A flow of 68°F air develops in a flat horizontal duct following a well-rounded entrance section. The duct height is H = 1 ft. Turbu- lent boundary layers grow on the duct walls, but the flow is not yetfully developed. Assume that the velocity profile in each boundarylayer is u/U = (v/8)'/7. The inlet flow is uniform at V = 40 ft/s atsection D. At section 2, the boundary-layer thickness on each wall of the channel is 82 = 4 in. Show that, for this flow, 8* = 8/8. Eval-uate the static gage pressure at section O. Find the average wall shearstress between the entrance and section 2, located at L = 20 ft.

(a) The machine's average hourly production rate without considering availability is 6.02 parts/hr.

(b) The machine's average hourly production rate, taking into account availability, is 6.17 parts/hr.

(c) The machine's average hourly production rate when only available during run time is 5.71 parts/hr.

(a) To calculate the average hourly production rate of the machine without considering availability, we need to first calculate the total time it takes to produce a batch of 52 parts.

Total time = (setup time) + (operation time per part x batch size)

Total time = 5.0 hr + (4.2 min/part x 52 parts)/60 min/hr

Total time = 5.0 hr + 3.64 hr

Total time = 8.64 hr

Average hourly production rate = Batch size / Total time

Average hourly production rate = 52 parts / 8.64 hr

Average hourly production rate = 6.02 parts/hr

Therefore, the average hourly production rate of the machine without considering availability is 6.02 parts/hr.

(b) To calculate the average hourly production rate of the machine taking into account availability, we need to first calculate the machine's availability using the mean time between failures (MTBF) and mean time to repair (MTTR) values.

Availability = MTBF / (MTBF + MTTR)

Availability = 37 hr / (37 hr + 0.92 hr)

Availability = 0.975 or 97.5%

Now we can calculate the total time that the machine is available for production:

Available time = Total time x Availability

Available time = 8.64 hr x 0.975

Available time = 8.42 hr

Average hourly production rate = Batch size / Available time

Average hourly production rate = 52 parts / 8.42 hr

Average hourly production rate = 6.17 parts/hr

Therefore, the average hourly production rate of the machine taking into account availability is 6.17 parts/hr.

(c) If availability only applies during the actual run time of the machine and not the setup time, we need to adjust the available time calculation:

Available time = (operation time per part x batch size) / 60 min/hr x Availability

Available time = (4.2 min/part x 52 parts) / 60 min/hr x 0.975

Available time = 4.11 hr

Total time = Available time + setup time

Total time = 4.11 hr + 5.0 hr

Total time = 9.11 hr

Average hourly production rate = Batch size / Total time

Average hourly production rate = 52 parts / 9.11 hr

Average hourly production rate = 5.71 parts/hr

Therefore, the average hourly production rate of the machine taking into account availability only during run time is 5.71 parts/hr.

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This question uses the theory of volume, which states that the volume of an object is the product of its width, depth, and height. The volume of the wood board is 221.25 cubic inches.

What is the volume of an object?

Volume is a measure of the amount of three-dimensional space a substance or object occupies. It is the amount of space that an object or substance occupies, or that is enclosed within a container. It is usually expressed in cubic units, such as liters (L), cubic centimeters (cm3), or cubic meters (m3). The basic formula for calculating the volume of a three-dimensional shape is length x width x height. This formula can be used to calculate the volume of a cube, rectangular prism, cylinder, or other three-dimensional shape.

The steps for the answer as follows:

Step 1: Calculate the volume of the board. This is done by multiplying the width, depth and height of the board together.

Step 2: The width, depth, and height of the board are 7.5, 14, and 1.75 inches, respectively.

Therefore, the volume of the board is 7.5 x 14 x 1.75 = 221.25 cubic inches.

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When designing a new material for use in an airplane body, the material should have the following properties:

High strength-to-weight ratio: The material should have high strength-to-weight ratio because the weight of the airplane body should be reduced so that it can fly easily. High stiffness: The material should have high stiffness because it should resist the forces acting on it. Low density: The material should have low density because the weight of the airplane body should be reduced so that it can fly easily. Corrosion-resistant: The material should be corrosion-resistant because it should resist corrosion by exposure to the atmosphere. High fatigue strength: The material should have high fatigue strength because it should resist the forces acting on it.

Fatigue strength is the maximum stress that can be applied to a material without causing it to break. The above properties are crucial when designing a new material for use in an airplane body.

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Yes, one pound-force is the force required to accelerate a mass of 32.174 lbm by 9.807 ft/s2.

This is the gravitational acceleration at sea level, which is the acceleration due to gravity. This means that a mass of 1 lbm will weigh 1 lbf if it is placed at sea level.

