Answers
Answer:
The elevation angle is \(\theta = 3.67^o\)
Explanation:
From the question we are told that
The velocity is \(u = 1114\ ft/s\)
The range of the bullet projection is \(R = 4950 \ ft\)
The initial height of bullet is \(h_1 = 0 \ ft\)
Range of this bullet projection is mathematically represented as
\(R = \frac{u^2 sin (2 \theta )}{g}\)
=> \(\theta = \frac{sin ^{-1} [\frac{R * g }{ u^2} ]}{2}\)
Here \(g = 32 ft/s^2\)
substituting values
\(\theta = \frac{sin ^{-1} [\frac{4950 * 32 }{ 1114^2} ]}{2}\)
\(\theta = 3.67^o\)
Related Questions
when is mechanical energy conserved
Answers
Mechanical energy is conserved in a closed system when there are no external forces acting upon it.
According to the principle of conservation of mechanical energy, the total amount of mechanical energy, which is the sum of kinetic energy and potential energy, remains constant as long as there is no work done by non-conservative forces like friction or air resistance.
In the absence of external forces, the total mechanical energy of the system remains unchanged throughout its motion. For example, in the case of a pendulum swinging back and forth, neglecting air resistance, the mechanical energy is conserved as the pendulum oscillates between its highest and lowest points.
However, it's important to note that mechanical energy conservation is an idealization and may not hold true in all real-world scenarios due to factors like friction, air resistance, and energy losses. In practical situations, mechanical energy conservation is often a useful approximation but may not be strictly maintained.
THerefore, mechanical energy is conserved in a closed system when there are no external forces acting upon it.
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A bug slides back and forth in a bowl 12 cm deep, starting from rest at the top, as shown in Fig. 7.20. The bowl is frictionless except for a 1.8-cm-wide sticky patch on its flat bottom, where the coefficient of friction is 0.83. How many times does the bug cross the sticky region?
Answers
The bug will cross the sticky region once in each cycle of its motion, where a cycle is defined as one complete round trip from the top of the bowl to the bottom and back to the top.
To find the number of cycles the bug goes through, we can use conservation of mechanical energy. At the top of the bowl, the bug has only potential energy, which is converted to kinetic energy as it slides down the bowl. At the bottom of the bowl, all of the potential energy has been converted to kinetic energy, and as the bug slides up the other side of the bowl, the kinetic energy is converted back into potential energy. At the top of the bowl again, the bug has only potential energy, and the cycle repeats.
Because there is no friction (except for the sticky patch), the total mechanical energy of the system is conserved. Therefore, the potential energy at the top of the bowl is equal to the potential energy at the bottom of the bowl, and the kinetic energy at the bottom of the bowl is equal to the kinetic energy at the top of the bowl.
We can set the potential energy at the top of the bowl to zero, and use the conservation of energy to find the potential energy at the bottom of the bowl:
mgh = (1/2)mv^2
where m is the mass of the bug, g is the acceleration due to gravity, h is the depth of the bowl, and v is the speed of the bug at the bottom of the bowl.
Solving for v, we get:
v = sqrt(2gh)
Plugging in the numbers, we get:
v = sqrt(29.810.12) = 0.775 m/s
The time it takes for the bug to slide from the top of the bowl to the bottom and back up to the top is twice the time it takes to slide from the top to the bottom:
t = 2sqrt(2h/g) = 2sqrt(2*0.12/9.81) = 0.774 s
Therefore, the frequency of the bug's motion is:
f = 1/t = 1/0.774 = 1.29 Hz
Since the bug completes one cycle in each oscillation, the bug will cross the sticky region 1.29 times per second, or approximately once every 0.78 seconds.
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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PLEASE HELP!! A TOTAL OF 50 POINTS WHEN GIVEN BRAINLIEST!!
Part A: Find the work done in lifting 1 L of blood (mass 1 kg ) from the foot to the head of a 1.9 m -tall person.
Part B: If blood circulates through the body at the rate of 5.0 L/min , estimate the heart's power output. (Your answer underestimates the power by a factor of about 5 because it neglects fluid friction and other factors.)
