A goat is tired to a pole at the center of a square of length of side 20m. If the rope is 10m long. Calculate the (I) area of the square that can't be grazed by the goat (ii) fraction of grazed portion to the whole area​

Answer:

Step-by-step explanation:

Formula

Area = 1/2 (b1 + b2)*h

Givens

b1 = 11 m

b2 = 13 m

Area = 96

h = ?

Solution

96 = 1/2 (11 + 13) * h      Multiply by 2     Combine the bases as well.

96*2 = (24) * h              Divide by 24

96*2/24 = h                  Multiply by 2 and divide by 24

h = 8

Answer:

An average Ilama weighs 160 kilograms and an average okapi weighs 290 kilograms.

Step-by-step explanation:

Let,

x be the average weight of a Ilamas

y be the average weight of an okapi

According to given statement;

x + y = 450     Eqn 1

3x = y + 190   Eqn 2

From Eqn 2

y = 3x - 190     Eqn 3

Putting this value of y in Eqn 1

x + (3x-190) = 450

x + 3x - 190 = 450

4x = 450 + 190

4x = 640

Dividing both sides by 4

\(\frac{4x}{4}=\frac{640}{4}\\x=160\\\)

Putting x = 160 in Eqn 3

y = 3(160) - 190

y = 480 - 190

y = 290

Hence,

An average Ilama weighs 160 kilograms and an average okapi weighs 290 kilograms.

The probability that a randomly selected student plays a sport, given

that the student is a senior is A. 0.32

Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.

This is a case of conditional probability and we know,

Conditional probability is a term used in probability theory to describe the likelihood that one event will follow another given the occurrence of another event.

Given, At a high school, the probability that a student is a senior is 0.25

and the probability that a student is a senior and plays a sport is 0.08.

Therefore, The probability that a randomly selected student plays a sport, given that the student is a senior is,

= 0.08/0.25.

= 0.32

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The relationship between the distance that birds fly in relation to the time they do so, is positive.

There are about 3 outliers but for the most part, the relationship is positive.

The graph which shows the distance that birds fly in relation to the time they do, shows that there is a positive relationship because as the time increases, the distance that the birds have flown also increases.

There are some outliers such as the bird that flew 1 mile in 7 hours but in general, as the time increases, the distance increases as well. There are two clusters of distance as well.

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The correct answer is, by choosing a = -2 and b = 1, we satisfy both inequalities .a < b:

To make both inequalities true, we need to select values for a and b that satisfy the given conditions:

a < b: This inequality means that the value of a should be less than the value of b.

|b| < |a|: This inequality means that the absolute value of b should be less than the absolute value of a.

One possible solution that satisfies both conditions is:

a = -2

b = 1

With these values, we have:

-2 < 1 (a < b)

|-1| < |2| (|b| < |a|)

Therefore, by choosing a = -2 and b = 1, we satisfy both inequalities.a < b:

This inequality states that the value of a should be less than the value of b. In other words, a needs to be positioned to the left of b on the number line. To satisfy this condition, we can choose a to be any number that is less than b. In the example I provided, a = -2 and b = 1, we can see that -2 is indeed less than 1, fulfilling the requirement.

|b| < |a|:

This inequality involves the absolute values of a and b. The absolute value of a number is its distance from zero on the number line, always resulting in a non-negative value. The inequality states that the absolute value of b should be less than the absolute value of a. To satisfy this condition, we can choose b to be any number with a smaller absolute value than a. In the example I provided, |1| is less than |(-2)|, as 1 is closer to zero than -2, fulfilling the requirement.

By selecting a = -2 and b = 1, we satisfy both inequalities: a < b and |b| < |a|. The specific values of -2 and 1 were chosen as an example, but there are multiple other values that would also satisfy the given conditions. The important aspect is that a is indeed less than b, and the absolute value of b is smaller than the absolute value of a.

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Answer:

y=1x-6

Step-by-step explanation:

First we find the slope by using rise over run. So you can either count up and over(rise/run) or use the slope formula y2-y1/x2-x1. You will find that the slope is 1, so plug that into the equation for mx. So we have y=1x so far. Then we find the y-intercept by looking where the graph intersects the y-axis. As you can see it intersects at -6, so plug -6 into the equation for b. No we have our full equation of y=1x-6.

-Hope this helped

The equation of the circle that has a diameter with endpoints located at (0, –3) and (6, 5) is;

The midpoint of the diameter of a circle is it's center.

As such; the coordinates of its center are;

The coordinates of the center are then; (3, 1)

The radius of a circle is half the length of the diameter;

Therefore, radius, r = 10/2 = 5.