The force of gravity is the result of an attractive force between two objects, which is proportional to the mass of both objects and inversely proportional to the square of the distance between them. This means that the greater the mass of an object, the greater the force of gravity it will experience.

Therefore, the mass of 1 lbm will experience a force of gravity of 1 lbf when placed at sea level. This is why the weight of an object is typically measured in units of pounds.

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Answer:

B. finding and fixing a problem

Explanation: is correct on edge2020

Please hit that thanks button below and mark brainliest if possible

The number of televisions per capital is calculated by dividing the number of television sets by the total US population. In this case, we divide the 285 million television sets by the population of 298.4 million.

This gives a result of 0.9551 televisions per capita. Note that this method (dividing the number by the population) also is used for calculating the per capita of many other things like GDP.

In this case, we divide the 285 million television sets by the population of 298.4 million. This gives a result of 0.9551 televisions per capita.

Therefore, The number of televisions per capital is calculated by dividing the number of television sets by the total US population. In this case, we divide the 285 million television sets by the population of 298.4 million.

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The torque needed. Ignore the mass of the arm is 26.86 L Nm . The force that must be exerted by the triceps muscle is 26.86 L/s N.

Torque is defined as a measurement of the rotational force that can be applied to an object.

The cross-product of the force and forearm length is torque.τ

τf = F × L

τf = (ma)Lsinθ

τf = (ma)L

Plugging in the given values:

τf = m a L

τf = (3.4 kg) (7.9 m/s2) × L

τf = 26.86 L Nm

The elbow rotates as a result of the triceps. The forearm must have the same amount of torque as the triceps in order for the triceps force to act on the forearm.

Assuming the elbow's length to be s:

τt = τf

Ft s = τf

Ft = τ f s

Ft = 26.86 Ls N

Hence, the required torque. Ignore the arm's mass of 26.86 L Nm. The triceps muscle must contract with a force of 26.86 L/s N.

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Unfortunately, you haven't provided the excerpt from the transcript of the interview with the production planner at FoodCo.

Without the specific information from the interview, I am unable to draw a use case diagram or create use case descriptions based on it. To create a use case diagram and use case descriptions, I would need the specific actions, interactions, and functionalities mentioned in the interview.

Please provide the relevant excerpt, and I'll be happy to assist you in creating the use case diagram and descriptions based on that information.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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Explanation:

print() has a variable number of parameters. this is the answer.

hope this helps you

have a nice day

Answer:

20% of the critical value. Determine (a) the damping factor, (b) the

Explanation:

The materials which are possible candidates are brass, stainless steel, aluminum and copper is to be subjected to a tensile load.

Tensile load, also known as tension, is a force applied to an object in order to extend, deform, or disrupt the object. Tensile load is the opposite of compressive load, which compresses or squeezes an object. Tensile load is often used in engineering and material science to measure the strength of a material or object. When a material is subjected to a tensile load, it will stretch and deform until it reaches its breaking point. The amount of force it takes to cause the material to reach its breaking point is known as the tensile strength of the material.

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Answer:

Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang

Answer:

Explanation:

In the development of a torsion formula for a circular shaft, the following assumptions are made: Material of the shaft is homogeneous throughout the length of the shaft. Shaft is straight and of uniform circular cross section over its length. Torsion is constant along the length of the shaft.

Answer:

33.56 ft^3/sec.in

Explanation:

Duration = 6 hours

drainage area = 185 mi^2

constant baseflow = 550 cfs

Derive the unit hydrograph using the inverse procedure

first step : calculate for the volume of direct runoff hydrograph using the details in table 2 attached below

Vdrh = sum of drh *  duration

        = 29700 * 6 hours ( 216000 secs )

        = 641,520,000 ft^3.

next step : Calculate the volume of runoff in equivalent depth

Vdrh / Area = 641,520,000  / 185 mi^2

                    = 1.49 in

Finally derive the unit hydrograph

Unit of hydrograph = drh /  volume of runoff in equivalent depth

                                = 50 ft^3 / 1.49 in  =  33.56 ft^3/sec.in

LEFM predicts an infinite stress at the crack tip, microstructural changes prevent this from occurring in metals, polymers, and ceramics. These changes lead to crack blunting, crack deflection, and stress redistribution, which help to reduce stress concentration and prevent catastrophic failure.

