A laser beam is aimed through a circular aperture of diameter 1 mm.

a. If the laser beam is red with a wavelength of 632. 8 nm, what is the angle from the center of the Airy disk to the first dark ring? (2 points)

sin(p) = 632. 8*10^-9 /. 001

sin^-1(. 0006328) =. 0363 degrees

b. If the screen you are projecting the Airy disk onto is 2 m from the aperture, what is the distance between the center of the disk and the first dark ring? (2 points)

Thanks everyone who can help!

Answers

Answer 1

The angle from the center of the Airy disk to the first dark ring is 0.0363 degrees, and the distance between the center of the disk and the first dark ring on a screen 2 meters away from the aperture is: 1.268 mm.

a. To find the angle from the center of the Airy disk to the first dark ring, we will use the formula sin(p) = (wavelength) / (aperture diameter). Plugging in the values, we get sin(p) = 632.8 * 10^-9 / 0.001. Then, we calculate the inverse sine, sin^-1(0.0006328) = 0.0363 degrees.

b. To determine the distance between the center of the Airy disk and the first dark ring on a screen that is 2 meters from the aperture, we will use the formula distance = (angle) * (distance to screen).

In this case, distance = 0.0363 degrees * 2 meters.

First, convert the angle to radians: 0.0363 degrees * (pi / 180) = 0.000634 radians.

Then, multiply by the distance to the screen: 0.000634 radians * 2 meters = 0.001268 meters or 1.268 mm.

In summary, the angle from the center of the Airy disk to the first dark ring is 0.0363 degrees, and the distance between the center of the disk and the first dark ring on a screen 2 meters away from the aperture is 1.268 mm.

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Complete question:

A laser beam is aimed through a circular aperture of diameter 1 mm.

a. If the laser beam is red with a wavelength of 632. 8 nm, what is the angle from the center of the Airy disk to the first dark ring? (2 points)

sin(p) = 632. 8*10^-9 /. 001

sin^-1(. 0006328) =. 0363 degrees

b. If the screen you are projecting the Airy disk onto is 2 m from the aperture, what is the distance between the center of the disk and the first dark ring? (2 points)


Related Questions

Which two statements are true about the wave shown?​

Which two statements are true about the wave shown?

Answers

Answer: The correct answers are C. and D.

Explanation:

Which two statements are true about the wave shown?

A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.

Answers

The arrow leaves the bow at a speed of 40.47 m/s.

When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma

m = mass of the arrow (kg) = 0.0850 kga = acceleration of the arrow (m/s²)F = force (N) = 89.0 N

\(a \:=\: \frac{F}{m}\)

\(a \:=\: \frac{89.0}{0.0850}\)

a = 1,047.059 m/s²

When the object has acceleration, the object will move in a non-uniform motion. The formula

v = u+atv² = u² + 2ad\(d \:=\: v_0 \times t \:+\: \frac{1}{2} \times a \times t^2\)u  = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)v = final speed (m/s) a = acceleration (m/s²) = 1,047.059 m/s²t = interval (s)d = distance (m) = 0.782 m

v² = u² + 2ad

v² = 0² + (2×1,047.059×0.782)

v² = 1,637.6

\(v_t \:=\: \sqrt{1,637.6}\)

\(v_t\) = 40.47 m/s

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A body weights 50 N in air and 45 N when wholly immersed in water calculate (i) the loss in weight of the body in water (ii) the upthrust on the body. (iii) volume of the body.​

Answers

Answer:

\(difference \: in \: weight = 150n - 100n = 50n\)

Now,buyantant force

\(difference \: in \: weight \: = volume(body) \times density \: of \: water \: \times g\)

so;

\(50 = {v}^{b} \times 1 \times {10}^{3} \times 9.8m {s}^{2}\)

\( {v}^{b} = \frac{50}{1000 } \times 9.8\)

\( = \frac{50}{9800} \)

\( = 0.0051\)

Now,

\(mass \: in \: air \: = 150n = \frac{150}{9.8kg} \)

\(density = \frac{weght}{volume} \)

\( = \frac{150}{0.0051} \times 9.8 \\ x = 3000\)

And now,

\(specific \: density \: = \frac{density of \: the \: body}{density \: of \: water} \)

\( = \frac{3000}{1000} \)

\( = 3\)

Hence that,specific density of a given body is 3

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Fill in the blank to answer the question!


At Position D, the Sun's most direct rays are hitting the ________ on Earth.

Answers

At Position D, the Sun's most direct rays are hitting the equator on Earth.

