A gas is compressed to 75cm3 to a volume of 30cm3. Its temperature remains the same The pressure of the gas after it has been compressed is 110 Pa. What was the pressure before it was compressed?

Answer:

The North Pole.

Explanation:

According to the Lenz's law of electromagnetic induction, an induced elemagnetic force tends to give rise to the current. In reaction, this current's magnetic field try to oppose any replacement in the magnetic flux.

So,  as per the law of Lenz's electromagnetic induction, when the current passes in a coil in anti-clockwise direction, this will produce the opposite end of the coil in the north pole.

So, the correct answer is north pole.

Answer:The disturbance created by a source of sound in the medium travels through the medium and not the particles of the medium

Explanation:i hope this is right

The root mean square (RMS) voltage of a standard alternating current (AC) outlet in a house or business in the United States is typically 120 volts. This is the effective voltage of the AC power supplied to homes and businesses in the United States and is used to power a wide variety of electrical devices and appliances.

It is important to note that the RMS voltage of an AC outlet is not the same as the peak voltage, which is the maximum voltage of the AC waveform. The peak voltage of a standard AC outlet in the United States is typically 170 volts. The RMS voltage is a measure of the effective voltage of the AC power, while the peak voltage is a measure of the maximum voltage of the AC waveform.

Learn more about The root mean square here: https://brainly.com/question/29732273

#SPJ4

Answer:

The atomic number of Aluminum is "13"!

Explanation:

The 27 means the atomic mass is 27 . The number of protons plus the number of neutrons is 27. That means the number of neutrons is 27–13=14. Number of neutrons depends on the isotopic form of aluminium.

A car is accelerated by the work from zero to 50 km/h. accelerating the car from requires 8wW0 of work.

When pressure is applied along a displacement, work is indeed the energy that is either added to or subtracted from an item. In its basic form, it equals equal product of the force's magnitude and the travel distance for a force applied directed in the same direction as the motion.

The joule is the Si derived unit of labor (J). It is described as the work accomplished over a one-meter distance by a pressure of one newton. A produce a satisfactory is something that candidates are asked to bring to a job interview, like an example of their writing or editing.

To know more about work visit:

https://brainly.com/question/18094932

#SPJ4

Answer:

W = 210 N

Explanation:

For an ideal machine:

\(Work\ In = Work\ Out\\(P)(L)=(W)(H)\)

where,

P = Effort = Spring Scale Reading = 70 N

L = Effort Arm = Length of inclined plane = 12 m

W = Actual Load (Weight) to be lifted = ?

H = Load Arm = Height = 4 m

Therefore,

\((70\ N)(12\ m) = (W)(4\ m)\\\\W = \frac{(70\ N)(12\ m)}{4\ m}\)

W = 210 N

Answer:

no

Explanation:

hope this helps........

By Newton's second law, the apparent weight of rider coming at rest is 3548 N.

According to formula, v = u + at

a = 39.2 m/\(s^{2}\)

Force, F = ma

F = m(a+g)

F = apparent weight

m = mass, given = 65 kg

a = acceleration, given = 39.2 m/\(s^{2}\)

g = 9.8 m/\(s^{2}\)

Put these values in formula, F = m(a+g)

F = 65(39.2+9.8)

F = 3548 N

Therefore, the apparent weight of rider coming at rest is 3548 N.

Learn more about apparent weight here:- https://brainly.com/question/24897276

#SPJ4

This expression gives the burning surface area A of one motor segment in terms of r1, r2, and w.

To find an expression for the burning surface area (A) of one motor segment, considering that both ends and the inner bore of the cylinder burn, we will use the terms r1, r2, and w.

The surface area A can be calculated as the sum of the areas of the two ends and the inner bore. The two ends have circular shapes, while the inner bore has a cylindrical shape.

