A light bulb has a resistance of 360. What is the current in the bulb when it has a potential difference of 120 V across it? 0. 33 A 3 A 480 A 43,200 A.

The loss of an electrical signal over distance as it travels along a conductor due to resistance is referred to as voltage drop. Thus, the correct option is B.

Voltage drop is the decrease of the electric potential along the path of a current which is flowing in an electric circuit. Voltage drops in the internal resistance of the source of an electric circuit, across the conductors, across contacts, and across the connectors of an electric circuit are all  undesirable because some of the energy supplied to it is dissipated.

Voltage drop of the circuit with conductors can be determined by multiplying the current flowing through the electric circuit with the total resistance of the circuit conductors of the electric circuit:

VD = I x R

where, VD = Voltage Drop,

I = Electric current,

R = Resistance.

Therefore, the correct option is B.

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Your question is incomplete, most probably the complete question is:

The loss of an electrical signal over distance as it travels along a conductor

due to resistance is referred to as:

A) its root mean square

B) voltage drop

C) the ampacity rating

D) a ground and bonding system

Answer:

• From first newtons equation of linear motion:

\({ \boxed{v = u + at}}\)

• from that equation, let's get the relation for the change in velocity;

\((v - u) = at \\ { \boxed{ \boxed{\delta v = at}}}\)

• a is the acceleration, a = 0.3 m/s and t is time, t = 3s

\( \delta v = (0.3 \times 3) \\ { \underline{ \underline{ \delta v = 0.9 \: \: m {s}^{ - 1} }}}\)

Answer: A. 0.9 m/s

The use of telemedicine for interpretation of x-rays by providers outside the organization and potentially out of the country can have an impact on credentialing and privileging decisions. Here are some ways this impact can occur:

1. Licensing and credentialing: Providers interpreting x-rays remotely need to be licensed and credentialed in the jurisdiction where the patient is located. If they are located outside the country, they may need to meet additional requirements to practice telemedicine internationally.

2. Quality assurance: Organizations need to ensure that the remote interpretation of x-rays meets the same standards as on-site interpretations. This may involve implementing quality control measures, such as ongoing monitoring and feedback, to ensure accuracy and reliability.

3. Compliance with regulations: Telemedicine practices must adhere to relevant laws and regulations, both in the country where the patient is located and where the interpreting provider is located. This includes compliance with data privacy and security requirements.

4. Cultural and language considerations: Providers interpreting X-rays remotely need to be proficient in the language and cultural context of the patients they are serving. This is particularly important when interpreting medical imaging, as accurate communication is essential for proper diagnosis and treatment.

Overall, the use of telemedicine for interpretation of x-rays by providers outside the organization and potentially out of the country requires careful consideration of licensing, credentialing, quality assurance, and compliance with regulations to ensure patient safety and quality of care.

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Wavelength of the photon: 4.52 x 10^-7 meters

Wavelength of the electron: 1.097 x 10^-9 meters

To find the wavelengths of a photon and an electron that have the same energy, we can use the energy-wavelength relationship for photons and the de Broglie wavelength equation for electrons.

1. Wavelength of a Photon:

The energy of a photon can be calculated using the equation:

E_photon = hc / λ

where E_photon is the energy of the photon, h is Planck's constant (6.626 x \(10^{-34\) J s), c is the speed of light in a vacuum (3.00 x \(10^8\) m/s), and λ is the wavelength of the photon.

Rearranging the equation, we can solve for the wavelength:

λ = hc / E_photon

Substituting the given energy of 29.0 eV (electron volts) into the equation, we need to convert it to joules:

1 eV = 1.602 x \(10^{-19\) J

E_photon = 29.0 eV * (1.602 x \(10^{-19\) J/eV) = 4.646 x \(10^{-18\) J

Plugging this value into the equation, we have:

λ_photon = (6.626 x \(10^{-34\) J s * 3.00 x \(10^8\)m/s) / (4.646 x \(10^{-18\) J)

λ_photon ≈ 4.52 x \(10^{-7\) meters

Therefore, the wavelength of the photon with an energy of 29.0 eV is approximately 4.52 x \(10^{-7\) meters.

