A hoop (i=mr^2) of radius 0.50 m and a mass of 0.20 kg is released from rest and allowed to o go roll down an inclined plane. how fast is it moving after dropping a vertical distance of 3.0 m?
a. 7.7 m/s
c. 5.4 m/s
b. 6.2 m/s
d 3.8 m/s
Answers
The movement of a hoop has converted potential energy to kinetic energy. The hoop dropped vertically for a distance of 3.0 m and is now moving at a velocity of 7.7 m/s. Therefore, the correct answer is option A.
To determine the velocity of a hoop of mass 0.20 kg and radius 0.50 m after it has fallen a vertical distance of 3.0 m, we can use the principle of conservation of energy.
At the top of the incline, the hoop has potential energy given by mgh, where m is the mass, g is the acceleration due to gravity, and h is the height of the incline.
At the bottom of the incline, all of the potential energy has been converted to kinetic energy given by \(1/2mv^2\), where v is the velocity of the hoop.
Using conservation of energy, we can set the initial potential energy equal to the final kinetic energy and solve for v. The potential energy at the top of the incline is mgh = \((0.20 \;kg)(9.81 \;m/s^2)(3.0 \;m)\) = 5.89 J.
The kinetic energy at the bottom of the incline is \(1/2\;mv^2\), so \(1/2(0.20 \;kg)v^2 = 5.89 J\). Solving for v, we get v = 7.7 m/s.
Therefore, the hoop is moving at a velocity of 7.7 m/s after dropping a vertical distance of 3.0 m. This demonstrates the conversion of potential energy to kinetic energy and the use of conservation of energy in solving physics problems. Therefore, the correct answer is option A.
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Related Questions
2. A quantity of gas is trapped by a piston in a cylinder with thin metal walls. The piston is free to move
without friction within the cylinder.
a) The air in the freezer is at atmospheric pressure, which is 1.0 × 105Pa. The area of the piston in
contact with the air in the freezer is 2.4 × 10–3m2
.
i. Calculate the force exerted on the piston by the air in the freezer.
ii. When the cylinder is first placed into the freezer, the temperature of the gas in the cylinder decreases
and the air pushes the piston into the cylinder. Calculate the work done on the piston by the air in the
freezer as the air pushes the piston at distance of 0.021m into the cylinder.
b) The initial temperature of the cylinder and the gas is 21°C and, in the freezer, the temperature of the
cylinder decreases to –18°C. The thermal capacity of the cylinder is 89J/ °C. Calculate the change in
the internal energy of the cylinder.
Answers
a)
i. The force exerted on the piston by the air in the freezer is 240 N.
ii. The work done on the piston by the air as it pushes the piston 0.021 m into the cylinder is 5.04 J.
b) The change in the internal energy of the cylinder is 3486 J.
a)
i. To calculate the force exerted on the piston by the air in the freezer, we can use the formula:
Force = Pressure * Area
Given:
Pressure (P) = 1.0 × \(10^5\) Pa
Area (A) = 2.4 ×\(10^(^-^3^) m^2\)
Substituting these values into the formula, we have:
Force = (1.0 × 10^5 Pa) * (2.4 ×\(10^(^-^3^) m^2)\)
= 240 N
ii. To calculate the work done on the piston by the air in the freezer as the air pushes the piston, we can use the formula:
Work = Force * Distance
Given:
Force = 240 N
Distance (d) = 0.021 m
Substituting these values into the formula, we have:
Work = (240 N) * (0.021 m)
= 5.04 J
b) To calculate the change in the internal energy of the cylinder, we can use the formula:
ΔU = mcΔT
Given:
Initial temperature (T1) = 21°C = 21 + 273 = 294 K
Final temperature (T2) = -18°C = -18 + 273 = 255 K
Thermal capacity (c) = 89 J/°C
Substituting these values into the formula, we have:
ΔU = (89 J/°C) * (294 K - 255 K)
= 3486 J
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40. A fly buzzes four and a half times around Kit Yan's head. The fly ends up on the opposite side from where it started. If the diameter of his head is 14 cm, what is the total distance the fly travels and its total displacement?
a. The distance is 63pi cm with a displacement of zero.
b. The distance is 7 cm with a displacement of zero.
c. The distance is 63pi cm with a displacement of 14 cm.
d. The distance is 7 cm with a displacement of 63pi cm.
Answers
Answer:
A fly is sitting at the midpoint of a wooden chord of a circular wheel. The wheel has a radius of 10cm and the chord has a length of12cm a How far from the hub (center) is the fly? b The wheel is spun. What is the path of the fly?
Explanation:
The distance is 63π cm with a displacement of 14 cm.
Hence, the correct option is C.
Each time the fly buzzes around Kit Yan's head, it travels the circumference of his head. The circumference of a circle is given by the formula:
Circumference = π × Diameter
Given the diameter of Kit Yan's head is 14 cm:
Circumference = π × 14 cm = 14π cm
The fly buzzes four and a half times around his head, so the total distance it travels is:
Total Distance = 4.5 × Circumference = 4.5 × 14π cm = 63π cm
Now, let's consider the displacement. Displacement is the straight-line distance between the initial and final positions.
Since the fly ends up on the opposite side from where it started, the displacement is equal to the diameter of Kit Yan's head, which is 14 cm.
Therefore, The distance is 63π cm with a displacement of 14 cm.
Hence, the correct option is C.
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g Two point charges -6 C and -8 C charge are 12 cm apart. What is the magnitude of the electric field at a point half-way between the two charges
Answers
Explanation:
q1 = -6
q2 = -8
d^2 = (6/100)^2 = 0.0036
k = 1/4*(pi*E) where E js the permittivity of free space
F = (k*q1*q2)/(d^2)
Substitute your values into this equation and solve
Did it seem the Law of Reflection held for planar waves? How could you check to be sure?
Answers
The Law of Reflection held for planar waves due to partial transmission of the wave.
What is a Planar wave?This is a wave which has a constant physical quantity which is perpendicular to the direction of wave travel.
These type of wave has normal wave characteristics such as frequency and is partially transmitted through reflection.
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Details The force on a particle is described by 10x³ - 5 at a point x along the x-axis. Find the work done in moving the particle from the origin to x = 2.
Answers
Answer:
To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.
The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):
W = ∫(0 to 2) (10x³ - 5) dx
Integrating the force function, we get:
W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2
Now, substituting the upper limit (2) and lower limit (0) into the equation:
W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]
= [2.5(16) - 10] - [0 - 0]
= 40 - 10
= 30
Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.
Explanation:
Relative density is known as ----------.A. gravity densityB. specific gravityC. weight
Answers
The relative density of the substance is equal to the density of the substance concerning the density of the reference substance.
The relative density of the substance is known as the specific gravity.
Hence, option B is the correct answer.
6. A student placed a cardboard box at the
bottom of a hill. The student then released a
ball from a point on the hill. The ball collided
with the box, and the box moved a distance
of 2 meters before both the box and the ball
came to rest. Which change to the initial
conditions would be most likfly to result in
the box moving a greater distance?
A. Decreasing the mass of both the ball and the
box
B. Decreasing the mass of the ball and
increasing the mass of the box
C. Increasing the mass of the ball and
releasing it from a lower point on the hill
D. Decreasing the mass of the box and
releasing the ball from a higher point on
the hill
Answers
The correct option for the given question is D. Decreasing the mass of the box and releasing the ball from a higher point on the hill.
A cardboard box was placed at the bottom of a hill, and a ball was released from a point on the hill. The box moved a distance of 2 meters before coming to rest, along with the ball. To move the box a greater distance, a change in the initial conditions is required. It can be achieved by decreasing the mass of the box and releasing the ball from a higher point on the hill.
According to the law of conservation of momentum, the total momentum before and after the collision is conserved. If the mass of the box is decreased, its momentum will be less after the collision. Therefore, the momentum of the ball will be greater than the momentum of the box, allowing it to move the box to a greater distance. Thus the correct option is Option D.
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Three different resistors are connected in series to a battery. Which of the following statements is correct about this circuit? The equivalent resistance of the circuit is the algebraic sum of all resistors. O All of these options are true. Currents through all resistors are the same. O Total voltage on this combination is an algebraic sum of voltages on each resistor.
Answers
When three different resistors are connected in series to a battery, the current through all resistors is the same.
In a series circuit, there is only one path for current to flow through. Current is the same through each component.
In a series circuit, the total voltage is divided across each component, and the voltage drop across each component is proportional to its resistance.
