Answers
Answer:
1.98 m/s
Explanation:
To solve this, we would be using the law of conservation of energy, i.e total initial energy is equal to total final energy.
E(i) = E(f)
mgh = ½Iw² + ½mv²
Recall, v = wr, thus, w = v/r
Also, I = ½mr²
I = 0.5 * 5 * 2²
I = 10 kgm²
Remember,
mgh = ½Iw² + ½mv²
Substituting w for v/r, we have
mgh = ½I(v/r)² + ½mv²
Now, putting the values in the equation, we have
5 * 9.8 * 0.3 = ½ * 10 * (v/2)² + ½ * 5 * v²
14.7 = 1.25 v² + 2.5 v²
14.7 = 3.75 v²
v² = 14.7/3.75
v² = 3.92
v = √3.92
v = 1.98 m/s
Thus, the speed is 1.98 m/s
Related Questions
A driver notices that her 1380-kg car, when in neutral, slows down from 95 km/h to 65 km/h in about 7.0 s on a flat horizontal road. Approximately what power (watts) is needed to keep the car traveling at a constant 80 km/h? Approximately what power (hp) is needed to keep the car traveling at a constant 80 km/h?
Answers
.The power of the car is 12.8 watt or 0.017 hp.
Work done per unit time is power of a machine. It is a scalar quantity. Its S.I. unit is watt(w). Energy change is equal to power.
1 hp is equal to 746 w.
The given is,
mass of car = 1380 kg
Initial velocity V1 = 65km/s
Final velocity V2 = 80 km/s
Time t = 7 s
change in kinetic energy = 1/2m ( -v12 = 1/2 ×(80-65) J
= 1/2×180
= 90 J
This is equal to work done.
Now. power = W/t
90/7 = 12.8 w
So the power is 12.8 w = 12.8/ 746 w
0.017 hp.
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A uniform narrow tube 1.90 m long is open at both ends. It resonates at two successive harmonics of frequencies 280 Hz and 294 Hz.(a) What is the fundamental frequency?_____Hz(b) What is the speed of sound in the gas in the tube?________ m/s
Answers
Answer:
a)14Hz
b)26.6m/s
Explanation:
a)we were given
the first harmonics frequencies as 280 Hz
The second harmonic frequency as 294 Hz.
The fundamental frequency is equal to the gap which means the distance that exist between the harmonics, then
the fundamental frequency=(294 - 280 = 10 Hz)
= 14Hz
b) We know the frequency and the wavelength of the sound wave (
We were told that the wavelength must be twice the length of the tube then, velocity can be calculated as
And fundamental frequency= 14Hz, and distance of 1.90 m then
v = f*2L = (14Hz)*2*(1.90 m) = 26.6m/s
Therefore, the speed of sound in the gas in the tubes is 26.6m/s
The efficiency of combine double pulley is 60% How much load is lifted usin SON effort I
Answers
The load lifted by the double pulley with the given efficiency and applied effort is determined as 30 N.
What is the amount of load lifted?The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;
E = L / E x 100%
where;
L is the load overcome or output workE is the effort applied or the input workThe amount of load lifted by the pulley is calculated as;
60 = L / 50 x 100%
60 = 100L / 50
100L = 50 x 60
100 L = 3000
L = 3000 / 100
L = 30 N
Thus, the amount of load lifted by the pulley is 30 N.
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The complete question is below:
the efficiency of combine double pulley is 60%. how much load is lifted using 50n effort?
Based on your average reaction time, how much time would it take to react to a traffic situation and stop a car traveling at 60 mph (1 mph equals 0.45 m/s) if you could decelerate the car at a rate of -3.4m/s2?
What distance would you travel (in meters) as the car came to a stop in the above situation?
Avg Reaction time: 0.218 ms
Answers
Answer:
d = 106.41 m
Explanation:
Given that,
Initial speed of the car, u = 60 mph = 26.9 m/s
The deceleration in the car, a = -3.4 m/s²
The average reaction time, t = 0.218 m/s
It finally stops, final velocity, v = 0
We need to find the distance covered by the car as it come to a stop.
Using third equation of motion to find.
\(v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-26.9^2}{2\times (-3.4)}\\\\d=106.41 m\)
So, the car will cover 106.41 m as it comes to a stop.
Goal posts at the ends of football fields are padded as a
safety measure for players who might run into them. How
does thick padding around the goal post reduce injuries
to players?
It would be awesome if you could use a sample response
Answers
Goal posts at the end of football field are padded as a safety measure to players who might run into them,these thick paddings of the goal posts are done to prevent injuries to the players because the padding of the goal post increases the time of impact and this in-turn decreases the force on the the players body or the force it will have when a player's body hit against it and therefore decreasing the force applied to bring the player to a stop.
We can also say that it increases the time of collision between the player's body and the post.
a mechanic uses a hydraulic lift to raise a 1,200 kg car 0.50 m off the ground . how much work does the lift do on the car
Answers
Answer:
The work done is 5880 J
Explanation:
Recall the formula for work as force times distance, therefore in this case the force is that oppose to the gravitational force on the car(of magnitude m * g), and the distance is 0.5 meters.
Then:
Work = 1200 * 9.8 * 0.5 J = 5880 J
A 2.5 kg block is initially at rest on a horizontal surface.A horizontal force of magnitude 6.0 N and a vertical force are
then applied to the block (Fig. 6-17).The coefficients of friction for
the block and surface are ms " 0.40 and mk " 0.25. Determine the
magnitude of the frictional force acting on the block if the magnitude
of is (a) 8.0 N, (b) 10 N, and (c) 12 N.
Answers
To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.
First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:
W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N
Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:
Fv = is sinθ
where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.
(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:
Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N
(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:
Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N
(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:
Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N
Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.
(a) When the horizontal force is 8 N the frictional force is 11.8 N.
(b) when the applied force is 10 N; the frictional force is 13.8 N.
(c) when the applied force is 12 N; the frictional force is 15.8 N.
What is the magnitude of the frictional force acting on the block?(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;
F - Ff = ma
where;
F is the horizontal force appliedFf is the frictional forcem is the massa is the accelerationF - μmg = ma
6 - 0.4 x 2.5 x 9.8 = 2.5 a
2.5 a = -3.8
a = -3.8/2.5
a = -1.52 m/s²
when the applied force is 8 N;
8 N - Ff = -1.52 m/s² x 2.5 kg
Ff = 11.8 N
(b) when the applied force is 10 N;
10 N - Ff = -1.52 m/s² x 2.5 kg
Ff = 13.8 N
(c) when the applied force is 12 N;
12 N - Ff = -1.52 m/s² x 2.5 kg
Ff = 15.8 N
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how many taste buds do humans have 100,000, 100, 10,000 1,000
Answers
The approximate number of taste buds that humans have is 10,000 (option C).
What are taste buds?Tastebuds are any of the small organs on the tongue used for tasting.
Taste buds are cells on the tongue that allow one to perceive tastes, including sweet, salty, sour, bitter and umami.
Taste buds regenerate approximately every 10 days, which means injured taste buds usually repair on their own. The average adult human has between 2000 and 8000 tastebuds.
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A new company is making security cameras. These security cameras will be different than other security cameras because instead of detecting motion, they will detect body heat.
What type of electromagnetic wave will the camera detect?
A
gamma ray
B
infrared
C
microwave
D
radio wave
Answers
Answer:
b
Explanation:
energy transferred from one thing to another when the gulf balls collide?
Answers
This is based on the principle of conservation of energy and momentum.
When the collision of golf balls takes place the energy gets transferred from one ball to the other.
The golf balls experience a force that causes them to change their form and also direction. During the collision, the mechanical energy is converted into heat, sound, and other forms of energy. The rest of energy is used to move in a new direction.
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A spectral line is emitted when an atom undergoes transition between two levels with a difference in energy of 2.4eV. What is the wavelength of the line?
Answers
Given:
The energy difference, E=2.4 eV
To find:
The wavelength of the emitted line.
Explanation:
The energy of the wave emitted will be equal to the energy difference between the two energy levels.
The energy of the wave is given by the equation,
\(E=\frac{hc}{\lambda}\)Where h is the Plank's constant and c is the speed of light.
The energy in joules is given by,
\(\begin{gathered} E=2.4\times1.6\times10^{-19} \\ =3.84\times10^{-19}\text{ J} \end{gathered}\)On substituting the known values in the equation of the energy,
\(\begin{gathered} 3.84\times10^{-19}=\frac{6.626\times10^{-34}\times3\times10^8}{\lambda} \\ \implies\lambda=\frac{6.626\times10^{-34}\times3\times10^8}{3.84\times10^{-19}} \\ =517.7\times10^{-9}\text{ m} \\ =517.7\text{ nm} \end{gathered}\)Final answer:
Thus the wavelength of the line is 517.7 nm
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answers
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
measurement is essential in our life.justify the statement.
Answers
Answer:
Measurements allow people to find their way to new places. Measurements such as miles or kilometers are used by GPS systems to give directions. Time measurements help to create schedules so tasks get done on time. Measurements are used in food as well. Ingredients in recipes have to be measured to make the dish correctly. Serving sizes are a measurement that keep people healthy by showing how much of each food you should eat.
A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2
Answers
As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.
