Answer:
\(\$0.26\) has to be paid more if the coupon is applied first
Step-by-step explanation:
Given: A grocery store has a discount of 13% off hand soap. At the same time the hand soap manufacturer has a coupon for $2.00 off.
To find: how much more would be paid if the coupon is applied first
Solution:
Let $ x denotes cost of hand soap
Case 1:
If the discount is given first,
cost of hand soap = \(x-\frac{13}{100} x=\$ \frac{87}{100}x\)
If the coupon for $2.00 off is applied,
Final cost of the hand soap = \(\$\,(\frac{87}{100}x-2)\)
Case 2:
If the coupon for $2.00 off is applied first,
cost of hand soap = \(\$(x-2)\)
If the discount is given then,
final cost of the hand soap = \((x-2)-\frac{13}{100}(x-2)=\frac{87}{100}(x-2)\) = \(\frac{87}{100}x-\frac{87}{50}\)
Here,
\(\frac{87}{100}x-\frac{87}{50}-\frac{87}{100}x+2=\frac{13}{50}=\$0.26\)
So, \(\$0.26\) has to be paid more if the coupon is applied first.
Answer:
$0.26
Step-by-step explanation: I took the test
f(x) = 3x+2
What is f(5)?
F(5)= 3.(5)+2=15+2=17
Another example: F(0)=3.(0)+2=0+2=2
You just replace the value in the two sides.
what expression gives the solution to -5+2x^2=-6x
Answer:
Step-by-step explanation:
2x² + 6x - 5 = 0
D = 36 + 40 = 76 = (2√19)²
\(x_{1}\) = ( - 6 - 2√19) / 4 = ( - 3 - √19) / 2
\(x_{2}\) = ( - 3 + √19) / 2
hellllllllpppppppppppppppppppppp
                                                Answer:他の答えを別の答えに移すことができ、それからミーズビルへの答えを得ることができるとき、それは数学の問題だと自分に言い聞かせてください。
Step-by-step explanation:there
lowest common factor of 72 and 108
Answer:
The lowest common factor of 72 and 108 is 216
Find the value of x. 
x = ___
                                                
                                                            A man gave 5/12 of his money to his son , 3/7 of the remainder to his daughter and the remaining to his wife if his wife gets rs 8700 what is the total amount
The total amount the man had = 52,200 rupees. Out of this, he gave 21,750 rupees to his son, 13,050 rupees to his daughter, and 17,400 rupees to his wife , the total amount given away by the man = 21,750 + 13,050 + 17,400 = 52,200 rupees.
A man gave 5/12 of his money to his son, 3/7 of the remainder to his daughter, and the remaining to his wife. If his wife gets Rs. 8,700, what is the total amount?
The given problem can be solved using the concept of ratios and fractions. Let us solve the problem step-by-step.Assume the man had x rupees with him.The man gave 5/12 of his money to his son.
The remaining amount left with the man = x - 5x/12= (12x/12) - (5x/12) = (7x/12)The man gave 3/7 of the remainder to his daughter.'
Amount left with the man after giving it to his son = (7x/12)The amount given to the daughter = (3/7) x (7x/12)= (3x/4)The remaining amount left with the man = (7x/12) - (3x/4)= (7x/12) - (9x/12) = - (2x/12) = - (x/6) (As the man has given more money than what he had with him).
Therefore, the daughter's amount is (3x/4) and the remaining amount left with the man is (x/6).The man gave all the remaining amount to his wife.
Therefore, the amount given to the wife is (x/6) = 8700Let us find the value of x.x/6 = 8700 x = 6 x 8700 = 52,200
Therefore, the man had 52,200 rupees with him.He gave 5/12 of his money to his son. Therefore, the amount given to his son is (5/12) x 52,200 = 21,750 rupees.
The remaining amount left with the man = (7/12) x 52,200 = 30,450 rupees.He gave 3/7 of the remainder to his daughter. Therefore, the amount given to his daughter is (3/7) x 30,450 = 13,050 rupees.
The amount left with the man = (4/7) x 30,450 = 17,400 rupees.The man gave 17,400 rupees to his wife.
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For the functions f(x)=−9x^2+9 and g(x)=8x^2+9x, find (f+g)(x) and (f+g)(−1)
Answer:
f(x) = - 9x² + 9
g(x) = 8x² + 9x
To find (f+g)(x) add g(x) to f(x)
That's
(f+g)(x) = -9x² + 9 + 8x² + 9x
Group like terms
(f+g)(x) = - 9x² + 8x² + 9x + 9
(f+g)(x) = - x² + 9x + 9To find (f + g)(- 1) substitute - 1 into (f+g)(x)
That's
(f + g)(- 1) = -(-1)² + 9(-1) + 9
= - 1 - 9 + 9
= - 1Hope this helps you
My dad is X years old and i am Y years old. How old shall we be in 10 years time.