LEFM predicts that there will be an infinite stress at the tip of a crack due to the stress concentration. However, this prediction is not the case due to the microstructural changes that occur in metals, polymers, and ceramics. In metals, the plastic deformation around the crack tip results in crack blunting, which reduces the stress concentration and prevents an infinite stress. In polymers, the highly mobile molecular chains absorb the stress and cause plastic deformation, which also leads to crack blunting. Similarly, ceramics undergo crack deflection due to the presence of grain boundaries and microcracks, which leads to a reduction in stress concentration.

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Answer:

Explanation:

Introduction:

Cryptology, the science of encoding and decoding information, has played a pivotal role in numerous historical incidents, often shaping the outcomes of major events. By providing secure communication and protecting sensitive data, cryptology has been instrumental in military operations, intelligence gathering, and safeguarding confidential information. One such significant incident where cryptology played a key role is the story of the Enigma machine during World War II.

Summary of the Incident:

During World War II, the Enigma machine, a complex encryption device used by the German military, posed a significant challenge to the Allied forces. The Enigma machine encrypted German communications, making it extremely difficult for the Allies to decipher their messages. However, a team of brilliant codebreakers at Bletchley Park, including renowned figures like Alan Turing, successfully cracked the Enigma code, providing invaluable intelligence to the Allies.

The codebreakers at Bletchley Park developed the Bombe machine, a mechanical device that aided in decrypting Enigma-encrypted messages. By exploiting weaknesses in the German encryption practices and employing innovative techniques like cribs and codebreaking algorithms, the codebreakers were able to unravel the Enigma code.

The successful decryption of Enigma messages proved to be a turning point in the war. The Allies gained vital insights into German military strategies, troop movements, and supply routes. This intelligence significantly contributed to key victories, such as the Battle of the Atlantic and the Normandy landings, and ultimately helped the Allies secure victory in World War II.

Conclusion:

The story of the Enigma machine and its decryption stands as a testament to the critical role of cryptology in historical incidents. The codebreakers' efforts at Bletchley Park showcased the power of cryptanalysis and demonstrated the immense impact that breaking an enemy's encryption can have on the outcome of a conflict. The successful decryption of Enigma messages not only provided the Allies with crucial intelligence but also exemplified the importance of cryptology in safeguarding communications and gaining a strategic advantage.

The incident highlights the ongoing significance of cryptology in modern times, where secure communication and protection of sensitive data remain paramount. Cryptology continues to evolve, playing a vital role in areas such as cybersecurity, secure online transactions, and ensuring the confidentiality of sensitive information.

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Aspiring for success in a chosen major such as Mechanical Engineering would require a strong will or zeal to pull through and succeed, which is an ideal psychological prerequisite to success.

Hence, the combination of practical and theoretical knowledge in basic subject coupled with determination should be enough to succeed.

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Answer:

Composite panel garage doors

Explanation:

Engineered lumber should not be used for composite panel garage doors. Hence, option C is correct.

Horizontal panels are connected to form a single garage door in panel lift doors, sometimes referred to as sectional doors. These panels have wheels attached to them that are positioned in tracks on either side and guide the door through a reasonably sharp turn to reposition it horizontally above the garage door opening.

Yes, however it's crucial to have a pro take their place for the finest outcomes. It can be unsafe for anybody other than a professional to install garage doors due to their complexity and difficulty.

One of the most affordable solutions on the market is an aluminum garage door. They are available in a variety of design options that can complement the exterior style of your home. Low-cost aluminum garage doors.

Thus, option C is correct.

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Explanation:

Outer di ameter \(d_{0}=400 \mathrm{mm}\( Thickness of the cylinder \(t=10 \mathrm{mm}\)

\(\therefore\( Inner diam eter \(d_{i}=d_{0}-2 t=400-2 \times 10\)

\(d_{1}=380 \mathrm{mm}\)

Given loading on the cylinder \(P=300 \mathrm{kN}\) Helix an gle of the weld form \(\theta=20^{\circ}\)

(i) Normal stress on the plane at angle \(\theta=20^{\circ}\) is

\(\sigma=\frac{P \cos ^{2} \theta}{A_{0}}\)

\(\text { Where } A_{0}=\frac{\pi}{4}\left(d_{0}^{2}-d_{1}^{2}\right)\)

\(\quad=\frac{\pi}{4}\left(400^{2}-380^{2}\right)\)

\(=12252.21 \mathrm{mm}^{2}\)

\(=12.25221 \times 10^{-9} \mathrm{m}^{2}\)

\(\sigma=\frac{-300 \times 10^{2} \times \cos ^{2} 20}{12.25221 \times 10^{-1}}\)

\(=-21.6 \mathrm{MPa}\)

(ii) Shear stress along an angle of \(\theta=20^{\circ}\) is \(\tau=\frac{P}{A_{0}} \cos \theta \sin \theta\)

\(=\frac{-300 \times 10^{-1} \times \cos 20 \times \sin 20}{12.25221 \times 10^{-3}}\)

\(=-7.86 \mathrm{MPa}\)

The normal and shearing stresses are equal to -21.63 MPa and -7.84 Mpa respectively.