For the ends, we have two circles with radii r1 and r2. The area of a circle is given by the formula A = πr². So, the total area of the two ends is:

A_ends = πr1² + πr2²

For the inner bore, we have a cylinder with radius r1 and height w. The lateral surface area of a cylinder is given by the formula A = 2πrh. So, the area of the inner bore is:

A_bore = 2πr1w

Now, we can find the total burning surface area A by adding the areas of the two ends and the inner bore:

A = A_ends + A_bore
A = (πr1² + πr2²) + 2πr1w

This expression gives the burning surface area A of one motor segment in terms of r1, r2, and w.

To learn more about cylinder, refer below:

https://brainly.com/question/16134180

#SPJ11

The given problem involves calculating the acceleration due to gravity on the surface of the Moon and Mars, given their masses and radii.

Specifically, we are asked to find the gravitational acceleration on the Moon and Mars, using their respective masses and radii.To calculate the acceleration due to gravity on the surface of a planet or moon, we can use the formula:g = G * M / R^2where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the planet or moon, and R is the radius of the planet or moon.Using the given values for the mass and radius of the Moon and Mars, we can calculate the acceleration due to gravity on their surfaces.

The final answer for each planet or moon is a number, which represents the gravitational acceleration on the surface.Overall, the problem involves applying the principles of gravity and using the formula for gravitational acceleration to calculate the acceleration due to gravity on the surface of different planets and moons in our solar system. It also requires an understanding of the relationship between mass, radius, and gravitational acceleration.

For more similar questions on topic gravitational acceleration

brainly.com/question/28188525

#SPJ11

The final angular speed of the system is 0.4424 rad/s.

Before the child jumps onto the merry-go-round, the system consists of only the merry-go-round and has zero angular velocity.

When the child jumps onto the merry-go-round, the system becomes a composite object consisting of the child, the merry-go-round, and the rotational motion of the two.

Let's first calculate the angular momentum of the system before the child jumps onto the merry-go-round. Since the system is not rotating, its initial angular momentum is zero.

When the child jumps onto the merry-go-round, the system conserves angular momentum. That is, the total angular momentum of the system before the child jumps must be equal to the total angular momentum of the system after the child jumps.

Let's use the conservation of angular momentum to solve for the final angular speed of the system:

Initial angular momentum = 0

Final angular momentum = (Iω)final = (Iω)merry-go-round + (Iω)child

where I is the moment of inertia of the merry-go-round, ω is the angular velocity, and the subscripts "merry-go-round" and "child" refer to the respective contributions from each object.

We can find the angular momentum of the child using the formula L = mvr, where m is the mass of the child, v is the tangential velocity, and r is the radius of the merry-go-round.

Lchild = mchildvchildr = (34.0 kg)(2.80 m/s)(2.31 m) = 225.48 kg m^2/s

Since the child was initially moving tangentially to the merry-go-round, the direction of their angular momentum is perpendicular to the direction of the angular momentum of the merry-go-round.

Therefore, we can find the total angular momentum of the system by taking the vector sum of the angular momentum of the merry-go-round and the angular momentum of the child. We can use the right-hand rule to determine the direction of the total angular momentum, which is out of the page.

Final angular momentum = (Iω)final = (510 kg m^2)(ω) + 225.48 kg m^2/s

Since the total angular momentum is conserved, we can set the initial and final angular momenta equal to each other:

0 = (510 kg\(m^2)(\)ω) + 225.48 kg \(m^2/s\)

Solving for ω, we get:

ω = -225.48 kg m^2/s ÷ (510 kg \(m^2\)) = -0.4424 rad/s

The negative sign indicates that the direction of the angular velocity is opposite to the initial direction of the child's motion.

Therefore, the final angular speed of the system is 0.4424 rad/s.

Learn more about angular momentum

https://brainly.com/question/29897173

#SPJ4

To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.

To calculate the average velocity, you can use the formula:

Average velocity = (change in velocity) / (change in time)

You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.

Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.

