A photon after being scattered from a free electron at rest moves at an angle of 120 degrees with respect to the incident direction. If the wavelength of the incident proton is .611 nm, what is the kinetic energy of the recoiling electron?

Answers

Answer 1

The kinetic energy of the recoiling electron is approximately 2.54 x 10^-17 J.

When a photon scatters off a free electron, both particles change direction and momentum. In this case, we know that the incident photon has a wavelength of .611 nm and is scattered at an angle of 120 degrees with respect to the incident direction. We can use conservation of energy and momentum to find the kinetic energy of the recoiling electron.

First, we can calculate the initial momentum of the photon using the formula p = h/λ, where p is momentum, h is Planck's constant, and λ is the wavelength. Plugging in the given values, we get:

p = (6.626 x 10^-34 J s) / (0.611 x 10^-9 m)

p = 1.084 x 10^-24 kg m/s

Conservation of momentum tells us that the total momentum before and after the scattering must be equal. Since the electron is initially at rest, the total momentum before the scattering is just the momentum of the photon. After the scattering, the photon and electron have new momenta that we can represent using vectors. If we draw a diagram of the scattering, we can see that the angle between the incident and scattered photon is also 120 degrees. Using the law of cosines, we can relate the magnitudes of the initial and final momenta to the scattering angle:

p^2 + p^2 - 2p^2 cos(120 degrees) = (2p cos(120 degrees))^2

2p^2 + p^2 = 4p^2 cos^2(120 degrees)

p^2 = 4p^2 cos^2(120 degrees) - 2p^2

p^2 = 2p^2 (1 - cos(120 degrees))

p^2 = 2p^2 (1/2)

p = p/√2

Thus, the momentum of the scattered photon is:

p' = p/√2 = 1.084 x 10^-24 kg m/s / √2

p' = 7.676 x 10^-25 kg m/s

The electron recoils in the opposite direction with an equal and opposite momentum. Therefore, the momentum of the recoiling electron is also p'. We can now use conservation of energy to find the kinetic energy of the electron. The energy of the scattered photon is:

E' = hc/λ' = pc

E' = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (0.611 x 10^-9 m)

E' = 3.269 x 10^-16 J

The initial energy of the photon is just its energy at rest, which is also E'. Therefore, conservation of energy tells us that:

E' + mc^2 = E + (mc^2 + T)

where m is the mass of the electron, c is the speed of light, T is the kinetic energy of the electron, and E is the total energy of the photon before scattering. We can solve for T:

T = E' + mc^2 - E - mc^2

T = E' - E

T = 3.269 x 10^-16 J - (hc/λ)

T = 3.269 x 10^-16 J - (6.626 x 10^-34 J s x 2.998 x 10^8 m/s) / (0.611 x 10^-9 m)

T = 2.54 x 10^-17 J

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Related Questions

Choose one of these three people and write a letter to them to express your concerns about the events of 01/06/21

Answers

Bro I didn’t put nothing

Question 50 Marks: 1 Microwave ovens that have magnetron tubes use electrical energy to generateChoose one answer. a. low frequency, short wave energy b. high frequency, long wave energy c. high frequency, short wave energy d. low frequency, long wave energy

Answers

The correct answer is c. high frequency, short wave energy. Microwave ovens use a magnetron to convert electrical energy into high frequency, short wave energy that is used to cook food.

Microwave ovens that have magnetron tubes use electrical energy to generate high frequency, short wave energy. This energy is generated by the oscillations of electrons in a magnetic field that is generated by the magnetron tube. The high frequency, short wave energy that is emitted from the magnetron tube is what heats up the food and other materials inside the microwave oven. This energy is also known as microwaves. These microwaves travel through the metal walls of the oven, which reflects them back into the oven’s cavity.