The equivalent resistance of the circuit is the sum of all resistors. It is not an algebraic sum, rather it is the arithmetic sum of the resistors. Hence, option A is incorrect.
The other two statements are also incorrect as the voltage on each resistor is not the same, it is divided across each resistor in proportion to its resistance. Therefore, the correct statement about the given circuit is: Currents through all resistors are the same.
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A force F~ = Fxˆı + Fyˆ acts on an object with Fx = 4 N and Fy = 6 N. The angle between F~ and the displacement vector ~s is 18◦ , and 106 J of work is done by F~. Find the magnitude of ~s. Answer in units of m
Answers
The magnitude of the vector displacement is 15.65 m.
Resultant force
The resultant force acting on the object is calculated as follows;
\(F = \sqrt{F_x^2 + F_y^2} \\\\F = \sqrt{4^2 + 6^2} \\\\F = 7.21 \ N\)
Displacement of the vectorThe displacement of the vector is calculated as follows;
W = Fs cosθ
\(s = \frac{W}{Fcos(\theta)} \\\\s = \frac{106}{7.12 \times cos(18)} \\\\s = 15.65 \ m\)
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Dark colors absorb light. What happens with light colors?
A. They absorb light.
B. They contain light.
C. They split apart light.
D. They reflect light.
Answers
Two wires of circular cross section are made of the same metal. Wire 1 has radius rr and length LL; wire 2 has radius 2r2r and length 2L2L. The potential difference between the ends of the wire is the same for both wires. Find the ratio of the resistance of wire 2 to the resistance of wire 1.
Answers
Answer:
Ratio of wire 2 to wire 1 is 0.5 : 1
Explanation:
Wire 1:
length = L
radius = r
Wire 2:
length = 2L
radius = 2r
Resistance of a conductor varies directly as the length and inversely as the cross sectional area. Mathematically
\(R = \frac{pl}{a}\)
l = length of conductor
a = cross sectional area of the conductor
p = resistivity of the material with which the conductor is made.
since we are considering the same material, we can ignore the resistivity of the wire.
For wire 1
cross sectional area = \(\pi r^{2}\)
therefore,
resistance R = \(\frac{L}{\pi r^{2} }\)
For the second wire 2
cross sectional area = \(4\pi r^{2}\)
therefore,
resistance R = \(\frac{2L}{4\pi r^{2} }\)
Ratio of wire 2 to wire 1 will be
\(\frac{2L}{4\pi r^{2} }\) ÷ \(\frac{L}{\pi r^{2} }\) = \(\frac{2L}{4\pi r^{2} }\) x \(\frac{\pi r^{2} }{L}\)
Ratio of resistance of wire 2 to wire 1 = 2/4 = 0.5 : 1
A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the arm of the centrifuge is 21m what is the speed of the centrifuge?
Answers
Answer:
\(approx.= 25\frac{m}{s}\)
Explanation:
Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:
\(a=\frac{V^{2} }{r}\)
which allows us to solve for the velocity:
\(V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...\)
Answer:
25 m/s
Explanation:
A = v^2r
The square root of Ar = v
V = square root of 3.04 x 21 x 9.8 = 25m/s
Make sure to add 9.8 as acceleration is 3.04g or 3.04 x 9.8
1. You have 750 g of water at 10°C in a large insulated beaker. How much boiling water at 100°C must you add to this beaker so that the final temperature of the mixture will be 75°C? For water, c = 4.19 × 103 J/(kg • K). 1950 g 2001 g 1800 g 2243 g
Answers
To calculate the amount of boiling water that must be added to the beaker, you need to use the heat capacity equation. This equation is given by:
Q = mcΔT
What is equation?An equation is a mathematical statement that expresses the equality of two expressions. It is typically used to describe the relationship between two variables or an expression and an unknown value. An equation is usually written as a statement of equality between two expressions separated by an equal sign.
Where Q is the amount of heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Since you are starting with 750 g of water at 10°C and you want to end up with a final temperature of 75°C, you can rearrange the equation to solve for m, the mass of boiling water:
m = Q/(cΔT) = (750g × 4.19 × 103 J/(kg•K) × 65°C)/(4.19 × 103 J/(kg•K)) = 1950 g
Therefore, you need to add 1950 g of boiling water at 100°C to the beaker in order to reach the desired final temperature of 75°C.
