A leftward force of 50 N is applied to an 8 kg
object to move it across a rough surface with a
leftward acceleration of 5 m/s/s. Determine the
gravitational force, normal force, frictional
force, net force, and the coefficient of friction
between the object and the surface.

Answer:

Molar mass of NH3=14+3=17g

\(mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65\)

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Within the subject of technology, radiogenic heat may be described because of the type of warmth that is released when radioactive isotopes disintegrate. consequently, we say that the thermal strength is launched by means of the nuclear disintegration of the radioactive isotopes.

Approximately 50% of the Earth's inner warmness originates from radioactive decay. four radioactive isotopes are chargeable for the general public of radiogenic warmness because of their enrichment relative to different radioactive isotopes uranium-238 (238U), uranium-235 (235U), thorium-232 (232Th), and potassium-40 (40K).

Radioactive heating refers back to the power dissipated within the interiors of planets, satellites, or asteroids as a consequence of the radioactive decay of radioactive isotopes (see radiochemistry). Radioactive isotopes are characterized by their decay energies and their half-lives.

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Answer:

4 Joules (if you mean 2000 grams)

4000 Joules (if you mean 2000 kilograms)

Explanation:

Answer:

Input work is the work done on a machine as the input force acts through the input distance. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance.Jan 15, 2020 whhdbd dhd dvd s bs sbs shs shs sh s

Explanation:

avsvsyxsgzvs zvx shs dhx xbx dhd dvd dj

The emission rate of sulfur with the 70% efficient scrubber would be 11.052 lb/hr.

To calculate the emission rate of sulfur in pounds per hour (lb/hr), we need to consider the efficiency of the power plant, the sulfur content in the coal, and the efficiency of the scrubber.

Given:

Power plant efficiency: 38%

Scrubber efficiency: 70%

Coal sulfur content: 1.0%

Power plant capacity: 600 MW

Coal burn rate: 9000 BTU/lb

Step 1: Calculate the coal burn rate in pounds per hour (lb/hr)

Coal burn rate = Power plant capacity / Efficiency

Coal burn rate = 600 MW / 0.38

Coal burn rate = 1578.947 lb/hr

Step 2: Calculate the emission rate of sulfur without the scrubber

Sulfur emission rate = Coal burn rate * Sulfur content

Sulfur emission rate = 1578.947 lb/hr * 0.01

Sulfur emission rate = 15.789 lb/hr

Step 3: Calculate the emission rate of sulfur with the scrubber

Sulfur emission rate with scrubber = Sulfur emission rate * Scrubber efficiency

Sulfur emission rate with scrubber = 15.789 lb/hr * 0.70

Sulfur emission rate with scrubber = 11.052 lb/hr

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Answer:

The height reached by the ball=0.459 m

Explanation:

We are given that

\(\theta=30^{\circ}\)

Initial speed, u=6 m/s

We have to find the maximum height reached by ball.

Maximum height reached by ball

\(h=\frac{u^2sin^2\theta}{2g}\)

Where \(g=9.8m/s^2\)

Substitute the values

\(h=\frac{6^2sin^230^{\circ}}{2\times 9.8}\)

\(h=\frac{36\times \frac{1}{4}}{2\times 9.8}\)

\(h=0.459 m\)

Hence, the height reached by the ball=0.459 m

Answer:

A. 2.58m

Explanation:

Using the formula;

F = GMm/r²

M and  m are the masses

G is the gravitational constant

r is the distance between the masses

Substitute

0.00006 = 6.67*10^-11(2000)(3000)/r²

0.00006r² = 6.67*10^-11*6000000

0.00006r² = 40.02*10^-5

0.00006r² = 0.0004

r² =  0.0004/0.00006

r² = 6.66

r = 2.58m

Hence the distance between them is 2.58m

The momentum of the 1.0-å photon is 6.63 x 10^-24 kg m/s and the energy is 1.9888 x 10^-15 J.

The momentum of a photon can be calculated using the formula p = E/c, where p is momentum, E is energy, and c is the speed of light. In this case, the energy of the photon is given as 1.0-å (which I assume means 1.0 angstrom), but we need to convert this to joules using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

First, we convert 1.0-å to meters:
1.0-å = 1.0 x 10^-10 meters

Now, we can use the formula for energy:
E = hc/λ
E = (6.626 x 10^-34 J s) x (3.00 x 10^8 m/s) / (1.0 x 10^-10 m)
E = 1.9888 x 10^-15 J

Now we can calculate the momentum:
p = E/c
p = (1.9888 x 10^-15 J) / (3.00 x 10^8 m/s)
p = 6.63 x 10^-24 kg m/s

So the momentum of the 1.0-å photon is 6.63 x 10^-24 kg m/s and the energy is 1.9888 x 10^-15 J.