2. Wavelength of an Electron:

The de Broglie wavelength of an electron is given by the equation:

λ_electron = h / (mv)

where λ_electron is the wavelength of the electron, h is Planck's constant, m is the mass of the electron, and v is the velocity of the electron.

Since the energy of the electron is given, we can use the relationship between energy and kinetic energy:

E_electron = (1/2)mv²

Solving for v:

v = √((2E_electron) / m)

Substituting the given energy of 29.0 eV and the mass of an electron (9.10938356 x \(10^{-31\) kg), we have:

v = √((2 * 29.0 eV * (1.602 x \(10^{-19\) J/eV)) / (9.10938356 x \(10^{-31\) kg))

Calculating the velocity, we find:

v ≈ 6.01 x \(10^6\) m/s

Now, we can calculate the wavelength of the electron:

λ_electron = (6.626 x \(10^{-34\) J s) / (9.10938356 x \(10^{-31\) kg * 6.01 x \(10^6\) m/s)

λ_electron ≈ 1.097 x \(10^{-9\) meters

Therefore, the wavelength of the electron with an energy of 29.0 eV is approximately 1.097 x \(10^{-9\) meters.

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The net force on q3 is -1.686 N, with the arrow pointing to the left.

We may compute the force exerted by q1 and q2 on q3 using Coulomb's law:

where k is Coulomb's constant, q1, q2, and q3 are particle charges, and r1 and r2 are the distances between q1 and q3, respectively.

When we substitute the provided values, we get:

The forces' negative sign implies that they point in the opposite direction as the axis's positive direction. As a result, F1 points to the left, whereas F2 points to the right.

The vector sum of F1 and F2 is the net force on q3:

Fnet = F1 + F2 = -0.056 N + (-1.686 N)

As a result, the net force on q3 is -1.686 N and the force is negative will point left.

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The total time the balls are in the air is 2.77 s.

The correct answer is option E.

To calculate the total time the ball is in the air, we need to analyze the vertical motion of the ball. Let's consider the given values:

Height of the taller platform (H1) = 6.0 m

Height of the shorter platform (H2) = 3.6 m

Horizontal speed of the ball (ux) = 15 m/s

We can neglect friction for this calculation. Since the ball rolls off the taller platform horizontally, the initial vertical velocity (uy) is zero. We can use the following equation to calculate the time of flight:

H = ut + (1/2)\(gt^2\)

Phase 1: Upward motion

In this phase, the ball moves vertically against the force of gravity. The acceleration due to gravity (g) is approximately 9.8 m/s^2. The initial vertical velocity (uy) is zero.

Using the equation of motion:

H1 = (1/2)\(gt^2\)

6.0 = (1/2)(\(9.8)t^2\)

12.0 =\(4.9t^2\)

\(t^2\) = 12.0 / 4.9

\(t^2\) ≈ 2.449

t ≈ \(\sqrt{2.449}\)

t ≈ 1.564 s

Phase 2: Downward motion

In this phase, the ball moves vertically downward. The final velocity in the upward phase (when it reaches the top of the shorter platform) is zero. We can calculate the time it takes to fall from the shorter platform using the same equation:

H2 = (1/2)g\(t^2\)

3.6 = (1/2)(9.8)\(t^2\)

7.2 = 4.9\(t^2\)

\(t^2\) = 7.2 / 4.9

\(t^2\) ≈ 1.469

t ≈ \(\sqrt{1.469}\)

t ≈ 1.212 s

Total time:

The total time the ball is in the air is the sum of the times for phase 1 and phase 2:

Total time = t1 + t2

Total time ≈ 1.564 + 1.212

Total time ≈ 2.776 s

Therefore, among the given options the correct one is option E.

