A hypothesis is

A) An experiment
B) an untestable statement
C) an education guess
D) A procedure
​

Answer:

Explanation:

charge on each proton = 1.6 x 10⁻¹⁹ C

mass of proton = 1.67 x 10⁻²⁷ kg

Electrostatic force of repulsion Fe = 9 x 10⁹ x ( 1.6 x 10⁻¹⁹ )² / d²

= 23.04 x 10⁻²⁹ / d²

Gravitational  force of attraction = G Mm / d²

M = m = 1.67 x 10⁻²⁷ kg

Gravitational  force of attraction  Fg = 6.67  x 10⁻¹¹ x ( 1.67 x 10⁻²⁷ )² / d²

= 18.60 x 10⁻⁻⁶⁵ / d²

So Fg is far less than Fe and former is attractive , later is repulsive .

Fe > Fg, opposite direction , is the answer .

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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Answer:

15,000 N

Explanation:

F = ma = (1,500 kg)(10 m/s^2) = 15,000 N

Based on the observations during the experiment, the car's velocity can be described as follows. .

The car had a   constant speed of approximately 60 km/h throughout the experiment,indicating a consistent rate of motion.

In terms of   direction, the car initially traveledin a straight line towards the east.

However, after a certain point,   it made a sharp turn towards the north, changing its direction but maintaining thesame speed.

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Answer:

The force exerted by the spring on the block is given by Hooke's Law:

F = -kx

where F is the force, k is the spring constant, and x is the displacement from the equilibrium position. Since the spring is initially unstretched, x = 0 at t = 0. The negative sign indicates that the force is in the opposite direction to the displacement.

The initial velocity of the block is -10.0 m/s, so its initial kinetic energy is:

KE = (1/2) * m * v^2

KE = (1/2) * (2.00 kg) * (-10.0 m/s)^2

KE = 100 J

According to the law of conservation of energy, the total mechanical energy of the system (spring-block) is conserved. Therefore, at any time t, the sum of the kinetic and potential energies is constant:

KE + PE = constant

where PE is the potential energy stored in the spring, given by:

PE = (1/2) * k * x^2

where x is the displacement from the equilibrium position. Since the spring is initially unstretched, the potential energy is also zero at t = 0.

At any time t, the displacement x can be expressed in terms of the velocity v using the equation of motion:

v = dx/dt

where x is the displacement from the equilibrium position. Since the block is moving in the negative direction at t = 0, we have:

x = -vt

Substituting this expression for x into the potential energy equation, we get:

PE = (1/2) * k * (-vt)^2

PE = (1/2) * k * v^2 * t^2

Substituting the given values, we get:

PE = (1/2) * (400 N/m) * (10.0 m/s)^2 * t^2

PE = 2000 t^2 J

At any time t, the total mechanical energy is:

E = KE + PE

E = 100 J + 2000 t^2 J

The maximum potential energy is equal to the maximum kinetic energy, which occurs when the velocity is zero at the equilibrium position. Therefore, we can solve for the time at which the velocity is zero:

KE + PE = 100 J + 2000 t^2 J = 0

Solving for t, we get:

t = sqrt(-0.05) s

This result is not physically meaningful because it implies a negative time. This indicates that the block does not come to a stop at the equilibrium position but instead continues to oscillate back and forth with a periodic motion.

To find the amplitude of the motion, we can use the equation of motion for simple harmonic motion:

x = A * sin(ωt)

where A is the amplitude, ω is the angular frequency, and t is the time. The angular frequency is given by:

ω = sqrt(k/m)

Substituting the given values, we get:

ω = sqrt(400 N/m / 2.00 kg)

ω = 10 rad/s

To find the amplitude, we need to use the initial conditions. At t = 0, the block has a negative velocity and is moving in the negative direction. Therefore, the displacement at t = 0 is:

x = -A

Substituting this into the equation of motion, we get:

-A = A * sin(0)

-A = 0

Explanation:

Therefore, the amplitude is zero. This means that the block does not oscillate but instead moves with a constant velocity of -10.0 m/s in the negative direction.

Explanation:

For electromagnetic waves    c = wavelength * frequency

 c = speed of light = 3 x 10^8 m/ s

                                    3 x 10^8 m/s = wl * 33 x 10^9  Hz

                                        wl = .009 m      ( or  9 mm)

If a radar signal that has a frequency of 33 GHz, Then the wavelength of the radar signal is  9 mm.

Wavelength is a fundamental concept in the study of waves, which are disturbances that propagate through space or a medium. It is defined as the distance between two consecutive points in a wave that are in phase, meaning that they have the same position in their respective cycles.