Given the following data:

Conversion:

Mathematically, the normal stress is given by this formula:

\(\sigma = \frac{P}{A} cos^2 \theta\)   ....equation 1.

Where:

Note: The steel pipe is hollow and as such its area would be calculated as that of a disk.

Generally, a disk can be described as a large outer circle with its smaller-inner circle expunged. Thus, the area of a disk is given by:

\(Area = \pi (r_o^2-r_i^2)\)    .....equation 2.

Where:

For the inner radius:

\(r_i = r_o-t\\\\r_i=0.2-0.01\\\\r_i=0.19\;m\)

Substituting the parameters into eqn. 2, we have:

\(Area = 3.142 (0.2^2-0.19^2)\\\\Area = 3.142(0.04-0.0361)\\\\Area = 3.142 \times 0.0039\\\\Area = 0.0123\;m^2\)

For the normal stress:

\(\sigma = \frac{-300 \times 10^3}{0.0123} \times cos^2 20\\\\\sigma =-24.49 \times 10^{6} \times 0.8830\\\\\sigma =-21.63 \times 10^{6}\;Pa\)

Note: 1 MPa = \(1\times 10^6\;Pa\)

Normal stress = -21.63 MPa.

We would derive the formula for shearing stress from the normal stress formula by applying trigonometric functions.

Note: \(sin2 \theta = 2sin \theta cos \theta\)

\(\tau = \frac{P}{A} sin \theta cos \theta\\\\\tau = \sigma \times \frac{sin \theta}{cos \theta}\\\\\tau = \frac{P}{A} cos^2 \theta \times \frac{sin \theta}{cos \theta}\\\\\tau = \frac{P}{2A} sin2\theta\)

Substituting the parameters into the formula, we have;

\(\tau = \frac{-300 \times 10^3}{2 \times 0.0123} \times sin 2(20)\\\\\tau = \frac{-300 \times 10^3}{0.0246} \times sin (40)\\\\\tau = -12.2 \times 10^6 \times 0.6428\\\\\tau = -7.84 \times 10^6\;Pa\)

Note: 1 MPa = \(1\times 10^6\;Pa\)

Shearing stress = -7.84 Mpa.

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Answer:

hello some part of your question is missing ( The table ) attached below is the missing detail related to your question

answer: cumulative infiltration after 30 mins = 6.7

Explanation:

Calculate the cumulative infiltration after 30 min

formula for calculating  cumulative infiltration

= 11( t - tp + t' ) = F - 34.3 In ( 1 + 0.0291 * F )

Attached below is a detailed solution to the problem

The maximum strain of the long rod suspended from one end is 0.008.

The strength or influence that stretches, pulls, or puts pressure on something, sometimes causing damage: The hurricane put such a strain on the bridge that it collapsed. As you get older, excess weight puts a lot of strain on the heart.

The strain is the ratio of the deformation to the total length. Then the formula is given as,

ε = Δ / L

Where 'ε' is the strain, 'Δ' deformation, and 'L' is the original length.

A 100 in. long rod is suspended from one end. The diameter of the rod is 1 in. and the total elongation is 0.80 in.

Then the maximum strain is given as,

ε = 0.80 / 100

ε = 0.008

The maximum strain is 0.008.

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To wrap the text and apply center alignment in a worksheet and change the row height, you have to follow well defined steps, which are mentioned below.

What are the steps to wrap the text and apply center alignment in a worksheet?

In a worksheet, wrap the text, use centre alignment, and change the row height by using these steps:

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Answer: (read explanation)

Explanation:

Symmetry and rigid transformations are related in that symmetry is a type of rigid transformation. A rigid transformation is a type of transformation in geometry in which the shape of an object is preserved after the transformation is applied. This means that the distances between all points on the object remain the same, and the angles between those points are also unchanged.

Symmetry is a specific type of rigid transformation that involves a reflection, rotation, or translation of an object such that the resulting image is congruent to the original. In other words, symmetry is a type of transformation in which an object is mapped onto itself in a way that preserves its shape and size.

For example, if an object has rotational symmetry, it means that it can be rotated by a certain angle and the resulting image will be congruent to the original. If an object has reflectional symmetry, it means that it can be reflected across a certain line and the resulting image will be congruent to the original.

