A grating has 2000 slits/cm/cm. How many full spectral orders can be seen (400 to 700 nmnm) when it is illuminated by white light

Answer: They will be clear

Explanation:

When hydrochloric acid (HCl) is mixed with sodium hydroxide (NaOH), a neutralization reaction occurs, and the products of the reaction are sodium chloride (NaCl) and water (H2O).

The chemical equation for this reaction is:

HCl + NaOH → NaCl + H2O

Sodium chloride is a salt that is commonly used in cooking and as a de-icing agent, while water is a familiar and essential compound that we use every day.

NaCl and water  can be a clear solution but it is not coorrosive and a new salt is formed thus it does not retain any properties of the initial reactants.

Answer:

1. The expansion rate of the universe, often measured using the Hubble Constant.

2. The cooling of the cosmic microwave background radiation.

3. The chemical abundances of light elements like helium and deuterium.

4. The abundance of elements heavier than hydrogen and helium created by stellar nucleosynthesis.

5. The redshift of galaxies and other distant objects.

Explanation:

It is possible to study the connection between motivation, rewards, and production from a variety of angles, including those of economics, psychology, and physics.

Because producers are motivated to satisfy consumer demand, free markets offer a larger variety of commodities than any other system. What is created is under the control of the consumer.

In theory, free markets work best because supply and demand are efficiently distributed by an invisible hand. Yet, in practise, open markets are prone to manipulation, false information, and imbalances of power and knowledge, which also contribute to wealth disparity.

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22920 years old is an artifact if four half-lives have occurred and the half-live of carbon-14 is 5730 years.

Due to radioactive decay to nitrogen-14, carbon-14 has a very short half-life of 5,730 years, which means that over this time, the proportion of carbon-14 in a sample will have decreased by 50%.

A half-life is the amount of time it takes for something to go from 100% to 50%. The phrase is most frequently used in reference to radioactive decay, which happens when energetic atomic particles that are unstable lose momentum.

The half-life of carbon-14 is 5730 years. Accordingly, a sample of 100 carbon-14 atoms has a half-life of 5730 years, or 50 carbon-14 and 50 carbon-12 (i.e., 100 carbon-14, one half-life = 50 carbon-14, 50 carbon-12).

4 half lives

=5730×4

=22,920 years old.

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Answer:

\(\displaystyle F = 150 \ N\)

General Formulas and Concepts:

Dynamics

Explanation:

We are given the following variables:

m = 50 kg

a = 3 m/s²

To find the object's force, we use Newton's Second Law of Motion. Plug in your variables into the equation:

F = (50 kg)(3 m/s²)

F = 150 kg · m/s²

F = 150 N

Topic: AP Physics 1 - Algebra Based

Unit: Dynamics

\(\huge\mathfrak{\fcolorbox{aqua}{lime}{Answer}}\)

Given :

\(Mass\:\: is\: \:50\: \:kg \:\)

\(Acceleration\: = \:{3m/s}^{2}\)

while finding force make sure that mass is in (Kg) and acceleration is in (m/s²)

\(Force\:=\:ma\)

\( Force\:=\:50kg\:×\:{3m/s}^{2}\)

\( Force\:=\:150 \:N \)

Answer:

0.705 kg less

Explanation:

Altitude at sea level = 0 ft

Altitude after climbing = 30,000 ft = 30,000 x 0.3048 = 9,144 m

Weight = W = mg

Change in weight = ΔW = (M-luggage) × (g-sea level - g-altitude)

g at sea level:

g1 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth)²

g at altitude of 30,000 ft:

g2 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth + Altitude)²

Gravitational constant = 6.674 × 10^-11 m^3 kg^-1 s^-2

g1 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6)^2

g1 ≈ 9.8358 m/s^2

g2 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6 + 9,144)^2

g2 ≈ 9.8076 m/s^2

ΔW = (M-luggage) × (g1 - g2)

= 25 kg × (9.8358 - 9.8076)

≈ 0.705 kg

Therefore, your luggage would weigh approximately 0.705 kg less when you climb to 30,000 ft compared to its weight at the airport.

Can't guarantee this is right, but I checked the numbers a few times and this is the best I can do!

Answer:

I've attached a screenshot of a document from K12 that should give you the answer to your question, and many more question you might have. If this is not helpful please say so in the replies to this answer and I'll try my best to find some more information.

Explanation:

May I have brainliest please? :)

Answer:

so you have your boxes go by tens on the x-axis okay which is the one going straight up then the second number goes by 5's is your y-axis. 30,6 so 30 is your x and 6 is your y. start at 0,0 which is the little corner piece. find 30 on x and then go over 6 and that's it!

Explanation:

Answer:

Well velocity is the varaible with direction

Explanation:

In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

Answer:

Explanation:

We can use the inverse-square law of universal gravitation to determine the weight of the missile at an altitude of 6.4 x 10^6 m. The law states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Let M be the mass of the Earth and m be the mass of the missile. At the Earth's surface, the weight of the missile is:

F1 = mg

where g is the acceleration due to gravity on the Earth's surface, which we assume to be 9.81 m/s^2.

At an altitude of 6.4 x 10^6 m, the distance between the center of the Earth and the missile is:

r = R + h

where R is the radius of the Earth (6.4 x 10^6 m) and h is the altitude of the missile (6.4 x 10^6 m).

The weight of the missile at this altitude can be calculated using the inverse-square law of universal gravitation:

F2 = G * M * m / r^2

where G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2).