Therefore, the equation of the circle usually takes the form;

In this scenario; the equation is;

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To prove that line segment a is parallel to line segment d, based on the given information, we can utilize the properties of perpendicular and parallel lines.

Given that a is perpendicular to b and b is perpendicular to c, we know that angles formed between a and b, as well as between b and c, are right angles. Let's denote these angles as ∠1 and ∠2, respectively.

Now, since c is parallel to d, we can conclude that the corresponding angles ∠2 and ∠3, formed between c and d, are congruent.Considering the fact that ∠2 is a right angle, it can be inferred that ∠3 is also a right angle.

By transitivity, if ∠1 is a right angle and ∠3 is a right angle, then ∠1 and ∠3 are congruent.Since corresponding angles are congruent, and ∠1 and ∠3 are congruent, we can deduce that line segment a is parallel to line segment d.

Thus, we have successfully proven that a is parallel to d based on the given information and the properties of perpendicular and parallel lines.

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Answer: \(215\ cm^2\)

Step-by-step explanation:

Given

Here the given figure can be divided into two shapes i.e. rectangle and a trapezium

For rectangle ABCD Area = \(10\times8=80\ cm^2\)

Area of trapezium CEFD Area is \(\frac{1}{2}[\text{sum of non-parallel sides}]\times[\text{distance between them}]\)

\(\Rightarrow \frac{1}{2}\times [10+17][10]=135\ cm^2\)

Total shaded area \(=80+135=215\ cm^2\)

Answer:

2x-3y<-9

Step-by-step explanation:

9514 1404 393

Answer:

  20 square centimeters

Step-by-step explanation:

The area of the dilated figure is the original area multiplied by the square of the dilation factor. The center of dilation is irrelevant.

  dilated area = (1/2)² × original area

  dilated area = 1/4 × 80 cm²

  dilated area = 20 cm²

Answer:

Brand A

Step-by-step explanation:

Brand A has a box of 25 forks for 1.99

Take the price per fork

1.99 /25 = .0796

              .08 per fork

Brand B has a box of 42 totals for 3.89

3.89 / 42

.092319048

.09 per fork

From the constraint, we have

\(x+y+z=9 \implies z = 9-x-y\)

so that \(s\) depends only on \(x,y\).

\(s = g(x,y) = xy + y(9-x-y) + x(9-x-y) = 9y - y^2 + 9x - x^2 - xy\)

Find the critical points of \(g\).

\(\dfrac{\partial g}{\partial x} = 9 - 2x - y = 0 \implies 2x + y = 9\)

\(\dfrac{\partial g}{\partial y} = 9 - 2y - x = 0\)

Using the given constraint again, we have the condition

\(x+y+z = 2x+y \implies x=z\)

so that

\(x = 9 - x - y \implies y = 9 - 2x\)

and \(s\) depends only on \(x\).

\(s = h(x) = 9(9-2x) - (9-2x)^2 + 9x - x^2 - x(9-2x) = 18x - 3x^2\)

Find the critical points of \(h\).

\(\dfrac{dh}{dx} = 18 - 6x = 0 \implies x=3\)

It follows that \(y = 9-2\cdot3 = 3\) and \(z=3\), so the only critical point of \(s\) is at (3, 3, 3).

Differentiate \(h\) again and check the sign of the second derivative at the critical point.

\(\dfrac{d^2h}{dx^2} = -6 < 0\)

for all \(x\), which indicates a maximum.

We find that

\(\max\left\{xy+yz+xz \mid x+y+z=9\right\} = \boxed{27} \text{ at } (x,y,z) = (3,3,3)\)

The second derivative at the critical point exists

\($\frac{d^{2} h}{d x^{2}}=-6 < 0\) for all x, which suggests a maximum.

Given, the constraint, we have

x + y + z = 9

⇒ z = 9 - x - y

Let s depend only on x, y.

s = g(x, y)

= xy + y(9 - x - y) + x(9 - x - y)

= 9y - y² + 9x - x² - xy

To estimate the critical points of g.

\($&\frac{\partial g}{\partial x}\) = 9 - 2x - y = 0

\($&\frac{\partial g}{\partial y}\) = 9 - 2y - x = 0

Utilizing the given constraint again,

x + y + z = 2x + y

⇒ x = z

x = 9 - x - y  

⇒ y = 9 - 2x, and s depends only on x.

s = h(x) = 9(9 - 2x) - (9 - 2x)² + 9x - x² - x(9 - 2x) = 18x - 3x²

To estimate the critical points of h.

\($\frac{d h}{d x}=18-6 x=0\)

⇒ x = 3

It pursues that y = 9 - 2 \(*\) 3 = 3 and z = 3, so the only critical point of s exists at (3, 3, 3).