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Help please! I hope the given possibles help

Help please! I hope the given possibles help

Answers

Answer:

The answer is "\(5.184 \times 10^{23}\) kg"

Explanation:

Given:

\(g= 6.003 \ \frac{m}{s^2}\\\\G= 6.67 \times 10^{-11} \ \frac{N - m^2}{kg^2}\\\\M=?\\\\radius= 2,400 \ km\\\\\)

Calculating diameter:

\(Diameter =radius \times 2\)

                \(=24\times 10^5 \times 2\\\\=48 \times 10^5 \ m\)

The formula for mass calculation:

\(\to g = G \times \frac{M}{(\frac{d^2}{4})}\\\\\to g=G\times \frac{4M}{d^2}\\\\\to 4M= \frac{g \times d^2}{G} \\\\\to M= \frac{g \times d^2}{4G} \\\\\)

         \(=\frac{6.003 \times (48 \times 10^{5})^2}{4 \times 6.67 \times 10^{-11}}\\\\=\frac{6.003 \times 2,304 \times 10^{10}}{26.68\times 10^{-11}}\\\\=\frac{13,830.912 \times 10^{10}}{26.68\times 10^{-11}}\\\\=518.4 \times 10^{21}\\\\= 5.184 \times 10^{23}\\\\\)

GIVING BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 25pts-

GIVING BRAINLIEST PLEASE HELP!!-if you answer correctly ill give you brainliest which will give you 25pts-

Answers

Answer:

A, and D are the answers

Explanation:

The pulley. It is located where the bicycle chain and gears are. The chain is wrapped around the pulley which turns and causes the wheel to turn on its axle.

HELP ME!!!!!!!!!!!!! DUE IN 10 MINUTES HURRY!!!!!!!

HELP ME!!!!!!!!!!!!! DUE IN 10 MINUTES HURRY!!!!!!!

Answers

Answer:

3.4 or 3 11/23

Explanation:

just dive so you can see it as if it were Evelyn distributed

3.4








Hope that’s right!

the coasting car stops 15m higher than where it started coasting. find the velocity when it began coasting, assuming no energy is dissipated.

Answers

The velocity of the car when it began coasting was approximately 17.2 m/s.

If a car is coasting without any external force acting on it (such as friction), then its initial kinetic energy is converted entirely into potential energy as it moves uphill. Therefore, we can use the principle of conservation of energy to solve this problem.

The principle of conservation of energy states that the total energy of a closed system (in this case, the car and the Earth) remains constant over time. Therefore, the initial kinetic energy of the car is equal to the potential energy gained as it moves uphill. Mathematically, we can express this as:

1/2 mv^2 = mgh

where:

m = mass of the car

v = initial velocity of the car when it began coasting

g = acceleration due to gravity (9.8 m/s^2)

h = height gained by the car (15 m)

We can simplify this equation by canceling out the mass (m) on both sides:

1/2 v^2 = gh

Substituting the given values, we get:

1/2 v^2 = 9.8 m/s^2 * 15 m

v^2 = 2 * 9.8 m/s^2 * 15 m

v = √(2 * 9.8 m/s^2 * 15 m)

v ≈ 17.2 m/s

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A bullet travelling horizontally with speed of 30m/s strike a wooden plank normal it surface, passing through it with a speed of 10m/s. Find the time taken by the the bullet to pass through the wooden plank of 5cm thickness

Answers

The bullet takes 0.0025 seconds to pass through the wooden plank of 5 cm thickness when it is traveling horizontally with an initial speed of 30 m/s and a final speed of 10 m/s.

The time taken by the bullet to pass through the wooden plank can be determined using the equation of motion for constant acceleration.

Given:
Initial speed (u) = 30 m/s


Final speed (v) = 10 m/s


Distance (s) = 5 cm = 0.05 m

To find the time taken (t), we need to calculate the acceleration (a) first. We can use the equation:

v² = u² + 2as

Rearranging the equation, we have:

a = (v² - u²) / (2s)

Substituting the given values:

a = (10² - 30²) / (2 * 0.05)

Simplifying the expression:

a = (-800) / (0.1)


a = -8000 m/s²

The negative sign indicates that the acceleration is in the opposite direction of the initial velocity.

