A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always remains on the ice and slides 115 m before coming to rest, determine the coefficient of kinetic friction between the puck and ice.

Answers

Answer 1

Answer:

μ_k = 0.1773

Explanation:

We are given;

Initial velocity;u = 20 m/s

Final velocity;v = 0 m/s (since it comes to rest)

Distance before coming to rest;s = 115 m

Let's find the acceleration using Newton's second law of motion;

v² = u² + 2as

Making a the subject, we have;

a = (v² - u²)/2s

Plugging relevant values;

a = (0² - 20²)/(2 × 115)

a = -400/230

a = -1.739 m/s²

From the question, the only force acting on the puck in the x direction is the force of friction. Since friction always opposes motion, we see that:

F_k = −ma - - - (1)

We also know that F_k is defined by;

F_k = μ_k•N

Where;

μ_k is coefficient of kinetic friction

N is normal force which is (mg)

Since gravity acts in the negative direction, the normal force will be positive.

Thus;

F_k = μ_k•mg - - - (2)

where g is acceleration due to gravity.

Thus,equating equation 1 and 2,we have;

−ma = μ_k•mg

m will cancel out to give;

-a = μ_k•g

μ_k = -a/g

g has a constant value of 9.81 m/s², so;

μ_k = - (-1.739/9.81)

μ_k = 0.1773

Answer 2

The coefficient of kinetic friction between the hockey puck and ice is equal to 0.178

Given the following data:

Initial speed = 20 m/sFinal velocity = 0 m/s (since it came to rest)Distance = 115 m

Scientific data:

Acceleration due to gravity = 9.8 \(m/s^2\)

To determine the coefficient of kinetic friction between the hockey puck and ice:

First of all, we would calculate the acceleration of the hockey puck by using the third equation of motion.

\(V^2 = U^2 + 2aS\\\\0^2 =20^2 + 2a(115)\\\\-400=230a\\\\a=\frac{-400}{230}\)

Acceleration, a = -1.74 \(m/s^2\)

Note: The negative signs indicates that the hockey puck is slowing down or decelerating.

From Newton's Second Law of Motion, we have:

\(\sum F_x = F_k + F_n =0\\\\F_k =- F_n\\\\\mu mg =-ma\\\\\mu = \frac{-a}{g}\\\\\mu = \frac{-(-1.74)}{9.8}\\\\\mu = \frac{1.74}{9.8}\)

Coefficient of kinetic friction = 0.178

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Related Questions

Something that has many particles in a small space would have a ————- density


Fill in blank

Answers

Answer:

a high density i believe

Explanation:

Answer:

it may have a higher density

The femur of a human leg (mass 10 kg,
length 0.9 m
) is in traction, as shown in the figure. The center of gravity of the leg is one-third of the distance from the pelvis to the bottom of the foot. Two objects, with masses 1
and 2,
are hung at the ends of the leg using pulleys to provide upward support. A third object of 8 kg
is hung to provide tension along the leg. The body provides tension as well.

Write a mathematical relationship relating 1
to 2
in terms of 2
and numerical coefficients.

Answers

The mathematical relationship between m₁ and m₂ is that m₁ is twice the value of m₂.

Length of the femur, L = 0.9 m

Mass of the femur, M = 10 kg

Centre of gravity = L/3

m₁ + m₂ = M

T₁ + T₂ = Mg

m₁g + m₂g = Mg

T₁ + T₂ = m₁g + m₂g

T₁(L/3) = T₂(2L/3)

m₁g(L/3) = 2m₂mg(L/3)

Therefore,

m₁ = 2m₂

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A 2.8 kg block slides along a frictionless surface at 1.1 m/s . A second block, sliding at a faster 4.8 m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.3 m/s.

What was the mass of the second block?

Answers

Conservation of momentum is a major law of physics which states that the momentum of a system is constant if no external forces are acting on the system. It is embodied in Newton’s First Law or The Law of Inertia.the mass of the second block is 1.1Kg.

principle of momentum conservation

M1u1 plus M2u2 equals M1v1 and M2V2.

As all collisions were elastic in nature and no energy loss through friction, heat, etc. was taken into account, theoretic calculations alone cannot guarantee that there was a complete transfer of energy.

Consider the scenario where a football with mass M2 is lying on the ground and a bowling ball with mass M1 is hurled at the football at a velocity of

The formula is: (2.8 kg * 1.1 m/s) + (m2 * 4.8 m/s) = (2.3 kg + m2). 2.3 m/s

The formula is 2.8 J + (4.8 m/s m2) = 4.8 J + (2.3 m/s m2).

