Answer:
resulting angular speed = 3.6 rev/s
Explanation:
We are given;
Initial angular speed; ω_i = 1.2 rev/s
Initial moment of inertia;I_i = 6 kg/m²
Final moment of inertia;I_f = 2 kg/m²
From conservation of angular momentum;
Initial angular momentum = Final angular momentum
Thus;
I_i × ω_i = I_f × ω_f
Making ω_f the subject, we have;
ω_f = (I_i × ω_i)/I_f
Plugging in the relevant values;
ω_f = (6 × 1.2)/2
ω_f = 3.6 rev/s
If a catalyst was added to the reaction below, which values would be affected? Check all that apply
If a Catatlyst was added the values affected would be 2, 3, 4
What is a cata;lyst?A catalyst is a substance that speeds up the rate of a chemical reaction without undergoing any permanent change itself. It facilitates the reaction by providing an alternative pathway with lower activation energy, which allows the reaction to occur more readily.
Catalysts work by interacting with the reactant molecules and weakening the existing bonds or creating new ones, making it easier for the reaction to proceed.
Catalysts are typically specific to certain reactions and can be used in small amounts relative to the reactants. They play a crucial role in many industrial processes and are essential for efficient chemical transformations.
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Descriptions of the sky at various locations on Earth
Why is meiosis a key step in sexual reproduction? Select all that apply. creates gametes with two sets of chromosomes creates the necessary male and female gametes prevents male and female gametes from combining creates gametes with one set of chromosomes
Answer:
creates the necessary male and female gametes
creates gametes with one set of chromosomes
Explanation:
Meiosis is a type of cell division employed by sexually-reproducing organisms. It produces four genetically different daughter cells that have their chromosome number reduced by half i.e. from diploid (2n) to haploid (n). Meiosis is the process whereby organisms produce their necessary gametes needed for sexual reproduction.
Male organism produces haploid male gametes(n) while female organisms produce haploid female gametes (n). These gametes contain one set of chromosome (haploid) because they have to unite in a process called FERTILIZATION. When they do, they form a diloid zygote (2n), which has the same number of chromosomes as each parent cell. That is n+n= 2n.
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
acting on it is equal to (41 - 9j) N. If the speed of the object at the initial position is 4.0 m/s,
what is its kinetic energy at its final position?
Answer:
Answer:
v_f = 10.38 m / s
Explanation:
For this exercise we can use the relationship between work and kinetic energy
W = ΔK
note that the two quantities are scalars
Work is defined by the relation
W = F. Δx
the bold are vectors. The displacement is
Δx = r_f -r₀
Δx = (11.6 i - 2j) - (4.4 i + 5j)
Δx = (7.2 i - 7 j) m
W = (4 i - 9j). (7.2 i - 7 j)
remember that the dot product
i.i = j.j = 1
i.j = 0
W = 4 7.2 + 9 7
W = 91.8 J
the initial kinetic energy is
Ko = ½ m vo²
Ko = ½ 2.0 4.0²
Ko = 16 J
we substitute in the initial equation
W = K_f - K₀
K_f = W + K₀
½ m v_f² = W + K₀
v_f² = 2 / m (W + K₀)
v_f² = 2/2 (91.8 + 16)
v_f = √107.8
v_f = 10.38 m / s
A surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 118 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is = 33.4°. How wide is the river?
Answer:
68.5 meters
Explanation:
To solve this problem, we can use trigonometry and create a right triangle with the river as the hypotenuse.
Let's call the width of the river "w". We can use the sine function to find the length of the opposite side of the triangle (the distance from the surveyor to the tree).
sin(33.4°) = opposite/hypotenuse
sin(33.4°) = w/x
w = x * sin(33.4°)
w = 118 m * sin(33.4°)
w = 68.5 m
Therefore, the width of the river is approximately 68.5 meters.
Use the sentence to answer the question.
Light is affected by gravity.
Which inference can be made based on this fact?
(1 point)
Light behaves differently in space than on Earth.
Light behaves differently in space than on Earth.
Gravity causes light to refract.
Gravity causes light to refract.
Light moves faster in space than on Earth.
Light moves faster in space than on Earth.
Stronger gravity causes an increase in light.
Answer:
Light behaves differently in space than on Earth.
Explanation:
Because the gravity field is greater near earth than in most of space. Not the areas near stars, black holes, pulsars, and such but in the vast emptyness between the clumpy spots.
find the finel angular velocity (w) when the intial angular velocity(w) is 5rad/s the Angular acceleration is 2rad/s² and the time of motion is 5sec
Answer:
15 rad/s
Explanation:
Given:
α = 2 rad/s²
ω₀ = 5 rad/s
t = 5 s
Find: ω
ω = αt + ω₀
ω = (2 rad/s²) (5 s) + (5 rad/s)
ω = 15 rad/s
Please Help!!!!
When energy is transferred in a system, the total amount of energy before the transfer is _____________ after the transformation is complete, just in different forms.
Group of answer choices
different
lost
transformed into light
the same
In 1994, a pumpkin with a mass of 449 kg was grown in Canada. Suppose you want to push a pumpkin with this mass along a smooth, horizontal ramp. You give the pumpkin a good push, only to find yourself sliding backwards at a speed of 4.0 m/s. How far will the pumpkin slide 3.0 s after the push? Assume your mass to be 60.0 kg.
After pushing the pumpkin hard, you find yourself reversing direction at a speed of 4.0 m/s. 3.0 seconds after being pushed, the pumpkin will slide 12 m. Assume you weigh 60.0 kg.
We can use the conservation of momentum to solve this problem. After the push, the momentum of the system is given by:
p = (449 kg + 60 kg) * v
where v is the speed of the pumpkin and you after the push. Since you end up sliding backward at 4.0 m/s, we have:
v = -4.0 m/s
Substituting this into the expression for momentum, we find:
p = (449 kg + 60 kg) * (-4.0 m/s) = -2036 kg·m/s
The negative sign indicates that the momentum of the system is in the opposite direction of your motion.
During the sliding motion, the net force on the system is given by:
Fnet = (449 kg + 60 kg) * g * sin(θ)
where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of the ramp. Since the ramp is smooth and horizontal, θ = 0 and Fnet = 0. Therefore, there is no net force to change the momentum of the system.
Using the equation for motion with constant acceleration, we can find the distance the pumpkin slides in 3.0 seconds:
x = x0 + v0t + (1/2)at²
Since the initial speed of the pumpkin is -4.0 m/s and there is no net force acting on it, its speed remains constant during the slide. Therefore, v0 = -4.0 m/s and a = 0. Substituting these values, we find:
x = x0 + v0t = (-4.0 m/s) * (3.0 s) = -12 m
The negative sign indicates that the pumpkin slides in the opposite direction to your motion. Therefore, the pumpkin slides 12 meters backward (i.e., towards you) in 3.0 seconds after the push.
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90 V
R₁
60
R2
30
R3
30
Based on the circuit above, what would be the current through the R3 resistor?
In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.
To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.
First, let's consider the parallel combination:
In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.
Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:
I_parallel = V / R3
= 90 V / 30 Ω
= 3 A
So, in the parallel combination, the current through R3 is 3 A.
Now, let's consider the series combination:
In a series combination, the total resistance is the sum of the individual resistances:
R_total = R1 + R2 + R3
= 60 Ω + 30 Ω + 30 Ω
= 120 Ω
To find the current through the series combination, we can use Ohm's Law:
I_series = V / R_total
= 90 V / 120 Ω
= 0.75 A
Therefore, in the series combination, the current through R3 is 0.75 A.
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Note the complete questions is User
90 V R₁=60 R2= 30, R3 = 30
Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.
please help meeee its for physics....
Nothing accelerates a Projectile Horizontally during Motion...
Consequently
Horizontal Acceleration is Always Zero.
The Horizontal Velocity is always Constant too.
Only the vertical Velocity changes by -9.8ms-².
If this is so...
∆x = v'∆t + ½(0)(∆t)²
∆x = v't.
I'd go with Option D.
Which electromagnet is the strongest?
An illustration of a metal bar with a coil of wire around it.
An illustration of a metal bar with a coil of wire around it it has more coils.
