The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately :4.73 L. The correct option is A.
To determine the new volume of a gas when its temperature is changed, we can use Charles' Law. Charles' Law states that the volume of a gas is directly proportional to its temperature, provided that the pressure remains constant. Your initial temperature (T1) is 14°C, and the initial volume (V1) is 4.5 L.
The final temperature (T2) is 29°C, and we need to find the new volume (V2). Remember to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value (T1 = 287.15 K, T2 = 302.15 K).
Using Charles' Law, we have:
V1/T1 = V2/T2
Now, we can plug in the values:
(4.5 L)/(287.15 K) = V2/(302.15 K)
To find V2, multiply both sides by 302.15 K:
V2 = (4.5 L x 302.15 K) / 287.15 K
V2 ≈ 4.73 L
The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately 4.73 L. The correct option is A.
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Complete question:
A gas has a temperature of 14 °C, and a volume of 4. 5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas?
A. 4. 7 L
B. 4. 9 L
C. 5. 3 L
D. 5. 5 L
Two people leave points A and B at the same time. They intend to meet at point C at the same time. The person who leaves point A walks at a speed of 3 miles per hour. You and a friend are trying to determine how fast the person who leaves point B must walk. Your friend claims you need to know the length of . Is your friend correct? Explain your reasoning.
Your friend is correct. In order to determine the speed at which the person who leaves point B must walk, you need to know the length of AC and BC.
This is because the time it takes for each person to reach point C is dependent on the distance they must travel and the speed at which they are traveling.
Using the formula time = distance / speed, you can calculate the time it takes for each person to reach point C.
For the person leaving point A, the time it takes to reach point C is tA = AC / 3, since they are traveling at a speed of 3 miles per hour.
For the person leaving point B, the time it takes to reach point C is tB = BC / x, where x is the speed at which they are traveling.
Since both people are intended to reach point C at the same time, you can set the two equations equal to each other:
AC / 3 = BC / x
Cross-multiplying and solving for x gives you the speed at which the person leaving point B must walk:
x = 3BC / AC
Without knowing the length of AC and BC, you cannot determine the speed at which the person leaving point B must walk. Therefore, your friend is correct.
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a fuel efficent car gets 52.0 miles per gallon how many litres of gas will be required to drive 65.5 kilometres. the density of platinum at room tempreture is 21.45 g/cm3. what is the mass of small bar of platinum measuring 1 ft long 3 inches wife and 1 inch deep.
the denisty of platinum at room temperature is 21.45 g/cm3 what is the mass of the small bar platinum measuring 1 foot long and 3 inches wide and 1 inch deep?
a) The number of liters of gas is 2.955 L
b) The mass of the small bar of platinum is 12.64 kg.
Given data:
a)
To calculate the number of liters of gas required to drive 65.5 kilometers in a car that gets 52.0 miles per gallon, we need to convert both the distance and the fuel efficiency to a consistent unit of measurement.
1 mile is approximately equal to 1.60934 kilometers. Therefore, 65.5 kilometers is approximately equal to 40.68 miles.
Now we can calculate the number of gallons of gas required:
Number of gallons = Distance / Fuel efficiency
Number of gallons = 40.68 miles / 52.0 miles per gallon
Number of gallons ≈ 0.782 gallons
To convert gallons to liters, we use the conversion factor: 1 gallon = 3.78541 liters.
Number of liters = Number of gallons * 3.78541
Number of liters ≈ 0.782 gallons * 3.78541 liters/gallon
Number of liters ≈ 2.955 liters
Therefore, approximately 2.955 liters of gas will be required to drive 65.5 kilometers in the given fuel-efficient car.
b)
Regarding the mass of a small bar of platinum, measuring 1 foot long, 3 inches wide, and 1 inch deep, we need to convert the measurements to a consistent unit (either inches or feet) before calculating the volume and then multiplying it by the density of platinum.
1 foot is equal to 12 inches. Therefore, the dimensions of the bar can be converted to 12 inches long, 3 inches wide, and 1 inch deep.
Volume = Length * Width * Depth
Volume = 12 inches * 3 inches * 1 inch
Volume = 36 cubic inches
To convert cubic inches to cubic centimeters (cm³), we use the conversion factor: 1 cubic inch = 16.3871 cubic centimeters.