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An electromagnetic wave of wavelength 435nm is traveling in vacuum in the − z-direction. The electric field has amplitude 2. 70×10−3v/m and is parallel to the x-axis.
Answers
The frequency of wave generated is \(6.9 * 10^{14} Hz\).
The electromagnetic wave travels at the speed of light.
Speed of light (c) = \(3 * 10^{8} m/s\)
Given wavelength is 435nm = \(435 * 10^{-9} m\)
We can find the frequency(f) of the wave by using the relationship between f and c:
Frequency = speed of light/ wavelength
= \(3 * 10^{8} / 435 * 10^{-9}\)
= \(6.9 * 10^{14} Hz\)
So the frequency of wave generated is \(6.9 * 10^{14} Hz\).
Complete question:
An electromagnetic wave of wavelength 435nm is traveling in vacuum in the − z-direction. The electric field has amplitude 2. 70×10−3v/m and is parallel to the x-axis. Find frequency of wave generated.
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burning of fuel in a car's motor reaches temperatures of 1,038 k. if the atmosphere is at 300 k, what is the maximum efficiency (in percent) of this heat engine? use exact numbers to two decimalplaces; do not estimate, do not include the % sign.
Answers
The efficiency of a heat engine is a measure of how much useful work it can produce from a given amount of heat energy input.
The Carnot efficiency formula provides an upper bound on this efficiency, and it depends only on the temperatures of the hot and cold reservoirs between which the engine operates. In this case, the hot reservoir is the temperature of the burning fuel in the car's engine (1038 K), and the cold reservoir is the ambient temperature of the atmosphere (300 K). Plugging these values into the Carnot efficiency formula gives us the maximum possible efficiency, which is 71.11%.
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Someone is singing in a shower that measures 2. 40 meters from floor to ceiling, and notices their voice causes the shower to resonate with a fundamental frequency of 73 Hz
Answers
When a person sings in a shower and causes the shower to resonate with a fundamental frequency of 73 Hz, this is an example of a standing wave, also known as a resonance.
The fundamental frequency of a standing wave is determined by the length of the resonant cavity, which in this case is the shower. The fundamental frequency is related to the length of the cavity by the equation:
f = v / 2L
where f is the frequency, v is the velocity of sound in the medium (in this case, air), and L is the length of the cavity. Given that the shower has a length of 2.40 meters and the fundamental frequency is 73 Hz, we can use the equation above to calculate the velocity of sound in air.
73 = v / (2 * 2.40)
Solving for v, we get:
= v
= (73 * 2 * 2.40)
= 350.4 m/s
The speed of sound in air is approximately 343 m/s at 20 °C at sea level. The velocity of sound in air can change with temperature, humidity and pressure. Given that the velocity of sound in air is around 343 m/s, the frequency of 73 Hz is a close match to the fundamental frequency of the shower with 2.40 meters high, It is important to note that the fundamental frequency is not the only frequency that could resonate in the shower, other overtones and harmonics might also resonate.
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Question- Someone is singing in a shower that measures 2.40 meters from floor to ceiling, and notices their voice causes the shower to resonate with a fundamental frequency of 73 Hz. Here, this situation is an example of? justify. The given situation is an example of which physics phenomenon and justify the given example with some details.
provide 2 important pitching tips you can tell someone else. softball
Answers
Tip 1 - throwing a fastball. Use two points to keep your arm properly aligned your biceps brush your ear at the top of the backswing, and your pitching hand brushes your hip at release.
Tip 2 - throwing a curveball. Pictures should know that in order to maximize your curves, you should visualize a series of dots from the mound to the outside corner of the plate. Pitch along those dots.
Tip 3 - throwing a fast pitch rise. It’s possible that your wrist snap may be sideways. Play with different grips or finger pressures and try to relax them.
Tip 4 - throwing a change-up. Don’t always throw the change-up in a given situation. Make sure to change your pitch selection.
