A glass slides across a bar and slows down due to a kinetic friction of 0.175n. if the glass weighs 0.500n, what is the coefficient of kinetic friction between the glass and the bar?

Answers

Answer 1

The coefficient of kinetic friction between the glass and the bar is 0.35. This is found by dividing the force of kinetic friction by the weight of the glass, using the formula for kinetic friction.

The coefficient of kinetic friction is a measure of the frictional force between two surfaces in contact when they are moving relative to each other.

In this problem, a glass slides across a bar and slows down due to kinetic friction of 0.175 N. The weight of the glass is 0.500 N, and we need to determine the coefficient of kinetic friction between the glass and the bar.

The formula for kinetic friction is:

\(f_k = \mu_k\; N\)

where \(f_k\) is the force of kinetic friction, \(\mu_k\) is the coefficient of kinetic friction, and N is the normal force between the two surfaces in contact.

The normal force is equal to the weight of the object in contact with the surface. Therefore, the normal force on the glass is 0.500 N.

Substituting the given values, we get:

\(0.175 N = \mu_k (0.500 N)\)

Solving for μ_k, we get:

\(\mu_k\) = 0.175 N / 0.500 N

\(\mu_k\) = 0.35

Therefore, the coefficient of kinetic friction between the glass and the bar is 0.35.

In summary, the coefficient of kinetic friction between the glass and the bar is 0.35. This is found by dividing the force of kinetic friction by the weight of the glass, using the formula for kinetic friction.

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Complete Question:

A glass slides across a bar and slows down due to a kinetic friction of 0.175N. If the glass weighs 0.500N, what is the coefficient of kinetic friction between the glass and the bar?

A. 0.350

B. 2.86

C. 1.48

D. 0.675


Related Questions

which statement best describes the position of the image of an object viewed in a plane mirror?
A). the image is a different distance from the mirror but on the same side of the mirror as the original object
B). the image is the same distance from the mirror and on the same side of the mirror as the original object
C). The image is a different distance from the mirror and on the other side of the mirror as the original object.
D). the image is the same distance from the mirror but on the other side of the mirror as the original object.

Answers

The statement D best describes the position of the image of an object viewed in a plane mirror, The image is the same distance from the mirror but on the other side of the mirror as the original object.

What is the image?

When light beams from an object reflect off a mirror, they intersect with the picture of that thing, called an image. Real and virtual images are the two sorts of images.

The following parameters can be used to describe an image:

1. It is possible for an image to be real or virtual.

2. Left-right reversal is possible or not.

3. The image can be inverted or upright.

4. The image can be enlarged, shrunk, or made the same size as the object.

Plane mirrors provide virtual images that are upright, inverted left-right, the same distance from the mirror as the item, and the same size as the thing.

As a result, the best description of image production by a plane mirror is “a virtual picture is produced behind the mirror.”

The statement D best describes the position of the image of an object viewed in a plane mirror, The image is the same distance from the mirror but on the other side of the mirror as the original object.

Hence, option D is correct.

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he first right-hand rule relates which two quantities?
A.
current (thumb) to magnetic field (fingers)
B.
magnetic field (thumb) to current (fingers)
C.
current (thumb) to force (fingers)
D.
force (thumb) to current (fingers)
Reset Next

Answers

Answer: A.

current (thumb) to magnetic field (fingers)

Answer:

A. current (thumb) to magnetic field (fingers)

Explanation:

According to the Right-Hand Thumb rule, if we are holding a current- carrying straight conductor in our right hand such that the thumb points toward the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field.

Hope it helps.

If you have any query, feel free to ask.

Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to _____.

Answers

Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength

What would the Increasing the distance between an electromagnet and the compass cause?


The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.

As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.

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Please answer quickly

Please answer quickly

Answers

Explanation:

I think the third container is in correct

Did you get ???? Tell me if you did

a = 40
B= 75
m = 50 kg
kt=0.3
------------
To which mass of m2 will mass ml go down the hill? What will be the
acceleration of m2 (a)?

On which interval of masses m2 will the system rest/not move?

On which mass m2 will the system go backwards (ml up the hill) What
will be the acceleration of ml (a)?

Solve with II. Newton's law.​

a = 40B= 75m = 50 kgkt=0.3------------To which mass of m2 will mass ml go down the hill? What will be

Answers

Answer:

A DAY IN THE LIFE OF METIS JOURNAL, I WROTE IT HOPE U LIKE IT ;))) XD

We, who live in the west, were Nomadic. So we always moved from place to place to hunt buffalo and other fur-bearing animals. And now again we have to shift everything we collected , like, all the essential needs we collected. It’s really hard to shift stuff, But when you move to a new place you get to see new beautiful places. They are just so satisfying to see! It’s like all my work(like the shifting work) is paid off. I love it! We always meet the Hudson’s bay company employees, and give them furs which we took from the bissons and other furry animals we hunted. And in exchange they give us their (Hudson’s Bay company) goods. Which is good! Because then we or I won't be able to enjoy that delicious pemmican!

 The one reason that makes me proud of my parents is that because of them I am like a translator for both sides in the fur trade! Anyways coming back to the present. As I said before, we were moving today to another place, But on the way some people along with my father will ride the famous York boats carrying supplies to fur posts. I begged my father to take me with him! And as usual he gave me some silly reason for me to stay. And now since I don’t have anything to do I will-..Nevermind, My mom’s calling me. Okay after helping my mom keep the fur posts into the York boats me , my mom, and the others are just relaxing and enjoying nature just to take a break. Since, I am so obsessed with my Journal notebook today I’m just going to sit here and right what comes to my mind. I’m not like the others who always seem to be talking with someone. I like my own space! 

I kind of miss my dad already, but he and his fellow members need to travel the waterways from the red river further west and north to hudson bay. These red river carts also travel the trek back and forth over land to St. Paul, Minnesota and to posts in saskatchewan.  Speaking about the red river, the only large settlement in the region is the red colony. About 12000 people lived in this colony around Fort Garry. Some were the original Selkirk settlers or their descendents. They had come from Scotland with lord Selkirk when he established the colony in 1811. Many of these original settlers were poor farmers who had been displaced  from their lands in scotland. They had endured many hardships in the early years of settlement, including foods, hunger, and sickness. I love studying about other colonies, cultures , history etc.

Explanation:

write this as your answer you will get extra marks

what is the density of an object with mass of 60 g and a volume of 2cm3

Answers

Answer:

D=mass /volume

=60/0.002

=30000

How does the compass react to being away from the magnetic bar?

Answers

Answer:

When you take the compass away from the bar magnet, it again points north. So, we can conclude that the north end of a compass is attracted to the south end of a magnet. ... In Experiment 2, when you move the north pole of a magnet toward the south pole of the other magnet, the two magnets attract.

The simplest compass is a magnetized metal needle mounted in such a way that it can spin freely. (You can make one yourself by magnetizing an ordinary needle, placing it carefully on a slice of cork, and letting the cork float in a tray of water.) Left to its own devices, the needle turns until one end points north and the other south. You can usually figure out which end is which from the position of the Sun in the sky, remembering that the Sun rises in the east and sets in the west. So if you're looking down on the floating needle at about noon, with the eye on the left and the point on the right, and the Sun in front of you, you know the point is indicating north.

A skydiver jumps from a high altitude balloon. 2. 0 s later another skydiver jumps. How far apart are the skydivers 8. 0 s after the second skydiver jumps

Answers

The skydivers are approximately 137.2 meters apart 8.0 seconds after the second skydiver jumps.

How to determine how far apart are the skydivers 8. 0 s after the second skydiver jumps

To determine the distance between the skydivers 8.0 seconds after the second skydiver jumps, we need to consider the vertical motion of the two skydivers.

Assuming no air resistance, both skydivers will experience free fall acceleration due to gravity, which is approximately 9.8 m/s^2.

Since the second skydiver jumps 2.0 seconds after the first skydiver, we can calculate their respective positions after 8.0 seconds using the equation of motion:

s = ut + (1/2)at^2

where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time.