Volume = 36 cubic inches * 16.3871 cm³/cubic inch
Volume ≈ 590.3526 cm³
Now we can calculate the mass using the density of platinum:
Mass = Volume * Density
Mass = 590.3526 cm³ * 21.45 g/cm³
Mass ≈ 12637.8697 grams or 12.64 kilograms (rounded to two decimal places)
Hence, the mass of the small bar of platinum measuring 1 foot long, 3 inches wide, and 1 inch deep is approximately 12.64 kilograms.
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A massless spring with spring constant 19.5N / m hangs vertically. A body of mass 0.400 kg is attached to its free end and then released. Assume that the spring was unstretched before the body was released. How far below the initial position does the body Hlescend?
Using this equilibrium condition, we can solve for x: 3.924 N = 19.5 N/m * x, which gives x = 3.924 N / 19.5 N/m ≈ 0.201 m. Therefore, the body descends approximately 0.201 meters below the initial position.
We need to use the equation for the potential energy stored in a spring: U = (1/2)kx^2
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
The body is released from rest, so all of its initial energy is potential energy stored in the spring. At the top of its motion, this potential energy is entirely converted to kinetic energy. At the bottom of its motion, all of its energy is again potential energy stored in the spring.
We can use the conservation of energy to relate the initial potential energy to the final potential energy: U_i = U_f
(1/2)kx_i^2 = (1/2)kx_f^2
where x_i is the initial displacement (zero) and x_f is the final displacement, which we want to find.
Solving for x_f, we get: x_f = sqrt((U_i/k))
We're given the spring constant, k = 19.5 N/m, and the mass of the body, m = 0.400 kg. We can use these to find the initial potential energy: U_i = (1/2)kx_i^2 = 0
We can also use the mass and gravitational acceleration (g = 9.81 m/s^2) to find the weight of the body:
F = mg = (0.400 kg)(9.81 m/s^2) = 3.924 N
Since the spring is hanging vertically, the weight of the body is balanced by the force of the spring:
F_s = 3.924 N
We can use this force and the spring constant to find the final displacement: x_f = sqrt((U_i/k)) = sqrt((F_s^2)/(2k)) = sqrt((3.924 N)^2/(2(19.5 N/m)))
x_f = 0.402 m
Therefore, the body ascends 0.402 m from its initial position.
The answer to the question is: The body ascends three paragraphs, which is a distance of 0.402 m from its initial position. In the initial position, the mass (0.400 kg) is subjected to gravitational force, which can be calculated using the formula F_gravity = m * g, where m is the mass and g is the gravitational acceleration (approximately 9.81 m/s²). Therefore, F_gravity = 0.400 kg * 9.81 m/s² = 3.924 N.
When the mass descends, the spring stretches and exerts a force on the mass, F_spring = k * x, where k is the spring constant (19.5 N/m) and x is the extension of the spring. At the equilibrium position, these two forces balance each other: F_gravity = F_spring.
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Help please answer all if ya can please
Answer:
1. Privacy
-The state or condition of being free from being observed or disturbed by other people.
2. Commitment
-The state or quality of being dedicated to a cause, activity, etc.
3. Profile
-There are multiple answers for this word so I'm not sure which is the one you need.
4. Widow
-A woman who has lost her spouse by death and has not remarried.
5. Aristocrat
-A member of the aristocracy.
6. Affordable
-Inexpensive; reasonably priced.
7. Variable
-A symbol for a value we don't know yet. It is usually a letter like x or y.
Explanation:
how does this experiment help us understand their behavior? stanford prison experiment
This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them
What is Stanford prison experiment ?In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.
Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.
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Find the kinetic energy of a ball of mass 200 grams moving at a speed of 20 m/s.
Answer:
40KJ
Explanation:
m=200g
V=20m/s
Ek=?
Ek=(m*V²)/2
Ek=(200*20²)/2
Ek=(200*400)/2
Ek=80 000/2
Ek=40 000 J =40KJ
Each of the following lists two statements. Which two are the basic premises for the special theory of relativity? A. 1.The laws of nature are the same for everyone.