Identify the body's starting velocity:
We may use the equation of motion to get the body's initial velocity (u)
\(v^2 = u^2 + 2as\)
\(0 = u^2 + 2(-9.8)m/s^2 * h\)
\(u^2 = 19.6h\)
u = √(19.6h)
Determine the coefficient of restitution (e):The body's initial velocity (u) and initial relative velocity (u_rel) are the same.
The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).
\(e = v_{rel }/ u_{rel}\)
e = 0 / u_rel = 0 / u
Now, one can investigate the forces affecting the body: When a body is on an inclined plane.
There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).
The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).
Determine the conditions for the body to stop:
μ * N = m * g * sin(45°)
μ * (m * g * cos(45°)) = m * g * sin(45°)
μ * cos(45°) = sin(45°)
(1/2) * cos(45°) = sin(45°)
Simplifying further, we have:
√2 / 4 = √2 / 2
Thus, the body will come to rest following the collision if the equation is valid.
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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin
Answers
The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.
1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).
2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.
3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.
4. However, the given equation does not explicitly mention resistance.
5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).
6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.
7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).
8. Therefore, V = VR + VL.
9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.
10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.
The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.
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3
What is true of tectonic plates?
А
They are constantly moving
B
Earthquakes cause them to move
C
They don't move for centuries at a time
D
There are fewer and fewer of them
Answers
A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 8.33 mmHg. Density of mercury is 13.6 g/cm3.A .By how much does the fluid level rise in the side of the manometer that is open to the atmosphere? (cm)B. By how much does the fluid level rise in the side of the manometer that is open to the atmosphere if the manometer used mercury instead? (cm)
Answers
ANSWER:
(a) 6.3 cm
(b) 0.42 cm
STEP-BY-STEP EXPLANATION:
Given:
Density of oil = 0.9 g/cm^3
Density of mercury = 13.6 g/cm^3
Rise in the height of the mercury = 8.33 mm of Hg = 0.833 cm of Hg
(a)
The change in pressure is:
\(\Delta P=\rho\cdot g\cdot\Delta h\)The change in pressure when oil is used is:
\(\Delta P=\rho_{\text{oil}}\cdot g\cdot d\)Equating the above two equation
\(\begin{gathered} \rho\cdot g\cdot\Delta h=\rho_{\text{oil}}\cdot g\cdot d \\ \text{ solving for d:} \\ d=\frac{\rho\cdot\Delta h}{\rho_{\text{oil}}} \\ d=\frac{13.6\cdot0.833}{0.9} \\ d=12.59\text{ cm} \end{gathered}\)The amount of fluid rise is half the difference of level, so the height of rise in the oil
\(\begin{gathered} \Delta h_{oil}=\frac{d}{2} \\ \text{ replacing} \\ \Delta h_{oil}=\frac{12.59}{2}=6.295\cong6.3 \\ \Delta h_{oil}=6.3\text{ cm} \end{gathered}\)(b) If the manometer uses mercury then
\(\begin{gathered} \Delta h^{\prime}=\Delta h_{oil}\cdot\mleft(\frac{\rho_{oil}}{\rho}\mright) \\ \text{ replacing:} \\ \Delta h^{\prime}=6.3\cdot\mleft(\frac{0.9}{13.6}\mright) \\ \Delta h^{\prime}=0.42\text{ cm} \end{gathered}\)describe the motion of the fireball in the air
Answers
Explanation:
doesn't get the question and the answer to
Answer:
(this is the sample answer:After the launch, the fireball moves upward, than it falls back down to EarthEartEarthEarthEarthEarth
Explanation:
compute the position and the focal lenght of a converging lens of which will profuce the image of a lamp magnified 4 times on a screen 10cm from the lamp
Answers
V=-4v
-5u=10
U=-2
V =8cm
1/f=1/8+1/2=1+4/8=5/8
F=8/5 M=1.6
Answer f= 1.6m
Phoebe wants to measure the volume of a small, irregularly
shaped rock. Which of the following instruments would be best
for Phoebe to use?
Answers
Answer:
A graduated cylinder
Explanation:
Car P travels due East along a straight highway at a constant speed of 30 m/s. At 9:00
a.m., P passes Exit 17. At precisely the same moment, car Q passes Exit 16, traveling due
West at a constant 26 m/s. Slightly later, car P and car Q pass the same point. Knowing
the exits are exactly 7 km apart, determine how many minutes past 9:00 a.m. the cars pass
each other.
Answers
Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.
How to calculate time?The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.
The distance between the cars is 7 km = 7000 m.
The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.
1750 seconds is 29 minutes and 15 seconds.