Answers
Explanation:
for part A:
work done is equal to change in potential energy which is
MgH
so the answer is 1.9 × 1 × 9.81
ANSWER FOR PART A: 18.639
FOR PART B:
power = flow rate x gh
= 5×9.81×1.9
93.195 watts
Two cannonballs are dropped from a second-floor physics lab at height h above the ground. Ball B has four times the mass of ball A. When the balls pass the bottom of a first-floor window at height above the ground, the relation between their kinetic energies, KA and KB, is
Answers
Answer:
1:4
Explanation:
The formula for calculating kinetic energy is:
\(KE=\dfrac{1}{2}mv^2\)
If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!
The relation between the kinetic energies of the freely falling balls A and B is obtained as \(\frac{KE_{A}}{KE_{B}} =\frac{1}{4}\).
Kinetic EnergyThe kinetic energy of an object depends on the mass and velocity with which it moves.
While under free-fall, the mass of an object does not affect the velocity with which it falls.
So, the velocities of both the balls are the same.
Let the mass of ball A is 'm'
So, the mass of ball B is '4m'
The kinetic energy of ball A is given by;
\(KE_{A}=\frac{1}{2} mv^2\)
The kinetic energy of ball B is given by;
\(KE_{B}=\frac{1}{2} 4mv^2 = 2mv^2\)
Therefore, the ratio of kinetic energies of A and B is,
\(\frac{KE_{A}}{KE_{B}} =\frac{1}{4}\)
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Please help with these MCQs.
1. Filter absorbs __________________.
- only primary coloured lights
- only secondary coloured lights
- only tertiary coloured lights
- all colors of white light
2. The light that has passed through a filter, is always ______________.
- dim
- bright
- sharp
- blur
Answers
1. Filter absorbs all colors of white light.
2. The light that has passed through a filter, is always dim.
Which colors are being absorbed by the filter?The filter selectively transmits the red and blue portions of the incident white light spectrum, but absorbs most of the green wavelength.
Color filters absorb certain wavelengths of color and transmit the other wavelengths allowing them to be seen.
Therefore in conclusion, the right filter can reduce glare, increase contrast, and make lunar features pop.
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a body with angular velocity of 2rev/s at t=0 has an angular acceleration of 0.5rev/s^2.After 10s,what will be
1.the final angular velocity
2.the average angular velocity
3.the angular displacement.
Answers
Answer:
We can use the equations of rotational motion to solve this problem:
Final angular velocity:
ω = ω0 + αt
where
ω0 = initial angular velocity = 2 rev/s
α = angular acceleration = 0.5 rev/s^2
t = time = 10 s
Plugging in the values, we get:
ω = 2 rev/s + (0.5 rev/s^2)(10 s) = 7 rev/s
Therefore, the final angular velocity is 7 rev/s.
Average angular velocity:
The average angular velocity is given by:
ωavg = (ω0 + ω) / 2
Plugging in the values, we get:
ωavg = (2 rev/s + 7 rev/s) / 2 = 4.5 rev/s
Therefore, the average angular velocity is 4.5 rev/s.
Angular displacement:
θ = θ0 + ω0t + (1/2)αt^2
where
θ0 = initial angular displacement = 0 (since the problem does not specify an initial angular displacement)
Plugging in the values, we get:
θ = (1/2)(0.5 rev/s^2)(10 s)^2 = 25 rev
Therefore, the angular displacement is 25 rev.
In six sentences discuss the 4 universal forces
Answers
There are four fundamental forces at work in the universe: the strong force, the weak force, the electromagnetic force, and the gravitational force.
for more details tell me in comments section
Title: The Four Universal Forces
There are four fundamental forces in the universe that govern the behavior of matter and energy. These forces are:
1. Gravity: Gravity is the force that attracts two objects with mass towards each other. It is the weakest of the four fundamental forces but has an infinite range. Gravity is responsible for the motion of planets, stars, and galaxies.