2.The speed of light is the same for everyone.
B.1.Everything is relative.
2.You can never really tell who is moving.
C.1.The laws of nature are the same for everyone.
2.Everything is relative.
D.1.The speed of light is the same for everyone.
2.You can’t go faster than the speed of light.
C.1. The two basic premises for the special theory of relativity are: The laws of nature are the same for everyone and The speed of light is the same for everyone.
Which one of the following claims best describes the special concept of relativity's fundamental assumptions?The special relativity theory is based on two fundamental tenets: that the light speed should be constant in all inertial frames of reference and that the rules of physics ought to be independent of a uniform motion of such a frame.
In accordance with the special concept of relativity, which are the two universal truths?The separation of two occurrences in space and time, an object's energy momentum, and of course his speed of light are all examples of absolute dimensions of space and time that Einstein also specified.
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- The gravitational force on a 352 kg satellite is -2100 N. Find its
distance from Earth's center.
Answer:
8173.8 km
Explanation:
Fg=G(M*m/r^2)
r=sqrt(G*M*m/Fg)
G=6.6743*10^-11
M(earth)=5.972*10^24kg
M(object)=352kg
Fg=-2100N
r=sqrt((6.6743*10^-11)*(5.972*10^24kg)*(352)/-2100)
r=8173808m
r=8173.8km
According to Newton's calculations, gravity reduces to a fourth of what it was at the surface of the Earth if the distance from the planet's centre is doubled. At the Earth's surface, a satellite with a mass of 1,000 kg exerts a weight force of 9,800 N.
What gravitational force act on satellite?Satellites are pulled toward Earth by its gravity, even when they are hundreds of kilometres distant. The satellite doesn't fall back to Earth; instead, it travels into orbit above it due to gravity and the velocity it acquired during launch into space.
A satellite that is in a steady circular orbit around the Earth is always falling. It encounters a gravitational pull toward the centre of Earth as it orbits, which forces it to shift course and “fall” towards Earth.
Therefore, Since gravity is the only force acting on a satellite in circular orbit, the centripetal force and gravity must be equal: Fc = Fg.
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A hummingbird is flying around and its velocity v as a function of time t is given in the graph below where
rightwards is the positive velocity direction.
v (m/s)
4
3
2
1
→t (8)
1.5 2 2.5 3 3.5
0.51
-1
-2
What is the hummingbird's displacement Ax from t = 3.0 s to 3.5 s?
Answer:
2 m
Explanation:
The following data were obtained from the question:
Time 1 = 3 s
Time 2 = 3.5 s
Velocity = 4 m/s (constant)
Displacement =?
Next, we shall determine the change in time. This can be obtained as follow:
Time 1 = 3 s
Time 2 = 3.5 s
Change in time = 3.5 – 3
Change in time = 0.5 s
Finally, we shall determine the displacement of the bird between 3 s and 3.5 s as follow:
Velocity = 4 m/s
Time = 0.5 s
Displacement =?
Velocity = Displacement /Time
4 = Displacement /0.5
Cross multiply
Displacement = 4 × 0.5
Displacement = 2 m
Therefore, the displacement of the birth between 3 and 3.5 s is 2 m.
how much heat energy must be added to a 6.0-cm-diameter copper sphere to raise its temperature from -50 c to 150 c?
The amount of heat energy required to raise the temperature of a 6.0-cm-diameter copper sphere from -50°C to 150°C is 7.8 kJ.
Given:Radius (r) = 3 cm, Diameter = 6 cm, Temperature T1 = -50°C, Temperature T2 = 150°C
Now we have to find the amount of heat energy required to raise the temperature from T1 to T2.To find out the amount of heat energy, we will use the following formula:
Q = m × C × ΔT
where
Q = heat energy in Joules, m = mass of the copper sphere in kg, C = specific heat capacity of copper, ΔT = change in temperature
ΔT = T2 - T1= 150°C - (-50°C) = 200°C
The specific heat capacity of copper is 0.385 J/g°C or 385 J/kg°C.
We need to convert the radius to meters and mass to kg. Density of copper is 8.96 g/cm³.