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Answer:

The atomic number of phosphorus is 15.

Explanation:

It’s found after Si(Silicon) and before S(sulphur)

Negative mass, if it exists, would exhibit unique behavior compared to positive mass.

In a scenario with two negative masses, they would likely repel each other due to their inverse properties, as described by the hypothetical concept of negative mass.

When interacting with a positive mass, a negative mass might cause mutual acceleration, resulting in both objects accelerating towards each other, rather than the attractive force observed between two positive masses.

The existence of negative mass remains speculative and is not supported by current scientific evidence.

While it provides interesting theoretical possibilities, more research is needed to determine if negative mass could exist within our physical universe.

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The statement "They have a positive charge and are present in the nucleus of an atom along with the neutrons" correctly describes protons.

Protons are small particles that make up the nucleus of an atom. They carry a positive charge and have a mass of approximately 1 atomic mass unit. The number of protons within an atom's nucleus defines its atomic number and thus its identity as an element.

For instance, carbon atoms have 6 protons, and oxygen atoms have 8 protons. Protons are vital building blocks of all atoms and play a significant role in the chemical behavior and reactions of elements.

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Answer:

1. The bird close to the center

2. 4/25 of the original force.

Explanation:

1. Tangential velocity is v=w*d (in m/s), where w is the rotational speed, commonly denoted as the letter omega (in radians per second). d is the distance from the center of the rotating object to the position of where you would like to calculate the velocity (in meters).

As we can note, the furthest from the center we are calculating the velovity the higher it is, because the rotational velocity is not changing but the distance of the object with respect to the center is. If v=w*d, then the lower the d (distance) the lower the tangential velocity.

2. Take a look at the picture:

We have the basic equation for the gravitational force.

We have to forces: Fg1, which is the original force, and Fg2, the force when the mass and the distance changes.

If we consider that mass 2 didn't change (m2'=m2), mass 1 is four times its original (m1'=4*m1) and distance is 5 times the original (r'=5*r), then next step is just plugging it into the equation for Fg2.

Dividing the original force Fg1 by the new force Fg2 (notice you can just as well do the inverse, Fg2 divided by Fg1) gives us the relation between the forces, cancelling all the variables and being left only with a simple fraction!

Answer:

f = 215.27 Hz

Explanation:

We have,

An open-pipe resonator has a length of 2.39 m.

It is required to find the frequency of its third harmonic if the speed of sound is 343 m/s.

For third harmonic, its length is equal to, \(l=\dfrac{3\lambda}{2}\)

So,

\(\dfrac{3v}{2f}=2.39\)

f is frequency in its third harmonics

\(f=\dfrac{3v}{2\times 2.39}\\\\f=\dfrac{3\times 343}{2\times 2.39}\\\\f=215.27\ Hz\)

So, the frequency of its third harmonic is 215.27 Hz.

5m I think,maybe, not a 100% sure die

Answer:

5m i think

Explanation:

WHATS THE ANSWER HELP!!

Answer:

6.6 Meters = 660 Meters

Explanation:

1 Meter = 100 Centimeters

Answer:

12V

Explanation:

from the formula, I=V/R

V=IR

V=24x0.50

Voltage difference in a circuit = 12V

Answer:

5v

Explanation:

W = 10J ;Q = 2C ;V = ?

So,potential between x and y is 5v

Hope it will help you if not so please sorry.

The mutual inductance between the coils is 6.25μH. the coefficient of coupling between the coils is approximately 0.447.

The mutual inductance between the coils can be determined using the formula:M = (Δφ_Y) / (N_X * ΔI_X)
Where M represents the mutual inductance, Δφ_Y is the change in flux in coil Y, N_X is the number of turns in coil X, and ΔI_X is the change in current in coil X.
Plugging in the values given, we have: M = (5mWb) / (200 * 4A)

M = 5mWb / 800A

M = 6.25μH. Therefore, the mutual inductance between the coils is 6.25μH.

(b) The coefficient of coupling (k) can be calculated using the formula:

k = M / √(L_X * L_Y)

Where k represents the coefficient of coupling, M is the mutual inductance, L_X is the self-inductance of coil X, and L_Y is the self-inductance of coil Y.
Substituting the given values: k = (6.25μH) / √((80mH) * (60mH))

k = 6.25μH / √(4.8mH^2)

k ≈ 0.447. Therefore, the coefficient of coupling between the coils is approximately 0.447.

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As a galaxy evolves and becomes more massive, the factor that is most likely to happen is option  B: It will merge with other galaxies.

When two galaxies merge, they can create a larger, more massive galaxy. This process can take millions or billions of years to occur, and it is driven by the mutual gravitational attraction between the two galaxies.

Therefore, During the merger, the individual stars and other celestial bodies within the galaxies will continue to orbit as they did before, but the overall shape and structure of the resulting galaxy may be significantly different from that of the original galaxies.

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A common activity like cooking a meal can use many natural Ingredients

Ingredients are substances combined to make a particular mixture such as a meal. most of the ingredients used for the preparation of a meal are sourced naturally.

In cooking different recipes of a meal the use of specific ingredients for each recipe differentiates the recipes.

Therefore we can conclude that cooking a meal requires the use of natural ingredients.

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Answer:

\(8.4 \times 10^{5}\; \rm J\), assuming that there's no heat exchange between the washing machine and the environment.

Explanation:

Let \(m\) denote the mass of water and \(c\) the specific heat capacity of water. The energy required to raise the temperature of that much water by \(\Delta T\) would be:

\(Q = c \cdot m \cdot \Delta T\).

Washing at \(30\; \rm ^{\circ} C\) would require a temperature change of \(\Delta T = 30\; \rm ^{\circ} C - 16\; ^{\circ} \rm C = 14\; \rm K\).

Washing at \(50\; \rm ^{\circ} C\) would require a temperature change of \(\Delta T = 50\; \rm ^{\circ} C - 16\; ^{\circ} \rm C = 34\; \rm K\).

In both situations, \(c = 4.2 \times 10^{3}\; \rm J \cdot kg \cdot K^{-1}\) while \(m = 10\; \rm kg\).

Calculate the energy required in either situation:

Washing at \(30\; \rm ^{\circ} C\):

\(\begin{aligned}& Q({30\; ^{\circ} {\rm C}}) \\ &= c \cdot m \cdot \Delta T \\ &= 4.2 \times 10^{3}\; \rm J \cdot kg \cdot K^{-1} \times 10\; \rm kg \times 14\; \rm K \\ &= 588000 \times 10^{5}\; \rm J\end{aligned}\).

Washing at \(50\; ^{\circ} {\rm C}\):

\(\begin{aligned}& Q({50\; ^{\circ} {\rm C}}) \\ &= c \cdot m \cdot \Delta T \\ &= 4.2 \times 10^{3}\; \rm J \cdot kg \cdot K^{-1} \times 10\; \rm kg \times 34\; \rm K \\ &= 1428000 \; \rm J\end{aligned}\).

\(1428000\; \rm J - 588000\; \rm J = 8.4 \times 10^{5}\; \rm J\).

The velocity of a dropped ball cannot be constant but instead increases as it falls due to the influence of gravity.

When a ball is dropped, it is subjected to the force of gravity, which causes it to accelerate downward. The acceleration due to gravity near the Earth's surface is approximately 9.8 m/s². This means that the velocity of the ball increases by 9.8 meters per second for every second it falls.

Since velocity is a vector quantity that includes both magnitude and direction, the velocity of the ball changes as it falls. Initially, when the ball is released, its velocity is zero. As it falls, the velocity increases in the downward direction. The ball gains speed and its velocity magnitude continuously grows.

The reason behind this acceleration is that the gravitational force acting on the ball is unbalanced. According to Newton's second law of motion, the net force acting on an object is equal to its mass multiplied by its acceleration. In the case of the falling ball, the force of gravity (weight) is the net force causing acceleration.

If the velocity were to remain constant during the fall, it would mean that there is no acceleration acting on the ball. This would imply that the net force is zero, which contradicts the presence of the gravitational force. Therefore, the velocity of a dropped ball cannot be constant but instead increases as it falls due to the influence of gravity.

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Hello jamaicandoll!

\( \huge \boxed{\mathfrak{Question} \downarrow}\)

What is the force on a body if the mass of the body is 2300g? (acceleration due to gravity = - 9.8m/s²) .

\( \huge \boxed{\mathfrak{Answer} \downarrow}\)

Given,

We know that, force = mass × acceleration.

So,

F = ma

F = 2.3 × -9.8

F = \(\boxed{\underline{\bf \: -22.54\:N}}\)

__________________

Hope it'll help you!

ℓu¢αzz ッ

Under certain circumstances, the grounded (neutral) conductors of a residential service are permitted to be sized smaller than the phase conductors.

What is conductors?