2. Electromagnetic force: The electromagnetic force is the force that exists between electrically charged particles. It is responsible for the behavior of atoms and molecules, and the interaction between light and matter.
3. Strong nuclear force: The strong nuclear force is the force that holds the nucleus of an atom together. It is a very strong force that only acts over short distances.
4. Weak nuclear force: The weak nuclear force is the force responsible for certain types of radioactive decay. It is a very weak force that only acts over very short distances.
These four fundamental forces are responsible for all the interactions that occur in the universe. While gravity dominates on the largest scales, the other three forces are more important on the atomic and subatomic scales. Understanding and describing the behavior of matter and energy at these scales requires a deep understanding of the four fundamental forces and their interactions.when an object (like a ball) falls, some of its _____ energy changes to _____ energy, due to the law of conservation of energy
a.) kinetic, potential
b.) kinetic, motion
c.) potential, kinetic
d.) motion, potential
Answers
Answer:
c ) potential your welcome heheWhat does the speedometer in a moving car measure?
Answers
You launch a model rocket from ground level. It moves directly upward with a constant acceleration of 71.0 m/s2 for 1.45 seconds, at which point it runs out of fuel. Assuming air resistance on the rocket is negligible, what is the maximum altitude (above the ground) achieved by the rocket?
m
Answers
Answer:
74.0 meters
Explanation:
We can use the kinematic equation for displacement with constant acceleration to solve this problem:
Δy = v0t + 1/2at^2
where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.
Plugging in the given values, we get:
Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2
Δy = 74.0 m
Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.
find it difficult to answer
Answers
The position of the body at time t is s (t) = -3 + 2t - 2 sin(2t³).
What is the position of the body at time t?The position of the body at time t is calculated by applying the second kinematic equation as shown below.
s = s₀ + vt + ¹/₂at²
where;
v is the initial velocitys₀ is the initial positiona is the acceleration t is the timeThe position at time t is calculated as;
s (t) = -3 + 2t + ¹/₂( - 4sin 2t )t²
s (t) = -3 + 2t - 2 sin(2t³)
Thus, the final position of the body is a function of the acceleration, initial velocity and time of motion of the body.
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WHAT IS THE MEAING OF- Grouping Data
Answers
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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a 27 kg is accelerated at a rate of 1.7m/s/s . what force does the object experience
Answers
A marine weather station reports waves along the shore that are 2 meters high, 8 meters long, and reach the station 8 seconds apart. Determine the speed of these waves.
Answers
One full weather station reports wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.
What is the frequency of a 30-second ocean wave that hits the shore?The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).
Which of the following statements most accurately sums up how a wave crosses a border and enters a new medium?A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.
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A thermionic tube with only a cathode and an anode is called?
Answers
I hope this helps.
why aeroplanes cannot travel in space
Answers
Answer:
- They need oxygen to burn fuel
- Aerodynamics
- Extreme temperatures
- Radiation
- Pressure issues
Explanation:
A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.
Aeroplanes cannot travel in space for several reasons:
They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.
Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.
Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.
Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.
Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.
In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.
Explanation:
The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.
In the diagram, q1 = +6.39 • 10-⁹ C and q2 = +3.22 10-⁹ C. What is the electric field at point P? Include a + or - sign to indicate the direction.
Answers
Answer:
-391. 1077613
Explanation:
Answer:248.3
Explanation: Acellus
(Credit to guy above in comments)
What does the Curl-up test assess?
O A.
Body composition
ОВ.
Muscular strength and endurance
O C. Flexibility
D.
Cardiovascular fitness
HURRRY
(it’s pe not physics)
Answers
Answer:
assesses C.) muscular endurance
Explanation:
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
Answers
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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We could, in theory, make all of our industrial processes sustainable if we could ________.
a. speed up the disposal of wastes by deep-well injection
b. develop more draconian policies to regulate manufacturing
c. reduce the use of biodegradable plastics
d. transform cyclic processes into linear ones
e. transform linear processes into circular ones
Answers
Answer:
transform linear processes into circular ones.