Let's apply this conversion:
Volume of the sphere= 4/3πr³= 4/3 × 3.14 × (0.03 m)³= 1.13 × 10⁻⁴ m³
Density of copper = mass / volume mass of copper = volume × density= 1.13 × 10⁻⁴ m³ × 8.96 × 10³ kg/m³= 1.01 × 10⁻¹ kg
Therefore,
Q = m × C × ΔT= 1.01 × 10⁻¹ kg × 385 J/kg°C × 200°C= 7.8 × 10³ J or 7.8 kJ
Hence, the amount of heat energy required to raise the temperature of a 6.0-cm-diameter copper sphere from -50°C to 150°C is 7.8 kJ.
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what is 6.39 times 10 to the 23rd power
Answer:
6.39*(10 to the 23rd)=
6.39*10²³
an oscilloscope is set in the 0.5volt per division scale. the signal measures four whole divisions. what is the value of voltage?
The voltage measured by the oscilloscope is 2 volts.
What is an oscilloscope and how is the voltage scale calibrated on it?An oscilloscope is a device used to display and analyze the waveform of electronic signals. The voltage scale on an oscilloscope is usually calibrated in volts per division. This means that each division on the screen represents a certain amount of voltage.
In the given scenario, the oscilloscope is set in the 0.5 volts per division scale. This means that each division on the screen represents 0.5 volts of voltage. The signal measures four whole divisions, which means the total voltage can be calculated by multiplying the number of divisions by the volts per division.
Therefore, the value of voltage can be calculated as follows:
4 divisions x 0.5 volts per division = 2 volts
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If the air pressure measures is 3 atm. How many mb of pressure is in the air?
Answer:
3
Explanation:
If there is 3 at the moment (atm) is the same as might be (mb) in the air.
4. A car accelerates at 2.5 m/s^2, covers 4 km in 0.8 min. How fast was it moving at the beginning
of the time interval? *
Answer:
Initial velocity, u = 23.33 m/s
Explanation:
Given the following data;
Acceleration = 2.5 m/s²
Distance = 4 km to meters = 4000 meters
Time = 0.8 mins to seconds = 0.8 * 60 = 48 seconds.
To find the initial velocity, we would use the second equation of motion;
\( S = ut + \frac {1}{2}at^{2}\)
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
4000 = u*48 + ½*2.5*48²
4000 = 48u + 1.25*2304
4000 = 48u + 2880
48u = 4000 - 2880
48u = 1120
Initial velocity, u = 1120/48
Initial velocity, u = 23.33 m/s
A particle moves along an s-axis, use the given information to find the position function of the particle.
To find the position function of the particle, we can integrate the given acceleration function, a(t), twice with respect to time. Given that a(t) = t^2 + 2t - 7, we'll integrate it twice to obtain the position function, s(t).
Let's proceed with the integration step by step:
Step 1: Integrate a(t) with respect to time to find the velocity function, v(t):
∫(a(t) dt) = ∫((t^2 + 2t - 7) dt)
Integrating each term separately:
∫(t^2 dt) + ∫(2t dt) - ∫(7 dt)
= (1/3)t^3 + t^2 - 7t + C1
Since we know that v(0) = 0, we can substitute t = 0 and solve for the constant C1:
v(0) = (1/3)(0)^3 + (0)^2 - 7(0) + C1
0 = 0 + 0 + 0 + C1
C1 = 0
Therefore, the velocity function becomes:
v(t) = (1/3)t^3 + t^2 - 7t
Step 2: Integrate v(t) with respect to time to find the position function, s(t):
∫(v(t) dt) = ∫(((1/3)t^3 + t^2 - 7t) dt)
Integrating each term separately:
∫((1/3)t^3 dt) + ∫(t^2 dt) - ∫(7t dt)
= (1/12)t^4 + (1/3)t^3 - (7/2)t^2 + C2
Since we know that s(0) = 0, we can substitute t = 0 and solve for the constant C2:
s(0) = (1/12)(0)^4 + (1/3)(0)^3 - (7/2)(0)^2 + C2
0 = 0 + 0 + 0 + C2
C2 = 0
Therefore, the position function becomes:
s(t) = (1/12)t^4 + (1/3)t^3 - (7/2)t^2
Hence, the position function of the particle moving along the s-axis is given by s(t) = (1/12)t^4 + (1/3)t^3 - (7/2)t^2.
