A large mining dump truck has a mass of 40,000 kg. If its engine produces
20,000N of force, how fast will the truck accelerate?

Answer:

22.2 m/s

Explanation:

First, we need to convert km to m by multiplying by 1000. This means that the car traveled 320 000 meters.

Next, we convert hours to minutes by multiplying by 3600 (the number of seconds in an hour). This means that overall, the car traveled 320 000 m in 14 400 seconds.

The average speed can be found by using the equation \(\frac{distance}{time}\). After substitution, this gives the fraction \(\frac{320 000}{14 400}\), which reduces to 22 \(\frac{2}{9}\) m/s, or about 22.2 m/s.

a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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When the wood comes down the change in potential energy of mass 2 kg and velocity 12 m/s is 144 J.

When the object is thrown vertically upwards, the height increases. The potential energy also increases with respect to the height. The potential energy is maximum, and the kinetic energy is zero when the stone moves vertically upwards.

When the object comes down, the potential energy decreases and results in increasing in kinetic energy. When the stone comes down, the potential energy is converted to kinetic energy, and the change in potential energy results in kinetic energy.

From the given,

mass of the wood (m) = 2kg

the velocity of the wood (v) = 12 m/s

kinetic energy (K.E) = mv² / 2

                                = (2×12×12) / 2

                                = 144 J

Thus, the change in kinetic energy is 144 J.

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Divide the net force by the mass:

a = (4.6 N) / (13 kg) ≈ 0.35 m/s²

also pointing backward, which looks like option B, but hard to say for sure since it's missing a decimal point.

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Answer:

Explanation:

Step 1) Combine all resistors into an equivalent overall resistor. These are all in series so you just add them up. Req = 10Ω + 20Ω + 30Ω = 60Ω:

Step 2) Using Ohm's Law, I = V/R = 120/60 = 2 A

Now you know how much current is flowing, and that current flows through each resistor the same. So the current in the 30 Ω resistor is 2.00 amps.

Answer:

am not sure about the answer

Explanation:

you need to find out the amount of force it's going in for example 10n or 100n then you need to times it the distance then devide by the time

Explanation:

To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:

Efficiency = (Output Work / Input Work) * 100

Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.

Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.

Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."

Using the velocity ratio, we have the following relationship:

dE / dL = 5

Now, we can calculate the input work (Wi) and the output work (Wo):

Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)

Output Work (Wo) = Load (L) * Distance moved by the load (dL)

Given that the efficiency is 80%, we can rewrite the formula for efficiency as:

0.80 = (Wo / Wi) * 100

Now, let's solve for the effort (E) using the given values:

Load (L) = 200N

Efficiency = 0.80

Velocity Ratio = 5

First, calculate the output work (Wo):

Wo = Load (L) * Distance moved by the load (dL)

Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):

dL = (1/5) * dE

Wo = L * (1/5) * dE

Wo = 200N * (1/5) * dE

Wo = 40N * dE

Next, calculate the input work (Wi):

Wi = Effort (E) * Distance moved by the effort (dE)

Wi = E * dE

Now, substitute the values into the efficiency formula:

0.80 = (Wo / Wi) * 100

0.80 = (40N * dE) / (E * dE) * 100

0.80 = 40 / E * 100

0.80 * E = 40

E = 40 / 0.80

E = 50N

Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.

1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.

We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.

The heat lost by the metal is given by

Q1 = m1c1ΔT1

Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.

The heat gained by the ice is given by

Q2 = m2c2ΔT2

Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.

Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2

m1c1ΔT1 = m2c2ΔT2

Solving for c1, we get

c1 = m2c2ΔT2 / (m1ΔT1)

By putting these values we get

c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]

c1 = 0.902 kJ/kg·K

Hence, the specific heat of the metal is 0.902 kJ/kg·K.

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Approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

To determine the amount of energy transferred into thermal energy during the fall of the diver, we can use the principle of conservation of energy.

