A planned high-speed train between Houston and Dallas will travel a distance of 386 kilometers in 5.40 × 10^3 seconds. What is the average speed of this train?

Answer:

The mass of a spacecraft is the same on earth as the moon.

W = F = M a    the weight is different because the acceleration due to gravity is less on the moon than it is on earth.

On could choose a different mode of acceleration, say a compressed spring, and find that mass of an object does not depend on gravitational attraction.   F = M a holds on the moon as well as on earth

Answer:

tôi đoán lagf  pjhAWN ỨNG HÓA HỌC

Explanation:

The block that is sitting motionless on top of a wall contains potential energy.

Energy is the ability to do work. There are several forms of energy. For the block that is sitting motionless on top of a wall, the block contains potential energy.

The potential energy is the block is used to do work when the block falls. The block can break a piece of glass on the floor due to the energy that it contains.

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Electric charge inside a sealed electrical system is influenced by power input signal and component resistance. The pace at which electrons travel is called current.

The elements influence very strong a current flow is: Resistance of the cable and its cross-section. the conductor's material composition and thickness. the possible difference between the conductor's two points. the rate of electron drift and its density

The amount or fluid velocity of electrons passing a location in the circuit inside one time is known as current. Cranking amps, or amps for short, is another name for current flow. More current is going to flow whenever the voltage is greater, and less current is going to move because when voltage is lesser.

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Answer:

Distance is 50m

Displacement is 0m

Explanation:

Distance is based on the amount of length you covered, regardless of where you end.

Displacement only considered where you started and where you ended, which is at the same spot in this case. Therefore, no displacement.

The third principal maximum is at an angle of 12.3 degrees and the fifth principal maximum is at an angle of 24.6 degrees.


When light passes through narrow slits, it diffracts and produces a pattern of bright and dark fringes on a screen. The bright fringes are called principal maxima and are spaced at regular intervals. The angular position of the nth principal maximum can be calculated using the equation θ = nλ/d, where λ is the wavelength of the light, d is the distance between the slits, and n is the order of the maximum.

For this problem, the third principal maximum is the one where n=3, and the fifth principal maximum is the one where n=5. Plugging in the values given, we get θ3 = 12.3 degrees and θ5 = 24.6 degrees. It's important to note that the central maximum is considered the zeroth principal maximum and is located at an angle of 0 degrees.

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The airline will need to have at least 167 passengers on each flight to break even.

To calculate the number of passengers needed to break even, we need to consider the total costs and the revenue generated per flight.

The total cost per flight consists of the fixed costs (£25,000) and the variable costs (£75 per passenger). The revenue per flight is determined by the ticket price (£225) multiplied by the number of passengers.

Let's denote the number of passengers as 'P'. The total cost per flight is given by:

Total Cost = Fixed Costs + (Variable Cost per Passenger * Number of Passengers)

Total Cost = £25,000 + (£75 * P)

The revenue per flight is given by:

Revenue = Ticket Price * Number of Passengers

Revenue = £225 * P

To break even, the total cost should equal the revenue:

£25,000 + (£75 * P) = £225 * P

Now, we can solve this equation for P to find the number of passengers needed to break even:

£25,000 + (£75 * P) = £225 * P

£25,000 = £225 * P - £75 * P

£25,000 = £150 * P

P = £25,000 / £150

P ≈ 166.67

Since the number of passengers must be a whole number, we round up to the nearest whole number:

P = 167

The airline will need at least 167 passengers on each flight to break even. However, since the maximum capacity of the aircraft is 200 passengers, the airline will need to fill the aircraft to its maximum capacity to break even on each flight.

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To react completely with 0.500 L of volume of 0.500 M Na2CO3, you would need 0.250 L of 2.00 M HCl.

Write down the balanced chemical equation for the reaction between HCl and Na2CO3:

2 HCl + Na2CO3 → 2 NaCl + H2O + CO2

Determine the stoichiometry of the reaction:

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3.

Calculate the number of moles of Na2CO3:

Given that the volume of Na2CO3 solution is 0.500 L and the concentration is 0.500 M, we can use the formula:

Moles = Concentration × Volume

Moles of Na2CO3 = 0.500 M × 0.500 L = 0.250 moles

Use the stoichiometry to determine the number of moles of HCl needed:

According to the stoichiometry of the balanced equation, 1 mole of Na2CO3 reacts with 2 moles of HCl.

Therefore, to react with 0.250 moles of Na2CO3, we would need 2 × 0.250 = 0.500 moles of HCl.

Convert moles of HCl to volume:

Given that the concentration of HCl is 2.00 M, we can use the formula:

Volume = Moles / Concentration

Volume of HCl = 0.500 moles / 2.00 M = 0.250 L

Convert the volume to liters:

The final answer is 0.250 liters of 2.00 M HCl are needed to react completely with 0.500 L of 0.500 M Na2CO3.

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The can be obtained by using the balanced chemical equation: Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2  Write the balanced chemical equation for the reaction.

Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2

Calculate the number of moles of Na2CO3. Using the formula n = c × V, where n is the number of moles, c is the concentration, and V is the volume, we get:

n = c × V

= 0.500 M × 0.500 L

= 0.250 mol

Calculate the number of moles of HCl required.The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. Hence, the number of moles of HCl required can be calculated as follows

:n(HCl) = 2 × n(Na2CO3)

= 2 × 0.250 mol

= 0.500 mol

Calculate the volume of 2.00 M HCl required.The number of moles of HCl required is 0.500 mol. Using the formula V = n/c, where V is the volume, n is the number of moles, and c is the concentration, we get:

V = n/c

= 0.500 mol ÷ 2.00 M

= 0.250 L

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Answer:

acceleration = 0.013 m/s²

Explanation:

formula for acceleration is

a = (v-u) / t

a= (0.7-0.3) / 30

= 0.013

The acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds is 0.0133m/s²

Acceleration is defined as the change in velocity of a body with respect to time. Mathematically:

\(a=\frac{v-u}{t}\)

v is the final speed = 0.7m/s

u is the initial speed = 0.3m/s

t is the time taken = 30seconds

Substitute the given values into the formula:

\(a=\frac{0.7-0.3}{30}\\a=\frac{0.4}{30}\\a = 0.0133m/s^2\)

Hence the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds is 0.0133m/s²

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The undamped natural frequency, the damping ratio and the damped natural frequency are 3.162 rad / s, 0.211 and 3.098 rad / s respectively.

ωn = √ ( k / m )

ζ = c / 2 √ k m

ωn = Undamped natural frequency

k = Stiffness

m = Mass

ζ = Damping ratio

c = Damping co-efficient

m = 150 kg

k = 1500 N / m

c = 200 kg / s

ωn = √ ( 1500 / 150 )

ωn = 3.162 rad / s

ζ = 200 / 2 √ ( 1500 * 150 )

ζ = 0.211

Since ζ < 1,  the system is underdamped and the solution will oscillate.

ωd = ωn √ ( 1 - ζ² )

ωd = Damped natural frequency

ωd = 3.162 √ ( 1 - 0.211² )

ωd = 3.162 √ 0.96

ωd = 3.162 * 0.98

ωd = 3.098 rad / s

Therefore,

The given question is incomplete. The complete question is:

A spring-mass-damper system has mass of 150 kg, stiffness of 1500 N/m and damping coefficient of 200 kg/s. Calculate the undamped natural frequency, the damping ratio and the damped natural frequency. Is the system overdamped, underdamped or critically damped? Does the solution oscillate?

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The maximum energy that an alpha particle can transfer is 1.63 KeV.

let mass of electron, Me = 1

let mass of proton, Mp = 1836Me = 1836

let mass of alpha particle, Ma = 4Mp = 7344

And mass of the pion,  M = 66.41Me

(a) The maximum energy transferred to an electron in a single collision will be calculated as

\(Q_{max} = \frac{4mME}{(M+m)^{2} }\)

= \(\frac{4(1)(7344)(3MeV)}{(1+7344)^{2} }\)

= 0.00163 MeV

= 1.63 KeV

(b) The electrons are called the subatomic particles. The electrons have one of the symbol of e-and β-. The electrons are the first generation of the Lepton particles. These are generally describe the elementary particles. These particles do not have components and substructure.

Hence, maximum energy that an alpha particle can transfer is 1.63 KeV.

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Answer:

a) increases

Explanation:

Almost all substance or material undergoes expansion due to heating. Heat gives thermal energy to the molecules of a substance increasing their body temperature. The temperature of a substance is the measure of the average kinetic energy of the molecules of that substance. When the temperature of a substance increases, the molecules begin to agitate and try to move far from each other, leading to either a linear, area, or cubic expansion, or all three of them. Metals like copper expand very well on heating, and their expansion is relatively minute, but very observable. When the face of such a copper is scratched to give and angle, heating the copper uniformly will cause the copper to expand, leading to an increase in the angle formed.

The ∆G°vap of butane at 1 atm and 228.5 K is +3.6 kJ/mol.

The standard Gibbs free energy change of vaporization (∆G°vap) can be calculated using the following equation:

∆G°vap = ∆H°vap - T∆S°vap

where ∆H°vap is the standard enthalpy change of vaporization, ∆S°vap is the standard entropy change of vaporization, and T is the temperature in Kelvin.

Substituting the values given for butane at 1 atm and 228.5 K:

∆H°vap = 22.4 kJ/mol

∆S°vap = 82.3 J/(mol K)

T = 228.5 K

Converting the units of ∆S°vap to kJ/(mol K):

∆S°vap = 82.3 J/(mol K) / 1000 J/(kJ) = 0.0823 kJ/(mol K)

∆G°vap = (22.4 kJ/mol) - (228.5 K)(0.0823 kJ/(mol K))

∆G°vap = 22.4 kJ/mol - 18.8 kJ/mol

Therefore, the ∆G°vap of butane at 1 atm and 228.5 K is +3.6 kJ/mol.

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We have that using the Equation \(w = mg\) we derive the various mass of the objects on the Gizmo

Example

\(14N\ object=1.42kg\\\\80N\ object=8.16\\\\98N\ object=10kg\)

From the Question we are told that

Generally

For a Gizmo Bearing Weight of represented as integers

Say

14N,80N,98N

Therefore

For 14N

\(w = mg.\\\\14 = m*9.8.\\\\m_1=1.42kg\)

For 80N

\(w = mg.\\\\80 = m*9.8.\\\\m_2=8.16kg\)

For 98N

\(w = mg.\\\\98 = m*9.8.\\\\m_3=10kg\)

Answer:

It is actually impossible. But the answer is: 270 km/h.

Explanation:

Answer:

girl what- I can't answer this but I need points so I'ma just put this random lol sorry tho . ask the tutor

Answer:

P = 5400[W]

Explanation:

We must use the following equation of kinematics to calculate the acceleration.

\(v_{f}=v_{o}+a*t\)

where:

Vf = final velocity = 9 [m/s]

Vo = initial velocity = 0 (starting from rest)

a = acceleration [m/s²]

t = time = 1.5 [s]

\(9=0+a*1.5\\a=9/1.5\\a=6[m/s^{2} ]\)

Now with this second equation of kinematics, we can determine the distance traveled.

\(v_{f}^{2}=v_{o}^{2}+2*a*x\)

where:

x= distance [m]

\(9^{2} = 0 +2*6*x\\12*x=81\\x=6.75[m]\)

Now we must use Newton's second law which tells us that the sum of forces is equal to the product of mass by acceleration.

∑F = m*a

Now replacing:

\(F=100*6\\F=600[N]\)

Ahora la potencia se puede calcular por medio del producto de la fuerza por velocidad.

\(P=F*v\)

where:

P = power [W]

F = force = 600 [N]

v = velocity = 9 [m/s]

\(P=9*600\\P=5400[W]\)

A rocket ship has several engines and thrusters. While the solid rocket booster (srb) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8. 5 minutes after the launch. Once the srbs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s. During the first two minutes of flight, the SRB and main engine accelerate at a rate of 52.16 m/s2.

Acceleration is the rate at which a moving object's speed and direction change over time. When something moves faster or slower, it is considered to be accelerating. The engine's initial velocity (u), final velocity (v), and time of motion (t), which is equivalent to two minutes, are the parameters given (2 x 60 s).

The calculations for the main engine's and SRB's acceleration are listed below.

a= Δv / Δt

a=7600-1341 /2*60s

a=52.16 m/s²

As a result, during the first two minutes of flight, the main engine and SRB accelerate at a rate of 52.16 m/s2.

Your question is incomplete but most probably your full question is

A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBS are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.

What is the height of the rocket when the rocket reaches the speed of 7600 m/s? Show your work.

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Answer:

the answer for this is Letter B

i was wrong sorry

Explanation:

Answer:

it is relatively weak distance Force

ordered from strongest to weakest the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity

The work done on an object by a constant force is given by the formula:

W = Fd cos(theta)

where:

W = work done (in joules)

F = applied force (in newtons)

d = displacement (in meters)

theta = angle between the force and displacement vectors (in degrees)

In this case, the force is in the same direction as the displacement, so the angle between them is 0 degrees. Therefore, we can simplify the formula to:

W = Fd

We are given that the work done is 100 J and the force is 30 N. Substituting these values into the formula, we get:

100 J = 30 N * d

Solving for d, we get:

d = 100 J / (30 N) = 3.33 meters

Therefore, the displacement is 3.33 meters.

Answer:

B.

Explanation:

You cannot scrub the energy away. The energy is coming from the atoms themselves.

Moreover, according to the law of conservation of energy, energy cannot be created or destroyed. You cannot destroy energy.

E = mc^2

Equation above states the relationship between energy and mass. Therefore you cannot destroy matter or energy.

Answer:

Diameter of Wire = 4.5 mm

Explanation:

First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:

Fractional Part = Circular Scale Reading x Least Count

where,

Circular Scale Reading = 50

Least Count = 0.01 mm

Therefore,

Fractional Part = (50)(0.01 mm)

Fractional Part = 0.5 mm

Now, the diameter of the wire can be given by using the following formula:

Diameter of Wire = Linear Scale Reading + Fractional Part

Diameter of Wire = 4 mm + 0.5 mm

Diameter of Wire = 4.5 mm

Just one electrons fill the outer shell of the smallest four elements( H, He, Li, & Be).

A chemical element is a described as chemical substance that cannot be broken down into other substances.

The elements Hydrogen (H), lithium (Li), and sodium (Na), are  group 1 elements and are called  inert gases or noble gases because of their non-reactivity, hence have just one electron in their outermost shells.

Elements has properties and the properties include, but are not limited to, conductivity, magnetism, melting point, boiling point, color, state of matter, and others.

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Answer: thermodynamics energy

Answer:

I would wanna meet juice if he was still alive ofc

Explanation:

Answer:

iyuksouijz

Explanation:

ok,kcipxuoa