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The question probable may be:

The diagram represents two horizontal platforms that are different height levels above ground ball rolls off the taller platform with a horizontal speed of 15 m/s in travels through the air landing on top of the short a platform. What is the total time the ball is in the air where H1 =6.0 m H2= 3.6m (NEGLECT FRICTION)

A.0.16 s

B. 0.70 s

C.0.49s

D. 1.1 s

E. 2.77 s

Answer:5.45X10^3m

Explanation:So use the formula,v= fλ

3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer

Answer:

5.45X10^3m

Explanation:

(a) As σ is increased, The minimum  angle will be "19.2°".

(b) The acceleration will be "0.91 m/s²"once the box has began to move.

(c) The speed will be "3 m/s" as the box slid a distance 4.7 m along the loading map.

According to the question,

Mass = 25.0 kg

Kinetic friction = 0.25

Coefficient of static friction = 0.35

(a) We know,

⇒ static friction = mg sine

⇒ mg cosine * u = mg sine

then,

tan A = u = 0.35

a = 19.2

Therefore, as α is increased,  the minimum angle at which the box starts to slip is 19.2°.

(b) We know that:

Kinetic friction = mgCos19.2 * 0.25

                        = 2.31m

and,

Net force downwards = mgSin19.2 -  mgCos19.2* 0.25

By substituting the values, we get

                                        = m(3.22-2.31)

                                        = 0.91m/s²

Therefore, As this angle, the acceleration once the box has begun to move at 0.91 m/s².

(c) since the box is sliding at a distance of 4.7 meter:

Thus,

The speed will be:

→ \(v^{2} - u^{2} + 2as\)

\(0 + 2* 0.91* 5\)

= 9.21

\(v = 3m/s\)

Therefore, at this angle, at 3m/s will the box be moving after it has slid a distance 4.7m along the loading ramp

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The distance for the first image is 22 ft for the second image is 44 ft, and for the third image is 66 ft.

The distance from the person to the first three images in the left-hand mirror can be found by using the equation of the image distance in a mirror:

Image distance = 2 x Object distance.

The object distance is 11.0 ft for the left-hand mirror and 4.00 ft for the right-hand mirror.

Therefore, the distance to the first image in the left-hand mirror is,

22 ft (11.0 ft x 2 = 22 ft),

the second image is,

44 ft (11.0 ft x 2 + 4.00 ft x 2 = 44 ft),

The third image is,

66 ft (11.0 ft x 2 + 4.00 ft x  2 + 4.00 ft x 2 = 66 ft).

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When you calculate the speed of a treadmill at 3.5 mph and obtain the same value, it indicates that the treadmill is properly calibrated and accurately measures the speed.

The speed of a treadmill is typically set by the user or controlled by the treadmill's console. If the speed is displayed as 3.5 mph and your calculation also yields 3.5 mph, it suggests that the treadmill is functioning correctly and accurately measuring the speed.

To ensure accurate speed measurements, treadmills undergo calibration processes during manufacturing or maintenance. Calibration involves setting the treadmill's speed settings to correspond accurately to the displayed values. This ensures that users can rely on the displayed speed as an accurate representation of their pace.

If the calculated speed significantly differed from the displayed speed, it could indicate a calibration issue, mechanical problem, or error in measurement. However, in this scenario where the calculated speed matches the displayed speed, it is an indication that the treadmill is calibrated correctly and provides accurate speed measurements.

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Answer:

-1.46 m/s^2

Explanation:

Write down what is given first:

v0 = 12 m/s

vf = 0 m/s

d = 45 m

We are trying to find acceleration, so we will use the equation vf^2 = v0^2 + 2ad

Plug in the values we have:

0^2 = 12^2 + (2 x 45 x a)

a = - 1.46 m/s^2

Note that this acceleration is negative because the body is slowing down, so the acceleration with be negative, because the change in velocity is negative.

According to the given statement - 1.46 m/s²  is the acceleration of the body.

Acceleration is the rate of change in a moving asteroid's speed and direction over time. When something moves faster or slower, it is considered to be accelerating.