The initial potential energy of the diver at the maximum height is given by:

Potential Energy (PE) = m * g * h

Where:

m = mass of the diver (48.0 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = maximum height (11.0 m)

Substituting the given values:

PE = 48.0 kg * 9.8 m/s^2 * 11.0 m = 5,219.2 J

The final kinetic energy of the diver just before hitting the pool is given by:

Kinetic Energy (KE) = (1/2) * m * v^2

Where:

m = mass of the diver (48.0 kg)

v = speed of the diver (8.81 m/s)

Substituting the given values:

KE = (1/2) * 48.0 kg * (8.81 m/s)^2 = 1,919.3 J

The difference between the initial potential energy and the final kinetic energy represents the energy transferred into thermal energy:

Energy transferred into thermal energy = PE - KE

                                     = 5,219.2 J - 1,919.3 J

                                     = 3,299.9 J

Therefore, approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

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The vessel can be immersed to a depth of 0.3006 m in the deep vat of mercury without being crushed.

The question requires us to determine the depth to which a closed vessel that can sink to a depth of 41.0 m in water before the external pressure crushes it could be immersed in a deep vat of mercury without being crushed. We can determine this using the concept of pressure.Pressure is defined as the amount of force acting per unit area. Pressure is given by the formula:

P = F/A,

where P is pressure, F is force, and A is area. Since the area remains constant, we can say that pressure is directly proportional to force. Thus, the greater the force acting on an object, the greater the pressure exerted on the object. The pressure exerted by a liquid depends on the density of the liquid, the depth of the liquid, and the acceleration due to gravity. This can be expressed using the formula:

P = ρgh,

where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth. Let us first calculate the pressure exerted by the water at a depth of

41.0 m:ρ of water = 1000 kg/m³g = 9.81 m/s²h = 41.0 m

Substituting these values in the formula, we get:

P = ρgh= (1000 kg/m³)(9.81 m/s²)(41.0 m)= 405570 Pa

Now, we need to determine the depth to which the vessel can be immersed in mercury without being crushed. Let us call this depth "d". The pressure exerted by the mercury at this depth is equal to the pressure exerted by the water at a depth of 41.0 m. Thus, we can equate the two pressure values:

ρ of mercury = 13600 kg/m³g = 9.81 m/s²P = 405570 Pa

Substituting these values in the formula, we get:ρgh = P(13600 kg/m³)(9.81 m/s²)(d) = 405570 PaSolving for d, we get:d = 0.3006 m.

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This question involves the concepts of thickness and length.

"40" gold atoms could stack on top of one another in the gold foil.

We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.

Therefore,

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The new amplitude B is 0.22 m.

Mass of block = M =0.1 kg

Spring constant = k = 15 N/m

Amplitude = A = 0.22 m

Mass of bullet = m = 3 g = 0.003 kg

Velocity of bullet = vᵇ = 42 m/s

Angular frequency of S.H.M is given by = ω₀ = \(\sqrt{\frac{k}{M}}\)

                                                      = \(\sqrt{\frac{15}{0.1} }\)

                                                      = 12.24 rad/sec

Speed of the block immediately before the collision:

Displacement of Simple Harmonic Motion is given as:

x= A Sin(ωt+Ф)

After differentiating:

v = A ω₀cos(ω₀t+Ф)

As bullet strikes at equilibrium position,

   φ = 0

    t= 2nπ

⇒ cos (ω₀t + φ) = 1

⇒ v= A ω₀

⇒ v= (0.22)(12.24)

⇒ \(v=2.692 ms^{-1}\)

If the simple harmonic motion after the collision is described by x = B sin(ωt + φ), new amplitude B:

S.H.M after collision is given as :

x= B Sin(ωt+Ф)

To find B, consider law of conservation of energy,

\(KE = PE\\KE =\frac{1}{2}(m+M)v^{2} \\PE= \frac{1}{2}kB^{2}\\\frac{(m+M)v^{2}}{k}=B^{2} \\B=\sqrt{\frac{(m+M)}{k}} v\\B= \sqrt{\frac{0.003+0.1}{15} } (2.69)\)

\(B= 0.22 m\)

Therefore, the new amplitude B is 0.22 m.