In other words, the wavelength is the spatial period of a wave, which is the distance over which the wave repeats itself. It is commonly represented by the Greek letter lambda (λ) and is measured in meters (m), although it can also be expressed in other units such as nanometers (nm) or micrometers (μm).

Wavelength is a key property of waves, as it determines many of their characteristics and behavior. For example, the wavelength of an electromagnetic wave (such as light or radio waves) determines its color or frequency, and thus its energy and ability to interact with matter. Similarly, the wavelength of a sound wave determines its pitch, and thus its perceived tone and musical quality.

The relationship between wavelength, frequency, and velocity is described by the wave equation, which states that the velocity of a wave is equal to the product of its wavelength and frequency. This relationship is important for understanding how waves behave and interact with their environment, such as when they are reflected, refracted, or diffracted.

So, the wavelength is a crucial concept in the study of waves, as it defines their properties and behavior. It is the distance between two consecutive points in a wave that are in phase, and is measured in meters or other units. The relationship between wavelength, frequency, and velocity is described by the wave equation, which is fundamental to the study of waves in various fields such as physics, engineering, and communication.

Here in the Question,

The wavelength of a radar signal can be calculated using the formula:

wavelength = speed of light/frequency

where the speed of light is approximately 3 x 10^8 meters per second.

Plugging in the given frequency of 33 GHz (33 x 10^9 Hz), we get:

wavelength = 3 x 10^8 / (33 x 10^9)

wavelength = 0.009090909... meters

Therefore, By rounding to the nearest millimeter, the wavelength of the radar signal is approximately 9 mm.

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Answer:

The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.

Answer:

the property of light travelling in a straight lines in a homogenous transparent medium

Explanation:

(a) Current in the upper branch is -0.4 A

(b) Current in the middle branch is 1.6 A

(c) Current in the lower branch is 1.2 A

Kirchhoff's current law states that, at a node, the current entering the circuit is equal to the current leaving the circuit. That means the sum of all currents at the node is zero.

Here,

According to Kirchhoff's current law,

I₁ + I₂ = I₃

Taking the clockwise direction from upper loop,

According to Kirchhoff's voltage law,

2I₁ -10 + 3I₁ - 4I₂ + 20 - I₂ = 0

5I₁ - 5I₂ = -10

I₁ - I₂ = -2

Taking clockwise direction from the lower loop,

According to Kirchhoff's voltage law,

-4I₂ + 20 - I₂ + 2I₂ - 10I₃ = 0

-5I₂ - 10I₃ = -20

Dividing by 5,

I₂ + 2I₃ = 4

So we get three equations,

I₁ + I₂ = I₃                 (1)

I₁ - I₂ = -2                 (2)

I₂ + 2I₃ = 4               (3)

From the above equations,

Adding (2) and (3), we get,

I₂ = 3I₃ - 2

Applying this in  eqn(3),

3I₃ - 2 + 2I₃ = 4

5I₃ = 6

I₃ = 1.2 A

So, I₂ = 3I₃ - 2 =3X 1.2 - 2

I₂ = 1.6 A

I₁ = -2 + I₂ = -2 + 1.6

I₁ = -0.4 A

Hence,

(a) Current in the upper branch is -0.4 A

(b) Current in the middle branch is 1.6 A

(c) Current in the lower branch is 1.2 A

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Wind Energy >> Uses groups of turbines to harness power from moving air, Solar Energy >>Can easily be harnessed by homeowners and businesses, Hydropower Energy >> Partly relies on the water cycle to provide its source and Biomass Energy >>Comes from organic plant and animal material

Wind Energy

Uses groups of turbines to harness power from moving air

It involves the use of wind turbines to convert the kinetic energy of moving air into electricity.

Solar Energy

Can easily be harnessed by homeowners and businesses

Homeowners and businesses can install solar panels on rooftops or open spaces to harness energy from the sun and convert it into electricity for their own use.

Hydropower Energy

Partly relies on the water cycle to provide its source

Hydroelectric power relies on the movement of water, driven by gravity, to spin turbines.

Biomass Energy

Comes from organic plant and animal material

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The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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The object's final velocity, given the data is 10.5 rad/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The following data were obtained from the question

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

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The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

The torque exerted on the merry-go-round is 766.95 Nm

Explanation:

Given;

mass of the merry-go-round, m = 416 kg

radius of the disk, r = 1.7 m

angular speed of the merry-go-round, ω = 3.7 rad/s

time of motion, t = 2.9 s

The torque exerted on the merry-go-round is calculated as;

\(\tau = Fr= I\alpha\\\\\tau = (\frac{1}{2} m r^2)(\frac{\omega }{t} )\\\\\tau = (\frac{1}{2} \times 416 \times 1.7^2)( \frac{3.7}{2.9} )\\\\\tau = 766.95 \ Nm\)

Therefore, the torque exerted on the merry-go-round is 766.95 Nm

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

The direction in which the 25 kg mass will move is to the Left. The correct option is A.