Given sin ti + cos ti + tk
Answers
Answer:
I don't understand the question that up added
Explanation:
what do you mean by ti and tk
What type of tv uses a VfL for backlighting
Answers
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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The radius of the aorta is about 1.4cm , and the blood passing through it has a speed of about 40cm/s .
Calculate the average speed of blood flow in the major arteries of the body, which have a total cross-sectional area of about 2.1cm2 .
Express your answer to two significant figures and include the appropriate units.
Answers
For the average speed of blood flow in the major arteries of the body is mathematically given as
v2 = 117.29m/s
What is the average speed of blood flow in the major arteries of the body?Generally, the equation for the average speed is mathematically given as
A1 v1 = A2 v2
(pi r1^2) v1 = A2 v2
(3.14x(1.4)^2 )x 40 = (2.1) xV2
v2 = 117.29m/s
In conclusion, the average speed of blood flow
v2 = 117.29m/s
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what is efficiency?
Answers
Explanation:
the state or quality of being efficient or able to accomplish something
there are two formulas I don't know which one it is
m1v1 + m2v2 = m1v1 + m2v2
m1v1 + m2v2 = (m1 + m2) vf
Tom is running at 6.0 m/s to the east. He collides with Jerry (mass = 84 kg), who was moving west at 4.0 m/s. Tom grabs hold of Jerry and the two move together at 0.72 m/s to the east. What is Tom’s mass?
Answers
Tom's mass is 75.1 kg
The law of conservation of momentum
This is the law of conservation of momentum which states that the initial and final momentum are the same.
The required equationSince Tom grabs hold of Jerry after the colision, both stick together. So, we use the second equation.
m₁v₁ + m₂v₂ = (m₁ + m₂)vf where
m₁ = Tom's mass, v₁ = Tom's velocity = + 6.0 m/s (since he is moving to the east), m₂ = Jerry's mass = 84 kg, v₂ = Jerry's velocity = -4.0 m/s (negative since he is moving to the west) and vf = their final velocity = 0.72 m/sSince we require Jerry's mass, we make m₁ subject of the formula.
So, m₁v₁ + m₂v₂ = (m₁ + m₂)vf
m₁v₁ + m₂v₂ = m₁vf + m₂vf
m₁v₁ - m₁vf = m₂vf - m₂v₂
m₁(v₁ - vf) = m₂(vf - v₂)
The equation for Tom's massm₁ = m₂(vf - v₂)/(v₁ - vf)
Substituting the values of the variables into the equation, we have
m₁ = m₂(vf - v₂)/(v₁ - vf)
m₁ = 84 kg(0.72 m/s - [-4.0 m/s])/(6.0 m/s - 0.72 m/s)
m₁ = 84 kg(0.72 m/s + 4.0 m/s)/(6.0 m/s - 0.72 m/s)
m₁ = 84 kg(4.72 m/s)/(5.28 m/s)
m₁ = 396.48 kgm/s ÷ 5.28 m/s
m₁ = 75.09 kg
m₁ ≅ 75.1 kg
So, Tom's mass is 75.1 kg
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In order to use a crowbar, you apply 12 N of force. The crow bar applies 38 N of force. What is the mechanical advantage of the crowbar?
Answers
The mechanical advantage of the crowbar is 3.1667.
What is mechanical advantage of inclined plane ?The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane.
The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.
Given parameters:
Input force by you= 12 N.
Output force from the crowbar = 38 N.
Then, the mechanical advantage of the crowbar = Output force from the crowbar / input force by you.
= 38N/12N.
=3.1667.
Hence, the mechanical advantage of the crowbar is 3.1667.
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Someone please help me !!
Answers
Answer:25
Explanation: because higher means less kinetic energ
QUESTION 3 (Start on a new page.)
A small disc, C, is thrown vertically upwards at a speed of 15 m-s¹ from the edge of
the roof of a building of height 30 m. AFTER 0,5 s, a small ball B is shot vertically
upwards from the foot of the building at a speed of 40 m-s in order to hit disc C.
Ignore the effects of air resistance.
3.1
3.2
3.3
15 m-s¹
30 m
Explain the term projectile.