Next, we can use the equation of motion:

v = u + at

Substituting the values:

10 = 30 + (-8000) * t

Simplifying the equation:

-8000t = -20

Dividing by -8000:

t = 20 / 8000
t = 0.0025 s

Therefore, the time taken by the bullet to pass through the wooden plank of 5 cm thickness is 0.0025 seconds.


To find the time taken by the bullet to pass through the wooden plank, we need to calculate the acceleration first using the equation of motion.

By rearranging the equation and substituting the given values, we can find the acceleration.

Then, using the equation of motion again, we can solve for time.

The negative sign in the acceleration indicates that it is in the opposite direction of the initial velocity.

The resulting time is 0.0025 seconds.

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what is parking orbit?​

Answers

A parking orbit is a temporary orbit used during the launch of a spacecraft. A launch vehicle boosts into the parking orbit, then coasts for a while, then fires again to enter the final desired trajectory.

Hope this helps!

Have a great day :)

Answer:

A temporary orbit in which a spacecraft awaits the next phase of its mission .

The density of air at a pressure of 1x105pa is 1.2kg/m3. What is the root mean
square speed (Vrms) of the air molecules?

Answers

The root mean square speed of the air molecules is 500 m/s.

What is the root mean square velocity?

The term root mean square speed has to do with the average speed of the molecules of a gas. In this case, we need to find the root mean square speed by the use of the pressure and the density of the gas. We have to use the relation;

Root mean square speed = √3 * pressure/ Density

Since 1 Pa = 1 N/m^2

1 x 10^5pa = 1 x 10^5 N/m^2

Then we can now substitute the values;

Root mean square speed = √3 * 1 x 10^5 N/m^2/ 1.2kg/m3

= 500 m/s

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A force of 250N is applied on an object causing it to move for 6m at uniform velocity of 32m/s. Determine the (I) work done (ii)power developed

Answers

The power developed is 8000 W.

Given data:

Force = 250 N

Distance traveled = 6 m

Velocity = 32 m/s

Let's find out the work done on the object by the applied force.

Work done is given by the product of force and distance covered:

W = F × s

W = 250 × 6 = 1500 J

Thus, the work done on the object by the applied force is 1500 J.

Next, let's determine the power developed.

Power is defined as the rate at which work is done, i.e.,

P = W / t

where P is power, W is work done, and t is time taken to do that work.

We know that velocity = distance / time. Rearranging the above expression, we get:

t = d / v

Substituting the given values, we get:

t = 6 / 32

P = W / t

Substituting the calculated value of W and t, we get:

P = 1500 / (6 / 32)

P = 8000 W

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which are cardiovascular drug classes? select all that apply

Answers

Cardiovascular drug classes are Beta-blockers, Diuretics, Calcium channel blockers, and ACE inhibitors. The correct answer is options are A, B, D, and F.

Cardiovascular drug classes refer to categories of medications specifically designed to treat conditions related to the cardiovascular system. These medications target various aspects of cardiovascular health, such as blood pressure regulation, heart rhythm management, and the prevention of clot formation. Several recognized cardiovascular drug classes include:A) Beta-blockers: These drugs block the effects of adrenaline on the heart and blood vessels, reducing heart rate and blood pressure.B) Diuretics: Also known as water pills, diuretics help eliminate excess fluid from the body, reducing fluid buildup and decreasing blood pressure.D) Calcium channel blockers: These medications relax and widen blood vessels, improving blood flow and reducing blood pressure. They also help regulate heart rate.F) ACE inhibitors: ACE (angiotensin-converting enzyme) inhibitors lower blood pressure by blocking the production of a hormone that narrows blood vessels.Therefore, the correct options for cardiovascular drug classes are A) Beta-blockers, B) Diuretics, D) Calcium channel blockers, and F) ACE inhibitors. These medications play crucial roles in managing cardiovascular conditions and promoting overall heart health.

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The correct question would be as

Which of the following are cardiovascular drug classes? Select all that apply.

A) Beta-blockers

B) Diuretics

C) Antibiotics

D) Calcium channel blockers

E) Antidepressants

F) ACE inhibitors

the critical angle for the total internal reflection at the liquid air interface is 42.5 degrees. (a) If a ray of light traveling in the liquid has an angle of incidence of 35.0 degrees at the interface, what angle does the refracted ray in the air make with the normal? (b) If a ray of light traveling in air has an angle of incidence of 35.0 degree at the interface, what angle does the refracted ray in the liquid make with the normal?

Answers

When a ray of light travels from liquid to air with an incidence angle of 35.0 degrees, the angle of refraction in air can be calculated using Snell's law.

(a) When a ray of light travels from a denser medium (liquid) to a less dense medium (air), with an angle of incidence of 35.0 degrees, and the critical angle is 42.5 degrees, total internal reflection does not occur. Therefore, the ray undergoes refraction. Using Snell's law (n₁sinθ₁ = n₂sinθ₂), we can calculate the angle of refraction in air.

(b) When a ray of light travels from air to a denser medium (liquid) with an angle of incidence of 35.0 degrees, which is less than the critical angle, refraction occurs. Again using Snell's law, we can calculate the angle of refraction in the liquid.

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why do all of the planets have orbits that lie in nearly the same plane and that are in the same direction -- counterclockwise looking down on the solar system from far above the earth's north pole? group of answer choices when they were captured by the sun, the sun was moving past a cluster of planets, and all of those planets were on one side of its path. shortly after they formed, the planets were moving in random directions. in the 4 1/2 billion years since then, the sun's gravity has pulled them into the same plane. the planets and sun all formed from a cloud of gas and dust that contracted as it cooled. as the cloud contracted, its spin increased and it flattened. by the time the planets formed, the cloud was a flat spinning disk.

Answers

The best answer ""The planets and sun all formed from a cloud of gas and dust that contracted as it cooled. As the cloud contracted, its spin increased and it flattened. By the time the planets formed, the cloud was a flat spinning disk.""

This explanation is based on the widely accepted theory of solar system formation called the nebular hypothesis. According to this hypothesis, the solar system formed from a rotating cloud of gas and dust known as the solar nebula. As the nebula contracted due to its own gravity, it began to spin faster and flatten into a spinning disk.

Because the initial cloud had a particular rotation and flattened shape, the resulting planetary system inherited these characteristics. The conservation of angular momentum caused the protoplanetary disk to form a nearly flat plane, and the counterclockwise direction of rotation was also preserved. This is why the planets have orbits in the same plane and in the same counterclockwise direction when viewed from above the Earth's North Pole.

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In a healthy body, the heart pumps blood efficiently. When the heart has a problem, heart failure can occur. Heart failure can happen on one side of the heart or on both sides. What would happen if a person had right-sided heart failure?
The heart would fail to receive oxygenated blood from the lungs.
The heart would fail to efficiently pump oxygenated blood to the body.
The heart would fail to efficiently pump blood to the lungs.
The heart wouldn’t be able to pump blood to or receive blood from the lungs or the body.

Answers

Answer:

the heart would fail to efficiently pump oxygenated blood to the body and lungs

Answer:

the heart is hard to pump

Erica forgot to put gas in her car (again) for two weeks. The graph below shows the last few seconds of her car being stalled along Elkins Drive st 7:23 am Friday. During the time shown, what was the acceleration of her car?
a 54 m
b 108 m/s
c 3 m/s^2
D -3 m/s^2

Erica forgot to put gas in her car (again) for two weeks. The graph below shows the last few seconds

Answers

Answer:

Option (D) : - 3 m/s^2

Explanation:

Acceleration = Slope of v-t graph

= 18/6

= - 3 m/s^2 (-ive since the car is decelerating )

Charge q1 = +2.00 μC is at -0.500 m along the x axis. Charge q2 = -2.00 μC is at 0.500 m along the x axis. Charge q3 = 2.00 μC is at 0.500 m along the y axis. What is the magnitude of electrical force on charge q3 due to the others?

Answers

The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons.

