A low C (f = 65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and its mass density is 5.0 g/m2, determine the tension of the wire.

Answer:

Isabella will not be able to spray Ferdinand.

Explanation:

We'll begin by calculating the time taken for the water to get to the ground from the hose held at 1 m above the ground. This can be obtained as follow:

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =.?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.9

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s

Next, we shall determine the horizontal distance travelled by the water. This can be obtained as follow:

Horizontal velocity (u) = 3.5 m/s

Time (t) = 0.45 s

Horizontal distance (s) =?

s = ut

s = 3.5 × 0.45

s = 1.58 m

Finally, we shall compare the distance travelled by the water and the position to which Ferdinand is located to see if they are the same or not. This is illustrated below:

Ferdinand's position = 10 m

Distance travelled by the water = 1.58 m

From the above, we can see that the position of the water (i.e 1.58 m) and that of Ferdinand (i.e 10 m) are not the same. Thus, Isabella will not be able to spray Ferdinand.

Answer:

Option A. The speed of sound through water is 4.3 times faster than sound through air.

Explanation:

To answer the question correctly, we shall determine the speed of the wave in both cases. This is illustrated below:

For Air:

Frequency (fₐ) = 195 Hz

Wavelength (λₐ) = 1.76 m

Velocity (vₐ) =?

vₐ = λₐfₐ

vₐ = 1.76 × 195

vₐ = 343.2 m/s

For Water:

Frequency (fᵥᵥ) = 195 Hz

Wavelength (λᵥᵥ) = 7.6 m

Velocity (vᵥᵥ) =?

vᵥᵥ = λᵥᵥfᵥᵥ

vᵥᵥ = 7.6 × 195

vᵥᵥ = 1482 m/s

Finally, we shall compare the speed in water to that of air. This can be obtained as follow:

Velocity in air (vₐ) = 343.2 m/s

Velocity in water (vᵥᵥ) = 1482 m/s

Water : Air

vᵥᵥ : vₐ =>

vᵥᵥ / vₐ = 1482 / 343.2

vᵥᵥ / vₐ = 4.3

Cross multiply

vᵥᵥ = 4.3 × vₐ

Thus, the speed in water is 4.3 times the speed in air.

Option A gives the correct answer to the question.

The speed of the ball as seen by a stationary observer in the street will be the sum of the speed of the ball relative to the bus and the speed of the bus relative to the observer.

From the viewpoint of a stationary observer on the street, the ball and the school bus are both moving forward at the same constant velocity. Therefore, the speed of the ball as seen by the observer in the street will be the sum of the speed of the ball relative to the bus and the speed of the bus relative to the observer.

Assuming the ball is thrown horizontally and neglecting any air resistance, the speed of the ball relative to the bus will be constant and equal to the speed at which the ball was thrown. However, since the bus is moving forward, the speed of the ball relative to the observer in the street will be the sum of the speed of the ball relative to the bus and the speed of the bus relative to the observer.

Suppose, if the bus is traveling at a speed of 20 km/h and the ball is thrown at a speed of 10 km/h relative to the bus, then the speed of the ball as seen by the observer in the street will be 30 km/h (20 mph + 10 km/h).  Therefore, the speed of the ball as seen by a stationary observer in the street will be the  of the relative speed of the ball relative to the bus and the speed of the bus relative to the observer.

Learn more about relative velocity :

https://brainly.com/question/19260269

#SPJ4

Time of flight = 1.6 s

Horizontal distance = 64 m

Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.

For the given case,

h = vt + ¹/₂gt²

h = height of tower

v = initial velocity

t = time of flight

55 = 50sin30t + ¹/₂9.8t²

55 = 25t + 4.9t²

4.9t² + 25t - 55 = 0

t = 1.6 s

X = vₓt

X = horizontal distance

vₓ = horizontal velocity

t = time of flight

X =  (50 x cos30) x 1.6

X =  64 m

To know more about projectile motion visit:

https://brainly.com/question/11049671

#SPJ13

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

The product in a chemical reaction is written on the Right side of the arrow, so

the product formed here in given reaction is :

We have that the time in seconds, minutes, and hours is

\(t=1.083*10^{-4}s\)

\(T_{min}=1.805*10^{-6}min\)