For the first skydiver:

Initial velocity (u) = 0 m/s (since the skydiver jumps from rest)

Acceleration (a) = 9.8 m/s^2

Time (t) = 8.0 s

Using the equation, we can calculate the displacement of the first skydiver after 8.0 seconds.

s1 = (0)(8.0) + (1/2)(9.8)(8.0)^2

s1 = 0 + (1/2)(9.8)(64)

s1 = 0 + 313.6

s1 ≈ 313.6 m

For the second skydiver:

Initial velocity (u) = 0 m/s

Acceleration (a) = 9.8 m/s^2

Time (t) = 6.0 s (since the second skydiver jumps 2.0 seconds after the first)

Calculating the displacement of the second skydiver after 8.0 seconds:

s2 = (0)(6.0) + (1/2)(9.8)(6.0)^2

s2 = 0 + (1/2)(9.8)(36)

s2 = 0 + 176.4

s2 ≈ 176.4 m

To find the distance between the skydivers, we subtract the displacement of the second skydiver from the displacement of the first skydiver:

Distance = s1 - s2

Distance ≈ 313.6 m - 176.4 m

Distance ≈ 137.2 m

Therefore, the skydivers are approximately 137.2 meters apart 8.0 seconds after the second skydiver jumps.

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Answer:

Approximately \(176.58\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\), both skydivers started with an initial velocity of zero, and that air resistance is negligible.)

Explanation:

Under the assumptions, each skydiver would be accelerating downward at \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\). The initial velocity of both skydivers would be \(u = 0\; {\rm m\cdot s^{-1}}\).

At \(t\) seconds after the second skydiver jumps, the first skydiver would have been in the sky for \((t + 2.0)\) seconds. Apply the SUVAT equation \(x = (1/2)\, a\, t^{2} + u\, t + x_{0}\) to model the position of each skydiver:

First skydiver: \((1/2)\, a\, (t + 2.0)^{2} + u\, (t + 2.0) + x_{0}\).Second skydiver: \((1/2)\, a\, t^{2} + u\, t + x_{0}\).

Subtract the two expressions to find the distance between the two skydivers:

\(\begin{aligned}& \frac{1}{2}\, a\, (t + 2.0)^{2} + u\, (t + 2.0) + x_{0} -\left(\frac{1}{2}\, a\, t^{2} + u\, t + x_{0}\right) \\ =\; & a\, (2.0)\, t + \frac{1}{2}\, a\, (2.0)^{2} + u\, (2.0) \end{aligned}\).

Substitute \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\), \(u = 0\; {\rm m\cdot s^{-1}}\), and \(t = 8.0\; {\rm s}\) into the expression and evaluate:

\(\begin{aligned}& a\, (2.0)\, t + \frac{1}{2}\, a\, (2.0)^{2} + u\, (2.0) \\ =\; & (-9.81)\, (2.0)\, (8.0) + \frac{1}{2}\, (-9.81)\, (2.0)^{2} + (0)\, (2.0) \\ \approx\; & -176.58\end{aligned}\).

In other words, the two skydivers would be approximately \(176.58\; {\rm m}\) apart.

A wave has a frequency of 12,000 Hz. What does this mean

Answers

It means that wave vibrates 12,000 times about its mean position per second.

Humans can hear sounds between about 20 Hz and 20,000 Hz (depending on the human!).

Below 20 Hz is called infrasound ("infra" means below), and above 20,000 Hz is ultrasound ("ultra" means beyond).

We are most sensitive to sounds between 1,000 and 4,000 Hz:

As we get older we are less sensitive to higher frequency sounds (a limit around 12,000 Hz is normal for an adult).

Vibration refers to the back-and-forth motion of an object or system about its equilibrium position. This motion can be periodic or random and can occur in a variety of mediums, including solids, liquids, and gases. Vibration is caused by a force or disturbance that creates an oscillation within the system.

Vibration can be both beneficial and detrimental. Beneficial vibrations can be used to create sound, power tools, and even musical instruments. On the other hand, detrimental vibrations can cause damage to structures, machinery, and even the human body. For example, exposure to high levels of vibration can cause hand-arm vibration syndrome or whole-body vibration syndrome, which can result in numbness, tingling, and even long-term health problems.

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What energy transformation takes place when you push a pencil off your desk? A. Mechanical energy transforms into kinetic energy. B. Potential energy transforms into nuclear energy. C. Potential energy transforms into kinetic energy. D. Kinetic energy transforms into potential energy.​

Answers

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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what is the maximum distance that matter is displaced from the resting position

Answers

The largest distance that matter may be moved from its resting state is called the amplitude.