Differentiate h again and review the sign of the second derivative at the critical point.

\($\frac{d^{2} h}{d x^{2}}=-6 < 0\)

for all x, which suggests a maximum.

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Answer:

whats the question?

Step-by-step explanation:

Answer:

2,437.05

Step-by-step explanation:

h: The domain

-5 ≤ x ≤ 5

Answer:

Step-by-step explanation:

It is a vertical section and the figure formed from the cross-section is:

Correct choice is B

The vertical displacement is of 2 units down, the correct option is B.

Remember that for a function f(x), a vertical displacement of N units is written in general form as:

g(x) = f(x) + N

If N > 0, the translation is upwards.

if N < 0, the translation is downwards.

Here we assume that we start with the parent cosine function:

y = cos(x)

And the transformed function is:

y = -2 - cos(x - π)

So we have some transformations, but the vertical translation is of 2 units down. So the correct option is B.

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Answer:

1600

please see the attached picture for full solution

Hope it helps...

The relationship between the dates of spread and the number of people infected can vary depending on various factors such as the infectiousness of the disease, the effectiveness of containment measures, population density, and individual behaviors.

However, there is a general rule that can describe the relationship:As the dates of spread progress, the number of infected individuals tends to increase initially, reaching a peak, and then gradually decreasing over time.

This pattern is often referred to as the epidemic curve or the epidemiological curve. In the early stages of an outbreak, the number of cases may grow rapidly as the disease spreads through a susceptible population. This rapid increase is often influenced by factors such as the contagiousness of the disease, population density, and social interactions.

As containment measures, such as vaccination campaigns, public health interventions, and behavioral changes, are implemented, the rate of new infections may start to decline. This can lead to a peak in the number of cases, after which the curve gradually decreases as the disease is brought under control and fewer susceptible individuals remain.

It's important to note that the specific shape, duration, and magnitude of the epidemic curve can vary significantly depending on the disease and the effectiveness of the response measures implemented. Additionally, emerging variants, changes in behavior, and other factors can impact the trajectory of the epidemic curve.

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The value of the z-score for the number 15  in a data set is 0.93.

Define z-score.

A data point's z-score, also known as a standard score, indicates how far it deviates from the mean. In practical terms, however, it's a measurement of how many standard deviations a raw number is from or above the population mean.

You can plot a z-score on a normal distribution graph. Z-scores can be anywhere between -3 and +3 standard deviations.

                     ∴  z = (x – μ) / σ

Given:

σ = 4.32

x = 15

Data set: 5, 7, 9, 11, 13, 15, 17

So, mean = 5 + 7 + 9 + 11 + 13 + 15 + 17/7

                = 77/7

            μ = 11

z = (x – μ) / σ

  = (15 - 11)/4.32

   = 4/4.32

z  = 0.93

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Answer:

\(the \: answer \: is \: \\ y - 7 = 1(x - 4) \\ y - 7 = x - 4 \\ or \: in \: other \: way \: \\ y = x+ 3\)

The equation of the line in the standard form exists 3x - y = 2.

The equation of a line is a representation of a line on an x-y plane that illustrates the relationship between x and y for each point on the specific line. When x and y are variables and a, b, and c are constants, a line has the standard form ax + by = c.

Y = mx + b is the slope-intercept form of a line, where x and y are variables, m is the line's slope, and b is the line's y-intercept.

The one-point formula reads: y - y₁ = m(x - x₁). to describe the equation of a line traveling through the point (x1, y1) and having a slope of m.

We are asked to graph a line with a slope = -3, passing through the point (1, -5).

We use the one-point formula to determine the equation of this line, with slope m = -3, (x₁, y₁) = (1, -5).

Substituting these values in the equation y - y₁ = m(x - x₁), we get

Let the equation be y - -5 = -3(x - 1)

simplifying the equation, we get

y = -3x + 3 - 5

y = -3x - 2

3x - y = 2

The equation of the line in the slope-intercept form exists y = -3x - 2

The equation of the line in the standard form exists 3x - y = 2.

We draw the locations (1,-5) (because it is obvious that the line goes through this location) and (0, 2) (since the y-intercept is at 2 and the line passes through the point (0, 2)) in order to graph this line. We draw a line connecting these places, then we expand it on both sides to create the necessary line.

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Answer: A) max at (14, 6) = 64,   min at (0,0) = 0

Step-by-step explanation:

Graph the lines at look for the points of intersection.

Input those points into the Constraint function (2x + 6y) and look for the maximum value and minimum value.