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If we aim a radio telescope at a distant spiral arm of the Milky Way Galaxy, we will probably observe a 21-cm line. If we point a large optical telescope at this same region, we will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal. Why not
Answer:
Because of the interstellar dust and interior location of the solar system.
Explanation:
We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.
Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.
So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.
a 77 kg man is riding on a 32 kg cart traveling at a speed of 3.8 m/s. he jumps off with zero horizontal speed relative to the ground. what is the resulting change in the cart's speed, including sign?
Answer:
See below
Explanation:
Using conservation of momentum:
Initial momentum = (77+32 kg)* 3.8 m/s = 414.2 kg m/s
Jumping off with zero speed relative to ground (I think this is what zero horizontal speed MEANS) means all of his momentum is given to the cart ( think about jumping off of a skateboard)
final momentum of the cart
mv = 414.2
v = 414.2/32 = 12.94 m/s for a + 9.13 m/s change
Conditions for uniform circular motion are constant speed and circular path. (True or false)
Uniform circular motion is a motion that is uniform in terms of speed and circular in terms of its path.
Uniform means constant speed and its path is circular.
Thus, the statement is true.
What is the general shape of the graph line?
A positively sloping diagonal
A negatively sloping diagonal
A half-parabola
A hyperbola
Answer:
A
Explanation:
Positive slope lines have a left to right ascent. A negative slope is present on lines that descend from left to right. Consequently, a diagonal line with a positive slope (/) would be to the right. Thus, option A is correct.
What is positively sloping diagonal?The height difference between two tile corners that is on the diagonal. A hidden value is used to determine if a tile can be seeded on, passed by a cart, or have the corner of the pavement tile lowered.
When two variables have a positive slope, it means that they are positively correlated; that is, when x rises, y rises as well, and when x falls, y falls as well.
A line on a line graph that has a positive slope rises as the line advances from left to right.
Be aware that a line's positive slope causes it to slope upward from left to right. Remember that a line with a negative slope descends from left to right. Keep in mind that a line has no slope when it is horizontal.
Therefore, positively sloping diagonal general shape of the graph line.
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How long can a tow rope or chain be?
1. 20 feet 2. 15 feet
3. 5 feet
4. 10 feet
Answer:
"For towing, a tow chain should be of a length that keeps both vehicles within the maximum 4.5 meter distance, also tow chains an be any length 20 foot chains are often chosen"
Explanation:
- https://letstowthat.com
Also Quick note the feet of tow rope or chain varies on the situation but most longest or 20 feet.
The light beam shown in the figure below makes an angle of? = 15.5° with the normal line NN' in the linseedoil. Determine the angles θ and θ'.(The refractive index for linseed oil is 1.48.)
θ = 1
°
θ' = 2
°
The angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.
To determine the angles θ and θ' in the given scenario, we can use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the media involved. Snell's Law can be stated as follows:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
Where:
n₁ is the refractive index of the medium of incidence (in this case, air with a refractive index close to 1),
θ₁ is the angle of incidence,
n₂ is the refractive index of the medium of refraction (in this case, linseed oil with a refractive index of 1.48), and
θ₂ is the angle of refraction.
Let's solve for the unknown angles θ and θ' using the given information.
Given:
Angle of incidence θ = 1°
Refractive index of linseed oil n₂ = 1.48
We need to find the angle of refraction θ₂.
Using Snell's Law, we have:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:
sin(θ₁) = n₂ * sin(θ₂)
Plugging in the values:
sin(1°) = 1.48 * sin(θ₂)
We can now solve for θ₂:
θ₂ = arcsin(sin(1°) / 1.48)
Calculating this value, we find:
θ₂ ≈ 0.688°
Now, let's determine the angle θ'.
Given:
Angle of refraction θ₂ = 0.688°
Refractive index of linseed oil n₂ = 1.48
We need to find the angle of incidence θ'.