This is because the force pulling to the left is greater than that to the right.

The velocity of the mass after 1 second will be 0.4 m/s

The velocity of the mass after 2 seconds will be 0.8 m/s

The net force o the mass of 25 kg is given below:

Net force = 20 N - 10 N

Net force = 10 N

The velocity of the mass is given by the formula below:

Velocity = net force * time / mass

velocity after 1 second = 10 * 1 / 25

velocity after 1 second = 0.4 m/s

velocity after 2 seconds = 10 * 2 / 25

velocity after 2 seconds = 0.8 m/s

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Answer:

electromagnetism....

Answer:

Shown by explanation;

Explanation:

The heat of the sample = mass ×specific heat capacity of the sample × temperature change(∆T)

Assumption;I assume the mass of the samples are : 109g and 192g

∆T= 30.1-21=8.9°c.

The heat of the samples are for 109g are:

0.109 × 4186 × 8.9 =4060.84J

For 0.192g are;

∆T= 67-30.1-=36.9°c

0.192 × 4186×36.9=29656.97J

Answer:

highest point

Explanation:

Potential energy is greatest when the most energy is stored. This could be when an object reaches its highest point in the air before falling, a rollercoaster just before it drops, or when a rubber band is stretched as far back as possible before it snaps.

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.

The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.

The amount of kinetic energy converted to internal energy can be calculated as follows:

m1*v1 = (m1 + m2)*vf

vf = (m1*v1)/(m1 + m2)

KE = (1/2)*m2*v2²

KE converted = KE initial - KE final

KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²

KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²

KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)

KE converted = 28.8 - 22.15

KE converted = 6.65 J

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Press Alt and 0176 on your keyboard. Please take note that this technique only functions on keyboard shortcut with a 10-key numeric pad.

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A marble at rest on the floor of a train car is an object in motion relative to the train station. When the train is at rest in the station, the marble is at rest relative to the smooth, horizontal floor of the train car. However, as the train begins to move, the marble will also begin to move relative to the floor of the train car.

When the train reaches a constant velocity, the marble will be at rest relative to the floor of the train car, and will stay at that position as long as the train maintains a constant velocity.

When the train begins to decelerate as it approaches the station, the marble will experience a force in the opposite direction of the train's motion, which will cause it to move in the opposite direction of the train's motion, and it will come to a rest on the floor of the train car once the train comes to a complete stop.

In all, the marble's displacement relative to the smooth, horizontal floor of the train car will be zero when the train is at rest, and will increase as the train moves through the station.

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Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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A ball at rest hit by a golf club has initial velocity zero. The ball will be moving after the impact at speed of  1.4 x 10⁵ m/s.

The action of push or pull which changes the state of motion or rest of a body is called force.

The club applies a force of 700N to the ball and the time of impact is 0.05s. The mass of ball is 0.10kg.

The impact force F is equal to the change in momentum of the ball multiplied by time of impact t. The momentum is the product of mass m and velocity v after impact.

F= (mv -mu) x t

The ball is initially at rest, so u =0

F = mvt

Substitute the values into the above equation of force to find the velocity.

v = F / mt

v =700 / (0.10 x 0.05)

v = 1.4 x 10⁵ m/s

Thus, the ball will be moving after the impact at speed of  1.4 x 10⁵ m/s.

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Mechanical energy → Electrical energy → Thermal energy

What is mechanical energy?

Mechanical energy is the energy possessed by an object due to its motion or position. It is the sum of kinetic energy and potential energy of an object, which can be converted to other forms of energy, such as electrical energy or thermal energy.

What is electrical energy?

Electrical energy is the energy associated with the movement of electrons through a conductor or an electrical circuit. It is the result of the movement of charged particles, such as electrons, and is commonly generated by the conversion of other forms of energy, such as mechanical, chemical, or solar energy.

What is thermal energy?

Thermal energy is the energy associated with the temperature of an object or a system. It is the result of the movement of atoms and molecules in matter, which leads to the transfer of heat from hotter to cooler objects. Thermal energy is commonly measured in units of joules or calories and is proportional to the mass and temperature of an object or a system.

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The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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Answer:

A. The rays can change molecules and atoms in the body into ions.

Answer:

Tension

Explanation: