Answers
Answer:
\(h_p = 30.46\ m\)
Explanation:
Free Fall Motion
A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.
The speed vf of the object when a time t has passed is given by:
\(v_f=g\cdot t\)
Where \(g = 9.8 m/s^2\)
Similarly, the distance y the object has traveled is calculated as follows:
\(\displaystyle y=\frac{g\cdot t^2}{2}\)
If we know the height h from which the object was dropped, we can solve the above equation for t:
\(\displaystyle t=\sqrt{\frac{2\cdot y}{g}}\)
The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:
\(\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec\)
The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:
\(t_2=2.56 - 2 = 0.56\ sec\)
Therefore, it has traveled down a distance:
\(\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m\)
Thus, the height of the pen is:
\(h_p = 32 - 1.54\Rightarrow h_p=30.46\ m\)
The pen is 30.52 m above the ground.
Given that the height of the stadium is h = 32m
The initial velocity of the glasses will be 0.
\(h=\frac{1}{2}gt^{2} \\t=\sqrt{\frac{2h}{g} } \\t=\sqrt{\frac{2*32}{9.8} }\\t=2.55s\)is the time taken for the glasses to hit the ground.
Now the pen is released 2 seconds later. So by the time the glasses hit the ground the pen has spent:
\(t^{'}=2.55-2\\t^{'}=0.55s\)in the air
distance traveled by the pen:
\(d=\frac{1}{2}gt^{2}\\\\d=\frac{1}{2}*9.8*0.55*0.55\\\\d=1.48m\)
So the pen is \(h-d=32-1.48=30.52m\) above the ground.
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Related Questions
Which of these are NOT units for speed?
i. miles/hour
ii.
meters/second
iii.
minutes/kilometer
iv. inches/year
Answers
Answer:
iv
Explanation:
to be honest the others make since but the last 1 and all of the others are actually used.
-NULL
Brainliest will be appreciated thank you!
What does a barometer measure?
Answers
Answer:
Have a great day!
Explanation:
Barometers. A barometer is a scientific instrument used to measure atmospheric pressure, also called barometric pressure.
Answer:
atmospheric pressure
Explanation:
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
Answers
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
Answers
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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What are the similarities and differences between these data sets in terms of their centers and their variability?
Data Set A: 12, 15, 18, 18, 22, 29
Data Set B: 13, 17, 17, 19, 20, 34
Select from the drop-down menus to correctly complete the statements.
Comparing the centers of the data sets, the median for Data Set A is Choose...
Choose.
Set A is Choose... the mean for Data Set B.
less than
equal to
greater than
the median for Data Set B. The mean for Data
4
Answers
Comparing the variability of the data sets, the range for Data Set A is 17 (29-12) and the range for Data Set B is 21 (34-13), so the range for Data Set B is greater.
Furthermore, the mean for Data Set A is 19 and the mean for Data Set B is 19.83, so the mean for Data Set B is slightly greater than the mean for Data Set A.
If the period of oscillation of a simple pendulum is 4s, find it's length. If the velocity of the bob at the mean position is 40cm/s, find it's amplitude. (take gravity =9.81m/s²)
Answers
If the period of oscillation of a simple pendulum is 4s and the acceleration due to gravity is given at 9.81m/\(s^{2}\), Then the length of the pendulum is 3.975m.
What is a period of oscillation?
The period of an oscillation is given by the reciprocal of the frequency.
It is the time taken to complete one cycle of oscillation.
The relation between the time period and length of the pendulum is,
T=2π√h/g
where T= time period.
h= length.
g= acceleration due to gravity.
In the given question,
T=4s
g=9.81m/\(s^{2}\)
To find the length, Use the relation of the time period and the length we get.
T=2π√h/g
h=\(T^{2}\)×g / 4×π²
h=4²×9.81 /4×π²
h=3.975m
Hence The length of the pendulum is 3.975m.
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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
Answers
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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Ann is driving down a street at 63 km/h.
Suddenly a child runs into the street.
If it takes Ann 0.777 s to react and apply
the brakes, how far will she have moved before
she begins to slow down?