4.8 m/s m2 = 2.8 J plus (2.3 m/s m2)

4.8 m2 = 2.8 + 2.3 m2

2.3 m2 on each side of the equation

2.5 m = 2.8 m = 2.8 / 2.5\sm = 1.1kg

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What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact

Answers

Answer:

The characteristics that determine how easily two substances change temperature are:

specific heat of the material that makes up the substancesarea in contact between the two substances

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Color is a result of the absorption and reflection of light. A shirt appears a color because it reflects that color of light. A shirt appears black when it absorbs all wavelengths of light.

Why does a shirt appear white outside on a sunny day?

O The light is transmitted through the shirt, so no color
wavelengths of light.
appears.
O The shirt absorbs the sunlight, so it appears white.
O All the light is reflected, so the shirt appears white.
The sunlight refracts when it hits the shirt, so the shirt
appears white.

Answers

Answer:

the light is reflected, because light is white when the spectrum is combined, and white reflects white. that's why wearing a white shirt outside feels cooler than wearing a black shirt, since it doesn't absorb light.

Answer:

All the light is reflected, so the shirt appears white.

Explanation:

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answers

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

\(90 \)

so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically
(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically
(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically

a
a
a
A single charge a produces a
potential Vo = 1000 V at point o
=
0
a
+9
+
a
What is the potential at point o
due to two identical charges as
shown to the right?
a
a
a
O
+9
A) 1000 V
B) 1414 V
C) 2000 V
D) 2828 V

Answers

Answer:

C 2000v its obviously ans because if o is 1000 2 vo is 2000v

relationship between the length (l) and ohmic conductor, its thickness (d) and the opposition (R) it offers a current passage​

Answers

Answer:

Ohm’s Law states that current is proportional to voltage; circuits are ohmic if they obey the relation V=IR.

Explanation:

LEARNING OBJECTIVES

Contrast shape of current-voltage plots for ohmic and non-ohmic circuits

formula for percentage error​

Answers

Answer:

PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

A dog runs out the door and through the neighborhood. It starts at point A and ends up at point F. What is its displacement at F? D C A 5 OA. 5 km east and 4 km north B. 2 km east and 5 km north OC. 11 km east and 4 km north D. 7 km east and 2 km north​

A dog runs out the door and through the neighborhood. It starts at point A and ends up at point F. What

Answers

The displacement of the dog can summarized as 4 km north and 5 km east with a resultant magnitude of 6.4 km.

Displacement of the dog

The displacement of the dog is the change in the position of the dog from the initial position to the final position.

The displacement is the straight line from point A to point F.

Vertical length, A - E = 4 kmHorizontal length, A - F = 5 km

Straight line from A to F is calculated as follows;

r = √(4² + 5²)

r = 6.4 km

Thus, the displacement of the dog can summarized as 4 km north and 5 km east with a resultant magnitude of 6.4 km.

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A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.

Answers

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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Please help me i need this to pass :((

Please help me i need this to pass :((

Answers

Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.

What is the height L of the light liquid in the column in the right arm of the U-tube?

Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.

The pressure at point A is equal to the pressure at point B

Therefore:

P₀ + ρgh = P₀ + ρgh

where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.

Simplifying this equation, we get:

ρgh = ρgh

Canceling out the ρ and solving for h, we get:

h = h

In other words, the height of the heavy liquid is the same in both arms of the U-tube.

Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.

Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).

Therefore, we can write:

P₀ + ρgh = P₀ + ρg(L+h)

where L is the height of the light liquid in the right arm.

Simplifying this equation, we get:

ρgh = ρgL + ρgh

Canceling out the ρgh and solving for L, we get:

L = (ρ/ρ₀)h

where ρ₀ is the density of the light liquid.

Substituting the given values, we get:

L = (0.92 g/cm³ / 13 g/cm³)h

L = 0.070769h

Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.

The volume of the heavy liquid in the left arm is:

V₁ = Ah = (13.2 cm²)(h cm)

V₁ = 13.2h cm³

The volume of the heavy liquid plus the light liquid in the right arm is:

V₂ = A(L+h) = (2.11 cm²)(L+h cm)

V₂ = 2.11(L+h) cm³

Since these volumes are equal, we can set them equal to each other and solve for h:

13.2h = 2.11(L+h)

13.2h = 2.11L + 2.11h

11.09h = 2.11L

h = (2.11/11.09)L

Substituting this into our expression for L, we get:

L = 0.070769(2.11/11.09)L

L = 0.01345L

L = 0.01444h

Substituting the given value for the density of the heavy liquid, we get:

L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)

L = 0.203 cm

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Complete question:

A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.

Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.

what is a shargaff rule

Answers

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Who is Chargaff ?

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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What is the source of the electrical energy in the brain

Answers

Answer:

What's the source of energy that powers the human brain?

Mainly sugar, glucose. Glucose is broken down, and in the process it is used to create a gradient of hydrogen ions (Oxygen is also needed, which is why we breath).

brainiest please

In the figure, an object of mass m moves a distance of 8.0 m on a rough horizontal surface. During this motion the speed changes from 9.0 m/s to 2.0 m/s. What is the coefficient of kinetic friction between the object and the rough surface? m |____ |_____________________
←--------- 8.0 m -------→

Answers

a) The angular velocity of the turntable after 0.200 s is 0.430 rev/s. b) the turntable has spun through 0.0088 revolutions in this time interval. c) the tangential speed of a point on the rim of the turntable at t = 0.002 s is 0.094 m/s.

The coefficient of kinetic friction between the object and the rough surface is 0.083. We can use the work-energy principle to solve this problem. According to the principle, the work done by all forces acting on an object is equal to the change in its kinetic energy.

The work done by the force of friction is given by W_friction = -f_k * d, where f_k is the force of kinetic friction and d is the distance traveled. The change in kinetic energy of the object is given by ΔK = K_f - K_i = (1/2) * m * v_\(f^2\) - (1/2) * m * v_\(i^2.\)

Since the object is moving on a horizontal surface, the work done by gravity is zero. Therefore, we have W_friction = ΔK.

Substituting the given values, we get:

-f_k * d = (1/2) * m * v_f^2 - (1/2) * m * v_\(i^2\)

-f_k * 8.0 m = (1/2) * m * (2.0 \(m/s)^2\) - (1/2) * m * (9.0\(m/s)^2\)

Simplifying and solving for f_k, we get:

f_k = (m/8.0 m) * [(1/2) * (2.0 \(m/s)^2\)- (1/2) * (9.0 \(m/s)^2\)]

f_k = 0.813 \(m/s^2\)

The coefficient of kinetic friction is given by μ_k = f_k / N, where N is the normal force. Since the object is moving horizontally, the normal force is equal to the weight of the object, which is N = m * g, where g is the acceleration due to gravity.

Substituting the value of f_k and N, we get:

μ_k = f_k / N = 0.813 \(m/s^2\) / (m * g)

The value of g is approximately 9.8 \(m/s^2\). Therefore, the coefficient of kinetic friction is:

μ_k = 0.083

Therefore, the coefficient of kinetic friction between the object and the rough surface is 0.083.

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Find the ratio of speeds of a proton and an alpha particle accelerated through the same voltage, assuming nonrelativistic final speeds. Take the mass of the alpha particle to be 6.64 ✕ 10−27 kg.

Answers

Answer:

The required ratio is 1.99.

Explanation:

We need to find the atio of speeds of a proton and an alpha particle accelerated through the same voltage.

We know that,

\(eV=\dfrac{1}{2}mv^2\)

The LHS for both proton and an alpha particle is the same.

So,

\(\dfrac{v_p}{v_a}=\sqrt{\dfrac{m_a}{m_p}} \\\\\dfrac{v_p}{v_a}=\sqrt{\dfrac{6.64\times 10^{-27}}{1.67\times 10^{-27}}} \\\\=1.99\)

So, the ratio of the speeds of a proton and an alpha particle is equal to 1.99.

a particle of mass m=375 g is launched with velocity of A =4 moves with a length AB=2.5m under the action of tractive force F=3.46 N making an angle 30. during its motion between A and B which is subjected to a frictional force f=1.5 N
calculate V of B by applying the kinetic energy theorem​

Answers

Answer:

The final speed is 5.78 m/s.

Explanation:

mass, m = 375 g = 0.375 kg

initial velocity, u = 4 m/s

Distance, s = 2.5 m

Angle, A = 30 degree

Force, F = 1.5 N

let the final velocity is v.