Overall, symmetry is a type of rigid transformation in which an object is mapped onto itself in a way that preserves its shape and size. This type of transformation is related to other types of rigid transformations, such as rotations and translations, which also preserve the shape and size of an object.

wing structures are subject to: Inertial loads of structural mass and non-structural mass, aerodynamic loads, fuel loads, engine loads, landing gear loads, and inertial loads.

Wings are airfoils that produce lift when they are moved quickly through the air. They come in a variety of sizes and forms. Different wing designs might offer specific desirable flight characteristics. Control at various operating speeds, the amount of lift produced, balance, and stability all change as the shape of the wing changes. Either the wing's leading and following edges are straight or curved, or one edge is straight while the other is curved. To make the wing smaller at the tip than at the base, where it joins the fuselage, one or both edges may be tapered. Wing tips can be pointy, rounded, or even square.

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(a) The active part of the inflow expands its cross-section as it passes the tidal turbine due to conservation of mass and energy.

(b) Several reasons contribute to the theoretical maximum efficiency not being achieved in practical tidal turbine deployments, including turbulence, non-uniform flow, and mechanical losses.

(c) Estimating the total fluid loading on the Alstom 1.4 MW OceadeTM turbine requires considering the flow velocity, rotor and tower dimensions, and making assumptions about the flow characteristics and structural properties.

(d) The estimates of forces obtained from the fluid loading calculations are essential for designing the turbine and tower structure by ensuring that they can withstand the anticipated loads and stresses.

(a) The active part of the inflow expands its cross-section as it passes the tidal turbine due to the principle of conservation of mass and energy. As the tidal flow encounters the turbine rotor, some of the kinetic energy of the flow is converted into mechanical energy to drive the turbine. To satisfy the conservation of mass, the cross-sectional area of the flow must increase to compensate for the reduction in flow velocity caused by energy extraction.

(b) Achieving the theoretical maximum efficiency in practical tidal turbine deployments is challenging due to several reasons. First, tidal flows are often characterized by turbulence, which disrupts the uniformity of the flow and reduces overall efficiency. Second, tidal flow itself is not uniformly distributed, and the flow characteristics vary with tidal cycles, further impacting efficiency. Lastly, mechanical losses in the turbine's components, such as friction and resistance, reduce the efficiency of energy conversion.

(c) Estimating the total fluid loading on the Alstom 1.4 MW OceadeTM turbine involves considering the flow velocity, rotor diameter, and tower dimensions. Assuming a tidal flow velocity of 3 m/s, the fluid loading can be estimated by considering the momentum change and forces acting on the rotor and tower surfaces. Assumptions may include a simplified flow model, neglecting factors such as turbulence and non-uniform flow, and assuming a stationary tower. These assumptions simplify the calculation while providing a reasonable estimate of the fluid loading.

(d) The estimates of forces obtained from the fluid loading calculations are crucial for designing the turbine and tower structure. These estimates help engineers determine the required structural strength, material selection, and design considerations to ensure that the turbine and tower can withstand the anticipated fluid forces and mechanical stresses. By considering the estimated forces, designers can optimize the structural integrity, stability, and reliability of the turbine and tower, ensuring safe and efficient operation in tidal environments.

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Answer:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

There are essentially two main types of tables in hive including Managed tables and External  tables.

The two main types of tables in Hive are:-

1. Managed tables: These tables are managed by Hive, and the data is stored in Hive's default file format, which is ORC format. They are physically stored in the Hadoop Distributed File System (HDFS) directory specified by the user. Managed tables are created using the `CREATE TABLE` statement, and they are dropped using the `DROP TABLE` statement.

2. External tables: An external table is a table that is not managed by Hive, and it is linked to data that is stored in a file or directory in HDFS. The data stored in external tables is generally stored in any Hadoop-supported file format, such as ORC, Parquet, CSV, or Avro.

External tables are created using the `CREATE EXTERNAL TABLE` statement, and they are dropped using the `DROP TABLE` statement. Therefore, the two words that can be used to fill in the blanks in the given question are Managed and External.

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The three-phase line voltage is given as 346.41 Vms

The real power drawn from the supply is given as 19.2kW

"Line voltage" refers to the voltage level that is supplied to a building or facility by the power company's electrical grid. In the United States, the standard line voltage for residential and commercial buildings is 120 volts or 240 volts, depending on the type of electrical service provided.

Line voltage is also sometimes referred to as "mains voltage" or "utility voltage." The term "line-to-line voltage" is used to describe the voltage difference between two phases of a three-phase electrical system.

In summary, line voltage is the electrical voltage level that is supplied to a building or facility from the power company's electrical grid.

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