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Answer:

Newton's second law says that when an unbalanced force is applied to a mass it causes it to accelerate

Explanation:

Answer:

0.130

Explanation:

From the given data, the coefficient of static friction for each trial are:

1. 0.053

2. 0.081

3. 0.118

4. 0.149

5. 0.180

6. 0.198

The sum of the coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198

                                              = 0.779

So that;

the average coefficient of static friction = \(\frac{sum of coefficient of static friction}{number of trials}\)

                                              = \(\frac{0.779}{6}\)

                                              = 0.12983

The average coefficient of static friction is 0.130

The average coefficient of static friction is 0.13.

The coefficient of static friction is obtained using the formula; μ = F/R

Where;

F = force acting on the body

R = reaction

μ = coefficient of static friction

The average of measurements is given as; ∑summation of measurements/number of measurements

We can see from the question that there were 6 measurements of the coefficient of static friction. Hence, the average coefficient of static friction is obtained from;

0.053 + 0.081 + 0.118 + 0.149 + 0.180 +  0.198/6

= 0.13

The average  coefficient of static friction is 0.13

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According to the given statement:

I) acceleration a=2m/s²

ii) deceleration a=−1  m/s²

iii) the distance travelled =200  m.

Velocity's rate of change with time, in both terms of speed and direction. A point or object moving straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on the a circle increases because the orientation is always shifting.

Briefing:

You use the standard formulas for distance as a function of speed, acceleration and time:

st = v0t + 0.10at²  for acceleration ( a >0) and deceleration ( a <0), or at constant speed ( a =0).

Now  a  is not given for acceleration and deceleration, so we need to compute this from

vt=v₀+at

Acceleration:  

20=10a⟹a=2m/s²

Distance travelled:  

0.10∗10∗10²=100  m

Distance travelled while at constant speed:

s=vt=20∗20=400  m

Deceleration:  

0=20+20a⟺a=−1  m/s²

Distance travelled:

20∗20+0.1(−1)20²=400−2∗100

=200  m.

So the total distance travelled is  100+400+200=700m

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Answer:

The sympathetic nervous system, part of the autonomic nervous system, also known as the involuntary system, is in charge of the fight-or-flight response, a response to the stress that leads to a hormonal cascade that boosts alertness and heart rate to prepare the body to respond.

Explanation:

Answer:

Rapid heart rate and breathing: Heartbeat and respiration rate increase to provide the body with the energy and oxygen needed to fuel a rapid response to danger. 2  Trembling: The muscles tense and become primed for action, which can cause trembling or shaking.

Answer: True

Explanation: When people pollute  it breaks down the earth, that is why icebergs are melting and animals are going extinct. Before we know it, people are gonna start losing hearing, and there brain will shut down. That is also why people should stop polluting.

Answer:

sorryyyyijyyyyyyyyyyyyyyyyyyyy&

Explanation:

soryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

To answer the first question, we need to determine the location of the center of gravity of the system. Assuming the person and ladder can be treated as a uniform object, the center of gravity will be located at the midpoint of the ladder.

Let's say the ladder is 10 feet long, so the midpoint would be 5 feet from either end. If we assume the ladder is resting at a 60 degree angle against a vertical wall, we can use trigonometry to determine the horizontal distance of the center of gravity from the point where the ladder touches the ground.
Using the sine function, we know that sin(60) = opposite/hypotenuse, so the opposite side (which is the vertical height of the ladder) is 10*sin(60) = 8.66 feet. Therefore, the horizontal distance from the center of gravity to the point where the ladder touches the ground is also 8.66 feet.
To answer the second question :

We need to calculate the torque about the axis of rotation (point B) by taking the total weight of the person + ladder acting at the center of gravity. The formula for torque is torque = force x distance.
The force is equal to the weight of the person + ladder, which we'll assume is 300 pounds. The distance is the horizontal distance we just calculated, which is 8.66 feet.

So the torque about point B would be 300 pounds x 8.66 feet = 2,598 Newton-meters (Nm) or 2,598 pound-feet (lb-ft).