In physics, amplitude refers to the greatest displacement or distance that a point on a vibrating body or wave may move relative to its equilibrium location.It is equal to the half-length of the vibration path.. The bob travels halfway across the pendulum's amplitude as it moves from one side to the other. Waves are produced by vibrating sources, and the amplitude of the waves is inversely proportional to the amplitude of the source. The largest deviation of any point on a transverse wave, such as the wave on a plucked string, from its location when the wave is at rest, is used to determine the wave's amplitude.

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THE CORANDO SPRING RESORT
Donnie Byrd, manager of the Mexican-themed resort with over 340 rooms is trying to provide 5-star customer
service. His position is contingent on having satisfied guests. Most recently, Donnie Byrd has been tasked with
remodeling the front desk area to provide a quick, convenient, and customer-centric check-in experience by
optimizing staffing levels and offering excellent guest service. Given the expanse of the resort and in order to
ensure that guests rooms are ready with customers arrive, the resort policy is that check-in begins at 3pm. As a
result, Mr. Byrd believes that the peak check-in time is between 3:00pm and 5:00pm. During this timeframe, an
average of 36 guests arrive each hour. A front-desk clerk spends an average of 6 minutes to process a registration
including providing room keys, a resort map, directions to the room, and answers to any additional questions.
Mr. Byrd’s goal is to improve guest services by reducing the length of time that guests spend waiting in line and
checking-in. Below are the current proposals that Mr. Byrd is considering to manage the queuing process.
PROPOSAL 1. Proposal 1 is the current layout where the resort has exactly four clerks on duty, each with a separate
waiting line where customers choose one of the four lines and remain on that line until the clerk
assigned to that line is available.
PROPOSAL 2. Proposal 2 would designate one of the four front desk clerks as a quick-service line for returning
guests registering with a corporate account. Approximately one-third of reservations fall into this
category. Because these corporate guests are preregistered, the registration takes an average of just
4 minutes. Without these guests on the other three lines, the average time to register a non-
corporate guest would increase to 6.5 minutes. Under this proposal, the non-corporate guests would
choose any of the three separate lines.
PROPOSAL 3. Proposal 3 is to re-configure the waiting area to have just one single-line system. All guests would
wait on the same line and then be processed by whichever of the four front-desk clerks became
available. (The only difference between proposal 1 and proposal 3 is the line formation) Note that
this would require enough space in the lobby to accommodate what could be a significant queue.
PROPOSAL 4. Proposal 4 is a variation on proposal 3. In this proposal, the servers will work in conjunction and
work as a team so there will only be two check-in stations. There will still be a single line and
guests will proceed to the next available check-in station (server). Since the clerks are working as
a team, they not are able to process a registration in an average of 3 minutes.
PROPOSAL 5. Proposal 5 uses a self-service kiosk. The time that a guest spends at the kiosk is comparable to the
time it takes for a front-desk clerk to process the check-in; however, since check-ins are automated
the service time would be a constant 5 minutes. Because some customers do have personal
questions related to their check-in, Donnie estimates that approximately 25% of the guests, would
use the self-service kiosk. Donnie hopes that this percent will increase in the future. For the
remaining 75% of the guests, Donnie would have a single queue for customers who prefer
traditional front-desk check-in clerks. This line would be serviced by three clerks working
independently. Similar to the current proposal, each clerk can process a check-in in an average of
6 minutes per guest.
PROPOSAL 6. Donnie is open to your suggestions. Please provide a suggestion for a "better" check-in system.
Describe your proposal and be sure to compare your performance measures to the other proposals.
b. (20 points) Methodology (include a discussion of what information was provided and how you used this information
to analyze the problem - create a summary table containing the data for of each of the proposals – including the model
or models used to evaluate each proposal, the value(s) of lambda and value(s) of mu)

Answers

Proposal 4 seems to be the best option, as it allows for efficient team processing, reducing the average registration time to 3 minutes while maintaining a single line system.


Proposal 4 stands out as it allows the front-desk clerks to work in conjunction, reducing the average check-in time to 3 minutes. The single line system prevents guests from getting stuck in a slower line, ensuring fair service. This proposal balances efficiency and customer experience by maintaining only two check-in stations.