Answer in units of m
Answers
Answer:
s = 13.6 m
Explanation:
Ann is driving at a constant speed. Hence, the formula of uniform motion shall be used here. The formula for the distance traveled during uniform speed motion is given as follows:
s = vt
where,
s = distance covered by the car before it begins to slow down= ?
v = uniform speed of car = (63 km/h)(1000 m/ 1 km)(1 h/3600 s) = 17.5 m/s
t = time to react before applying brakes = 0.777 s
Therefore, using the values in the equation, we get:
s = (17.5 m/s)(0.777 s)
s = 13.6 m
Suppose an empty grocery cart starts at a rest and rolls downhill in a parking lot. The cart has a maximum speed of 2.2km/s when it hits the side of the store and comes to rest 1.5 min later. If an unbalanced force of 65 N stops the cart, what is the mass of the grocery cart?
Answers
Answer: i dont know
Explanation:
E
if the amplitude of vibration is large sound is feeble true or false
Answers
Answer:
False
Explanation:
Complete this concept map about types of waves.
Answers
Answer:
The answer is within the picture.
Explanation:
. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
Answers
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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If your speedometer has an uncertainty of 2.5 km/h at a speed of 92 km/h, what is the percent uncertainty
Answers
Answer:
2.7%
Explanation:
Given:
Uncertainty of the speedometer (u)= 2.5km/h
Speed measured at that uncertainty (v) = 92km/h
Percent uncertainty (p) is given as the ratio of the uncertainty to the speed measured then multiplied by 100%. i.e
p = \(\frac{u}{v} * 100\)%
p = \(\frac{2.5}{92} * 100\)%
p = 2.7%
Therefore, the percent uncertainty is 2.7%
A person pushes a box across a horizontal surface at a constant speed of 0.5 meter per second The box has
a mass of 40 kilograms, and the coefficient of sliding friction is 0.25. The power supplied to the box by the
person is
a. 0.2 W
c. 50 W
b. 5W
d. 100 W
Answers
Answer:
The correct option
(C) 50W
-
Hope it help's u :))!
a story that ends indeed God knows the best
Answers
Answer:
In fact, God already knows how your story will end. The thing is, it’s really his story and he created you to be a unique and significant part of it. That’s why you can have faith that he is working to take care of you and to give you a good future. God repeatedly says in Scripture that he will one day reward us for our faith.
Good luck
Explanation:
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Answers
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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A student notices that he does better on tests if he sleeps for at least 8 hours. He decides that for the next 3 tests he has in science class, he will sleep different amounts of times and see how he does on his tests. For his next science test, he sleeps only 4 hours the night before, 6 hours before the next test, and 8 hours before the final exam. The chart shows his data. grade Test 1 2 3 Hours of Sleep 4 6 8 Grade 56 75 80 What is the dependent variable?
Answers
The dependent variable in the experiment in which a student sleeps different intervals of time to get different grades is the grade
In this experiment,
Independent variable = Hours of sleepDependent variable = GradesControl variable = The studentAn independent variable is the variable that can be altered by the researcher to get different results. The dependent variable is the variable that gets altered due to the change in independent variable.
Therefore, the dependent variable is the Grades
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A force of 60. newtons is applied to a rope to pull a sled across a horizontal surface at a constant velocity. The rope is at an angle of 30. Degrees above the horizontal.8-9. Calculate the magnitude of the component of the 60.-newton force that is parallel to the horizontal surface. [Show all work, including the equation and substitution with units.] [2]
Answers
ANSWER:
51.96 N
STEP-BY-STEP EXPLANATION:
The horizontal component of the pulling force of Force is FAx since the axis is horizontal, therefore:
\(\begin{gathered} F_x=F\cdot\cos _{}\theta \\ \text{ replacing} \\ F_x=60\cdot\cos 30 \\ F_x=51.96\text{ N} \end{gathered}\)The magnitude of the component of the 60 newton is 51.96 N
3. A 1.23 kg object slides down a 1.25 m incline of 35º. Use the data table to construct a graph for force due to gravity vs. distance. Trial 1 Trial 2 Trial 3 Averages Distance (m) 1.25 1.32 1.28
4. Based on the graph in #3, calculate the work done by gravity. Assume work is constant for this data.
5. Using the data from #3, construct a free body diagram and calculate work done by gravity. Explain how this value compare to the value determined graphically in #4.