It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.

learn more about velocity-time graph here:

https://brainly.com/question/33160974

#SPJ11

Answer:

Explanation: 3200j = 1/2mv2

3200j = 1/2*6*v

3200= 3

v= 1066.66

Answer:

They are transverse waves

Explanation:

Answer:

60m/s

Explanation:

We are given that

Speed of car after 5 sec, v=40m/s

Acceleration ,a=\(-4m/s^2\)

We have to find the initial speed of car.

We know that

Acceleration, a=\(\frac{v-u}{t}\)

Where v=Final speed

u=Initial speed

Using the formula

\(-4=\frac{40-u}{5}\)

\(-4\times 5=40-u\)

\(-20=40-u\)

\(u=40+20\)

\(u=60\)

Hence, initial speed of car=60m/s

Answer:

According to Newton's third law, the force exerted on each driver during the collision is equal and opposite to the force exerted on their respective vehicles. We can use the principle of conservation of momentum to find the force experienced by each driver.

The initial momentum of the car and driver is the product of their mass and velocity: (800 kg)(6.60 m/s) = 5280 kgm/s. The initial momentum of the truck and driver is (4000 kg)(6.60 m/s) = 26400 kgm/s. After the collision, the final momentum of the combined system (the car, truck, and drivers) is 0, since the collision is perfectly inelastic and the two vehicles stick together. This means that the final momentum of the car and driver is equal and opposite to the final momentum of the truck and driver.

We can set up the following equation to solve for the force experienced by the car driver:

Force (car driver) = (final momentum of car and driver) / (collision time)

= (-final momentum of truck and driver) / (collision time)

= (-26400 kg*m/s) / (0.100 s)

= -26400 N

The negative sign indicates that the force is in the opposite direction of the initial momentum of the car and driver. The force experienced by the truck driver is equal in magnitude to the force experienced by the car driver, so the force experienced by the truck driver is also -26400 N.

Explanation:

The beetle's actual distance beneath the surface is 1.70 cm.

The given information states that the beetle appears to be 1.70 cm within the plastic. This means that the beetle is located at a distance of 1.70 cm from the outer surface of the cube of polystyrene plastic. However, the actual distance of the beetle beneath the surface is also 1.70 cm since it is embedded within the cube.

The phrase "appears to be" suggests that the observation of the beetle's position within the plastic is deceiving. The beetle is not deeper or closer to the surface than the given measurement. Therefore, the beetle's true depth beneath the surface is equivalent to the stated distance of 1.70 cm.

Distances and interpreting spatial relationships within objects like the embedded beetle.

Learn more about beetle

brainly.com/question/11338404

#SPJ11

The thermal expansion of a metal door is directly related to the kinetic energy of the metal particles. As the temperature increases, the particles gain kinetic energy, which causes them to move and vibrate more vigorously, resulting in the expansion of the metal door.

The thermal expansion of a metal door is related to kinetic energy through the underlying principle of thermal expansion and the behavior of particles in a substance. When a metal door is heated, its temperature increases, causing the particles within the metal to gain kinetic energy. This increase in kinetic energy leads to an increase in the vibrational and translational motion of the particles.

The relationship between temperature, kinetic energy, and thermal expansion can be explained by the kinetic theory of matter. According to this theory, when the temperature of a substance increases, the average kinetic energy of its particles also increases. The increased kinetic energy results in greater particle movement and collisions, leading to an expansion of the substance.

In the case of a metal door, as the temperature rises, the kinetic energy of the metal atoms and ions increases. This increased kinetic energy causes the particles to vibrate and move more vigorously, leading to an expansion in the dimensions of the metal door.

The thermal expansion of a metal door is directly related to the kinetic energy of the metal particles. As the temperature increases, the particles gain kinetic energy, which causes them to move and vibrate more vigorously, resulting in the expansion of the metal door. Understanding this relationship helps in predicting and managing the thermal expansion of metal doors and other objects when subjected to temperature changes.