\(T_{hours}=3.0083*10^{-8}hours\)

From the Question we are told that

Velocity \(v=13.0m/s\)

Distance \(d=120 km\)

Generally the equation for the Time  is mathematically given as

\(t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s\)

Therefore

\(T_{min}=1.083*10^{-4}s/60\)

\(T_{min}=1.805*10^{-6}min\)

And

\(T_{hours}=T_{min}/60\)

\(T_{hours}=3.0083*10^{-8}hours\)

For more information on this visit

https://brainly.com/question/12319416?referrer=searchResults

Answer:

Study More You will get it :L

In this solution, the unit vectors in the directions of A + B, A × B, and 2A + 3C are √62,√1915, and √686. The magnitudes of A + B, A × B, and 3A - 2C are √62, √1915, and √164. The angles between A × B and B × A, A and C, and B and C are √30, cos-1(4/√35), and cos-1(-1/√14).

For more questions on unit vectors

https://brainly.com/question/2094736

#SPJ8

Answer:

Both speed and velocity are changing!

Explanation:

I could make a poem for you if you actually gave the words...... what 10 words do i need to incorporate???☹︎

Answer:

Education has not embraced artificial intelligence. Some educators find themselves reluctant to join their peers in its adoption !

Technological platforms that students can use to collaborate on group assignments. Due to technology, learning, collaboration, and communication can now take place outside traditional classroom limits.

Some educators have admitted that they worry about not being able to monitor what children are doing online. They also believe that if technology were included in their classes, students wouldn't be as engaged with the material.

Through the use of personalized programs and AI, learning may be modified and adjusted to each student's unique needs, goals, and talents. This can assist close any gaps in teaching and learning.

Therefore,Artificial intelligence has not been embraced by education. Some educators are hesitant to adopt it with their colleagues.

Learn more about classrooms here:

https://brainly.com/question/25127617

#SPJ2

Answer:

true true fales true

Explanation:

Initial position, u = 10 m

Final position, v = 5 m

Change in time, ∆t = 5 s

We know that, velocity = ∆x / ∆t

where, ∆x is the displacement and ∆t is the change in time.

∆x = v - u

∆x = 5 m - 10 m

∆x = -5 m

Velocity = ∆x / ∆t

Velocity = -5 m / 5 s

Velocity = -1 m/s

Therefore, B: -1 m/s is the correct answer. A negative velocity means the object is traveling in the other direction.

The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).

During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.

A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.

Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.

Learn more about chemical change:

brainly.com/question/26264541

#SPJ1

Answer:

Rayleigh scattering

Explanation:

The blue color of the sky is due to a phenomenon called Rayleigh scattering. When sunlight enters the Earth's atmosphere, the shorter blue wavelengths of light are scattered more than the other colors by the tiny molecules of nitrogen and oxygen in the air. This causes the blue light to be redirected in many different directions, making the sky appear blue to our eyes. The other colors of light are scattered as well, but to a lesser extent, which is why the sky appears blue instead of a mixture of all colors. This effect is also the reason why the sun appears more yellow, orange or red during sunrise or sunset, when its light has to travel through more of the Earth's atmosphere before reaching our eyes, causing the shorter blue wavelengths to be scattered even more, leaving behind the longer wavelengths of light.

Answer:

help

Explanation:

Answer:

15 seconds

Explanation:

If car was moving at 20m/s for 3 sec.

if car traveled 100m = 15 sec total

The potential energy U of an object with mass m located a distance h above the ground is given by the expression:

Where g=9.81m/s^2 is the gravitational acceleration on the surface of Earth.

Since the 2.85kg object is located 12.7 meters below the ground, we can consider h to be negative. Replace m=2.85kg, g=9.81m/s^2 and h=-12.7m to find the potential energy of the object measured from the ground level:

Therefore, the potential energy of the object measured from the ground level is approximately 355J.

Answer:

0.01s : Average velocity = - 102.22 ft/s

0.005s : Average velocity = - 102.11 ft/s

0.002s : Average velocity = - 102.044 ft/s

0.001s: Average velocity = - 102.022 ft/s

Instantaneous velocity at t = 3 is - 102 ft/s

Explanation:

The position-time function is expressed as

y = 30t - 22t^2

y(t) = 30t - 22t^2

1) To find the average velocity between t = 3 and t = 3 + 0.01 = 3.01, we would substitute these values into the position-time function. Thus,

y(3) = 30(3) - 22(3)^2 = - 108

y(3.01) = 30(3.01) - 22(3.01)^2 = - 109.0222

Average velocity = (- 109.0222 - - 108)/(3 - 3.01) = (- 109.0222 + 108)/0.01

Average velocity = - 102.22 ft/s

2) To find the average velocity between t = 3 and t = 3 + 0.005 = 3.005, we would substitute these values into the position-time function. Thus,

y(3) = 30(3) - 22(3)^2 = - 108

y(3.005) = 30(3.005) - 22(3.005)^2 = - 108.51055

Average velocity = (- 108.51055 - - 108)/(3 - 3.005) = (- 108.51055 + 108)/0.005

Average velocity = - 102.11 ft/s

3) To find the average velocity between t = 3 and t = 3 + 0.002 = 3.002, we would substitute these values into the position-time function. Thus,

y(3) = 30(3) - 22(3)^2 = - 108

y(3.002) = 30(3.002) - 22(3.002)^2 = - 108.204088

Average velocity = (- 108.204088 - - 108)/(3 - 3.005) = (- 108.204088 + 108)/0.002

Average velocity = - 102.044 ft/s

4) To find the average velocity between t = 3 and t = 3 + 0.001 = 3.001, we would substitute these values into the position-time function. Thus,

y(3) = 30(3) - 22(3)^2 = - 108

y(3.001) = 30(3.001) - 22(3.001)^2 = - 108.102022

Average velocity = (- 108.102022 - - 108)/(3 - 3.001) = (- 108.102022 + 108)/0.001

Average velocity = - 102.022 ft/s

To find the velocity function, we would differentiate the position time function. Thus,

v(t) = dy(t)/dt = 30 - 44t

To find the instantaneous velocity at t = 3, we would substitute t = 3 into v(t) = 30 - 44t

Thus,

v(3) = 30 - 44 x 3 = 30 - 132

v(3) = - 102

Instantaneous velocity at t = 3 is - 102 ft/s

The new force is obtained as 228 N since the product of the masses is directly proportional to the force.

From the Newton law of universal gravitation, we can see that the gravitational force that exists between two masses is directly proportional to the product of the masses and inversely proportional to the distance between the masses.

Where the distance between the masses, remain the same, we can see that the new force would be three times the initial force since the the force and the mass are directly proportional.

Learn more about the new force:https://brainly.com/question/14276767

#SPJ1

larong pinoy

Explanation:

ito ay larong Pinoy

Answer:

50000N

Explanation:

Force = mass × acceleration

= 2500 × 20

= 50000N

Answer:

a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while  b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.

a. Isothermal compression:

For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Since the process is isothermal, we can write:

\(P_1V_1 = P_2V_2\)

where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.

We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:

\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)

To find the final temperature, we can use the ideal gas law again:

PV = nRT

Rearranging, we get:

T = PV/(nR)

Substituting the values we know, we get:

T = (\(1.5*10^5\)Pa)(V1)/(nR)

Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:

T2 = T1 = 293 K

b. Adiabatic compression:

For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:

PV^γ = constant

where γ = Cp/Cv is the ratio of specific heats.

Since the process is adiabatic and reversible, we can write:

\(P_1V_1\)^γ = \(P_2V_2\)^γ

We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:

\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)

To find the final temperature, we can use the adiabatic equation again:

\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K

Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.

Know more about   isothermal compression   here:

https://brainly.com/question/29882250

#SPJ11

Answer:

add molecules

Answer:

b) 20 kJ

Explanation:

Efficiency of carnot engine = (T₁ - T₂ ) / T₁  Where T₁ is temperature of hot source  and T₂ is temperature of sink .

T₁ = 270 + 273 = 543K

T₂ = 50 + 273 = 323 K

Putting the given values of temperatures

efficiency = (543 - 323) / 543

= .405

heat input = 50 KJ

efficiency = output work / input heat energy

.405 = output work / 50

output work = 20.25 KJ.

= 20 KJ .