A mass attached to the end of a spring is set in motion, the mass is observed to oscillate up and down, completing 24 complete cycles every 6. 00 s, the period of the oscillation: 0.25 seconds.
The mass attached to the end of a spring completes 24 cycles in 6.00 seconds. To determine the period of the oscillation, we need to find the time taken for one complete cycle. The period (T) is calculated by dividing the total time by the number of cycles, which is:
T = total time / number of cycles = 6.00 s / 24 cycles = 0.25 s per cycle.
The period of the oscillation is 0.25 seconds.
Now, to find the frequency of the oscillation, we need to determine the number of cycles that occur in one second. The frequency (f) is the inverse of the period:
f = 1 / T = 1 / 0.25 s = 4 cycles per second (Hz).
The frequency of the oscillation is 4 Hz.
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A rock climber is about to haul up 100 N (about 22.5 pounds)
A rock climber is about to haul up 100 N (about 22.5 pounds) of equipment that has been hanging beneath her on 40 meters of rope that weighs 0.8 newtons per meter. How much work will it take?
8000 Joules is the amount of work required to haul up the equipment.
Work to haul equipment?To calculate the work required to haul up the equipment, we need to consider two components: the work done against gravity and the work done against the weight of the rope.
Work against gravity:The force due to gravity is given by the weight of the equipment, which is 100 N. The distance over which the force is applied is the height the equipment is being hauled, which is 40 meters. The work done against gravity can be calculated using the formula:
Work = Force × Distance
Work against gravity = 100 N × 40 m = 4000 N·m or 4000 J (Joules)
Work against the weight of the rope:The weight of the rope can be calculated by multiplying the weight per meter (0.8 N/m) by the length of the rope (40 m):
Weight of the rope = 0.8 N/m × 40 m = 32 N
Since the rope is being hauled up, the work done against the weight of the rope is the same as the work done against gravity. Therefore, the work against the weight of the rope is also 4000 J.
The total work required to haul up the equipment is the sum of the work against gravity and the work against the weight of the rope:
Total work = Work against gravity + Work against rope weight
Total work = 4000 J + 4000 J
Total work = 8000 J
Therefore, it will take 8000 Joules of work to haul up the equipme
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10) Which would be the most appropriate description of how energy is distributed when a torch is turned on?
A 70% light energy, 30% thermal energy
B 70% thermal energy, 30% electrical energy
C 65% light energy, 30% thermal energy
D 40% thermal energy, 55% light energy
Your friend is a new driver in your car practicing in an empty parking lot. She is driving clockwise in a large circle at a constan speed. Is the car traveling with a constant velocity or is it accelerating?: Since the car is changing direction as it travels around the circle, it has a centripetal acceleration and does not have a constant velocity. The car has a constant speed, so the velocity is constant and there is no acceleration.
Centripetal acceleration, which points towards the center of the circle, is responsible for this change in direction. Thus, while the car is traveling at a constant speed, it is still accelerating since the direction of its velocity is constantly changing.
The car has a centripetal acceleration and does not have a constant velocity. Although the car is traveling with a constant speed, it is still accelerating.What is acceleration?Acceleration refers to the rate of change of velocity. Acceleration may be either positive or negative. When an object speeds up, it has positive acceleration.
When an object slows down, it has negative acceleration, which is also known as deceleration. When an object changes direction, it experiences acceleration.A car driving in a circle at a constant speed is an example of uniform circular motion.
The car's direction is constantly changing since it is moving in a circular path. As a result, the car's velocity is constantly changing even if its speed is constant.
Centripetal acceleration, which points towards the center of the circle, is responsible for this change in direction.
Thus, while the car is traveling at a constant speed, it is still accelerating since the direction of its velocity is constantly changing.
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A long wire carries a long wire carries a current toward the east in a magnetic field that is directed due south. What is the direction of the magnetic force on the wire? a) west b) north c) east d) vertically upward e) vertically downward
When a long wire carries a current towards the east in a magnetic field that is directed due south, the direction of the magnetic force on the wire is vertically downward.
The force exerted by a magnetic field on a moving charged particle is described by the Lorentz force equation. The direction of the magnetic force F on a moving charged particle with charge q is given by F = qv x B, where v is the velocity of the particle and B is the magnetic field vector.