Remember that this object is on an angle. You'll need to multiply the value for work by cos0
Keep in mind that you'll need to use the angle that forms between the force of gravity and distance.
Answers
Answer:
Explanation:
To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.
Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.
Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.
It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.
It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.
What is the momentum if the mass is 1.5 kg and the velocity is 4 m/s?
Answers
Answer:
6
Explanation:
momentum = mass * velocity
momentum = 1.5 * 4
momentum = 6
*69. ssm A 1.0 x 10-kg spider is hanging vertically by a thread that
has a Young's modulus of 4.5 X 10 N/m² and a radius of 13 x 10 m.
Suppose that a 95-kg person is hanging vertically on an aluminum wire.
What is the radius of the wire that would exhibit the same strain as
the spider's thread, when the thread is stressed by the full weight of the
spider?
Answers
The radius of the wire that would exhibit some strain the same strain as a spider is 0.06m.
How to calculate the radius?The strain in a wire is given by the change in length divided by the original length, and is equal to the force applied divided by the cross-sectional area times the Young's modulus.
The force applied to the spider's thread is the weight of the spider, which is 1.0 x 10⁻³ kg x 9.8 m/s² = 9.8 x 10⁻³N.
The original length of the spider's thread is L = h, where h is the height of the spider.
The change in length is given by ΔL = FL/AY, where F is the force applied, L is the original length, A is the cross-sectional area, and Y is the Young's modulus.
Solving for the cross-sectional area, A = FL/ΔL = FL/ (FY/Y) = FLY/F = LY/F = πr²
We can now substitute the known values into the equation and solve for the radius, r:
πr² = LY/F = hY/F = 4.5 x 10 N/m² x (13 x 10⁻⁶ m) / (9.8 x 10⁻³ N)
r = sqrt(hY/Fπ) = sqrt(4.5 x 10 N/m² x (13 x 10⁻⁶ m) / (9.8 x 10⁻³ Nπ))
The radius of the aluminum wire that would exhibit the same strain as the spider's thread is the same as the calculated radius, 0.06m.
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If a charge is doubled, what happens to electric potential and electric potential energy?
Answers
The required charge on an object is doubled, and the electric potential energy stored in the system also doubles.
What is electric charge?
Electric charge is the property of subatomic particles that causes them to experience a force when placed in an electric and magnetic field.
Here,
If the charge on an object is doubled, the electric potential at a given point around the object also doubles. The electric potential energy stored in an object with a given charge at a certain distance from another charged object is proportional to the product of the two charges and inversely proportional to the distance between them. Thus, if the charge on an object is doubled, the electric potential energy stored in the system also doubles.
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An object of mass 1. 0 kilogram changes speed from 2. 0 meters per second to 5. 0 meters per second. What is the magnitude of the change in the object's momentum?.
Answers
Answer:
Below
Explanation:
Change in v = 5-2 = 3 m/s
Change in momentum = m * change in v = 1 * 3 = 3 kg m/s
The amount of energy needed to a power a 0.20kw bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of
Answers
The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.
To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:
Potential energy (PE) = mass (m) × gravity (g) × height (h)
Where:
m = 2.5 kg (mass of the object)
g = 9.8 m/s² (acceleration due to gravity on Earth)
h = ? (height)
First, let's find the height (h) by rearranging the formula:
h = PE / (m × g)
Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):
Energy (E) = power (P) × time (t)
E = 0.20 kW × 1 min × 3,600 J/kW
Now, we can substitute the values into the equation to find the height:
h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)
Calculating the expression on the right side:
h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)
Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.
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what would the net force be on the box in the problems shown below.( both force and direction).
Answers
Answer:
4
Explanation:
The net force on the box a will be 20 N to the left and that on box b is 6 N downwards. The net force on box c is 90 N to the left and that on box d is zero.
What is net force?Force is an external agent acting on a body to change its motion or to deform it. The net force acting on a body depends on all the the forces with their magnitudes and directions.
If two same or different forces acts from the same direction they will add up and net force will be their sum. If they acts from the different directions, they will cancel each other in magnitudes.
In box a, the equal forces of 20 N opposes from each direction cancel and the net force will be 20 N to the left. I box b the 15 N cancel each other. Where the 4N and 2 N add up to have net force of 6 N downwards.
In box c, 10 N from opposite direction cancels and the 60 N and 30 N to the left add ups to have the net force of 90 N to the left. On box d, 5 N from opposite directions cancels as 12 N. Hence, net force is zero.
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A car speeds up from 3 m/s to 10 m/s in 8 s. How far does the car travel while doing this? 2. A
Answers
Initial velocity=u=3m/s
Final velocity=v=10m/s
Time=t=8s
\(\boxed{\sf Acceleration=\dfrac{v-u}{t}}\)
\(\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}\)
\(\\ \sf\longmapsto Acceleration=\dfrac{7}{8}\)
\(\\ \sf\longmapsto Acceleration=0.8m/s^2\)
Distance =sUsing second equation of motion
\(\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2\)
\(\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2\)
\(\\ \sf\longmapsto s=24+0.4(64)\)
\(\\ \sf\longmapsto s=24+25.6\)
\(\\ \sf\longmapsto s=49.6m\)
A. If an electron of 16 eV had a head-on collision with a Cs atom at rest, what would be the kinetic energy in eV) of the recoiling Cs atom? Assume an elastic collision. (Take the atom to be the most abundant isotope of the element. B. In a Frank-Hertz experiment, the first excited state of Hg is obtained at an accelerating voltage measured to be 4.87 V. Based on this measured value, determine the wavelength of the ultraviolet radiation you expect to be emitted.
Answers
Answer:
A) 1.96 * 10^-8 J
B) 2.55 * 10^-7 m
Explanation:
A) calculate the kinetic energy in eV of the recoiling Cs atom
we have to apply the principle of energy conservation and momentum
Initial kinetic energy of electron = 16 eV = 16 * (1.6 * 10^-19 ) J
Initial kinetic energy of atom = 0
therefore the final kinetic energy after collision ( E )
= [ 16 * ( 1.6 * 10^-19 ) ] + 0
= 1.96 * 10^-8 J
B) Determine the wavelength of the ultraviolet radiation
accelerating Voltage = 4.87 V
K.E = eV = 1.6 * 10^-19 * 4.87
next we will apply Planck's relationship
\(\frac{hc}{w} = KE\) --------- ( 1 )
w = wavelength
h = 6.64 * 10^-34 J-S ( Planck's constant )
c = 3 * 10 ^8 m/sec ( speed of light )
KE = 1.6 * 10^-19 * 4.87
substitute given values into equation 1 above
w ( wavelength ) = 2.55 * 10^-7 m
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 50 centimeters to 80 centimeters
Answers
The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
Hooke's LawHooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.
To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.
Formula:
F = ke................. Equation 1Where:
F = Force appliedk = Spring constante = extensionmake k the subject of the equation
k = F/e................ Equation 2From the question,
Given:
F = 450 Ne = 30 cm = 0.3 mSubstitute these values into equation 2
k = 450/0.3k = 1500 N/m.Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.
W = ke²/2........... Equation 3Where:
W = Work donek = spring constante = extensionAlso, From the question,
Given:
e = (80-50) = 30 cm = 0.3 mk = 1500 N/mSubstitute these values into equation 3
W = 1500(0.3²)/2W = 67.5 J.Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
Learn more about Hooke's law here: https://brainly.com/question/12253978
In many cartoon shows, a character runs of a cliff, realizes his predicament and lets out a scream. He continues to scream as he falls. If the physical situation is portrayed correctly, from the vantage point of an observer at the foot of the cliff, the pitch of the scream should be Group of answer choices
Answers
Answer:
Increasing until terminal velocity is reached
Explanation:
Provided the scream is a constant pitch at the source, Doppler effect will make the pitch increase as the velocity of the source towards the listener increases.