What is the equator?

The equator is a geographic coordinate that is defined as an imaginary line that stretches approximately 40,075 km or 24,901 miles across the Earth's surface. The equator is an imaginary circle that is equidistant from the North and South Poles. This circle divides the Earth into the Northern Hemisphere and the Southern Hemisphere.

In summary, the Sun's most direct rays hit the equator on Earth when it is at Position D.

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Question 1 12.5 pts Describe and explain two components of how wind and air pressure fluence our weather. Indicate too, whether the rotation of the earth influences each of the components you are discussing

Answers

Atmospheric circulation: The uneven heating of the earth's surface leads to differences in air pressure, creating regions of high and low pressure. This pressure gradient drives the movement of air, creating atmospheric circulation.

The rotation of the earth influences atmospheric circulation through the Coriolis effect, which causes the air to deflect to the right in the Northern Hemisphere and to the left in the Southern Hemisphere. This deflection causes the formation of large-scale wind patterns, such as the trade winds and westerlies, which influence global weather patterns. Frontal systems: Fronts are the boundaries between air masses with different temperatures, humidities, and pressures. When these air masses meet, they can create weather disturbances such as thunderstorms, tornadoes, and hurricanes. The rotation of the earth influences frontal systems through the same Coriolis effect mentioned above. The deflection of the air masses causes the formation of curved fronts, which can intensify weather systems and create complex weather patterns.

In summary, the rotation of the earth influences both atmospheric circulation and frontal systems, which are two important components of how wind and air pressure influence our weather.

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The electric in a region surrounding the origin is uniform and along the x-axis. A small circle is drawn with the centre at the origin cutting the axes at the origin cutting the axes at points A, B, C, and D having coordinates (a, o), (o, a). (-a, o) and (o, -a), respectively, as shown. then, the potential is minimum at a. A
b. B
c. C
d. D

Answers

The electric in a region surrounding the origin is uniform and along the x-axis. Then, the potential is minimum at A.

What is electric?

Electricity is a form of energy resulting from the presence and flow of electric charge. It is a natural phenomenon that occurs in nature, such as lightning, and can also be produced artificially through the use of electrical devices. It is a fundamental part of the universe, and is used to power almost everything in our lives. Electric energy is created when electrons move from one atom to another. This movement of electrons can be done through a conductor, such as a wire, creating an electric current.

The electric field is uniform and along the x-axis. This means that the electric field is constant along the x-axis, and thus the potential is also constant along the x-axis. Since Point A is located on the x-axis, it has the same potential as the origin, which is the minimum potential of the region. Hence, the potential is minimum at Point A.

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Pls help me label. Anyone who answers will be marked brainiest

Pls help me label. Anyone who answers will be marked brainiest

Answers

Explanation:

what is it of? I maybe able to help.

Two loud speakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from other speaker.
What is the lowest frequency at which destructive interference will occur at this point if the speakers are in phase?

Answers

Answer:

f = 343 Hz

Step by step explanation:

For destructive interference to occur, the sound waves from the two speakers must be out of phase by half a wavelength. This means that the path difference between the two waves must be an odd multiple of half the wavelength.

In this case, the path difference between the two waves is given by:
Δx = d₂ - d₁
where d₂ is the distance from the second speaker to the person, and d₁ is the distance from the first speaker to the person.

Substituting the given values, we get:
Δx = 3.5 m - 3.0 m
Δx = 0.5 m

For destructive interference to occur, the path difference must be an odd multiple of half the wavelength, i.e.:
Δx = (2n + 1)λ/2
where n is an integer.

Solving for the wavelength, we get:
λ = 2Δx/(2n + 1)

The lowest frequency occurs when n is the smallest possible value, i.e. n = 0. Substituting this value, we get:
λ = 2Δx/1
λ = 2(0.5 m)
λ = 1.00 m

The frequency of the sound wave is given by:
f = c/λ
where c is the speed of sound in air (approximately 343 m/s).

Substituting the values, we get:
f = 343 m/s/1.00 m
f = 343 Hz

Therefore, the lowest frequency at which destructive interference will occur at the given point is 343 Hz.

The wavelength of a ray of blue light is 475 nm. If its frequency is x×10^14Hz

what is the value of x?

Answers

The value of the variable in the frequency will be 3.316.

What is the wavelength and frequency of light?

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), millimeters (mm), or nanometers (nm).

The formula of the frequency is given as,

f = c / λ

Where 'f' is the frequency, c is the speed of light, and 'λ' is the wavelength.