The direction of the magnetic force is perpendicular to both the velocity of the particle and the direction of the magnetic field.
If the current in the wire is towards the east and the magnetic field is directed towards the south, then the magnetic force on the wire will be perpendicular to both these directions, which is vertically downward.
Therefore, the correct option is e) vertically downward.
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To what subnet does the ip address 10.1.100.50 belong if a subnet mask of 255.255.0.0 is used?
The IP address 10.1.100.50 belongs to the subnet 10.1.0.0 when a subnet mask of 255.255.0.0 is used.
When the subnet mask 255.255.0.0 is applied, it indicates that the first two octets (10.1) are the network address, and the last two octets (100.50) are available for host addresses within that network. This subnet mask allows for a larger number of host addresses compared to a subnet mask with a higher number of network bits.
By matching the network portion of the IP address with the network address derived from the subnet mask, we can determine the subnet to which the IP address belongs. In this case, the subnet is 10.1.0.0.
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Bx = -1.33 m and By = 2.81 m
Find the magnitude of the
vector.
Answer:
Explanation:
The formula for the magnitude of a vector is
\(B_{mag}=\sqrt{(-1.33)^2+(2.81)^2}\) and then round to the hundredths place:
3.11 m. Since we are in Q2, we can also find the direction of this vector:
\(tan^{-1}(\frac{2.81}{-1.33})=-64.7\) but since we are in Q2, we add 180 degrees to the result, getting the angle to be 115.3
Answer:115.33
Explanation:
How do you determine the effect of initial speed on the horizontal distance traveled by a projectile?
x(t)=voₓ.t = vo cos α.t
the greater the initial speed, the further the distance obtained
The horizontal distance traveled by a projectile (also known as the range of the projectile) is determined by the initial speed of the projectile, as well as other factors such as the angle at which it is launched and the gravitational acceleration acting on it.
What is a projectile?A projectile is an object that is projected into the air and follows a parabolic path under the influence of gravity. Examples of projectiles include balls thrown or kicked in sports, bullets fired from guns, and rocks or other objects that are thrown or dropped.
To determine the effect of the initial speed on the horizontal distance traveled by a projectile, you can use the following formula:
\(Range = (Initial speed)^2 * sin(2 * Launch angle) / gravitational acceleration\)
This formula shows that the range of a projectile is directly proportional to the initial speed of the projectile squared, and is also affected by the launch angle and gravitational acceleration.
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What is environment
Answer:
environment is the situation of the place
Explanation:
i think helping you... have a great day:)
Examine the Porter's 5 forces and explain how the forces are interconnected? Use examples to explain your answers. No less than 100 words
Porter's Five Forces is a framework used to analyze the competitive intensity and attractiveness of an industry. The five forces are: Threat of New Entrants, Bargaining Power of Suppliers, Bargaining Power of Buyers, Threat of Substitute Products or Services and Intensity of Competitive Rivalry.
Threat of New Entrants: This force considers the ease or difficulty for new competitors to enter an industry. It includes barriers to entry such as high capital requirements, economies of scale, brand loyalty, and government regulations.
Example: The airline industry is known for its high barriers to entry due to the significant capital required to purchase aircraft, establish routes, and secure necessary licenses and permits. Additionally, established airlines often have loyal customer bases and strong brand recognition, making it challenging for new entrants to compete effectively.
Bargaining Power of Suppliers: This force assesses the power suppliers have over the industry in terms of pricing, quality, and availability of inputs. It considers factors such as the concentration of suppliers, uniqueness of their products, and their ability to forward integrate.
Example: In the smartphone industry, major suppliers of components like microchips and display screens hold significant bargaining power. These suppliers provide essential inputs, and their products may have limited alternatives or require specialized manufacturing processes. As a result, smartphone manufacturers must negotiate favorable terms with these suppliers to ensure a reliable supply chain and competitive pricing.
Bargaining Power of Buyers: This force examines the power customers have in influencing prices, demanding better quality or service, and potentially switching to alternative products or suppliers. It considers factors such as buyer concentration, product differentiation, and switching costs.
Example: The retail industry experiences strong buyer power, particularly in highly competitive markets. Customers have access to various options, and their ability to compare prices and products easily through online platforms empowers them to demand competitive pricing, promotions, and high-quality products and services.