To know more about energy visit:

https://brainly.com/question/25959744

#SPJ11

Answer:

option 3, as circuit breakers are mostly used as precautions

The Apparent magnitude of a star depends directly upon its luminosity and distance. Option D is correct.

A celestial object with a positive number higher than one is fainter; whereas a brighter celestial object indicates a negative number that is higher. For instance, Venus has a magnitude of -4.6 at its brightest point, while the faintest star that can be seen by the  eye has a magnitude of +6.0.

The brightness of a star or other astronomical object seen from Earth is measured in apparent magnitude (m). An item's clear greatness relies upon its natural glow, its separation from Earth, and any eradication of the article's light brought about by interstellar residue along the view to the eyewitness.

Incomplete question:

The _____ magnitude of a star depends directly upon its luminosity and distance.

a. absolute

b. bolometric

c. visual

d. apparent

Learn more about Apparent magnitude of star:

brainly.com/question/31912542

#SPJ4

Combination of these two waves produces a new wave with a similar appearance to the originals but a larger amplitude. So, the statement is true.

Constructive interference is the scientific term for this circumstance, in which the final wave is larger in amplitude than either of the two initial waves.

Interference is a phenomenon where two waves combine to create a new wave that may have a bigger, smaller, or identical amplitude.

Two waves of the same type can interfere with one another, such as interference between two light waves or interference between two sound waves.

To learn more about constructive interference, click:

https://brainly.com/question/12077579

#SPJ4

Answer: LOL Hello! for the third time! the answer is Inverse distance weighting (IDW) is a type of deterministic method for multivariate interpolation with a known scattered set of points. The assigned values to unknown points are calculated with a weighted average of the values available at the known points.

Explanation: ^^ Up there have a good day and hope this helps you!

Question: Hello: ) ✨What is Inverse Distance Weighting?​

Answer: a method of interpolation that estimates cell values by averaging the values of sample data points in the neighborhood of each processing cell. The closer a point is to the center of the cell being estimated, the more influence, or weight, it has in the averaging process.Inverse Distance Weighting (IDW) interpolation estimates unknown values with specifying search distance, closest points, power setting & barriers.”

Hope this helps<3

Answer:

Total resistance in parallel is 1.2703136679494.

Total resistance in series is 155.Total resistance in series is 155.

Explanation:

Answer:

P = I V = I^2 R

R = 150 + 300 = 450 Ω

I = 150 / 450 = .333 amps

P(150) = .333^2 * 150 = 16.7 W

Answer:

Density of the mixture = 855.56kgm-3

Explanation:

Density = Mass / Volume

Volume of Liquid X = 0.5m³

Density of Liquid X = 900kgm-3

Mass of Liquid X = Density × Volume

= 900kgm-3 × 0.5m³ = 450kg

Volume of Liquid Y = 0.4m³

Density of Liquid Y = 800kgm-3

Mass of Liquid Y = Density × Volume

= 800kgm-3 × 0.4m³= 320kg

As X and Y are mixed, we add their masses and volumes together:

Mass = 770kg

Volume = 0.9m³

Now we can find the density of the mixture:

Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)

At kelvin temperature T, cylinder A includes n molecule of a gas, and the force exerted by the gas on the cylinder is NkBT/l.

When two bodies interact, it refers to any form of pushing or pulling that one body exerts on the other. A vector quantity, that is. For instance, a person pushes or pulls on something to provide force, such as opening a door.

Contact forces that act at a remove forces are the two different types of forces. Your daily use of force is evident. Basically, pressure and pull are forces.

Formulas,

-P = F/A

-n = n/Na

-PV = nRT

= NKT (R = KNa)

- Volume of cylinder: A* l

F=PA

P = NKbT / V

P = NKbT / A* l

F = NkBT / A * l (A)

Cross out A,

Final, F = NkBT/l.

To know more about force visit:

https://brainly.com/question/13191643

#SPJ1