Use the formula a = v / t to determine acceleration, where v stands for the change in velocity and t for the time it took for the change to take place. Use the formula v = vf - vi to determine v, where vf stands for final velocity and vi for starting velocity.

Write down what is given first:

v0 = 12 m/s

vf = 0 m/s

d = 45 m

We are trying to find acceleration, so we will use the equation

vf² = v0² + 2ad

Plug in the values we have:

0² = 12² + (2 x 45 x a)

a = - 1.46 m/s²

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Answer:

control group and experimental group

The energy of the mass-spring system is approximately 12.407 J.

The energy of a mass-spring system can be calculated using the formula for the total mechanical energy, which is the sum of the potential energy and the kinetic energy.

To find the potential energy, we can use the formula for the potential energy of a spring:

Potential energy = (1/2) x k x x²

where k is the force constant of the spring and x is the displacement from the equilibrium position.

Given that the force constant of the spring is 284 N/m and the amplitude of the motion is 0.21 m, we can calculate the potential energy as follows:

Potential energy = (1/2) x 284 N/m x (0.21 m)²

Simplifying this expression gives:

Potential energy = 0.5 x 284 N/m x 0.0441 m²

Potential energy = 6.12984 Nm

To find the kinetic energy, we can use the formula for kinetic energy:

Kinetic energy = (1/2) x m x v²

where m is the mass of the block and v is the velocity of the block.

Since the motion is simple harmonic, the maximum velocity occurs at the equilibrium position, where the block passes through the midpoint of its oscillation. At this point, the velocity is maximum and equal to the angular frequency (ω) times the amplitude (A). The angular frequency can be calculated using the formula:

Angular frequency (ω) = √(k/m)

Given that the mass of the block is 4.4 kg and the force constant of the spring is 284 N/m, we can calculate the angular frequency as follows:

Angular frequency (ω) = √(284 N/m / 4.4 kg)

Simplifying this expression gives:

Angular frequency (ω) = √(64.5455 N/kg)

Angular frequency (ω) = 8.0345 rad/s

Therefore, at the equilibrium position, the maximum velocity is:

v = ω x A

v = 8.0345 rad/s  0.21 m

v = 1.6872 m/s

Now we can calculate the kinetic energy:

Kinetic energy = (1/2) x 4.4 kg x (1.6872 m/s)²

Simplifying this expression gives:

Kinetic energy = 0.5 x 4.4 kg x 2.8439 m²/s²

Kinetic energy = 6.27716 J

The total mechanical energy of the mass-spring system is the sum of the potential energy and the kinetic energy:

Total mechanical energy = Potential energy + Kinetic energy

Total mechanical energy = 6.12984 J + 6.27716 J

Total mechanical energy = 12.407 J

Therefore, the energy of the mass-spring system is approximately 12.407 J.

In conclusion, the energy of the mass-spring system is approximately 12.407 J.

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Answer:

the helis speed increased its speed by 35 m/s. Unless you are asking me what was the speed per second. if you were asking me for the speed per second then that would be a different answer

Explanation:

Answer:

7 m/s ^2

Explanation:

a=  60 m/s - 25 m/s over 5 s

a= 35 m/s over  5 s

a= 7 m/s^2

This motion of the balloon is an example of buoyancy, which is the upward force exerted by a fluid on an object immersed in it.

When the balloon is neutrally buoyant, it means that the weight of the balloon and the weights attached to it is equal to the weight of the water displaced by the balloon.

If you push the balloon down to a greater depth and then release it, the balloon will rise back up to its original position.

This is because the balloon is still partially inflated and contains air, which is less dense than water. When you push the balloon down, the water pressure compresses the air in the balloon, causing it to become smaller in size.

When you release the balloon, the compressed air expands and pushes the balloon upwards towards the surface of the water.

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The arrow A represents the direction of upthrust.

Thrust is the pressure acting generally on a surface. Its SI unit is Newton (N). Thrust is the pressure that actions a plane via the air. Thrust is used to triumph over the drag of an airplane, and to conquer the load of a rocket.