A material that easily permits the flow of electricity is referred to as an electrical conductor. Conductivity is the quality of conductors that enables them to conduct electricity.

Electric current is the name given to the movement of electrons through a conductor. Voltage is the amount of power necessary to cause that current to flow through the conductor.

What is phase ?

Phases are parts of a system that are mechanically separable from other parts of the system and are physically distinct from other parts of the system. types of substance. Solid, liquid, or gaseous phases can exist in a system. Strong atomic bonding and high viscosity, which produce a hard form in solids, are their distinguishing characteristics.

Therefore, Under certain circumstances, the grounded (neutral) conductors of a residential service are permitted to be sized smaller than the phase conductors.

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The movement of crustal plates is best described as a continuing long-term process.

Plate tectonics is a theory of geology that describes the movement and interactions of lithospheric plates that cover the Earth's surface. There are three types of plate boundaries: divergent, convergent, and transform. They all have varying rates of movement and result in various geological phenomena.

As a result, the movement of crustal plates is best described as a continuing long-term process. Crustal plates move slowly over time as they are pushed and pulled by the Earth's internal forces. The direction and speed of movement vary from one plate to another, and the rate of movement is determined by several factors, including the thickness and composition of the lithosphere.

Plate tectonics is a process that operates on a global scale and has a significant impact on the Earth's surface features and geological history.

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Answer:

Selected answers A) and D)

Explanation:

Acceleration

According to the Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass:

\(\displaystyle a=\frac{F}{m}\)

We are given four situations, let's compute the acceleration on each case.

A) The block A has a mass of m=5 kg and a net force of F=20 N. The acceleration is:

\(\displaystyle a=\frac{20}{5}=4\ m/s^2\)

This option must be selected because the acceleration is the same as the option D. Correct option A

B) The block B has a mass of m=10 kg and a net force of F=25 N. The acceleration is:

\(\displaystyle a=\frac{25}{10}=2.5\ m/s^2\)

No other option has this value of acceleration, so this option is not correct.

C) The block C has a mass of m=20 kg and a net force of F=100 N. The acceleration is:

\(\displaystyle a=\frac{100}{20}=5\ m/s^2\)

No other option has this value of acceleration, so this option is not correct.

D) The block D has a mass of m=20 kg and a net force of F=80 N. The acceleration is:

\(\displaystyle a=\frac{80}{20}=4\ m/s^2\)

This option must be selected because the acceleration is the same as the option A. Correct option D

Block A (m = 5kg; F = 20 N) and Block D (m = 20 kg; F = 80 N) have the same acceleration.

Acceleration (a) is the change in velocity over time.

It is directly proportional to the force applied (F) and inversely proportional to the mass of the object (m).

We can calculate the acceleration of each block using Newton's second law of motion.

\(a = \frac{F}{m}\)

\(a = \frac{F}{m} = \frac{20N}{5kg} = 4m/s^{2}\)

\(a = \frac{F}{m} = \frac{25N}{10kg} = 2.5m/s^{2}\)

\(a = \frac{F}{m} = \frac{100N}{20kg} = 5m/s^{2}\)

\(a = \frac{F}{m} = \frac{80N}{20kg} = 4m/s^{2}\)

Block A (m = 5kg; F = 20 N) and Block D (m = 20 kg; F = 80 N) have the same acceleration.

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The Communist Party of Germany (German: Communistic Partee Deutschland's, pronounced [kmunst pata dtlants]

KPD was a significant political force in the Weimar Republic from 1918 to 1933, a clandestine resistance organization in Nazi Germany, and a minor party in West Germany during the postwar years until it was outlawed by the Federal Constitutional Court in 1956.

Socialists who had opposed the war founded the party in the years following the First World War, and it participated in the Spartacist rebellion of January 1919, which aimed to establish a soviet republic in Germany. Following the uprising's failure and the murders of KPD leaders Leo Jogiches, Karl Liebknecht, and Rosa Luxemburg, the party briefly adopted a more moderate, parliamentary course under the direction of Paul Levi will be teaching the course on parliament. Typically receiving between 10 and 15 percent of the vote throughout the Weimar Republic era, the KPD had representatives in both the national Reichstag and state parliaments. The party became firmly Stalinist and obedient to the Soviet Union's leadership under Ernst Thomann's leadership starting in 1925. Starting in 1928, the Commenter in Moscow largely controlled and provided funding for the party. In the Weimar Republic, the KPD believed all other parties to be "fascists," and under Thomann's leadership, the party focused the majority of its attacks on the Social Democratic Party of Germany, which it viewed as its main rival and referred to as "social fascists.

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