Threat of Substitute Products or Services: This force looks at the availability of alternative products or services that can satisfy customer needs. It considers factors such as price-performance trade-offs, switching costs, and customer loyalty.
Example: The rise of streaming services such as Netflix, Amazon Prime Video, and Hulu posed a significant threat to traditional cable and satellite TV providers. These streaming platforms offer a wide range of content at competitive prices, allowing customers to switch from traditional TV services to streaming options, resulting in a decline in subscriber numbers for traditional providers.
Intensity of Competitive Rivalry: This force evaluates the level of competition among existing firms in the industry. It considers factors such as the number and size of competitors, industry growth rate, product differentiation, and exit barriers.
Example: The soft drink industry, dominated by major players like Coca-Cola and PepsiCo, experiences intense competitive rivalry. These companies fiercely compete for market share through advertising campaigns, new product launches, pricing strategies, and distribution channels. The rivalry is further intensified by the high market saturation and the limited scope for differentiation among similar products.
The interconnection of these forces lies in their collective influence on the competitive dynamics and profitability of an industry. Changes in one force can trigger a chain reaction that impacts the others. For instance, a high threat of new entrants may lead to increased competitive rivalry as existing firms strive to defend their market share. Similarly, a strong bargaining power of buyers can limit the pricing power of suppliers and impact their profitability. Understanding these interconnections helps businesses assess the overall attractiveness and competitive landscape of an industry and develop appropriate strategies to thrive within it.
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charges move through the circuit from one plate to the other until both plates areuncharged.
The movement of charges from one plate to the other in a capacitor is a fundamental process that underlies many electronic devices and applications.
When a capacitor is connected to a circuit, charges begin to flow from one plate to the other until both plates reach the same potential and the capacitor becomes fully charged.
This process involves the movement of electrons, which are negatively charged particles, from one plate to the other.
Initially, the capacitor is uncharged, and the plates have an equal number of positive and negative charges.
When a voltage is applied to the capacitor, electrons begin to flow from the negative plate to the positive plate, creating an electric field between the two plates. This electric field stores energy in the capacitor, which can be released later when the capacitor is discharged.
If the voltage across the capacitor is removed, the capacitor will retain its charge and will discharge slowly over time as the electrons flow back from the negative plate to the positive plate.
This discharge process can be used in various applications, such as in flash photography, where a capacitor is charged rapidly and then discharged quickly to produce a bright flash of light.
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How will the element Ca + O bond ?
Answer:
Ionic bonding
Explanation:
Since Ca is a metal and O is a nonmetal, they will experience ionic bonding. This means that Ca will "donate" two of its valence electrons to O. This will give both Ca and O a complete octet.
Answer:
CaO
Explanation:
Depending on the element "a" stands for, there is not enough info to conclude how these elements would bond. however, if they are typed out correctly then one possible bond would be CaO. I am assuming that the C and O represent Carbon and Oxygen.
The gasoline in a car engine provides 600,000
joules of heat every second. the car loses
450,000 joules of heat every second as waste
heat. calculate how much work the car does
every second and explain your answer.
To calculate the work done by the car engine every second, we need to use the first law of thermodynamics.
Which states that the total energy supplied to a system is equal to the sum of the work done by the system and the heat transferred into the system minus the heat transferred out of the system.
In this case, the energy supplied to the car engine every second is 600,000 joules, and the waste heat lost is 450,000 joules every second. Let's denote the work done by the car engine as W.
According to the first law of thermodynamics:
Energy supplied = Work done + Waste heat lost
600,000 joules = W + 450,000 joules
To solve for W, we subtract 450,000 joules from both sides:
600,000 joules - 450,000 joules = W + 450,000 joules - 450,000 joules
150,000 joules = W
Therefore, the work done by the car engine every second is 150,000 joules.
This means that out of the total energy supplied to the car engine every second (600,000 joules), 150,000 joules are converted into useful work to propel the car, while 450,000 joules are lost as waste heat.
The work represents the useful output of the engine, such as mechanical work to move the car forward, while the waste heat represents the energy that is not converted into useful work and is dissipated into the surroundings.
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A 0.48-kg ball is thrown with a speed of 8.8 m/s at an upward angle of 36 degrees.
(a) What is its speed at its highest point?
(b) How high does it go? (Use conversation of energy.)
Answer: (a) The velocity of the ball at its highest point is 10.12 m/s
(b) The height that the ball goes is 1.13 m.
Mass of ball, m = 0.48 kg
Initial velocity, u = 8.8 m/s
Initial angle, θ = 36°
Using the principle of conservation of energy, the final velocity at the highest point can be found. The potential energy of the ball is converted into kinetic energy at its highest point, where the ball will stop momentarily. Then, we know that the total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴
mgh + 1/2mu² = mgh(max) where h(max) is the maximum height the ball attains. At this point, the kinetic energy will be zero. Therefore,0.5mv² + mgh = mgh(max). Since the kinetic energy of the ball at the top is zero, the total energy at the top of the projectile’s trajectory is the potential energy at the start of the trajectory, which is mgh.∴ v = √(2gh).
This is the velocity at the maximum height.
(a) Speed at its highest point:
Initial velocity of ball, u = 8.8 m/s
Angle made with horizontal, θ = 36°
The vertical component of velocity, v_y = usinθv_y = 8.8 sin 36°v_y = 5.0 m/s
Now using the formula, v = √(u² + v_y²)v = √(8.8² + 5.0²)v = √(77.44 + 25)v = √102.44v = 10.12 m/s
Therefore, the velocity of the ball at its highest point is 10.12 m/s
(b) How high does it go: lets calculate the potential energy at the initial position. Potential energy, Ep = mgh
Ep = 0.48 * 9.8 * 0Ep = 0 J. The total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴ mgh + 1/2mu² = mgh(max). Substituting the values,0.48*9.8*h(max) + 0.5*0.48*8.8² = 0.48*9.8*0hmax = (0.5*0.48*8.8²)/(0.48*9.8)h(max) = 1.13 m.
Therefore, the height that the ball goes is 1.13 m.
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Coulombs law describes how the charge on and the distance between two particles affect the electric force between them . which situation will result in the two particles being rebelled by each other
According to Coulomb's law, the charge on a device and the distance between two. The electric force between particles is affected. The circumstance will cause two positively charged particles to repel one another; hence, option A is the best choice.
Coulomb's law states that the electrical force between two charged bodies is inversely proportional to the square of the separation distance between the two bodies and directly proportional to the product of the quantity of charge on the bodies.
The formula for Coulomb's law in mathematics is written as
F=kQ₁Q₂/r²
The electric force is F.
The Coulomb constant is k.
Charges Q1 and Q2 are involved.
The separation between the charges is measured in units of r.
The correct choice is A because, in line with Coulomb's rule, when two particles have a positive charge, the effect of force will be that they repel one another.
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An object of mass 0.9 kg is attached to a massless string of length 3 m, and swung with a tangential velocity of 3 m/s. What is the force exerted by the string on the object?
According to the given statement The force exerted by the string on the object is 2.7 N.
What does tangential velocity mean?Any item travelling in a circular direction has a tangential velocity, which is its linear speed. On a turntable, a point in the centre moves less distance in a full rotation than a point near the outside edge.
How do you calculate tangential velocity?Tangential velocity is determined by dividing the circle's circumference by the time required for one complete rotation: 2*pi*r/t. The formula V = w * r, where w (omega) is the angular velocity of the rotating object and r is the radius of the circle, also relates it to angular velocity.
Briefing:m = 0.9 kg
r = 3m
v = 3m/s
Force (f) = mv2/r
Now ,putting values
force (f) = \(\frac{0.9 k g \times\left(3 \mathrm{~ms}^{-1}\right)^2}{3 \mathrm{~m}}\)
F = 2.7 N
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what is the wavelength of the electromagnetic wave produced by your cell phone, if the frequency of that wave is 2700 mhz ?
The wavelength of the electromagnetic wave produced by your cell phone is approximately 11.1 centimeters, calculated using the formula wavelength = speed of light / frequency. The speed of light is approximately 3 x 10^8 meters per second.
Hi! To calculate the wavelength of the electromagnetic wave produced by your cell phone, you can use the formula:
Wavelength (λ) = Speed of light (c) / Frequency (f)
Given the frequency of the wave is 2700 MHz, first convert it to Hz:
2700 MHz * 1,000,000 = 2,700,000,000 Hz
Now, use the speed of light, which is approximately 3 * 10^8 meters per second:
Wavelength (λ) = (3 * 10^8 m/s) / (2,700,000,000 Hz)
Wavelength (λ) ≈ 0.111 meters
So, the wavelength of the electromagnetic wave produced by your cell phone with a frequency of 2700 MHz is approximately 0.111 meters.
The wavelength of the electromagnetic wave produced by your cell phone, if the frequency of that wave is 2700 MHz, is 0.11 m
How do i determine the wavelength?The wavelength of the electromagnetic wave having a frequency of 2700 MHz can be obtained as follow:
Speed of electromagnetic wave (v) = 3×10⁸ m/sFrequency of electromagnetic wave (f) = 2700 MHz = 2700 × 10⁶ = 27×10⁸ HzWavelength of electromagnetic wave (λ) = ?Velocity (v) = wavelength (λ) × frequency (f)
3×10⁸ = wavelength × 27×10⁸
Divide both sides by 27×10⁸
Wavelength = 3×10⁸ / 27×10⁸
Wavelength = 0.11 m
Thus, we can conclude that the wavelength of the electromagnetic wave is 0.11 m
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I'm taking physics and trying to figure out the 4 questions to this problem.
Answer:
Explanation:
At t = 1 velocity = 0
At t = 3 velocity = 3
slope of the line = 3-0 / 3-1 = 3/2
At t = 2
velocity = 3/2 x ( 2 - 1 )
= 1.5 m /s
velocity at t = 2 is 1.5 m /s
Position at t = 2 :
displacement at t = 2
area of graph upto t = 2
= 1 / 2 x 1 x 1.5 = .75
position at t = 2 :
= initial position + displacement
= 10 + .75 = 10.75 m
position at 6 s :
displacement at t = 6
area of curve upto t = 6
= 1 / 2 x 2 x 3 + 3 x 3 + 1/2 x 3 x ( 4.5 - 3 )
= 3 + 9 + 2.25
= 14.25 m
position at t = 6
= initial position + displacement
= 10 + 14.25 = 24.25 m
position at 9 s :
displacement at t = 9
area of curve upto t = 9
= 1 / 2 x 2 x 3 + 4 x 3 + 1/2 x 4 x ( 5 - 3 )- 1/2 x 2 x 1.5
= 3 + 12 + 4 - 1.5
= 17.5 m
position at t = 9
= initial position + displacement
= 10 + 17.5 = 27.5 m
How much power is used by a 120 V circuit using 6 amps?
Answer:
P= 720 watt
Explanation:
P= IV
P= (6)(120)
P= 720 watt
What is the minimum stopping distance for the same car traveling at a speed of 36 m/s ?
The minimum stopping distance for the car traveling at a speed of 36 m/s is 117 meters.
The minimum stopping distance for a car can be calculated using the formula:
Stopping Distance = Thinking Distance + Braking Distance
The thinking distance is the distance the car travels while the driver reacts to a situation and applies the brakes. The braking distance is the distance the car travels while braking to a stop.
To calculate the thinking distance, we can use the formula: Thinking Distance = Speed x Reaction Time.
Given that the car is traveling at a speed of 36 m/s, we need to know the reaction time of the driver to calculate the thinking distance. Let's assume a typical reaction time of 1 second for this example.
Thinking Distance = 36 m/s x 1 s = 36 m
To calculate the braking distance, we need to use the formula: Braking Distance = (Speed 2) / (2 x Deceleration)
Deceleration is the rate at which the car slows down. Let's assume a deceleration of 8 m/s^2 for this example.
Braking Distance = (36 m/s) 2 / (2 x 8 m/s 2) = 81 m
Therefore, the minimum stopping distance for the same car traveling at a speed of 36 m/s is the sum of the thinking distance and the braking distance:
Stopping Distance = 36 m + 81 m = 117 m
The minimum stopping distance for the car traveling at a speed of 36 m/s is 117 meters.
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3. A skydiver started his jump from the airplane. He fell 4.9 m in the 1st second, 14.7 m
in the 2nd second, 24,5 m in the 3rd second. How far did he fall between the 7th and the
10th seconds?