An illustration of a metal bar with a coil of wire around it it has less coils.
* The Answer is the 2nd picture - An illustration of a metal bar with a coil of wire around it it has more coils.
Therefore, of the three options given, the electromagnet with more coils around the metal rod is the most powerful if all other factors such as current and core material are kept constant.
What is the very short response to an electromagnet?
An electromagnet is a temporary magnet made by winding a wire around an iron core. When current flows through the coil, iron becomes a magnet, and when the current is cut off, it loses its magnetic properties.
What is Electromagnetism?
Electromagnetism is the branch of physics that deals with the electromagnetic forces that occur between charged particles. Electromagnetic force is one of the four basic forces and describes the electromagnetic field.
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Answer: The answer is B
Explanation:
You are on the west bank of a river which flows due south and want to swim to the east bank (draw a picture!). You have told your friends to meet you on the east bank directly opposite your starting point and there is no bridge so, being the nut you are, you decide to swim it. Before starting out, you realize that, since the river is flowing swiftly at a speed of 12 ft/s and since your fastest swimming speed in still water is only 5 ft/s, you will inevitably be carried downstream. Nevertheless, you want to minimize the effort expended by your friends in walking downstream to meet you. Your guide book to the region tells you that the width of the river is 300 ft. After a quick calculation, you call your friends on your cellular phone and tell them to start walking to a new meeting point.
Required:
How far downstream of the original meeting point should you tell them to walk?
Answer:
θ = 50 , y' = 360 ft
Explanation:
This exercise is related to the addition of speeds, as they ask us the lower the starting point the swimmer reaches.
Let's solve the problem in parts, let's start by knowing the time it takes to reach the opposite shore, its velocity of v = 5ft / s and the width of the river is x = 300 ft
v = d / t
t = d / v _man
t = 300/5
t / 60 s
This is the time it takes to get to the opposite shore if there is no current, now let's find when the current of the river that goes to the South diverts it
v_river = y / t
y = v_river t
y = 12 60
y = 720 ft
To minimize the distance that your friend must travel, we can glass the distance, for this the swimmer must swim at an angle with respect to the river.
So let's use trigonometry to find out what angle you should swim at to cover
y ’= y / 2
y ’= 720/2 = 360 ft
tg θ= y '/ x
θ = tg⁻¹ y'/ x
θ = tg⁻¹ 360/300
θ = 50
This is the angle at which the friend must swim the minimum distance downstream.
1. In mechanical waves, which property determines the energy of the wave?
a. Frequency
b. Wavelength
c. Amplitude
d. Period
2. In light waves, which property determines the amount of energy in the wave?
a. Frequency
b. Wavelength
c. Amplitude
d. Period
3. Which mathematical function models the shape of a transverse wave?
a. Sine
b. Cosine
c. Tangent
4. What is the relationship between period and frequency?
a. Period is the inverse of frequency.
b. Period is a multiple of frequency.
c. Period is the quotient of frequency.
d. Period is the sum of all the frequencies.
Answer:
I only know the first 2
Explanation:
1. A
2. B
In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb
Answer:
Hola eres nuevo yo nací en el 2021 del 4 de junioNewton’s second law of motion says when a is applied to a it causes it to.
Answer:
When force is applied to an object it causes to to accelerate.
Explanation:
A big rock falls from a height towards water below, and hits water at a speed of 12 m/s. Rock was at a height of 15 m before falling and weighs 65 kg.
a) What was the average force of air resistance (e.g., friction) acting on the rock?
b) What is the force of friction underwater if the rock reaches a depth of 2.5 m before stopping and there is a buoyant force of 650 N [upward] acting on the rock once underwater.
The frictional force of air resistance is; 949N while the force of friction underwater is; 1859N.
What is the Frictional force of air resistance?The frictional force on the action rock can be evaluated as follows;
F - W = ma
However, the acceleration of fall a can be evaluated as follows;
a = (12² -0²)/2× 15
a = 144/30 = 4.8m/s².
a) Hence, the air resistance, frictional force, F = (65×9.8) + (65 ×4.8)
F = 949N.
b) When reaches a depth of 2.5m, it follows that the acceleration is;
a = (0²-12²)/(2×2.5)
a = 144/5 = 28.8m/s².
On this note, the force balance is;
F + 650 = 65(9.8 + 28.8)
F = 2509 - 650
F = 1859N.
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What impulse occurs when an average force of 8.0 N
is exerted on a cart for 2.6 s
?
Answer:
20.8 N*s
Explanation:
Brainly is being odd so I can't give a good explanation. But the impulse is the average force multiplied by the time the force acts on the object. impulse is basically just the total force
Impulse=Force * time=8*2.6=20.8
helpp pleaseeeeee …..
Answer:
300 cos 30 = 40 a + 40 * .2 * 10
Total force = mass * acceleration + frictional force
260 = 40 a + 80
a = 180 / 40 = 4.5 m/s^2
Check:
15 a + 15 * 10 * .2 = T acceleration of 15 kg block (assuming a = 4.5)
T = 15 (4.5) + 30 = 97.5 force required to accelerate 15 kg block
260 - 97.5 = 162.5 net force on 25 kg block
162.5 = 4.5 (25) + 25 * 10 * .2
162.5 = 112.5 + 50 = 162.5
4.5 m/s^2 checks out as correct
The softest sound a human ear can hear is at 0 dB (Io = 10-12 W/m2). Sounds above 130 dB cause pain. A particular student's eardrum has an area of A = 51 mm2. What is the most power, in watts, the ear can receive before the listener feels pain?
Im so confused on how to even start with this problem, my main question is how sound and power are related.
Answer:
Sound and power are related through intensity, which is the amount of power per unit area. The intensity of a sound wave is proportional to the square of its amplitude, which is a measure of how far the wave oscillates from its equilibrium position.
To solve this problem, you can use the formula for sound intensity:
I = P/A
where I is the intensity of the sound wave in watts per square meter (W/m^2), P is the power of the sound wave in watts (W), and A is the area of the eardrum in square meters (m^2).
You are given that the softest sound a human ear can hear is 0 dB, which corresponds to an intensity of 10^-12 W/m^2. You are also given that sounds above 130 dB cause pain. To find the maximum power the ear can receive before the listener feels pain, you can rearrange the formula for intensity to solve for power:
P = AI
where A is the area of the eardrum in square meters.
Substituting the given values, you get:
P = (51 x 10^-6 m^2)(10^-12 W/m^2 x 10^(130/10))
Simplifying this expression, you get:
P = 1.8 x 10^-3 W
Therefore, the most power the ear can receive before the listener feels pain is 1.8 x 10^-3 watts.
Thallium-201 is a radioisotope used in brain scans. If the recommended dose is 3.0 mCi and a vial contains 60. mCi in 50. mL , how many milliliters should be injected?
2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.
Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:
a/b = c/d.
Cross-multiplying gives us the equation
ad = bc.
This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:
3.0 mCi / x mL = 60. mCi / 50. mL
To solve for x, we can cross-multiply:
3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL
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which hand has a negatively charged?
Answer:
The dryer sheet is negatively charged and your hand is positively charged
Explanation:
While diving in cancun Mexico where the seawater has a density of 1,015 kg/m3 Nana observed that her pressure meter device reading was 3.75 atm. The reading at sea level is standard 1.0 atm. At what depth is she diving when the meter read 3.75 atm g
Answer:
The depth of the diver is 28.01 m
Explanation:
Given;
density of the seawater, ρ = 1,015 kg/m³
standard sea level pressure, P₀ = 1.0 atm = 101,325 Pa
the final reading of her pressure, P₁ = 3.75 atm = 379968.75 Pa
acceleration due to gravity, g = 9.8 m/s²
Let the depth she was diving at the final pressure = h
This depth is calculated as;
P₁ = P₀ + ρgh
P₁ - P₀ = ρgh
\(h = \frac{ P_1 \ - \ P_o}{\rho g} = \frac{379968.75 \ - \ 101325}{1015 \ \times \ 9.8} = 28.01 \ m\)
Therefore, the depth of the diver is 28.01 m
1. How many valence electrons does each atom of arsenic (As) have? Arsenic is element 33. It is in period 4 and family 15 (5A or the Nitrogen family).
2.Two representative elements are in the same period of the periodic table. Which statement correctly describes the atoms of the two elements?
3. Helium is in group 18 of the periodic table. How is helium different from the other elements in this group?
4. Which element has atoms with valence electrons in a higher energy level than those of calcium (Ca)
5.Which statement best describes the arrangement of electrons in an atom of fluorine (F)?
A representative element is an element whose properties can be used to discuss the chemistry of the group into which the element falls.
What is a representative element?A representative element is an element whose properties can be used to discuss the chemistry of the group into which the element falls. Now we will try to answer each of the questions.
1) The atoms of arsenic and nitrogen have five valence electrons
2) The statement that correctly describes the two representative elements are in the same period of the periodic table is that they belong to the same period and have the same number of shells.
3) Helium is different from the other members of group 18 because it has 2 and not eight valence electrons
4) The element that has atoms with valence electrons in a higher energy level than those of calcium (Ca) is barium
5) The statements that best describes the arrangement of electrons in fluorine is that the the electronic configuration is [He] 2s2 2p5.
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A 50-kg ice skater turns a bend at 7 m/sec. If the radius of the curve is 5 m, what is the centripetal force in Newtons provided by the friction between the blade of the skate and the ice?
The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N
How do i determine the centripetal force?The following data were obtained from the question:
Mass of ice skater (m) = 50 KgVelocity (v) = 7 m/sRadius (r) = 5 metersCentripetal force (F) =?The centripetal force can be obtained as illustrated below:
F = mv²/r
= (50 × 7²) / 5
= (50 × 49) / 5
= 2450 / 5
= 490 N
Thus, we can concluded that the centripetal force is 490 N
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The Milky Way is our home galaxy. Which of the following are the main components of a galaxy?
A.
gravity, sedimentary rocks, and water
B.
ice, meteoroids, and minerals
C.
orbits, cores, and eclipses
D.
gas, dust, and stars
Answer:
D
Explanation:
most probable answers. I miss however here few things like eg. dark matter
When you heat water on a stove, how does its energy change?
A. Its electromagnetic energy decreases.
B. Its thermal energy decreases. c. Its thermal energy increases.
D. Its electromagnetic energy increases.
Answer:
C. its thermal energy increases
Answer:
Explanation:
C
1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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A 682-kg elevator starts from rest and moves upward for 3.10 s with constant acceleration until it reaches its cruising speed, 1.80 m/s.
(a) What is the average power of the elevator motor during this period? (Answer in horsepower)
(b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with
constant speed.) (answer in horsepower)
a) the average power of the elevator motor during this period is 0.1696 hp
b) The power during an upward trip with constant speed is 16.13 horsepower.
To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.
Given:
Mass of the elevator (m) = 682 kg
Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²
Time taken for acceleration (t) = 3.10 s
(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:
d = 0.5 * a * t^2
= 0.5 * 0.5806 m/s² * (3.10 s)^2
= 1.0153 m
Next, we can calculate the work done (W) by the elevator motor:
W = m * a * d
= 682 kg * 0.5806 m/s² * 1.0153 m
= 391.55 J
Now, to find the average power (P), we divide the work done by the time taken:
P = W / t
= 391.55 J / 3.10 s
= 126.36 W
To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.
Therefore, the average power of the elevator motor during this period is:
P = 126.36 W / 745.7
= 0.1696 hp
(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.
The force of gravity (Fg) can be calculated using:
Fg = m * g
= 682 kg * 9.8 m/s²
= 6683.6 N
The power (P) required is given by the formula:
P = Fg * v
= 6683.6 N * 1.80 m/s
= 12030.5 W
To convert the power to horsepower:
P = 12030.5 W / 745.7
= 16.13 hp
Therefore, the power during an upward trip with constant speed is 16.13 horsepower.
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what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2
The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)
Pressure (P) = Density (ρ) × g × Depth (h)
Given: Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Depth (h) = 6 m
Using the given values, one can calculate the pressure:
Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure
= 58800 kg·m⁻¹·s⁻²
Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:
Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)
Pressure = 580.124 atm
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