The wavelength of a ray of blue light is 475 nm. If its frequency is x · 10¹⁴ Hz. Then the value of the variable 'x' is given as,

x · 10¹⁴ = (3 · 10⁸) / (475 · 10⁻⁹)

Simplify the equation, then we have

x · 10¹⁴ = (3 · 10⁸) / (475 · 10⁻⁹)

x = (3 · 10⁸) / (475 · 10⁻⁹ · 10¹⁴)

x = (3 · 10⁸) / (475 · 10⁵)

x = 6.316

The value of 'x' is 6.316.

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A steel cable has a diameter of 0.16 cm. The tensile strength of the steel is 4 × 108 N/m2. What is the approximate tension force that will snap the cable?

A. 8.0×\(10^{8}\) N
B. 5.0×\(10^{7}\) N
C. 8.0×\(10^{6}\) N
D. 4.0×\(10^{8}\) N
E. 800 N

Answers

Answer:

800 N

Explanation:

The formula to solve this equation is stress = Force/ Area.

The first step is to rearrange this equation for force: Force = stress * area

The second step is to determine the area: A = pi/4 * d^2

A = pi/4 * (0.0016m)^2=0.00000201 m^2

The third step is to substitute the area back into the equation:

Force = (4 * 10^8)(0.00000201) = 804 N

804 N is approximately 800 N

which statement illustrates how progress in engineering has affected the natural enironment

Answers

The statement that illustrates how progress in engineering has affected the natural environment is extracting mineral resources with modern mining equipment removes fertile topsoil.

What is the Natural Environment?

The natural environment may be defined as anything that can be present in the surroundings of living entities whether it is a biotic or abiotic factor.

The utilization of contemporary mining tools terminates fertile topsoil and admiringly impacts the fertility of the soil.  It is tough to rebuild topsoil and modern mining tools constantly damage soil fertility.

Advancement in engineering has influenced the natural environment and mining is one of the most accepted measures of this.

The complete question is as follows:

Extracting mineral resources with modern mining equipment removes fertile topsoil.Mining companies use modern equipment to extract mineral resources more efficiently.Modern mining equipment has improved the health and safety of workers.Modern mining practices provide materials that can be used for technological advances.

Therefore, it is well described above.

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as measured in earth's rest frame, a spaceship traveling at 0.9640c takes to travel between two planets that are not moving relative to each other. how long does the trip take as measured by someone on the spaceship? a. 2.79 y b. 6.83 y c. 39.5 y d. 28.8 y

Answers

b) 6.83 years, which corresponds to approximately 2.165 years as measured by someone on the spaceship.

According to special relativity, time dilation occurs when an object is moving relative to an observer. Time dilation means that time appears to pass more slowly for the moving object compared to a stationary observer.

In this scenario, the spaceship is traveling at a speed of 0.9640c, which is 0.9640 times the speed of light. We want to find out how long the trip takes as measured by someone on the spaceship, which means we need to consider time dilation.

The time dilation factor, γ, is given by the equation:

γ = 1 / √(1 - (v^2 / c^2))

where v is the velocity of the spaceship and c is the speed of light.

Substituting the given values:

γ = 1 / √(1 - (0.9640c)^2 / c^2)

= 1 / √(1 - 0.9298)

= 1 / √(0.0702)

≈ 3.160

This means that time appears to pass approximately 3.160 times slower for someone on the spaceship compared to someone in the Earth's rest frame.

Now, let's consider the time it takes for the trip in the Earth's rest frame. We'll denote this time as t_earth.

Given that the spaceship takes t_earth to travel between the two planets as measured in the Earth's rest frame, the time it takes for someone on the spaceship, t_ship, can be calculated by:

t_ship = t_earth / γ

Substituting the provided answer options:

a) t_earth = 2.79 years

t_ship = 2.79 years / 3.160 ≈ 0.883 years

b) t_earth = 6.83 years

t_ship = 6.83 years / 3.160 ≈ 2.165 years

c) t_earth = 39.5 years

t_ship = 39.5 years / 3.160 ≈ 12.50 years

d) t_earth = 28.8 years

t_ship = 28.8 years / 3.160 ≈ 9.13 years

Based on the calculations, the correct answer is option b) 6.83 years, which corresponds to approximately 2.165 years as measured by someone on the spaceship.