Calculate the:
40 m-s¹
B
3.2.1
Time taken by disc C to reach its maximum height
3.2.2
Maximum height above the ground reached by disc C
Calculate the time from the moment that disc C was thrown upwards until
the time ball B hits the disc..
(2)
(3)
(4)
(6)
Answers
A projectile is an object thrown into the air and subject only to gravity and, if applicable, air resistance. The time taken by disc C to reach its maximum height is approximately 1.53 seconds, and its maximum height above the ground is around 11.48 meters. The time from when disc C was thrown upwards until ball B hits the disc is roughly 1.29 seconds.
3.1 Explanation of the term projectile:
A projectile refers to an object that is launched or thrown into the air and is subject only to the forces of gravity and air resistance (if applicable). The motion of a projectile can be analyzed independently of its mass, shape, or any other physical property. The key characteristic of a projectile is that it follows a curved path known as a trajectory.
When a projectile is launched, it moves along a parabolic trajectory due to the combination of its initial velocity and the force of gravity acting vertically downward. The horizontal motion of a projectile remains constant and unaffected by gravity, while the vertical motion is influenced by the acceleration due to gravity.
The path of a projectile can be described mathematically by considering its initial velocity, angle of projection, and the acceleration due to gravity. Projectile motion finds applications in various fields, such as sports, engineering, and physics, where objects are launched or thrown.
3.2.1 Time taken by disc C to reach its maximum height:
To determine the time taken by disc C to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:
vf = vi + at
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
t = time
Since the disc is thrown vertically upwards, its initial velocity is 15 m/s. We want to find the time it takes for the disc to reach its maximum height, so we'll use the equation and solve for time (t):
0 = 15 + (-9.8)t
Rearranging the equation, we get:
9.8t = 15
t = 15 / 9.8
Calculating this, we find:
t ≈ 1.53 seconds
Therefore, it takes approximately 1.53 seconds for disc C to reach its maximum height.
3.2.2 Maximum height above the ground reached by disc C:
To determine the maximum height reached by disc C, we can use another kinematic equation for vertical motion:
vf² = vi² + 2ad
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
d = displacement (maximum height)
Since we know the initial velocity (vi) and acceleration (a), we can solve for the displacement (d), which represents the maximum height:
0² = 15² + 2(-9.8)d
Rearranging the equation, we get:
0 = 225 - 19.6d
19.6d = 225
d = 225 / 19.6
Calculating this, we find:
d ≈ 11.48 meters
Therefore, the disc C reaches a maximum height of approximately 11.48 meters above the ground.
Calculating the time from the moment that disc C was thrown upwards until the time ball B hits the disc:
To find the time it takes for ball B to hit disc C, we need to calculate the time it takes for both objects to reach the same height.
Since disc C was thrown upwards from the edge of the roof and ball B was shot vertically upwards from the foot of the building, we need to consider the additional height of the building (30 meters).
The time it takes for disc C to reach the ground is the same as the time it takes for ball B to reach a height of 30 meters above the ground.
Using the kinematic equation for vertical motion, we can calculate the time for ball B:
d = vit + 0.5at²
Where:
d = displacement (30 meters)
vi = initial velocity (40 m/s)
a = acceleration (acceleration due to gravity, -9.8 m/s²)
t = time
30 = 40t + 0.5(-9.8)t²
Rearranging the equation, we get:
4.9t² + 40t - 30 = 0
Solving this quadratic equation, we find:
t ≈ 1.29 seconds or t ≈ -5.82 seconds
Since time cannot be negative in this context, we discard the negative solution.
Therefore, it takes approximately 1.29 seconds from the moment that disc C was thrown upwards until ball B hits the disc.
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Which is a characteristic of an electromagnetic wave?
The fields are at right angles to each other and to the direction of the wave.
The waves are produced when an electric charge is at rest.
The fields are aligned with each other and to the direction of travel.
The fields are independent of each other.
Answers
Answer:
The fields are at right angles to each other and to the direction of the wave.
Explanation: