A particle of weight W is placed on a rough plane which is inclined at an angle y to the horizontal. The coefficient of friction between the particle and the plane is where < tan . Show that the magnitude of the least horizontal force tan - W μ 9 F needed to maintain the particle in equilibrium is F=;
\( \frac{tan \beta - \alpha }{?} w \div 1 + \beta tan \alpha \)
​

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer:  momentum is determined and conserved.

Answer:

monument is determined

Julianna's resultant displacement when she walks 10 meters East, and 15 meters South and 20 meters North is 11.18m North-East.

displacement can be defined as distance in a specified direction.

To calculate the resultant displacement of the Julianna, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, Julianna's resultant displacement is 11.18 m North-East.

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Answer:

1.60 x 10-10 C

Explanation:

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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The maximum force of static friction that the car's wheels can experience with the flat concrete road is  μ×5000 N.

The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.

The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.

As the normal force = 5000 N.

The maximum force of static friction = μ×5000 N.

The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.

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A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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a. The minimum time for the rocket to reach the sound barrier is 33.67 seconds.

b. The maximum vertical thrust of the rocket engines under these conditions is 250,893.6 N.

c. The rocket is 5548.1 meters above the Earth's surface when it breaks the sound barrier.

To solve this problem, we'll use Newton's second law of motion (F = ma) and consider the forces acting on the rocket and the instrument inside.

Calculating the minimum time for the rocket to reach the sound barrier without breaking the inside wire.

a) Minimum time to reach the sound barrier:

Given:

Mass of the rocket (m) = 2.56 × \(10^4\) kg

Acceleration due to gravity (g) = 9.8 m/\(s^2\)

Maximum tension the wire can support (T_max) = 27.5 N

Weight of the instrument (W) = mass of the instrument × acceleration due to gravity = 13.6 N

The forces acting on the instrument inside the rocket are its weight (W) and the tension in the wire (T). At maximum tension, the net force on the instrument is zero.

T - W = 0

T = W

Therefore, the maximum tension in the wire is equal to the weight of the instrument, which is 13.6 N.

Now, let's determine the acceleration of the rocket. The total force acting on the rocket is the sum of the rocket's weight (mg) and the tension in the wire (T).

F_total = mg + T

F_total = (2.56 × \(10^4\) kg)(9.8 m/\(s^2\)) + 13.6 N

F_total = 250,880 N + 13.6 N

F_total = 250,893.6 N

Since we're assuming the rocket's acceleration is constant.

we can use Newton's second law:

F_total = ma

250,893.6 N = (2.56 × \(10^4\) kg)a

Solving for acceleration:

a = 250,893.6 N / (2.56 × \(10^4\) kg)

a ≈ 9.8 m/\(s^2\)

The acceleration of the rocket is approximately 9.8 m/\(s^2\), which is the same as the acceleration due to gravity.

To find the minimum time to reach the sound barrier, we can use the following equation of motion:

v = u + at

where,

v = final velocity (sound barrier velocity = 330 m/s)

u = initial velocity (which is zero since the rocket starts from rest)

a = acceleration

t = time

330 m/s = 0 + (9.8 m/\(s^2\))t

Solving for t:

t = 330 m/s / 9.8 m/\(s^2\)

t ≈ 33.67 s

Therefore, the minimum time for the rocket to reach the sound barrier without breaking the inside wire is approximately 33.67 seconds.

b) Maximum vertical thrust of the rocket engines:

The maximum vertical thrust of the rocket engines is equal to the total force acting on the rocket, which we calculated earlier:

Maximum vertical thrust = F_total

Maximum vertical thrust ≈ 250,893.6 N

Therefore, the maximum vertical thrust of the rocket engines under these conditions is approximately 250,893.6 N.

c) Distance above the Earth's surface when breaking the sound barrier:

To determine the distance above the Earth's surface when breaking the sound barrier, we can use the following equation of motion:

s = ut + (1/2)at^2

where,

s = distance

u = initial velocity (which is zero)

a = acceleration

t = time it takes to reach the sound barrier (33.67 s).

s = 0 + (1/2)( 9.8 m/\(s^2\))\((33.67 s)^2\)

s = (\(4.9 m/s^2\))(1132.8289 \(s^2\))

s ≈ 5548.1 m

Therefore, the rocket is approximately 5548.1 meters (or 5.55 kilometers) above the Earth's surface when it breaks the sound barrier.

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A sine bar is used to get the angular measurement of a part feature. The angle of the part feature is 18.24°

From the question

Given that,

Length of the sine bar, L = 8.000 in

Diameter of the rolls = 1.000 in

Height under the roll, H = 2.0000 + 0.5000 + 0.0050

                                     = 2.505 in

From sine bar formula,

we know that,

H = sin A x L

sin A = H ÷ L  

where,

A ⇒ angle of part feature

H ⇒ height under the roll

L ⇒ length of the sine bar

Substituting values in the above equation,

sin A = H / L

A = sin⁻¹ ( 2.505 ÷ 8 )

A = sin⁻¹ (0.3131)

A = 18.24⁰

Hence the angle of the part feature = 18.24°

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Answer:

The force of gravity on an object depends on the mass of the object and the mass and distance of the celestial body it is on or near. The formula for the force of gravity is:

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

To compare the force of gravity on an 81 kg mass on the Moon's surface with the force on the Earth's surface, we need to calculate each force using the above formula and then compare the results.

First, let's calculate the force of gravity on an 81 kg mass on the Earth's surface:

F_Earth = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 5.97 x 10^24 kg) / (6.38 x 10^6 m)^2

= 7.92 x 10^2 N

So the force of gravity on an 81 kg mass on the Earth's surface is 792 N.

Next, let's calculate the force of gravity on an 81 kg mass on the Moon's surface:

F_Moon = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 7.35 x 10^22 kg) / (1.74 x 10^6 m)^2

= 1.32 x 10^3 N

So the force of gravity on an 81 kg mass on the Moon's surface is 1320 N.

Therefore, the force of gravity on the Moon's surface is greater than the force of gravity on the Earth's surface. The ratio of F_Earth to F_Moon is:

F_Earth / F_Moon = 792 N / 1320 N

= 0.6

So the force of gravity on the Moon's surface is about 60% of the force of gravity on the Earth's surface.

Answer: A.

Lithium sulfide is the inorganic compound with the recipe Li2S. It solidifies in the antifluorite theme, depicted as the salt (Li+)2S2−. It frames a strong yellow-white deliquescent powder. In air, it effectively hydrolyses to deliver hydrogen sulfide (spoiled egg scent).

Answer:

Communicating each person's job effectively.

The time it will take for the plane to speed 40m/s is 12.9s.

Acceleration in physics is the change of velocity with respect to time (can include deceleration or changing direction).

The time it will take for a moving body to accelerate 40m/s can be calculated using the following expression:

v = u + at

Where;

40 = 0 + 3.1t

40 = 3.1t

t = 12.9s

Therefore, 12.9s is the time it will take for the plane to speed.

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Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.

In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.

In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.

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To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

Given what we know, as with any binary star system, the life cycle of these stars will end with one of them forming a white dwarf star, and the other becoming a red giant that will engulf the white dwarf.

Taking information from the diagram provided, we can infer that the star Sabik is in its white dwarf state at the current time. This means that before long, the remaining star in this binary system will become a red giant. When this happens, it will engulf star Sabik, and that will be the end of this star's life cycle.

Therefore, we can confirm that as with any binary star system, the life cycle of these stars will end with one of them forming a white dwarf star, and the other becoming a red giant that will engulf the white dwarf.

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Answer:

True,

Explanation:

Over the entire surface, the variation in gravitational acceleration is about 0.0253 m/s2 (1.6% of the acceleration due to gravity). Because weight is directly dependent upon gravitational acceleration, things on the Moon will weigh only 16.6% (= 1/6) of what they weigh on the Earth.

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

Answer:

The digestive system is made up of the gastrointestinal tract—also called the GI tract or digestive tract—and the liver, pancreas, and gallbladder. The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.The small intestine has three parts. The first part is called the duodenum. The jejunum is in the middle and the ileum is at the end. The large intestine includes the appendix, cecum, colon, and rectum. The appendix is a finger-shaped pouch attached to the cecum. The cecum is the first part of the large intestine. The colon is next. The rectum is the end of the large intestine

Explanation:

Answer:

A. The rays can change molecules and atoms in the body into ions.

Answer:

VPA

Explanation:

Approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

To determine the amount of energy transferred into thermal energy during the fall of the diver, we can use the principle of conservation of energy.

The initial potential energy of the diver at the maximum height is given by:

Potential Energy (PE) = m * g * h

Where:

m = mass of the diver (48.0 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = maximum height (11.0 m)

Substituting the given values:

PE = 48.0 kg * 9.8 m/s^2 * 11.0 m = 5,219.2 J

The final kinetic energy of the diver just before hitting the pool is given by:

Kinetic Energy (KE) = (1/2) * m * v^2

Where:

m = mass of the diver (48.0 kg)

v = speed of the diver (8.81 m/s)

Substituting the given values:

KE = (1/2) * 48.0 kg * (8.81 m/s)^2 = 1,919.3 J

The difference between the initial potential energy and the final kinetic energy represents the energy transferred into thermal energy:

Energy transferred into thermal energy = PE - KE

                                     = 5,219.2 J - 1,919.3 J

                                     = 3,299.9 J

Therefore, approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

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8.27 x 1013 meres is the orbital radius.

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.

The Brundtland Commission was set up with the intention to achieve sustainable development. The tenure of the commission lasted from 1984 to 1987.

The commission identified the pillars of sustainable growth as economic growth, environmental protection, and social equality. The committee opined that environmental problem emanates from poverty in the southern region and reckless consumption of resources in the northern region.

The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.

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Answer:

Well, yes.

We can have an isolated light wave that is defined by only one frequency (and one wavelenght). But this is not a really common situation, most of the light that we can see in nature, is actually a composition of different waves with different frequencies.

Even if we have, for example, a red laser, the actual frequency of the light that comes from the laser may be in a range of frequencies, so the actual wave is a composition of different waves with really close frequencies.

An example of a light wave defined by only one frequency can be, for example, the photon that comes out of a change in energy of an electron.

Here we have a single photon, with a single frequency, that is modeled as a single frequency wave.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Answer:

The size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.

Explanation:

To determine the size of the magnetic force on the wire due to the Earth's magnetic field,

The magnetic force is given by the formula

F = ILB sinθ

Where F is the magnetic force on the wire

I is the electric current in Amperes (A)

L is is the length of wire in meters (m)

B is the magnetic field in Tesla (T)

and θ is the angle between current and magnetic field

From the question,

L = 0.30 m

I = 0.50 A

B = 0.50 gauss = 0.5 × 10⁻⁴ T (NOTE: 1 Gauss = 10⁻⁴ Tesla)

θ = 38°

Now, putting the values into the equation

F = ILB sinθ

F = 0.50 × 0.30 × 0.5 × 10⁻⁴ sin38°

F = 7.5 × 10⁻⁶ (0.61566)

F = 4.62 × 10⁻⁶ N

Hence, the size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.

Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.

The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.

So, the mass of the block of lead is approximately 1.63 metric tons.