How to calculate the electrical force experimented on a particle

The vector position of each particle respect to origin are described below:

\(\vec r_{1} = (-0.500, 0)\,[m]\)

\(\vec r_{2} = (+0.500, 0)\,[m]\)

\(\vec r_{3} = (0, +0.500)\,[m]\)

Then, distances of the former two particles particles respect to the latter one are found now:

\(\vec r_{13} = (+0.500, +0.500)\,[m]\)

\(r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}\)

\(r_{13} =\frac{\sqrt{2}}{2}\,m\)

\(\vec r_{23} = (-0.500, +0.500)\,[m]\)

\(r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}\)

\(r_{23} =\frac{\sqrt{2}}{2}\,m\)

The resultant force is found by Coulomb's law and principle of superposition:

\(\vec R = \vec F_{13}+\vec F_{23}\) (1)

Please notice that particles with charges of same sign attract each other and particles with charges of opposite sign repeal each other.

\(\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}\) (2)

Where:

\(k\) - Electrostatic constant, in newton-square meters per square Coulomb.\(q_{1}\), \(q_{2}\), \(q_{3}\) - Electric charges, in Coulombs.\(r_{13}\), \(r_{23}\) - Distances between particles, in meters.\(\vec u_{13}\), \(\vec u_{23}\) - Unit vectors, no unit.

If we know that \(k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}\), \(q_{1} = 2\times 10^{-6}\,C\), \(q_{2} = 2\times 10^{-6}\,C\), \(q_{3} = 2\times 10^{-6}\,C\), \(r_{13} =\frac{\sqrt{2}}{2}\,m\), \(r_{23} =\frac{\sqrt{2}}{2}\,m\), \(\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)\) and \(\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\), then the vector force on charge \(q_{3}\) is:

\(\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\)

\(\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]\)

\(\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]\)

And the magnitude of the electrical force on charge \(q_{3}\) (\(R\)), in newtons, due to the others is found by Pythagorean theorem:

\(R = 0.102\,N\)

The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons. \(\blacksquare\)

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A substance that heats up relatively quickly has a low specific heat capacity. Select one: O True O False

Answers

As the given statement is False. As a substance that heats up relatively quickly must has a high specific heat capacity.

What is specific heat capacity?

A physical property of matter is specific heat capacity. The quantity of heat energy required to raise a substance's temperature per unit of mass is known as the specific heat capacity. It serves as an illustration of a large property. Since the scale of the system under study directly affects it. Therefore, it is the amount of heat absorbed by the substance per unit mass when its temperature is elevated. Specific Heat Capacity is measured in J/(kg K) or J/(kg °C) units.

As heating is quick when the substance have high specific heat capacity and the heating will be slow when the substance have less specific heat capacity.

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what is the weight of a 45kg box
____ N

Answers

The weight of a \(45 kg\) box is \(441.45 N\).

Weight refers to the measure of the force exerted on an object due to the gravitational pull of the Earth.

Given the mass of the box is \(m=45 kg\).

The weight of an object (\(W\)) can be found by multiplying the mass of the object (\(m\)) by the acceleration due to gravity (\(g\)).

So, \(W=mg\).

It is known that acceleration due to gravity, \(g=9.81 m/s^2\).

Hence, the weight of the box, \(W=(45kg)\times (9.81 m/s^2)\).

\(\Rightarrow W=441.45 (kg\cdot m/s^2)\\\Rightarrow W=441.45 N\)

Therefore, the weight of the box is \(441.45 N\).

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when we increase the exponent 10 to 10 we must

Answers

Answer:

If you say it like this (x^10)^10, then it would be x^100.

Briefly describe how polygraph tests work. According to the American Psychological Association, these tests are not accurate at all, and they compare them to the flip of a coin. After describing how polygraph test works (in two to three sentences), discuss your thoughts on the accuracy of polygraph tests. Do you agree with the American Psychological Association? Do you think the tests have any benefit, or do you think they should be completely discontinued?