I'm assuming X and Y are current present day ages.
Simply add 10 to each variable to find the future ages ten years from now.
Your dad's future age = X+10
Your future age = Y+10
Since we don't know what X or Y is, we cannot combine those terms. We leave them as is.
Answer:
\(\bold{x+10,y+10}\)
Step-by-step explanation:
Hi there!
Right now, your dad's age is X years.
In 10 years, it will be x+10.
If your age is y years, in 10 years, it will be y+10.
No matter what x is, no matter what y is, it will be x+10 and y+10.
Thus, x+10 and y+10 is our final answer.
Hope it helps! Enjoy your day!
\(\bold{GazingAtTheStars}\)
X
If the edges of a rectangular prism are increased by a scale factor of 3, how will the volume change
O A. The new volume is 3 times the old volume,
B. The new volume is 9 more than the old volume.
O C. The new volume is 9 times the old volume,
D. The new volume is 27 more than the old volume,
O E. The new volume is 27 times the old volume,
9514 1404 393
Answer:
E. The new volume is 27 times the old volume
Step-by-step explanation:
If L, W, and H are the original length, width, and height, then the original volume is ...
V = LWH
The volume after the scale factor is applied is ...
V' = L'W'H' = (3L)(3W)(3H) = 27LWH = 27V
The new volume is 27 times the old volume.
A gym charges membership dues of $25 per month. Since joining the gym, Aaron has spent $200.
Which of the following is an equation which represents the total amount of money Aaron has spent on membership fees at the gym?
A.m=25 x 200
B.200 = 25m
C.200 25+ m
D.m= 25+ 200
YALL HELP ME 
Answer: B. 200=25m
Step-by-step explanation:
$200 (total) = $25 x m (number of months)
- 7x - 5y = 36
x = 2y + 3
Answer:
Solution
\(x = - 3,\: y = -3\)
Step-by-step explanation:
If the objective is to solve for the system of equations
- 7x - 5y = 36    [1]
x = 2y + 3 [2]
Then the process is as follows
Substitute x = 2y + 3 from eq [2] in eq [1] : -7 x- 5y = 36What is the value of x in the equation 2/3x = 12
Answer:
x = 8
The value of 'x' is 8
Step-by-step explanation:
2/3(8)=12
2/(24)=12
Good luck!!
13. You are using a nozzle to extinguish a fire. The nozzle is delivering at a rate of 100
gallons per minute. You open the nozzle and water flows for 30 seconds. (Therefore you flowed
50 gallons and a gallon of water weighs 8.34 pounds.) The water in the nozzle is at room
temperature which is 20°C. The water hits the fire and it absorbs heat, raising the temperature
of the water to 95°C.
Using the following formula, calculate how much energy, in joules, was required to raise the
temperature of the volume of water from 20°C to 95°C.
Z
You will need to convert to metric because the temperature is in Celsius; therefore your
answer will be in joules or kilojoules. The specific heat of water is 4.18 J/g °C.
Show your work for partial credit.
q=CPMAT
The amount of energy is the energy needed to extinguish the fire
The amount of energy is 1187.0 kilojoules
How to calculate the amount of energyThe given parameters are:
Mass, m = 8.34 poundsInitial Temperature = 20°CFinal Temperature = 95°CSpecific heat of water, C = 4.18 J/g °C.Start by converting the mass from pounds to grams
\(m = 8.34\ lb\)
Convert
\(m = 8.34 * 454\ g\)
\(m = 3786.36\ g\)
The amount of energy is then calculated as:
\(q = C_p * m * \Delta T\)
So, we have:
\(q = 4.18 * 3786.36 * (95 - 20)\)
Evaluate the product
\(q = 1187023.86j\)
Express as kilojoule
\(q = 1187023.86 * 0.001 kJ\)
\(q = 1187.02386kJ\)
Approximate
\(q = 1187.0kJ\)
Hence, the amount of energy is 1187.0 kilojoules
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Please help a lot of points!! Will put bainliest answer!
                                                Answer:
I haven't got a real clue
Step-by-step explanation:
I did some learning about it, I may be wrong(most likely)
but I think it might be SAS.