As anxiety is the significance of pressure, it is measured in newtons (or now and again kilos-force) and is usually measured parallel to the string on which it applies. Thrust is a response pressure defined quantitatively by means of Newton's.

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The frequency change, in accordance with the presented description, is 636 Hz.

The quantity of occurrences of a recurring event per unit of time is its frequency. It is distinct from angular frequency, and for clarification, it is sometimes referred to as sampling rate. One occurrence per second, or hertz (Hz), is the unit of frequency.

Speed (v1) = 36 m/s

Speed (v2) = 45 m/s

Frequency (f) = 500 Hz

Speed of sound (s) = 343 m/s

We are aware of the modification of frequency formula, which

Frequency = s+v1/ s+v2(f) -------(1)

Put a value here and apply equation (1).

We'll use v2 = -45 since it's the other way.

Frequency = s+v1/ s-v2(f)

Frequency = 343+36 / 343-45(500)

Frequency = 636

Thus, the frequency shift is 636 Hz.

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The complete question is-

A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren relative to the police car is 500 Hz, what is the frequency heard by an observer in the truck after the police car passes the truck? (The speed of sound in air is 343 m/s.)

a). 396 Hz

b). 636 Hz

c). 361 Hz

d). 393 Hz

e). 617 Hz

When air rises in a low-pressure system, it can lead to the formation of clouds and precipitation, such as rain or snow. The rising air also cools and condenses, releasing latent heat, which can further contribute to the development of the storm.

A low-pressure system is a weather pattern characterized by a region of lower atmospheric pressure compared to the surrounding areas. It is often associated with unsettled and stormy weather.

Clouds are formed when moist air rises and cools, causing water vapour to condense into tiny water droplets or ice crystals. This process occurs when the temperature of the air decreases, either because it is rising, or because it is mixing with cooler air.

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The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.

The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

The force on particle q2 due to q1 will be:

F1 = k * (q1 * q2) / (0.980m)^2

The force on particle q2 due to q3 will be:

F2 = k * (q2 * q3) / (0.750m)^2

The net force acting on q2 will be the vector sum of F1 and F2.

Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.

Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.

Check the images.. it has a few different questions and answers! Hope it helps

Answer:

B

Explanation:

An attractive force will occur between the plastic rod and nearby object.

An object is placed near the plastic rod, and an attractive force is detected then the object react when near the glass rod due to presence of attractive force between them. Attraction occurs between two bodies or objects when there is presence of opposite charges on both objects.

So we can conclude that an attractive force will occur between the plastic rod and nearby object.

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Answer: c

Explanation: 125/20 =6.25

The ball will hit the ground 54.4 meters from the base of the cliff. This can be determined using the equation for the horizontal range of a projectile, which is x = vx*t. In this case, vx is 11.5 m/s, and t is the time it takes for the ball to reach the ground. This time can be determined using the equation for the vertical range of a projectile, which is y = vyo*t + 0.5*g*t^2. In this case, vyo is 0 m/s (since the ball is thrown horizontally), g is 9.81 m/s^2, and y is 45.2 m (the height of the cliff). Solving for t gives us 3.86 seconds. Plugging this value into the equation for the horizontal range gives us x = 54.4 m.

the change in direction of a wave passing from one medium to another caused by its change in speed this is from my study guide hope that helps

example: when you are sitting in a pool and ur leg looks deformed or even cut in half its caused my refraction.

Answer:

nope the dog jumped over the river

Explanation:

Answer:

Explanation:

The resistance of the wire will be 5 ohm.

Resistance is nothing but the opposing force applied during charges moving from one side of the wire to the another side of the wire.

According to the ohm's law we have

V ∝ I

or we can write

V = IR

where, V is the voltage applied and I is the current applied and the R is the resistance of the wire.

so we can write,

R = V/I

R = 10/2

R = 5 Ohm

Hence the resistance of the wire will be 5 ohm.

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