Answers

Answer:

no such thing i dont think

Explanation:

Answer:

Polygraph tests are used to determine whether someone is lying or not, and display the physical signs someone is showing when they speak to be interpreted. Polygraphs measure things like heartbeat, breathing rate, and electrical conductivity of the skin, which are signs that get more and more severe when someone tells major lies or lies a lot. Polygraph tests are pretty unreliable because everyone shows different reactions to speaking depending on how anxious they are or any other medical condition, which could falsely incriminate them, but I think it is still important to determine the signs someone displays to use as a datapoint later on in the trial. For those reasons, they should still be used but shouldn't be relied on as heavily.

Explanation:

Manu took a pebble and a sheet of paper both weigh one gram. His friend told that if we drop both at the same time, the pebble will fall straight to the floor, while the paper will slowly drift to the ground. Do you think friction have any role in this case? How can we relate that to the topic which we are learning today?

Answers

Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).

Explanation:

However what this topic relates to is gravity. The pebble and paper both weigh one gram, but have different density this is the sole reason why if both are drop from same height the pebble would reach the ground faster than the paper because it is more denser. unlike the paper with a lesser density which would take a longer time to reach the ground.

Parents bring their 2-month-old into the clinic with concerns the baby seems "floppy". The parents say the baby seems to be working hard to breathe. The nurse can see intercostal retractions, although the baby is otherwise in no distress. The parents say the baby eats very slowly and seems to tire quickly. They add there was a cousin with similar symptoms. The nurse would be most concerned with what possible complications. a Respiratory compromise b. Dehydration c. Need for emotional support for the family d. Risk for constipation

Answers

The nurse would be most concerned with a respiratory compromise possible complications when parents bring their 2-month-old into the clinic with concerns the baby seems "floppy".

The baby is also working hard to breathe and seems to tire quickly. The nurse can see intercostal retractions, although the baby is otherwise in no distress. The parents add that there was a cousin with similar symptoms.

A respiratory compromise is a medical emergency and the nurse must act fast in this situation. Infants with respiratory compromise can develop hypoxia, which can lead to significant morbidity or death if not addressed promptly. Hypoxia can lead to brain damage or other organ damage, and it can be difficult to identify in infants and children.

Therefore, prompt identification and treatment of respiratory compromise are critical for infants.The nurse should assess the baby’s breathing and immediately report to a medical doctor if she observes the following signs: Grunting, Breathing is rapid and labored, Flaring of nostrils, Cyanosis is present.

The presence of intercostal retractions indicates increased respiratory work. Infants use their chest muscles to breathe when their lung function is compromised. Therefore, intercostal retractions, a sign of respiratory distress, indicate a medical emergency that needs immediate attention.

Dehydration and constipation are unlikely concerns given the current symptoms. Emotional support is important to family members, but it is not the priority in this situation. Therefore, the nurse should prioritize the baby's respiratory compromise as a priority.

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Abishek is a runner. He runs the 100 m sprint
in 10 x 6s. What speed did he travel at?
(in m/s)​

Answers

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

The answer you are looking for is approximately 1.67 m/s.

Solution/Explanation:

Distance Ran: 100 m.

Time ran: 10x6s, or 60s, or one minute.

Speed: Unknown?

Writing out the formula for speed, using distance and time,

S=D/T.

S=Speed.

D=Distance.

T=Time.

Substituting the given values of the variables,

S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.

100÷60=1.6667≈1.67.

So, therefore, the final answer is approximately 1.67 m/s.

I hope that this has helped you. Enjoy your day, and take care.

g what is the speed, in m/s, of the roller coaster at the top of the loop if the radius of curvature there is 13.0 m and the downward acceleration of the car is 1.50 g?

Answers

The acceleration of an item moving in a circle always points in that direction. Centripetal acceleration is the name given to this speed. The roller coaster travels at a 12.7 m/s speed.

Centripetal acceleration may be calculated using a straight forward equation.

a = v^2 / r

The speed of the automobile may be determined using the same equation.