Arithmetic or geometric
The distance between the 7th and the tenth second is 29.4 m.
What is the progression?We know that we can have to formulate the information that has been given here so as to obtain a proper progression and this would help us to get the common difference of the progression that we are looking at.
Now we know that the progression would look something like; 4.9, 14.7, 24.5 ....
We can see that this is an arithmetic progression that has a common difference of 9.8.
U7 = a + (n - 1)d
a = first term
n = Number of terms
d = common difference
U7 = 4.9 + (7 - 1) 9.8
= 63.7
U10 = 4.9 + (10 - 1) 9.8
U10 = 93.1
Between the 7th and 10th seconds, we have;
93.1 - 63.7
= 29.4 m
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a line perpendicular to the boundary between two media a line parallel to the boundary between two media a vertical line separating two media
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Please write in complete sentences.
How does density affect refraction?
Diamonds are a very dense material. Predict what would happen to the light ray if you projected it from the air through a diamond.
Answer:
The density of a material affects the speed that a wave will be transmitted through it. In general, the denser the transparent material, the more slowly light travels through it.
Glycerin flows through a tube that expands from a 1.00 cmcross-section area at point 1 to a 4.00 cm² cross-section area farther downstream at point 2. The pressure difference between points 1 and 2 is 9.45 kPa.
Part A
What is the speed of the glycerin at point 1? Assume that the glycerin flows as an ideal fluid.
Express your answer with the appropriate units.
Part B
What is the speed of the glycerin at point 2? Assume that the glycerin flows as an ideal fluid.
Express your answer with the appropriate units.
To solve this problem, we can use the continuity equation, which states that the mass flow rate (the rate at which mass flows through a point in a system) must be constant throughout the system. In other words, the mass flow rate at point 1 must equal the mass flow rate at point 2.
The mass flow rate is equal to the density of the fluid times the flow rate (also known as the volume flow rate). The flow rate is equal to the cross sectional area of the tube times the velocity of the fluid. Therefore, we can write the continuity equation as:
\(density $*($ cross-sectional area $*$ velocity $)=$ constant\)
We can rearrange this equation to solve for the velocity at each point: \(velocity $=$ constant $($ density $*$ cross $-$ sectionalarea $)$\)
At point 1 , the velocity can be calculated as follows: $V 1=$ constant $/($ \(density $*$ A1 $)=$ constant $/\left(\right.$ density $\left.* 1.00 \mathrm{~cm}^{\wedge} 2\right)$\)
At point 2 , the velocity can be calculated as follows: \($\mathrm{V} 2=$ constant $/($ density $*$ A 2$)=$ constant $/\left(\right.$ density $\left.* 4.00 \mathrm{~cm}^{\wedge} 2\right)$\)
We can find the value of the constant by using the pressure difference between the two points and the ideal gas law:
\(P $1-\mathrm{P} 2=\left(\right.$ density $*$ velocity $\left.{ }^{\wedge} 2\right) / 2$\)
Substituting the known values, we have:
\(9.45 \mathrm{kPa}=\left(\text { density }{ }^* \mathrm{~V} 1^{\wedge} 2\right) / 2\)
Solving for , we find that the velocity at point 1 is:
V1 = sqrt(2 * 9.45 kPa / density)
Similarly, we can solve for V2:
V2 = sqrt(2 * 9.45 kPa / density) / 2 = V1 / 2
Note that the density of glycerin is not given, so we cannot calculate the exact values of V1 and V2. However, we can still determine the relationships between the velocities at the two points. Specifically, we can see that the velocity at point 2 is half the velocity at point 1.
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A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes the conservation of energy in position A?
\(E=\frac{1}{2} mv^{2} \\E=mgh\\E=\frac{1}{2} kx^{2} \\E=\frac{1}{2} k2kx^{2}\)
Answer:
Explanation:
The energy conservation is equal to half of the product of the spring constant and the square of displacement of the spring, so option C is correct.
a ray of light ( f = 5 * 10 to power -1 ) travelling in air strikes a block of sodium chloride at an angle of 30. what is the angle of refraction for the light ray in the sodium chloride?
1) 19
2) 25
3) 40
4) 49
Answer:
The correct answer is 1) 19.
a 0.25-kg rock just balances a uniform meter stick when the pivot or balance point is at the 25 centimeter mark as shown. what is the mass (in kg) of the meter stick?