Using Snell's Law, we have:
n₂ * sin(θ₂) = n₁ * sin(θ')
Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:
n₂ * sin(θ₂) = sin(θ')
Plugging in the values:
1.48 * sin(0.688°) = sin(θ')
Solving for θ', we find:
θ' = arcsin(1.48 * sin(0.688°))
Calculating this value, we get:
θ' ≈ 1.988°
Therefore, the angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.
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place the following types of electromagnetic radiation in order of decreasing energy: microwave, ultraviolet, visible, radio waves.
Electromagnetic radiation is a form of energy that travels in waves and includes a wide range of frequencies and energies. Different types of electromagnetic radiation have varying amounts of energy associated with them.
In order of decreasing energy, the types of electromagnetic radiation you provided can be arranged as follows:
Ultraviolet: Ultraviolet (UV) radiation has higher energy than all the other types mentioned.Visible: Visible light consists of the colors we perceive with our eyes, and it has slightly lower energy compared to UV radiation.Microwave: Microwaves have lower energy than visible light and UV radiation.Radio waves: Radio waves have the lowest energy among the types you listed.So, the correct order from highest to lowest energy is:
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While traveling north on an expressway, a car traveling 60 mph (miles per hour) slows down to 30 mph in 12 minutes
due to traffic conditions. Calculate the acceleration.
Answer:
the acceleration is 2.5 MPH over 12 mins.
Explanation:
30 MPH in 12 minutes=
30/12=
2.5
What percentage of the speed of light will an electron be moving after being accelerated through a potential difference of 1,485 Volts?
The voltage generates a force over the electron, this force is the one we use to calculate the acceleration
\(\begin{gathered} V=\frac{Fd}{q} \\ 1485V\cdot1.602\cdot10^{-19}=Fd=2.38\cdot10^{-16} \end{gathered}\)\(\begin{gathered} Fd=m(a\cdot d) \\ m(ad)=2.38\cdot10^{-16} \\ ad=\frac{2.38\cdot10^{-16}}{9.109\cdot10^{-31}}=2.612\cdot10^{14} \end{gathered}\)\(\begin{gathered} vf^2=vi^2+2ad \\ vf=\sqrt{2\cdot2.612\cdot10^{14}} \\ vf=22.85\cdot10^6m/s \end{gathered}\)First, we apply the energy equation to find the Fd result based on voltage. Then we find the acceleration times distance. Finally, we find the speed with a kinematic equation.
Now I'm going to find the percentage of the speed of light.
\(\frac{22.85\cdot10^6}{3\cdot10^8}=0.0762=7.62\%\)A 745 kg race car experiences an applied force from the engine of 38900 N and a frictional force of 34000 N. How long does it take to go from rest to 21 m/s ?
The time taken for the car to go from rest to 21 m/s is 3.2 seconds.
What is the acceleration of the car?The acceleration of the car is determined by applying Newton's second law of motion as shown below.
Mathematically, the formula for Newton's second law of motion is given as;
F (net) = ma
where;
m is the mass of the cara is the acceleration of the carThe net force acting on the car is calculated as follows;
F (net) = F - Ff
where;
F is the applied forceFf is the force of frictionF (net) = 38,900 N - 34,000 N
F (net) = 4,900 N
The acceleration of the car is calculated as follows;
a = F (net) / m
a = ( 4,900 N ) / ( 745 kg )
a = 6.58 m/s²
The time of motion of the car is calculated as follows;
v = u + at
v = 0 + at
v = at
t = v / a
t = ( 21 m/s ) / ( 6.58 m/s² )
t = 3.2 s
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In the classical projectile problem, in the vertical direction, the acceleration is the negative of the gravitational acceleration (g) and a term (αv) due to the friction with the air medium. Mathematically, for the viscous air resistance, the vertical velocity satisfies the following. dv/dt+αV+g=0 where v is the velocity, α is friction coefficient and g are the gravitational acceleration. Assuming; v(0)=520 m/s,g=9.8 m/s2, and h=0.04, and employing the Euler method to find out how long the shot takes to reach its maximum height [i.e., v(t)=0] for the following cases: i. α=0 (no friction) ii. α=0.034 (light friction) iii. α=0.136 (considerable resistance)
Using the Euler method, the time taken for the projectile to reach its maximum height (v(t) = 0) is approximately 7.5 seconds for all three cases: i) no friction (α = 0), ii) light friction (α = 0.034), and iii) considerable resistance (α = 0.136).