\(v^2 = a * r v = \sqrt {(1.50)(9.80 m/s2)(11.0 m)\\ v^2 = a * r v = \sqrt v = 12.7 m/s\)

Acceleration is the rate at which an object changes its velocity over a period of time. In other words, it's the measure of how quickly the velocity of an object is changing. Acceleration can occur in various directions, and its magnitude depends on the force that is being applied to the object.

Acceleration is often denoted by the symbol "a" and is measured in units of meters per second squared (m/s²). The equation for acceleration is a = (v_f - v_i) / t, where v_f is the final velocity of the object, v_i is its initial velocity, and t is the time it takes for the object to change its velocity. Acceleration refers to how fast an object is speeding up or slowing down.

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Help me as pleasessss help with 1,2 and 3

Help me as pleasessss help with 1,2 and 3

Answers

1.) Flammability
2.) Physical Properties
3.) Flammability, Reactivity, Ability to Rust

What is brewster's angle for light traveling in vacuum and reflecting off a piece of glass having a refractive index of 1.52?

Answers

The Brewster's angle for light traveling in vacuum and reflecting off a piece of glass having a refractive index of 1.52 is 56.7 degrees.

Brewster's angle is the angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.

When unpolarized light is incident at this angle, the light that is reflecting from the surface is therefore perfectly polarized.

The special angle of incidence that produces a 90 degrees angle between the reflected and refracted ray is called the Brewster angle, ∅p.

Formula for Brewster's angle: tan(∅) = μ

Given, The refractive index is μ. =1.52

By given the above relation,

tan∅ = μ

∅ = \(tan^{-1}\)(μ)

∅ = \(tan^{-1}\)(1.52)

∅ = 56.7°

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Which of the following is an example of an electromagnetic wave? (2 points)

Red light

Ocean waves

Sound waves

Earthquakes

Answers

a) red light
red lights are an example of an electromagnetic wave. visible lights are the only electromagnetic waves we can actually see on the spectrum. red, in particular has the biggest wavelength.

b) ocean waves
ocean waves are not an electromagnetic wave. in fact, it’s a mechanical wave. electromagnetic waves can travel through a vacuum, that is empty space, but mechanical waves cannot.

c) sound waves
sound waves are also not an electromagnetic wave. it’s a mechanical wave. you cannot hear electromagnetic waves.

d) earthquakes
an earthquake is also not an example of electromagnetic waves. it’s a mechanical wave.

hope this helps!

Answer:

a

Explanation:

In handball, who is the only player allowed in the goalie area?

Answers

Answer:

Only the goalie is allowed inside the goal crease. The only exception when another player is allowed in the goal area is when they take off from outside the goal area, and shoots or passes the ball before landing. To avoid interference with other players, the player must then exit the goal area as soon as possible.

Explanation:

Why do the constellations seem to move around in the sky?.

Answers

Answer: As Earth spins on its axis, we, as Earth-bound observers, spin past this background of distant stars. As Earth spins, the stars appear to move across our night sky from east to west, for the same reason that our Sun appears to “rise” in the east and “set” in the west.

Explanation:

A 0.8 kg baseball bat moving at 12m/s collided head on with a .13 kg baseball traveling at -39 m/s. If the ball returns in the opposite direction at +13 m/s what is the resulting speed of the bat?

Answers

The baseball bat's actual velocity is -4.625 m/s, which indicates that it is travelling in the opposite direction at a speed of 4.625 m/s.

How quickly does a cricket ball leave the bat?

The ball will bounce off the bat at a speed of around 20 km/h if the bat is held in a fixed position and a ball is launched at it at, say, 100 km/h.

The following is the equation for momentum conservation:

m1v1 + m2v2 = m1v1' + m2v2'

By entering the specified values, we obtain:

(0.8 kg)(12 m/s) + (0.13 kg)(-39 m/s) = (0.8 kg)(v1') + (0.13 kg)(13 m/s)

By finding v1', we obtain:

v1' = [(0.8 kg)(12 m/s) + (0.13 kg)(-39 m/s) - (0.13 kg)(13 m/s)] / (0.8 kg)

v1' = -4.625 m/s

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