To calculate the time in minutes;
Let:
v_p = the speed of car P (m/s)
v_q = the speed of car Q (m/s)
d = the distance between the cars (m)
t = the time it takes for the cars to pass each other (s)
Given that:
v_p = 30 m/s
v_q = 26 m/s
d = 7000 m
Use the equation for relative velocity to find the velocity of the cars relative to each other:
v_r = v_p - v_q
v_r = 30 m/s - 26 m/s = 4 m/s
Use the equation for distance to find the time it takes for the cars to pass each other:
d = v_r × t
7000 m = 4 m/s × t
t = 7000 m / 4 m/s = 1750 s
Convert 1750 seconds to minutes and seconds:
1750 s = 29 minutes and 15 seconds
Therefore, the cars pass each other at 9:29 and 15 seconds a.m.
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a block of mass m is at rest on the table .is it possible for this block at rest to have only a single force acting on it
Answers
Answer:
In short no , there is always minimum 2 forces.
Explanation:
First force: Weight force ( The force of gravity on the object attracting the block of masse m to earth)
Second force: Normal reaction ( This force is perpendicular to the surface )
Answer:
no
Explanation:
if only single force acts on the block it will stay at rest and it will accelarate in direction of force
Q10. Explain the Retention time, in GC. What will happen to retention time, if you increase the detector temperature
Answers
Answer:
The detector temperature doesn't affect retention time
Explanation:
Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.
A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.
The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.
In hiking, what fitness component is required of you
Answers
Identify the Action and Reaction Forces
Answers
A pair of forces that will always move in conflict with one another is referred to as an action-reaction force.
What is newton's third law?The third law of Newton asserts because when bodies interact, they exert forces that are equal in size and directed in the reverse way. Another name for the newton's third is the law of action and reaction. This equation is crucial for understanding issues with static balance, in which all forces are all in balance, but it also holds true for bodies moving at a steady or accelerated speed.
Hammer hitting a nail : In this, the hitting by the hammer is the action and the nail is going into the surface is the reaction force.
Book placed on the table : In this book is applying gravitational force that is action force and the reaction force is applied by the table.
Hitting a tennis ball : In this, hitting the ball is the action and the ball is going in the direction of hitting is the reaction force.
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What is the net force?
60N left
4ON, right
60N, right
0N
Answers
Answer:
60n left
Explanation:
Do
Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.
Answers
Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
How do we explain?In a mixed economy, economic decisions are made by both the government and consumers.
The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.
In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.
The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.
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ATTA-KAY PHYSICS 121 3. A ball A is left to roll down an inclined plane of inclination 30º. Just at the moment a second ball B is pushed up the plane with a velocity of 45ms¹. The balls met at a point where the velocity of B is 1.8 times the velocity of A. Calculate (a) the velocities of A and B when they meet. (b) when the two balls meet. (c) where the two ball meet. (g = 10 ms²)
Answers
vr>vs because the rolling ball acquires rotational as well as translational kinetic energy.
The accelerating force acting on the ball as it goes along a smooth plane is mgsin. Its acceleration is therefore equal to gsin. The mgsin acts down the plane as the ball travels down the rough inclined plane, but friction develops that acts up the plane.
Since both balls' potential energy is lost at the same rate, their KEs are actually equal at the base of the planes. However, a ball sliding down a smooth plane has only translational kinetic energy, but a ball rolling down a rough plane contains both translational and rotational kinetic energy at the bottom of the plane. As a result, the ball's translational KE will be lower than its translational Kinetic energy.
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10. Ahmad drives 60 km from his house to the petrol station in a car moving at a constant speed of
60 km/h. Then he moves the same distance to a shop at a constant speed of 120 km/h. The
average speed for the entire trip from his house to the shop is
Answers
Answer:
Explanation:
Average speed is distance traveled over time taken to do so
home to station
d = 60 km
t = 60 km/60 km/hr = 1 hr
station to shop
d = 60 km
t = 60 km / 120 km/hr = ½ hr
speed
s = (60 + 60) / (1 + ½) = 120/1.5 = 80 km/h
Use Eq. (9.20) to calculate the moment of inertia of a uniform, solid disk with mass M and radius R for an axis per- pendicular to the plane of the disk and passing through its center
Answers
Circular disc's moment of inertia around axis passing through mass and parallel to disc Icm=MR22
Explain about the moment of inertia?The phrase "moment of inertia" in physics refers to the precise calculation of a body's inertia with respect to rotation, or the resistance a body exhibits when a torque is applied to alter its rate of rotation around an axis (turning force).
It is a broad (additive) property: the moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.
Moment of inertia is the propensity of an object to continue rotating at a constant speed or in a condition of rest. More torque is needed to shift this state the higher the moment of inertia.
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