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sort the facts into the category that they best describe sound waves and electromagnetic waves

Answers

Answer:

Sound waves have a low speed of 330 m/s

Sound waves are mechanical waves

Electromagnetic waves have a greater speed of 3.0×10^8 m/s

Electromagnetic waves are due to disturbance of electromagnetic objects.

explain why the meter stick center of mass must now be located at the support position

Answers

When a meter stick is placed on a support, such as a pivot or fulcrum, it will balance if the center of mass of the meter stick is directly above the support. This is because the center of mass is the point where the weight of the meter stick can be considered to be concentrated, and if this point is directly above the support, the weight will be balanced.

If the center of mass of the meter stick is not directly above the support, the meter stick will not be balanced and will tip over. This is because there will be a net torque acting on the meter stick, which is the product of the weight force and the distance between the center of mass and the support. If the torque is non-zero, the meter stick will rotate until the torque is balanced.

Therefore, to ensure that the meter stick is balanced on the support, the center of mass must be located at the support position. If the center of mass is not at the support position, the meter stick will not balance and will either tip over or rotate until it reaches a balanced position.

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In a room in a house, there are four electric lamps in parallel with each other, controlled by a single switch. With all the lamps working, one of the lamp filaments suddenly breaks.What, if anything happens to the remaining lamps? Explain your answer.

Answers

Explanation:

In a parallel circuit, each lamp is connected to the power source independently, meaning that the lamps are not directly connected to each other. Therefore, if one lamp filament breaks in this setup, the other three lamps will continue to work unaffected.

When the filament of one lamp breaks, it essentially opens the circuit for that particular lamp. However, the remaining lamps are still connected in parallel, so the current can flow through them independently. The other lamps will continue to receive electricity from the power source and light up normally.

This behavior is a characteristic of parallel circuits, where each component has its own individual connection to the power source. If the lamps were connected in series, the situation would be different. In a series circuit, a break in one lamp's filament would interrupt the flow of current throughout the entire circuit, and all the lamps would go out.

The Law of Conservation of Momentum states that Momentum between two moving
objects is conserved when those two objects collide.
Consider the following:
Two cars are moving in the same direction, one behind the other. The rear car is moving
with a momentum of 50 kg*m/s, and the front car moves with a momentum of 100
kg*m/s. The cars have a combined momentum of 150 kg*m/s.
The rear car HITS the car in front of it, but no brakes or other stopping forces are
applied. The rear car's momentum changes to 40 kg*m/s. What is the new momentum
front car?

Answers

Answer:

As stated, the momentum of the system is conserved during the collision (even the kinetic energy is not - some energy is lost to heat, deformation, etc)

M1 V1 = M2 V2 expresses momentum conservation

150 kg-m/s = (40 + X) kg-m/s

X = 110 kg-m/s     is the new momentum of the front car

More specifically,

M1 V1 + M2 V2 = M1 V1' + M2 V2'

How far will a 70 N crate be moved if 3500 J of work is accomplished?

Answers

Answer:

18 meters

Explanation:

How many meters did the car go in the first 4 seconds?​

How many meters did the car go in the first 4 seconds?

Answers

Are there numbers on the y axis?

A copper rod is sliding on two conducting rails that make an angle of 19 degree with respect to each other, as in the drawing. The rod is moving to the right with a constant speed of 0.60 m/s. A 0.35-T uniform magnetic field is perpendicular to the plane of the paper. Determine the magnitude of the average emf induced in the triangle ABC during the 6.0-s period after the rod has passed

Answers

The magnitude of the average emf induced in the triangle ABC during the 6.0-s period after the rod has passed is E m f = 0.124 V.  

Calculation:-

As B is constant, then

E m f = B (A f - Ai) / t

Here,

Ai = 0

A f = b h /2

As

b = 0.60 m/s * 6.0 s = 3.6 m

h = b tan 19 = 0.5457 m

A f = 1.9646 m^2

e m f = 0.124 V  

A magnetic field is a vector area that describes the magnetic impact on moving electric costs, electric powered currents, and magnetic substances. A moving price in a magnetic area reviews a pressure perpendicular to its very own pace and to the magnetic area.

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cecil wants to be able to leap tall doghouses in a single bound while wearing her super dog costume. cecil can almost jump up over an annoying pet gate. cecil can just barely clear a pet gate that is 0.81-m tall when she launches herself at a 45° angle from a distance of 1.5-m from the base of the gate. (a) what is her launch speed? (b) how long is she in the air for? (c) how far behind the gate does she land? you may ignore air resistance and treat cecil as a point particle.