The shape can be proven congruent.
if you can find an angle which I think is H and K then most likely SAS. If this is a test and is very important then don't listen to this I am most likely wrong
\((w +  \frac{4}{w} )  {}^{2} \)
Help pls part b is how many batches of jam can the farmer make
                                                The equation we need to find will relate the amount of remaining berries to the number of batches of jam the farmer can make is 16 = 2 1/2 + 2 1/4b (option b)
To start with, we know that the farmer picks 16 quarts of berries. Out of those, 2 1/2 quarts cannot be used, which means the farmer has 16 - 2 1/2 quarts of berries that can be used to make jam.
Now, the recipe requires 2 1/4 quarts of berries to make one batch of jam. Let's represent the number of batches of jam the farmer can make with the remaining berries as "b".
Therefore, the equation we need to find will relate the amount of remaining berries to the number of batches of jam the farmer can make is written as,
=> 16 = 2 1/2 + 2 1/4b
Hence the correct option is (b).
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PLZZZ HELP ITS FOR MY FINAL if 7a/8=14 then 12a=
solve the equation 
a) y''-2y'-3y= e^4x
b) y''+y'-2y=3x*e^x
c) y"-9y'+20y=(x^2)*(e^4x)
Answer:
a) To solve the differential equation y''-2y'-3y= e^4x, we first find the characteristic equation:
r^2 - 2r - 3 = 0
Factoring, we get:
(r - 3)(r + 1) = 0
So the roots are r = 3 and r = -1.
The general solution to the homogeneous equation y'' - 2y' - 3y = 0 is:
y_h = c1e^3x + c2e^(-x)
To find the particular solution, we use the method of undetermined coefficients. Since e^4x is a solution to the homogeneous equation, we try a particular solution of the form:
y_p = Ae^4x
Taking the first and second derivatives of y_p, we get:
y_p' = 4Ae^4x
y_p'' = 16Ae^4x
Substituting these into the original differential equation, we get:
16Ae^4x - 8Ae^4x - 3Ae^4x = e^4x
Simplifying, we get:
5Ae^4x = e^4x
So:
A = 1/5
Therefore, the particular solution is:
y_p = (1/5)*e^4x
The general solution to the non-homogeneous equation is:
y = y_h + y_p
y = c1e^3x + c2e^(-x) + (1/5)*e^4x
b) To solve the differential equation y'' + y' - 2y = 3xe^x, we first find the characteristic equation:
r^2 + r - 2 = 0
Factoring, we get:
(r + 2)(r - 1) = 0
So the roots are r = -2 and r = 1.
The general solution to the homogeneous equation y'' + y' - 2y = 0 is:
y_h = c1e^(-2x) + c2e^x
To find the particular solution, we use the method of undetermined coefficients. Since 3xe^x is a solution to the homogeneous equation, we try a particular solution of the form:
y_p = (Ax + B)e^x
Taking the first and second derivatives of y_p, we get:
y_p' = Ae^x + (Ax + B)e^x
y_p'' = 2Ae^x + (Ax + B)e^x
Substituting these into the original differential equation, we get:
2Ae^x + (Ax + B)e^x + Ae^x + (Ax + B)e^x - 2(Ax + B)e^x = 3xe^x
Simplifying, we get:
3Ae^x = 3xe^x
So:
A = 1
Therefore, the particular solution is:
y_p = (x + B)e^x
Taking the derivative of y_p, we get:
y_p' = (x + 2 + B)e^x
Substituting back into the original differential equation, we get:
(x + 2 + B)e^x + (x + B)e^x - 2(x + B)e^x = 3xe^x
Simplifying, we get:
-xe^x - Be^x = 0
So:
B = -x
Therefore, the particular solution is:
y_p = xe^x
The general solution to the non-homogeneous equation is:
y = y_h + y_p
y = c1e^(-2x) + c2e^x + xe^x
c) To solve the differential equation y" - 9y' + 20y = x^2*e^4x, we first find the characteristic equation:
r^2 - 9r + 20 = 0
Factoring, we get:
(r - 5)(r - 4) = 0
So the roots are r = 5 and r = 4.
The general solution to the homogeneous equation y" - 9y' + 20y = 0 is:
y_h = c1e^4x + c2e^5x
To find the particular solution, we use the method of undetermined coefficients. Since x^2*e^4x is a solution to the homogeneous equation, we try a particular solution of the form:
y_p = (Ax^2 + Bx + C)e^4x
Taking the first and second derivatives of y_p, we get:
y_p' = (2Ax + B)e^4x + 4Axe^4x
y_p'' = 2Ae^4x +
Can you guys help me out here?
