three equations of motion are as follows:

from equation of motion

s = ut + ½at².

here u =0 a =3 m/s^2 t= 30s

put these values on the above equation

s= 1/2x 3x 30x30= 1350 m

length of the Run way = 1350m

from equation of motion ,

v = u + at.

= 0+ 3x 30 = 90m/s.

Take of speed of the plane is 90 m/s.

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Distance = 1350m, speed = 90m/s

Given:

Initially the Aero plane is at rest. Therefore, initial velocity:

u = 0m/s

Acceleration = 3m/\(s^{2}\)

Time taken = 30 seconds

So according to question, we have to find distance & speed

we know that

s = ut + 1/2a\(t^{2}\)

Putting all the values, we get S = 1350 m

Now to find speed, we know,

\(v^{2} = u^{2} + 2aS\)

Putting all the values,

v = \(\sqrt{8100}\)

v = 90m/s

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Agriculture is the science, the practice of cultivating the soil, art, producing crops, raising livestock, and in varying degrees the preparation and marketing of the resulting products cleared the land to use for agriculture.

This is what I found during my research and I hope this helps. Correct me if I am incorrect! Have a good one.

The y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.

The y component of the vector will be determined from the resultant vector and the x component of the vector.

R² = Y² + X²

Y² = R² - X²

Where;

Y² = 85.2² - 76.4²

Y² = 1,422.08

Y = √1,422.08

Y = 37.7 N

θ = arc tan (Y/X)

θ = arc tan (37.7/76.4)

θ = 26.2⁰

Thus, the y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.

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The velocity of the egg thrown off the tall building just before hitting the ground is 22.41m/s.

The final velocity of the egg can be determined using the third equation of motion;

v² = u² + 2gs

Where v is final velocity, u is initial velocity, s is distance and g is acceleration due to gravity. ( g = 9.8m/s² )

Given the data in the question;

To determine the final velocity of the egg just before hitting the ground, plug the given values into the third equation of motion and solve for v.

v² = u² + 2gs

v² = (3.5)² + ( 2 × 9.8 × 25 )

v² = 12.25 + 490

v² = 502.15

Take the square root of both sides

v = √502.15

v = 22.41m/s

The velocity of the egg thrown off the tall building just before hitting the ground is 22.41m/s.

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The speed of the second marble must be 14.8 m/s so that the two marbles reach the ground at the same time.

The time taken by the first stone to reach the ground is calculated using the formula below:

h = ut + ¹/₂gt²

where:

From the data provided;

h = 30, u = 10m/s, g = 9.8 m/s

30 = 10t  + 0.5 * 9.8t²

30 = 10t + 4.9t²

4.9t² + 10t - 30 = 0

t = 1.65 s

For the second marble, time taken = 1.65 - 0.50

t = 1.15 s

Initial velocity, u will be:

30 = u(1.15)  + 0.5 * 9.8 * 1.15²

1.15u = 30 - 12.96

u = 14.8 m/s

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It will decrease the capacitance. this effect will be produced on a capacitor if the separation between the plates is increased. Hence option D is correct.

The capacity of a capacitor to store electric charge is determined by its capacitance. It is inversely proportional to the gap or distance between the capacitor plates and directly proportional to the area of the capacitor plates.

The capacitance of a capacitor reduces when the distance between the plates is increased. Because of the weaker electric field and decreased capacity to store charge caused by the increased gap between the plates, this happens. The capacitor's capacitance therefore drops.

As stated in option D, a capacitor's capacitance will decrease as the distance between its plates increases.

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Answer:

W = 1413.75 J

Explanation:

It is given that,

Mass of car, m = 650 kg

Initial speed of the car, u = 0.7 m/s

Let a man pushes the car, increasing the speed to 2.2 m/s, v = 2.2 m/s

Let us assume to find the work done by the man. According to the work energy theorem, work done is equal to the change in kinetic energy.

\(W=\dfrac{1}{2}m(v^2-u^2)\\\\W=\dfrac{1}{2}\times 650\times ((2.2)^2-(0.7)^2)\\\\W=1413.75\ J\)

So, the work done by the car is 1413.75 J.

The speed of the object v is 16 m/s.

The mass of the object moving on the horizontal surface is m.

The speed of the object is v m/s.

The coefficient of friction, μ = 0.40

The acceleration due to gravity, g = 10 m/s²

So, the initial velocity is v m/s and the final velocity is 0 m/s.

The total distance traveled by the object is 32 meters.

The formula for force is:

F = ma

Now,

ma = - μmg

a = - μg

a = - 0.40 × 10 = - 4 m/s²

The distance, s = 32 meters

Using the equation of motion,

v² = u² + 2as

0 = v² + 2( - 4 )( 32 )

0 = u² - 256

u² = 256

u = √256 = 16 m/s

Hence, the value of the speed v is 16 m/s.

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Answer:

When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.

Explanation:

Hope it helped =)

The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m

According to the question;

The cannonball is fired straight up at a speed of 25 m/s

Additionally, the cannonball is fired against the force of gravity.

Consequently, the motion is in the opposite direction of the acceleration due to gravity.

From the equation of motion;

At the maximum altitude, V = 0.

The maximum altitude that it will reach is;

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Jupiter is the largest. the closest Jovian planet to the sun is Jupiter and most farthest is  Neptune. moons of Jupiter are Europa, lo, Ganymede, etc. Saturn has an orbital period equal to 29 earth years. Uranus's rotational period is equal to 17h 14m.

In terms of size-

In terms of location-

Jovian planets are generally farther from the sun while terrestrial plants are closer to the sun. therefore Jupiter, Saturn, Uranus, and Neptune are away from the sun whole earth is closer to the sun.

In terms of moons-

Jovian planets have more moons as compared to earth. Jupiter has 53 moon, Uranus has 27 Miranda, ariel ,Oberon) while the earth has one moon.

In terms of the orbital period-

Jovian planets have a longer orbital period than earth as they are further from the sun.

In terms of the rotational period-

The rotational period of the Jovian planet is approximately 10 to 17 hours.

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Answer:

Blood is moved away from the brain

Explanation:

Took the test

Answer:

Below

Explanation:

0-1 sec descends at constant rate from 10 to 6 m

1-2 sec stops at 6m

2-3 sec descends at constant rate to 2 m

3-4 sec stops at 2 m

4-5 sec descends at another constant rate to 0 m