Although other proposals offer quicker service for specific groups (Proposal 2) or introduce technology (Proposal 5), Proposal 4 focuses on optimizing the existing staff and layout without excluding or creating disparities among guests. By implementing Proposal 4, Donnie can improve guest satisfaction, reduce wait times, and streamline the check-in process at the Corando Spring Resort.

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Specifications for a part for a 3-D printer state that the part should weigh between 24.7 and 25.7 ounces. The process that produces the parts has a mean of 25.2 ounces and a standard deviation of .20 ounce. The distribution of output is normal. Use Table-A.

a.What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places.)

b.Within what values will 99.74 percent of the sample means of this process fall if samples of n = 10 are taken and the process is in control (random)? (Round your answers to 2 decimal places.)

Answers

1.24% percentage of parts will not meet the weight specs amd the sample means will fall between 25.046 and 25.354 ounces.

a. To determine the percentage of parts that will not meet the weight specifications, we need to calculate the probability of a part weighing less than 24.7 ounces or more than 25.7 ounces. First, we need to calculate the z-scores for these values using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. For 24.7 ounces:

z1 = (24.7 - 25.2) / 0.20 = -2.50

For 25.7 ounces:

z2 = (25.7 - 25.2) / 0.20 = 2.50

Using Table-A (Z-score table), we can find the area under the standard normal curve corresponding to these z-values. From the table, the area to the left of -2.50 is 0.0062, and the area to the right of 2.50 is also 0.0062. Therefore, the total probability of a part not meeting the weight specs is:

P(z < -2.50 or z > 2.50) = P(z < -2.50) + P(z > 2.50) = 0.0062 + 0.0062 = 0.0124

So, the percentage of parts that will not meet the weight specs is .

b. To determine the values within which 99.74% of the sample means will fall, we need to calculate the margin of error for a sample mean. The margin of error is given by the formula:

E = z * (σ / sqrt(n))

where E is the margin of error, z is the z-score corresponding to the desired level of confidence (in this case, 99.74% corresponds to a z-score of 2.75), σ is the standard deviation, and n is the sample size.

Plugging in the values:

E = 2.75 * (0.20 / sqrt(10)) ≈ 0.154

The range of sample means will be within ±E of the population mean. Therefore, the values within which 99.74% of the sample means will fall are:

25.2 ± 0.154 = (25.046, 25.354)

So, for samples of size 10, 99.74% of the sample means will fall between 25.046 and 25.354 ounces.

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Timmy throws a ball upward. As it falls, it is caught at the same height as it was thrown. What are the signs of the vertical position, velocity, and acceleration during the downward part of the trajectory of the ball? a. Position + Velocity + Acceleration - b. Position + Velocity - Acceleration - c. Position - Velocity - Acceleration - d. Position + Velocity - Acceleration +

Answers

The sign of the vertical position is positive, velocity is negative, and acceleration during the downward part of the trajectory of the ball is negative.

option B is the correct answer.

What is vertical velocity of a projectile?

During a projectile motion, the vertical velocity of a projectile decreases as the projectile moves upwards and eventually become zero as the object reaches the maximum height.

As the object begins move downwards, the vertical velocity of the projectile increases and eventually becomes maximum before the object hits the ground.

During the horizontal motion of a projectile, the horizontal velocity of the projectile does not change. That is the initial horizontal velocity of the projectile equals the final horizontal velocity of the projectile.

Thus, we can conclude the following about the signs, as the ball falls down;

the vertical position will be positivethe velocity will be negativethe acceleration will be negative

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Suzie Skydiver with her parachute has a mass of 46kg. Before opening her chute what force of air pressure will she have when she reaches terminal velocity

Answers

Before opening her chute, Suzie Skydiver would experience a force of air pressure of approximately 450 N at terminal velocity.

Terminal velocity is the point where the force of air resistance, or drag, acting on the skydiver becomes equal in magnitude to the force of gravity pulling the skydiver down. At this point, the net force acting on the skydiver is zero, and they fall at a constant velocity. At terminal velocity, Suzie Skydiver is falling at a constant rate, meaning that the force of gravity pulling her down is balanced by the force of air resistance pushing her up.

This force of air resistance, also known as drag, can be calculated using the formula:

F = 1/2 * rho * v^2 * Cd * A,

where F is the force of drag, rho is the density of the air,

v is the velocity of the object,

Cd is the drag coefficient

A is the cross-sectional area of the object.