                                                Answer:
F(-5) = -2.25
f(-2) = -2
f(0) = 4
Step-by-step explanation:
Just plug in the value in the parentheses for x
plz help i have 9 min and i dont understand plz help worth 20 points
Answer:
no question
Step-by-step explanation:
When Tammy was 4, the ratio of Tammy’s age to her father’s age was 1:7. What will the ratio of their ages be when Tammy’s father is 48?
The ratio of Tammy's age to his father's age when his father is 48 will be 1:2.
Since we are informed that when Tammy was 4, the ratio of Tammy’s age to her father’s age was 1:7. This means that his father's age when he was 4 years will be:
= 4 × 7 = 28 years.
Now since his father is 48 years, this means it was 20 years after. Therefore, Tammy's age will be:
= 4 + 20 = 24 years.
Therefore, the ratio of their ages will be:
= 24 / 48 = 1/2 = 1:2.
The ratio of Tammy's age to his father's age when his father is 48 will be 1:2.
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1) To make plaster, Kevin mixes 3 cups of water with 4 pounds of plaster powder. Complete the table.
How much water will Kevin mix with 20 pounds of powder?
Four movie tickets cost $26. How much do seven movie tickets cost?
Answer:
45.5
Step-by-step explanation:
Directions: Calculate the volume of each of the following prisms.
                                                The volumes of the prisms are :- 1) 11760 units³, 2) 7938 units³, 3) 9261 units³, 4) 22800 unit³, 5) 11781 units³, 6) 38936 units³, 7) 23125 units³, 8) 26208 units³ and 9) 14688 units³
What are prisms?A prism is a solid shape that is bound on all its sides by plane faces.
Given are prisms, we need to find their volumes :-
Volume = area of base × height
1) Base is a rectangle, area = length × width, height = 24
Volume = 24·14·35 = 11760 units³
2) Base is a rectangle, area = length × width, height = 21
Volume = 21·14·27 = 7938 units³
3) This is a cube, with side 21 units
Volume of cube = side³ = 9261 units³
4) This is a trapezoidal prism,
Volume = 1/2(b1+b2) × height × length = 1/2(36+24) × 38 × 20
= 22800 unit³
5) This is a triangular prism,
Volume = 1/2 × height × length × base
= 1/2 × 33 × 34 × 21 = 11781 units³
6) This is a cylinder,
Base is circular, volume = π·radius²·height
= 3.14·20·20·31 = 38936 units³
7) Base is a rectangle, area = length × width, height = 37
Volume = 25·37·25 = 23125 units³
8) Base is a rectangle, area = length × width, height = 28
Volume = 39·24·28 = 26208 units³
9) Base is a rectangle, area = length × width, height = 36
Volume = 36·24·17 = 14688 units³
Hence, the volumes of the prisms are :- 1) 11760 units³, 2) 7938 units³, 3) 9261 units³, 4) 22800 unit³, 5) 11781 units³, 6) 38936 units³, 7) 23125 units³, 8) 26208 units³ and 9) 14688 units³
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Answer this arithmetic progression question and get 50 points + brainliest
                                                Answer:
The 9th term is 30
---------------------------------
Use nth term equation:
\(a_n=a+(n-1)d\), where a- the first term, n - number of terms, d - common differenceWe have:
\(a_7=21\ and\ a_{11}=39\)And we need to find the 9th term.
Write the given terms as below and solve for d:
a + 6d = 21 anda + 10d = 39Subtract the first equation from the second:
10d - 6d = 39 - 214d = 18d = 18/4d = 4.5The first term is:
a + 10*4.5 = 39a + 45 = 39a = - 6Find 9th term:
\(a_9=a+8d=-6+8*4.5=-6+36=30\)Answer:
The 9th term is 30
Step-by-step explanation:
The lacrosse team has played 35 matches so far this season. They have won 14 matches so far. How many matches will the team need to win for the team to have a 65% success rate?
 a
12
 b
15
 c
18
 d
25
The number of matches the team will need to win to have a 65% success rate is; 25
How to find the Percentage?
We are given;
Number of matches played by Lacrosse team this season = 35 matches
Number of matches won so far = 14 matches
Now, we want to know how many matches the team will need to win to have a 65% success rate.
Let the extra number of games played and won be x. Thus;
(14 + x)/(35 + x) = 65/100
(14 + x)/(35 + x) = 13/20
20(14 + x) = 13(35 + x)
280 + 20x = 455 + 13x
20x - 13x = 455 - 280
7x = 175
x = 175/7
x = 25
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please i need help what is 2/3 + 1/6
Answer: 5/6
Step-by-step explanation:
(2/3×2/2)+(1/6×1/1)=?