Tip 5 - throwing a drop-ball. Keep your pitching arm close to your body to avoid injury.
how long will it take an object traveling at 25m/s to reach a distance of 125 meters
Answers
Answer:
5 seconds
Explanation:
25 x 5 = 125
A toy electric car uses 2 amps of current when the car is running. If the resistance of the car's motor is 3ohms, what is the voltage of the battery in the car?
fog
Answers
The voltage of the battery in the car, given that the toy car uses 2 amps of current when the resistance is 3 ohms is 6 volts
How do I determine the voiltage of the battery?Ohm's law gives a well defined relationship between voltage and current. This is shown by the formula below:
Voltage (V) = Current (I) × resistance (R)
V = IR
From the question given above, the following data were obtained:
Current used by car (I) = 2 ampsResistance of motor (R) = 3 ohmsVoltage of battery (V) = ?The voltage of the battery can be obtained by using the above formual:
Voltage (V) = Current (I) × resistance (R)
Voltage of battery = 2 × 3
Voltage of battery = 6 volts
This, the voltage of the battery is 6 volts
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A box is moved up a conveyor belt without slipping. Which of the following statements is correct about the friction force on the box (from the conveyor belt)? a) The friction force is kinetic and points up the incline Ob) The friction force is kinetic and points down the incline c) The friction force is static and points up the incline O d) The friction force is static and points down the incline
Answers
Option (d) is correct. The friction force acting on the box is static and points down the incline.
Can the cosmic microwave background radiation be explained by individual stars and galaxies?The question asks about the correct statement regarding the friction force on a box moved up a conveyor belt without slipping. The friction force is the force that opposes the relative motion between two surfaces in contact and it acts parallel to the surface of contact.
When a box is moved up a conveyor belt without slipping, it means that the box is moving in the same direction as the conveyor belt's motion, and therefore, the box and the conveyor belt are in contact, and friction acts between them.
Option (d) is correct. The friction force acting on the box is static and points down the incline. This is because the box is moving up the conveyor belt without slipping, and the conveyor belt is moving in the upward direction.
Therefore, the relative motion between the box and the conveyor belt is in the downward direction. The static friction force acts in the direction opposite to the relative motion, which is down the incline. The friction force is static because the box is not slipping on the conveyor belt, and the magnitude of the friction force is equal to the force that the box exerts on the conveyor belt.
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The correct statement about the friction force on the box (from the conveyor belt) is: c) The friction force is static and points up the incline.
When the box is moved up the conveyor belt without slipping, it indicates that the box and the conveyor belt are moving together, maintaining their points of contact. In this situation, the friction force between the box and the conveyor belt is static, as there is no relative motion between their surfaces.
Static friction prevents the box from slipping and helps it move along with the conveyor belt. Since the box is moving up the incline, the static friction force also points up the incline, acting in the same direction as the box's movement. This friction force is essential for the box to maintain its position on the conveyor belt and follow its upward motion.
In summary, when a box is moved up a conveyor belt without slipping, the friction force experienced by the box from the conveyor belt is static and points up the incline, allowing the box to stay in contact with the conveyor belt and move along with it. Hence, the correct answer is Option C.
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How many significant figures are in 0.0069
Answers
Answer:
2
Explanation:
If the force to stretch a spring is given as k = (100N/m), then what is the potential energy of the spring if it is stretched 1 meters from rest?
Answers
Answer:
50 Joules
Explanation:
an apple of mass 444 g breaks loose of a tree and falls for 1.11 s before being caught by a person. the person’s hand is moved downward 9.99 cm by the apple as it is caught. (a) describe the action-reaction pairs of forces for the apple and the earth and for the apple and the hand. (b) find the amount that the earth (m
Answers
The action-reaction pairs of forces for the apple and the earth are; they both applies force on each other. The Earth moves with a mass of 0.452 kg when an apple of 0.444 kg falls off the tree and accelerates downwards due to gravity.
(a) Action and reaction pairs of forces are pairs of forces that objects apply on each other. They are equal in magnitude but opposite in direction. When an apple falls off a tree, there are two action-reaction pairs of forces that can be described; the earth applies a force on the apple, and the apple applies a force on the earth. The apple also applies a force on the person's hand, and the person's hand applies a force on the apple.
(b) Calculation of the amount that the Earth (m) moves with the same force as the apple is accelerated downwards due to gravity.