Assuming that Suzie Skydiver falls in a typical skydiving posture with a drag coefficient of around 1.0 and a cross-sectional area of 1.0 square meter,

Using the standard atmospheric density of 1.2 kg/m³,

We can calculate that her terminal velocity is approximately 54 m/s.

At this velocity, the force of air resistance, or drag, acting on Suzie Skydiver is equal in magnitude to the force of gravity, which is approximately 450 N.

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At what degree is the Equator
located on the globe?

Answers

Answer:

0 degrees latitude

Explanation:

At 0 degrees latitude, the Equator is an invisible line that circles the Earth's center.

Boat Engine An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. What power does the engine develop

Answers

An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. Power is the measure of how fast work can be done. The unit of power is watts (W), which can be defined as the amount of work done in one second.

Power is usually calculated as the product of the amount of work done and the time it takes to do it. Power can also be defined as the rate at which work is done.First, we need to calculate the work done by the engine. Work = Force x distance . Since the boat moves at a constant speed of 15 m/s, we can use the following formula to calculate the distance traveled by the boat:Distance = Speed x TimeTherefore, distance = 15 m/s x 1 s = 15 m Now we can calculate the work done by the engine:Work = Force x Distance = 6.0 kN x 15 m = 90 kJNow that we know the amount of work done by the engine, we can use the formula for power:Power = Work/Time Since we don't know the time it took the engine to do the work, we can't calculate power directly. However, we can make some assumptions and estimate the time it took the engine to do the work. For example, if we assume that the engine did the work in one minute, then the time is 60 seconds:Power = Work/Time = 90 kJ/60 s = 1.5 kWTherefore, the power developed by the boat engine is 1.5 kW.

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A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)

Answers

Answer:

T= 0.6 sec

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

This doesn’t make sense, there is no angle so I can’t use Fnet=mgcos(theta) and can’t find acceleration in a=mgsin(theta).

This doesnt make sense, there is no angle so I cant use Fnet=mgcos(theta) and cant find acceleration

Answers

The magnitude of the net force on the block while it is sliding is 9.8 N.

What is the angle of inclination of the plane?

The angle of inclination of the plane is calculated by applying the principle of trigonometry ratio.

Considering the vertical height (10 m) and length of the incline (20 m);

sin θ = 10 m / 20 m

sin θ = 1/2

sin θ = 0.5

θ = arc sin(0.5)

θ  = 30⁰

The magnitude of the net force on the block while it is sliding is calculated as follows;

F(║) = F(net) = mg sinθ

where;

m is mass of the blockg is acceleration due to gravityF(║)  implies parallel force, since there is no friction on the incline

F(net) = (2 x 9.8) x sin(30)

F(net) = 9.8 N

Thus, the net force on the block is the parallel component of the weight of the block.

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Which person below is likely to have better health?
A. Jenna, who is optimistic about life
B. Albert, who thinks that events in his life are not in his control
C. Peter, who is depressed
D. Claire, who blames everyone else for her circumstances
SUBMIT

Answers

A. Jenna because an optimistic person always has a healthier look in life!

Jenna, who is optimistic about life, is likely to have better health. Hence, option (A) is correct.

What is mental health?

Mental health affects cognition, perception, and behavior and includes emotional, psychological, and social well-being. It also affects how someone responds to stress, interacts with others, and makes decisions.

Subjective well-being, perceived self-efficacy, autonomy, competence, generational reliance, and self-actualization of one's intellectual and emotional potential are only a few examples of what is considered to be mental health.

The ability to enjoy life and strike a balance between daily activities and endeavors to develop psychological resilience may be considered a sign of mental health from the viewpoints of positive psychology or holistic approaches.

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afootball of mass 550g is at rest on the ground the football is kicked with a force of 108 newton the footballers boot is in contact with the ball for 0.3 minute what is the kenitic

energy of the ball​

Answers

If "0.3 minute" is correct, then it's 9,543,272 Joules.

If it's supposed to say "0.3 SECOND", then the KE is 2,651 Joules.

The length of a hollow pipe is 297 cm. The
air column in the pipe is vibrating and has
five nodes.
Find the frequency of the sound wave in the
pipe. The speed of sound in air is 343 m/s.
Answer in units of Hz.