4/6+1/6=5/5
What is the area of this figure?
                                                Answer:
286 mm ^2
Step-by-step explanation:
The figure is a trapezoid
The area of a trapezoid is given by
A = 1/2 ( b1+b2) *h where b1 and b2 are the lengths of the bases and h is the height
A = 1/2 ( 28+24) * 11
A = 1/2 (52)*11
A =286 mm ^2
Answer:
The area of this figure is 286
Step-by-step explanation:
The formula for the area of a trapezoid is A = (a+b/2)h, or the top line plus the bottom line divided by 2 times the height. a is given as 24 mm and b is given as 28 mm so 24 plus 28 is 52. 52 divided by 2 is 26. 26 times 11 is 286 therefore the answer and area is 286.
For each ordered pair (x, y), determine whether it is a solution to the inequality y≤0.
(8,-43)
(4.-22)
(-3,25)
(-7,45)
Is it a solution?
Answer:
(8,-43)
(4,-22)
Step-by-step explanation:
In order for the ordered pair to be a solution of the inequality, you must be able to plug in the y-value of the ordered pair and it must be less than or equal to 0.
For example:
(4,-22)
x=4 ; y=-22
Plug y into the inequality
y≤0
-22≤0
Since the statement is true, I know that (4,-22) must be a solution to the inequality.
Another way to solve this problem is by graphing. If an ordered pair is in the shaded region, it is a solution to the inequality. Attached is a graph of both the inequality and ordered pairs plotted.
If this answer helped you, please leave a thanks or a Brainliest!!!
Have a GREAT day!!!
                                                            Answer:
Step-by-step explanation:
To determine whether each ordered pair is a solution to the inequality y ≤ 0, we need to check if the y-coordinate of each pair is less than or equal to zero.
Let's check each ordered pair:
(8, -43):
The y-coordinate is -43. Since -43 is less than zero, this ordered pair is a solution to the inequality y ≤ 0.
(4, -22):
The y-coordinate is -22. Since -22 is less than zero, this ordered pair is a solution to the inequality y ≤ 0.
(-3, 25):
The y-coordinate is 25. Since 25 is greater than zero, this ordered pair is not a solution to the inequality y ≤ 0.
(-7, 45):
The y-coordinate is 45. Since 45 is greater than zero, this ordered pair is not a solution to the inequality y ≤ 0.
So, the solutions to the inequality y ≤ 0 are:
(8, -43) and (4, -22).
Assume that program runs in f (n) microseconds; where f (n) is the function given on the left. Fill in how large an input can be calculated, given cach of the runtimes given along the top. have filled in two values for you: You do not need to fill in every box, but should have at least of every row filled in, and at least half of the rows complete: second minute hour day month year Ign Vnl n lgn 72 1000 2n Show some calculations, O some of your code if you use code: What row is the most sucktastic one? Why? Do you have any non-integer answers?
The row with the most sucktastic runtime is the one with\(2^n\), as it takes exponentially longer to run than the other runtimes.
No, we do not have any non-integer answers.
Second: 72
Minute: 1000
Hour: \(2^(17)\)
Day: \(2^25\)
Month: \(2^30\)
Year: \(2^35\)
Second: f(n) = 72 => n = 72
Minute: f(n) = 1000 => n = 1000
\(Hour: f(n) = 2^n = > n = 17Day: f(n) = 2^n = > n = 25 Month: f(n) = 2^n = > n = 30Year: f(n) = 2^n = > n = 35\)
Seconds: The runtime for an input of size n is 72 microseconds, so the largest input that can be calculated in a second is 72.
Minutes: The runtime for an input of size n is 1000 microseconds, so the largest input that can be calculated in a minute is 1000.
Hours: The runtime for an input of size n is\(2^n\) microseconds, so the largest input that can be calculated in an hour is \(2^17.\)
Days: The runtime for an input of size n is \(2^n\) microseconds, so the largest input that can be calculated in a day is \(2^25\)
Months: The runtime for an input of size n is \(2^n\) microseconds, so the largest input that can be calculated in a month is \(2^30.\)
Years: The runtime for an input of size n is \(2^n\) microseconds, so the largest input that can be calculated in a year is \(2^35.\)
The row with the most sucktastic runtime is the one with \(2^n\), as it takes exponentially longer to run than the other runtimes. Therefore, the longer the time period, the larger the input size that can be calculated. No, we do not have any non-integer answers as the runtimes of the inputs are in microseconds and the input size is given as an integer.
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