Substituting the given values, we get:

F2 = (6.6743 x 10^-11 N * m^2 / kg^2) * (5.97 x 10^24 kg) * (400 N) / (6.4 x 10^6 m + 6.4 x 10^6 m)^2

F2 = 39.61 N

Therefore, the weight of the missile at an altitude of 6.4 x 10^6 m is approximately 39.61 N.

The correct answer is: a non-contact force from a magnet on a magnetic material, which is the second option, as magnetic force refers to the force exerted by a magnet on a magnetic material. It is a non-contact force, meaning it can act on objects without physical contact.

Magnets have two poles, a north pole and a south pole, and they exert forces on other magnets or magnetic materials. Like poles (north-north or south-south) repel each other, while opposite poles (north-south) attract each other. This magnetic force is responsible for various phenomena, such as the attraction and repulsion between magnets, the alignment of magnetic materials, and the operation of magnetic devices like motors and generators.

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The coefficient of static friction between the block of wood and the table is 0.449.

The weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.

The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.

Since the block is not accelerating vertically, we know that N = Mg, so we have:

μs = fs/N = 17.64 N / 39.24 N = 0.449

Therefore, the coefficient of static friction between the block of wood and the table is 0.449.

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2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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Answer:

Maximum height = 2040 m

Explanation:

We can solve the problem using kinematics.

Consider the vertical motion of the object and use the equation:

\(\boxed{v^2 = u^2 + 2as}\)

where:

• v = final velocity      (0 m/s, because when the object is at max. height, it has no vertical velocity)

• u = initial velocity    (400sin30° m/s ⇒ vertical component of 400 m/s at 30° to horizontal)

• a = acceleration      (-9.81 m/s²; considering upward acceleration to be negative)

• s = displacement    (? m; this represents the max. height of the object),

Substitute the values into the equation and solve for s :

\(0^2 = (400 sin (30 \textdegree))^2 + 2(-9.81)(s)\)

⇒ \(2(9.81)(s) = (400 sin (30 \textdegree))^2\)

⇒  \(s = 2040 \space\ m\)     (3 s.f.)

The sentence that best describes the motion is "the motion is a circular motion and has completed one revolution".

Question: "If a car moved one full circular track of 15 Km, which sentence describes its motion?​"

An object moves in a circle at a constant speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is spinning continuously, is moving uniformly in circles.

There are two types of circular motion: uniform and non-uniform.

Circular motion can be seen in the orbit of a satellite, ice skaters moving at a constant speed in a circle, and vehicles traveling in a circle.

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Answer:

\(P=45.2W\)

Explanation:

From the question we are told that:

Amplitude \(A=0.56m\)

Period \(T=3.4s\)

Wavelength \(\lambda=2.0\)

Area \(a=0.14m^2\)

Generally the equation for Power is mathematically given by

\(Power = 2 \pi ^2 \rho a(\frac{\lambda}{T})(\frac{1}{T})*A\)

\(P= 2 3.142^2 1025 0.14(\frac{2.0}{3.4})(\frac{1}{3.4})^2*0.56^2\)

\(P=45.2W\)

Answer:

The charge flowing through the filament is 0.08C

Explanation:

\(I=20mA = 0.02A\\t= 4s\\\)

Plug your given values into the charge and current formula:

\(I=\frac{Q}{t} \\Q=I*t\\Q= (0.02A)(4s)\\Q= 0.08C\)

The average acceleration of the bus is −6.00 m/s².

a = ? ; Δt = 1.50 s ; v1 = 9.00 m/s ; v2 = 0.00m/s

The formula to use in this case is the definition of acceleration stating that the acceleration a = Δv / Δt or a = (v2- v1) / Δt where v2 is the final velocity and v1 is the initial velocity.

Solving for the acceleration a

a = (v2- v1) / Δt

a = (0 - 9.00 m/s) / 1.50 s

a = - 9.00 m/s / 1.50 s

a = −6.00 m/s^2

The average acceleration of the bus is −6.00 m/s^2.

The complete question is,
When a bus comes to a sudden stop to avoid hitting a dog, it slows from 9.00 m/s to 0.00m/s in 1.50 seconds. What is the average acceleration of the bus?

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Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

Answer:

2.1m/s towards your grandmother's house

Explanation:

Given parameters:

Time taken  = 204s

Distance  = 430m

Unknown:

Velocity  = ?

Solution:

The velocity is determined by:

    Velocity  = \(\frac{displacement}{time}\)  

   Velocity  = \(\frac{430}{204}\)   = 2.1m/s towards your grandmother's house

Answer:

Force acting on a body of mass 7 kg which produces an accceleration of 10 m/s2 is 70 N

Answer:

10 m/s2 or 70 newtons.

Explanation:

............................

............

ANSWER

EXPLANATION

The distance for the car is the total space between the start of the journey and the end i. e. the amount of space the car covers in its 100 laps.

Therefore, the car's distance is:

The displacement of the car is the measure of change in the position of the car.

Since the car returns to its starting position after 100 laps, there is no change from the original position of the car, hence , its displacement is:

Answer:

D

Explanation:

Answer:

Wl = 1740 N

Explanation:

maximum lift weight unaided = force exerted (F) = 650 N

length of the wheelbarrow (L) = 1.4 m

weight of the wheelbarrow (w) = 80 N

distance of center of gravity of the wheel barrow from the wheel = 0.5 m

distance of center of gravity of the load from the wheel = 0.5 m

find the weight of the load (Wl)

from the diagram attached we can see that there is going to be a rotation about the axis A. let clockwise rotation be positive

ΣT = (F x 1.4) - ((Wl x 0.5) + (w x 0.5) = 0

(F x 1.4) = ((Wl x 0.5) + (w x 0.5)

Wl =

Wl =

Wl = 1740 N

Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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