Answers

The frequency of sound in the pipe is 231 Hz.

What is the frequency of sound in the pipe?

The frequency of sound in the pipe is calculated as follows;

N - N = λ/2

The total length of nodes, L = 4 (N - N) = 4 (λ/2)

L = 2λ

λ = L/2

The relationship between, frequency, speed and wavelength of sound is given as;'

f = v/λ

f = ( 343 m/s )/ (2.97 m / 2)

f = 231 Hz

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Ammonia is a common____?

Answers

Answer:

Base

Hope this helps! :)

Ammonia (NH3) is a common toxicant derived from wastes (see Figure 1), fertilizers and natural processes. Ammonia nitrogen includes both the ionized form (ammonium, NH4+) and the unionized form (ammonia, NH3). ... Temperature also affects the toxicity of ammonia to aquatic life.

What is the kinetic energy of a 150 kg object that is moving at a speed of 5
m/s?

Answers

Answer:

Kinetic Energy=1/2×m×v^2,Where m=mass,v=velocity. So, kinetic energy of the object=1/2×150×15^2 = 16875 kg m^2 s^-2 .

Explanation:

math lol

A jogger runs 6.0 km [E], then 4.0 km [N], and finally 2.0 km [W]. The entire trip takes 2.0 h to complete. Calculate the jogger's
(a) average speed
(b) average velocity

Answers

(a) The trip covers a total distance of 6.0 + 4.0 + 2.0 = 12.0 km, so the jogger's average speed is (12.0 km)/(2.0 h) = 6.0 km/h.

(b) The jogger undergoes a total displacement given by the vector

(6.0 km) i + (4.0 km) j + (-2.0 km) i = (4.0 km) (i + j)

where i is the unit vector pointing due East and j is the unit vector pointing due North. This vector has magnitude

||(4.0 km) (i + j)|| = (4.0 km) √(1² + 1²) ≈ 5.7 km

so the jogger's average velocity is approximately (5.7 km)/(2.0 h) ≈ 2.8 km/h.

An electric motor is used to lift a load. When 7000 J of electrical energy are supplied to the motor the load gains 3100 J of gravitational potential energy. The amount of wasted energy by the motor is

Answers

Answer:

W = 3900 J

Explanation:

Given that,

Electrical energy supplied = 7000 J

Gain in gravitational potential energy = 3100 J

We need to find the amount of wasted energy. Let it is W. So,

W = 7000 J - 3100 J

= 3900 J

So, the amount of wasted energy by the motor is 3900 J.

A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T.

If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?

9.1 × 10–5 m/s
1.3 × 10–4 m/s
7.6 × 103 m/s
1.1 × 104 m/s

Answers

Answer:

the correct answer is D

Explanation:

Identify the smallest measurement.
a) attometer
b) nanometer
c) centimeter
d) megameter
e) petameter

Answers

Answer:

Attometer

Explanation:

an attometer is the smallest unit of measurement.

Hope it helped!

Solve it pleaseeeeeeeee

Solve it pleaseeeeeeeee

Answers

The force exerted to push the 25 Kg wooden box across the wooden floor at a constant speed of 1.0 m/s is 49 N (2nd option)

How do i determine the force exerted?

Frictional force is given by the following formula

Frictional force = coefficient of friction (μ) × normal reaction (N)

Since the speed is constant,

Frictional force = Force exerted

Thus,

Force exerted = coefficient of friction (μ) × normal reaction (N)

F = μN

Now, we shall determine the force exerted to push the box. Details below:

Mass of box (m) = 25 KgCoefficient of friction (μ) = 0.2Acceleration due to gravity (g) = 9.8 m/s² Normal reaction (N) = mg = 25 × 9.8 = 245 NForce exerted (F) =?

F = μN

F = 0.2× 245

F = 49 N

Thus, the force exerted to push the box is 49 N (2nd option)

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Electromagnetic waves are made by vibrating electric charges and can travel through what​

Answers

Answer:

vibrates, and they carry energy from one place to another. Look at the sound wave and the water wave. vibrating electric charges and can travel through space where matter is not present. to particle, electromagnetic waves travel by transferring energy between vibrating electric and magnetic fields.

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