Use the work energy theorem

Work done = change in kinetic energy

\(W= 0.5 m(v^2 - u^2)\\\\F s cos A= 0.5 m (v^2 - u^2)\\\\1.5\times 2.5\times cos30= 0.5\times 0.375\times (v^2 - 16)\\\\v = 5.78 m/s\)

Which graph shows the change in velocity of an object in free fall?

Which graph shows the change in velocity of an object in free fall?

Answers

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

How many meters across is a road sign that has an angular size of 120 arcseconds and is 1 km away?

Answers

That’s the one I’m struggling withhhh aswellll

What is the powder taking the shape of?
The magnetic field
The poles
A snowman
A star

Answers

The powder takes the shape of a magnetic field.

What is the particle shape of powder?

Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying/mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.

Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.

So we can conclude that Powders are a group of particles of different sizes.

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Note: Use g=9.8 N/kg in this assignment.

A vertical spring with a force constant of 520 N/m. A block that weighs 1370 g is hanging from this spring. Hooke’s law can be applied to this spring. [7 marks]

(a) Calculate the stretch that this spring experiences to reach equilibrium due to the block hanging.
(b) Calculate the net force on the block when it is falling, and the spring stretches 1.59 cm starting from unstretched position.
(c) Calculate the acceleration of the block after it has fallen 2.05 cm.


A vertical spring is attached to a ball that is hanging from it. Ball with a mass of 0.20 kg falls when it is released stretching the spring to reach new equilibrium position. Spring has a force constant of 55 N/m. Using the law of conservation of energy, determine the following: [8 marks]
(a) Calculate the speed of the ball after it has fallen 1.5 cm.
(b) Calculate how far does the ball fall before it starts to go back up.

Answers

Answer:

16.12

thistle seed oil benefits to be deposited on your way

what is the value of pi(8.104)^2 written with correct significant numbers

Answers

Answer:206.3

Explanation:

For the purpose of calculating the electric field strength by means of Gauss’s law, determine whether approximate cylindrical symmetry holds in each of the following situations.
Part (a) We have a 3.6-m long copper rod of radius 1 cm, carrying a charge of 1.5 nC distributed uniformly along the rod’s length. We want to calculate the electric field strength at a point 4.9 cm from the rod near its center.
TRUE FALSE
Part (b) We have a 8.9-cm long copper rod of radius 1 cm, carrying a charge of 1.5 nC distributed uniformly along the rod’s length. We want to calculate the electric field strength at a point 4.9 cm from rod near its center.
TRUE FALSE
Part (c) A 1.9-m long wooden rod is glued end-to-end to a 1.9-m long plastic rod, both of radius 1 cm. The combined rod is then painted with an electrically charged paint so that it is covered with a uniform charge density, giving it total charge of 1.5 nC. We want to calculate the electric field strength at a point 4.9 cm from the rod near its center.
TRUE FALSE
Part (d) For the same charged rod as in part (c) we want to calculate the electric field strength at a point 8.9 m from each end of the rod.
TRUE FALSE

Answers

Answer:

1. True

2. False

3. True

4. False

Explanation:

a) In this case, length of the copper rod is 3.6 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.

b) In this case, length of the copper rod is 8.9 cm which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.

c) In this case, length of the copper rod is 3.8 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.

d) In this case, length of the copper rod is 3.6 m which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.

In the figure, suppose the length L of the uniform bar is 3.2 m and its weight is 220 N. Also, let the block's weight W = 270 N and the angle θ = 45˚. The wire can withstand a maximum tension of 450 N. (a) What is the maximum possible distance x before the wire breaks? With the block placed at this maximum x, what are the (b) horizontal and (c) vertical components of the force on the bar from the hinge at A?

Answers

Answer:

a)   x = 2.46 m

b)   318.2 N

c)    177.8 N

Explanation:

Need to resolve the tension of the string at end say B.

The vertical upward force at B due to tension is 450 sin 45°.  

Using Principle of Moments, with the pivot at A,

Anti clockwise moments = Clockwise moments

450 sin 45° X 3.2   = 220 X (3.2/2) + (270 X x)  

x = 2.46 m

(b) The horizontal force is only due to the wire's tension, so it is  

450 cos 45° = 318.2 N

(c) total downward forces = 270 + 220 = 496 N  

Total upward forces = 450 sin 45° (at B) + upForce (at A)

Equating, upForce = 496 - 318.2  

= 177.8 N

Why is DNA a useful evolutionary clock?

Answers

Because analyzing DNA from present-day and ancient genomes provides a complementary approach for dating evolutionary events. Because certain genetic changes occur at a steady rate per generation, they provide an estimate of the time elapsed.

