a) Draw a diagram to show the forces acting on the sledge b) Consider mechanical energy to find the coefficient of friction between the sledge and the ground

A) Draw A Diagram To Show The Forces Acting On The Sledge B) Consider Mechanical Energy To Find The Coefficient

Answers

Answer 1

the first image shows the force acting on the sledge

\(\begin{gathered} here\text{ given v}_i=3m\text{/s} \\ v_{f=}12m\text{/s} \\ v_i=velocticy\text{ at the top.} \\ v_f=velocity\text{ at the lower end.} \\ m=10kg \\ h(at\text{ the top\rparen=8m} \\ Hypotenuse(of\text{ the plane\rparen =16m} \\ friction\text{ force = }\mu_kN \\ here\text{ }\mu_k=cofficient\text{ of kinetic friction.} \\ N=Normal\text{ force on the sledge.} \end{gathered}\)\(\begin{gathered} Work\text{ }done\text{ }by\text{ }all\text{ }theforces=Change\text{ }in\text{ }Kinetic\text{ }Energy\text{ \lparen from work energy thorem\rparen} \\ Wg+W_N+Wf=Kf-Ki \\ WhereWg=work\text{ }done\text{ }by\text{ }gravity. \\ W_N=work\text{ }done\text{ }by\text{ }a\text{ }normal\text{ }force. \\ Wf=work\text{ }done\text{ }byfriction \\ Kf=final\text{ }kinetic\text{ }energy \\ Ki=initial\text{ }kinetic\text{ }energy \\ W=\frac{1}{2}mv_f^2-\frac{1}{2}mv^2_i \end{gathered}\)\(\begin{gathered} force\text{ working on the particle} \\ normal\text{ force N perpendicular to the plane in updard direction.} \\ mgsin\theta\text{ perpendicular to the plane in downward direction } \\ since\text{ particle is in the plane so these forces must be equal.} \\ N=mgcos\theta \\ f=\mu_kN\text{ \lparen friction force acting on the sledge antiparallel to the plane\rparen} \\ mgsin\theta\text{ acting on the particle parallel to the plane.} \\ since\text{ the particle is moving downwards along the plane so the force is along } \\ downward. \\ \end{gathered}\)\(\begin{gathered} from\text{ Wg + W}_N\text{ + Wf =Kf – Ki} \\ Wg=mgsin\theta *d \\ W_N=0\text{ \lparen angle between N and d is 90 degree\rparen} \\ Wf=-\mu N*d \\ Wf=-\mu mgcos\theta *d \\ so\text{ from} \\ Wg+W_N+Wf=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 \\ mgsin\theta *d-\mu mgcos\theta *d=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 \\ \lbrace mgsin\theta-\mu mgcos\theta\rbrace *d=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 \\ put\text{ all the values} \\ \lbrace10kg*9.8m\text{/s}^2*sin30\degree-\mu(10kg*9.8m\text{/s}^2*cos30\degree)\rbrace16m=\frac{1}{2}*10kg*12^2(m\text{/s\rparen}^2\text{-}\frac{1}{2}*10kg*3^2(m/s\rparen^2 \\ solve\text{ this equation } \\ \lbrace9.8*\frac{1}{2}-\mu(\frac{9.8}{2}*\sqrt{3})\rbrace16=\frac{144}{2}-\frac{9}{2} \\ \lbrace4.9-\mu(8.48)\rbrace16=67.5 \\ 78.4-\mu *135.68=67.5 \\ \mu *135.68=78.4-67.5 \\ \mu=\frac{10.9}{135.68} \\ \mu=0.08 \end{gathered}\)

so μ=0.08 ( dimensionless quantity)

A) Draw A Diagram To Show The Forces Acting On The Sledge B) Consider Mechanical Energy To Find The Coefficient
A) Draw A Diagram To Show The Forces Acting On The Sledge B) Consider Mechanical Energy To Find The Coefficient

Related Questions

please help PLEASE NOW

Journal prompt to be answered in 2 fully developed paragraphs

Prompt: What are some products (or programs) that you could purchase to help your performance in your current physical activity? How would the product (or program help)? Do you really think it is effective? Use specific examples from your experience.

Answers

You could purchase a fitness tracker to help your performance in your current physical activity.

Fitness tracker would help you in the area of goal setting.

Fitness trackers are effective because they have helped my friends to improve workout routine.

What are some products and programs that do help to physical activity?

Wearable fitness trackers can monitor data like heart rate, number of steps taken, distance traveled, and number of calories burned.