Answers

Cecil can just barely clear a pet gate that is 0.81-m tall when she launches herself at a 45° angle from a distance of 1.5-m from the base of the gate. Her launch speed is 4.4 m/s. She was in the air for 0.193 s. She lands 0.556 m behind the gate.

To determine Cecil's launch speed, we can use the kinematic equations for projectile motion. Let's break down the problem into three parts:
(a) Launch speed:
Given that Cecil can barely clear the pet gate, we can assume that her vertical displacement (Δy) is equal to the height of the gate, which is 0.81 m. The launch angle (θ) is 45°. We can use the following equation to calculate her launch speed (v):
Δy = (\(v^2\) * sin²θ) / (2 * g)
Where g is the acceleration due to gravity, approximately \(9.8 m/s^2.\)
Plugging in the values:
0.81 m = (v^2 * sin² 45°)) / (2 * \(9.8 m/s^2.\))
Simplifying the equation, we get:
v^2 = (0.81 m * 2 * \(9.8 m/s^2.\)) / sin²(45°)
Taking the square root of both sides, we find:
v = sqrt((0.81 m * 2 * \(9.8 m/s^2.\)) / sin²(45°))
Calculating the value, we find:
v ≈ 4.4 m/s
Therefore, Cecil's launch speed is approximately 4.4 m/s.
(b) Time in the air:
To determine how long Cecil is in the air, we can use the vertical component of her motion. We can use the following equation:
Δy = v0y * t - (1/2) * g * t²
Where Δy is the vertical displacement, v0y is the initial vertical velocity (which can be found using the launch speed and launch angle), t is the time in the air, and g is the acceleration due to gravity.
Given that the initial vertical velocity (v0y) is equal to v * sinθ, we can rearrange the equation to solve for t:
0.81 m = (v * sinθ) * t - (1/2) * g * t²
Plugging in the values:
0.81 m = (4.4 m/s * sin(45°)) * t - (1/2) * \(9.8 m/s^2.\) * t²
Simplifying the equation, we get a quadratic equation:
(1/2) * \(9.8 m/s^2.\)* t² - (4.4 m/s * sin(45°)) * t + 0.81 m = 0
Solving this quadratic equation, we find two possible solutions for t:
t ≈ 0.193 s or t ≈ 0.046 s
Since Cecil cannot be in the air for a negative amount of time, the valid solution is:
t ≈ 0.193 s
Therefore, Cecil is in the air for approximately 0.193 seconds.
(c) Distance behind the gate:
To determine how far behind the gate Cecil lands, we can use the horizontal component of her motion. We can use the following equation:
Δx = v0x * t
Where Δx is the horizontal displacement, v0x is the initial horizontal velocity (which can be found using the launch speed and launch angle), and t is the time in the air.
Given that the initial horizontal velocity (v0x) is equal to v * cosθ, we can plug in the values to calculate Δx:
Δx = (4.4 m/s * cos(45°)) * 0.193 s
Simplifying the equation, we find:
Δx ≈ 0.556 m
Therefore, Cecil lands approximately 0.556 meters behind the gate.

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Which of the following slope failures is most likely to cause large numbers of casualties? a) earth flow b) debris slide c) creep d) rock avalanche

Answers

Of the four slope failures listed, a rock avalanche is most likely to cause large numbers of casualties.

A rock avalanche is a rapid and chaotic movement of rock debris down a slope, often triggered by earthquakes, heavy rainfall, or other geological factors. The fast-moving rocks can cause significant damage to anything in their path, including buildings, vehicles, and people.

In contrast, an earth flow is a slower and more gradual movement of soil or rock material down a slope, which can cause property damage but is less likely to result in casualties. Debris slides and creep are also slower and more gradual movements, although they can still cause significant damage in certain circumstances.

Therefore, a rock avalanche is the most dangerous of the four slope failures listed in terms of potential for casualties.

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which are considered noble gases

Answers

Answer:Argon

Neon

Helium

Krypton

Xenon

Any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og)

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Consider an iron rod of 200 mm long and 1 cm in diameter that has a _______N force applied on it. If the bulk modulus of elasticity is 70 GN/m2, what are the stress, strain and deformation in the rod?
Use the last three digits of your ID number for the amount of force.

Answers

The force applied to the iron rod is the last three digits of the ID number. Assuming it is 123 N, the stress, strain and deformation in the rod are 1.93 x 108 Pa, 1.66 x 10-4 and 0.033 m respectively.