A woman lifts a barbell 2.0 m in 5.0 s. If she lifts it the same distance in 10 s, the work done by her is:

Answers

The work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.

The work done by the woman lifting the barbell can be calculated using the formula:

work = force x distance

Assuming the force required to lift the barbell remains constant, the work done is directly proportional to the distance lifted.

Therefore, if the woman lifts the barbell 2.0 m in 5.0 s, the work done is:

work1 = force x distance1 = force x 2.0 m

If she lifts it the same distance in 10 s, the work done is:

work2 = force x distance2 = force x 2.0 m

Since the distance lifted is the same in both cases, the work done by the woman is the same, and can be expressed as:

work1 = work2 = force x 2.0 m

Therefore, the work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.

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An injured monkey sits perched on a tree branch 4.5 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 85.5 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey

Answers

Answer:

3.03°

Explanation:

Given that

Height of the tree branch, h = 4.5 m

Distance of the veterinarian away, d = 85.5 m

The vet is to aim at the monkey at a particular angle. If we consider the force of gravity that will be acting on the dart. Then the angle that will be needed will be calculated as this.

So the angle is

Tan θ = opposite / adjacent

Tan θ = 4.5 m/ 85.5 m

Tan θ = 0.053, then

θ = Tan^-1 (0.053)

θ = 3.03°

Therefore, the angle needed is 3.03°

A researcher investigated whether job applicants with popular (i.e. common) names are viewed more favorably than equally qualified applicants with less popular (i.e. uncommon) names. Participants in one group read resumes of job applicants with popular (i.e. common) names, while participants in the other group read the same resumes of the same job applicants but with unpopular (i.e. uncommon) names. The results showed that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level

Answers

The researcher did not find strong evidence to support the idea that job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

What factors plan an important role in the hiring process for a job?

It sounds like the researcher conducted an experiment to investigate whether job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

Based on the information provided, the researcher found that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level.

The factors that play an important role in the hiring process for a job:

(1) Qualifications and experience: Employers typically look for candidates who possess the necessary qualifications and experience for the job. This includes education, training, certifications, and work experience.

(2) Skills and abilities: Employers also consider a candidate's skills and abilities related to the job. These may include technical, interpersonal, communication, and problem-solving skills.

(3) Personal characteristics: Personal characteristics, such as motivation, work ethic, and adaptability, can also play a role in the hiring process. Employers may look for candidates who demonstrate a positive attitude, a willingness to learn, and the ability to work well with others.

(4) Fit with company culture: Companies may also consider whether a candidate fits with their company culture, values, and mission. This can include factors such as teamwork, creativity, and innovation.

Learn more about evaluations here:

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Two blocks of the same mass but made of different material slide across a horizontal, rough surface and eventually come to rest. A graph of the kinetic energy of each block as a function of position along the surface . Which of the following is a true statement about the frictional force Ff that is exerted on the two blocks?
a. Fr=2F8, since the force of friction is represented as the slope for each of the two curves.
b. Fr.-12Fri, since the force of friction is represented as the inverse slope for each of the two curves.
c. Ff:=2Ffi, since the force of friction is represented as the inverse of the area bound by each curve and th horizontal axis.
d. Fe=1/2Fr., since the force of friction is represented as the area bound by each curve and the horizontal axis.

Answers

Answer:

a. \(\mathbf{F_{f_2} = 2 F_{f1}}\), \(\mathbf { since \ the \ force \ o f \ friction \ is \ represented \ as \ the \ slope \ for \ each \ of \ the \ two \ curves.}\)

Explanation:

From the information given;

Using the work-energy theorem

ΔKE = W = \(\mathbf{ F_f \times r}\)

K = \(\mathbf{ F_f \times r}\)

\(\dfrac{K_1}{K_2} = \dfrac{F_{f1}}{F_{f2}} (\dfrac{r_1}{r_2})\)

Since \(K_1 = K_2\) and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

Then;

\(1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})\)

\(\mathbf{F_{f_2} = 2 F_{f1}}\)

Two blocks of the same mass but made of different material slide across a horizontal, rough surface and

Why does a sharp nail easily penetrate wood,but not a blunt nail

Answers

Answer:

Force and pressure

Explanation:

Pressure is inversely proportional to area

Or by using:

Force and pressure

Of course a burnt nail is “ scorched “ meaning it doesn’t have that much “ power “ or it an chip away

Force and pressure

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