To solve this problem, we can use the principle of moments or torques.
The principle of moments states that for an object to be in equilibrium, the sum of the clockwise moments must be equal to the sum of the counterclockwise moments about any chosen pivot point.
In this case, we have a rock of mass 0.25 kg at the 25 centimeter mark and a meter stick. The meter stick can be considered as a uniform rod with its mass distributed along its length. Let's assume the mass of the meter stick is M kg.
Since the rock balances the meter stick, the clockwise moment caused by the rock is equal to the counterclockwise moment caused by the meter stick.
Clockwise Moment (caused by the rock) = Counterclockwise Moment (caused by the meter stick)
To calculate the moments, we need to consider both the mass and the distance from the pivot point.
The clockwise moment caused by the rock is given by: 0.25 kg * g * (0.25 m)
The counterclockwise moment caused by the meter stick is given by: M kg * g * (0.75 m)
Setting these two moments equal to each other:
0.25 kg * g * (0.25 m) = M kg * g * (0.75 m)
Simplifying the equation:
0.25 kg * (0.25 m) = M kg * (0.75 m)
0.0625 kg m = 0.75 M kg m
Dividing both sides by 0.75 m:
0.0625 kg = M kg
Therefore, the mass of the meter stick is 0.0625 kg or 62.5 grams.
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Sound energy travels through matter in waves. Do sound waves travel
faster through air or water? Explain your answer.
Answer:
So I think that the sound waves travel faster through water than air.
Explanation:
And the explanation would be that sound travels faster in more denser substances like water.
icon review. a small object of mass carries a charge and is suspended by a thread between the vertical plates of a parallel-plate capacitor. the plate separation is . if the thread makes an angle with the vertical, what is the potential difference between the plates?
The potential difference between the plates of a parallel-plate capacitor is determined by the plate separation, the charge of the object, and the angle of the thread. In this case, the potential difference (V) can be calculated as follows:
V = (Q * g* cosθ) / (2 * εo * d)
Where Q is the charge of the object, g is the acceleration due to gravity, θ is the angle of the thread, εo is the permittivity of free space, and d is the plate separation.
The electric field between the plates of a parallel-plate capacitor is determined by the potential difference between the two plates. This electric field (E) is calculated using the formula:
E = V/d
Where V is the potential difference between the two plates and d is the plate separation.
The capacitance of a parallel-plate capacitor is determined by the plate separation, the permittivity of free space, and the area of the plates. The capacitance (C) is calculated using the formula:
C = εo * A/d
Where εo is the permittivity of free space, A is the area of the plates, and d is the plate separation.
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43. What is precipitation hardening? 44. Diffusion is driven by two things, what are they? 45. Diffusion processes can be in two states, what are they? 46. Which Laws pertain to each type of Diffusion
43. Precipitation hardening is a heat treatment technique used to strengthen certain alloys by creating a fine dispersion of precipitates within the material, increasing its strength and hardness.
44. Diffusion is driven by two things: concentration gradient (difference in concentration) and temperature gradient (difference in temperature).
45. Diffusion processes can be in two states: Fickian diffusion and Non-Fickian diffusion.
46. Fick's first law and Fick's second law pertain to Fickian diffusion, which is the diffusion process governed by concentration gradients and follows Fick's laws.
Heat is a form of energy that is transferred between objects or systems due to temperature difference. It flows from hotter regions to colder regions until thermal equilibrium is reached. Heat can be transferred through conduction, or radiation. It is measured in units of joules (J) or calories (cal) and plays crucial role in thermodynamics and understanding thermal processes.
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Describe the importance that keystone species have in the environment. What would happen if these species disappeared? How would it affect the local ecosystems?
Answer:
See the answer below
Explanation:
The keystone species of an environment are those species of organisms that are highly influential to the functioning of the ecosystem without whom the ecosystem would be drastically affected, lose its structure, or cease to exist totally.
The influence of keystone species in an environment is disproportionately high when compared to their population in the environment. If keystone species disappeared from an environment, such an environment will find it difficult to perform ecosystem functions with an entirely different structure. In some cases, the ecosystem might cease to exist in its entirety because the species that hold it together are no longer present.