In this case:
mass of apple, m = 0.444 kg f = 4.44
Newtons fa l time, t = 1.11 s
displacement, s = 9.99 cm = 0.0999 m
Using the formula:
distance = 1/2 × g × t2s = 1/2 × 9.81 m/s2 × (1.11 s)2s = 5.45 m
Therefore, the mass of the Earth that moves with the same force as the apple is: m = F / a
where F is the force exerted by the apple on the Earth and a is the acceleration of the Earth. Using Newton's second law:
F = ma F = 4.44 Ns = 5.45 ma =
F / mam = F / a = 4.44 N / 9.81 m/s2 = 0.452 kg
Therefore, the Earth moves with a mass of 0.452 kg when an apple of 0.444 kg falls off the tree and accelerates downwards due to gravity.
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PLEASE HELP I PAY 88 POINTS AND THANK YOU AND BRAINLIEST
Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.
Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)
Answers
Answer: Down below is the answer in complete sentences!
Explanation:
PART A:
Gravity and Acceleration are two additional forces acting upon the sled.
PART B:
Gravity will affect the sled by pulling it down, since the slope of the hill is negative.
Acceleration will affect the sled by gradually increasing it's speed, since the slope is downwards, which in addition to the initial force exerted plus gravity increases the speed, thus the sled accelerates.
Which best describes energy changes in a system?
Energy is not conserved, but it cannot be created or destroyed.
Energy is conserved, but it can be created or destroyed.
Energy is conserved, and it cannot be created or destroyed.
Energy is not conserved, and it can be created or destroyed.
Answers
Answer:
The correct answer is: Energy is conserved, and it cannot be created or destroyed. This is known as the law of conservation of energy, which states that in a closed system, the total amount of energy remains constant and cannot be created or destroyed, only transformed from one form to another. This means that energy can be converted from one form to another, such as from potential energy to kinetic energy, but the total amount of energy in the system remains the same.
What would happen to our transportation if a CME hit earth
Answers
Answer:
here is the answer .
Explanation:
If a Coronal Mass Ejection (CME) hit Earth, it would cause a huge power surge that could damage or destroy many electrical systems, including those used to power transportation systems. This would mean that many forms of transportation, including cars, buses, trains, and airplanes, could be out of commission for an indefinite period of time. There is also the possibility that communication systems, such as the internet and telephone networks, could be affected, making it impossible for people to effectively coordinate transportation.
A radioactive substance, kryptonite, has a half-life of 5 hours. If there is 1500 mg of kryptonite at 10 am in the morning, determine a function which models this situation. How much will be left"
Answers
The half-life of a radioactive substance is the time it takes for half of the substance to decay. So, if there is 1500 mg of kryptonite at 10 am, then there will be 750 mg of kryptonite left after 5 hours, 375 mg of kryptonite left after 10 hours, and so on.
The function that models this situation is A(t)=1500(0.5) t
where A(t) is the amount of kryptonite left after t hours.
To find how much kryptonite will be left at 1 pm, we can substitute t=5 into the function. This gives us A(5)=1500(0.5) 5
=375 mg.
So, there will be 375 mg of kryptonite left at 1 pm.
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what is the magnitude of the angular momentum of the asteroid about the earth just before the asteroid strikes the moon?
Answers
The Earth's rotation is slowed down as a result, although there is a slight price to pay. Due to the conservation of angular momentum, when the Earth's rotation slows down, something else must acquire angular momentum to compensate.
What magnitude of the angular momentum of the asteroid?The angular momentum of an asteroid is obtained from its rotation rate, which is shown by the period of its light curve, its shape.
Which is suggested by the amplitude of its light curve, and, whenever possible, its size, which is indicated by polarimetry or radiometry.
However, if there are no external torques, a fundamental principle of physics states that energy and angular momentum are preserved.
Therefore, The moon is therefore traveling away from the Earth while gaining energy and angular momentum.
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Which law best describes this behavior of gases in the Sun?
Answers
Answer:
The extreme pressure from the weight of the gases that make up the Sun raises the temperature of the core enough for the nuclear reactions to take place, Which law best describes this behavior of gases in the Sun? A. Charles law.
Explanation:
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Calculate the net force on particle q₁.First, find the direction of the force particle q2 isexerting on particle q₁. Is it pushing to the right (+),or to the left (-)?
Answers
All we need to do in order to find out the direction is to take into account the sign of the charge. As they are both positive, the particles will repel each other, which can be seen on the following drawing:
Thus, particle q2 will try to push particle q1 to the left
The answer is: -