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Answer:

A) The formula used to convert from degrees fahrenheit to degrees celsius is °C = 5/9 (° F - 32)

Thus, 5/9 (134°F-32)

5/9=0,55

=0,555 * 102°F

=56,66 °C

B) 5/9 (-79.8°F-32)

=0,555 * -111,8

=-62.11 °C

A) The formula used to convert from degrees Celcius to degrees Kelvin is °K = °C + 273.15

56,66 °C + 273.15

= 329.81 °K

B) K = -62.11 °C + 273.15

=211.04 °K

Answer:

α = π/3

β = π/6

Explanation:

Use arc length equation to find the sum of the angles.

s = rθ

π/20 m = (0.1 m) (α + β)

π/2 = α + β

Draw a free body diagram for each sphere.  Both spheres have three forces acting on them:

Weight force mg pulling down,

Normal force N pushing perpendicular to the surface,

and tension force T pulling tangential to the surface.

Sum of forces on A in the tangential direction:

∑F = ma

T − m₁g sin α = 0

T = m₁g sin α

Sum of forces on B in the tangential direction:

∑F = ma

T − m₂g sin β = 0

T = m₂g sin β

Substituting:

m₁g sin α = m₂g sin β

m₁ sin α = m₂ sin β

(1 kg) sin α = (√3 kg) sin (π/2 − α)

1 sin α = √3 cos α

tan α = √3

α = π/3

β = π/6

The electrostatic force of attraction between the proton and electron is 4.2 x 10⁻⁸N.

The gravitational force between the proton and electron is 1.9 x 10⁻⁴⁷N.

a) Charge on proton = charge on electron = q = 1.6 x 10⁻¹⁹C

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The electrostatic force of attraction between the proton and electron is given by,

F = 1/4πε₀(q²/r²)

F = 9 x 10⁹ x (1.6 x 10⁻¹⁹)²/(7.4 x 10⁻¹¹)²

F = 9 x 10⁹ x 2.56 x 10⁻³⁸/54.76 x 10⁻²²

F = 4.2 x 10⁻⁸N

b) Mass of the electron, m₁ = 9.1 x 10⁻³¹kg

Mass of the proton, m₂ = 1.67 x 10⁻²⁷kg

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The gravitational force between the proton and electron is given by,

F = Gm₁m₂/r²

F = 6.67 x 10⁻¹¹x 9.1 x 10⁻³¹x 1.67 x 10⁻²⁷/(7.4 x 10⁻¹¹)²

F = 1.9 x 10⁻⁴⁷N

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500 energy sted dissipated as thermal energy.

In the question total work done is

W= force x displacement

= 150x 20

=3000 J

But we know that work is done against weight and against frictional force

Work done against friction is dissipated as thermal energy

So resolving g to components

g sin(Q) will be parallel to inclined plane

So we have work done = mg sinQ x S

= 25 x 10 x 10/20

=2500 J

So thermal energy dissipation = 3000-2500

=500 J

What is thermal energy?

Thermal energy is the energy contained inside a system that is accountable for its temperature. Heat is the passage of thermal energy. Thermodynamics is a whole field of physics that deals with how heat is transmitted between various systems and how work is done in the process.

Hence B  is a correct answer.

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Answer:

the liquid state

Explanation:

because the particles can move about freely, a liquid has no definite shape and takes a shape dictated by its container.

Work is referred to as the displacement of an object when a force (push or pull) is applied to it while energy is referred to as the capacity to do the work. It exists in various forms like potential, kinetic, chemical, thermal, nuclear, electrical energy and so on. Power is the work done per unit of time.

power and energy are the same.
Work is usualy doing a task that gets rid of said energy.

Answer:

\(\boxed {\boxed {\sf 6,000 \ Newtons}}\)

Explanation:

Force is the product of mass and acceleration.

\(F=ma\)

The mass of the Kia Soul is 1200 kilograms and its acceleration is 5 meters per square second.

\(m= 1200 \ kg \\a= 5 \ m/s^2\)

Substitute the values into the formula.

\(F= 1200 \ kg * 5 \ m/s^2\)

Multiply.

\(F= 6000 \ kg*m/s^2\)

\(F= 6000 \ N\)

Answer:

Force

We know that

F = ma

F = Force

m = mass

a = acceleration

F = 1200 × 5

F = 6000 N

\( \\ \)