Supplements including protein powders, creatine, and beta-alanine can enhance recovery, muscular growth, and endurance.

Working with a coach or personal trainer can help you attain your fitness objectives by offering personalized training regimens, comments on form and technique, and accountability.

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Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct?

Answers

We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.

Who is a geologist?

A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.

Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.

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The complete question is that:

Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)

A. The rock display with smaller holes shows copper drilling, which is deep underground.

B. The rock display with larger holes shows petroleum drilling, which is deep underground.

C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.

D. The rock display with larger holes shows copper drilling, which is closer to the surface.

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O is

Answers

The point through which this ray will pass, after refraction by the lens is point D.

What is refraction of light?

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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If the ball rebounds with only half the velocity it comes in with, what is the magnitude of the impulse in kg m/s?

Answers

the magnitude of the impulse in kg m/s is equal to 3/2 times the product of the mass of the ball and its initial velocity.

If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?
OA.50
B. 320 C
O c. 40 c
OD. 8C
Reset Selection

Answers

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

Given the following the details;

Energy = 40 JoulesElectric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

\(Quantity \; of \; charge = \frac{Energy}{Electric \; potential}\)

Substituting the values into the formula, we have;

\(Quantity \; of \; charge = \frac{40}{8}\)

Quantity of charge = 5 Coulombs

Therefore, the quantity of charge must be 5 Coulombs.

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Energy=E=40JPotential difference=V=8VCharge=Q

\(\boxed{\sf E=QV}\)

\(\\ \rm\longmapsto Q=\dfrac{E}{V}\)

\(\\ \rm\longmapsto Q=\dfrac{40}{8}\)

\(\\ \rm\longmapsto Q=5C\)

Hence total charge must be 5C.

Note:-

SI unit of charge is Coulomb (C)

I need help with this question

I need help with this question

Answers

Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

A room of volume 33 m³ contains air having
an average molar mass of 43.5 g/mol.
If the temperature of the room is raised
from 16.4°C to 25°C, what mass of air will
leave the room? Assume that the air pressure
in the room is maintained at 121.8 kPa.
Answer in units of kg.

Answers

The mass of air that will leave the room is 2.1 kg.

What is the number of moles of air in the room?

The number of moles of air in the room is calculated by applying Ideal gas law as shown below.

PV = nRT

where;

P is the pressure of the roomV is the volume of the air = 33m³ = 33,000 Ln is the number of moles of the airR is ideal gas constant = 8.314 kPa.L/K.molT is temperature of the room

When the temperature =  25⁰C = 298 K

n = PV / RT

n = (121.8 x 33,000) / (8.314 x 298)

n = 1,622.3 moles

when  the temperature =  16.4⁰C = 289.4 K

n = PV / RT

n = (121.8 x 33,000) / (8.314 x 289.4)

n = 1,670.5 moles

difference in number of moles = 1,670.5 moles - 1,622.3 moles = 48.22 moles

mass of the air that will leave the room = 43.5 g/mol x 48.22 moles = 2,097.73 g = 2.1 kg

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A mom pushes her 19.3 kg daughter on the swing. If she gives her an initial velocity of 7.5 m/s at the bottom of the swing and the swing sits 0.6 m above the ground at it's lowest point, what height does she reach above the ground?

Answers

Answer:

3.17333333333? I hope I get it right

Explanation:

..................hello

Physics question URGENT PLEASE!!!

Physics question URGENT PLEASE!!!

Answers

\(\left(95\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{231}{1.00}\dfrac{\mathrm{in}^3}{\rm gal}\right)\left(\dfrac{1.0}{12}\dfrac{\rm ft}{\rm in}\right)^3\left(\dfrac{1.0}{60}\dfrac{\rm min}{\rm s}\right)\approx0.211661\dfrac{\mathrm{ft}^3}{\rm s}\)

Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.

What does democratized knowledge mean?
A. People decide together what information the public needs to
know
B. Everyone has a right to own a computer with Internet access.
C. Everyone can vote to determine what knowledge should be
shared.
D. Everyone has equal access to knowledge that they can also
contribute to

Answers

I think it’s A I got that off the information I got in the internet

Answer:

d

Explanation:

The democratization of knowledge is the acquisition and spread of knowledge amongst a wider part of the population, not just privileged elites such as clergy and academics.

What role does a resistor play in an electrical circuit? A. it removes excess electrons from the outer surface of a conducting wire. B. it transforms light energy and thermal energy into electrical energy. C. it transforms the electrical energy of the electrons into other forms of energy. D. it stores electrical energy until it can be released by closing a switch

Answers

Answer:

It transforms the electrical energy of the electrons into other forms of energy.

Explanation:

Just took the quiz

Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

Answers

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Which statement about technology is true?
Technology improves a scientist’s ability to make observations.
Technology does not have any effect on a scientist’s work.
Technology is necessary for scientists to perform experiments.
Technology only helps scientists analyze data and write reports.

Answers

Answer:

Technology improves a scientist’s ability to make observation

hope this helps

:D

Answer:

Technology improves a scientist’s ability to make observations.

Explanation:

What is the difference between classical mechanics and quantum mechanics?

Answers

Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.

~~~Harsha~~~

the main difference between classical mechanics and quantum mechanics lies in how they describe the behavior of objects.

classical mechanics is the branch of physics that deals with the motion of everyday objects like balls, cars, and planets.

quantum mechanics is a branch of physics that focuses on the behavior of very small particles, such as atoms and subatomic particles like electrons.

A sample of unknown material weight 900N In air and and 400N when submerged in an alcohol solution with a density of 0.7 g/cm³.What is the density of the material ?

Answers

1.26 g/cm³

Explanation

Step 1

given

\(\begin{gathered} F_{g(air)}=900\text{ N} \\ F_{g(alchodol)}=400\text{ N} \\ \rho_{alcohol}=0.7\text{ }\frac{g}{cm^3} \end{gathered}\)

unknown; the density of the material, so

\(\begin{gathered} F_B=F_{g(air)}-F_{g(alcohol)} \\ F_B=900\text{ N-400 N=500 N} \end{gathered}\)

so, the proportion is

the ratio of the force equals the ratio of the density ,so

\(\begin{gathered} \frac{F_{g(air)}}{F_B}=\frac{\rho_{material}}{\rho_{alcholol}} \\ replace \\ \frac{900\text{ N}}{500\text{ N}}=\frac{\rho_{material}}{0.7\text{ }\frac{g}{cm^3}} \\ mutliply\text{ both sides by 0.7}\frac{g}{cm^3} \\ \frac{900\text{N}}{500\text{N}}*0.7\text{ }\frac{g}{cm^3}=\frac{\rho_{mater\imaginaryI al}}{0.7\text{\frac{g}{cm^{3}}}}*0.7\frac{g}{cm^3} \\ 1.26\frac{g}{cm^3}=\text{ density of the material } \\ \end{gathered}\)

so, the density of the material is

1.26 g/cm³

I hope this helps you

A sample of unknown material weight 900N In air and and 400N when submerged in an alcohol solution with

A battery is connected to an electrical circuit. During each second, 2.3 coulombs of charge pass through the battery when the switch is closed. The battery supplies energy to each coulomb of charge at a rate of 4.2J C^-1. Take 1 C = 6.24 x 10^18 electrons
State the potential difference across the battery

Answers

Answer:

The potential difference across the battery can be calculated using the equation:

Potential difference (V) = Energy supplied (J) / Charge (C)

Energy supplied during each second = 2.3 coulombs * 4.2 J/C = 9.66 J

Therefore, the potential difference across the battery would be:

Potential difference (V) = 9.66 J / 2.3 C = 4.2 V

So the potential difference across the battery is 4.2 volts.

A train slows down as it rounds a sharp horizontal turn, going from 96.0 km/h to 52.0 km/h in the 16.0 s that it takes to round the bend. The radius of the curve is 160 m. Compute the acceleration at the moment the train speed reaches 52.0 km/h. Assume the train continues to slow down at this time at the same rate.
magnitude : m/s2
direction:
° backward (behind the radial line pointing inward)

Answers

The direction of the acceleration at the moment the train speed reaches 52.0 km/h is backward (behind the radial line pointing inward).

What does negative sign indicates?

The negative sign indicates that the acceleration is in the opposite direction to the motion of the train. Since the train is moving in a circular path, the direction of the acceleration is towards the center of the circle, which is inward.

\(v^2 = u^2 + 2as\)

where:

u = initial velocity = 96.0 km/h = 26.67 m/s

v = final velocity = 52.0 km/h = 14.44 m/s

s = distance traveled around the bend = circumference of the circle = 2πr = 2π(160 m) = 1005.31 m

\(a = (v^2 - u^2) / (2s)\\= ((14.44 m/s)^2 - (26.67 m/s)^2) / (2 * 1005.31 m)\\= -0.56 m/s^2\)

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can you help me? please

Answers

Answer
Yes i will help u!

An object traveling at a constant
angular speed requires 4.0 seconds
to make one complete revolution.
What is its angular speed?
rad
S

Answers

Answer:

pi / 2  radians / s

Explanation:

One revolution = 2 pi Radians    in 4 seconds

2 pi  /  4   =   pi/2   radians / s

If magma is defined as molten rock material,do you need to melt rocks to form magma?

Answers

Explanation: Magma is molten rock found below the earth's surface. ... On the other hand, if the rocks are under greater pressure, they will require higher temperatures to melt. Melting of rocks typically occurs in the lower lithosphere or upper asthenosphere. The earth gets hot pretty quickly as you dig down from the earth's surface.

What is the average velocity of a car that travels 120 km in 3.5 hours?

Answers

Answer:

34.29 km/hr

Explanation:

Looking for km/hr

  so plug in the values given   120 km / 3.5 hr = 34 .29 km / hr  

                                                                                       ( 34  2/7 km/hr)

What energy transformation is performed by a radio?
A. Sound energy to gravitational potential energy.
B. Electrical energy to sound energy
C. Kinetic energy to electrical energy
O D. Chemical energy to nuclear energy
SUBMIT

Answers

Answer:

B) Electrical energy to sound energy.

Explanation:

hope this helps.


When you drop a 0.37 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s² to-
ward the earth's surface. According to New-
ton's third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 x 10²4 kg, what
is the magnitude of the earth's acceleration
toward the apple?
Answer in units of m/s².

Answers

The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.

How is this acceleration determined?

The apple weighs m = 0.37 kg.

The apple's speed when it approaches the earth's surface is 9.8 meters per second.

Earth's mass, M, is 5.98 × 1024 kg.

Using Newton's Second Law of Motion, we may now:

The strength of the force exerted by Earth on the apple is,

F = ma

⇒ F = 0.37 × 9.8

⇒ F = 3.626 N

We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.

Therefore, the force exerted by the apple on Earth will be of the following magnitude:

F = 3.626 N

Let "A" be the acceleration of the earth relative to the apple in m/s2.

Thus,

The following will be used to determine how quickly the earth is moving toward the apple:

F = MA

⇒ 3.626 = [5.98 × 10²⁴] × A

⇒ A = 3.626 / [5.98 × 10²⁴]

⇒ A = 0.606 × 10⁻²⁴

A = 6.06 × 10⁻²⁵ m/s²

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Can anyone help me on this? It’s a water cycle.

Can anyone help me on this? Its a water cycle.

Answers

Answer:

The water cycle shows the continuous movement of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow.

Explanation:

Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare to this diagram?
A
Her diagram shows higher wavelengths.
B
Her diagram shows lower wave amplitudes.
С
Her diagram shows lower wave frequencies.
D
Her diagram shows higher wave amplitudes.

HELPPPP MEEE PLEASEEEE 55 POINTS!!!

Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare

Answers

Skansen ah w very video ne lol lay

How do first impressions help us form schemas?

Answers

Answer:

i dont know im so sorry for making you feel like you

Explanation:

i dont know im so sorry for making you feel like you

A man weighing 980 n on earth

Answers

Answer:

91.84kg

Explanation:

91.84KG is the answer :) -sorry if i am late-
I Hope That Could Help !


A cyclist bikes with an average velocity of 20 m/s for 5 seconds.

What is the magnitude of the cyclist's displacement?
Your answer should have one significant figure.

Answers

Explanation:

v = s/t

20 = s/5

100 = s

s = 100 = 1 × 10².

When a cyclist bikes with an average velocity of 20 m/s for 5 seconds, the magnitude of the cyclist displacement would be 1×10² meters.

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.

The mathematical expression for velocity is given by the formula

velocity= total displacement/Total time

The area under the velocity-time graph represents the total displacement covered by the object while the slope of the velocity time graph represents the acceleration of the object.

For the given problem when a cyclist bikes with an average velocity of 20 m/s for 5 seconds,

Displacement =velocity×time

                       =20×5

                       =1×10²

The magnitude of the cyclist's displacement is 1×10²

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compare the times of all sunsets during the same period what do you observe​

Answers

Answer:

Theres no given?

Explanation:

Well, whatever.

I observed the shift of their sunset time.

Examples like:

January to June = their sunset time increased while

July to December = their sunset time decreased

Do you think Kepler will be able to detect Earth-sized planets in transit?

Answers

Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.

Explanation:

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