Points of Intersection: (0, 0), (17, 0), (0, 10), (14, 6)

Point     Constraint 2x + 6y

(0, 0):                    2(0) + 6(0) = 0              Minimum

(17, 0):                    2(17) + 6(0) = 34

(0, 10):                    2(0) + 6(10) = 60

(14, 6):                    2(14) + 6(6) = 64           Maximum

Answer:

Step-by-step explanation:

For one cake= 2/3 dozen

for 6 cakes= 2/3x6=4 dozen

Answer:

A. 16% of scores are at his/her score or below

Step-by-step explanation:

When a student's score is at the 16th percentile, it means that their score is equal to or better than 16% of the scores in the population. In other words, 16% of the scores are at their score or below.

Answer:

$32,000

Step-by-step explanation:

From the information given, the equation would indicate that the total salary is equal to the base salary plus the result of subtracting $7,000 from the amount of sales for 8%:

1,000+(x-7,000)*0.08=3,000, where x is the amount of sales

Now, you can solve for x:

1,000+0.08x-560=3,000

0.08x+440=3,000

0.08x=3,000-440

x=2,560/0.08

x=32,000

According to this, the answer is that the employee must sell $32,000 in one month to earn a total of $3,000 for the month.

Answer:

Step-by-step explanation:

To calculate the reorder level of component X, we need to find out the average weekly consumption of X.

Average consumption of X per unit of 'RED' = 0.4 kg

Average weekly production of 'RED' = 400 units

Average weekly consumption of X for producing 400 units of 'RED' = 0.4 kg/unit x 400 units/week = 160 kg/week

Assuming lead time of 3 weeks for delivery of X, the reorder level of X would be:

Reorder level of X = Average weekly consumption of X x Lead time for delivery of X

Reorder level of X = 160 kg/week x 3 weeks = 480 kg

To calculate the maximum level of X, we need to take into account the economic order quantity and the maximum storage capacity.

Economic order quantity of X = Square root of [(2 x Annual consumption of X x Ordering cost per order) / Cost per unit of X]

Assuming 52 weeks in a year:

Annual consumption of X = Average weekly consumption of X x 52 weeks/year = 160 kg/week x 52 weeks/year = 8,320 kg/year

Ordering cost per order of X = 600

Cost per unit of X = 1

Economic order quantity of X = Square root of [(2 x 8,320 kg x 600) / 1] = 2,771.28 kg (approx.)

Maximum storage capacity of X = Economic order quantity of X + Safety stock - Average weekly consumption x Maximum lead time

Assuming a safety stock of 20% of the economic order quantity and a maximum lead time of 3 weeks:

Maximum storage capacity of X = 2,771.28 kg + (0.2 x 2,771.28 kg) - (160 kg/week x 3 weeks) = 2,815.82 kg (approx.)

To calculate the maximum level of Y, we follow the same approach as for X:

Annual consumption of Y = Average weekly consumption of Y x 52 weeks/year

Average consumption of Y per unit of 'RED' = 0.6 kg

Average weekly consumption of Y for producing 400 units of 'RED' = 0.6 kg/unit x 400 units/week = 240 kg/week

Annual consumption of Y = 240 kg/week x 52 weeks/year = 12,480 kg/year

Economic order quantity of Y = Square root of [(2 x Annual consumption of Y x Ordering cost per order) / Cost per unit of Y]

Ordering cost per order of Y = 1,000

Cost per unit of Y = 1.5

Economic order quantity of Y = Square root of [(2 x 12,480 kg x 1,000) / 1.5] = 915.65 kg (approx.)

Maximum storage capacity of Y = Economic order quantity of Y + Safety stock - Average weekly consumption x Maximum lead time

Assuming a safety stock of 20% of the economic order quantity and a maximum lead time of 3 weeks:

Maximum storage capacity of Y = 915.65 kg + (0.2 x 915.65 kg) - (240 kg/week x 3 weeks) = 732.52 kg (approx.)

The missing ordered pairs that satisfy the equation y = 2x + 4 are (3, 10) and (2, 8).

The equation given is y = 2x + 4. To compute the missing x and y values, we need to substitute the given ordered pairs into the equation and solve for the missing variable.

Let's assume we have an ordered pair (x, y) that satisfies the equation y = 2x + 4.

For example, let's say one missing value is x = 3. We can substitute this into the equation:

y = 2(3) + 4

y = 6 + 4

y = 10

So, the missing ordered pair is (3, 10).

Similarly, if another missing value is y = 8, we can substitute this into the equation and solve for x:

8 = 2x + 4

4 = 2x

x = 2

So, the missing ordered pair is (2, 8).

In summary, the missing x and y values that satisfy the equation y = 2x + 4 are (3, 10) and (2, 8).

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