To find the time taken for the projectile to reach its maximum height, we can solve the differential equation dv/dt + αv + g = 0 using the Euler method. The Euler method approximates the solution by discretizing time steps.
v(0) = 520 m/s, g = 9.8 m/s², and h = 0.04.
Using the Euler method, the iterative formula for each time step is:
v(i+1) = v(i) + (dv/dt) * h
where v(i) represents the velocity at the ith time step, (dv/dt) is the derivative of velocity at time i, and h is the time step.
To find the time taken for v(t) to reach 0 (maximum height), we iterate until v(i) becomes negative (indicating the projectile has reached its peak).
For each case:
i) α = 0 (no friction),
ii) α = 0.034 (light friction),
iii) α = 0.136 (considerable resistance),
we use the same iterative formula and iterate until v(i) becomes negative. The time taken for this to happen is approximately 7.5 seconds for all three cases.
Therefore, using the Euler method, the time taken for the projectile to reach its maximum height is approximately 7.5 seconds for all cases.
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A fellow student reports his measurements of time for a speed calculation in minutes. How could he express that calculation using SI
base units?
convert minutes to meters and redo his calculations
convert minutes to hours and redo his calculation
convert minutes to seconds and redo his calculation
Okeep his calculation as it is
Convert minutes to seconds and redo his calculation.
How do we measure time?The quick response. Atomic clocks are the most precise timekeeping devices we have for measuring the length of time between two events. Atoms in the clocks jump from one energy level to another as a result of the precise frequency at which these clocks emit electromagnetic radiation, such as microwaves.
Time is an illusion, says theoretical physicist Carlo Rovelli, because our simple perception of its flow doesn't match up with physical reality. In fact, much more, including Isaac Newton's depiction of a constantly ticking clock, is illusory, according to Rovelli's claim in The Order of Time.
How do you calculate hours and minutes?In an hour, there are 60 minutes. Divide the amount of minutes by 60 to convert it to hours. For instance, 120/60=2 means that 2 hours are equal to 120 minutes.
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Calculate the TOTAL mechanical energy of pendulum is it swings from his highest point to its lowest point. Pendulum mass is 4 kg. Use your equations for gravitational potential energy and kinetic energy to determine these values based on the data given below. Total energy is the sum of gravitational potential energy and kinetic energy. In this problem, round gravity to: g = 10 m/s^2.
Answer:
its should be 2.0 and 4.5 on it
Which statement about velocity is true?
Answer: velocity is the study of how fast an object changes its place, or is displaced.
Explanation: An example would be how fast a basketball reaches the other side of a gym, the acceleration and speed are measured and calculated to find velocity
A jetliner can fly 8.0 hours on a full load of fuel. Without any wind it flies at a speed of 2.42 x 102 m/s. The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 40.7-m/s wind from the jet stream, which blows from west to east. What is the maximum distance (in kilometers) that the plane can travel due west and just be able to return home
Answer:
3386.23 Km
Explanation:
Without any wind interference the speed of the plane, it flies at 2.42 x 102 m/s or 242 m/s
The magnitude of the velocity of the air = 40.7-m/s
The time taken, for the plane to fly due west, tw = distance, x ÷ (speed of the plane without wind interference, up - the magnitude of the velocity of the air, ua).......... (equation 1)
The time taken, for the plane to fly due east, te = distance, x ÷ (speed of the plane without wind interference, up + the magnitude of the velocity of the air, ua).......... (equation 2)
To calculate the total time, t, the plane can fly to cover east and west distances, we add equation 1 and 2 together
t = (x ÷ (up - ua)) + (x ÷ (up + ua))
Making distance x, the subject of the formula we have:
x = t ( up²- ua²) ÷ 2up
note t = 8.0 hours which is (8 x 60 x 60) seconds = 28,800
So, x = 28,800 ((242 m/s)² - (40.7-m/s)²)÷ 2(242 m/s)
x= 1,638,936,288 ÷ 484
= 3386.23 Km