Bulk modulus of elasticity is defined as the ratio of volumetric stress to volumetric strain. It determines the compressibility of fluids and solids. The bulk modulus is given as K = -V(dp/dV), where V is the volume of the object, p is the pressure and dp/dV is the derivative of pressure with respect to volume.

For a rod, stress is defined as force per unit area, and strain is defined as change in length per unit length.

Deformation is the change in length of the rod due to the applied force.

Assuming the force to be 123 N, the stress, strain and deformation in the rod are calculated using the formulae

stress = force/area

strain = change in length/original length

deformation = strain x length.

Therefore, stress is 1.93 x 108 Pa, strain is 1.66 x 10-4 and deformation is 0.033 m.

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1) Did your data display the expected relationship between the centripetal force and angular speed of the rotation? What evidence do you have of this? What changed when you changed either the mass or radius? Write out your answer in a clear and well supported paragraph.
2) With the radius held constant, should a greater increase in force be required to increase the angular speed of a larger or smaller mass by the same amount? What did you observe experimentally in Part A? Write out your answer in a clear and well supported paragraph.
3) With the mass held constant, should a greater increase in force be required to increase the angular speed of a larger or smaller radius by the same amount? What did you observe experimentally in Part B? Write out your answer in a clear and well supported paragraph.

Answers

The data displayed the expected relationship between the centripetal force and angular speed of the rotation. Increasing the angular speed led to a proportional increase in the centripetal force, indicating a direct relationship between the two variables.

This relationship was supported by the experimental evidence obtained in the investigation. When the mass was changed while keeping the radius constant, the centripetal force increased as the mass increased.

Similarly, when the radius was changed while keeping the mass constant, the centripetal force increased as the radius increased. These observations demonstrate that both mass and radius have a direct effect on the required centripetal force to maintain a certain angular speed.

In the experiment, the relationship between centripetal force and angular speed was confirmed. As the angular speed increased, the centripetal force also increased proportionally. This relationship was evident through the data collected during the investigation. When the mass was altered while maintaining a constant radius, an increase in mass resulted in a corresponding increase in the required centripetal force. Likewise, when the radius was modified while keeping the mass constant, an increase in radius led to a greater centripetal force.

These experimental observations support the notion that both mass and radius directly influence the amount of force required to achieve a specific angular speed.

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que 2. Why do we keep frequency constant instead of keeping vibrating length constam second law of vibrating string?​

Answers

Answer:

The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant

The law can be expressed mathematically as follows;

\(f = \dfrac{1}{2\cdot l} \cdot \sqrt{\dfrac{T}{m} }\)

The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously

Therefore, the law is verified indirectly, by rearranging the above equation as follows;

\(m = \dfrac{1}{ l^2} \cdot \dfrac{T}{4\cdot f^2} }\)

From which it can be shown that the following relation holds with the limits of error in the experiment

m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²

Explanation:

An airplane traveling from San Francisco northeast to Chicago travels 1260 km in 3.5 h. What is the airplanes average velocity?

Please help i have to turn this in quick

Answers

Answer:

Average velocity = 360km/h due Northeast.

Explanation:

Given the following data;

Distance = 1260km

Time = 3.5h.

Velocity =?

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

\(Velocity = \frac{distance}{time}\)

\(V = \frac{d}{t}\)

Substituting into the above equation;

\(V = \frac{1260}{3.5}\)

Velocity, V = 360km/h.

Since velocity is a vector quantity, it must have both magnitude and direction.

Hence, the average velocity of the airplane is 360km/h due Northeast.

some answer now hurry

some answer now hurry

Answers

Answer:

Hee answer is B

Explanation:

____________.

2. True or false. As a wave travels through a given material its velocity changes.​

Answers

Answer:

the answer is false

Explanation:

A wave travels at a constant velocity through a given material.

The Jamaican bobsled team hit the brakes on their sled so that it decelerates at
a
uniform rate of 0.43 m/s?. How long does it take to stop if it travels 85 m before
coming to rest?

Answers

the answer is in the photo

hopes it help!

The Jamaican bobsled team hit the brakes on their sled so that it decelerates atauniform rate of 0.43

examples of contact force

Answers

Answer:

Reaction force. An object at rest on a surface experiences reaction force.

Tension. An object that is being stretched experiences a tension force.

Friction. Two objects sliding past each other experience friction forces.

Air resistance.

Explanation:

Answer with Explanation:

Conntact forces: Frictional force, Muscular force etc

Non-contact : gravitational, electrostatic, and magnetic

I hope   im right!!

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